James weighs 8712 pounds. he has 2 dogs that each weigh 1314 pounds. how many more pounds does james weigh than both of his dogs combined?

Answer: 14 - 3(4)

Step-by-step explanation:

Decreased just means subtract

The correct answer is D. setne 23 47. Based on the provided information, I understand that you have a comparison function in C code and its corresponding assembly code. You are asked to fill in the blanks by selecting the appropriate instructions based on the given values of a and b and the status flags SF, OF, ZF, and CF. Let's go through the options:

A. setg 47 23: This option is incorrect because setg is used to set a byte to 1 if the Greater flag (ZF=0 and SF=OF) is set, but the given values of a and b are 47 and 23, respectively, so it does not satisfy the condition for setg to be set.

B. setl 23 47: This option is incorrect because setl is used to set a byte to 1 if the Less flag (SF≠OF) is set, but the given values of a and b are 23 and 47, respectively, so it does not satisfy the condition for setl to be set.

C. sete 23 23: This option is incorrect because sete is used to set a byte to 1 if the Zero flag (ZF=1) is set, but the given values of a and b are 23 and 23, respectively, so it does not satisfy the condition for sete to be set.

D. setne 23 47: This option is correct. setne is used to set a byte to 1 if the Zero flag (ZF=0) is not set, which means the values of a and b are not equal. In this case, the given values of a and b are 23 and 47, respectively, so they are not equal, and setne should be used.

Therefore, the correct answer is D. setne 23 47

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If an event occurs 0 times (out of 4, in this case) then it does not occur at least once. So we can find the probability of it not occurring and then subtract that value from 1.

So, what are the chances of it not occurring in 1 trip?

1−.37=.63

What about not occurring in 2 trips?

(1−.37)⋅(1−.37)=.63⋅.63=.3969

Now what about not occurring in 4 trips?

.63^4 = 0.15752961

We must subtract this value from 1

(recall that what we just calculated is the probability of it not occurring, so the probability of it occurring at least once is:

1−0.15752961 = .84247039

TLDR - In 4 trips the chance of a guest catching a cutthroat once in under 4 trips in 0.84.

a. The general solution to the Euler equation x²y" + 7xy' + 8y = 0 is y(x) = c₁x⁻⁴ + c₂x⁻², where c₁ and c₂ are arbitrary constants.

b. For the initial value problem 2x²y" - 3xy' + 2y = 0 with y(1) = 3 and y'(1) = 0, the solution is y(x) = 3x².

c. The solution to the initial value problem 4x²y" + 8xy' + y = 0 with y(1) = -3 and y'(1) = k is y(x) = (-3 + k)x⁻².

d. The general solution to the Euler equation x²y" - xy' + 5y = 0 is y(x) = c₁x⁵ + c₂x⁻¹, where c₁ and c₂ are arbitrary constants.

a. To solve the Euler equation x²y" + 7xy' + 8y = 0, we assume a solution of the form y(x) = xⁿ. Plugging this into the equation, we find the characteristic equation n(n - 1) + 7n + 8 = 0, which gives us n = -4 and n = -2. Therefore, the general solution is y(x) = c₁x⁻⁴ + c₂x⁻², where c₁ and c₂ are arbitrary constants.

b. For the initial value problem 2x²y" - 3xy' + 2y = 0 with y(1) = 3 and y'(1) = 0, we solve the differential equation using the method of undetermined coefficients. The particular solution turns out to be y(x) = 3x². Substituting the initial conditions, we find that the solution to the problem is y(x) = 3x².

c. Similarly, for the initial value problem 4x²y" + 8xy' + y = 0 with y(1) = -3 and y'(1) = k, we solve the differential equation and find the particular solution y(x) = (-3 + k)x⁻². The value of k can be determined using the initial condition y'(1) = k. The solution becomes y(x) = (-3 + k)x⁻², where k is the value that satisfies the initial condition.

d. Finally, for the Euler equation x²y" - xy' + 5y = 0, the characteristic equation gives us the solutions n = 5 and n = -1. Therefore, the general solution is y(x) = c₁x⁵ + c₂x⁻¹, where c₁ and c₂ are arbitrary constants.

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The break-even point is the point where the profit and the loss are the same (equal). To calculate it, we have the following formula:

where "Price" denotes the value estimate (per unit) by the company. In this case, such a value is $50. And "Variable costs" denotes the variable cost per table; in this case, it's $22. Then,

Now, note that the obtained number of sales is not an entire number. In such cases, we choose the next integer (for we prefer no loss); in this particular case, it's 465.

The total sales the company needs to break even are 465.

To determine the equation of the tangent plane and normal line of the given curve at the point P(2, -3, 18), we need to find the partial derivatives of the function f(x, y, z) = x^2 + y^2 - 2xy - x + 3y - z - 4.

Taking the partial derivatives with respect to x, y, and z, we have:

fx = 2x - 2y - 1

fy = -2x + 2y + 3

fz = -1

Evaluating these partial derivatives at the point P(2, -3, 18), we find:

fx(2, -3, 18) = 2(2) - 2(-3) - 1 = 9

fy(2, -3, 18) = -2(2) + 2(-3) + 3 = -7

fz(2, -3, 18) = -1

The equation of the tangent plane at P is given by:

9(x - 2) - 7(y + 3) - 1(z - 18) = 0

Simplifying the equation, we get:

9x - 7y - z - 3 = 0

To find the equation of the normal line, we use the direction ratios from the coefficients of x, y, and z in the tangent plane equation. The direction ratios are (9, -7, -1).Therefore, the equation of the normal line passing through P(2, -3, 18) is:

x = 2 + 9t

y = -3 - 7t

z = 18 - t

where t is a parameter representing the distance along the normal line from the point P.

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The correct option is D. 1/4 of the distance from A to B.

D. 1/4 of distance from A to B.

The potential energy of a spring varies with the displacement of the object from its equilibrium position. At the equilibrium position, the potential energy is at a minimum, and the kinetic energy is at its maximum. As the object moves away from the equilibrium position, the potential energy increases and the kinetic energy decreases until the object reaches the maximum displacement point, where the potential energy is at a maximum and the kinetic energy is at a minimum.

In the case of a vertical spring, the equilibrium position is the midpoint between the two extreme points, A and B. At this point, the object has zero potential energy and maximum kinetic energy. As the object moves away from the equilibrium position towards point A, its potential energy increases and its kinetic energy decreases until it reaches point A, where the potential energy is at a maximum and the kinetic energy is at a minimum. Therefore, the object is located at point A when the kinetic energy is at a minimum.

Since the spring is ideal and massless, the potential energy is proportional to the square of the displacement from the equilibrium position. The kinetic energy is proportional to the square of the velocity of the object. At point A, the velocity of the object is zero, and hence the kinetic energy is at a minimum. Therefore, the object is located at point A when the kinetic energy is a minimum.

The distance from A to B is divided into four equal parts, and the object is located at the first quarter point from A to B, which is 1/4 of the distance from A to B. Therefore, the correct option is D. 1/4 of the distance from A to B.

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a) The recurrence relation for the number of ways to deposit n dollars in the vending machine can be expressed as follows:

W(n) = W(n-1) + W(n-1) + W(n-5)

b) The initial conditions for the recurrence relation are as follows:

W(0) = 1 , W(1) = 2 , W(2) = 4

c) There are 17 ways to deposit $10 for a book of stamps.

a) The recurrence relation for the number of ways to deposit n dollars in the vending machine, where the order matters, can be defined as follows: Let f(n) be the number of ways to deposit n dollars. We can break down the problem into three cases: depositing a $1 coin, depositing a $1 bill, or depositing a $5 bill. The recurrence relation is f(n) = f(n-1) + f(n-1) + f(n-5), where f(n-1) represents the number of ways to deposit n-1 dollars and f(n-5) represents the number of ways to deposit n-5 dollars.

b) The initial conditions for the recurrence relation are as follows: f(0) = 1 (there is one way to deposit $0, which is not depositing anything), f(1) = 1 (one way to deposit $1, using a $1 coin), f(2) = 2 (two ways to deposit $2, either using two $1 coins or a $1 coin and a $1 bill), f(3) = 4 (four ways to deposit $3, using three $1 coins, a $1 coin and a $1 bill, or a $1 coin and a $5 bill).

c) To find the number of ways to deposit $10 for a book of stamps, we use the recurrence relation. Plugging in n = 10, we get f(10) = f(9) + f(9) + f(5). Using the initial conditions and recursively applying the relation, we can calculate f(10) to find the answer.

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Answer:

B. -9

Step-by-step explanation:

3(-9)-6/3=-11

7(-9)-3/6=-11

Answer:

1

Step-by-step explanation:

Anything raised to the power of 0 is 1

Answer: =1

Step-by-step explanation:

the number is 1 because the Logical conjunction is 0

Answer:

(3x − 1)(x 8)

Step-by-step explanation:

Answer:

12,13

9,12

Step-by-step explanation:

really really easy in an order pair

this is how you would do it

x. y

12,13

the first number is X on your graph or chart and the second one is Y

Therefore ,the solution to the given problem of proportion comes out to be karen got  £70.

The rule of three is used to link the measures because a proportion is a fraction of a total amount. It is possible to construct equation or relations between variables that are either direct (when both rise or decrease) or inverse proportional (when one increases and the other declines, or vice versa) in order to determine the necessary measures in the situation.

Here,

Given :

Siobhan and Ralph shared £700 in the

ratio 2:3.

Thus,

280 / 420 = 2/3

Thus,

Siobhan and Ralph has  £280 and £420  respectively.

and Siobhan gave a share of quarter to karen :

So,

280/4 =70

Therefore ,the solution to the given problem of proportion comes out to be karen got  £70.

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To find a positive number such that the sum of and is as small as possible, we need to use optimization. This problem requires optimization over a closed interval. The given problem is as follows, Let x be a positive number. Find a positive number such that the sum of and is as small as possible.

To find a positive number such that the sum of and is as small as possible, we need to use optimization. This problem requires optimization over a closed interval. The given problem is as follows, Let x be a positive number. Find a positive number such that the sum of and is as small as possible. So, we need to minimize the sum of and . Now, let's use calculus to find the minimum value of the sum.To find the minimum value, we have to find the derivative of the sum of and , i.e. f(x) with respect to x, which is given by f '(x) as shown below:

f '(x) = 1/x^2 - 1/(1-x)^2

We can see that this function is defined on the closed interval [0, 1]. The reason why we are using the closed interval is that x is a positive number, and both endpoints are included to ensure that we cover all positive numbers. Therefore, the problem requires optimization over a closed interval. This means that the minimum value exists and is achieved either at one of the endpoints of the interval or at a critical point in the interior of the interval.

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Answer:

No, this triangle is NOT a right angle.

Step-by-step explanation:

The known fact is that the largest number is our hypotenuse. The other two numbers can go on either side.

A square plus B square equal C square is our equation

Let's plug in the numbers: 15^2+5^2=16^2

Now we solve.

Once we solve our squares and add them together, we get 250=256. Since these two number are not equal to each other, this triangle is NOT a right angle

much love to you.

Line charts represents changes over a period of time and they represent data in a clear manner . Line charts handles variety of data as compared to a column or a bar chart.

In order to compare data set we can use various types of  compare utilities

On comparing data sets we get two types of resulting sets one is the original one and the other is the updated one.

All the comparison can also be performed in the background.

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Answer:

Step-by-step explanation:

The dimension of boards to one decimal place is 0.9m * 0.7m

"Dimensions in mathematics are the measure of the size or distance of an object or region or space in one direction. In simpler terms, it is the measurement of the length, width, and height of anything.

Dimensions are generally expressed as:

Length

Breadth

Width

Height or Depth"

The correct dimension of board are to one decimal place is 0.9m * 0.66m

Hence, B is the correct option.

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We can use Coulomb's law to calculate the magnitude of the electric field at a distance r away from a point charge Q:

E = k * Q / r^2

where k is Coulomb's constant, Q is the charge of the point charge, and r is the distance from the point charge.

In this problem, we have a point charge Q of -10 nC located at (1.2 cm, 0 cm), and we want to find the x-component of the electric field at a distance r = 5.3 cm away at position (-4.1 cm, 0 cm).

To find the x-component of the electric field, we need to use the cosine of the angle between the electric field vector and the x-axis, which is cos(180°) = -1.

So, the x-component of the electric field at position (-4.1 cm, 0 cm) is:

E_x = - E * cos(180°) = - (k * Q / r^2) * (-1)

where k = 9 x 10^9 N*m^2/C^2 is Coulomb's constant.

Substituting the given values, we get:

E_x = - (9 x 10^9 N*m^2/C^2) * (-10 x 10^-9 C) / (0.053 m)^2

E_x ≈ -30,566.04 N/C

Rounding this to two significant figures and including the appropriate units, we get:

The x-component of the electric field is about -3.1 x 10^4 N/C (to the left).

Given:

Principal = Rs. 2000

Rate of interest = 20% p.a. compounded quarterly.

Time = 1 year

To find:

The compound interest.

Solution:

Formula for amount:

\(A=P\left (1+\dfrac{r}{n}\right)^{nt}\)

where,

P = Principal

r = Rate of interest

t= Time

n = number of times interest compounded in an year.

Putting P=2000, r=0.2, n=4 and t=1, we get

\(A=2000\left (1+\dfrac{0.2}{4}\right)^{4(1)}\)

\(A=2000\left (1.05\right)^{4}\)

\(A=2000\left (1.21550625\right)\)

\(A=2431.0125\)

Now, the compound interest is

\(C.I.=A-P\)

\(C.I.=2431.0125-2000\)

\(C.I.=431.0125\)

Therefore, the compound interest is Rs 431.0125.

Step-by-step explanation:

divide it by 2...............

9514 1404 393

Answer:

  C, B, D

Step-by-step explanation:

We can estimate the relative lengths of the segments using the difference of their coordinates:

  BC = (2-0, -5-6) = (2, -11)

  CD = (-8-2, -1-(-5)) = (-10, 4)

  DB = (0-(-8), 6-(-1)) = (8, 7)

Then the lengths of the segments will be ...

  BC = √(2^2 +11^2) = √125

  CD = √(10^2 +4^2) = √116

  DB = √(8^2 +7^2) = √113

DB is the shortest segment, so opposite the smallest angle, C.

The next-shortest segment is CD, opposite angle B.

The longest segment is BC, opposite angle D.

In order from least measure to greatest, the angles are C, B, D.

Answer:

450cm3

Step-by-step explanation:

10 times 5 times 9

Answer:

Simple . the cuboid have to go to GYM to Work out the Volume .  1+2= 11 Answer

Answer:

What do you need help with?

Step-by-step explanation:

Answer:

whts the problem-

Step-by-step explanation:

Answer:

16

Step-by-step explanation:

Sum of all angles of triangle = 180

30 + 90 + 4x - 4 = 180

30 +90 - 4 + 4x = 180

116 + 4x = 180

Subtract 116 form both sides

4x = 180 - 116

4x = 64

Divide both sides by 4

x = 64/4

x = 16

Answer:

x = 4

Step-by-step explanation:

\(\sqrt{(x -4)(x - 4)\\}\)

x - 4 = 0

x = 4

Answer:

Step-by-step explanation:

dtuyhgtrfedfgrthyuj

Answer:

124.63 in² (to the nearest hundredth)

Step-by-step explanation:

For this problem:

\(\pi\)= 3.14

\(r\) = 12.6 ÷ 2 = 6.3

Therefore, area = 3.14 x 6.3²

                          = 124.6266

                          = 124.63 in² (to the nearest hundredth)

Answer: 4

Step-by-step explanation:

35.2/ 8.8= 4

4

Answer:

2

Step-by-step explanation:

f = a

48 = 3

32 = x

48x= 98

x=2