in triangle ABC, M angle A=40 degrees and m angle B=80 degrees. which of the following triangles is similar to triangle ABC will mark brainiest​

Answer: 160

Step-by-step explanation: 20% of 160 is 32. 100% of 160 is 160, therefore 20 percent of 160 equals 32.

Brooklyn needs to invest $432.43, rounded to the nearest ten dollars.

To determine how much Brooklyn needs to invest in an account that pays a continuously compounded interest rate, we can use the formula:

A = \(Pe^(^r^t^)\)

where A is the future value of the account, P is the principal investment, e is the mathematical constant approximately equal to 2.71828, r is the interest rate, and t is the time in years.

In this case, we want the future value of the account to be $640, the interest rate is 3.5% (or 0.035 as a decimal), and the time is 9 years. We can substitute these values into the formula and solve for P:

640 = \(Pe^(^0^.^0^3^5^*^9^)\)

640 = Pe^0.315

P =\(640/e^0^.^3^1^5\)

P = 432.43

Therefore, to have a future value of $640 in 9 years with a continuously compounded interest rate of 3.5%.

For such more questions on invest

https://brainly.com/question/29227456

#SPJ8

Answer:

80,000 + 6,000 + 500 + 3

Step-by-step explanation:

Expand so that all non-zero digits are by itself. Remember to retain it's place value:

86503 = 80,000 + 6,000 + 500 + 3

~

Answer:

d is the correct option

Step-by-step explanation:

when powers are raised to powers

they got multiplied

Answer:

Step-by-step explanation:

NOTE:

   \((x^p)^q=x^{p\times q}\)

As a result of this law the correct solution is (d). )

first off, let's take a peek at the picture above

hmmm the hyperbola is opening sideways, that means it has a horizontal traverse axis, it also means that the positive fraction will be the one with the "x" variable in it.

now, the length of the horizontal traverse axis is 4 units, from vertex to vertex, that means the "a" component of the hyperbola is half that or 2 units, and 2² = 4, with a center at the origin.

\(\textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{(x- 0)^2}{ 2^2}-\cfrac{(y- 0)^2}{ (\sqrt{3})^2}=1\implies {\Large \begin{array}{llll} \cfrac{x^2}{4}-\cfrac{y^2}{3}=1 \end{array}}\)

The average is 40 and  the margin of error is 10.95.

What is margin of error?

The margin of error is a statistic expressing the amount of random sampling in the result of a survey.

Average (A) = sum of all the value/ given set.

A = (51+ 41 + 28)/3 = 40

margin of error = 100/square root of 120 = 10.95.

Therefore, the average is 40 and  the margin of error is 10.95.

Learn more about margin of error here:

https://brainly.com/question/31154636

#SPJ1

By conducting mathematical operations, we know that John's gross pay will be $1,012 if he works 44 hours a week.

A mathematical "operation" is the process of calculating a value utilizing operands and a math operator.

The supplied operands or integers must adhere to a set of predefined rules that are connected to the symbol of the math operator.

The order of operations refers to the rules that specify how to solve an expression including many operations.

Parentheses, Exponents, Multiplication, Division, Addition, and Subtraction are all referred to as PEMDAS (from left to right).

So, we know that:

John earns $22 per hour for the first 40 hours of a week.

After every additional hour, he earns 1.5 times $22 each hour.

22 * 1.5 = $33

So, John's gross pay if he worked 44 hours will be:

22*40 + 33*4

880 + 132

$1,012

Therefore, by conducting mathematical operations, we know that John's gross pay will be $1,012 if he works 44 hours a week.

Know more about mathematical operations here:

brainly.com/question/28937023

#SPJ4

The probabilities is as follows:

a) P(Z \(\leq\) -1.0) = \(\Phi\)(-1.0) = 0.1587.

b) P(Z \(\geq\) -1.0) = 1 - P(Z < -1.0) = 1 - 0.1587 = 0.8413.

c) P(Z \(\geq\) -1.5) = 1 - P(Z < -1.5) = 1 - \(\Phi\)(-1.5) = 1 - 0.0668 = 0.9332.

d) P(Z \(\geq\) -2.5) = 1 - P(Z < -2.5) = 1 - \(\Phi\)(-2.5)=1-0.0062=0.9938

e) P(-3 < Z \(\leq\) 0) = P(Z \(\leq\) 0) - P(Z < -3) = \(\Phi\)(0) - \(\Phi\)(-3) = 0.5 - 0.0013 = 0.4987.

The standard normal distribution, commonly known as the z-distribution, is a unique type of normal distribution in which the mean and standard deviation are both equal to 1.

Any normal distribution can be made into the conventional normal distribution by converting the ad hoc data into z-scores. Z-scores in a z-distribution show the number of standard deviations that each value deviates from the mean.

Let Z be a random variable following N(0,1).

Then, Z is also called a standard normal variable.

The cumulative distribution function of Z exists represented by Ф(.) where Ф(z) = P(Z \(\leq\) z).

Suppose we wish to find \($P(a \leq X \leq b)$\).

Then, P(a \(\leq\) X \(\leq\) b) = P(X \(\leq\) b) - P(X < a) = \(\Phi(b)-\Phi(a)$\).

Suppose \($Z \sim N(0,1)$\).

a) P(Z \(\leq\) -1.0) = \(\Phi\)(-1.0) = 0.1587.

b) P(Z \(\geq\) -1.0) = 1 - P(Z < -1.0) = 1 - 0.1587 = 0.8413.

c) P(Z \(\geq\) -1.5) = 1 - P(Z < -1.5) = 1 - \(\Phi\)(-1.5) = 1 - 0.0668 = 0.9332.

d) P(Z \(\geq\) -2.5) = 1 - P(Z < -2.5) = 1 - \(\Phi\)(-2.5)=1-0.0062=0.9938

e) P(-3 < Z \(\leq\) 0) = P(Z \(\leq\) 0) - P(Z < -3) = \(\Phi\)(0) - \(\Phi\)(-3) = 0.5 - 0.0013 = 0.4987.

To learn more about Standard normal distribution refer to:

https://brainly.com/question/4079902

#SPJ1

The savings plan balance after 2 years with an APR of 6% and monthly payments of $150 is approximately $3,814.79.

What are payments?

In compensation for products or services received or to fulfill a legal duty, payment is the voluntarily given exchange of money, its equivalent, or other valuables from one person to another. Frequently, the individual giving the money is referred to as the payer, while the person receiving it is referred to as the payee.

Assuming that the payments are made at the end of each month, we can use the formula -

\(A = PMT\Bigg[\frac{\big(1+\frac{APR}{n}\big)^{nY}-1}{\frac{APR}{n}}\Bigg]\)

where -

A = the savings plan balance after 2 years

PMT = the monthly payment ($150)

APR = the annual percentage rate (6%)

n = the number of compounding periods per year (12, since the payments are made monthly)

Y = the number of years (2)

Plugging in the values, we get -

\(A = 150\Bigg[\frac{\big(1+\frac{0.06}{12}\big)^{12 \times 2}-1}{\frac{0.06}{12}}\Bigg]\)

A ≈ $3,814.79

Therefore, value is obtained as $3,814.79.

To learn more about payments from the given link

https://brainly.com/question/29475683

#SPJ1

Answer:

The correct option - Figure A

Step-by-step explanation:

The exact question is as follows :

Given - Royce kept track of the inches of snowfall in his town over a 15-day period. Royce's data is given below.

1, 0, 0, 3, 5, 0, 0, 0, 2, 2, 1, 7, 2, 2, 3

To find - Which box plot shows this data set?

Solution -

Given the data is -

1, 0, 0, 3, 5, 0, 0, 0, 2, 2, 1, 7, 2, 2, 3

Firstly,

Arrange the data from smallest to largest

0, 0, 0, 0, 0, 1, 1, 2, 2, 2, 2, 3, 3, 5, 7

Now,

Find the median

Median is the middle value - i.e. (15 + 1)/2 = 8th value

So, we get Median = 2

Now,

Find the Quartile -

The first quartile is the median of the data points to the left of the median.

i.e. Median of 0, 0, 0, 0, 0, 1, 1

so, we get

Q1 = 0

The third quartile is the median of the data points to the right of the median.

i.e. Median of 2, 2, 2, 3, 3, 5, 7

so, we get

Q3 = 3

Now,

Compute the min and the max

Minimum value = 0

Maximum value - 7

So,

five number summary is -

0, 0, 2, 3, 7

And we draw the box as follows -

So,

The correct option - Figure A

ATQ

\(\\ \sf\longmapsto R+B+G=10\)

\(\\ \sf\longmapsto 6+2+2=10\)

\(\\ \sf\longmapsto 4+1+1=5\)

Now

Two of same colour so we need P(R')

\(\\ \sf\longmapsto P(R')=\dfrac{|R|}{|S|}\)

\(\\ \sf\longmapsto \dfrac{4}{10}\)

\(\\ \sf\longmapsto 0.4\)

The rate at which the depth of the liquid is increasing when the depth of the liquid reaches one-third of the height of the bowl is 1.25 cm s⁻¹.

The volume of the liquid in the bowl is given by the following integral:

\(V = \int\limitsx_{0}^{h} \, \pi r^{2}(y) dy\)

where r = radius of the bowl and y = height of the liquid.

The radius of the bowl is equal to the distance from the curve y = (4/(8-x)) - 1 to the y-axis. This can be found using the following equation:

r = √{(4/(8-x)) - 1}² + 1²

The height of the liquid is equal to the distance from the curve y = (4/(8-x)) - 1 to the x-axis. This can be found using the following equation:

h = (4/(8-x)) - 1

Substituting these equations into the volume integral:

\(V = \int\limitsx_{0}^{h } \, \pi {\sqrt{(4/(8-x)) - 1)^{2} + 1^{2} (4/(8-x))} - 1 dy\)

Evaluate this integral using the following steps:

Expand the parentheses in the integrand.

Separate the integral into two parts, one for the integral of the square root term and one for the integral of the linear term.

Integrate each part separately.

The integral of the square root term can be evaluated using the following formula:

\(\int\limits^{b} _{a} \, dx \sqrt{x} dx = 2/3 (x^{3/2}) |^{b}_{a}\)

The integral of the linear term can be evaluated using the following formula:

\(\int\limits^{b} _{a} \, {x} dx = (x^{2/2}) |^{b}_{a}\)

Substituting these formulas into the integral:

V = π { 2/3 (4/(8-x))³ - 1/2 (4/(8-x))² } |_0^h

Evaluating this integral:

V = π { 16/27 (8-h)³ - 16/18 (8-h)² }

The rate of change of the volume of the liquid is given by:

dV/dt = π { 48/27 (8-h)² - 32/9 (8-h) }

The rate of change of the volume of the liquid is 7π cm³ s⁻¹. Also the depth of the liquid is one-third of the height of the bowl. This means that h = 2/3.

Substituting these values into the equation for dV/dt:

dV/dt = π { 48/27 (8-2/3)² - 32/9 (8-2/3) } = 7π

Solving this equation for the rate of change of the depth of the liquid:

dh/dt = 7/(48/27 (8 - 2/3)² - 32/9 (8 - 2/3)) = 1.25 cm s⁻¹

Therefore, the rate at which the depth of the liquid is increasing when the depth of the liquid reaches one-third of the height of the bowl is 1.25 cm s⁻¹.

Find out more on linear equations here: https://brainly.com/question/14323743

#SPJ1

1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)

2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)

3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)

4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)

5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)

6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)

7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)

8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)

9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)

10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)

11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)

12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)

13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)

14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)

Here are the journal entries for the given transactions:

1. Bricks and timber purchased for construction:

Debit: Bricks (Asset) - Rs 60,000

Debit: Timber (Asset) - Rs 35,000

Credit: Bank (Liability) - Rs 95,000

2. Transfer to fixed deposit account:

Debit: Fixed Deposit (Asset) - Rs 13,000

Credit: Current Account (Asset) - Rs 13,000

3. Appointment of Mr. S.N. Rao as Accountant:

Debit: Salary Expense (Expense) - Rs 300

Debit: Security Deposit (Asset) - Rs 1,000

Credit: Accountant (Liability) - Rs 300

4. Goods sold to Shruti:

Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000

Credit: Sales (Income) - Rs 80,000

5. Goods purchased from Richa:

Debit: Purchases (Expense) - Rs 60,000

Credit: Accounts Payable - Richa (Liability) - Rs 60,000

6. Goods sold to Shilpa:

Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000

Credit: Sales (Income) - Rs 50,000

7. Goods sold to Garima:

Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000

Credit: Sales (Income) - Rs 1,00,000

8.Purchase of land:

Debit: Land (Asset) - Rs 2,00,000

Debit: Brokerage Expense (Expense) - Rs 2,000

Debit: Registration Charges (Expense) - Rs 15,000

Credit: Bank (Liability) - Rs 2,17,000

9. Goods and cash taken away by proprietor:

Debit: Proprietor's Drawings (Equity) - Rs 65,000

Credit: Goods (Asset) - Rs 25,000

Credit: Cash (Asset) - Rs 40,000

10. Goods sold to Charu:

Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000

Credit: Sales (Income) - Rs 1,20,000

Credit: Cost of Goods Sold (Expense) - Rs 80,000

Credit: Profit on Sales (Income) - Rs 40,000

11. Rent paid for the building:

Debit: Rent Expense (Expense) - Rs 60,000

Credit: Bank (Liability) - Rs 60,000

12. Goods sold to Sunil:

Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000

Credit: Sales (Income) - Rs 24,000

Credit: Cost of Goods Sold (Expense) - Rs 20,000

Credit: Profit on Sales (Income) - Rs 4,000

13. Goods purchased from Nanda and supplied to Helen:

Debit: Purchases (Expense) - Rs 1,000

Debit: Accounts Payable - Nanda (Liability) - Rs 1,000

Credit: Accounts Receivable - Helen (Asset) - Rs 1,300

Credit: Sales (Income) - Rs 1,300

14. Goods received from Rohit and Sons and supplied to Madan:

Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)

Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700

Debit: Accounts Receivable - Madan (Asset) - Rs 3,000

Credit: Sales (Income) - Rs 3,000

for such more question on journal entries

https://brainly.com/question/28390337

#SPJ8

A perfect square refers to a number that is the result of multiplying an integer by itself. In this case, 6^1 is equal to 6.

However, 6 is not a perfect square because it cannot be obtained by multiplying an integer by itself. The perfect squares up to 6^1 would be 1^2 = 1 and 2^2 = 4.

Answer:The answer is B

x=0.75

I’m not sure though

Step-by-step explanation:

The corresponding areas under the curves for y = 2x-x² in the interval [1, 2] and y = x³-6x²+8x in the interval [0, 4] are 2/3 unit² and 0 unit²

Given:

1. y = 2x-x² in the interval [1, 2]

2. y = x³-6x²+8x in the interval [0, 4]

In order to find  the area under the curve for these functions for the given intervals, we will take the integral of the functions and use the intervals as upper and lower limits: Thus:

y = 2x-x² in the interval [1, 2]  will be:

\(\int\limits^2_1 {2x-x^{2} } \, dx = \left[\frac{ 2x^2}{2}-\frac{ x^3}{3}\right]_1^2\)

                   \(= \left[x^{2} -\frac{ x^3}{3}\right]_1^2\)

Substitute the value of the upper and lower limits into x:

               =  [2²- 2³/3] - [1²- 1³/3]

              =   [4 - 8/3] - [ 1 - 1/3]

              =   [4/3] - [2/3]

              = 2/3 unit²

y = x³-6x²+8x in the interval [0, 4] will be:

 \(\int\limits^4_0 {x^{3} -6x^{2} + 8x } \, dx = \left[\frac{ x^4}{4}-\frac{ 6x^3}{3}+\frac{ 8x^2}{2}\right]_0^4\)

                               \(= \left[\frac{ x^4}{4}- 2x^3+4x^2\right]_0^4\)

                              = [4⁴/4 - 2(4)³ + 4(4)²] - [0⁴/4 - 2(0)³ + 4(0)²]

                              =  [ 64 - 128 + 64] - [0 - 0 -0]

                              = 0 unit²

Therefore, the areas under the curves y = 2x-x² in the interval [1, 2]

and y = x³-6x²+8x in the interval [0, 4] are 2/3 unit² and 0 unit² respectively

Learn more about area under the curve on:

https://brainly.com/question/20733870

#SPJ1

1) The sculptor created a marble basin with an approximate volume of 94,509.6 cubic centimeters -  Option D, 2) The approximate area of the heart-shaped cake is 283 square inches - Option B, 3) The length of the wooden frame around the window is 94.3 inches - Option B.

In this question we should make use of geometric formulas for volumes and areas and key information from statement in order to find the right choices.

1) In this case, the volume occupied by the marble water basin (\(V\)), in cubic centimeters, by subtracting the volume of the hemisphere from the volume of the cylinder:

\(V = \pi\cdot R^{2}\cdot h - \frac{2\pi}{3} \cdot r^{3}\) (1)

Where:

If we know that \(R = 30\,cm\), \(h = 45\,cm\) and \(r = 25\,cm\), then the volume of the marble is:

\(V = \pi \cdot (30\,cm)^{2}\cdot (45\,cm) - \frac{2\pi}{3}\cdot (25\,cm)^{3}\)

\(V \approx 94509.579\,cm^{3}\)

The right choice is D.

2) To determine the approximate surface area of the cake covered in red frosting (\(A_{s}\)), in square inches, we need to find the sum of the surface area of the entire circle and the surface area of the square:

\(A_{s} = l^{2} + 2\cdot l\cdot h + \frac{\pi}{4}\cdot D^2 + \pi \cdot D\cdot h\) (2)

Where:

If we know that \(l = 9\,in\), \(h = 3\,in\) and \(D = 9\,in\), then the approximate area covered in red frosting:

\(A_{s} = (9\,in)^{2} + 2\cdot (9\,in)\cdot (3\,in) + \frac{\pi}{4}\cdot (9\,in)^{2} + \pi \cdot (9\,in)\cdot (3\,in)\)

\(A_{s} \approx 283.440\,in^{2}\)

The right choice is B.

3) The frame around the window is found by means of the following perimeter formula (\(s\)), in inches:

\(s = \pi\cdot r + 2\cdot h + 2\cdot r\) (3)

Where:

If we know that \(r = 9\,in\) and \(h = 24\,in\), then the length of the frame around the window is:

\(s = \pi\cdot (9\,in) + 2\cdot (24\,in) + 2\cdot (9\,in)\)

\(s \approx 94.274\,in\)

The right choice is B.

We kindly invite to see question on volumes: https://brainly.com/question/1578538

Answer: A 95% lower confidence bound for the mean capacity of this type of battery = 175.85

Step-by-step explanation:

Given: The capacities were measured for a sample : n= 120 batteries.

\(\overline{x}=178\) and  \(\sigma=12\)

lower confidence bound= \(\overline{x}-z^c\times\dfrac{\sigma}{\sqrt{n}}\)

Critical z value for 9%% confidence = 1.96

So,  a 95% lower confidence bound for the mean capacity of this type of battery will be :

\(178-(1.96)\dfrac{12}{\sqrt{120}}\\\\=178-(1.96)(1.0954451)\\\\=(1.96)(1.0954451)\approx175.85\)

Hence, a 95% lower confidence bound for the mean capacity of this type of battery = 175.85

Answer:

-923

Step-by-step explanation:

Answer:

4608

Step-by-step explanation:

answer is 4,608

6+2 = 8, 8^3 = 512, 512*9 = 4608

Answer:

\(5x\leq 20\)

\($4\) \(dollars\)

Step-by-step explanation:

For the first question, since the maximum cost is $20, it has to be \(5x\leq 20\) because less than or equal to 20 is the maximum.

For the second question, we solve:

\(5x\leq 20\)

\(\frac{5x}{5} \leq \frac{20}{5}\)

\(x\leq 4\)

\(Answer\) \(is\)\(:\) \(4\) \(dollars\)

Answer:

110 hours

Step-by-step explanation:

just you have to solve this and you willl get tge answer

#BRAINLIEST

#CARRYONLEARNING

Answer:

Step-by-step explanation:

You want to identify the given shapes as a regular or irregular polygon, or neither.

A regular polygon is one that has all sides congruent, and all interior angles congruent. Polygon E is marked as having congruent sides and congruent angles.

Polygon E is a regular polygon.

A polygon is a closed figure formed by line segments connected end-to-end. A simple polygon is one that has no intersecting line segments. A convex polygon is one that has all interior angles measuring 180° or less.

Any simple polygon that is not a regular polygon is an irregular polygon.

Polygons A, B, D are irregular polygons.

A circle is not a polygon. Figure C is neither a regular polygon nor an irregular polygon.

<95141404393>

The length of the hypotenuse is 7m.

Let the side opposite to 30° be the shortest leg.

The side opposite to 60° is the longest leg.

So, the side opposite to 90° is hypotenuse.

Length of the shortest side is x.

Length of longest side is \(\sqrt{3}x\)

Length of the hypotenuse is 2x.

We know x = 7

So, \(\sqrt{3}(x)=\sqrt{3}(7)\)

Thus, the length of the longer leg is \(\sqrt{3}(7)\) m

Length of hypotenuse = 2x = 2(7) = 14m

\(x^{2} +(\sqrt{3} x)^2 =(2x)^2\\\\(7)^2+(\sqrt{3} (7))^2=(2x)^2\\\\49 + (3(49)) = (2x)^2\\\\49 + 147= (2x)^2\\\\(2x)^2=196\)

Taking square root on both sides:

\(2x = \sqrt{196}\)

2x = 14

x = 7

Therefore, the length of the hypotenuse is 7m.

Learn more about Triangle at:

https://brainly.com/question/2773823

#SPJ1

The probability of a student being signed up for Algebra 2 but not Chemistry is 0.54 or 54%.

Probability is a way to gauge how likely or unlikely something is to happen. It is a number between 0 and 1, where 0 denotes an impossibility and 1 denotes a certainty for the event.

To find P(Algebra 2 ∩ Not Chemistry), we need to look at the number of students who are signed up for Algebra 2 but not Chemistry. From the table, we can see that there are 260 students who are signed up for Algebra 2 and not Chemistry.

P(Algebra 2 ∩ Not Chemistry) = number of students signed up for Algebra 2 and not Chemistry / total number of students

= 260 / 480

= 0.54

Therefore, the probability of a student being signed up for Algebra 2 but not Chemistry is 0.54 or 54%.

So the answer is 0.54.

To know more about probability visit:

https://brainly.com/question/29221515

#SPJ1

Answer:

D: 14.5

Step-by-step explanation:

4.1 = d - 10.4    add 10.4 to each side

14.5 = d

Answer:

14.5

Step-by-step explanation:

10.4 - 4.1 = 14.5