The smallest metal in Period 3 is Aluminium
Which elements are included in period 3?
A period 3 element is one of the chemical elements in the third row (or period) of the periodic table of the chemical elements. The periodic table is laid out in rows to illustrate recurring (periodic) trends in the chemical behaviour of the elements as their atomic number increases: a new row is begun when the periodic table skips a row and a chemical behaviour begins to repeat, meaning that elements with similar behaviour fall into the same vertical columns. The third period contains eight elements: sodium, magnesium, aluminium, silicon, phosphorus, sulfur, chlorine, and argon. The first two, sodium and magnesium, are members of the s-block of the periodic table, while the others are members of the p-block. All of the period 3 elements occur in nature and have at least one stable isotope.
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100 POINTS PLS HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
i need this im struggling with my work
Explanation:
Last one and the first
Calculate the percent yield of the aldol condensation-dehydration reaction.
I did the following
Put 0.8 mL aldehyde, 0.2 mL ketone, 4 mL ethanol, 3 mL of 2M sodium hydroxide in a flask. Then swirled it for 15 min. Then I added 6 mL ethanol and 4 mL of 4% acetic acid. I put the solution on ice and crystals formed. I ended up with 0.305 g of product. Please show me how to calcualte my percent yield for my product.
ketone= acetone (0.791 g/ mL)
aldehyde= 4-Methylbenzaldehyde (1.019 g/ m
The percent yield of the aldol condensation-dehydration reaction is 69.2%.
To calculate the percent yield of the aldol condensation-dehydration reaction, we need to compare the actual yield of the product with the theoretical yield that we would expect based on the amounts of starting materials used. The balanced chemical equation for the reaction is:
2 aldehyde + 2 ketone + base + ethanol → aldol + water + salt
From the given information, we used 0.8 mL of aldehyde (density = 1.019 g/mL) and 0.2 mL of ketone (density = 0.791 g/mL), which correspond to masses of 0.8152 g and 0.1582 g, respectively. The molar mass of the aldehyde is 120.15 g/mol, and the molar mass of the ketone is 58.08 g/mol. Therefore, we have:
moles of aldehyde = 0.8152 g / 120.15 g/mol = 0.00679 mol
moles of ketone = 0.1582 g / 58.08 g/mol = 0.00272 mol
Assuming complete conversion of the starting materials, the theoretical yield of the product can be calculated based on the limiting reagent (the ketone in this case). The molar ratio of ketone to aldol in the balanced equation is 1:1, so we would expect to obtain 0.00272 mol of product. The molar mass of the aldol is 162.23 g/mol, so the theoretical yield in grams is:
theoretical yield = 0.00272 mol * 162.23 g/mol = 0.441 g
Therefore, the percent yield of the reaction is:
percent yield = (actual yield / theoretical yield) * 100%
percent yield = (0.305 g / 0.441 g) * 100%
percent yield = 69.2%
So, the percent yield of the aldol condensation-dehydration reaction is 69.2%.
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The energy levels in which electrons orbit around the ____________ are also called ____________ .
The energy levels in which electrons orbit around the nucleus are also called electron shells.
All atoms contain electrons, protons and neutrons. The protons and neutrons are located in the center of the atom called the nucleus. Electrons orbit around the nucleus in electron orbits or shells.
Electron shells or energy levels are the paths followed by electrons as they orbit round the nucleus. The shells are used to determine an atom's electronic configuration and atomic structure.
The shells in an atom are given a number, starting from the innermost shell to the outermost shell, called the principal quantum number, denoted with the letter n. The farther away a shell is from the nucleus, the higher the energy level and the higher the principal quantum number.
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In the arrhenius equation, the collision frequency and molecular orientation are incorporated in the value of?
The collision frequency and molecular orientation are incorporated in the value of the activation energy (Ea) in the Arrhenius equation.
The Arrhenius equation is a mathematical expression that describes the temperature dependence of reaction rates. It states that the rate constant (k) of a chemical reaction is directly proportional to the frequency of successful collisions between reacting molecules, and is given by the equation:
k = Ae^(-Ea/RT),
where A is the pre-exponential factor, Ea is the activation energy, R is the gas constant, and T is the temperature in Kelvin.
This equation predicts that as the temperature increases, the reaction rate will also increase due to the increase in collision frequency and molecular orientation, which are both incorporated in the activation energy (Ea).
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hydrogen fuel can be produced from methane or by electrolysis of water. as of 2020, the majority of hydrogen (∼95%) is produced from fossil fuels by steam reforming or partial oxidation of methane and coal gasification with only a small quantity by other routes such as biomass gasification or electrolysis of water.
Natural gas contains methane (CH\(4\)), which is used to produce hydrogen by thermal processes like stem-methane reformation and partial oxidation.
In steam-methane reforming, which is the most common method to produce hydrogen, high temperature steam (700°C - 1000°C). The pressure required is 3-25 bar pressure, in the presence of a catalyst. Steam reforming is an endothermic process. Carbon monoxide and steam are reacted using catalyst to produce carbon dioxide and hydrogen.
Partial oxidation is an exothermic process. It is much faster than steam reforming. This method initially produces less hydrogen.
These processes are more preferred because the use of petroleum is low and the emissions is also low. Total greenhouse gases emission is cut.
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In the video, we use the atomic model to describe pressure as resulting from?
The atomic model which has been used to describe the pressure resulting from the force from the collision of the gas molecules with the walls of their container.
In the container, the molecules of a gas having their own kinetic energy. The molecules move from one place to another as well as in the process, they will collide with the walls of the container. The collision will results in the formation of a momentum by the particle against the wall of the container. The perpendicular force exerted by the gas molecules will be divided by the area, which will describe the pressure.
Thus, the atomic model has been also used to describe the pressure resulting from the force from the collision of gas molecules with the walls of their container.
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how many moles of silver nitrate are needed to produce 6.75 moles of copper (II) nitrate upon reacting with excess copper?
Answer:
13.50 moles of AgNO₃ are needed to produce 6.75 moles of Cu(NO₃)₂
Explanation:
We state the reactants:
AgNO₃
Cu
Then, the products are:
Cu(NO₃)₂
Ag
The reaction is: 2AgNO₃ + Cu → 2Ag + Cu(NO₃)₂
Ratio is 1:2.
The copper is in excess, so the limiting reactant is the silver nitrate:
1 mol of Cu(NO₃)₂ is produced by 2 moles of AgNO₃
Then, 6.75 moles of copper (II) nitrate would be produced by, the double of moles
(6 75 . 2) /1 = 13.50 moles
the dominant inter-atomic bond in a h2o molecule is permanent dipole bond. question 1 options: true false
The given statement "the dominant inter-atomic bond in a H2O molecule is a permanent dipole bond" is true.
The permanent dipole-dipole force occurs in polar molecules. In polar molecules, the electrons are distributed unevenly. A positive end and a negative end are created as a result of the unequal sharing of electrons.
Permanent dipole bonds are a type of chemical bond that forms between two polar molecules. This bond exists due to the attraction between the partially positively charged end of one polar molecule and the partially negatively charged end of another polar molecule.
In a water molecule, the oxygen atom is more electronegative than the hydrogen atoms, resulting in a partial negative charge on the oxygen atom and partial positive charges on the hydrogen atoms. This leads to the creation of a permanent dipole bond in H2O.
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simplify 2²×2³ someone plz help
Answer:
\(2^5\) or 32
Explanation:
The rule for exponents is that \(x^a*x^b = x^{a+b\). Thus, we have a+b = 5 so the answer is 2^5 or 32
as the temperature of a gas decreases is volume
Answer:
it's volume also decrease
You have a 0.05 M solution of sulfuric acid. What is the concentration in grams per liter (or dm3)?
The sulfuric acid solution has a concentration of 4.904 grams per liter (or dm3).
What is sulphuric acid?With the chemical formula H₂SO₄, sulfuric acid is a potent, colorless, odorless, and extremely corrosive mineral acid. It is also referred to as "vitriol oil." An extremely significant industrial chemical, sulfuric acid is used to make a variety of goods, including fertilizers, detergents, pigments, dyes, medicines, and explosives.
The formula below can be used to get the molar mass of sulfuric acid (H₂SO₄):
H₂SO₄'s molar mass is calculated as follows: 2 × (1.008 g/mol) + 32.06 g/mol + 4(16.00 g/mol) = 98.08 g/mol.
Hence, 98.08 g equals one mole of sulfuric acid.
We must multiply the molarity by the sulfuric acid's molar mass in order to translate the molarity (0.05 M) to grams per liter:
4.904 g/L = 0.05 mol/L x 98.08 g/mol
As a result, the sulfuric acid solution has a concentration of 4.904 grams per liter (or dm³).
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Which of the following best describes a pair of elements that will form an ionic bond
Answer:
One of the elements must be a metal and another be a non metal.
One of the elements must lose electrons and the other must gain electrons.
Electrically conductive functionalized GNP/epoxy based composites: From nanocomposite to multiscale glass fibre composite material.
The given phrase describes "Electrically conductive functionalized GNP/epoxy based composites" and their transition from a "nanocomposite" to a "multiscale glass fibre composite material." This suggests a progression in the composition and structure of the composites, potentially involving the incorporation of glass fibers at a larger scale.
The phrase highlights the use of electrically conductive functionalized graphene nanoplatelets (GNP) in combination with epoxy to create composite materials. The functionalized GNP enhances the electrical conductivity of the composites.
The transition from a nanocomposite to a multiscale glass fiber composite material suggests a shift in the reinforcement mechanism, where additional glass fibers are incorporated to improve the mechanical properties at a larger scale.
The concept described in the given phrase focuses on the development of electrically conductive composites by incorporating functionalized GNP and epoxy.
This development encompasses a progression from nanocomposites to multiscale glass fiber composites, indicating a shift towards larger-scale reinforcement.
The use of such composites holds potential for applications requiring both electrical conductivity and mechanical strength, providing versatility in material design for various industries, including aerospace, automotive, and electronics. It is essential to conduct further research and experimentation to explore the performance and properties of these composite materials in different applications.
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suppose you are performing a hydroboration oxidation of 1-hexene to form 1-hexanol. your reaction includes 0.84 ml of 1-hexene, which has a density of 0.673 g/ml, 1.73 ml of 1.00 m borane in thf, and 1.26 ml of 30.0% m/v hydrogen peroxide. what is the theoretical yield of 1-hexanol (in g) for the reaction?
The theoretical yield of 1-hexanol (in g) for the reaction is: 102.18 g
Theoretical Yield of 1-HexanolIn the reaction for the hydroboration oxidation of 1-hexene to form 1-hexanol, the theoretical yield of 1-hexanol (in g) can be calculated by applying the formula:
Theoretical yield = (mass of limiting reactant x molecular weight of 1-hexanol) / molecular weight of limiting reactant
Given that the reaction includes 0.84 ml of 1-hexene, which has a density of 0.673 g/ml, 1.73 ml of 1.00 m borane in thf, and 1.26 ml of 30.0% m/v hydrogen peroxide. The molecular weight of 1-hexene is 84.16 g/mol, and the molecular weight of 1-hexanol is 102.18 g/mol.
To find out the limiting reactant, we need to first calculate the moles of each reactant as follows:
Moles of 1-hexene = volume x density / molecular weight = 0.84 ml x 0.673 g/ml / 84.16 g/mol = 0.00675 mol
Moles of borane = volume x concentration = 1.73 ml x 1.00 M = 0.00173 mol
Moles of hydrogen peroxide = volume x concentration = 1.26 ml x 30.0% m/v / (100 g/L) / (34.0147 g/mol) = 0.00113 mol
From the above calculations, the borane is the limiting reactant since it produces the least amount of moles of product. Therefore, the moles of 1-hexanol produced is also equal to the moles of borane used in the reaction.
Moles of 1-hexanol produced = moles of borane used = 0.00173 mol
The theoretical yield of 1-hexanol can be calculated by applying the formula:
Theoretical yield = (mass of limiting reactant x molecular weight of 1-hexanol) / molecular weight of limiting reactant= (0.00173 mol x 102.18 g/mol) / 0.00173 mol= 102.18 g
The theoretical yield of 1-hexanol is 102.18 g.
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Cual es la masa atómica del fósforo si tiene 16 neutrones?
Answer:
nbfuhbcuwcbevbeufvhev
Explanation:
jejfihfirhugv
A 17.1 g sample of a hydrocarbon was analyzed by combustion analysis. The products were 17.9 g CO2 and 14.7 g H2O. What is the empirical formula
The empirical formula for the hydrocarbon that was analyzed by combustion analysis is C2H5.
Combustion analysis is a technique for identifying the components of a compound by igniting it and measuring the weight of the resulting products. The empirical formula for a hydrocarbon that was analyzed by combustion analysis is required.17.1 g sample of a hydrocarbon was burned, and the products were 17.9 g of CO2 and 14.7 g of H2O.
Calculate the amount of carbon and hydrogen present in the sample:17.9 g of CO2 contain: 1 mole of CO2 contains 1 mole of carbon atoms.1 mole CO2 weighs 44 g:44 g CO2 = 12 g of C1 mole of CO2 weighs 44 g:44 g CO2 = 32 g of O2Moles of CO2 = 17.9 g / 44 g/mol = 0.407 moles of CO2Moles of C = 0.407 moles of CO2Moles of H = (14.7 g of H2O / 18 g/mol) × (1 mol of H / 1 mol of H2O) = 0.817 mol of H.
To calculate the empirical formula, we must divide the mole quantities by the lowest quantity of moles to obtain the simplest whole number ratios of atoms: Mole ratio C:H = 0.407/0.817 = 0.498:
1 Empirical formula C2H5 for the hydrocarbon containing 2 carbon atoms and 5 hydrogen atoms.
Therefore, the empirical formula for the hydrocarbon that was analyzed by combustion analysis is C2H5.
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Which molecule contains a nonpolar covalent bond?
A) H2
B) NH3
C) H₂O
D) CO
Steven wants to build an ornamental fish pond in his garden. the expert at the garden center said he must get an air pump to ensure that the water is oxygenated. what is the correct term for a body of water that is devoid of oxygen?
The correct term for a body of water that is devoid of oxygen is Hypoxic. Therefore, option (A) is correct.
Hypoxic water can still harm aquatic life. In hypoxic conditions, organisms may not get enough oxygen, causing stress or death, especially for delicate species like fish.
In Steven's beautiful fish pond, proper oxygenation prevents anoxic and hypoxic conditions and keeps the fish healthy. The garden center expert's air pump will avoid hypoxia by oxygenating the water. Therefore, option (A) is correct.
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Your question is incomplete but your full question was:
Steven wants to build an ornamental fish pond in his garden. The expert at the garden center said he must get an air pump to ensure that the water is oxygenated. What is the correct term for a body of water that is devoid of oxygen? A.hypoxic B.acerbic C.anoxic D.aerobic E.eutrophic
The term for a body of water that lacks oxygen is anoxic. Water in an ornamental fish pond needs to be oxygenated to support aquatic life like fish, which use their gills to absorb dissolved oxygen from the water.
Explanation:The correct term for a body of water that is devoid of oxygen is anoxic. It's essential for an ornamental fish pond to have an adequate supply of oxygen. Oxygen dissolves in water but at a lower concentration than in the atmosphere, hence the need for an air pump to ensure that the water is oxygenated, which is key for aquatic life, especially for fish. Fish and many other aquatic organisms have evolved gills to take up the dissolved oxygen from water. When water passes over the gills, the dissolved oxygen in water rapidly diffuses across the gills into the bloodstream, helping the fish live and thrive in its environment.
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rusting is the common name for the corrosion of iron or steel. the brown-orange rust commonly seen on iron or steel cars, nails, chains, or posts has the formula fe2o3. what is its iupac name?
Rusting is the common name for the corrosion of iron or steel. The chemical name of rust is iron oxide, particularly iron (III) oxide.
Rust is the reddish-brown coating that often appears on certain types of metal. Rust forms when these metals are exposed to moisture and air. This combination causes a chemical reaction, producing the red substance.
The chemical name for rust is iron oxide, with the chemical formula Fe2O3. Iron or alloys that contain iron (such as steel) are metals that become rusty. When iron comes into contact with both water and oxygen in the air, a chemical reaction occurs over a period of time. This reaction forms a new compound that is iron oxide. Iron oxide is found in nature and is also abundant on Mars, giving it its reddish colour.
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HOW DOES ONE ISOTOPE OF HYDROGEN DIFFER FROM ANOTHER ISOTOPE OF HYDROGEN?
An experiment was conducted in order to determine the enthalpy change that occurs when 1.0 mole of ice at 0 degrees Celsius melts and becomes 1.0 mole of water at 0 degrees Celsius. The enthalpy change associated with this process is referred to as the heat of fusion of ice. In the experiment a 9.68g sample of ice at 0 degrees Celsius was added to the coffee cup calorimeter containing 278.25 mL of distilled water. The temperature of the water was 22.485 degrees Celsius before The ice was added. The lowest temperature that was recorded after the ice had melted was 19.050 degrees Celsius.
A) find the amount of heat lost or gained by the water in the calorimeter.
B) in this experiment the ice melted and then the temperature of the water produced by the ice increased from 0 degrees Celsius to 19.050 degrees Celsius. Calculate the amount of heat absorbed by the melted ice as it’s temperature increased from 0.000 degrees Celsius to 19.050 degrees Celsius
C) calculate the heat that was gained by the ice during melting process
D) calculate the heat of the fusion of ice
E) is the reaction endothermic or exothermic?
F) energy was transferred from one system to another during this experiment. Identify the two interacting systems and outline the direction of energy flow.
G) was energy conserved in the process? Justify your answer.
Answer: 1
Explanation:
Experiment on enthalpy change.
The enthalpy is a hydrodynamic system that is made to collect the internal energy. The product is of pressure and volume. The experiment was conducted to see the enthalpic change that occurred at a 1.0 mole of ice at 0 degrees.
The answer is 9.68 grams.
The enthalpy change linked with the process is called as a fusion of heat of the ice. The temperature of the water was 278.25 ml hat of distilled water and the calorimeter consisted of 278.35 ml of water.The enthalpy change linked with this process is referred to as the heated fusion of ice. In the experiment a 9.68g sample.Learn more about the experiment was conducted.
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if the electronic abbreviation for S is equal to [Ne] 3s2 3p4.
What is the electronic abbreviation for the S^-2 ion?
The electronic configuration for the \(S^{-2}\) ion is [Ne] 3s2 3p6.
\(S^{-2}\) ions are negatively charged ions that are composed of two sulfur atoms. They are produced when sulfur atoms gain two electrons, creating a net negative charge. These ions are highly reactive and can form strong bonds with other atoms, molecules, and ions. This is because when an atom loses two electrons, the outermost shell (3p) must gain two electrons to fill the quantum level. its electron configuration changes to the next noble gas (in this case, Neon) plus two additional electrons. Since 3p has six electrons, the electronic abbreviation for the \(S^{-2}\) ion is [Ne] 3s2 3p6.
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A 46.2-g sample of copper is heated to 95.4oC and then placed in a calorimeter containing 75.0 g water at 19.6oC. The equilibrium temperature in the calorimeter is 21.8oC. Calculate the specific heat of copper; assuming that all the heat lost by the copper is gained by the water (specific heat of water is 4.184 J/g oC).
The specific heat of copper is approximately 0.386 J/g°C, A 46.2-g sample of copper is heated to 95.4 C and then placed in a calorimeter containing 75.0 g water at 19.6 C.
The equation for heat (q) is q = m x c x ΔT, where m is the mass of the substance, c is its specific heat capacity, and ΔT is the change in temperature. To find the specific heat of copper, we can set the heat lost by the copper equal to the heat gained by the water.q lost by copper = q gained by water 46.2 g x cCu x (95.4°C - T) = 75.0 g x 4.184 J/g°C x (T - 19.6°C) First, let's find T, the final temperature when the copper and water are mixed together.
Since the two substances will reach thermal equilibrium, we can use the formula:mcΔT = -mcΔTmCu x cCu x (95.4°C - T) = -mH2O x cH2O x (T - 19.6°C)46.2 g x cCu x (95.4°C - T) = -75.0 g x 4.184 J/g°C x (T - 19.6°C)194.16 x cCu x (95.4 - T) = -313.8 x (T - 19.6 Note that we can multiply both sides by -1 to simplify the equation: 194.16 x cCu x (T - 95.4) = 313.8 x (T - 19.6)194.16 x cCu x T - 18497.23 = 313.8 x T - 6164.68(194.16 - 313.8) x T = 18497.23 - 6164.68 xCu = (18497.23 - 6164.68) / (194.16 - 313.8) ≈ 0.386 J/g°CT
herefore, the specific heat of copper is approximately 0.386 J/g°C.
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Jaiden Drives for 800 km at an average speed of 120 km/h. How long was her journey?
Answer:
i think her journey was 680 km/h long
Answer:
6.67 hours
Explanation:
(800 km) / (120 km/hr) = 6.67 hours
a teacher divides her class into groups and assigns each group a task of measuring the mass of the same object three times.the teacher already knows that the mass of the object is 25g based on the results each group records,which group makes the most precise measurement of the object
Answer:
This question lacks options, the options are:
A. Group C: 32.1 g, 35.0 g, 25.0 g
B. Group B: 25.5 g, 25.0 g, 24.8 g
C. Group A: 28.5g, 28.4 g, 28.5 g
D. Group D: 20.0 g, 25.0 g, 30.09
The answer is C. GROUP A
Explanation:
Precision in measurements refers to the degree of closeness between the repeated or measured values irrespective of how close they are to the true or accepted value, which is 25g in this case.
The precision of a measurement can be determined by simply finding the range (highest - lowest) of the measurements. The lowest range represents the most precise. The measurements for each group are:
Group C: 32.1 g, 35.0 g, 25.0 g
Range = 35.0 - 25.0 = 10g
Group B: 25.5 g, 25.0 g, 24.8 g
Range = 25.5 - 24.8 = 0.7g
Group A: 28.5g, 28.4 g, 28.5 g
Range: 28.5 - 28.4 = 0.1g
Group D: 20.0 g, 25.0 g, 30.09
Range = 30.09 - 25.0= 5.09g
Based on the ranges of the measurements in each group, one would notice that Group A has the lowest range (0.1g), hence, GROUP A is the most precise.
Answer: group A
Explanation: I got the answer right on my quiz.
Which of these is found in the energy levels of an atom?
Answer:
Electrons
Explanation:
Because the nucleas is In the middle and the Electrons surround it
the sodium-22 nuclide radioactively decays by positron emission. write a balanced nuclear chemical equation that describes this process.
A balanced nuclear chemical equation describes this process is:
Na-22 → Ne-22 + e+ (or β+)
To write a balanced nuclear chemical equation for this process, follow these steps:
1. Identify the initial nuclide: Sodium-22 (Na-22) has an atomic number of 11 (protons) and a mass number of 22 (protons + neutrons).
2. Identify the emitted particle: Positron emission involves the release of a positron, which has the symbol e+ or β+ and has an atomic number of -1 and a mass number of 0.
3. Determine the resulting nuclide: In positron emission, a proton in the nucleus is converted into a neutron, decreasing the atomic number by 1.
Thus, the resulting nuclide will have an atomic number of 10 and a mass number of 22, which corresponds to neon-22 (Ne-22).
Now, we can write the balanced nuclear chemical equation for this process:
Na-22 → Ne-22 + e+ (or β+)
This equation shows that sodium-22 decays by positron emission to form neon-22 and a positron.
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During recrystallization, why is it necessary to cool the solution slowly?
answer:
the reason is to ensure more solute is dissolving as it cools down. it is important to do it slowly because water will be sucked into buchner flask by a partial vaccum through the rubber tubing and be able to arrange molecules.
A solution is prepared from 8 grams of acetic acid ( CH3COOH ) and 725 grams of water.What is the molality of this solution?0.0002 m0.01 m0.2 m11 m
Answer:
0.2m
Explanation:
I just took the test
Your welcome
Taking into account the definition of molality, the correct answer is the third option: the molality of the solution is 0.2 \(\frac{moles}{kg}\).
Definition of molalityMolality is a measure of concentration that indicates the number of moles of solute that are dissolved in 1 kilogram of solvent.
This is, molality is the ratio of the number of moles of any dissolved solute to kilograms of solvent.
The Molality of a solution is determined by the expression:
\(molality=\frac{number of moles of solute}{kilograms of solvent}\)
Molality in this caseIn this case, you know:
number of moles of solute: 8 grams×\(\frac{1 mole}{60 grams}\)= 0.133 moles, being 60 \(\frac{grams}{mole}\)the molar mass of acetic acid, that is, the amount of mass that a substance contains in one mole.kilograms of solvent: 725 grams= 0.725 kg (being 1000 grams= 1 kg)Replacing in the definition of molality:
\(molality=\frac{0.133 moles}{0.725 kg}\)
Solving:
molality= 0.18 \(\frac{moles}{kg}\)≅ 0.2 \(\frac{moles}{kg}\)
Finally, the correct answer is the third option: the molality of the solution is 0.2 \(\frac{moles}{kg}\).
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determine the concentration of the sugar standards in g/100 ml of solution. the first two have been done for you. note: 1 sugar packet contains 3.5 g of sugar number of packs of sugar dissolved in 100 ml of solution 0 1 2 3 4 g sugar/100 ml (% w/v) 0 3.5 ? ? ? concentration of solution 2 ( g sugar/100 ml): concentration of solution 3 ( g sugar/100 ml): concentation of solution 4 ( g sugar/100 ml):
By using the information provided in the table and the amount of sugar packets added to 100 ml of solution, we can determine the concentration of sugar standards in g/100 ml.
To determine the concentration of the sugar standards in g/100 ml of solution, we can use the information provided in the table. The sugar standards are solutions with varying amounts of sugar dissolved in 100 ml of solution. The sugar concentration is expressed as g sugar/100 ml or % w/v.
According to the table, the first two sugar standards have been done for us. The first standard has 0 g sugar/100 ml, which means no sugar was added to the solution. The second standard has 3.5 g sugar/100 ml, which means one sugar packet was dissolved in the solution.
To determine the concentration of the third sugar standard, we need to know how many sugar packets were dissolved in 100 ml of solution. Since the second standard has 3.5 g sugar/100 ml, we can assume that one sugar packet was used. Therefore, to make the third standard, we need to add two sugar packets to 100 ml of solution, which gives us a concentration of 7 g sugar/100 ml.
Similarly, to determine the concentration of the fourth sugar standard, we need to add three sugar packets to 100 ml of solution, which gives us a concentration of 10.5 g sugar/100 ml.
Therefore, the concentrations of the sugar standards in g/100 ml of solution are:
- Standard 1: 0 g sugar/100 ml
- Standard 2: 3.5 g sugar/100 ml
- Standard 3: 7 g sugar/100 ml
- Standard 4: 10.5 g sugar/100 ml
In summary, by using the information provided in the table and the amount of sugar packets added to 100 ml of solution, we can determine the concentration of sugar standards in g/100 ml.
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