The motor in a hairdryer is attached to a 3V battery. A current of 0.8A flows through the motor for 3 minutes. Calculate the total charge in this time.

The power consumed across AB would be 4W.

A passive electrical component called a resistor prevents the flow of electric current by introducing resistance. They are prevalent in practically all electrical networks and electronic circuits. Ohms () are used to measure resistance. An ohm is the resistance that develops when a resistor has a one-volt (V) drop between its terminals and a one-ampere (A) current flows through it.

Five resistors in total are positioned at various points in the terminal AB in the preceding diagram. We must now determine the five resistors' equivalent resistance.

Let's split it into two sections. Two resistors make up the part below and three resistors make up the part above.

Now, we must determine the part's actual resistance.

Req=(r1r2/ r1+r2)×r3 * (r1r2/ r1+r2+r3)⇒Req=7×721∴Req=7/3

The obtained resistance is then parallel to the below traitor and in series with the neighboring resistor.

The net effective resistance will therefore be b,

Req=7/3+7=28/3\s⇒Reff=28/3×7/49/3∴Reff=4Ω

As a result, the power through terminal AB will be as follows:

P=1×4=4W.

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The frequency of light with a wavelength of 655 nm is\(4.57 x 10^14 Hz\) and 515 nm is \(5.82 x 10^14\) Hz and  475 nm is\(6.31 x 10^14 Hz\)

The equation that links the speed of light to wavelength and frequency is

c = λν

Where, c = speed of lightλ = wavelengthν = frequency c is a constant of 2.998 x 10^8 m/s.

Calculating the frequency of light with a wavelength of

655 nm:λ = 655 nm = \(6.55 x 10^-7m\)

Using the above equation, we get

c = λνν = c/λ = \((2.998 x 10^8 m/s)/(6.55 x 10^-7m)ν = 4.57 x 10^14 Hz\)

Therefore, the frequency of light with a wavelength of 655 nm is 4.57 x \(10^14 Hz.\)

Calculating the frequency of light with a wavelength of 515 nm:λ = 515 nm = \(5.15 x 10^-7m\)

Using the above equation, we get

c = λνν = c/λ =\((2.998 x 10^8 m/s)/(5.15 x 10^-7m)ν = 5.82 x 10^14 Hz\)

Therefore, the frequency of light with a wavelength of 515 nm is 5.82 x \(10^14 Hz\).

Calculating the frequency of light with a wavelength of 475 nm:λ = 475 nm = \(4.75 x 10^-7\)m Using the above equation, we get

c = λνν = c/λ = \((2.998 x 10^8 m/s)/(4.75 x 10^-7m)ν = 6.31 x 10^14 Hz\)

Therefore, the frequency of light with a wavelength of 475 nm is 6.31 x \(10^14 Hz.\)

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Answer:

The angle is  \(\theta =21.8 ^o\)

Explanation:

From the question we are told that

   The mass of the crate is  \(m_c = 20 \ kg\)

   The coefficient of static friction is  \(\mu_s = 0.40\)

   The  coefficient of kinetic friction is  \(\mu_k = 0.30\)

Generally  for the the crate not to slip , the static frictional  must be equal to the force driving the truck

   i.e

           \(F_f = F\)

Now since we are considering a slope that static frictional force is mathematically represented as

            \(F_f = mg * cos(\theta) * \mu_s\)

While the force driving the truck is mathematically represented as

          \(F = mg * sin (\theta )\)

Here  mg is the weight of the crate  so

         So

               \(mg * cos (\theta ) \mu_s = mg * sin (\theta )\)

=>             \(\frac{sin (\theta )}{cos (\theta)} = \mu_s\)

=>          \(\theta = tan ^{-1} [\mu_s ]\)

=>          \(\theta = tan ^{-1} [0.40 ]\)

=>          \(\theta =21.8 ^o\)

A diagram show an illustration is on the first uploaded image

Answer:

Do we have to choose out of those three?

Explanation:

The momentum of the baseball with a mass of 0.14 kg and velocity of 41.26 m/s is determined as 5.78 kgm/s.

The momentum of the baseball is calculated by applying the following formula as shown below;

P = mv

where;

The momentum of the baseball is calculated as follows;

mass of the baseball = 0.14 kg

velocity of the baseball = 41.26 m/s

momentum, P = mv

P = 0.14 kg  x  41.26 m/s

P = 5.78 kgm/s.

Thus, the momentum of the baseball with a mass of 0.14 kg and velocity of 41.26 m/s is determined as 5.78 kgm/s by applying the formula for linear momentum.

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The complete question is below:

Imagine a baseball pitcher and a batter. The baseball has a mass of 0.14 kg. The ball is pitched to the right with a velocity of 41.26 m/s. What is the momentum of the baseball?

To calculate the torque required to create an angular acceleration, we can use the formula:

Torque = Moment of Inertia × Angular Acceleration

The moment of inertia of a disk can be calculated using the formula:

Moment of Inertia = (1/2) × Mass × Radius^2

Given:

Mass = 15,000 kg

Radius = 6.14 m

Angular Acceleration = 0.0500 rad/s^2

First, calculate the moment of inertia:

Moment of Inertia = (1/2) × Mass × Radius^2

Moment of Inertia = (1/2) × 15,000 kg × (6.14 m)^2

Next, calculate the torque:

Torque = Moment of Inertia × Angular Acceleration

Torque = Moment of Inertia × 0.0500 rad/s^2

Now, let's plug in the values and calculate:

Moment of Inertia = (1/2) × 15,000 kg × (6.14 m)^2

Moment of Inertia ≈ 283,594.13 kg·m^2

Torque = 283,594.13 kg·m^2 × 0.0500 rad/s^2

Torque ≈ 14,179.71 N·m

Rounding to three significant figures, the torque required to create an angular acceleration of 0.0500 rad/s^2 is approximately 14,180 N·m.

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Answer:

C-How much matter is in an object

Explanation:

Answer:

If ur talking abkut hamstrings then it would be running that mimics them xplanation:

This was on a gym class quizz and I got it wrong but turned out this was the right answer

Answer:

In this activity, I exercised my hips, thighs, knees, calves, ankles, and legs. In some exercises, I specifically worked on only one type of muscle or on a combination of muscles. For example, the lunges mainly exercised the muscles of the inner thighs while the dead lift worked the muscles of the leg as well as the back and shoulders. I haven't consciously exercised my leg muscles before, but I have often noticed their tightening during my daily body movements, like when I climb the stairs or run to catch the school bus.

Explanation:

Hope this helped:)

Answer:

331.7m/s

Explanation:

Given parameters:

Initial velocity  = 100m/s

Acceleration  = 50m/s²

Distance  = 1km   = 1000m

Unknown:

Final velocity = ?

Solution:

To solve this problem, we have to apply the right motion equation shown below;

     v²  = u²  + 2aS

 v is the final velocity

 u is the initial velocity

 a is the acceleration

 S is the distance

 Now insert the parameters and solve;

     v² = 100² + (2 x 50 x 1000)

     v² = 110000

     v = √110000  = 331.7m/s

The time taken for the ball to reach its maximum height is 1 second.

To calculate the time taken for the ball to reach its maximum height, we can use the kinematic equation for vertical motion. The equation is:

v = u + at

Where:

v = final velocity

u = initial velocity

a = acceleration

t = time

In this case, the ball is thrown vertically upwards, so the initial velocity (u) is 10 m/s (considering upwards as positive) and the acceleration (a) is -10 m/s² (negative because it opposes the motion).

The final velocity (v) at the maximum height will be zero because the ball momentarily comes to a stop before reversing its direction. Therefore, we can rewrite the equation as:

0 = 10 - 10t

Simplifying the equation, we get:

10t = 10

Dividing both sides by 10, we find:

t = 1 second

Therefore, the time taken for the ball to reach its maximum height is 1 second.

During this time, the ball covers the distance required to reach the maximum height, overcoming the gravitational acceleration. After reaching the maximum height, it will start to descend towards the ground due to the gravitational pull.

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Answer:

The range of the photon energies is between:

2.652 x 10⁻²⁵ J    to    4.973 x 10⁻²⁵ J

Explanation:

The energy of a photon is calculated using the following equation;

E = hf

where;

h is Planck's constant = 6.63 x 10⁻³⁴ Js

f is frequency of the photon

\(E = h \frac{c}{\lambda} \\\\where;\\\\\lambda \ is \ the \ wavelength\\\\c \ is \ the \ speed \ of \ light \ = 3\times 10^8 \ m/s\\\\When \ \lambda = 400 \ mm = 400 \ \times 10^{-3} \ m\\\\E = \frac{(6.63 \times 10^{-34})(3\times 10^8)}{400 \times 10^{-3}} \\\\E = 4.973 \times 10^{-25} \ J\)

\(When \ \lambda = 750 \ mm = 750 \ \times 10^{-3} \ m\\\\E = \frac{(6.63 \times 10^{-34})(3\times 10^8)}{750 \times 10^{-3}} \\\\E = 2.652 \times 10^{-25} \ J\)

The range of the photon energies is between:

2.652 x 10⁻²⁵ J    to    4.973 x 10⁻²⁵ J

It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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Answer:

Salt water is more dense than freshwater

Explanation:

The only and best explanation for this phenomenon for this occurrence is that salt water is more dense than freshwater.

As a young person, can use social media platforms to promote respect for the different rights in the Bill of Rights by sharing information, starting conversations, and advocating for change.

Here are some ways you can use social media to promote respect for the different rights in the Bill of Rights:

Highlight Positive Examples: Use social media to highlight positive examples of individuals or organizations that are respecting the different rights in the Bill of Rights. Share stories of people who are fighting for justice and equality, and celebrate when positive change is made.

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a. It takes 13.94 seconds to change your displacement by 18.0m east.

b. It takes 28.9 seconds to change your displacement by 32.0m north,

In geometry and mechanics, a displacement is described as a vector whose length is the shortest distance from the initial to the final position of a point P undergoing motion.

To change your displacement by 18.0m east, we use the

X direction = \(\frac{18}{1.70 cos 22.7}\)

x direction = 13.94 seconds

To change your displacement by 32.0m north, we use the

Y direction = \(\frac{32}{1.70 sin 22.7}\)

y direction= 28.9 seconds

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Answer:

a protective and waxy or hard layer covering the epidermis of a plant, invertebrate, or shell.

Answer:

The cuticles for animals are a thin layer of clear dead skin around the nail bed on fingers and toes. As the nail grows, it naturally pushes and damages the underside of the skin around the base of the nails, called the eponychium. The space between the eponychium and the bottom of the nail is where the cuticle is located.  

The cuticle definition related to plants is a protective and waxy or hard layer covering the epidermis. The plant cuticle is an extracellular hydrophobic layer that covers the aerial epidermis.

Explanation:

1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point ,  the heat of fusion of the substance is 548 joules .

Heat of fusion, also known as enthalpy of fusion or latent heat of fusion, is the amount of energy required to melt or freeze a substance under constant pressure conditions. When it comes to chemistry, "fusion" is basically synonymous with "melting." In the classroom, heat of fusion is typically used when a substance is at its melting or freezing point. In such instances, most people consider heat of fusion to be a constant.

Water, for example, has a heat of fusion of 334 J/g at its melting point of 0°C. At 0°C, one grams  of liquid water requires 334 Joules of energy to completely freeze into ice. In addition, one grams of ice requires 334 Joules of energy to melt entirely.

q = m×∆Hf

q: Total change in heat energy (in Joules)

∆Hf: Heat of fusion of substance (in Joules per gram)

m: Mass of substance (in grams)

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The current drawn by a 125-ohm resistance on 220 volts is 1.76 A.

Current is the ratio of voltage and resistance

To calculate the current, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, The current drawn by a 125-ohm resistance on 220 volts is 1.76 A.

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Answer:

1.8 A

Explanation:

I got it right on the test.

Answer:

The temperature of silver at this given resistivity is 2971.1 ⁰C

Explanation:

The resistivity of silver is calculated as follows;

\(R_t = R_o[1 + \alpha(T-T_o)]\\\\\)

where;

Rt is the resistivity of silver at the given temperature

Ro is the resistivity of silver at room temperature

α is the temperature coefficient of resistance

To is the room temperature

T is the temperature at which the resistivity of silver will be two times the resistivity of iron at room temperature

\(R_t = R_o[1 + \alpha(T-T_o)]\\\\\R_t = 1.59*10^{-8}[1 + 0.0038(T-20)]\)

Resistivity of iron at room temperature = 9.71 x 10⁻⁸ ohm.m

When silver's resistivity becomes 2 times the resistivity of iron, we will have the following equations;

\(R_t,_{silver} = 2R_o,_{iron}\\\\1.59*10^{-8}[1 + 0.0038(T-20)] =(2 *9.71*10^{-8})\\\\\ \ (divide \ through \ by \ 1.59*10^{-8})\\\\1 + 0.0038(T-20) = 12.214\\\\1 + 0.0038T - 0.076 = 12.214\\\\0.0038T +0.924 = 12.214\\\\0.0038T = 12.214 - 0.924\\\\0.0038T = 11.29\\\\T = \frac{11.29}{0.0038} \\\\T = 2971.1 \ ^0C\)

Therefore, the temperature of silver at this given resistivity is 2971.1 ⁰C

Answer:

160 meters

Relative of speed Vr = 10 -2 = 8 m/s    (horizontal speed)

20 sec * 8 m/s = 160 m      since ball travels 20 sec

Answer:

160 meters

Explanation:

(a) The potential energy of the rock relative to the base of the cliff can be calculated using the formula for gravitational potential energy:

PE = mgh

where m is the mass of the rock (24.0 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the height of the cliff (80.0 m).

PE = 24.0 kg * 9.8 m/s^2 * 80.0 m = 15,360 J

(b) The kinetic energy of the rock just before it strikes the ground can be calculated using the formula for kinetic energy:

KE = 0.5 * m * v^2

where m is the mass of the rock (24.0 kg) and v is the velocity of the rock just before it strikes the ground. The velocity can be calculated using the equation of motion for a freely falling object:

v = sqrt(2gh)

v = sqrt(2 * 9.8 m/s^2 * 80.0 m) = 44.72 m/s

KE = 0.5 * 24.0 kg * 44.72 m/s^2 = 507.84 J

Radiations associated with electric and magnetic field is called Electromagnetic radiations.

electric and magnetic field radiations = electromagnetic radiations.

a}The work is done by the piston in the process is 199 cal.

b) The increase in internal energy of the gas is  703 cal

c) The heat was supplied to the gas is  3771 J

(a) To calculate the work done by the piston, we can use the formula:

Work = P * ΔV

Where P is the constant pressure and ΔV is the change in volume. Since the pressure is constant, the work done is given by:

Work = P * (\(V_2 - V_1\))

Since the amount of gas is constant (1 mole), we can use the ideal gas law to calculate the initial and final volumes:

PV = nRT

\(V_1 = (nRT_1) / P_1\)

\(V_2 = (nRT_2) / P_2\)

Here, n is the number of moles (1 mole), R is the gas constant (1.99 cal/mol·°C), T1 is the initial temperature (27 °C + 273 = 300 K), T2 is the final temperature (127 °C + 273 = 400 K), and P1 and P2 are the initial and final pressures, respectively (both 1 atm).

Substituting the values into the equation, we have:

V1 = (1 mol * 1.99 cal/mol·°C * 300 K) / (1 atm) ≈ 597 cal

V2 = (1 mol * 1.99 cal/mol·°C * 400 K) / (1 atm) ≈ 796 cal

Therefore, the work done by the piston is:

Work = 1 atm * (796 cal - 597 cal) = 199 cal

(b) The increase in internal energy of the gas can be calculated using the equation:

ΔU = n * C * ΔT

Where ΔU is the change in internal energy, n is the number of moles (1 mole), C is the molar heat capacity (7.03 cal/mol·°C), and ΔT is the change in temperature (127 °C - 27 °C = 100 °C).

Substituting the values into the equation, we have:

ΔU = 1 mol * 7.03 cal/mol·°C * 100 °C = 703 cal

(c) The heat supplied to the gas can be calculated using the equation:

Q = ΔU + Work

Substituting the values calculated in parts (a) and (b), we have:

Q = 703 cal + 199 cal = 902 cal

Since 1 cal = 4.184 J, the heat supplied to the gas is:

Q = 902 cal * 4.184 J/cal ≈ 3771 J

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The net work done per cycle for 1.00 mol of gas initially at 0°C is 4.88 kJ.

An isothermal process is a thermodynamic process in which the temperature of the system remains constant, while other state variables such as pressure and volume may change. An adiabatic process is a thermodynamic process in which there is no exchange of heat between the system and its surroundings, while other state variables such as pressure and volume may change.

a) The net work done by the gas per cycle is equal to the area enclosed by the cycle on the PV diagram. From the given figure, the cycle can be divided into two parts: the first part is an isothermal expansion from volume V0 to volume 5V0 and the second part is an adiabatic compression from volume 5V0 to volume V0.

For the isothermal expansion, the pressure decreases from P0 to P0/4. Using the equation for the work done during an isothermal process, the work done by the gas during this part of the cycle is:

W1 = nRT0 ln(5) = 4RT0 ln(5)

For the adiabatic compression, the pressure increases from P0/4 to P0. Using the equation for the work done during an adiabatic process, the work done by the gas during this part of the cycle is:

W2 = (P0V0^m/P0/4*(5V0)^m)^(1 - m)/1-m - (P0/4*(5V0)^m/P0/4)^(1 - m)/1-m = 4P0V0/3(1 - 1/5^(4/5))

The net work done by the gas per cycle is the sum of the work done in each part of the cycle:

W = W1 + W2 = 4RT0 ln(5) + 4P0V0/3(1 - 1/5^(4/5))

b) Since the cycle is closed, the net energy added to the system per cycle must be equal to the net work done by the gas per cycle:

Q = W = 4RT0 ln(5) + 4P0V0/3(1 - 1/5^(4/5))

c) To obtain a numerical value for the net work done per cycle for 1.00 mol of gas initially at 0°C, we need to substitute the appropriate values for R, T0, P0, V0, n, and m. Assuming the gas is an ideal gas, R = 8.314 J/mol K. At 0°C (273 K), the pressure of 1.00 mol of gas in a volume of V0 = 22.4 L (molar volume of ideal gas at STP) is P0 = 1 atm. Therefore,

W = 4(8.314 J/mol K)(273 K) ln(5) + 4(1 atm)(22.4 L)/3(1 - 1/5^(4/5))) = 4.88 kJ

Therefore, the net work done per cycle for 1.00 mol of gas initially at 0°C is 4.88 kJ.

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I think the puck pushes the stick backwards

Explanation:

Dark Energy. Dark Energy is a hypothetical form of energy that exerts a negative, repulsive pressure, behaving like the opposite of gravity. It has been hypothesised to account for the observational properties of distant type Ia supernovae, which show the universe going through an accelerated period of expansion

Answer:

Explanation:

Hydrostatic pressure due to a water column of height  h can be given by the following expression.

P = hρg

where ρ is density of water and g is acceleration due to gravity .

Substituting the values.

P = 380 x 1000 x 9.8

= 3.72 x 10⁶ Pa.

Answer:

\(F=\dfrac{3.72\times 10^6\ Pa}{A}\ N\)

Explanation:

Given that,

The density of water, d = 1000 kg/m³

Depth, h = 380 m

We need to find the force exerted on a thresher shark's eye by the hydrostatic pressure in ocean water. The force exerted by the hydrostatic pressure is given by :

\(P=\rho gh\)

Put all the values,

\(P=1000\times 9.8\times 380\\\\P=3.72\times 10^6\ Pa\)

Force exerted,

F = P/A

So,

\(F=\dfrac{3.72\times 10^6\ Pa}{A}\ N\)

Where

A is the area of crosss section

Hence, this is the required solution.