it would take approximately years to receive light from a civilization on the opposite side of the galaxy. a. 100000 years. b. 10 yrs. c. 100 yrs. d. 1/4 of a year.
Answers
It would take approximately 100,000 years to receive light from a civilization on the opposite side of the galaxy. The correct answer is, therefore (a) "100,000 years".
This is because the distance between the Earth and the opposite side of the galaxy is approximately 100,000 light-years. Light travels at a speed of approximately 300,000,000 meters per second, so it would take approximately 100,000 years for light to travel from the opposite side of the galaxy to the Earth.
A light-year is a unit of distance that is equal to the distance that light travels in one year. Light travels at a very high speed, approximately 300,000,000 meters per second, so it is able to cover a large distance in a relatively short amount of time.
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Related Questions
A 0.5 kg object is given an initial velocity of 3m/s after which it slides a distance of 8 m across a level floor. what is the cofficient of kinetic friction between the object anda the floor.please answer
Answers
Answer: average speed = (3+0)/2 = 1.5 m/s so t = 8/1.5 = 80/15 = 5.33
Explanation:
5.How can we determine if an object is charged or not?
Answers
Hope this helps have an excellent day!
Answer:
through the use of a Gold leaf electroscope
5
A 4-kg rifle fires a 0.01-kg bullet at a velocity of 300 m/s. If they
were both at rest before firing, what is the recoil velocity of the
rifle?
Answers
The recoil velocity of the rifle is -0.75 m/s.
What is recoil velocity of the rifle?
The recoil velocity of the rifle is calculated by applying principle of linear momentum as follows;
m₁u₁ + m₂u₂ = v₁m₁ + v₂m₂
where;
m₁ is the mass of the riflem₂ is the mass of the bulletu is their initial velocity v is their final velocity( 4 kg x 0 ) + ( 0.01 kg x 0 ) = 4v₁ + ( 0.01 kg x 300 m/s )
0 = 4v₁ + 3
v₁ = - 3 /4
v₁ = -0.75 m/s
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A box that weighs 5.00×10^2 N is sliding down a ramp at a constant speed. The angle the ramp makes with the horizontal is 25°. What is the coefficient of friction between the box and the ramp?
Answers
Answer:
0.466 (3 sig. fig.)
Explanation:
Frictional force acting on the box = 5.00×10^2xsin25
Normal force acting on the box = 5.00×10^2xcos25
coefficient of friction = 0.466 (3 sig. fig.)
How do conditions in the wild differ from conditions in captivity?
Answers
The wild offers more natural structures and temperatures that keep animals adapted to their surroundings. However, in captivity animals tend to differ from their wild counterparts. For one thing, the wild cultivates an animal's hunting skills but, when or if they are releasing into the wild, they do not know what to do whereas they have been sheltered their entire life. They don't know how to find natural structures to keep warm in, what places are safe or even survival strategies. The conditions in the wild teach an animal to survive while the conditions from man-made structures just give them an easy survival.
Hope this helps and have a nice day.
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Two college students push a broken down, 711 kg car to a mechanic. If the first student pushes with a force of 638 N and the second student pushes with a force of 573 N, what is the magnitude of acceleration of the car?
Answers
The magnitude of acceleration of the car is 1.70 \(m/s^{2}\) .
Acceleration is the rate of change of velocity with respect to time.
Also it is the capacity of the vehicle to gain speed.Mass of the car = 711 kg
Force exerted by the Student 1 = \(F_1\) = 638 N
Force exerted by the Student 2 = \(F_2\) = 573 N
Total force exerted on the car = F = \(F_1\) + \(F_2\)
F = 638 + 573
F = 1,211 N
As we know that, Force is the product of mass and acceleration i.e.
F = m * a
\(a = \frac{F}{m}\)
a = \(\frac{1211}{711}\)
a = 1.70 \(m/s^{2}\)
The magnitude of acceleration of the car is 1.70 \(m/s^{2}\) to push it to a car mechanic.
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A hawk sits on a telephone wire. If the wire dips so that it makes a 30 degree angle with the horizontal, and the tension in the wire is 25 N, what is the hawk’s weight?
Answers
The weight of the hawk is found to be 25 N.
What is the tension?The tension is the force that acts on the wire. Given the fact the we are told in the question that a hawk sits on a telephone wire. If the wire dips so that it makes a 30 degree angle with the horizontal, and the tension in the wire is 25 N.
The image that depicts this problem have been attached to this solution. Now we have from the image that we have attached to this answer;
W = 2T sin θ
W = 2 * 25 * sin 30
W = 2 * 25 * 0.5
W = 25 N
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A block of mass 290 kg slides on a frictionless plane inclined at 39◦ with the horizontal under the influence of a restraining force of 1643 N acting parallel to the incline and up the incline. The acceleration of gravity is 9.8 m/s^2
What is the magnitude of the acceleration of the block? Answer in units of m/s^2
The resulting motion is
1. down the plane, since the acceleration is positive.
2. up the plane, since the acceleration is negative.
3. undetermined.
Answers
The magnitude of the acceleration is −0.50 m/s² of the block of mass 290kg that slides on a frictionless plane inclined at 39◦ with the horizontal under the influence of a restraining force of 1643 .
The resulting motion is
2. up the plane, since the acceleration is negative.
What is acceleration?Acceleration describes the speed and direction changes in velocity over time. Acceleration refers to the change in speed or direction of an object or point moving straight ahead.
Due to the constant change in direction, motion on a circle accelerates even when the speed is constant. Both effects help to accelerate all other types of motion.
We have given that,
m = 290 kg
θ = 39◦
F = 1643 N
g = 9.8 m/s²
The force due to gravity
F₁ = m × g × sinθ
F₁ = 290 × 9.8 × sin 39°
F₁ = 1790.46 N
Lets take acceleration is a m/s²
Form Newtons second law
F - F₁ = m × a
1643 - 1790.46 = 290 x a
a = −0.50 m/s²
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A car heading north collides at an intersection with a truck of the same mass as the car heading east. If they lock together and travel at 28 m/s at 46° north of east just after the collision, how fast was the car initially traveling? assume that any other unbalanced forces are negligible.
Answers
Answer: A car heading north collides at an intersection with a truck of the same mass as the car heading east. If they lock together and travel at 28 m/s at 46° north of east just after the collision, then the car initially traveling with a velocity of 40.28m/s.
Explanation: To find the answer, we need to know more about the Perfectly inelastic collision.
What is perfectly inelastic collision?Collision is an interaction between two bodies due to which the individual momenta of the colliding bodies are changed, but the total momentum remains constant.If the colliding bodies stick together after collision, then it is called perfectly inelastic collision.here, the coefficient of restitution will be equal to 0.For, inelastic collision, the momentum is conserved, but the energy is not conserved.How to solve the problem?let's write the conservation equation of momentum as,\(m_1v_1+0=(m_1+m_2)v_2\\\)
We have to find the value of initial velocity v1,\(mv_1=(m+m)28 sin46\\v_1=2*28*0.719=40.28 m/s\)
Thus, we can conclude that, the initial velocity of the car will be 40.28m/s.
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A jet plane is speeding down the runway during takeoff. Airresistance is not negligible, friction is negligible.identify the forces on the jet. Choose your answers from thefollowing list:GravitySpring ForceTensionNormal ForceFrictionDragThrust
Answers
The answer following list are Gravity, Drag, Thrust, Normal Force.
What is Gravity?Gravity is the force of attraction between two objects with mass. It is one of the four fundamental forces, along with the electromagnetic force, the weak nuclear force, and the strong nuclear force. Gravity is the weakest of the four forces, but it has the longest range, allowing it to affect objects even at a great distance. On Earth, gravity is responsible for keeping us on the ground and providing the force of weight that gives objects their mass. It also provides the force that keeps the planets, moons, and other objects in the solar system in orbit. Gravity is caused by the curvature of space-time due to the presence of matter and energy.
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Alvin and Theodore race across a parking lot 451 cm long. Alvin travels at 19.28 cm/s and Theodore at 12 cm/s. When the Alvin crosses the finish line, how far behind is Theodore?
Answers
Theodore is 170 centimeters from the finish line when Alvin crosses it.
The total distance is 451 cm, so we can find the time that takes Alvin to crosses the finish line as follows:
\( v_{a} = \frac{x}{t} \) (1)
Where:
\( v_{a}\): is the speed of Alvin = 19.28 cm/s
x: is the total distance = 451 cm
t: is the time that takes Alvin to crosses the finish line =?
By solving equation (1) for t, we have:
\(t = \frac{x}{v} = \frac{451 cm}{19.28 cm/s} = 23.4 s\)
Now, after 23.4 seconds have elapsed, Theorode has traveled the following distance (\(x_{t}\)):
\( x_{t} = v_{t}*t \)
Where:
\(v_{t}\): is the speed of Theodore = 12 cm/s
\( x_{t} = v_{t}*t = 12 cm/s*23.4 s = 281 cm \)
The distance (d) that Theodore needs to travel to cross the finish line is:
\(d = x - x_{t} = 451 cm - 281 cm = 170 cm\)
Therefore, Theodore is 170 centimeters from the finish line when Alvin crosses it.
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How do media literacy , information literacy and technology literacy and media and information literacy differ in terms of use?
Answers
Answer:
Media literacy creates a conscious awareness, the ability to understand, analyze, the messages various media like the newspapers, the radio, that is for the consumer, and it also promotes how best media create information for production.
While information literacy and technology literacy differs from other literacy asked in the question above, as information literacy and technology could be used when describing getting information through adequate research and further dishing out this available information so as to effectively use the information with the aim to solve problems, create awareness, or educate, through technologies such as for example, email.
Lastly, media and information literacy differ in terms of use from the other two explained above, as media and information literacy describes discerning information credibility, accuracy, and objectivity of sources they come from, and it shows people how important it is to have credible information to make informed judgments and the ethical use of the information they consume.
x Methane, has a molar mass of 16.03 grams per mole. How many particles o of methane are present in 120 grams?
Answers
In order to determine the number of particles of methane, use the following expression:
number of particles = (mass /molar mass ) x Avogadro's number
in this case, you have:
molar mass = 16.03 grams/mole
mass = 120 grams
Avogadro's number = 6.02*10²³ particles/mol
replace the previos values of the parameters into the formula for the number of particles:
number of particles=(120 grams/ 16.03 grams/ mol)x(6.02*10²³particles/mol)
= (7.46 mol) x (6.02*10²³ particles/mol)
= 4.50*10²⁴ particles
Hence, the number of particles of methane, in 120 grams, is 4.50*10²⁴
The mass of an object is the measure of what characteristic of the object?
O A. its volume
OB. the space it occupies
O c. the amount of matter it has
O D. its weight
please help asap
Answers
The Enterprise wants to orbit a4.15 x 10^24kg planet with a period of14100 s. What should the radius oftheir orbit be?
Answers
Given:
Mass of planet, m = 4.15 x 10²⁴ kg.
Period, T = 14100 s
Let's find the radius.
To find the radius, apply the formula from Kepler's Third aw:
\(\begin{gathered} \frac{T^2}{R^3}=\frac{4\pi^2}{GM} \\ \\ \end{gathered}\)Where R is the radius.
Rewrite the formula for r:
\(R=\sqrt[3]{\frac{GM*T^2}{4\pi^2}}\)Where:
G is gravitational constant = 6.67 x 10⁻¹¹ m3 kg-1 s-2
M is the mass = 4.15 x 10²⁴ kg
T is the period = 14100 s
π = 3.54
Plug in values and solve for R;
\(\begin{gathered} R=\sqrt[3]{\frac{6.67\times10^{-11}*4.15\times10^{24}*14100^2}{4\pi^2}} \\ \\ R=\sqrt[3]{\frac{5.503\times10^{22}}{39.4784}} \\ \\ \end{gathered}\)Solving further:
\(\begin{gathered} R=\sqrt[3]{1.394\times10^{21}} \\ \\ R=11170796.49\approx1.12\times10^7\text{ m} \end{gathered}\)Therefore, the orbital radius will be 1.12 x 10⁷ meters.
ANSWER:
1.12 x 10⁷ m
multimode fiber is capable of longer transmission distances than single mode fiber.
Answers
The given statement "multimode fiber is capable of longer transmission distances than single mode fiber" is incorrect. The multimode fiber is not capable of longer transmission distances than single mode fiber.
What is single mode fiber?
Single mode fiber is the type of fiber optic cable that carries light directly down the fiber. The core diameter of single mode fiber is much smaller than that of multimode fiber. The small core reduces the dispersion of light. Single mode fiber can be used to transmit data over longer distances than multimode fiber because it has a lower attenuation rate.
What is multimode fiber?
Multimode fiber is the type of fiber optic cable that carries light down the fiber in many modes. In multimode fiber, the diameter of the core is large and is measured in 50 to 100 microns. Multimode fiber is used for short-distance communication. The data transmission rate is slower, but the larger core allows for a higher bandwidth than single mode fiber.Multimode fiber is less expensive than single mode fiber, but it has a shorter transmission distance. In contrast, single mode fiber is more expensive but offers longer transmission distances due to its low attenuation rate.
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When is the best time to take a resting heart break
A. One hour after eating a meal.
B. Just before going to bed at night.
C. One hour after vigorous exercise.
D. Just after waking in the morning.
Answers
Answer:
I believe D
Explanation:
You need to have a more accurate reading and you want to test it multiple times throughout the week though to get a base resting rate.
I hope this is correct good luck!
An object that is negatively charged could contain only electrons with no accompanying protons. O True False
Answers
The given statement is '' An object that is negatively charged could contain only electrons with no accompanying protons '' is false because
All electrons carry a negative charge and all protons carry a positive charge. An object that is negatively charged must have an excess of electrons compared to protons, but it will still contain protons. In fact, all ordinary matter consists of atoms that contain both protons and electrons (as well as neutrons). The number of electrons and protons in an atom is usually equal, so the overall charge of the atom is neutral. However, when electrons are added or removed from an atom, the resulting ion can be either positively or negatively charged. So, an object that is negatively charged must have gained extra electrons or lost some protons, but it will still contain protons.
However, the number of electrons will be greater than the number of protons, resulting in a net negative charge.
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a wind turbine with an efficiency of 45% for converting wind energy into electrical energy is designed to yield 10 kw of electrical power in a 20 mi/h wind. [the density of air is 1.2 kg/m3.] (a) what length rotor blades does this wind turbine hav
Answers
A wind turbine with an efficiency of 45% for converting wind energy into electrical energy is designed to yield 10 kW of electrical power in a 20 mph wind. The density of air is 1.2 kg/m³. The length of rotor blades that this wind turbine
Given that electrical power is 10 kW.
Electrical Power = (efficiency) × (wind energy intercepted by the rotor blade).
The wind energy intercepted by the rotor blade can be defined as:
Wind energy intercepted by rotor blade = (1/2) × (density of air) × (area swept by the rotor blade) × (velocity³)A = (2 × electrical power) ÷ (efficiency × density of air × velocity³)A = (2 × 10000) ÷ (0.45 × 1.2 × (20 × 0.447)³).
The area swept by the rotor blade is 128.6 m².
Since, Area of a circle = πr²
Where A = 128.6 m²πr² = 128.6 m²∴ r² = 41.016∴ r = 6.407 m.
So, the rotor blade of the wind turbine is 12.814 meters in length. Hence, the correct answer is 12.814 meters.
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what are the two elements used most often to make semiconductors?
Answers
The two elements most commonly used to make semiconductors are silicon and germanium.
Answer: Silicon and Germanium
Explanation: They are used as such because
1. More stability at high temperature
2. Reverse current is low
3. Easily available
a 1250-kg car moves at 15.7 m/s. what force is required from the engine to increase the car’s speed to 32.4 m/s over a distance of 28 m?
Answers
Force required to increase the speed of a car is 8.48 × \(10^{4}\)N, we need to consider the work done by the engine to overcome the forces of friction and air resistance.
The work done to increase the car's kinetic energy. The work done can be calculated using the equation W = F×d, where W is the work done, F is the force applied, and d is the distance over which the force is applied. The change in kinetic energy can be calculated using the equation
ΔKE = 1/2 m\(v^{2}\), where ΔKE is the change in kinetic energy, m is the mass of the car, and v is the change in velocity. Using these equations, we can calculate the force required to increase the car's speed from 15.7 m/s to 32.4 m/s over a distance of 28 m as follows:
F = ΔKE / d = (1/2) × 1250 kg × (32.4 m/s - 15.7 m/s\()^{2}\) / 28 m = 8.48 × \(10^{4}\) N.
This force must be applied over the 28 m distance to overcome the forces of friction and air resistance and increase the car's kinetic energy. The actual force required will depend on the specific conditions of the scenario, including the road conditions, weather, and the car's aerodynamics.
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consider a 10 g mass traveling at 10 m/s impacting and sticking to a 990 g mass that is initially at rest. what is the speed of the combined mass after the collision (in m/s)?
Answers
The velocity of the combined weight at rest following the collision. 15 m/sec.
What do mass and an example mean?The amount of material that makes up every object and body is the simplest method for comprehending mass. Everything that we can see has mass. Examples of objects with mass include a desk, a seat, your mattress, a football, a glass, or even air. The mass of a thing determines whether it is light or heavy.
What is the best way to define mass?A measure of how much matter is present in or makes up a physical body. In classical mechanics, an object's mass is crucial to Newton's motion laws because it influences the force needed to accelerate it and, consequently, how much inertia it has.
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which form of energy in the circuit lights the bulb.?
Answers
Answer:
electric energy.......
an aircraft covers 8,000 km in 30 minutes what is the speed of the aircraft
Answers
Answer:
267km per minute.
Explanation:
If the wave height of 1500 waves is recorded, significant wave height will be the average of the highest _______ waves.
Answers
If the wave height of 1500 waves is recorded, the significant wave height will be the average of the highest one-third waves.
The significant wave height is a statistical measure used in oceanography to describe the average height of the highest one-third of waves in a given wave record.
It represents the average height of the waves that are most representative of the sea state.
To calculate the significant wave height, the wave heights of a large number of individual waves are measured or recorded.
These wave heights are then sorted in descending order, and the highest one-third of the waves are selected. The average height of these highest one-third waves is considered the significant wave height.
By considering the average height of the highest one-third waves, the significant wave height provides a useful measure to describe the typical wave conditions and the wave energy in a given area.
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A person rides in an elevator.
What is the equal and opposite force for the force of the elevator floor pushing up on the person as described by Newton's third law?
Answers
The equal and opposite force for the force of the elevator floor pushing up on the person as described by Newton's third law is the weight and the reaction force from its effect.
What is an Elevator?This is referred to as a device which is used in the vertical transportation of goods and people among the floors in a buildings.
When an individual steps into the elevator, the weight acts on it and it is known as a downward force while the reaction acts upward in an opposite reaction as described by Newton's third law in this scenario.
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if the height of the mercury column in the leveling bulb is 10 mm greater than that in the gas buret and atmospheric pressure is 670 mm, what is the pressure on the gas trapped in the buret? (hint: raising the leveling bulb, increases the p on the gas)
Answers
The pressure on the gas trapped in the buret is 680 mm.
The air around you has weight, and it presses against everything it touches. That strain is referred to as atmospheric pressure or air pressure. it's miles the force exerted on a surface by way of the air above it as gravity pulls it to Earth. Atmospheric strain is normally measured with a barometer.
Atmospheric pressure strain is the pressure exerted via the air around us while Atmospheric stress is the stress exerted by means of the environment on the earth. Air pressure is measured with the aid of a tore gauge while atmospheric stress is measured with the use of a mercury barometer.
Given;
If the height of the mercury Column in the leveling bulb is 10 mm greater than the gas buret and the atmos[pheric pressure is 670 mm.
The pressure on the gas trapped in the buffet = 670 + 10
= 680 mm
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While participating in a blood drive at school, Keona learns that blood has a density of 1.06 g/mL. She donates one pint of blood, which is equal to 473.176 mL.
Answers
The mass of the blood denoted is 501.6 g.
What is the mass of the blood she denoted?The mass of the blood denoted by Keona is calculated by applying the formula for density of a liquid as shown below.
density = mass/volume
mass = density x volume
The given parameters include;
density of the blood = 1.06 g/mLvolume of the blood, = 473.176 mLThe mass of the blood is calculated as follows;
mass = 1.06 g/mL x 473.176 mL
mass = 501.6 g
Thus, the mass of the blood is calculated from the formula of density.
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The complete question is below
While participating in a blood drive at school, Keona learns that blood has a density of 1.06 g/mL. She donates one pint of blood, which is equal to 473.176 mL. find the mass of the blood denoted.
If the coefficient of static friction is 0.753, the length of the ladder is 9.9 m, and its mass is 39 kg, find the minimum height LaTeX: h below which the ladder will slip.
Answers
The ladder will slip at the point where the reaction at the wall is just over
the force due to friction.
Response:
The minimum height below which the ladder will slip, is approximately 5.48 meters above the ground.Which method is used to calculate the minimum height before slipping?The given parameter are;
The coefficient of friction, μ = 0.753
Length of the ladder = 9.9 m
Mass of the ladder = 39 kg
Required:
The minimum height below which the ladder will slip.
Solution:
Assumption: The friction of the wall on the ladder is 0.
The weight of the ladder, W = The normal reaction = N
The friction force, \(F_f\) = The reaction force of the wall, \(F_w\)
\(F_f\) = W × μ
Which gives;
\(F_f\) = 39 × 9.81 × 0.753 ≈ 288.09
The friction force, \(F_f\) ≈ 288.09 N = \(F_w\)
Taking moments about the contact between the ladder and the ground, we have;
\(F_w\) × h = W × x
Where;
\(h = \mathbf{L \times sin(\theta)}\)
\(x = \mathbf{\dfrac{L}{2} \times cos(\theta)}\)
Which gives;
\(x = \dfrac{9.9}{2} \times cos(\theta) = \mathbf{4.95 \cdot cos(\theta)}\)
\(h = 9.9 \cdot sin(\theta)\)
θ = The angle made by the ladder and the ground
Therefore;
288.09 × 9.9·sin(θ) = 39 × 9.81 × x = 382.59 × 4.95·cos(θ)
\(\dfrac{sin(\theta)}{cos(\theta)} = tan(\theta) = \dfrac{382.59 \times 4.95}{288.09 \times 9.9}\)
\(\theta = arctan \left(\dfrac{382.59 \times 4.95}{288.09 \times 9.9} \right) \app\)
Which gives;
\(h = \mathbf{9.9 * sin\left(arctan \left(\dfrac{382.59 \times 4.95}{288.09 \times 9.9} \right) \right)} \approx 5.48\)
The minimum height below which the ladder will slip, h ≈ 5.48 m
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A ball is thrown horizontally at a height of 1.6 metres above the ground, with initialspeed 14 m s^-1a)Find the time of flight of the ball, giving the answer as a fraction.b)Find the range of the ball.
Answers
Given:
The initial height of the ball, h=1.6 m
The initial speed of the ball, u=14 m/s
To find:
a) The time of flight of the ball.
b) The range of the ball.
Explanation:
As the ball is thrown horizontally, the ball will have no vertical component of the initial velocity. The velocity of the ball is completely horizontal.
Thus the vertical component of the initial velocity of the ball is u_y=0 m/s.
The horizontal component of the initial velocity of the ball is u_x=u=14 m/s.
a)
From the equation of motion,
\(h=u_yt+\frac{1}{2}gt^2\)Where g is the acceleration due to gravity and t is the time of flight of the ball.
On substituting the known values,
\(\begin{gathered} 1.6=0+\frac{1}{2}\times9.8\times t^2 \\ \implies t=\sqrt{\frac{2\times1.6}{9.8}} \\ =0.57\text{ s} \end{gathered}\)b)
The range of the ball is given by,
\(R=u_xt\)On substituting the known values,
\(\begin{gathered} R=14\times0.57 \\ =7.98\text{ m} \end{gathered}\)Final answer:
a) The time of flight of the ball is 0.57 s
b) The range of the ball is 7.98 m