la 212 what are some of the ways that science is modeled in the garden of cosmic speculation by charles jencks and maggie keswick?

Answer:

6.76875 • 10 ^-10 F

Explanation:

You just follow the formula:

C = εA/d

ε = 8.85 • 10^-12

A = 3.61 • 10^-4

D = 4.72 • 10 ^-6

So:

C = (8.85 • 10^-12)(3.61 • 10^-4)/4.72 • 10 ^-6 = 6.76875 • 10 ^-10 F

Good Luck!  :)

If the right safety measures are implemented, explosives can be transported across great distances without blowing up since they need a precise combination of circumstances to detonate. A particular temperature, pressure, and confinement are some of these conditions. The explosive won't go off if these requirements are not met.

Explosives are kept in specialized containers during transit in order to prevent accidental detonation owing to environmental conditions like heat, shock, or pressure. The containers are made to keep the explosive from coming into contact with anything else that might set it off.

Additionally, the transportation of explosives is strictly regulated and subject to tight safety guidelines. These safety precautions guarantee that explosives are handled, transported, and stored safely to reduce the possibility of unintentional detonation.

Transporting explosives still entails inherent dangers, thus it should only be done by skilled experts who are aware of the necessary safety procedures and potential hazards.

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When two rope segments pull up on the load in the single movable pulley, the optimal mechanical advantage is 2. This sort of pulley does not change the direction of the applied force, but it does increase it by a factor of two.

There are two methods for calculating a pulley system's mechanical advantage.

The mechanical advantage may be calculated simply by counting the number of falls (or active lifting ropes) that are really attached to the load. You may also split the effort distance by the load distance.

Assuming an ideal rope and pulley system with a mechanical advantage of  \(2.00\) , the output load that can be lifted with an input force of \(200 N\) can be calculated using the formula:

Output force = Input force x Mechanical advantage

Where the mechanical advantage is given as \(2.00\)  .

Thus, the output force is:

Output force \(= 200 N \times 2.00 = 400 N\)

Therefore, with an input force of \(200 N\)  , the rope and pulley system can lift an output load of up to \(400 N\) .

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Erik Erikson believes that midlife involves a psychosocial crisis characterized by generativity versus stagnation. This stage focuses on establishing and nurturing the next generation, contributing to society, and finding a sense of accomplishment.

This crisis occurs in the stage of adulthood known as middle adulthood, typically between the ages of 40 and 65 years old. Generativity refers to a sense of productivity and accomplishment in one's work, family, and community, while stagnation refers to a lack of growth and development in these areas.

During this stage, individuals may reflect on their past accomplishments and failures and begin to focus on leaving a legacy for future generations. They may also experience a sense of loss or regret if they feel they have not achieved their goals or contributed meaningfully to their communities. Erikson believed that successfully navigating this crisis requires finding a balance between caring for oneself and others, maintaining productivity and creativity, and developing a sense of purpose and meaning in life.

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Answer:

315N each

Explanation:

sence no one is winning, they must be pulling the same amount. So this means that we have to devide the total energy in half to find each side. 630/2 =315

The average power developed by the boy during the climb is approximately 29.4 W.

In physics, the amount of energy transferred or converted per unit time is called power.

total height = number of steps x height of each step

total height = 30 x 0.15 m = 4.5 m

Given, time = 60 s

As power = work done / time

work done = force x distance

force = mass x gravity

mass is boy's mass (40 kg) and gravity is acceleration due to gravity (9.81 m/s²).

force = 40 kg x 9.81 m/s² = 392.4 N

The distance that the boy moves is equal to the total height that he has climbed: distance = total height = 4.5 m

work done = force x distance

work done = 392.4 N x 4.5 m = 1765.8 J

power = work done / time

power = 1765.8 J / 60 s

power ≈ 29.4 W

Therefore, the average power developed by the boy during the climb is approximately 29.4 W.

As for the anomalous behavior of water, water has a higher boiling point and melting point as compared to other substances with similar molecular weight. This is due to the strong hydrogen bonding between water molecules, which requires more energy to break the bonds and change the state of water from solid to liquid to gas.

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The compression of 10 cm by a 100 N force on the plane that has a

coefficient of friction of 0.39 give the following values.

Mass of the block, m = 3 kg

\(Spring \ constant, K = \dfrac{100 \, N}{0.1 \, m} = \mathbf{ 1000\, N/m}\)

Coefficient of kinetic friction, \(\mu_k\) = 0.39

Therefore, we have;

Friction force = \(\mathbf{\mu_k}\)·m·g·cos(θ)

Which gives;

Friction force = 0.39 × 3 × 9.81 × cos(48°) ≈ 7.68

Work done by the motion of the block, W ≈ 7.68 × d

The work done = The kinetic energy of the block, which gives;

\(\mathbf{\dfrac{1}{2} \times k \cdot x^2 }= 7.68 \cdot d\)

The initial kinetic energy in the spring is found as follows;

K.E. = 0.5 × 1000 N/m × (0.1 m)² = 5 J

The initial velocity of the block is therefore;

5 = 0.5·m·v²

v₁ = √(2 × 5 ÷ 3) ≈ 1.83

Work done by the motion of the block, W ≈ 7.68 N × 0.07 m ≈ 0.5376 J

Chane in kinetic energy, ΔK.E. = Work done

ΔK.E. = 0.5 × 3 × (v₁² - v₂²)

Which gives;

ΔK.E. = 0.5 × 3 × (1.83² - v₂²) = 0.5376

Which gives;

The height at which the block will stop moving, h, is given as follows;

\(At \ the \ maximum \ height, \ h, \ we \ have ; \ \dfrac{1}{2} \times 1000 \times 0.1^2 = 7.68 \times x\)

Which gives;

\(Length \ of \ the \ incline \ at \ maximum \ height, \ x_{max} =\dfrac{ 7.68 }{ \dfrac{1}{2} \times 1000 \times 0.1^2 } \approx 1.536\)

The distance up the inclined, the block rises, at maximum height is therefore;

\(x_{max}\) ≈ 1.536 m

Therefore;

h = 1.536 × sin(48°) ≈ 1.1415

From the above solution for the height, the length of the incline is he

distance along the incline at maximum height which is therefore;

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To calculate the density of the metal, the person needs the length, width, height, and mass of the metal.

The density of a metal is defined as the mass of the metal per unit volume of metal. Therefore the density of the metal is given as, D= M/V, where 'M' is the mass of the metal and 'V' is the volume of the metal. Now the volume of the metal is obtained by the product of its length, width, and height. so, the volume of the metal is given as, V=l×b×h, where 'l' is the length of the metal block, 'b' is the width of the metal block, and 'h' is the height of the metal block. The person measures the mass and the length, width, and height of the block with rectangular sides. All these measurements are required to calculate the density of the metal block.

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To find the profit-maximizing energy level of output for a firm in monopolistic competition, we need to use the following formula: MC = MR, Where MC is the firm's marginal cost and MR is the firm's marginal revenue.

The profit-maximizing level of output for the firm is 49 units. To find the profit at this level of output, we plug Q = 49 into the demand and cost functions:
P = 200 - 2(49) = 102
C(Q) = 10 + 4(49) = 206
Profit = Total revenue - Total cost
Profit = P * Q - C(Q)
Profit = 102 * 49 - 206
Profit = 4,988

In this case, the profit-maximizing level of output is 49 units. This is because, at this level of output, the marginal profit is zero, meaning any additional units produced would not increase profit further.

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Answer: The car slows down by 10 meters per second every second.

Explanation:

AnswerThe speed of a car is decreased uniformly from 30. meters per second to 10. meters per second in 4.0 seconds. What was the car's acceleration ?

We have the following data:

V (final velocity) = 10 m/s

Vo (initial velocity) = 30 m/s

ΔV  (speed interval)  = V - Vo → ΔV  = 10 - 30 → ΔV  = - 20 m/s

ΔT (time interval) = 4.0 seconds

a (average acceleration) = ? (in m/s²)

Explanation:

The x-component of the net force on q2 is -1.439 × 10^-10 N.

The given charges are Q1 = -4.60 * 10^-6 C, q2 = +3.75 * 10^-5 C, and q3 = -5.30 * 10^-6 C. We need to find the x-component of the net force on q2.

The formula for force is F = K(q1 * q2) / r^2, where K is Coulomb's constant = 8.99 × 10^9 Nm^2/C^2, q1 and q2 are the charges in Coulombs, and r is the separation distance in meters.

The force between q2 and Q1 on the x-axis can be calculated as:

F1 = K(Q1 * q2) / r^2 ... (i)

Here, K = 8.99 × 10^9 Nm^2/C^2, Q1 = -4.60 × 10^-6 C, q2 = 3.75 × 10^-5 C, and r = 0.05 m.

Calculating F1:

F1 = (8.99 × 10^9) * (-4.60 × 10^-6) * (3.75 × 10^-5) / (0.05)^2

F1 = -1.242 × 10^-10 N

Similarly, the force between q2 and q3 on the x-axis can be calculated as:

F2 = K(q2 * q3) / r^2 ... (ii)

Here, K = 8.99 × 10^9 Nm^2/C^2, q2 = 3.75 × 10^-5 C, q3 = -5.30 × 10^-6 C, and r = 0.06 m.

Calculating F2:

F2 = (8.99 × 10^9) * (3.75 × 10^-5) * (-5.30 × 10^-6) / (0.06)^2

F2 = -1.971 × 10^-11 N

The net force can be calculated by adding F1 and F2, considering their x-components:

Fnet = F1 + F2

Fnet = (-1.242 × 10^-10) + (-1.971 × 10^-11)

Fnet = -1.439 × 10^-10 N

As both forces act in opposite directions along the x-axis, the net force is in the negative x-direction.

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Answer:

20kgm/s

Explanation:

p=mv

p=5*4

p=20kgm/s

If the volume of the gas is made to be 29 litres by raising the temperature to 325 K and lowering the pressure to 20.0 atm, then (d) 5.9 litres of gas are present initially.

Temperature is a measure of hotness and coolness on a variety of scales, including the Fahrenheit and Celsius systems. According to temperature, heat energy will naturally move from a hotter (body with a higher temperature) to a colder (body with a lower temperature) (one at a lower temperature). The physical concept of temperature indicates in numerical form how hot or cold something is. A thermometer is used to determine temperature.

A branch of physics called thermodynamics investigates heat and temperature. The movement of energy all through the cosmos is governed by the principles of thermodynamics. They are researched in many branches of engineering and science, including chemistry, biology, and environmental science. Temperature can be expressed in Celsius (°C), Kelvin (K), Fahrenheit (°F), or Rankine units and describes the average energy of molecules inside a substance or system (R). It is a quantifiable physical characteristic of an object; a state variable.

The Ideal Gas Law can be used to find the gas's initial volume.

PV = nRT, where P is pressure, V is volume, n is number of moles of gas, R is ideal gas constant, and T is temperature in kelvins, is the formula for the Ideal Gas Law.

Initially:

P1 * V1

= n * R * T1

After change:

P2 * V2

= n * R * T2

We may put the two equations equal to one another and find the starting volume because the quantity of gas in a given mole does not vary.

P1 * V1 = P2 * V2

V1 = (P2 * V2) / P1

V1 = (20.0 atm * 29 L) / 60.0 atm

V1 = (20.0/60.0) * 29 L

V1 = (1/3) * 29 L

V1 = 9.67 L

Therefore, the gas's starting volume was 9.67 litres. The closest option is d. 5.9 litres, so that is the correct response.

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Answer:it takes approximately 148.8 seconds to achieve. The average person in a free-fall will hit the ground going at 9.66 m/s from the top of the Empire State Building.

Explanation:

Explanation:

sorry_______________

Answer:

1. 180 m

2. 1.5 miles/hour

3. 0 m/s

Explanation:

The complete question is

A dog runs 300 m North and sees the dog catcher and runs 120 m south Whats the dogs displacement.

A jogger runs north for 3.0 miles. If this took 2.0 hours, what is the jogger’s average velocity in miles per hour?

The same jogger runs 3.0 miles on the track, starting and finishing his run after completing exactly 12 laps around the track. What is his average velocity?

1. Displacement is how far the dog moves from the original starting point.

If the dog runs 300 m north, and then 120 m south, then the displacement from the starting point will be

displacement = 300 - 120 = 180 m

2. Displacement of the jogger = 3 miles

Time taken by the jogger = 2 hours

velocity of the jogger = ?

Velocity is = displacement/time

velocity = 3/2 = 1.5 miles/hour

3. velocity = displacement/time

if the jogger completes exactly 12 laps around the track, then the jogger will return to the starting point. This means that the jogger's displacement from the starting point is 0 miles

Jogger's velocity will therefore be = 0 m/s

The mass at the other end of bar will be 50g .

what is mass

It is the fundamental property of matter , every single property which exist in this world has mass

Mass never can be 0 .

So , the system is in equilibrium

let mass of the body be m

55×5= m×5.5

m= 5 5 × 5 /. 5.5

m= 5 0g



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137.5 kg mass can be placed 2m away from the other end of the bar to keep the bar horizontally.

To keep the bar horizontal, the right and left side torques must be equal:

\(F_{1} d_{1} =F_{2} d_{2}\)

\(F_{2} =F_{1} \frac{d_{1} }{d_{2} }\)

    \(=(55.9.8)\frac{5}{2}\)

    =1347.5 N.

Convert this force of gravity into mass:

\(F_{2} =m_{2} g,\)

\(m_{2} =\frac{F_{2} }{g}\)

     \(=\frac{1347.5}{9.8}\)

     =137.5 kg.

The answer is 137.5 kg.

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The object distance at which the magnification will be +0.80 for a diverging lens with a focal length of magnitude 13 cm is:

do = -21.67 cm

To solve this problem, we can use the formula for magnification:

m = -di/do

Where m is the magnification, di is the image distance, and do is the object distance.

We are given that the focal length of the lens, f, is 13 cm. For a diverging lens, the focal length is negative, so we can write:

f = -13 cm

We are also given that the magnification, m, is +0.80. Substituting these values into the formula above, we get:

0.80 = -di/do

Solving for di, we get:

di = -0.80do

Now we can use the lens equation to relate do and di:

1/do + 1/di = 1/f

Substituting the values we know, we get:

1/do + 1/(-0.80do) = 1/(-13 cm)

Simplifying and solving for do, we get:

do = -21.67 cm

However, we need to express our answer with the appropriate units, which are centimeters. Therefore, the object distance at which the magnification will be +0.80 for a diverging lens with a focal length of magnitude 13 cm is:

do = -21.67 cm

(Note that the negative sign indicates that the object is on the opposite side of the lens from the observer, which is consistent with the fact that we are dealing with a diverging lens)

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Answer:59.3

Explanation:

The force due to gravity or weight is 582 N. The mass of a student  is 59.39 Kg.

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Force = mass.acceleration

582 = m*9.8

m = 59.39 Kg.

The force due to gravity or weight is 582 N. The mass of a student  is 59.39 Kg.

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Answer:

temporary iron r made up of soft iron its " true.."

Answer:

25.6 meters

Explanation:

have a good day

Answer:

Explanation:

liquids have definite volume

liquids do not have definite shape. The take the shape of the container in which they are kept.

gases do not have definite volume.

gases do not have definite shape. They take the shape of the container in which they are kept.

Hope this helps

plz mark as barinliest!!!!!!

Stay safe!

Explanation:

Liquids- Have definite volume

             No definite shape(takes the shape of the container)

Gases-  No definite volume

             No definite shape(takes the shape of the container)

Using lens equation:

Answer:

1.21 cm

To further stretch the spring from l m to L m, the work done is given by W = 0.5k (L² - l²), where k is the spring constant and l and L are the initial and final lengths respectively.

Given, it requires a force of 18 N to hold a spring stretched l m beyond its natural length.Since the work done is equal to the change in potential energy, therefore, the work required to further stretch the spring from l m to L m is given by:

W = Uf - Ui

= 0.5 k L² - 0.5 k l²

Now, we have k = F / x where F is the force required to stretch the spring by a distance x.So,

k = 18 / l

Also, the force required to stretch the spring to length L is given by:

F' = k (L - l) = 18 (L - l) / l

Therefore, the work done is given by:

W = 0.5 k (L² - l²) = 0.5 x 18 / l x (L² - l²) = 9 (L² - l²) / l

Hence, the work done to further stretch the spring from l m to L m is 9 (L² - l²) / l J.

Therefore, the work required to stretch the spring from l m to L m is given by the equation: W = 9 (L² - l²) / l.

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If the energy change of a reaction \(($\Delta E$)\) is positive, then it indicates that the reaction is endothermic, meaning it absorbs energy from its surroundings.

When the energy change of a reaction is positive \(($\Delta E > 0$)\), it implies that the products of the reaction have a higher energy level than the reactants. In an endothermic reaction, energy is absorbed from the surroundings to break the bonds in the reactant molecules, resulting in the formation of new bonds in the product molecules. This absorption of energy leads to an overall increase in the system's energy.

Endothermic reactions typically require an external source of energy to proceed, such as heat or light. Common examples of endothermic reactions include the process of photosynthesis in plants and the evaporation of liquid water. These reactions are characterized by a decrease in temperature as energy is absorbed from the surroundings.

In summary, if the energy change of a reaction \(($\Delta E$)\) is positive, it signifies an endothermic reaction where energy is absorbed from the surroundings. This results in the products having a higher energy level than the reactants, and the reaction usually requires an external source of energy to proceed.

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The Carnot engine is an idealized heat engine that operates between two temperature extremes, a heat source temperature (TH) and a heat sink temperature (TC). The heat source energy is 7500 = 5088.86 / (1 - (60 / TH)).

It follows the Carnot cycle, which consists of two isothermal and two adiabatic processes.

To find the heat source temperature (TH) of the Carnot engine, we need to use the given information.

First, let's convert the power output from horsepower (hp) to units of energy per unit time. We know that 1 horsepower is approximately equal to 2544.43 BTU/hr (British thermal units per hour). Therefore, 2 hp is equivalent to 5088.86 BTU/hr.

Next, we need to calculate the heat input (QH) to the Carnot engine. We can use the equation:

QH = Power Output / Efficiency

Since the Carnot engine is the most efficient heat engine, its efficiency (η) is given by the equation:

η = 1 - (TC / TH)

where TC is the temperature of the heat sink (60°F) and TH is the unknown heat source temperature.

Given that the power output is 5088.86 BTU/hr, we can substitute these values into the equation to solve for QH:

QH = 5088.86 / (1 - (60 / TH))

Now, we can calculate QH using the given information:

QH = 7500 BTU

Substituting this into the equation, we have:

7500 = 5088.86 / (1 - (60 / TH))

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Answer:

Okay I might be wrong and sorry if i am either its 12 or 0.402

Explanation:

* I recommend the second one cause its more logical

Be aware I might be wrong

Answer:

The truce ended all wars

Explanation:

The Olympic Truce or the sacred truce, is the declaration made by ambassadors for the laying down of arms and the stop of all hostilities starting from seven days before the  Olympic games began and ending seven days after the games to provide safe passage for travelling athletes and also spectators to and from the Olympic games

However, the  games were held during Persian wars and also during the Peloponnesian wars. As such the truce stopped mainly conflicts that have direct impact on the Olympic games and there was an attack in Olympia in 364 BC during the games.

Answer:

The truce ended all wars

Explanation:

Apex

Answer:

a' = 2a

Explanation:

The acceleration during this circular motion is the centripetal acceleration. Initially, the acceleration will be given as:

a = v²/r   --------------------- equation (1)

Where,

a = centripetal acceleration at outer edge

v = speed of merry go round = 5 m/s

r = distance from center of round to person (outer edge)

Now, when the person moves half way towards center. Then, the acceleration becomes:

a' = v²/r'

where,

r' = r/2

Therefore,

a' = v²/(r/2)

a' = 2v²/r

using equation (1):

a' = 2a

The probability that the item actually has a flaw given that it passed the first inspector is approximately 0.021, or 2.1%.

To calculate the probability that an item actually has a flaw given that it passed the first inspector, we need to use Bayes' theorem.

Let's define the events as follows:

A: The item has a flaw.

B: The item is passed by the first inspector.

We are given:

P(A) = 0.02 (probability that an item has a flaw)

P(B|A) = 1 (probability that the item is passed by the first inspector given that it has a flaw)

We want to calculate:

P(A|B) = ? (probability that the item has a flaw given that it is passed by the first inspector)

According to Bayes' theorem:

P(A|B) = (P(B|A) * P(A)) / P(B)

To calculate P(B), we need to consider both scenarios: the item has a flaw (A) and the item does not have a flaw (A').

P(B) = P(B|A) * P(A) + P(B|A') * P(A')

Given that P(B|A') is the probability that the item is passed by the first inspector given that it does not have a flaw, we can assume this probability to be high, such as 0.95. Therefore, P(B|A') = 0.95.

Using these values, we can calculate P(B) as follows:

P(B) = P(B|A) * P(A) + P(B|A') * P(A')

= 1 * 0.02 + 0.95 * (1 - 0.02)

= 0.02 + 0.95 * 0.98

= 0.02 + 0.931

= 0.951

We can calculate P(A|B) using Bayes' theorem:

P(A|B) = (P(B|A) * P(A)) / P(B)

= (1 * 0.02) / 0.951

= 0.02 / 0.951

≈ 0.021

Therefore, the probability that the item actually has a flaw given that it passed the first inspector is approximately 0.021, or 2.1%.

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