Kaitlyn can run 1.35 miles in 12 minutes. What is her running speed per hour?

AC is greater than the distance between A and C, then the triangle will be acute-angled, otherwise, it will be obtuse-angled. The two sides and a non-included angle, you can form two different triangles.

If you are given the measurements for two sides and an angle that is not between those sides, you can create two different triangles. This is because a triangle is uniquely determined by three pieces of information: either three sides, two sides and the included angle, or one side and two angles not containing that side.

Let's consider two sides of a triangle, AB and BC, and angle BAC not between AB and BC. We can form two different triangles by changing the length of the side AC.

If AC is greater than the distance between A and C, then the triangle will be acute-angled, otherwise, it will be obtuse-angled.

So, with two sides and a non-included angle, you can form two different triangles.

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Considering the given functions, we have that:

a. The expense function in terms of p is: E = -720p + 20,400.

b. At a price of $15, the demand is of 7200.

c. The cost to produce the 7200 widgets is of $58,200.

The demand function is given as follows:

q = -120p + 9000.

The expense function is:

E = 6q + 15,000.

In terms of p, the expense function is given as follows:

E = 6(-120p + 900) + 15,000

E = -720p + 20,400.

At a price of $15, the demand is calculated as follows:

q = -120 x 15 + 9000 = 7200.

The cost to produce the 7200 widgets is calculated as follows:

E = 6(7200) + 15,000 = $58,200.

Both numeric values were found replacing the single instance of the variable by the inputs.

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Answer

x = 2

x = 3

x = 1

x = 4

have a good day :)

Answer:

2 2/3 hrs

Step-by-step explanation:

Rearrange the equation d = rt to solve for t. t = d/r. D represents distance, r represents rate, and t represents time. You need to divide 2000/750 to get 2.66667 hrs. Round that to 2 and 2/3 hrs.

Answer:

it 2 parts away

Step-by-step explanation:

Answer:

(0,0)  (20, 10)  (40,10)   (60,40)  (100,0)

 A          B           C            D           E

Step-by-step explanation:

Answer:

40 degreses

Step-by-step explanation:

there is a right angle and that means it is 90 degreese then it gives you 50 degreese so you add them up and get 140 then you subtract that 140 from 180 and get 40 degreese.

Answer:

c

Step-by-step explanation:

cause it is

The function f(x) = 0.45x + 12.50 models the situation where a bank charges $.45 for each check written plus a service charge of $12.50. The "x" represents the number of checks written during the month.

The function that models this situation can be written as:

f(x) = 0.45x + 12.50

In this function, "x" represents the number of checks written during the month. The term "0.45x" represents the monthly charge for maintaining the account based on the number of checks written (0.45 for each check). The term "12.50" represents the service charge.

To calculate the total monthly charge, you would substitute the value of "x" into the function. For example, if you wrote 10 checks during the month, the total monthly charge would be:

f(10) = 0.45(10) + 12.50
      = 4.50 + 12.50
      = $17.00

In conclusion, the function f(x) = 0.45x + 12.50 models the situation where a bank charges $.45 for each check written plus a service charge of $12.50. The "x" represents the number of checks written during the month.

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Answer:

Online Real Estate Investment Opportunities

Hiring a Property Management Company

Make Sure There's Enough Money Available

Calculate Your Expenses

You Should Earn roughly 10% After Costs and Income are Calculated

Step-by-step explanation:

hope it helps

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We are given the following function:

The graph of this equation is a parabola for values of x < 2 and a line for values of 2<= x <= 6. The graph is the following:

\(\bold{Heya...}\)

3x + y = 11.

Let's solve for x ~

3x + y = 11

Step 1: Add -y to both sides.

\(\mathtt{3x \: + \: y \: + \: -y \: = \: 11 \: + \: -y}\)

\(\mathtt{3x \: = \: -y \: + \: 11}\)

Step 2: Divide both sides by 3.

\(\mathtt{\frac{3x}{3} \: = \: \frac{-y \: + \: 11}{3}}\)

↓ \(\underline{A \: n \: s \: w \: e \: r :}\) ↓

\(\bold{x \: = \: \frac{-1}{3}y \: + \: \frac{11}{3}}\)

Let's solve for x ~

5x - y = 21.

Step 1: Add y to both sides.

\(\mathtt{5x \: - \: y \: + \: y \: = \: 21 \: + \: y}\)

\(\mathtt{5x \: = \: y \: + \: 21}\)

Step 2: Divide both sides of 5.

\(\mathtt{\frac{5x}{5} \: = \: \frac{y \: + \: 21}{5}}\)

↓ \(\underline{A \: n \: s \: w \: e \: r :}\) ↓

\(\bold{x \: = \: \frac{1}{5}y \: + \: \frac{21}{5}}\)

Hope It Helps U...

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\(\huge{\bold{\red{\star{\pink{ItzSehzadi}}}}\)

It is False that based only on the r and p values listed above you can come to the conclusion that age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.

In the given scenario, it is not completely true that based only on the r and p values listed above, you can come to the conclusion that age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.

Let's first understand what is meant by the term "moderator.

"Moderator: A moderator variable is a variable that changes the strength of a connection between two variables. If there is a statistically significant bivariate relationship between the amount of texting during driving and the number of accidents, scientists investigate whether this bivariate relationship is moderated by age.

Therefore, based on the values of r and p, it is difficult to determine if age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.

As we have to analyze other factors also to determine whether the age is a moderator or not, such as the sample size, the effect size, and other aspects to draw a meaningful conclusion.

So, it is False that based only on the r and p values listed above you can come to the conclusion that age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.

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Queremos ver que fracción de la finca se ha destinado a plazas de aparcamiento.

La solución es:

La fracción de la finca que se destina a plaas de aparcamiento es 3/56

Sabemos que originalmente se iba a destinar 3/14 del total de la finca a plazas de aparcamiento, pero finalmente se destino 3/4 de lo previsto a zonas ajardinadas.

Es decir, se destino 3/4 de los 3/14 del total de la finca a zonas ajardinadas, entonces el 1/4 restante se dedico a plazas de aparcamiento, esto da:

(1/4)*3/14  = 3/56

La fracción de la finca que se destina a plaas de aparcamiento es 3/56

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A $450 principal and a simple interest rate of 0.35% each quarter for 212 years would result in a savings account balance of $3768.

We can use the formula for simple interest to solve this problem:

Simple Interest = Principal x Rate x Time

where Rate is the interest rate as a decimal, and Time is the time in years.

The quarterly interest rate is 0.35% / 4 = 0.00875, and the time is 212 years, or 848 quarters.

Plugging in these values, we get:

Simple Interest = $450 x 0.00875 x 848 = $3318

Therefore, the balance of the savings account after 212 years would be:

Balance = Principal + Simple Interest = $450 + $3318 = $3768

Therefore, the balance of the savings account after 212 years with a simple interest rate of 0.35% each quarter and a principal of $450 would be $3768.

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Partial fraction decomposition and specific integration techniques are required.

To integrate the given expression, we need to break it down into simpler terms and then apply integration rules.

Let's start by simplifying the expression:

\(∫[4(2x + 5)] / [(3x^2 + 1)(x + 2) + 6x + 4x^5 - 3x^4 - 6x^3] dx\)

First, we can distribute 4 to (2x + 5) to get:

\(∫[8x + 20] / [(3x^2 + 1)(x + 2) + 6x + 4x^5 - 3x^4 - 6x^3] dx\)

Next, we can simplify the denominator:

\(∫[8x + 20] / [4x^5 - 3x^4 - 6x^3 + 3x^2 + 8x + 2] dx\)

Now, we can factor out common terms from the denominator:

\(∫[8x + 20] / [x^2(4x^3 - 3x^2 - 6x + 3) + 2(4x^3 - 3x^2 - 6x + 3)] dx\)

Notice that (4x^3 - 3x^2 - 6x + 3) appears in both terms. We can factor it out:

\(∫[8x + 20] / [(x^2 + 2)(4x^3 - 3x^2 - 6x + 3)]dx\)

Now, we have two separate fractions:

\(∫[8x] / [(x^2 + 2)(4x^3 - 3x^2 - 6x + 3)] dx + ∫[20] / [(x^2 + 2)(4x^3 - 3x^2 - 6x + 3)] dx\)

To solve these integrals, we need to apply partial fraction decomposition and use integration techniques specific to each term. However, due to the limited response length, it's not possible to provide a complete step-by-step solution in 100 words. I recommend consulting a math textbook or using an online integral calculator to obtain the detailed solution.

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The probability that each child develops Tay-Sachs disease is 0.25. Since the outcomes of the six pregnancies are mutually independent, we can multiply the probabilities to find the probability that all six children develop the disease. 0.25^6 = (1/4)^6 = 0.00390625

(b) The probability that only one child develops Tay-Sachs disease is 6 * (0.25)^1 * (0.75)^5 = 0.140625.

There are six possible ways for one child to develop Tay-Sachs disease and the other five children to not develop the disease. We can find the probability of each way and then add them up.

The probability that one child develops Tay-Sachs disease is 0.25. The probability that the other five children do not develop Tay-Sachs disease is 0.75.

The probability that one child develops Tay-Sachs disease and the other five children do not develop the disease is 6 * (0.25)^1 * (0.75)^5 = 0.140625

(c) The probability that the third child develops Tay-Sachs disease, given that the first two did not, is 0.25.

The fact that the first two children did not develop Tay-Sachs disease does not affect the probability that the third child will develop the disease. The probability that the third child develops Tay-Sachs disease is still 0.25.

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:According to the question:You are working with a population of crickets. Before the mating season you check to make sure that the population is in Hardy-Weinberg equilibrium, and you find that the population is in equilibrium.

During the mating season you observe that individuals in the population will only mate with others of the same genotype (for example Dd individuals will only mate with Dd individuals). There are only two alleles at this locus ( D is dominant, d is recessive), and you have determined the frequency of the D allele =0.6 in this population. Selection acts against homozygous dominant individuals and their survivorship per generation is 80%. After one generation the frequency of DD individuals will decrease in the population.

According to the Hardy-Weinberg equilibrium equation p² + 2pq + q² = 1, the frequency of D (p) and d (q) alleles are:p + q = 1Thus, the frequency of q is 0.4. Here are the calculations for the Hardy-Weinberg equilibrium:p² + 2pq + q² = 1(0.6)² + 2(0.6)(0.4) + (0.4)² = 1After simplifying, it becomes:0.36 + 0.48 + 0.16 = 1This means that the population is in Hardy-Weinberg equilibrium. This is confirmed as the frequencies of DD, Dd, and dd genotypes

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Answer:

1. 98.7 km

2. 303.5 degree

Step-by-step explanation:

Using the alternate angle, the angle at B will be 50 + 10 = 60 degree.

To calculate the length AC of the returning journey, use cosine formula to calculate it.

To find the bearing of the returning journey, use sine rule to calculate it.

Please find the attached file for the solution

Answer: -24x^2+28x

Step-by-step explanation: -4x*6x-(-4x)*7 to -24x^2+28x

Answer: 817.9

Step-by-step explanation:

area of sector : 150/360 x 3.14 (pi) x (27.8)^2 = 1011.1323

area of circle: 1/2 x 27.8^2 x sin150 = 193.21

subtract area of sector from area of circle to get area of shaded region :)

Answer:

The percentage increase is 78.72%

Step-by-step explanation:

Here, we want to calculate a percentage increase

We proceed to use the mathematical relation as follows;

Percentage increase = (new value - old value)/old value * 100%

new value is value in 2011 = 252

old value is value in 2006 = 141

Substituting these values, we have;

(252-141)/141 * 100%

= 111/141 * 100%

= 78.72%

It depends on the sign of \(x-4\).

Recall the absolute value function's definition:

\(|x| = \begin{cases}x & \text{if } x \ge 0 \\ -x & \text{if } x < 0\end{cases}\)

Now, if \(x-4\ge0\), then

\((x-4)|x-4| = (x-4)(x-4) = x^2 - 8x + 16\)

On the other hand, if \(x-4<0\), then

\((x-4)|x-4| = -(x-4)(x-4) = -(x-4)^2 = -x^2 + 8x - 16\)

What you first suggested is incorrect. We have

\(x^2 - 16 = (x - 4) (x + 4)\)

but \(|x-4| \neq x + 4\).

We can show this using the definition again. If \(x-4\ge0\), then

\(x-4 = x+4 \implies -4=4\)

which is a contradiction; on the other hand, if \(x-4<0\), then

\(-x+4 = x+4 \implies 2x = 0 \implies x =0\)

holds for only one value of \(x\).

Answer: 1.8 L/h

Step-by-step explanation:

To convert the rate of water dripping from a tap from millilitres per second (ml/sec) to litres per hour (L/h), we need to use conversion factors.

Step 1:

First, let's convert the rate from millilitres per second to litres per second.

There are 1000 millilitres in a litre, so we can divide the rate in millilitres per second by 1000 to get the rate in litres per second:

\(\LARGE \boxed{\textsf{0.5 ml/sec $\div$ 1000 = 0.0005 L/sec}}\)

Step 2:

We can convert the rate from litres per second to litres per hour. There are 3600 seconds in an hour, so we can multiply the rate in litres per second by 3600 to get the rate in litres per hour:

\(\LARGE \boxed{\textsf{0.0005 L/sec $\times$ 3600 = 1.8 L/h}}\)

Therefore, the rate of water dripping from the tap is 1.8 L/h.

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Answer:

4x+12 ≤ 0 or 4x+1>3

4x ≤ -12 or 4x+1 > 3

x ≤-3 or x >1/2

Answer:

it will option D 100degree bcz of corresponding angle property

It's 100° for me on Ap3x..

Answer:

A≈804.25m²

Step-by-step explanation:

A=πr2=π·162≈804.24772m²

You can easily find the percentage of dogs that are walked at least 1.5 hours but under 4.2 hours per week by counting the number of data values in the appropriate class and dividing by the total number of data values, then multiplying by 100.

Determine the range of the data: 0.6 to 4.7.

Divide the range by the number of classes (5) to find the class width: (4.7 - 0.6) / 5 = 0.76.

Determine the lower limits of each class by starting at the minimum value (0.6) and adding the class width repeatedly: 0.6, 1.36, 2.12, 2.88, 3.64, 4.4.

Count the number of data values that fall into each class and record it in a table.

Draw a bar for each class using the lower limit of the class as the x-axis value and the height of the bar equal to the number of data values in the class.

After creating the histogram, you can easily find the percentage of dogs that are walked at least 1.5 hours but under 4.2 hours per week by counting the number of data values in the appropriate class and dividing by the total number of data values, then multiplying by 100.

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Therefore , the solution of the given problem of surface area comes out to be 160 peoples can be fit in that region.

Its surface area is a good indicator of how much space it takes up overall. When estimating the surface area of a three-dimensional shape, the entire environment is taken into consideration. Its surface area determines how big something is overall. The sum of the faces on any and all six of a cuboid's rectangular sides yields the amount of water contained within.

Here,

Given : one person occupies 360 square inches

is 2.5 square foot.

So,

The given dimension of region are :

length = 20 feet and width 20 feet.

Thus,

=> Area = 20*20

=> Area = 400 square foot.

So , number of people in that area will be :

=> 400/2.5

=> 160 peoples.

Therefore , the solution of the given problem of surface area comes out to be 160 peoples can be fit in that region.

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