Look at the distance-time graph for a remote-controlled car. What is the speed of the car?
Pls help

Look At The Distance-time Graph For A Remote-controlled Car. What Is The Speed Of The Car?Pls Help

Answers

Answer 1

Answer:

10 m/s

Explanation:


Related Questions

Microwaves have a frequency of 10 000 million Hz. Their wavelength is 0.03 m.
Calculate the speed of microwaves.
Show clearly how you work out your answer.

Answers

The speed of the microwaves is 3 × 10^10 meters per second. This result indicates that microwaves, like all electromagnetic waves, travel at the speed of light in a vacuum.

The speed of a wave can be calculated using the formula: speed = frequency × wavelength. In this case, the frequency of the microwaves is given as 10,000 million Hz, which is equivalent to 10,000 × 10^6 Hz or 10^10 Hz. The wavelength is given as 0.03 m.

Plugging these values into the formula, we have:

Speed = (10^10 Hz) × (0.03 m)

Simplifying the calculation, we find:

Speed = 3 × 10^10 m/s

Therefore, the speed of the microwaves is 3 × 10^10 meters per second. This result indicates that microwaves, like all electromagnetic waves, travel at the speed of light in a vacuum. The speed of light is approximately 3 × 10^8 meters per second, so microwaves have a slightly higher speed due to their longer wavelength. It's important to note that the speed of light is a fundamental constant of nature and does not depend on the properties of the specific electromagnetic wave being considered.

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Problem B
A 1 kg cart A is initially at rest on a horizontal frictionless air track. A 0.2 kg cart B is
moving to the right at 10 meters per second on the same track. Cart B collides with
cart A causing cart A to move to the right at 3 meters per second.
17.- Calculate the velocity of cart B after the collision. Indicate the direction

Answers

Answer:

\(-5.0\frac{m}{s}\) or \(5.0\frac{m}{s}\) to the left

Explanation:

The equation for an elastic collision is \((m_1v_1)_i+(m_2v_2)_i=(m_1v_1)_f+(m_2v_2)_f\). Rearrange the equation for an elastic collision to solve for \((v_2)_f\):

\(\frac{[(m_1v_1)_i+(m_2v_2)_i-(m_1v_1)_f]}{m_2}\)

For this problem, let

\(m_1=1\ kg\\m_2=0.2\ kg\\(v_1)_i=0.0\ \frac{m}{s}\\(v_2)_i=10.0\ \frac{m}{s}\\(v_1)_f=3.0\ \frac{m}{s}\)

So,

\(\frac{[(1\ kg*0.0\ \frac{m}{s})+(0.2\ kg*10.0\frac{m}{s})-(1\ kg*3.0\ \frac{m}{s})]}{0.2\ kg}\\\frac{(0.0\ \frac{kg*m}{s})+(2.0\ \frac{kg*m}{s})-(3.0\ \frac{kg*m}{s})}{0.2\ kg}\\\frac{-1.0\ \frac{kg*m}{s}}{0.2\ kg}\\-5.0\ \frac{m}{s}\)

This result indicates that cart B will move to the left after the collision.


Find the velocity of the car after 6.9 s if its acceleration is 1.5 m/s² due south.

Answers

Velocity is 6.9 x 1.5 = 10.35 m/s due South

The velocity of the car after 6.9 s if its acceleration is 1.5 m/s² due south would be  10.35 meters / seconds.

What are the three equations of motion?

There are three equations of motion given by  Newton

v = u + at

S = ut + 1/2×a×t²

v² - u² = 2×a×s

Note that these equations are only valid for a uniform acceleration.

As given in the problem we have to find the velocity of the car we have to find the velocity of the car  after 6.9 s if its acceleration is 1.5 m/s² due south,

The acceleration of the car = 1.5 m/s²

The time taken by the car = 6.9 seconds

By using the first equation of the motion,

v = u + at

v = 0 + 1.5*6.9

v = 10.35 meters / seconds

Thus, the velocity of the car after 6.9 s, if its acceleration is 1.5 m/s² due south, would be  10.35 meters / seconds.

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Why is DNA a useful evolutionary clock?

Answers

Because analyzing DNA from present-day and ancient genomes provides a complementary approach for dating evolutionary events. Because certain genetic changes occur at a steady rate per generation, they provide an estimate of the time elapsed.

Light of wavelength 575 nm falls on two double slits spaced 0.30 mm apart. What is the required distance from the slits to a screen if the spacing between the first and second dark fringe is to be 4.00 mm

Answers

Answer:

L = 2.1 m

Explanation:

From Young's Double Slit Experiment, the formula for the distance between two consecutive dark or bright fringes, called fringe spacing, is derived as:

Δx = λL/d

where,

Δx = distance between first and second dark fringe = 4 mm = 4 x 10⁻³ m

λ = wavelength of light = 575 nm = 5.75 x 10⁻⁷ m

d = distance between the slits = 0.3 mm = 3 x 10⁻⁴ m

L = Distance from slits to screen = ?

Therefore,

4 x 10⁻³ m = (5.75 x 10⁻⁷ m)(L)/(3 x 10⁻⁴ m)

L = (4 x 10⁻³ m)/(1.92 x 10⁻³)

L = 2.1 m

A dentist causes the bit of a high speed drill to accelerate from an angular speed of 1.76 x 10^4 rads to an angular speed of 4.61 x 10^4 rat. In the process, the bit turns through 1.97 x 10 ^4 rad. Assuming a constant angular acceleration, how long would it take the reach its maximum speed of 7.99 x 10^4 rads starting from rest?

Answers

The time taken for the bit to reach the maximum speed is 1.35 seconds.

What is the angular acceleration of the bit?

The angular acceleration of the bit is determined by applying the following kinematic equation as shown below.

ωf² = ωi² + 2αθ

where;

ωf is the final angular speedωi is the initial angular speedθ is the angular displacementα is the angular acceleration

α = (ωf² - ωi²)/2θ

α = (46,100² - 17,600²) / (2 x 19,700)

α = 46,077.4 rad/s²

The time taken for the bit to reach the maximum speed is calculated as follows;

ωf = ωi + αt

t = (ωf - ωi) / α

t = (79,900 - 17,600) / (46,077.4)

t = 1.35 seconds

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A soccer ball is kicked with an initial horizontal velocity of 11 m/s and an initial vertical velocity of 17 m/s.
1)what is the initial speed of the ball?20.25 m/s
2)what is the initial angle 0 of the ball with respect to the ground? 57.09 degrees
3)what is the maximum height the ball goes above the ground? 14.74m
I need help with 4,5 and 6
4)How far from where it was kicked will the ball land?
5) what is the speed of the ball 2.5 second after it was kicked?
6)how high above the ground is the ball 2.5 seconds after it is kicked?

Answers

The answers are 4. The distance from where the ball was kicked is 38.06 meters, 5. The speed of the ball 2.5 seconds after it was kicked is 13.82 m/s, and  6. The ball is 21.88 meters above the ground 2.5 seconds after it is kicked.

4) To calculate the distance from where the ball was kicked, we need to find the time it takes to reach the ground. We can use the fact that the vertical displacement of the ball is zero at the highest point. Using the formula vf = vi + at, the time it takes to reach maximum height is t = vf / g where g is the acceleration due to gravity which is -9.8 m/s² since it is downward and vf is the final velocity which is 0 because the ball comes to rest at the highest point. t = 17 / 9.8 = 1.73 s. This means the total time for the ball to hit the ground is 2 x 1.73 = 3.46 s. Using the formula for horizontal distance traveled d = vt, we get d = 11 x 3.46 = 38.06 m. So, the distance from where the ball was kicked will be 38.06 meters.5) To calculate the speed of the ball 2.5 seconds after it was kicked, we need to find the horizontal and vertical components of the velocity of the ball at 2.5 seconds. The horizontal component is constant, so it will still be 11 m/s. To find the vertical component, we use the formula vf = vi + at where vi is initial velocity, a is acceleration due to gravity which is -9.8 m/s² and t is the time which is 2.5 seconds. vf = 17 + (-9.8 x 2.5) = -7.5 m/s. Since the ball is moving downward, the velocity is negative. Therefore, the speed of the ball 2.5 seconds after it was kicked is sqrt(11² + (-7.5)²) = 13.82 m/s.6) To calculate how high above the ground is the ball 2.5 seconds after it is kicked, we use the formula for the displacement of an object in the vertical direction y = vi*t + (1/2)*a*t² where vi is initial velocity, a is acceleration due to gravity which is -9.8 m/s² and t is the time which is 2.5 seconds. y = 17*2.5 + (1/2)*(-9.8)*(2.5)² = 21.88 m. So, the ball is 21.88 m above the ground 2.5 seconds after it is kicked.

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How far did the object travel from time = 0 to time =15 s 120 m. 180 m 90 m 45 m

How far did the object travel from time = 0 to time =15 s 120 m. 180 m 90 m 45 m

Answers

Answer:Position is an object’s location in relation to a reference point.

Yes. As in the movie theater example, an object can be one unit positive from the reference point and a different object can be one unit negative from the reference point. Both objects are one unit away (the same distance), but they occupy different locations in space because they are in different directions.

Distance is the total amount an object has traveled, while displacement is the shortest distance between the object’s starting and finishing point.

Distance does not have direction. Objects can be one unit away from a point in every direction. However, displacement does have a direction. Displacement is defined as a specific distance in a specific direction.

Explanation: hope it helped

carts, bricks, and bands

8. What acceleration results when 2 rubber bands stretched to 20 cm are used to pull a cart with three bricks?
a. About 0.25 m/s2
b. About 0.33 m/s2
c. About 0.50 m/s2
d. About 1.00 m/s2

Answers

A.  The acceleration results when 2 rubber bands stretched to 20 cm are used pull a cart with three bricks is 0.25 m/s².

What is the applied force on an object?

The force applied on object is obtained by multiplying the mass and acceleration of the object.

According to Newton's second law of motion, the force exerted on an object is directly proportional to the product of mass and acceleration of the object.

Also, the applied force is directly proportional to the change in the momentum of the object.

Mathematically, the force acting on object is given as;

F = ma

a = F/m

where;

a is the acceleration of the objectm is the mass of the objectF is the applied force

From the trials, the acceleration results when 2 rubber bands stretched to 20 cm are used pull a cart with three bricks is 0.25 m/s².

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carts, bricks, and bands8. What acceleration results when 2 rubber bands stretched to 20 cm are used

A marine weather station reports waves along the shore that are 2 meters high, 8 meters long, and reach the station 8 seconds apart. Determine the speed of these waves.

Answers

One full weather station reports  wave passing a spot every second is equivalent to a frequency of 1 Hz. The frequency is 48=12=0.5 Hz if 4 waves pass a spot in 8 seconds.

What is the frequency of a 30-second ocean wave that hits the shore?

The number of cycles that make up a time unit is the frequency. The frequency of a wave with a 30-second period is therefore 1 30 = 0.033 cycles per second, or 0.033 Hertz (Hz).

Which of the following statements most accurately sums up how a wave crosses a border and enters a new medium?

A wave's speed and wavelength vary as it crosses a border and enters a new medium, but its frequency doesn't.

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A high voltage (4.0×105 V) power transmission line delivers electrical energy from a generating station to a substation at a rate of 1.5×109 W. What is the current in the lines?

Answers

In order to find the current, we can use the formula below for the electric power:

\(P=I\cdot V\)

Where I is the current (in A) and V is the voltage (in V).

So, using P = 1.5 * 10^9 W and V = 4 * 10^5 V, we have:

\(\begin{gathered} 1.5\cdot10^9=I\cdot4\cdot10^5\\ \\ I=\frac{1.5\cdot10^9}{4\cdot10^5}\\ \\ I=0.375\cdot10^4\\ \\ I=3.75\cdot10^3\text{ A} \end{gathered}\)

Therefore the current is 3.75 * 10^3 A or 3.75 kA.

Which description accurately describes the tide represented by the image below? (4 points)
Image of the sun and moon at a 90 degree angle to Earth. An oval is around Earth that points toward and away from the moon to show the tidal bulges.

High tides occur when the sun and moon are at right angles to one another.
Low tides occur when the sun and moon are at right angles to one another.
The gravitational pull of the sun and moon combined creates larger than normal tides.
The gravitational pull of the sun reduces the moon's gravitational pull to create moderate tides.

Answers

High tides occur when the sun and moon are at right angles to one another. This is because the gravitational pull of the moon and the sun combine to create larger-than-normal tides, known as spring tides. The correct option is A.

Gravitational pull is the force of attraction that exists between two objects with mass. The greater the mass of an object, the greater its gravitational pull.

Option B, "Low tides occur when the sun and moon are at right angles to one another," is incorrect. Low tides occur when the sun and moon are at a 90-degree angle (or "quarter moon") to each other, but this position also results in high tides on the opposite side of the Earth.

Option C, "The gravitational pull of the sun and moon combined creates larger than normal tides," is partially correct. The gravitational pull of both the sun and moon does contribute to the tides, but the specific position depicted in the image (sun and moon at right angles to each other) does not necessarily create larger than normal tides.

Option D, "The gravitational pull of the sun reduces the moon's gravitational pull to create moderate tides," is also incorrect. The sun's gravitational pull does have an effect on the tides, but it does not reduce the moon's gravitational pull. Rather, the combined gravitational pull of the sun and moon creates the tides we observe.

Therefore,The accurate description of the tide represented by the image below is option A: "High tides occur when the sun and moon are at right angles to one another."

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plzzzzzzzzzzz help meeeeee

plzzzzzzzzzzz help meeeeee

Answers

Explanation:

The answer is C thick carpet

PLEASE MARK ME AS BRAINLIEST

Answer:

it is C

Explanation:

How does something(the big bang) come from nothing by nothing i mean the first universe although we don't know where the first universe is but we do know that nothing can't come from something.

Answers

The Big Bang theory is the most widely accepted explanation for the origins of the universe, but it does not necessarily imply that the universe emerged from nothing.

It is possible that new discoveries or insights may shed light on this fundamental question in the future. The universe may have arisen from a pre-existing state or through some other natural process that we do not yet understand.

Instead, the theory describes how the universe underwent a rapid expansion from a very dense and hot state. The conditions and laws of physics that applied during the earliest moments of the universe may not necessarily be the same as those we observe today, and there are many unknowns and uncertainties in our understanding of these early stages.

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(20%) Problem 5: Two identical springs, A and B, each with spring constant k=54.5 N/M, support an object with a weight W=11.6N. Each spring makes an angle of θ=20.6 degrees to vertical, as shown in the diagram.
50% Part (a) Write an expression for the tension in spring A (which is equal to the tension in spring B) in terms of W and θ.
T= W cos (θ) -sin (θ)

(20%) Problem 5: Two identical springs, A and B, each with spring constant k=54.5 N/M, support an object

Answers

The expression for the tension in the spring A is T(A) = √[(-W cos(90 - θ))² + (W sin(90 - θ))²]

What is the tension in spring A?

The tension in spring A can be determined by resolving the forces into x and y components as shown below.

The angle spring A makes with horizontal is calculated as;

A = 90⁰ - θ

The horizontal component of the tension on spring A;

T(Aₓ) = -W cos(A)

T(Aₓ) = -W cos(90 - θ)

The vertical component of the tension of spring A is calculated as;

T(Ay) = W sin(A)

T(Ay) = W sin(90 - θ)

The expression for the tension in spring A is calculated as;

T(A) = √[(T(Aₓ)² + T(Ay)²]

T(A) = √[(-W cos(90 - θ))² + (W sin(90 - θ))²]

Thus, the expression for the tension in the spring A is determined through resolution of vector components.

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Which example is an abiotic factor of an aquarium environment?

Answers

Answer:

See Explanation

Explanation:

salt, water, rocks, sediment, trash.

Abiotic factors are non-living organisms in an ecosystem.

Hope this helps and have a nice day

A grinding wheel with radius of 20 cm is speed of 200 rpm when its power is cut off. It slows to a stop in 90s What was is the angular displacement of a point located at Yr? b) That is the angular displacement of a point located at r? Through what linear distance will the point at h travel? d) Through what linear distance will the point at travel? Before it was cut off, what was the period of one rotation?

Answers

The angular displacement of a point located at r  is 7200π radians.

The angular displacement of a point located at Yr can be calculated using the formula: θ = ωₒt + (1/2)αt^2, where ωₒ is the initial angular velocity (in radians per second), t is the time it takes to come to rest, and α is the angular acceleration (in radians per second squared).

The initial angular velocity of the wheel can be calculated as ωₒ = 2πnₒ, where nₒ is the initial speed in revolutions per minute (RPM). We have nₒ = 200 RPM, so ωₒ = 2π * 200 / 60 = 40π radians per second.

The angular acceleration can be calculated as α = - ωₒ / t = - 40π / 90 = - 2π / 4.5 radians per second squared.

Plugging in the values, we get θ = 40π * 90 + (1/2)(-2π / 4.5) * 90²2 = 3600π radians.

The angular displacement of a point located at r can be calculated as θ = 2θ, since the distance traveled is twice as long. So, the angular displacement of a point located at r = 2θ = 2 * 3600π = 7200π radians.

The linear distance traveled by the point at h can be calculated as d = θ * Yr, where Yr is the radius of the wheel. Plugging in the values, we get d = 7200π * 20 cm = 144000π cm.

The period of one rotation before it was cut off can be calculated as T = 60 / nₒ = 60 / 200 = 0.3 seconds.

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A train is traveling at a constant rate of speed of 64 kilometers per hour. How many
hours will it take the train to travel a distance of 160 kilometers?
Please provide the units with it

Answers

Answer:

2.5 hours

Explanation:

we know that the train travels 64km every hour so we just need to divide 160km by 64km to see how many hours it will take

160÷64= 2.5

hope this helps chu :3

what is the pressure of a tank of uniform cross sectional area 4.0m2 when the tank is filled with water a depth of 6m when given that 1 atm=1.013 x 10^5pa density of water=1000kgm-3 g=9.8m/s2​

Answers

The pressure of the tank, when filled with water at a depth of 6 m, is approximately 580.124 atmospheres (atm). To calculate the pressure of the tank, one can use the equation: Pressure (P) = Density (ρ) × g × Depth (h)

Pressure (P) = Density (ρ) × g × Depth (h)

Given: Density of water (ρ) = 1000 kg/m³

Acceleration due to gravity (g) = 9.8 m/s²

Depth (h) = 6 m

Using the given values, one can calculate the pressure:

Pressure = 1000 kg/m³ × 9.8 m/s² × 6 m Pressure

= 58800 kg·m⁻¹·s⁻²

Now, let's convert the units to pascals (Pa) using the conversion 1 atm = 1.013 x \(10^5\) Pa:

Pressure = 58800 kg·m⁻¹·s⁻² × (1 atm / 1.013 x\(10^5\) Pa)

Pressure = 580.124 atm

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A large bagel spins with angular speed w about its center. A smaller bagel spins with triple the angular speed.
How does the period Tlarge of the large bagel compare with the period Tsmall of the small bagel?

Answers

Answer:

T large = 3T small

Explanation:

It's just 3 times larger

mila jogged 4.6 miles in 48 minutes. if she jogged at a constant rate, what was her jogging speed? miles per hour https://web2.0calc/questions/

Answers

Jogging speed typically ranges from 4 to 6 mile per hour . Jogging frequently maintains the touch with the ground, but running is sometimes regarded as requiring a brief break from it.5.75 miles per hour

How fast should I be running?

Simply dividing you run distance with your run time will give you your running speed. Thus, if someone ran 10 kilometers in half an hour, you can run 0.2 kilometers per minute. Flip the numbers to determine your pace for running. 5 minutes per kilometer equals four hours divided by 10 kilometers.

Does running help you lose tummy fat?

A great weight-loss workout is running. It reduces dangerous belly fat while burning much more calories during and possibly long after exercise. Running is easy to learn how to do and has a lot of other health advantages.

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The driver of a car steps on the brakes, and the velocity drops from 43 m/s due east to 3.38 m/s due east in a time of 70seconds. What is the acceleration?

Answers

Answer:

Explanation:

initial velocity, u = 43 m/s

final velocity, v = 3.38 m/s

time, t = 70 sec

acceleration, a = v - u / t

3.38 - 43 / 70

= -39.62/ 70

= -0.56 m/s^2

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thermometer is preferred fir very cold region give reason​

Answers

Answer:

alcohol thermometer is preferred for a very cold region. Alcohol thermometer is preferred for a very cold region because its freezing point of alcohol is - 117°C. So, it can measure the temperature of the very cold region.

A spaceship enters the solar system moving toward the Sun at a constant speed relative to the Sun. By its own clock, the time elapsed between the time it crosses the orbit of Jupiter and the time it crosses the orbit of Mars is 35.0 minutes. How fast is the spaceship traveling towards the Sun? The radius of the orbit of Jupiter is 43.2 light-minutes, and that of the orbit of Mars is 12.6 light-minutes.
A. 0.438c
B. 0.671c
C. 0.319c
D. 0.874c
E. 0.658c

Answers

B is the answer to this

The spaceship is traveling towards the Sun with velocity  0.319c.

What is special theory of relativity?

One of the most significant works in the history of physics is Albert Einstein's 1905 theory of special relativity. The theory of special relativity explains how speed affects space, time, and mass. Small amounts of mass (m) can be interchangeable with large amounts of energy (E), as defined by the classic equation E = mc², according to the theory, which offers a means for the speed of light to define the link between energy and matter.

Given parameters:

The radius of the orbit of Jupiter is 43.2 light-minutes.

that of the orbit of Mars is 12.6 light-minutes.

Hence, actual distance between them l₀= 43.2 - 12.6 light-minute = 30.6  light-minute.

Let the velocity of the spaceship is v.

Time taken to travel this actual distance  = l₀ √(1+v²/c²)/v

According to the question

l₀ √(1+v²/c²)/v = 35.0

√(c²+v²) = 35.0 v

c² = 1224 v²

v =  0.319c

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Express the mathematical formula to calculate the number of images formed when two mirrors are inclined at θ angle.

Answers

Answer:

The number of images formed by two adjacent plane mirrors depends on the angle between the mirror. If (in degrees) is angle between the plane mirrors then number of images are given by, n = 360 θ − 1.

Find the surface of each pyramid round to nearest tenth if necessary
12.2m
16m
10.6m
12.2m
12.2m

Answers

Surface area of pyramid 1  539.2 \(m^{2}\) Pyramid 2: 370.9 \(m^{2}\) Pyramid 3: 446.4 \(m^{2}\)

To find the surface area of a pyramid, we need to know the dimensions of its base and its slant height. Assuming the base of each pyramid is a square, we can calculate the surface area using the formula:

Surface Area = Base Area + (0.5 × Perimeter of Base × Slant Height)

Let's calculate the surface area for each pyramid using the given dimensions:

1. Pyramid 1: Base = 12.2 m Slant Height = 16 m Base Area = (12.2 \(m^2\)= 148.84 \(m^2\)Perimeter of Base = 4 × 12.2 m = 48.8 m

Surface Area = 148.84 \(m^2\)+ (0.5 × 48.8 m × 16 m) = 148.84 m^2 + 390.4 \(m^2\) = 539.24 \(m^2\) (rounded to nearest tenth)

2. Pyramid 2: Base = 10.6 m Slant Height = 12.2 m Base Area = (10.6 \(m^2\))= 112.36\(m^2\) Perimeter of Base = 4 × 10.6 m = 42.4 m

Surface Area = 112.36\(m^2\)+ (0.5 × 42.4 m × 12.2 m) = 112.36 \(m^2\)+ 258.56 \(m^2\) = 370.92 \(m^2\)(rounded to nearest tenth)

3. Pyramid 3: Base = 12.2 m Slant Height = 12.2 m Base Area = (12.2 \(m^2\)= 148.84 \(m^2\)Perimeter of Base = 4 × 12.2 m = 48.8 m

Surface Area = 148.84 m^2 + (0.5 × 48.8 m × 12.2 m) = 148.84 \(m^2\)+ 297.52 \(m^2\) = 446.36 \(m^2\) (rounded to nearest tenth)

Therefore, the surface areas of the given pyramids are approximately: Pyramid 1: 539.2 \(m^2\)Pyramid 2: 370.9 \(m^2\) Pyramid 3: 446.4 \(m^2\).

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plz help me

what do you meant by significant figure?give different rules to clarify significant figure.​

Answers

A significant figure is one that is measured rather than “guessed”. If you say that length is “approximately” 100m, then that is only 1 significant figure. If you measure accurately 100m for a race than that is 3 significant figures. If you are given the number 100 without comment, it could be 1,2 or 3 significant figures! The number 1.01 has 3 significant figures. The number 0.001 has only 1 significant figure. I hope this helps.

When ice melts, is thermal energy released or absorbed? What is an example of a chemical change in which thermal enersy is realeased?​

Answers

Answer:

energy is absorbed during the process of the ice melting.

In what ways does ecotourism help living things in ecosystems?

Answers

Ecotourism has the potential to eliminate the requirement to hunt wildlife for a living. Ecotourism generates revenue by maintaining the rainforest; deforestation is discouraged because it reduces tourist revenue.

What role does ecotourism play in biodiversity conservation?

Ecotourism firms safeguard biodiversity by preserving animals in their natural habitats and preserving natural ecosystems in biosphere reserves, wildlife sanctuaries, and national parks.

Can tourism save the environment?

Ecotourism contributes to the preservation of a destination's ecological and biological diversity. For example, since Costa Rica's jungle is so popular with visitors, inhabitants work hard to protect it instead of attempting deforest it for a short-term profit.

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A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm,find the emf of the cell.​

Answers

A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.

To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.

Given:

Resistance of the coil, R1 = 4 ohm

Resistance of the other resistor, R2 = 8 ohm

Current passing through the 8-ohm resistor, I = 2A

First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.

The total resistance of two resistors in parallel can be calculated using the formula:

1/Rp = 1/R1 + 1/R2

Substituting the given values, we have:

1/Rp = 1/4 + 1/8

1/Rp = 2/8 + 1/8

1/Rp = 3/8

Rp = 8/3 ohm

Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).

R_total = R_internal + Rp

R_total = 0.5 + 8/3

R_total = 1.833 ohm

Now, we can find the emf of the cell using Ohm's Law:

emf = I * R_total

emf = 2 * 1.833

emf ≈ 3.667 volts

Therefore, the emf of the cell is approximately 3.667 volts.

However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.

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