The density of a pillow is greater than the density of a rock. Is this true of false

The identity of the gas sample that weighs 4.84g and occupies a volume of 0.918L at 35 °C and 850torr is CHCl₃ with molar mass of 119.4g/mol (option A).

The number of moles of an ideal gas can be calculated using the ideal gas law equation as follows:

PV = nRT

Where;

According to this question, a sample of gas weighs 4.84g and occupies a volume of 0.918L at 35 °c and 850 torr. The number of moles can be calculated as follows:

1.12 × 0.918 = n × 0.0821 × 308

1.028 = 25.286n

n = 0.041moles

molar mass of gas = 4.84g ÷ 0.041moles

molar mass = 119.4g/mol

Therefore, the identity of the gas is CHCl₃.

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Answer:

Due to the accumulation of static charges/due to static electricity

The entropy change for the system when 1.73 moles of CO₂ react at standard conditions is -617.5 J/K.

The entropy change for the given reaction can be calculated using the formula ΔS° = ΣnS°(products) - ΣmS°(reactants), where n and m are the stoichiometric coefficients and S° is the standard absolute entropy.

The balanced equation shows that 2 moles of CO₂ react with 5 moles of H₂ to produce 1 mole of C₂H₂ and 4 moles of H₂O. Therefore, the entropy change for the system can be calculated as follows:

ΔS° = (1 mol C₂H₂ x S°(C₂H₂)) + (4 mol H₂O x S°(H₂O)) - (1.73 mol CO₂ x S°(CO₂)) - (5 x 1.73 mol H₂ x S°(H₂))

ΔS° = (1 mol x 200.9 J/K/mol) + (4 mol x 188.7 J/K/mol) - (1.73 mol x 213.6 J/K/mol) - (5 x 1.73 mol x 130.7 J/K/mol)

ΔS° = -617.5 J/K

Therefore, the entropy change for the system when 1.73 moles of CO₂ react at standard conditions is -617.5 J/K. This indicates that the reaction leads to a decrease in the randomness or disorder of the system.

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The original concentration of HNO3 is 0.11 M.

The equivalence point is the point in the titration process where the amount of reactant in one solution is chemically equivalent to the amount of reactant in the other solution.

In acid-base titrations, the equivalence point is the point at which the acid and the base are neutralized and the pH is equal to 7.0 (neutral).The given question is related to titration.

To find the original concentration of HNO3, we need to know the volume of NaOH solution added to the acid in the titration process and the molarity of NaOH solution.

Using these data, we can calculate the moles of NaOH used in the titration. Since the reaction between HNO3 and NaOH is a 1:1 ratio, we can find the moles of HNO3 present in the original solution.

From this, we can calculate the original concentration of HNO3.Let’s assume that the molarity of NaOH solution is x M and the volume of NaOH solution added is 22.0 ml.

According to the balanced chemical equation of the reaction between HNO3 and NaOH,1 mole of HNO3 + 1 mole of NaOH → 1 mole of NaNO3 + 1 mole of H2O

Moles of NaOH used in titration = (22.0 ml) (x M) = 22x/1000 moles

Moles of HNO3 present in original solution = moles of NaOH used in titration = 22x/1000 moles

Assuming the initial volume of HNO3 is 25.0 ml, the moles of HNO3 present in the original solution would be calculated as follows:

Molarity (M) = moles/volume (L)Initial moles of HNO3 = M × V = (22x/1000) moles

Moles of HNO3 present in the original solution = (22x/1000) moles - (1/2) × (22x/1000) moles = 11x/1000 moles

Initial volume of HNO3 = moles/M = (11x/1000) moles / (25/1000) L = (11/25) L = 0.44 L = 440 ml

Therefore, the original concentration of HNO3 is 0.11 M.

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The entire energy of all internal molecular motion makes up an object's heat.The thermal energy or average heat of the molecules in a substance is measured by temperature.It is a measurement of the quantity of atoms times the energy that each atom possesses.

How do heat and temperature relate to one another?

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Answer:

Electrons

Explanation:

The source that gives the voltage (force) causes the electrons to move.

Answer:

The answer is Electron

Explanation:

Acetylsalicylic acid (aspirin), HC9H7O4, in a 0.593 M solution has a percent ionization of 0.784 percent.

In a solution, ionization is the process of producing ions. A chemical substance that splits into electrically charged particles, ions, when dissolved in water is said to undergo ionization. The ionization constant (Ka) is a measure of the tendency of a weak acid to ionize, which is calculated by multiplying the molar concentration of the ionized acid by the molar concentration of the hydrogen ion to get the concentration of the undissociated acid divided by the concentration of the dissociated acid squared. In addition, the equation for calculating percent ionization is as follows: % ionization = (ionized concentration/initial concentration) × 100 percent. Calculation Acetyl salicylic acid is a weak acid that partially ionizes in aqueous solution, producing H+ ions. The following equation represents the ionization of aspirin in water: HC9H7O4 + H2O → H3O+ + C9H7O4¯ Initially, the concentration of the undissociated acid is equal to the initial concentration. The ionized concentration is determined by the ionization constant (Ka) and the initial concentration. For weak acids such as acetylsalicylic acid, the value of Ka is typically small. So, at equilibrium, the concentration of ionized acid is also quite small.

To find % ionization, we use the equation: % ionization = (ionized concentration/initial concentration) × 100 percent From the equation:HC9H7O4 + H2O → H3O+ + C9H7O4¯Initial Concentration: 0.593 M Concentration of H3O+ ion (ionized concentration): x Concentration of C9H7O4¯ ion (ionized concentration): x The amount of HC9H7O4 that ionizes is equal to the amount of H3O+ ions formed, which is equal to the amount of C9H7O4¯ ions formed. Thus, we can consider the equilibrium concentrations to be 0.593 - x for HC9H7O4, x for H3O+, and x for C9H7O4¯.Ka = [H3O+] [C9H7O4¯]/[HC9H7O4] Ka = (x)²/(0.593 - x) Using the quadratic formula, we can solve for x, the concentration of ionized acid. This will be approximately equal to the concentration of H3O+.Ka = (x)²/(0.593 - x)0.784 x 10¯5 = (x)²/(0.593 - x)x = 0.000053 M Therefore, ionized concentration = 0.000053 M So, % ionization = (ionized concentration/initial concentration) × 100% = (0.000053/0.593) × 100%= 0.784 %Therefore, the percent ionization of a 0.593 M solution of acetylsalicylic acid (aspirin), HC9H7O4, is 0.784 percent.

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We need to understand that temperature is a measure of the average kinetic energy of the particles in a substance, whereas internal energy is the total energy of all the particles in a substance, including kinetic and potential energy.

Given that gas A registers a slightly higher temperature than gas B when measured using a thermometer, we can conclude that the average kinetic energy of the particles in gas A is higher than that in gas B. However, this does not necessarily mean that gas A has more internal energy.

To determine which gas has more internal energy, we need to consider other factors such as the mass and specific heat capacity of the gases, as well as any changes in their state or conditions in summary, a higher temperature reading on a thermometer only indicates a higher average kinetic energy of the particles in a substance, but does not necessarily indicate which substance has more internal energy. Therefore, we cannot make a definitive conclusion about which gas has more internal energy based solely on the temperature readings.

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Answer:..A.) Each chlorine atom shares a pair of electrons with the sulfur atom

The change in entropy when 1g of water freezes is 1.22 J/K .The heat of fusion of water = 334 J/g, The temperature at which water freezes = 0°CChange in entropy when 1g of water freezes is to be calculated

As we know that the heat of fusion of water is the amount of heat required to convert one gram of ice at its melting point to water at the same temperature.The heat of fusion of water is 334 J/g.Therefore, the amount of heat required to freeze 1g of water at 0°C is given as;Heat required to freeze 1g of water = (1g) (334 J/g) = 334 J0

The entropy change is given by the formulaΔS = q/T where ΔS is the change in entropy, q is the heat supplied and T is the temperature in Kelvin.The temperature at which water freezes is 0°C = 273.15KTherefore, the change in entropy when 1g of water freezes isΔS = 334 J/273.15K = 1.22 J/K

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Answer:

b refraction

Explanation:

i saw on nasa's website lol

The amount of water removed from every kilogram of commercial sea salt would be 27.57 kg.

Seawater contains 3.5% sodium chloride by mass. This means every 1 kg of seawater contains 0.035 kg of sodium chloride.

Sea salt contains about 10% water. This means every 1 kg of sea salt contains 0.1 kg of water.

In order to calculate the amount of water removed from every kilogram of commercial sea salt produced, we need to know the amount of seawater that will give 1 kilogram of sea salt.

We said every 1 kg of seawater contains 0.035 kg of salt. How many 0.035 kg can be found in 1kg?

1/0.035 = 28.57

This means 28.57 kg of seawater would need to be processed in order to have 1 kg of salt. Thus, the amount of water removed can be calculated as:

28.57 - 1 = 27.57 kg

In other words, about 27.57 kg of water is removed for every kilogram of commercial salt produced.

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18 × 10⁻³ micromoles of mercury(i) chloride the chemist has added to the flask.

Volume (V) = 90 ml = 90 / 1000 L

Volume (V) = 0.09 L

Molarity (M) = 2.0 × 10 ⁻⁷ M

Molarity (M) = 2.0 × 10 ⁻⁷ moles/L

moles = Molarity × Volume

          = 2.0 × 10 ⁻⁷ moles/L × 0.09 L

          = 0.18 × 10 ⁻⁷ mole

          = 0.18 × 10 ⁻⁷ × (100/100) moles

          = 18 × 10 ⁻⁹ moles

Now, 1 mole = 1 × 10⁶ micromoles

∴ 18 × 10 ⁻⁹ moles = ?

 18 × 10 ⁻⁹ moles × 1 × 10⁶ micromoles

 = 18 × 10⁻³ micromoles

So, Mercury chloride moles = 18 × 10⁻³ micromoles.

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Answer:

Explanation:

D

Answer:

I'm not sure who made this app but someone made it so that people who understand certain topics can help others who are confused about it.

The mass of an object is the product of its volume and density. The mass of a the object with a volume of 825 cm³ and a density of 13.6 g/cm³ is 11220 g.

Density of substance is the measure of its mass per unit volume. It describes how closely its particles are packed. Density depends on the bond type, temperature and pressure.

Volume of the object is the space occupied by its particles. Volume can be expressed in L, ml, cm³, dm³ etc. Only solids and liquids has a definite volume and the volume of gases is that of the container.

Give that, volume of the object = 825  cm³

density =  13.6 g/cm³

Mass = volume × density

m = 825  cm³ ×  13.6 g/cm³ = 11220 g

Therefore, the mass of the object is 11220 g.

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Answer:Its c

Explanation:

Let us use a double displacement reaction of Lead (II) Nitrate and Potassium Chromate to produce Lead (II) Chromate and Potassium Nitrate to practice balancing an equation.

We begin with the base equation provided in the question.Pb(NO3)2(aq)+K2CrO4(aq)→PbCrO4(s)+KNO3(aq)

Looking at the the atom inventory ReactantsPb=1NO3=2

K=2CrO4=1

Products

Pb=1

NO3=1

K=1

CrO4=1

We can see that the

Kand NO3

are imbalanced.

If we add a coefficient of 2 in front of the

KNO3

this will balance the equation.

Pb(NO3)2(aq)+K2CrO4(aq)→PbCrO4(s)+2KNO3(aq)

Answer:

N=35%. so 35/100*7 =2.45%

H=5.0 so 5/100*1=0.05%

o=60% so 60/100*8=4.8%

Answer:

Sex cells are different in body cells because the sex cells are eggs while body cells are formed.

The limiting reactant if 70.0 g of C7H6O3 and 80.0 g of C4H6O3 react is salicylic acid (C7H6O3).

In this case, given that:

70g C7H6O3

80g C4H6O3

Molar mass of C7H6O3 = 138 g/mol

Molar mass of C4H6O3 = 102 g/mol

So, we need to convert C7H6O3 to C4H6O3 as below:

= 70g C7H6O3

= (molar mass of C4H6O3 / molar mass of C7H6O3) * mass of C7H6O3

= (102 / 138) * 70

= 51.74g C4H6O3

Thus, when 70.0 g of C7H6O3 and 80.0 g of C4H6O3 react, it will be:

80g C4H6O3 – 51.74g C4H6O3 = 28.26g C4H6O3

And, that means there are 28.26g C4H6O3 left after reacting it with C7H6O3.

Hence, the limiting reactant is salicylic acid (C7H6O3).

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Answer:

K is a group 1 element while Ne is a group 0 element

K is a good reducing agent while Ne is inert

K is metal while Ne is a gas

K has one valence electron while Ne has no valence electron

Explanation:

Among the given statements, the true statement is that Reaction I is exothermic, whereas Reaction II is endothermic.

The given information describes a sequence of two reactions involving the conversion of solid carbon (C) to carbon monoxide (CO) in a blast furnace. The standard enthalpies of formation for CO2 and CO are provided.

Reaction I: C (s) + O2 (g) → CO2 (g)

This reaction involves the combustion of carbon (C) with oxygen (O2) to produce carbon dioxide (CO2). Since the formation of CO2 releases heat, this reaction is exothermic.

Reaction II: C (s) + CO2 (g) → 2CO (g)

In this reaction, solid carbon (C) reacts with carbon dioxide (CO2) to form carbon monoxide (CO). The formation of CO in this reaction requires an input of energy, making the reaction endothermic.

Based on the enthalpies of formation, Reaction I releases heat (-394 kJ/mol), indicating it is exothermic. Reaction II requires energy input (-111 kJ/mol), indicating it is endothermic. Therefore, the statement "Reaction I is exothermic, whereas Reaction II is endothermic" is true.

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To prevent warping when sintering a broad plate-shaped body, it is important to use appropriate methods.

Here are some steps that can be taken to prevent warping when sintering a broad plate-shaped body:

1. Keep the plate-shaped body flat: It is important to ensure that the plate-shaped body is flat before sintering. If the plate is warped before sintering, it will be difficult to straighten it out afterward.

2. Use appropriate supports: Use appropriate supports to hold the plate-shaped body in place during sintering. This will help to prevent warping due to thermal expansion.

3. Control the temperature: It is important to control the temperature during sintering to prevent warping. If the temperature is too high, the plate-shaped body may warp due to thermal expansion.

4. Use appropriate cooling: Use appropriate cooling methods to prevent warping. Slow cooling can help to prevent warping due to thermal contraction.

5. Avoid overloading the furnace: Overloading the furnace can cause uneven heating and lead to warping. It is important to avoid overloading the furnace and to use appropriate spacing between parts to ensure even heating.

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Valence bond theory proposes that before a covalent bond forms, atomic orbitals from a given atom combine to form new atomic orbitals. This process is called hybridization of orbitals and the new atomic orbitals are referred to as hybrid orbitals.

Hybridization occurs when an atom has unpaired electrons in its valence shell and these electrons can be shared in covalent bonding. The atomic orbitals involved in hybridization are typically s and p orbitals, which can combine to form sp, sp2, or sp3 hybrid orbitals.

The resulting hybrid orbitals have unique shapes and energies that make them better suited for bonding with other atoms.

For example, sp3 hybridization creates four identical hybrid orbitals that are arranged in a tetrahedral shape, allowing for optimal bonding with four other atoms. The concept of hybridization is essential in understanding the formation of covalent bonds and the resulting molecular geometries.

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Answer:

Animals

I took the test

:))

Answer:

151.87dm³

Explanation:

Given parameters:

Volume of hydrogen gas  = 6.78mole

Unknown:

Volume of hydrogen gas formed at STP  = ?

Solution:

To solve this problem;

   1 mole of a gas at STP  = 22.4dm³ So;

   6.78 mole of gas  = 6.78 x 22.4  = 151.87dm³

The empirical formula of compound is Na3AlF6.

what is empirical formula?

A formula that lists the proportions of the constituent elements but not the number or arrangement of atoms in the composite.

We convert the percentages from percent to grams since they represent the mass percentages of each component in the entire composite.

32.79% Na      -32.79g Na

13.02% Al - 13.02g AL

54.19% F        -54.19g F

The number of moles is determined by dividing each mass by its corresponding molar mass.

32.79g÷22.99 g/mol

 Na = 1.426 mol Na

13.02g÷26.98g/mol

Al = 0.4825 mol Al

59.19g÷18.99 g/mol

 F= 2.85 mol F

We divide each of these amounts by the least number of moles among the three quantities in order to find the empirical form of the compound that demonstrates the simplest ratios between its constituents.

Na= 1.426 mol Na÷0.4825 mol=3Na

Al=0.4825mol Al÷0.4825mol = 1 Al

F= 2.85mol F÷0.4825mol = 6 F.

The empirical formula is Na 3AlF 6

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Each stage of an electron transport chain releases Energy.

The oxidative phosphorylation process, also known as the electron transport chain, is a collection of four protein complexes that combine redox events to produce an electrochemical gradient that results in the production of ATP. Both photosynthesis and cellular respiration take place in mitochondria.

A sequence of chemical processes known as cellular respiration convert glucose into ATP, which can then be used as energy for a variety of bodily functions. Glycolysis, the citric acid cycle, and oxidative phosphorylation are the three basic processes that take place during cellular respiration.

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The number and type of chemical bonds in phosphorus trifluoride , PF₃ is covalent compound having three sigma bond. Cs₂Se is ionic compound and having 2 sigma bond.

The PF₃ is having three sigma bond.  the bond is formed is covalent bond the compound is called as covalent compound. the covalent compound formed between the sharing of valence electrons. Cs₂Se is ionic compound and having 2 sigma bond. ionic bond is formed between the positively  and negatively charged element.

Thus, The number and type of chemical bonds in phosphorus trifluoride , PF₃ is covalent compound having three sigma bond. Cs₂Se is ionic compound and having 2 sigma bond.

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