Is the area of the base of a shape different from the area of the whole shape?

what help? how can i help you?

Answer:

\(x {}^{3} \)

Step-by-step explanation:

\(\frac{(x {}^{5} )}{( {x}^{2} )}\)

\(x {}^{3} \)

The percentage of 27 miles in 23 miles is 117.39%.

Percentage is a way of expressing a fraction or a portion of a whole number in relation to 100. It is denoted by the symbol "%". A percentage is calculated by dividing the part (numerator) by the whole (denominator) and multiplying the result by 100. A percentage can also be used to represent a rate or a percentage change over time.

In this case, we are asked to find what percentage of 23 miles is 27 miles. The part is 27 miles and the whole is 23 miles. Therefore, the percentage is:

% = part/whole = 27/23 x 100 = 117.39%

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Hello !

Answer:

\(\boxed{\sf V{cone} \approx 2408.55 m^3}\)

Step-by-step explanation:

To find the volume of a cone with the radius of its base and its height, we will apply the following formula:

\( \sf V{cone} = \dfrac{\pi \times r^2 \times h}{3} \)

Where r is the radius of its base and h is its height.

Given:

Let's substitute our values into the formula:

\(\sf V{cone} = \dfrac{\pi (10)^2(23)}{3} = \dfrac{2300\pi}{3} \ \ \\\boxed{\sf V{cone} \approx 2408.55 m^3}\)

Have a nice day ;)

Answer:

Step-by-step explanation:

14 doughnuts in total

Answer:

x = 9

Step-by-step explanation:

2x + 8 = 4x - 10 Given

2x + 8 - 2x = 4x - 10 - 2x Subtraction property of equality

8 = 2x - 10

8 + 10 = 2x - 10 + 10 Addition property of equality

18 = 2x

18 ÷ 2 = 2x ÷ 2 Division property of equality

9 = x Answer

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Solution  of the given equation 2x+8=4x-10 is x=9.

Solution of an equation are the values to the unknown variables that makes the equality in the equation true

Given equation is :

2x+8=4x-10,   consider it as equation (1)

To solve this equation firstly, we isolate the terms which contain x in the LHS and the constant terms in RHS.

Then, the equation will become:

2x-4x = -10-8

Solving the LHS and RHS:

-2x = -18

Divide both the sides by -2, we get:

x = -18/(-2)

x = 9

That means x=9 satisfies the given equation.

Hence, x=9 is the solution of the given equation.

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Answer:

Hi, I'm Za'Riah! I will gladly assist you with your problem. (see explanation)

Step-by-step explanation:

y=3x+13; y=7x+17

Step: Solve y = 3x + 13 for y:

y=3x+13

Step: Substitute 3x + 13 for y in y = 7x + 17 :

y=7x+17

3x+13= 7x+17

3x+13+-7x=7x+17+-7x (Add -7x to both sides)

-4x+13=17

-4x+13+-13=17+-13 (Add -13 to both sides)

-4x=4

-4x/-4 = 4/-4 (Divide both sides by -4)

x=-1

Step: Substitute -1 for x in y=3x+13:

y=3x+13

y=(3)(-1)+13

y=10(simplify both sides of the equation)

Answer:

x= -1 and y= 10

(Hope this helped!)

The mass of a banana is about C. 150 g.

A can of cola would be around A. 300 ml.

From the options, the best estimate for the mass of a banana is 150 g. This is because 1. 5 kg is much too heavy for a single banana which makes 15 kg ridiculously heavy. 15 g would be too light however as this is the mass of about 6 pennies.

There are several quantities for a can of cola, and they are all in 100s of milliliteters. The most likely quantity of a can of cola from the options is therefore 300 ml.

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Answer:

C

Step-by-step explanation:

75.54*550=41,497.5

Answer:

See Below.

Step-by-step explanation:

We want to verify the equation:

\(\displaystyle \frac{\cos y}{1-\sin y}=\frac{1+\sin y}{\cos y}\)

On the left, we can multiply both layers by (1 + sin(y)):

\(\displaystyle \frac{\cos y}{1-\sin y}\left(\frac{1+\sin y}{1+\sin y}\right)=\frac{1+\sin y}{\cos y}\)

Multiply:

\(\displaystyle \frac{\cos y(1+\sin y)}{1-\sin^2 y}=\frac{1+\sin y}{\cos y}\)

From the Pythagorean Theorem, we know that sin²(y) + cos²(y) = 1. Hence, 1 - sin²(y) = cos²(y). Substitute:

\(\displaystyle \frac{\cos y(1+\sin y))}{\cos^2 y}=\frac{1+\sin y}{\cos y}\)

Cancel:

\(\displaystyle \frac{1+\sin y}{\cos y}=\frac{1+\sin y}{\cos y}\)

Hence proven.

To make expression (6y + 10) + (3y + 5) equivalent to (ny + 15),the value of n is 6.

To find the value of n that makes the expressions equivalent, we can equate the coefficients of y on both sides of the equation.

On the left side, the coefficient of y in the expression (6y + 10) is 6, and the coefficient of y in the expression (3y + 5) is 3.

On the right side, the coefficient of y in the expression (ny + 15) is n.

Equating the coefficients, we have:

6 = n

Therefore, the value of n that makes the expressions equivalent is 6.

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MATHEMATICALLY WE SAY

\( - 2 < x \leqslant 3\)

THE CIRCLE AT THE ENDPOINT OF THE LINE WHICH IS NOT SHADED MEANS NOT INCLUDED AND THE SHADED CIRCLE MEANS INCLUDED

HOPE THIS HELPS.

The predicted cost for a student attending a arts college with 1,500 students and a rank of 4.5 can be calculated using the given regression model: Tuition = 7 + 4*Rank - 0.20*Size + 8*Private - 0.4*LibArts.

In this case, Rank = 4.5, Size = 1.5 (since it's measured in 1,000s), Private = 1 (since it's a private college), and LibArts = 1 (since it's a liberal arts college). Plugging these values into the model, the predicted tuition cost would be: Tuition = 7 + 4*(4.5) - 0.20*(1.5) + 8*1 - 0.4*1 = $26.1 thousand.

If the student switches from her current private liberal arts college to a public, non-liberal arts college with a rank 0.5 lower and 15,000 more students, we need to adjust the Size and Rank variables accordingly. Assuming the student's current college is still private, the new values would be Rank = 4.5 - 0.5 = 4 and Size = 1.5 + 15 = 16.5 (since it's measured in 1,000s). With the new values, we can calculate the predicted tuition cost for the public college: Tuition = 7 + 4*(4) - 0.20*(16.5) + 8*0 - 0.4*0 = $22.4 thousand.

To determine how much money the student saves in tuition, we calculate the difference between the predicted costs of the two colleges: $26.1 thousand - $22.4 thousand = $3.7 thousand. Therefore, by switching from her current private liberal arts college to a public, non-liberal arts college with a lower rank and larger size, the student saves $3.7 thousand in tuition.

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Answer:

7x-6= 6x+12

x=18

Step-by-step explanation:

The fraction shows that D. Maddy made 4 bows from the piece of ribbon and had enough left for of a bow.

A fraction is simply a piece of a whole. The number is represented mathematically as a quotient where the numerator and denominator are split. In a simple fraction, the numerator as well as the denominator are both integers.

In this case the fraction divided will be:

= 3 1/2 ÷ 3/4.

= 7/2 ÷ 3/4

= 7/2 × 4/3

= 28/6

= 14 / 3

= 4 2/3

Therefore, the correct option is D.

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The solutions to the given algebraic expressions are;

1) 3x + 4 = 7x - 8; Letter C

2) 2x = 7x - 5; Letter E

3) 5x - 8 = 5x + 12; Letter D

1) We are given the algebraic expression as;

3x + 4 = 7x - 8

Add 8 to both sides to get;

3x + 12 = 7x

Subtract 3x from both sides to get;

12 = 4x

divide both sides by 4 to get;

x = 3

2) 2x = 7x - 5

Add 5 to both sides to get;

2x + 5 = 7x

Subtract 2x from both sides to get;

5x = 5

divide both sides by 5 to get;

x = 1

3) 5x - 8 = 5x + 12

Subtract 5x from both sides gives;

-8 = 12

Thus, no solution

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Step-by-step explanation:

6785*7%=474.95

Hope this helps

Answer:

B (-3,3)

Step-by-step explanation:

calculate where the lines cross each other

Answer:

x=12

Step-by-step explanation:

Those two angles equal each other. Set them equal to each other and solve for x.

4x+54 = 126-2x

So let's solve for x.

4x+2x = 126-54

6x = 72

Now divide both sides by six.

x = 12.

Answer:

It's -3

Step-by-step explanation:

I got it right on Edge 2020

Answer:

21.75

Step-by-step explanation:

Because 6.00+6.25=12.25+7.00=19.75+8.00=27.75

The interpretation of this expression is that the partial derivative of TC w.r.t. x is the rate of change of TC with respect to x, considering all other variables constant. It means if we change one unit of labor, TC will increase by 2e2x - 4 units, considering all other variables remain constant.

T C = 1/2 e2x + ey - 4x - 2ywhere x = units of labor and y = units of human capital, x, y > 0.Calculate:We need to calculate dTC/dx.

Interpretation:First, we need to calculate partial derivative of T C w.r.t. x. We know that partial derivative of a function with respect to one of its variable means to find the derivative of that variable with respect to the function, considering the other variables constant. Hence, it is a rate of change of one variable with respect to other variables considered constant. This is used to find the slope of a surface in a given direction.

The partial derivative of T C w.r.t. x is given as:

∂/∂x (T C)

= 2e2x - 4.∂/∂x (T C)

= 2e2x - 4

The interpretation of this expression is that the partial derivative of TC w.r.t. x is the rate of change of TC with respect to x, considering all other variables constant. It means if we change one unit of labor, TC will increase by 2e2x - 4 units, considering all other variables remain constant.

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The function f(x) is increasing over the interval [-2, 0) and decreasing over the interval (0, 2].

To determine where the function is increasing or decreasing, we need to find the critical points, which are the values of x where the derivative of the function is zero or undefined.

In this case, the derivative of f(x) is

f'(x) = -0.6x.

Setting this equal to zero, we get

-0.6x = 0,

f x = 0. This is the only critical point.

Next, we can test intervals around the critical point to see where the function is increasing or decreasing.

For x < 0 (to the left of the critical point), f'(x) is negative, which means that f(x) is decreasing. For x > 0 (to the right of the critical point), f'(x) is positive, which means that f(x) is increasing.

Therefore, the function is increasing over the interval [-2, 0) and decreasing over the interval (0, 2].

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To show that the total charge contained in the charge distribution is Q, we integrate the charge density over the entire volume. The charge density is given by:

ρ(r) = ρ₀(1 - r/R) for r ≤ R,

ρ(r) = 0 for r > R,

where ρ₀ = 3Q/πR³.

To find the total charge, we integrate ρ(r) over the volume:

Q = ∫ρ(r) dV,

where dV represents the volume element.

Since the charge density is spherically symmetric, we can express dV as dV = 4πr² dr, where r is the radial distance.

The integral becomes:

Q = ∫₀ᴿ ρ₀(1 - r/R) * 4πr² dr.

Evaluating this integral gives:

Q = ρ₀ * 4π * [r³/3 - r⁴/(4R)] from 0 to R.

Simplifying further, we get:

Q = ρ₀ * 4π * [(R³/3) - (R⁴/4R)].

Simplifying the expression inside the parentheses:

Q = ρ₀ * 4π * [(4R³/12) - (R³/4)].

Simplifying once more:

Q = ρ₀ * π * (R³ - R³/3),

Q = ρ₀ * π * (2R³/3),

Q = (3Q/πR³) * π * (2R³/3),

Q = 2Q.

Therefore, the total charge contained in the charge distribution is Q.

To show that the electric field in the region r > R is identical to that created by a point charge Q at r = 0, we can use Gauss's law. Since the charge distribution is spherically symmetric, the electric field outside the distribution can be obtained by considering a Gaussian surface of radius r > R.

By Gauss's law, the electric field through a closed surface is given by:

∮E · dA = (1/ε₀) * Qenc,

where ε₀ is the permittivity of free space, Qenc is the enclosed charge, and the integral is taken over the closed surface.

Since the charge distribution is spherically symmetric, the enclosed charge within the Gaussian surface of radius r is Qenc = Q.

For the Gaussian surface outside the distribution, the electric field is radially directed, and its magnitude is constant on the surface. Hence, E · dA = E * 4πr².

Plugging these values into Gauss's law:

E * 4πr² = (1/ε₀) * Q,

Simplifying:

E = Q / (4πε₀r²).

This is the same expression as the electric field created by a point charge Q at the origin (r = 0).

To derive an expression for the electric field in the region r ≤ R, we can again use Gauss's law. This time we consider a Gaussian surface inside the charge distribution, such that the entire charge Q is enclosed.

The enclosed charge within the Gaussian surface of radius r ≤ R is Qenc = Q.

By Gauss's law, we have:

∮E · dA = (1/ε₀) * Qenc.

Since the charge distribution is spherically symmetric, the electric field is radially directed, and its magnitude is constant on the Gaussian surface. Hence, E · dA = E * 4πr².

Plugging these values into Gauss's law:

E * 4πr² = (1/ε₀) * Q.

Simplifying:

E = Q / (4πε₀r²).

This expression represents the electric field inside the charge distribution for r ≤ R.

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