The length of NM and OL in the parallelogram LMNO are both 36 units.
How we find the value of x?Since LMNO is a parallelogram, we know that opposite sides are equal in length. Therefore, we can set NM and OL equal to each other:
NM = OL
We also know that NM = x + 27 and OL = 3x + 9, so we can substitute these expressions into the equation:
x + 27 = 3x + 9
Solving for x:
2x = 18
x = 9
Now that we know x, we can substitute it back into the expressions for NM and OL:
NM = x + 27 = 9 + 27 = 36
OL = 3x + 9 = 3(9) + 9 = 36
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Find the length of the segment indicated.
A) 8.3
C) 9.3
B) 14
D) 10
Answer:
B
Step-by-step explanation:
radius + equivalent tangents
one morning, ms. simon drove directly from her home to her workplace in 242424 minutes. what was her average speed, in miles per hour, during her drive that morning?
The average speed in miles per hour during her drive that morning is 43.5 miles per hour .
In the question ,
it is given that ,
the distance between home to freeway entrance is = 0.6 miles
the distance between freeway entrance to freeway exit is = 15.4 miles
the distance between freeway exit to workplace is = 1.4 miles
So , the distance from home to work place = 0.6 + 15.4 + 1.4 = 17.4 miles
we know that 24 minutes = 24/60 = 0.4 hours ,
the average speed = total distance / total time
= 17.4/0.4
= 43.5 miles per hour
Therefore , the average speed is 43.5 miles per hour .
The given question is incomplete , the complete question is
One morning, Ms. Simon drove directly from her home to her workplace in 24 minutes. what was her average speed, in miles per hour, during her drive that morning ?
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Solve 3[-x + (2 x + 1)] = x - 1.
x=
Answer:
x= -2
Step-by-step explanation:
what is the image of (5,7) under the glide reflection consisting of a reflectoin abou the y-axis followed by a translation of threee units in a positive direciton parallel to the y-axis
The image of the point (5,7) under the reflection about the y axis followed by a translation of 3 units in a positive direction parallel to y-axis is (-2,7) .
The reflection about the y-axis changes the sign of the x-coordinate , the y coordinate of the point remains unchanged .
So , the image of (5,7) under the reflection is (-5,7).
Next, there is a translation of 3 units in the positive direction parallel to y-axis , that means 3 units will be added to the x-coordinate and y coordinate remains unchanged .
So , the image of (-5,7) under the translation is (-5+3,7) = (-2,7) .
Therefore, the image of (5,7) is (-2,7) .
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if my y-int is (5,0) and my x-int is (0,80) what is my vertex??
PLEASE HELP ME
The vertex of the Quadratic function with a y-intercept of (5, 0) and an x-intercept of (0, 80) is located at the point (0, 0).
The vertex of a quadratic function given the y-intercept and x-intercept, we need to determine the axis of symmetry, which is the line that passes through the vertex. The x-coordinate of the vertex will be the midpoint between the x-intercepts, while the y-coordinate will be the same as the y-intercept.
Given that the y-intercept is (5, 0) and the x-intercept is (0, 80), we can determine the x-coordinate of the vertex by finding the midpoint of the x-intercepts. The x-coordinate of the midpoint is simply the average of the x-values:
x-coordinate of vertex = (0 + 0) / 2 = 0 / 2 = 0
Since the y-coordinate of the vertex is the same as the y-intercept, the vertex will have the coordinates (0, 0).
Therefore, the vertex of the quadratic function is (0, 0).
In conclusion, the vertex of the quadratic function with a y-intercept of (5, 0) and an x-intercept of (0, 80) is located at the point (0, 0).
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Given the equation of a circle, identify the center and the radius by completing the square.
x² + y² - 32x+24y +396 = 0
Center:
Radius:
The center and the radius by completing the square of the given equation of circle is x² + y² - 32x+24y +396 = 0 is C( -16, 12) and radius is 2.
The equation of the circle is given as x² + y² - 32x+24y +396 = 0.
Comparing the given equation with general equation of circle, x² + y² + 2gx + 2fy + c = 0.
The center of circle is C = (-g, -f)
The radius of circle is r = √g² + f² - c
Therefore, from the given equation,
2g = -32
g = -16
2f = 24
f = 12
C( -16, 12)
And the radius is
r = √(-16)² + (12)² - 396
= √256 + 144 -396
=√4
= 2
Hence, the center and the radius by completing the square of the given equation of circle is x² + y² - 32x+24y +396 = 0 is C( -16, 12) and radius is 2.
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17 feet in 4 minutes
pls hurry
Answer:
4.25
Step-by-step explanation:
17/4
= 4.25
I hope it helps! Have a great day!
Muffin ^^
Answer:
4.25
Step-by-step explanation:
The answer is 4.25 because you have to divide the feet by min and when you do that you get 4.25.
I hope it helps! Have a great day!
bren~
Can someone pls help?!
Answer:
A
Step-by-step explanation:
Will mark brainliest !!!
Answer:
27
Step-by-step explanation:
Length * width * height to find the volume so it is 3*3*3=27
take all coins that are still on tails and keep flipping them until they land on heads. what is the expected number of total flips until all coins are on heads?
The probability that all coins show heads up is 1/16.
How to calculate the probabilityThe probability of one is 1/2: Half of the time (on average, as all numbers in this answer will be) it will show heads.
Of those times it shows heads, only half of the time will the second coin also show heads. We're down to a quarter of the time now.
Of those times the second coin shows heads, only half of the time will the third coin also show heads. This is 1/8.
And, of the times the third coin also shows heads, only half of the time will the fourth coin also show heads. Half of 1/8 is 1/16.
You can simplify this by calculating (1/2)^4.
= 1/16
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Take all coins that are still on tails and keep flipping them until they land on heads. We flip 4 coins simultaneously. What is the probability that all coins show heads up?
Identify the highlighted part of circle O shown below
Central angle
Secant
Inscribed angle
Chord
Answer:
Chord
Step-by-step explanation:
Notice that the highlighted part is the line segment that joins the points J and E on the circle, which is known as a chord.
Solve the following equation for x.
Answer:
If you just solve normally, you will get x=2 and x=-3. But if you plug these in to check your work, you will find that they are wrong. Your answer is no solution
Step-by-step explanation:
ln(2x+3)+ln(x-2)=ln(x^2-2x)
Rule: log(a) + log(b) = log(a*b)
ln( (2x+3)(x-2) ) = ln(x^2-2x)
Rule: If log(a) = log(b) then a = b
(2x+3)(x-2) = x^2 - 2x
2x^2-x-6=x^2-2x
x^2+x-6=0
Using Quadratic Formula:
x = 2 and x = -3
But, plugging these numbers back into the original equation is false!
the ratio of boys to girls is 3:4 if there are 48 girls, what is the total number of sixth graders
Answer:
84
Step-by-step explanation:
The 4 part of the ratio relates to 48 girls, then
48 ÷ 4 = 12 ← value of 1 part of the ratio , then
3 parts = 3 × 12 = 36 ← number of boys
total number of students = 48 + 36 = 84
Let y be a random variable with cdf 10, X < 0 0.15, OSX<1 F(x) = 0.3, 1
Based on the information provided, we know that the random variable y has a cumulative distribution function (cdf) of 10 when X < 0, 0.15 when 0 <= X < 1, and F(x) = 0.3 when X >= 1.
To find the probability distribution function (pdf) of y, we need to take the derivative of the cdf. However, since the cdf is not continuous at X = 0 and X = 1, we need to break it up into three parts:
For X < 0:
F(y) = 10
For 0 <= X < 1:
F(y) = 0.15y + 10
For X >= 1:
F(y) = 0.3
Taking the derivative of each part, we get:
For X < 0:
f(y) = 0
For 0 <= X < 1:
f(y) = 0.15
For X >= 1:
f(y) = 0
Therefore, the pdf of y is:
f(y) =
0 for y < 0
0.15 for 0 <= y < 1
0 for y >= 1
Hi! Based on the information provided, it seems you are asking about the cumulative distribution function (CDF) of a random variable y. Here's an explanation using the given terms:
Let y be a random variable with CDF F(y). For the specified intervals, the CDF is defined as follows:
1. F(y) = 0.1, when y < 0
2. F(y) = 0.15, when 0 ≤ y < 1
3. F(y) = 0.3, when y = 1
The CDF F(y) describes the probability that the random variable y takes on a value less than or equal to a specific value. In this case, there is a 10% chance that y is less than 0, a 15% chance that y is in the range [0, 1), and a 30% chance that y is equal to 1.
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Full question:
Question 19 5 Pts Let Y Be A Random Variable With Cdf 10, X < 0 0.15, OSX≪1 F(X) = 0.3, 1
it is not possible to use a relational operator and math operators in the same expression.
It is possible to use a relational operator and math operators in the same expression.
In programming, you can use relational operators (e.g., <, >, ==, !=) and math operators (e.g., +, -, *, /) together in the same expression. This is often used in conditional statements or loops to compare calculated values.
For example, consider the following expression:
`if (2 * 3) > (4 + 1)`
In this expression, we have math operators (*) and (+) and a relational operator (>). The math operations are evaluated first, resulting in:
`if (6) > (5)`
Then, the relational operator (>) is evaluated, and the expression becomes:
`if True`
The expression is true because 6 is greater than 5.
It is possible to use both relational operators and math operators in the same expression, which can be useful in various programming situations such as conditional statements or loops.
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helppppppppppppppppp
Answer:
42 cm²
Explanation:
cut into 2 rectangles
area of rectangle: Length * Width
4 * (3+3+3) + 3 * 24 * 9 + 636 + 642 cm²Anna has a loyalty card good for a 7% discount at her local grocery store. What number should she multiply the prices on the tags by to find the price she would have to pay, before tax, in one step?
Anna should multiply the prices on the tags by 0.93 to find the price she would have to pay before tax in one step.
Given that Anna has a loyalty card good for a 7% discount at her local grocery store.
We have to find the number should she multiply the prices on the tags by to find the price she would have to pay, before tax
Anna should multiply the prices on the tags by 0.93 (which is 1 minus the 7% discount) to find the price she would have to pay before tax in one step.
For example, if an item costs $10 before the discount, Anna would pay $10 x 0.93 = $9.30 after the discount.
Hence, Anna should multiply the prices on the tags by 0.93 to find the price she would have to pay before tax in one step.
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Write an equation that passes through (-3,2) and (-2,5) in slope intercept form
Answer:
y = 3x + 11
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
calculate m using the slope formula
m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)
with (x₁, y₁ ) = (- 3, 2 ) and (x₂, y₂ ) = (- 2, 5 )
m = \(\frac{5-2}{-2-(-3)}\) = \(\frac{3}{-2+3}\) = \(\frac{3}{1}\) = 3 , then
y = 3x + c ← is the partial equation
to find c substitute either of the 2 points into the partial equation
using (- 2, 5 )
5 = 3(- 2) + c = - 6 + c ( add 6 to both sides )
11 = c
y = 3x + 11 ← equation of line
write an addition or subtraction problem that is modeled by the number line below
-2 + 2
If you need an answer too. The answer is 0.
what is the arithmetic mean of all of the positive two-digit integers with the property that the integer is equal to the sum of its first digit plus its second digit plus the product of its two digits?
The arithmetic mean is 59.
What is arithmetic mean?
It is the sum of collection of numbers divided by the count of the numbers.
Conider AB is the nuber satisfying the condition. Hence,
\(10A+B=A+B+A\times B\\9A=A\times B\\\)
Since AB is a two digit number hence, \(A\neq 0\\\). Hence, divide both sides by \(A\).
\(9=B\)
Hence, B is 9 and A can take any value from 1 to 9.
Hence, numbers are 19, 29, 39, 49, 59, 69, 79, 89,99.
Now, calculate arithmetic mean as follows:
\(AM=\frac{Sum \ of \ numbes}{Count \ of \ numbers}\\=\frac{19+29+39+49+59+69+79+89+99}{9}\\=59\)
Hence, arithmetic mean of numbers is 59.
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how is the answer to this 15.7 please explain in detail
The mean of the given histogram is: 15.7
How to find the mean of the histogram?The steps to find the mean of the histogram are:
step 1:
For each bar in the histogram, we multiply the categories (numbers) by the height of the bar (how many of each number there are).
Step 2:
Sum all the products found in step 1 to get the grand total of the data.
Step 3:
Divide this total by the total bar height to get the average.
Thus, we can find the mean of the given histogram as follows:
(5 * 2.5) + (7.5 * 8) + (12.5 * 14) + (17.5 * 14) + (22.5 * 2) + (27.5 * 2) + (32.5 * 2) + (37.5 * 1) + (42.5 * 1) + (47.5 * 1))/(5 + 8 + 14 + 14 + 2 + 2 + 2 + 1 + 1 + 1)
= 785/50
= 15.7
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Omg please help
I’m failing my math class and I need it to graduate
Answer:
$203.56
Step-by-step explanation:
Look up the column with heading 3-year loan.
It starts with
$28.21 for 1-yrst loan
$28.64 for 2-year loan
$29.08 for 3-year loan
Since he is taking a 3-year loan, the amount we need from the table is
$29.08.
Now read the title of the table carefully.
All these amounts shown in the table are the monthly payment for a $1000 loan. Since this loan is $7,000, we need to multiply the monthly payment we found by 7.
7 × $29.08 = $203.56
Use the given transformation to evaluate the integral. double integral 9xy dA R , where R is the region in the first quadrant bounded by the lines y = 2 3 x and y = 3x and the hyperbolas xy = 2 3 and xy = 3; x = u/v, y = v
It looks like the boundaries of \(R\) are the lines \(y=\dfrac23x \) and \(y=3x\), as well as the hyperbolas \(xy=\frac23\) and \(xy=3\). Naturally, the domain of integration is the set
\(R = \left\{(x,y) ~:~ \dfrac{2x}3 \le y \le 3x \text{ and } \dfrac23 \le xy \le 3 \right\}\)
By substituting \(x=\frac uv\) and \(y=v\), so \(xy=u\), we have
\(\dfrac23 \le xy \le 3 \implies \dfrac23 \le u \le 3\)
and
\(\dfrac{2x}3 \le y \le 3x \implies \dfrac{2u}{3v} \le v \le \dfrac{3u}v \implies \dfrac{2u}3 \le v^2 \le 3u \implies \sqrt{\dfrac{2u}3} \le v \le \sqrt{3u}\)
so that
\(R = \left\{(u,v) ~:~ \dfrac23 \le u \le 3 \text{ and } \sqrt{\dfrac{2u}3 \le v \le \sqrt{3u}\right\}\)
Compute the Jacobian for this transformation and its determinant.
\(J = \begin{bmatrix}x_u & x_v \\ y_u & y_v\end{bmatrix} = \begin{bmatrix}\dfrac1v & -\dfrac u{v^2} \\\\ 0 & 1 \end{bmatrix} \implies \det(J) = \dfrac1v\)
Then the area element under this change of variables is
\(dA = dx\,dy = \dfrac{du\,dv}v\)
and the integral transforms to
\(\displaystyle \iint_R 9xy \, dA = \int_{2/3}^3 \int_{\sqrt{2u/3}}^{\sqrt{3u}} \frac{dv\,du}v\)
Now compute it.
\(\displaystyle \iint_R 9xy \, dA = \int_{2/3}^3 \ln|v|\bigg|_{v=\sqrt{2u/3}}^{v=\sqrt{3u}} \,du \\\\ ~~~~~~~~ = \int_{2/3}^3 \ln\left(\sqrt{3u}\right) - \ln\left(\sqrt{\frac{2u}3}\right) \, du \\\\ ~~~~~~~~ = \frac12 \int_{2/3}^3 \ln(3u) - \ln\left(\frac{2u}3\right) \, du \\\\ ~~~~~~~~ = \frac12 \int_{2/3}^3 \ln\left(\frac{3u}{\frac{2u}3}\right) \, du \\\\ ~~~~~~~~ = \frac12 \ln\left(\frac92\right) \int_{2/3}^3 du \\\\ ~~~~~~~~ = \frac12 \ln\left(\frac92\right) \left(3-\frac23\right) = \boxed{\frac76 \ln\left(\frac92\right)}\)
Each of the following represents a type of radiation. Identify Q in each of the symbols. 0 4 0 a. Q b. Q c. e +1 0 4 0 2 +1
Hence, we have identified Q in each of the symbols as alpha radiation, beta radiation, and positron emission radiation.
Given, Each of the following represents a type of radiation. Identify Q in each of the symbols.0 4 0 a. Q b. Qc. e+1 0 4 0 2+1The symbols given represent the type of radiation and we need to identify Q in each of the symbols. Q represents the type of radiation in each of the symbol.
The types of radiation are given below: Symbol: 040 a type of radiation: Alpha radiation Q: Symbol: 0Qb. Q Type of radiation: Beta radiation Q: e+1 040 2+1Type of radiation: Positron emission radiation
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The one-year zero rate is 6% and the three-year zero rate is 6.5%. What is the forward rate from the first year ( t=1 ) to the third year ( t=3 )? A. 6.75% B. 7.00% C. 7.25% D. 7.50% QUESTION 21 Bonus Question: please show the details so I can follow your logic. An interest rate is 6% per annum with quarterly compounding. The equivalent rate with monthly compounding is ? (Keep 4 decimals. E.g 6% as 0.0600)
To calculate the forward rate from year 1 (t = 1) to year 3 (t = 3), we use the formula:F(1,3) = ((1 + R3)^3 / (1 + R1)^1)^(1 / (3 - 1)) - 1
Where R1 is the one-year zero rate and R3 is the three-year zero rate.
Substituting the given values, we get:
F(1,3) = ((1 + 0.065)^3 / (1 + 0.06)^1)^(1 / 2) - 1= ((1.065^3) / (1.06))^(1/2) - 1= (1.206320125 / 1.06)^(1/2) - 1= 1.0717857394 - 1= 0.0717857394
The required forward rate from year 1 (t = 1) to year 3 (t = 3) is approximately 7.18% (rounded to two decimal places).
The formula to find the equivalent rate with monthly compounding is:i_m = (1 + i_q / 4)^4 - 1
Where i_q is the quarterly interest rate.
Substituting the given values, we get:i_m = (1 + 0.06 / 4)^4 - 1= (1.015)^4 - 1= 0.06167859024
Therefore, the equivalent rate with monthly compounding is approximately 6.17% (rounded to four decimal places).
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A movie theater in town posted these prices for tickets and snacks.
A 2-column table with 7 rows. Column 1 is labeled Item with entries adult ticket, child ticket, drink, popcorn, veggie cup, soft pretzel, apple slices. Column 2 is labeled cost (dollars) with entries 9, 6, 1.35, 3.50, 1.74, 2.65, 3.85.
Sally and Anne went to the movies. They each purchased a drink. They also bought one popcorn and one veggie cup to share. Which expression can be used to find how much money each woman spent?
One-half (9 + 1.35 + 3.50 + 1.74)
9 + 1.35 + one-half (3.50 + 1.74)
18 + 2.70 + one-half (3.50 + 1.74)
9+1.35+2(3.50+1.7)
Answer:
9 + 1.35 + one-half (3.50 + 1.74)
Step-by-step explanation:
Sally pay
9 - adult ticket
1.35 - drink
1/2 ( 3.50 popcorn + 1.74 veggie cup)
= 9 + 1.35 + 1/2(3.50 +1.74)
A gardener planted a newly sprouted oak tree that was just 3.5 inches tall. The sapling grew 12 inches each year.
Write an equation that shows how the sapling's height in inches, y, depends on the number of years since it was planted, x.
Answer:
y = 12x + 3.5--------------------------------------
Initial height is the y-intercept of the line.
Yearly growth rate is the slope.
So we have:
m = 12, b = 3.5.The equation of the line with these constants is:
y = mx + by = 12x + 3.5please please help me super quickkk
Answer:
C
Step-by-step explanation:
Using the formula do you sound level and disciples are use the intensity of the sound you're measuring. Set an alarm to normal conversation has an intensity of 3.2×10 to the -6
Answer:
65.1 decibels
Step-by-step explanation:
Given
\(I = 3.2 * 10^{-6}\) --- intensity
Required
Determine the sound level
This is calculated using:
\(B = 10\log(\frac{I}{I_o})\)
Where:
\(I_o = 1 * 10^{-12}\)
So, we have:
\(B = 10\log(\frac{3.2 * 10^{-6}}{1 * 10^{-12}})\)
Apply law of indices
\(B = 10\log(\frac{3.2 * 10^{-6+12}}{1})\)
\(B = 10\log(3.2 * 10^{6})\)
Using a calculator, we have:
\(B = 10*6.51\)
\(B = 65.1\)
How do you know if the linear term will be a plus or a minus ?
Answer:
I think these links will help you out here: (I read through and watch both)
https://www.purplemath.com/modules/factquad.htm
https://www.khanacademy.org/math/algebra/x2f8bb11595b61c86:forms-of-linear-equations/x2f8bb11595b61c86:standard-form/v/standard-form-rules
Step-by-step explanation:
Hope that this helps! :)
Have a great rest of your day/night!