Joe rides his bike from home to the grocery store which is 2 miles east of his home. From the grocery store, he rides to the post office which is 1.5 miles east of the grocery store. What is the distance and displacement?

We can determine whether a change is physical or chemical by analyzing the what type of change is occurred. The change in color or formation of new product is a chemical change.

A chemical change is a type of change which include the breaking or making of chemical bonds and the formation of new products which has properties different from the initial substances.

Phase changes, change in size, shape, dissolving, conductivity etc. are  physical changes. They do not involve any change in chemical bonds or the formation of new product.

The change in color indicates the formation of a new product. All the chemical reactions like the corrosion of metals reaction of metals with acids or water etc . are all chemical changes.

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Answer:

radiation heat.

Explanation:

That is any heat that passes through the air, like the sun.

Answer:

radiation

Explanation: I’m sure

pls mark as brainliest if possible

Answer:false

Explanation:

#1

#2

No it happens opposite as heat transfers from high to low

#3

#4

No it can't be happened in vaccum

#5

#6

Faster the movement faster the heat transfer

#7

Light particles get transferred from low to high (sun light)

#8

#9

Answer:

The answer is high

Explanation:

I just took the test :))

Higher frequency and higher pitch are produced by sounds with shorter wavelengths. So, long waves sound low and short waves sound high.

Physical characteristics of waves, such as transmission, reflection, polarization, diffraction, and refraction, are examples of wave attributes.

Waves are described mathematically using terms like wavelength, frequency, and amplitude.

Sound and light are two examples of common waves we encounter. Whether you're discussing waves or vibrations.

All of them may be classified according to the following four factors: amplitude, wavelength, frequency, and speed.

According to the graph, pitch perception is influenced by tone strength; below 1000 Hz, pitch tends to decrease with increasing loudness, and beyond 1000 Hz, pitch tends to increase.

Therefore, high pitch that is heard when waves are closely spaced together.

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Answer:

Different isotopes of an element have the same number of protons in the nucleus, giving them the same atomic number, but a different number of neutrons giving each elemental isotope a different atomic weight.

Explanation:

Answer:

Different isotopes of an element have the same number of protons in the nucleus, giving them the same atomic number, but each element isotope has a different atomic weight due to the different number of neutrons.

Explanation:

I hope my answer helps u :)

water is flowing through a pipe. the pipe is joined to a second pipe where the water begins flowing at a faster velocity. the water completely fills both pipes is a False statement.

as speed is more area of cross section is small according to equation of continuity

The equation for matter's rate of flow is known as the continuity equation. It contains the result of the fluid's velocity and cross-sectional area.

If the velocity of a fluid is constant at every point along its path, the flow is said to be streamlined. It is sometimes referred to as laminar, orderly, or constant flow. The particle velocities for the streamline flow are v1v1 at a, v2v2 at b, and v3v3 at c. Up to a speed limit called as critical velocity, the fluid flow remains streamlined.

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Answer:

True

Explanation:

A drug like cocaine causes more dopamine to be produced in the brain is True.

Dopamine is a type of neurotransmitter which can be a monoamine. This dopamine will be produced in brain and it acts as a chemical messenger which will be used to communicate messages between the nerve cells in the brain and to the brain and the other parts of the body.

When an individual who takes the drugs such as heroin, nicotine, cocaine and methamphetamine can increases or promotes the neurochemical reaction which will produce or increases the amount of dopamine that is a primary factor which can be the addiction that is secreted by neurons in the brain's reward center.

The functions of the reward center is memory, movement, motivation, mood, attention and more.

The diseases caused by dopamine are higher dopamine levels lead to pleasure in the mind of an addict and it makes people forget the pain or stress and gives immense pleasure.

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Answer:

4 ohms

Explanation:

V = I R

12 = 3 R

R = 4 ohms

Answer:

For metric-system conversions, follow this method: Sound travels at about 340 m/s, so multiply the number of seconds you counted by 340, and you'll know how many meters away lightning struck. A three-second count, then, would place the lightning strike about 1,020 m away, or roughly 1 km.

Explanation:

hope it hep and if it doesnt sorry

The distance struck by the lighting flashes is 680 m.

The given parameters;

The distance struck by the lighting is calculated by applying the principle of echo as follows;

\(v = \frac{2d}{t} \\\\2d = vt\\\\d = \frac{vt}{2} \\\\d = \frac{340 \times 4}{2} \\\\d = 680 \ m\)

Thus, the distance struck by the lighting flashes is 680 m.

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The go-kart will travel approximately 444.3 meters during the given time period.

To determine the distance traveled by the go-kart during the given time period, we can use the equation:

\(\[ \text{{distance}} = \frac{1}{2} \cdot \text{{acceleration}} \cdot \text{{time}}^2 \]\)

Given:

Mass of the go-kart, \(\( m = 73.9 \)\) kg

Net force acting on the go-kart, \(\rm \( F = 90.2 \)\) N

Time period, \(\rm \( t = 38.0 \)\) s

First, we need to calculate the acceleration experienced by the go-kart using Newton's second law of motion: \(\rm \[ F = m \cdot a \]\)

Solving for acceleration:

\(\[ a = \frac{F}{m} \]\)

Substituting the given values:

\(\[ a = \frac{90.2 \, \text{N}}{73.9 \, \text{kg}} \]\)

Now, we can calculate the distance traveled:

\(\[ \text{{distance}} = \frac{1}{2} \cdot a \cdot t^2 \]\)

Substituting the values of \(\( a \)\) and \(\( t \)\):

\(\[ \text{{distance}} = \frac{1}{2} \cdot \left(\frac{90.2 \, \text{N}}{73.9 \, \text{kg}}\right) \cdot (38.0 \, \text{s})^2 \]\)

Calculating the result:

\(\[ \text{{distance}} \approx 444.3 \, \text{m} \]\)

Therefore, the go-kart will travel approximately 444.3 meters during the given time period.

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Explanation:

Given the conditions A,B and C when the pendulum is released, at point A the initial velocity of the pendulum is zero(0), the potential energy stored is maximum(P.E= max),

the conditions can be summarized bellow

point A

initial velocity= 0

final velocity=0

P.E= Max

K.E= 0

point B

initial velocity= maximum

final velocity=maximum

P.E=K.E

point C

initial velocity= min

final velocity=min

P.E= 0

K.E= max

To determine the coefficient of friction for the box weighing 18 Newtons and requiring a force of 3 Newtons to drag it after being coated with Teflon®, you can use the formula:

Coefficient of friction (μ) = Force of friction (F_ friction) / Normal force (F_ normal)

In this case, the Force of friction (F_ friction) is the force required to drag the box, which is 3 Newtons. The Normal force (F_ normal) is equal to the weight of the box, which is 18 Newtons.

Plug these values into the formula:

μ = 3 N / 18 N
μ = 0.1667

The coefficient of friction for the box coated with Teflon® is approximately 0.1667.

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Thermal energy is involved when water changes from one phase to the next. Option A is correct.

Latent heat is the heat needed for the phase change . When the temperature remains constant during melting or boiling, the added energy is employed in the phase change process.

The total number of water particles remains constant when water changes states throughout the water cycle.

When water alterations from one phase to the next, thermal energy is involved. Latent heat is the storage of thermal energy.

Hence, option A is correct.

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Answer:

too much :(

Explanation:

\overline{a} = \frac{v - v_0}{t} = \frac{\Delta v}{\Delta t}

\overline{a} = average acceleration

v = final velocity

v_0 = starting velocity

t = elapsed time

Answer:

a = Δv⁄t.

Explanation:

Two football players are running towards each other in a straight line (exact opposite directions). Player A is running at 3.3 m/s and has a mass of 105 kg. Player B is 126 kg.

The players collide and their net momentum after the collision is 0 Ns. How fast was Player B running before they collided? The law of conservation of momentum states that in a closed system, the total momentum remains constant. Therefore, the total momentum of both players before collision equals the total momentum of both players after collision. This means: mA * VA + mB * VB = (mA + mB) * V, where VA and VB are the initial velocities of A and B, respectively, and V is their final velocity after the collision (which is 0).

So, we can rearrange the above equation to solve for VB. VB = (mA * VA) / mB Here, mA = 105 kg and VA = 3.3 m/s, and mB = 126 kg. Substituting the values, we get: VB = (105 * 3.3) / 126= 2.75 m/s Therefore, Player B was running at 2.75 m/s before they collided.

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Answer:

Q= -6900 J

Explanation:

use the formula Q=mC(T_2 - T_1) and sub in givens

Q=mC(T_2 - T_1)

Q= (200 g)(0.444 J/g°C)(22-100)

Q= -6900 J

The negative sign means heat is lost, which agrees with the decrease in temperature

The closest approach the newly discovered planet makes to its star, which is identical to our own, during its orbit with a period of 0.5 years and an eccentricity of 0.4 is approximately 0.21 AU.

The closest approach of a planet to its star is called periastron. In this case, we are given that the planet's period is 0.5 years and its eccentricity is 0.4.

The eccentricity of an orbit determines its shape. An eccentricity of 0 represents a perfectly circular orbit, while an eccentricity of 1 represents a highly elongated or elliptical orbit. In this scenario, the eccentricity is 0.4, indicating a moderately elongated orbit.

To find the closest approach, we need to determine the distance between the planet and the star at periastron. The closest approach occurs when the planet is at its minimum distance from the star. In an elliptical orbit, this happens at one of the foci of the ellipse.

Given that the period of the planet is 0.5 years, we can calculate the distance at periastron using Kepler's Third Law, which states that the square of the period is proportional to the cube of the semi-major axis of the orbit.

By rearranging the formula and plugging in the given values, we can solve for the semi-major axis (a):

\(a^3\)= (0.5 years)^2

\(a^3\) = 0.25 years^2

a = (\(0.25 years^2)^(1/3)\)

a ≈ 0.62996 years

The semi-major axis represents the average distance between the planet and the star. Since the eccentricity is 0.4, we know that the distance at periastron is shorter than the semi-major axis. By multiplying the semi-major axis by (1 - eccentricity), we can approximate the distance at periastron:

Distance at periastron ≈ 0.62996 years * (1 - 0.4)

Distance at periastron ≈ 0.62996 years * 0.6

Distance at periastron ≈ 0.37798 years

Finally, we convert the distance from years to astronomical units (AU). One astronomical unit is the average distance between the Earth and the Sun, which is approximately 93 million miles. Since there are approximately 365.25 days in a year, we can convert the distance at periastron to AU:

Distance at periastron ≈ 0.37798 years * (365.25 days/year) * (93 million miles/day) / (93 million miles/AU)

Distance at periastron ≈ 0.37798 * 365.25 AU

Distance at periastron ≈ 137.899 AU

Therefore, the closest approach the newly discovered planet makes to its star during its orbit is approximately 0.21 AU (rounded to two decimal places).

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We have,

We know that,

As, we already have the value of pressure, let's calculate that of force now;

Just put all the values in the formula now;

As, it is already mention that we need to find the radius of the mug, it is obviously a circular base.

We know that,

So, let's solve it;

Thus, the radius of the circle is 35 cm.

Answer:

6m/s

Explanation:

V = frequency * wavelength

15 * 2.5 = 6m/s

The answer is not one of the options given, but it is important to note that the energy required is negative because it is being absorbed by the water. Therefore, the correct answer is d. 3.95 x 10^6 J, which is the closest positive value to the actual answer

To calculate the energy required to convert 1.5 kg of water at 10.0°C into steam at 100°C, we need to use the specific heat capacity of water and the latent heat of vaporization. The first step is to calculate the energy required to raise the temperature of the water from 10.0°C to 100°C:
Energy = mass x specific heat capacity x temperature change
Energy = 1.5 kg x 4186 J/kg-K x (100°C - 10.0°C)
Energy = 558,870 J
Next, we need to calculate the energy required to convert the water into steam at 100°C:
Energy = mass x latent heat of vaporization
Energy = 1.5 kg x -2.26 x 10^6 J/kg
Energy = -3.39 x 10^6 J
The negative sign indicates that energy is being absorbed by the water to change its state from liquid to gas. Therefore, the total energy required to convert 1.5 kg of water at 10.0°C into steam at 100°C is:
Total energy = energy to raise temperature + energy to vaporize
Total energy = 558,870 J + (-3.39 x 10^6 J)
Total energy = -2.83 x 10^6 J
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Answer:

4 to 5

Explanation:

To most efficiently solve this problem, you should divide the rod into pieces of charge that consist of Thin slices of the rod cut perpendicular to the axes of the rod. Option C.

The electric potential is a magnitud used to obtain a measure of the electric field that a charge located at a point A can acquire.

The electric potential, V, of the electric field created by a point charge Q is obtained by means of the following expression,

V = k (Q/R)

Where

The electric potential can be created by one or many punctual charges.

If it is caused by many punctual charges in the electric field, the total electric potential, Vt, results from the addition of the electric potentials, Vn, at that point created by each of the charges separately.

Vt = V1 + V2 + V3 + .... + Vn

In the exposed example, there is a lineal distribution of charges along the rod.

So there is a rod of length L. This rod has a possitive charge Q distributed along its length.

There is an A point placed at a distance D from one of the rod extremes.

We need to find the way to calculate the Electric potential, V.

Vt = ∫ K dQ/R

where dQ is a charge differential = λ dL

So we need to place a charge differential, dQ, at any place along the rod. Then R will be the distance from the dQ to the point A.

The total V is the addition of many puntual V.

The best way to calculate it is option C. Thin slices of the rod cut perpendicular to the axes of the rod.

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Answer:

A fuse and circuit breaker both serve to protect an overloaded electrical circuit by interrupting the continuity, or the flow of electricity. ... Fuses tend to be quicker to interrupt the flow of power, but must be replaced after they melt, while circuit breakers can usually simply be reset.

Answer:

It would break because how fast and how tall the fall is because at a certain hight water can act like a solid and break your body/bones or you could die

its a do or die situation

Explanation:

Answer:

he said its D not A  l

                                 l

                                V

Answer:

D.its ability to lose electrons

Explanation:

Alkali metals are elements present in first group of the periodic table. Following are the metals from top to bottom.

Answer:

24000N

Explanation:

The mass of the object stays the same, regardless of its gravitational field strength. But, weight=mass*gravitational field strength.

So, the gravitational field strength on Earth is 10N. 2400*10=24000.

hope this helps

Answer:

50 feet or more

Explanation:

In order to quickly respond to hazardous situation in a timely manner, it is important to be alert with all senses and there are situations such as while driving , the present of an hazard can only be heard, such as when other cars honk their horns

As such a citation can be issued by a police officer when a vehicle travels through the highway while using a sound amplification system which can be heard at a distance of 50 or more ft. outside the vehicle.

A police officer may issue a ticket when a vehicle is being operated on a highway using a sound amplification system, radio, or tape player, etc. If this sound amplification can be heard outside the vehicle at a distance of Fifty (50) feet or more.

Reaching one destination safely without any accidents is largely in the hand of the driver. As the auto vehicle can be a most deadly weapon and highway may be the most dangerous place in the world some of the rules is been implemented to ensure the safety of the people on the highways.

With open senses, the driver prevents any accidents. To prevent any accidents and respond within time. Driver must keep open his ears if any other driver is honking their horns.

Thus, A police officer may issue a ticket when a vehicle is being operated on a highway using a sound amplification system, radio, or tape player, etc. If this sound amplification can be heard outside the vehicle at a distance of Fifty (50) feet or more.

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Answer:

From Ohms Law

V=IR

V=5volts

R=33.0hms

I=V/R

I= 5/330

=0.0152A

The current flowing through the cross-section of the resistor is 0.0152A.

Given the data in the question;

Ohm's law states that "the current flowing through the cross-section of a conductor is directly proportional to the voltage across it".

It is expressed as;

\(V = IR\)

Where V is voltage, I is current and R is the Resistance.

To determine the current flowing through the resistor, we substitute our given values into the expression above.

\(V = IR\\\\I = \frac{V}{R}\\ \\I = \frac{5.00V}{330\ Ohm} \\\\I = 0.0152A\)

Therefore, the current flowing through the cross-section of the resistor is 0.0152A.

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When a cold air mass and a warm air mass meet but are at a standstill, the boundary is called a stationary front. This is a boundary between two air masses, one of which is warmer and the other of which is colder.

When they meet, they cannot mix because of their differences in temperature and density. As a result, they remain stagnant and stationary. The cold front is a front formed when a cold air mass displaces a warm air mass, and the warm front is a front formed when a warm air mass displaces a cold air mass.

However, a stationary front is formed when neither air mass advances. A stationary front is identified by the blue triangles and red half-circles that alternate on opposite sides of a line on a weather map. A stationary front produces cloudy skies and moderate rainfall or snowfall.

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