In many residential water systems, the aqueous Fe³⁺concentration is high enough to stain sinks and turn drinking water light brown. The iron content is analyzed by first reducing the Fe³⁺ to Fe²⁺ and then titrating with MnO₄⁻ in acidic solution. Balance the skeleton reaction of the titration step:\mathrm{Fe}^{2+}(a q)+\mathrm{MnO}_{4}^{-}(a q) \longrightarrow \mathrm{Mn}^{2+}(a q)+\mathrm{Fe}^{3+}(a q)

The pH of an aqueous solution is 11.11

The pH scale, which previously stood for "potential of hydrogen," is used to describe how acidic or basic an aqueous solution is. The pH values of acidic solutions are typically lower than those of basic or alkaline solutions.

            CN-  + H2O ↔ HCN  + OH-

initial  0.09                        0          0

change -X                        +X          +X

Equ    (0.09-X)                    X            X

so from the equilibrium equation, we can get Ka expression

when Ka = [HCN] [OH-]/[CN-]

when Ka = Kw/Kb

              = (1 x 10^-14) / (4.9 x 10^-10)

              = 2 x 10^-5

So, by substitution:

2 x 10^-5 = X^2 / (0.09 - X)

X= 0.0013

∴ [OH] = X = 0.0013

∴ POH = -㏒[OH]

           = -㏒0.0013

           = 2.886

∴ PH = 14 - POH

        = 14 - 2.886 = 11.11

to learn more about pH go to -

https://brainly.com/question/12609985

#SPJ4

Answer:

cause pollution on a small scale can make big difference......

Explanation:

factory isn't a single source of pollution

there are many more.....

Answer:

1 not

2 not

3 not

4 balanced

5 not

6 not

7 balanced

Explanation:

the amount of elements must be equal in the reactant and products

The molarity of the acid is given, so the number of moles titrated can be calculated: 0.050 L × 6 mol/L = 0.3 moles of strong acid added thus ...

A strong acid-strong base titration is used to determine the concentration of an acidic solution by titrating it with a known concentration of a basic solution, or vice versa, until neutralisation occurs. Because both the acid and base are strong (high Ka and Kb values), they will fully dissociate, which means that all the molecules of acid or base will separate into ions. Equivalent amounts of H+ and OH- ions combine to form H2O at the equivalence point, resulting in a pH of 7.0. (neutral).

In aqueous solution, an acid that has been completely ionised. In contrast to a weak acid, when a strong acid is placed in a solution such as water, all of the strong acid dissociates into its ions. The general equation for strong acid dissociation is:

HA(aq)→H+(aq)+A−(aq)

The H stands for hydrogen, and the A stands for the acid's conjugate base (anion).

A base that is completely ionized in aqueous solution. This means when the strong base is placed in a solution such as water, all of the strong base will dissociate into its ions. The general equation of the dissociation of a strong base is:

XOH(aq)→X+(aq)+OH−(aq)

The OH represents hydroxide and the X represents the conjugate acid (cation) of the base.

To learn more about titration equation refer to:https://brainly.com/question/19556786

#SPJ4

Explanation:

hrhrbdbc hdbdbdhdbdbdbdebebebrbbrbrdbbc bf bdvdbf bdbdbdbdbdhdhdhdhdhdhdhdhdhdhdhdhdhdhdhdhdhdhdgdgdggdgdgddgdhdhdhdhdhddgghdhdgdhdhdhhdhdhdhhdgdgdhdgdgdhdhdgfhfhdv dvdvvvdvdvdvdvddvdvfvdvfgddgfvvgdhhdvdvdvdgfvdhfdvdddhdhfh ddhfhdddhdhhdhfhfhfhhdhdhdhvffv

The different allotropes of carbon are graphite, nanotubes, fullerenes, and diamond.

Graphite is an allotrope of carbon where carbon atoms are arranged in sheets, forming a two-dimensional hexagonal lattice.

Within each sheet, carbon atoms are covalently bonded to one another by a network of sigma and pi bonds, resulting in a strong and stable structure.

However, these sheets are held together by weak dispersion forces, allowing them to slide over each other easily. This characteristic gives graphite its slippery and lubricating properties. Graphite is an excellent electrical conductor due to the presence of delocalized electrons within the sheets, allowing electricity to flow through the planes.

Learn more about allotropes

brainly.com/question/13904504

#SPJ11

Answer:

15

Explanation:

Because the ratio of copper in the solution is 15

Answer:

1. Anything that has mass and occipies space is called matter.

2. The difference between Living and Non-Living Matter are :

Living Matter :

Non - Living Matter :

3. Atom is the smallest particle from which matter is made up of.

4. The one difference between atoms and Molecules are :

Atoms

Molecules :

Answer:

what even is the question?

Answer:

A. discuss the issue with your instructor.

Explanation:

If a lab experiment is not completed then one should discuss it with their instructor because instructor guides how to perform the experiment and also gives instructions to avoid any mis-happening during experiment.

No one should perform any experiment without their instructor in school or college as it can be dangerous to experiment with chemicals or other experimental devices without any supervision.

Hence, the correct option is "A".

1. The expected theoretical rate of diffusion of Cl- can be calculated based on its molecular weight using Graham's Law of Diffusion. Graham's Law states that the rate of diffusion of a gas is inversely proportional to the square root of its molecular weight. While Cl- is not a gas, the same principle can be applied to its diffusion through a liquid or a membrane.

The molecular weight of Cl- is approximately 35.5 g/mol. If we compare it to the molecular weight of a hypothetical gas with a molecular weight of 1 g/mol (used as a reference), we can calculate the expected rate of diffusion of Cl- as follows:

Rate of diffusion of Cl- = (Molecular weight of reference gas / Molecular weight of Cl-)^(1/2)

Rate of diffusion of Cl- = (1 / 35.5)^(1/2) = 0.188

Therefore, the expected theoretical rate of diffusion of Cl- is approximately 0.188 times the rate of diffusion of the reference gas.

2. Similar to Cl-, the expected theoretical rate of diffusion of Br- can also be calculated based on its molecular weight using Graham's Law. The molecular weight of Br- is approximately 80 g/mol. Using the same equation as before, we get:

Rate of diffusion of Br- = (Molecular weight of reference gas / Molecular weight of Br-)^(1/2)

Rate of diffusion of Br- = (1 / 80)^(1/2) = 0.125

Therefore, the expected theoretical rate of diffusion of Br- is approximately 0.125 times the rate of diffusion of the reference gas.

3. The fact that the rate of transport of a substance into a cell is drastically reduced when the formation of ATP is blocked suggests that the transport system must be a form of active transport. Active transport requires the input of energy (in this case, ATP) to move substances against their concentration gradient, from an area of low concentration to an area of high concentration. This process is in contrast to passive transport, which does not require energy and moves substances down their concentration gradient, from an area of high concentration to an area of low concentration.

4. To calculate the rate of diffusion of ferricyanide, we need to use the formula:

Rate of diffusion = Distance traveled / Time taken

We can use the distance between the outer edge of the ferricyanide well and the precipitation band, divided by the distance from the Ag well to the precipitation band with ferricyanide to calculate the rate of diffusion of ferricyanide. However, we are not provided with the time taken for the diffusion.

Learn more about ferricyanide here:

https://brainly.com/question/30903018

#SPJ11

If the conversion of glucose to \(CO_2\) and \(H_2O\) in the body is 90% complete, then the volume of  \(O_2\) consumed would be 0.745 L x 0.9 = 0.671 L (rounded to three significant figures).

The balanced equation for the reaction of glucose (C6H12O6) with oxygen ( \(O_2\)) in the body is:

\(C_6H_{12}O_6 + 6O_2\) → 6 \(CO_2\)  + \(6H_2O\) + energy

According to the equation, 1 mole of glucose reacts with 6 moles of  \(O_2\) to produce 6 moles of  \(CO_2\)  and 6 moles of  \(O_2\) Therefore, to determine the volume of  \(O_2\) consumed, we need to calculate the moles of glucose and the moles of  \(O_2\) consumed.

Calculate the moles of glucose:

moles of glucose = mass of glucose / molar mass of glucose

moles of glucose = 1 g / 180.16 g/mol

moles of glucose = 0.00555 mol

Calculate the moles of  \(O_2\) consumed:

moles of  \(O_2\) = 6 x moles of glucose

moles of  \(O_2\) = 6 x 0.00555 mol

moles of  \(O_2\) = 0.0333 mol

Calculate the volume of  \(O_2\) consumed at STP (standard temperature and pressure, which is 0°C and 1 atm):

volume of  \(O_2\) = moles of  \(O_2\) x molar volume at STP

molar volume at STP = 22.4 L/mol

volume of  \(O_2\) = 0.0333 mol x 22.4 L/mol

volume of \(O_2\) = 0.745 L

Learn more about glucose visit: brainly.com/question/7224754

#SPJ4

Answer:

16 atm

Explanation:

Answer:

The Lydia Bourouiba is recorded is around more than the 100 sneezes and coughs cases.

Explanation:

Lydia Bouroubia was a mathematical physicist who does experiments on sneezes and coughs. She was a leading expert in coughs and sneezes. Sneezing is a phenomenal activity that occurs in our body to excrete the dust particles and germs.

The disease also spread through it. Lydia thought that her research will help people related to their health. It will help in stopping epidemics in public. It is a type of outbreak of disease at a bigger level in the public.

Answer:

Letter B.

Explanation:

Changing its direction and climbing a steep incline can't be proven only by the graph info. You can see that it's speed isn't constant in the graph.

We have letter B left.

Answer:

0.473 moles

Explanation:

(2.85x10e23)/(6.02x10e23) = 0.47342

The following statements is accurate: D.)compound made of a metal and  nonmetal is hydrophilic.

Hydrophilic molecule or portion of molecule is one whose interactions with water and other polar substances are more thermodynamically favorable than interactions with oil or other hydrophobic solvents. They are charge-polarized and capable of hydrogen bonding.

Degree or extent to which molecule attracts water is known as the 'hydrophilicity' of that molecule. Some of the common examples of hydrophilic substances are : sugar, salt, starch, and cellulose.

Hydrophilic means that it tends to be attracted to water or that it tends to easily dissolve in, mix with, absorb, or to be saturated by water.

To know more about hydrophilic, refer

https://brainly.com/question/1600542

#SPJ4

As there are \($2.32 \times 10^{-23} \mathrm{~g}$\) nitrogen atoms in 28.02 g of nitrogen, there are the same number of oxygen atoms in the mass of oxygen.

Nitrogen atomic mass \($=14 \mathrm{~g} / \mathrm{mole}$\)

e.g., mass of one mole of \($\mathrm{N}=14 \mathrm{~g}$\)

Contains in 1 mole \($6.022 \times 10^{23}$\) atoms

\($\therefore$\) mass of \($6.022 \times 10^{23}$\) atoms of \($\mathrm{N}=14 \mathrm{~g}$\)

one atom's mass \($\mathrm{N}=\frac{14 \mathrm{~g}}{6.022 \times 10^{23} \text { atoms }}$\)

One N atom has a mass of \($2.32 \times 10^{-23} \mathrm{~g}$\)

Mole of Molecules: One mole is equal to \(6.022 \times10^{23}\) molecules, or the molecular mass of one gram of any given substance. As a result, 1 mole of oxygen weighs 32 grams and has \(6.022 \times10^{23}\) molecules in it. A mole of water weighs 18 grams and has \(6.022 \times10^{23}\) molecules in it.

In 28 g of nitrogen, there are 2 moles. In order to find the number of molecules in one mole of oxygen, we will multiply 9.03 times 10 to the 23 molecules of oxygen, then by the molar mass of oxygen, which is 32.00 g of oxygen. This will give us 48.0 g of oxygen, which has the same number of molecules as one mole. As 42 g

To learn more about molecules refer to :

https://brainly.com/question/475709

#SPJ4

Answer:

An air mass is a large mass of air that has similar characteristics of temperature and humidity within it. An air mass acquires these characteristics above an area of land or water known as its source region. When the air mass sits over a region for several days, or longer, it picks up the distinct temperature and humidity characteristics of that region.

Explanation:

Three moles of sulfur dioxide are required to produce 1 mole of sulfur, thus 15.0 moles of sulfur dioxide are required to produce 5.0 moles of sulfur.

The balanced equation is SO₂ + 2H₂S → 3S + 2H₂O. In this equation, three moles of sulfur dioxide react with two moles of hydrogen sulfide to produce three moles of sulfur and two moles of water. From the balanced equation, we can see that three moles of sulfur dioxide are required to produce 1 mole of sulfur.

Therefore, to calculate how many moles of sulfur dioxide are required to produce 5.0 moles of sulfur, we multiply the number of moles of sulfur by three. 5.0 moles of sulfur x 3 moles of SO₂/mole of S = 15.0 moles of sulfur dioxide. Thus, 15.0 moles of sulfur dioxide are required to produce 5.0 moles of sulfur.

Learn more about moles here:

https://brainly.com/question/30885025

#SPJ11

The energy that drives the hydrologic (water) cycle primarily comes from the sun.

The sun's energy is responsible for fueling various processes within the cycle, such as evaporation, condensation, and precipitation.

When the sun heats the Earth's surface, water from oceans, lakes, rivers, and other bodies of water evaporates and turns into water vapor. This vapor rises into the atmosphere, where it cools and condenses into clouds. The clouds, composed of tiny water droplets or ice crystals, eventually become heavy enough for the water droplets to fall as precipitation (rain, snow, sleet, or hail).

The precipitation replenishes the Earth's water bodies and provides moisture to the land, enabling plant growth and supporting life. Some water soaks into the ground and becomes part of the groundwater system, while other water flows over the surface as runoff, eventually making its way back to oceans, lakes, and rivers.

The hydrologic cycle is essential for maintaining Earth's water balance and supporting ecosystems. It is a continuous process, powered by solar energy, that redistributes water across the planet, ensuring that the natural resources necessary for life are available to all living organisms.

Learn more about hydrologic cycle here: https://brainly.com/question/2164391

#SPJ11

The first six terms of the sequence, defined by the nth term formula \((-1)^n/(2n + 5)\), are calculated and listed as -1/7, 1/9, -1/11, 1/13, -1/15, and 1/17.

To find the first six terms of the given sequence, we can substitute values for n into the formula (-1)^n/(2n + 5) and simplify the expression. Let's calculate the values for n = 1, 2, 3, 4, 5, and 6:

For n = 1:

\((-1)^1/(2(1) + 5) = -1/7\)

For n = 2:

\((-1)^2/(2(2) + 5) = 1/9\)

For n = 3:

\((-1)^3/(2(3) + 5) = -1/11\)

For n = 4:

\((-1)^4/(2(4) + 5) = 1/13\)

For n = 5:

\((-1)^5/(2(5) + 5) = -1/15\)

For n = 6:

\((-1)^6/(2(6) + 5) = 1/17\)

Therefore, the first six terms of the sequence are -1/7, 1/9, -1/11, 1/13, -1/15, and 1/17.

Learn more about sequences here:

https://brainly.com/question/30262438

#SPJ11

Answer:

7,5km/h

Explanation:

Average speed = total distance travelled/time taken

Average speed = 15/2

Average speed = 7,5km/h

(This should be in physics/maths not Chemistry)

Shale is a type of sedimentary rock that is formed from the accumulation of clay and silt-sized particles.

A rock's mass-spectrum is a graph that shows the relative abundance of each element present in a rock sample. The graph is created by using a mass spectrometer, an instrument that separates the different elements in a sample by their atomic mass. The resulting graph shows the relative abundance of each element as a peak, with the height of the peak representing the concentration of that element.

From the first attachment

The Cambrian period, which occurred around 540 million years ago, is known for the development and diversification of various forms of life,  The rocks from this period are typically composed of shallow marine sandstones and shales, with some limestone formations. The mass-spectrum of these rocks would likely show a high concentration of calcium and carbon, as well as traces of other elements such as silicon and oxygen.

The Ordovician period, which occurred around 490-443 million years ago, is characterized by the diversification of marine life, including the first appearance of fish and the diversification of brachiopods, bryozoa, and corals. The rocks from this period are typically composed of shallow marine sandstones and shales. The mass-spectrum of these rocks would  show a high concentration of calcium and carbon,

The Silurian period, which occurred around 443-416 million years ago, is characterized by the diversification of marine life, including the first appearance of jawed fish and the diversification of coral reef communities.  The mass-spectrum of these rocks would likely show a high concentration of calcium and carbon, as well as traces of other elements such as silicon and oxygen.

The Devonian period, whicoccurred around 416-359 million years ago, is characterized by the diversification of land plants and the first appearance of amphibians. The rocks from this period are typically composed of a mix of marine and terrestrial sediments, including sandstones, shales, and limestones. The mass-spectrum of these rocks would likely show a high concentration of calcium and carbon, as well as traces of other elements such as silicon and oxygen.

The Carboniferous period, which occurred around 359-299 million years ago, is characterized by the diversification of land plants, including the first appearance of trees, and the first appearance of reptiles. The rocks from this period are typically composed of a mix of marine and terrestrial sediments, including sandstones, shales, and coal deposits. The mass-spectrum of these rocks would likely show a high concentration of carbon, as well as traces of other elements such as silicon and oxygen.

The Permian period, which occurred around 299-252 million years ago, is characterized by the diversification of reptiles, including the first appearance of dinosaurs. The rocks from this period are typically composed of a mix of marine and terrestrial sediments, including sandstones, shales, and limestones. The mass-spectrum of these rocks would likely show a high concentration of calcium and carbon, as well as traces of other elements such as silicon and oxygen.

Table C description

Learn more here on Mass spectrum of rocs https://brainly.com/question/30349684

#SPJ1

The primary difference between the oxidation of glucose to CO₂ by glycolysis and the critic acid cycle vs by the pentose phosphate is the glycolysis occurs in cytosol. to CO₂ is release of CO₂ is in mitochondria and in the pentose phosphate CO₂ is generated in the cytosol.

When the glucose oxidation takes place  by glycolysis and the citric acid cycle , the total catabolism will occur. The energy is released and this energy is trapped in ATP. in this glucose is catabolizes. in pentose phosphate  CO₂   is generated in the cytosol.

Thus, The primary difference between the oxidation of glucose to CO₂ by glycolysis and the critic acid cycle vs by the pentose phosphate is the glycolysis occurs in cytosol. to CO₂ is release of CO₂ is in mitochondria and in the pentose phosphate CO₂ is generated in the cytosol.

To learn more about oxidation here

https://brainly.com/question/9496279

#SPJ4

Answer:

a) Secretion of unpleasant liquids which make them distasteful.

Possession of spines or thorns or irritating hairs which cause pain or irritation on contact.

Possession of poisonous parts which cause pain or itching or death or swelling on contact.

b) An anion is a negatively charged atom (or group of atoms).

OR

An anion is an ion formed when an atom (or group of atoms) gain electrons.

c) i. NH4OH and dilute HCL.

= Ammonium chloride, water

ii. CACO3 and dilute HCL.

= Calcium chloride, water, carbon dioxide or carbon (IV) oxide.

Hope it helps. Please mark as brainliest.

Explanation:

Same as cherishdisah's answer. Thanks.

The factor that favors attack of 2,6-dimethylaniline (36) at the carbonyl carbon atom rather than the α-carbon atom of α-chloroacetyl chloride is: the greater electrophilicity of the carbonyl carbon due to the presence of the electron-withdrawing chlorine atom.

The electrophilicity of a carbon atom is determined by its electron density. In the case of α-chloroacetyl chloride, the chlorine atom is electron-withdrawing due to its higher electronegativity. This electron-withdrawing effect destabilizes the electron density on the α-carbon atom, making it less electrophilic.

On the other hand, the carbonyl carbon atom in α-chloroacetyl chloride is positively polarized due to the electron-withdrawing effect of both the chlorine atom and the electronegative oxygen atom in the carbonyl group. This increased positive charge on the carbonyl carbon makes it more electrophilic compared to the α-carbon atom.

As a result, 2,6-dimethylaniline (36) preferentially attacks the carbonyl carbon, forming a bond with the carbon atom and displacing the chlorine atom, leading to the formation of an acylated product.

To know more about dimethylaniline, refer here:

https://brainly.com/question/13147442#

#SPJ11

The value of ΔG for this reaction at 298 K when the partial pressures of A and B are 4.60 atm and 0.120 atm, respectively, is -880.15 J/mol.

Given:

Kp = 0.701

Partial pressures: \(P_A\\\) = 4.60 atm, \(P_B\) = 0.120 atm

To calculate the value of ΔG (Gibbs free energy) for the reaction A(g) → 3B(g) at 298 K, the formula:

ΔG = ΔG° + RT × ln(Q)

where:

ΔG is the change in Gibbs free energy

ΔG° is the standard Gibbs free energy change

R is the gas constant (8.314 J/(mol·K))

T is the temperature in Kelvin

ln is the natural logarithm

Q is the reaction quotient

The reaction quotient Q can be calculated using the partial pressures:

Q = \(\frac{(P_B)^3}{P_A}\)

Plugging in the values:

Q = \(\frac{(0.120)^3}{(4.60 atm)}\)

Q = 0.0000375

Now, ΔG:

ΔG = ΔG° + RT × ln(Q)

At equilibrium, ΔG = 0 since the reaction is in a state of minimum energy. Therefore:

0 = ΔG° + RT × ln\((K_p)\)

ΔG° = -RT × ln\((K_p)\)

Plugging in the values:

ΔG° = -8.314 × 298 × ln(0.701)

ΔG° = -880.15 J/mol

Learn more about partial pressure, here:

https://brainly.com/question/30114830

#SPJ12

The pH of a 0.300 M formic acid solution is  0.0073.

The acid dissociation constant determines the difference between strong and weak acids (Ka). Extremely high Ka values are present in strong acids. The Ka value can be found by looking at the equilibrium constant for the dissociation of the acid. The Ka increases as the acid dissociates more.

PKₐ value is 1.80 × 10⁻⁴

The concentration of formic acid (HCOOH) is 0.300 M.

HCOOH + H₂O ⇄ ⁻(HOOC⁻) + H₃O⁺

(0.300) (x) (x)

Let x represent the concentration of H⁺ that dissociates from HCOOH (formic acid), then [HCOOH] = 0.050 – x

Kₐ = [H₃O⁺] [HOOC⁻] / [HCOOH]

Kₐ =  1.80 × 10⁻⁴ = x²/0.300x- x

let 0.300 -x = 0.300

x² = 1.80 × 10⁻⁴ × 0.300

x² = 0.54 × 10⁻⁴

x² = 54 × 10⁻⁶

x = 7.3 × 10⁻³

pH = - log [H₃O⁺]

pH = - log [x]

pH = - log [7.3 × 10⁻³]

pH = 0.0073

So,

The pH of a 0.300 M formic acid solution is  0.0073.

To know more about dissociation constant visit:

https://brainly.com/question/28197409

#SPJ4