In her hand, a softball pitcher swings a ball of mass 0.245 kg around a vertical circular path of radius 59.8 cm before releasing it from her hand. The pitcher maintains a component of force on the ball of constant magnitude 30.9 N in the direction of motion around the complete path. The speed of the ball at the top of the circle is 16.0 m/s. If she releases the ball at the bottom of the circle, what is its speed upon release?

Answers

Answer 1

Answer:

The velocity is \(v_b = 20.17 \ m/s\)

Explanation:

From the question we are told that

   The mass of the ball is  \(m = 0.245 \ kg\)

   The radius is  \(r =  59.8 \  cm  =  0.598 \ m\)

   The force is  \(F =  30.9 \ N\)

   The speed of the ball is  \(v = 16.0 \ m/s.\)

Generally the kinetic energy at the top of the circle is mathematically represented as

    \(K_t  =  \frac{1}{2} *  m  *  v^2\)

=> \(K_t  =  \frac{1}{2} *  0.245   *  16.0 ^2\)  

=> \(K_t  =  31.36 \ J\)  

Generally the work done by the force applied on the ball from the top to the bottom  is mathematically represented as

       \(W =  F *  d\)

Here  d is the length of  a semi - circular arc which is mathematically represented as

       \(d =  \pi * r\)

So

      \(W =  30.9 *  0.598  \)

      \(W = 18.48 \ J \)

Generally the kinetic energy at the bottom is mathematically represented as

      \(K_b  =  \frac{1}{2} *  m *  v_b^2\)

=>    \(K_b  =  \frac{1}{2} *  0.245  *  v_b^2\)

=>   \(K_b  =  0.1225  *  v_b^2\)

From the law of energy conservation

     \(K_t +  W  =K_b\)

=>    \(31.36+  18.48 = 0.1225  *  v_b^2\)

=>    \(v_b = 20.17 \ m/s\)


Related Questions

As an electromagnetic wave travels, what is the relationship between the
magnetic field and the electric field along its path?
A. They are parallel to each other.
B. The angle between them decreases with an increase in energy
O C. The angle between them increases with an increase in energy.
D. They are at a 90° angle to each other.

Answers

Answer:

Its D

Explanation:

They are at a 90° angle to each other.

Do good on your tests :]

The answer is D) They are at a 90° angle to each other.

What is an electromagnetic wave?

One of the waves which are propagated with the aid of simultaneous periodic versions of electrical and magnetic subject depth and consists of radio waves, infrared, seen mild, ultraviolet, X-rays, and gamma rays.

Radio waves, microwaves, seen light, and x-rays are all examples of electromagnetic waves that range very differently in wavelength. (a) Longer wavelength; (b) shorter wavelength. Electromagnetic waves are produced by means of the motion of electrically charged debris.

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25. The length of a bow is L. When it vibrates in the fundamental mode with a length of 2 L, the frequency is f. Taking half of the given length and pulling it to a length of 2L as before, the frequency obtained by vibrating in the basic method is,

(i) 3fo

(iv) √3f

(ii) 6fo

(v) √6fo

(iii) f/3​

Answers

Taking half of the given length and pulling it to a length of 2L as before, the frequency obtained by vibrating in the basic method is 6fo. option(ii)

When a bow vibrates in its fundamental mode with a length of 2L, the frequency is denoted as f. Now, let's consider the scenario where half of the given length (L) is pulled to a length of 2L.

In the fundamental mode of vibration, the frequency is inversely proportional to the length of the vibrating object. Therefore, if the length of the bow is halved to L, the frequency would double to 2f.

When this new length of L is pulled to a length of 2L, we need to determine the frequency obtained in the fundamental mode.

Since the frequency is inversely proportional to the length, we can use the inverse relationship to find the new frequency.

If the original frequency was 2f at length 2L, when the length is reduced to L, the new frequency would be (2f)/(2L) = f/L.

Now, if this length of L is stretched to 2L again, the new frequency in the fundamental mode would be (f/L) * (2L) = 2f. option(ii)

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A net force of 275 N accelerates a 18.0 kg mass. What is the resulting acceleration? (5 points)

Answers

Answer:

The answer is 15.28 m/s²

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

where

m is the mass

f is the force

We have

\(a = \frac{275}{18} \\ = 15.277777...\)

We have the final answer as

15.28 m/s²

Hope this helps you

The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?

Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.

Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!

Answers

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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Determine the magnitude as well as direction of the electric field at point A, shown in the above figure. Given the value of k = 8.99 × 1012N/C.

Answers

Answer:

Electric field at A = 9.28 x 10¹² N/C

Explanation:

Given:

K = 8.99 x 10¹² N/C

Missing information:

Length = 11 cm = 11 x 10⁻² m

q = 12.5 C

Find:

Electric field at A

Computation:

Electric field = Kq / r²

Electric field at A = [(8.99 x 10¹²)(12.5)] / [11 x 10⁻²]²

Electric field at A = 9.28 x 10¹² N/C

A skier at the bottom of a hill has 900J of kinetic energy. After sliding a ways along the flat, the kinetic energy is 300J. How much energy was lost due to friction?

Answers

Answer:

600 J

Explanation:

900 j = 300j = 600 j lost due to friction

Energy lost due to friction is 600 J.

The kinetic energy before and after friction is given as 900J and 300J.

What is friction?

   The force that resists the sliding or rolling over one object with another is called friction. The energy which possess in virtue of being in motion is said to be Kinetic Energy.

                                   f = μN

                      Energy lost = 900J - 300J

                                          =  600J

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If a Mack truck and a Honda Civic have a head-on collision, which vehicle will experience the greater force of contact? The greater impulse? The greater change in momentum? The greater acceleration? Discuss how a failure to distinguish between these concepts leads to difficulties in understanding physics!

Answers

The Honda Civic is the car that would have greater impulse, momentum change and acceleration due to Collison.

What is the impact?

The term impulse has to do with the product of force and time. The impact is literally the force that acts on an object for a short time. We know that the mass of the object is very important when we are discussing the impulse on the object.

When there is a  head-on collision that occurs between the  Mack truck and a Honda Civic, the Honda Civic would have the greater impulse and the greater change in momentum and thus the greater acceleration.

If we do not understand the concept of the effect of momentum and the acceleration of an object, we would not be able to understand the basic interaction that occur between objects using the principles of physics.

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A stone is dropped from top of a tower. If it takes 6 sec to hit the ground, find the height of tower and velocity with which the stone hits the ground ?​

Answers

Answer:

Explanation:

s = ut+ 0.5at²

u = 0

t = 6

a = 9.81

s = 0 + 0.5 * 9.81 * 36 = 176.58 m

v = u + at

v = 9.81* 36 = 353 m/s

wavelength = 5.4 cm and frequency = 9.4 Hz
What is the speed

Answers

v = f x λ = 9.4 x 0.054 = 0.51 m/s

2. A kayaker is paddling south at 2.50 m/s, and encounters a weird current moving 1.15 m/s west.
What is the resultant velocity?

Answers

Answer:

v = 2.91 m/s

Explanation:

Given that,

A kayaker is paddling south at 2.50 m/s, and encounters a weird current moving 1.15 m/s west.

We need to find the resultant velocity. Both velocities are perpendicular to each other. So,

\(v=\sqrt{v_1^2+v_2^2} \\\\=\sqrt{2.5^2+1.5^2} \\\\=2.91\ m/s\)

So, the magnitude of the resultant velocity is equal to 2.91 m/s.

When a slab is placed and finished, which of the following operations comes immediately after the concrete is screeded?A). rough gradingB). consolidatingC). bull floatingD). edging and jointingE). finishing with steel trowels

Answers

When a slab is placed and finished, D). Edging and jointing operations come immediately after the concrete is screeded finishing with steel trowels.

Edging and jointing is the operation that comes immediately after the concrete is screeded. Edging and jointing are the processes of using a tool, often a straightedge, to define the edges of the concrete slab and then using a trowel to smooth down the edges. This process is important to ensure that the slab joints and edges are even, level, and free of any air pockets or voids. Additionally, edging and jointing help to create a smoother surface that is less likely to crack or chip. This process should be done as soon as possible after screeding to ensure the best results.

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How wide is the central diffraction peak on a screen 2.30 m behind a 0.0368-mm-wide slit illuminated by 558-nm light

Answers

Answer:

The  value \(y = 0.0349 \ m\)

Explanation:

From the question we are told that

   The  distance of the screen is  \(D = 2.30 \ m\)

   The  width of the slit is  \(d = 0.0368 \ nm = 0.0368 *10^{-3} \ m\)

   The  wavelength is  \(\lambda = 558 \ nm = 558 *10^{-9} \ m\)

The  width of the central diffraction peak is  mathematically represented as

        \(k = 2 * y\)

Where  y is the distance from the center to the high peak which  is mathematically represented as

       \(y = \frac{\lambda * D }{d }\)

substituting values

      \(y = \frac{ 558 *10^{-8} * 2.30 }{0.0368 *10^{-3} }\)

      \(y = 0.0349 \ m\)

A rectangular copper strip 1.5cm wide and 0.10cn thick carries a current of 5.0A. Find the Hall voltage for a 1.2T magnetic field applied in a direction perpendicular to the loop

Answers

Answer:

4.4345× 10^-7V

Explanation:

The computation of the half voltage for a 1.2T magnetic field applied is shown below

The volume of one mole of copper is

v = m ÷p

= 63.5 ÷ 8.92

= 7.12cm

Now the density of free electrons in copper is

n = Na ÷ V

= 6.02 × 10^23 ÷ 7.12

= 8.456× 10^28/m^3

Now the half voltage is

= IB ÷ nqt

= (5 × 1.20) ÷ (8.456× 10^28 × 1.6 × 10^-19 × 0.1× 10^-2)

= 4.4345× 10^-7V

A rectangular copper strip 1.5cm wide and 0.10cn thick carries a current of 5.0A. Find the Hall voltage

What is the Main impact that tsunamis have on humans? (Science)

Answers

Answer:

Explanation:

Tsunamis can have a devastating impact on human populations. The primary impact of a tsunami is the destruction of coastal communities and infrastructure. The powerful waves can inundate low-lying areas, destroying buildings, homes, and infrastructure such as roads, bridges, and ports. The destruction caused by tsunamis can result in the loss of life, injury, displacement, and economic disruption.

Tsunamis can also have secondary impacts on human populations, such as the disruption of essential services like water and electricity, which can exacerbate the already difficult living conditions in affected areas. The destruction of crops and fisheries can also have long-term economic impacts on affected communities.

It is essential to note that the impact of a tsunami can vary greatly depending on a range of factors, such as the size of the wave, the distance from the epicenter of the earthquake that caused the tsunami, and the preparedness and resilience of the affected communities. Therefore, it is crucial to have effective early warning systems and evacuation plans in place to minimize the impact of a tsunami on human populations.


A spherical bowling ball of mass 7 kg and radius 0.18 m rolls down a hill that has a vertical height of 7 m. If the ball started from rest at the top, what is its angular momentum at the bottom of the hill? Use two sig figs.

Answers

Answer:

er so ue 0.984 kg study your self brhh

A bullet is fired horizontally into an initially stationary block of wood suspended by a string and remains embedded in the block. The bullet’s mass is m = 0.0075 kg, while that of the block is M = 0.95 kg. After the collision the block/bullet system swings and reaches a maximum height of h = 1.1 m above its initial height. Neglect air resistance.

Calculate the ratio, expressed as a percent, of the kinetic energy of the block/bullet system immediately after the collision to the initial kinetic energy of the bullet.

KEf/KEi(%) =

Answers

The ratio of the kinetic energy of the block/bullet system immediately after the collision to the initial kinetic energy of the bullet is 0.78 %.

Final velocity of the block/bullet system

Apply the principle of conservation of energy to determine the final velocity of the block/bullet system.

K.E = P.E

¹/₂mv² = mgh

¹/₂v² = gh

v² = 2gh

v = √2gh

where;

h is the maximum height reached by the systemv is the initial velocity of the system

v = √(2 x 9.8 x 1.1)

v = 4.64 m/s

Initial velocity of the bullet

Apply the principle of conservation of linear momentum.

m₁u₁ + m₂u₂ = v(m₁ + m₂)

where;

u₁ is the initial velocity of the bulletu₂ is the initial velocity of the blockv is the final velocity after collisionm₁ is mass bulletm₂ is mass of block

(0.0075)u₁ + (0.95)(0) = 4.64(0.0075 + 0.95)

0.0075u₁ = 4.4428

u₁ = 4.4428/0.0075

u₁ = 592.37 m/s

Initial kinetic energy of the bullet

K.Ei = ¹/₂m₁u₁²

K.Ei = ¹/₂(0.0075)(592.37)²

K.Ei = 1,315.88 J

Final kinetic energy of the block/bullet system

K.Ef = ¹/₂(m₁ + m₂)v²

K.Ef = ¹/₂(0.0075 + 0.95)(4.64)²

K.Ef = 10.31 J

Ratio of final kinetic energy to initial kinetic energy

= K.Ef/K.Ei x 100%

= (10.31 / 1,315.88) x 100%

= 0.78 %

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Which element has the same number of valence electrons as krypton (Kr)?

fluorine (F)

chlorine (Cl)

neon (Ne)

selenium (Se)

Answers

Neon (Ne) Look at the periodic table :)

The element that has the same number of valence electrons as krypton (Kr) is known as Neon (Ne). Thus, the correct option for this question is C.

What are Valence electrons?

Valence electrons may be defined as the number of electrons present in the outermost shell of any atom during the time of electronic configuration. For example, Sodium has an atomic number of 11, its electronic configuration is 2, 8, and 1. It means that the valence electron on sodium is 1.

Neon and Krypton being the members of the same family which is known as noble gases or inert gases occupy the same valence electrons of eight in their outermost shell. It is group 8A of the periodic table. Apart from Ne, and Kr, other elements like argon, Xenon, and Radon also belong to the same family and occupy the same valence electron except for helium.

Therefore, the element that has the same number of valence electrons as krypton (Kr) is known as Neon (Ne). Thus, the correct option for this question is C.

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Predict what will happen to the disk of an uncharged electroscope when a positively charged obsject is brought near the disk.
I said: All of the positive charges in the disk will move towards the vanes in the electroscope, being repelled by the similarly charged obsject. When a positively charged object is brought near the uncharged disk of an electroscope then the positive charges attract the negative charges from the disk and repel positive charges from the disk. So, the unchaged disk will become positively charged.
QUESTION: Continue your previous answer so that you describe what happens to the charge in the other parts of the electroscope. Use this to infer what happens to the vanes.

Answers

When a positively charged object is brought near an uncharged electroscope, the vanes will move apart due to the separation of charge within the electroscope.

As the positive charges in the disk are repelled by the positively charged object and move towards the vanes, the negative charges in the disk are attracted to the positively charged object and move towards it. This creates a separation of charge within the electroscope, with the disk becoming positively charged and the vanes becoming negatively charged. As a result, the vanes will repel each other and move apart. This movement of the vanes is an indication of the presence of charge in the electroscope.

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If the wind bounces backward from the sail, will the craft be set in motion?

Answers

If the wind bounces backward from the sail, the boat will not be set in motion as no forward force is generated. For the boat to move forward, the sail must be positioned to catch the wind and create lift in the desired direction.

If the wind bounces backward from the sail, the craft will not be set in motion. In order for a sailboat to move forward, the wind must push on the sail, creating a force that propels the boat forward through the water. When the wind hits the sail, it creates lift in a direction perpendicular to the sail's surface, which results in a forward force that propels the boat.

However, if the wind bounces backward from the sail, it does not create lift and therefore does not result in a forward force on the boat. Instead, the wind is redirected in a different direction, and the boat remains stationary. In order for the boat to move forward, the sail must be positioned to catch the wind and create lift in the desired direction, propelling the boat forward.

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what is the amount of force required to keep a 6 kg object that is in outer space moving with a constant velocity of 2 m/s is _ N

Answers

The amount of force required is (V) is v(t) = at.

What is velocity?

The speed of something in a given direction. Velocity is the directional speed of to an object in motion as an indication of its rate of the  change in position as in observed from a particular to frame of reference and it's as measured by a particularly standard of time.

Sol-As per the newton's first law of motion.

Vt= vo+at

Here,

velocity at time t is v(t).

Initial velocity is vo.

Acceleration is a and the time is t.

The initial velocity is zero. Put the 0 for vo in above equation.

v(t) = 0+at

v(t)= at

Thus, the acceleration of a falling body (a), the time it takes to fall (t), and its instantaneous velocity when it hits the ground.

(V) is v(t) = at.

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If magma is defined as molten rock material,do you need to melt rocks to form magma?

Answers

Explanation: Magma is molten rock found below the earth's surface. ... On the other hand, if the rocks are under greater pressure, they will require higher temperatures to melt. Melting of rocks typically occurs in the lower lithosphere or upper asthenosphere. The earth gets hot pretty quickly as you dig down from the earth's surface.

calculate the total resistance in the circuit​

Answers

Answer:

The total resistance of a series circuit is equal to the sum of individual resistances. Voltage applied to a series circuit is equal to the sum of the individual voltage drops. The voltage drop across a resistor in a series circuit is directly proportional to the size of the resistor.


If you know the total current and the voltage across the whole circuit, you can find the total resistance using Ohm's Law: R = V / I. For example, a parallel circuit has a voltage of 9 volts and total current of 3 amps. The total resistance RT = 9 volts / 3 amps = 3 Ω.

If a cyclist is traveling along a road due east at 12km/h and wind is blowing from south-west at 5km/h. find the velocity of the wind relative to the cyclist.​

Answers

The velocity of the wind with respect to the cyclist is 9.173 m/s its direction is 67.33⁰ from the southeast.

What is Triangle law?

It states that "when two vectors are represented in a direction and magnitude by two sides of a triangle in the same order then its results will be represented in magnitude and direction of the closing side of the triangle in the opposite order."

then the resultant will be calculated as:

R= \(\sqrt{F1^{2} +F2^{2} +2F1F2cos\alpha }\)

Here in the given question

F1= -12m/s because the wind is opposing the cyclist who is moving with 12m/s so its direction is now east to west.

F2=5m/s

here angle between the two vectors is =45 degrees

now resultant of the vectors are

Vwc=\(\sqrt{(-12^{2}+5^{2} -2*12*5cos(45) }\)

=9.173km/h

Its direction will be applying sine the law

\(\frac{sin(45)}{9.173} =\frac{sine(\alpha) }{12}\)

\(\alpha =\)67.67⁰

now \(\beta =180-75-67.67\)

=67.33⁰

Hence the velocity of wind w.r.t. cyclist is 9.173m/s and its direction is towards the southeast.

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If a cyclist is traveling along a road due east at 12km/h and wind is blowing from south-west at 5km/h.

A big weight *
Alice has picked up a big weight.
Her friends are talking about the forces that hold it steady.
What forces hold the big weight steady?
A It is not moving, so there are no forces.
OB The only force is gravity, pushing it onto Alice's hand.
C The only force is Alice pushing up, to hold it steady.
D Gravity pushes the weight down and Alice pushes it up.
1 point

Answers

Answer:

Gravity pushes the weight down and Alice pushes it up.

Explanation:

In this case, Gravity pushes the weight down and Alice pushes it up. The correct option is D.

what conditions made it possible for earth's interior to separate into layer?

Answers

Answer:

Separation of the Earth into layers (crust, mantle, inner core, and outer core) was largely caused by gravitational differentiation (separating different constituents at temperature where materials are liquid or plastic, owing to differences in density) early in Earth's history.

Explanation:

hoped it helped!!

I drop a meterstick, and my reaction time is 0.2 seconds. How far does the meterstick travel
before I catch it?

Answers

The distance formula used for a falling object is y = 1/2gt^2 where g is gravity which is 9.80m/s^2 and t is the time it falls ( reaction time).

Y = 1/2(9.8)0.2^2

Y = 0.196

It travels 0.196 meters

Mrs. Archer spent her Saturday running a bunch of errands. She started out by
traveling 2 km east, then 5 km south, 12 km east, 2 km south then 40 km west, 60
km north. Calculate her displacement on the Y AXIS.

Answers

Answer:

Velocity = displacement/time whereas speed is distance/time. use the formula

Explanation:

A car starts from rest and accelerates at a constant rate in a straight line. In the first second the car moves a distance of 2.0 meters. How much additional distance will the car move during the second second of its motion?

Answers

Since the car is accelerating at a constant rate, the distance it travels during each second of its motion will be directly proportional to the time it has been accelerating.

In the first second, the car moved a distance of 2 meters, and in the second second, it will move twice the distance of the first second, so the car will move additional distance of 2*2 = 4 meters during the second second of its motion.

The distance traveled during the second second of its motion is 1/2 * 2 = 1 meters.

A car that accelerates at a constant rate will move a distance equal to the initial velocity multiplied by time plus 1/2 the acceleration multiplied by the square of time. Since the car starts from rest, the initial velocity is zero.

Therefore, the distance traveled during the second second is 1/2 * acceleration \(* (time)^2 = 1/2 * a * t^2 = 1/2 * a * 1^2 = 1/2 * a\) Since the car moved 2.0 meters in the first second, it means the acceleration is\(2m/s^2\), and the distance traveled during the second second is 1/2 * 2 = 1 meters.

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What question did use of a telescope by hubble answer A) Is earth the center of the universe B) Is the sun the center of the universe C) How do the planets move in the solar system D) Are there more galaxies beyond the milky way

Answers

Answer: C

Explanation:

The characteristics and problems of telescopes we can find the correct answer to the question that the Hubble telescope helps to answer is:

           D) Are there more galaxies beyond the milky way

Telescopes are instruments that can perceive very small amounts of light and have very large magnifications, in general to be able to see objects increasingly weak in intensity, telescopes become larger and the observation times of the object increase.

When we increase the observation times, the problem is that atmospheric movement changes the observation conditions and makes it difficult to obtain good images. One way to solve the problem was with telescopes in near space, the environmental disturbance is eliminated.

When the Hubble telescope was placed in space, there were already many answers but they continue to wonder what the limit of the universe is, this telescope allowed us to observe a body much farther away than ground-based telescopes, which is why it answered the question how many and to where there are galaxies out of the milky way.

Let's review the statements given to see the correct ones;

A) False. Copernicus clarified that the Sun is the center of the solar system

B) False. The center of the universe is not known, but the sun is a star in one of the arms of the milky way that is not the center of the universe either.

C) False. It has been known for a century what the movement of the planets in the solar system

D) True. The telescope in space allowed us to expand the limit of vision of the universe and respond to where there are galaxies outside the Milky Way.

In conclusion with the characteristics and problems of telescopes we can find the correct answer to the question that the Hubble telescope helped to answer is:

      D) Are there more galaxies beyond the milky way

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What question did use of a telescope by hubble answer A) Is earth the center of the universe B) Is the

Emily wanted to see what battery lasted the longest. She put each battery into a clock and recorded the time that the clock stopped. She used Duracell, Energizer, Kroger brand, and EverReady. Iv,Dv, Control, consistent

Answers

Answer:

This question is asking to identify the following variables:

Independent variable (IV): Battery

Dependent variable (DV): Time the clock stopped

Constant: Same clock

Control: No stated control

Explanation:

The independent variable in an experiment is the variable that is subject to manipulation or change by the experimenter. In this experiment, the independent variable is the BATTERIES (Duracell, Energizer, Kroger brand, EverReady).

The dependent variable is the variable that responds to the changes made to the independent variable. It is the variable that the experimenter measures. In this case, the dependent variable is the TIME IT TAKES FOR THE CLOCK TO STOP.

Constants or control variable is the variable that the experimenter keeps constant or unchanged for all groups throughout the experiment in order not to influence the outcome of the experiment. The constant in this case is the SAME CLOCK USED.

Control group is the group that does not receive the experimental treatment or independent variable in an experiment. In this case, all groups received a different kind of battery.

Other Questions
how does energy bulb works A payment of $2,300 is due in 2 years and $3,900 is due in 4 years. These two original payments are to be rescheduled with a payment of $1,800 in 1 year and the balance in 3 years. Calculate the payment required in 3 years for the rescheduled option. Assume that money earns 4.75% compounded monthly. 50 Points!! 25 Each Points Please Help ASAP!! View Attached Image!! Will Mark Brainliest If All Are Answered!! what is the first function performed by the public relations practitioner? The Lopez family uses up a 12-gallon jug of milk every 3 days. At what rate do they drink milk?Simplify your answer and write it as a proper fraction, mixed number, or whole number. gallons per day What happened during Louis XIV reign? Jay recently was promoted to a management position in a firm that had been extremely bureaucratic. However, the environment changed dramatically and the new management team knew it needed to change the organization quickly if it was to survive. Jay suggested that the management team allow the employees to develop more confidence in their ability to do a good job by sharing power with them. The others on the team were skeptical, but they allowed Jay to experiment. In this situation Jay is suggesting using __________ to increase employee confidence in their ability to do the job. Change the following sentences so that they are negative, and replace the IO noun with the correct IO pronoun.Escribo una carta a mi novia. Please help me with this homework what are the benefits of the mercator projection Question 5 (1 point)How is Mary treated when she arrives at Misselthwaite Manor?Mr. Craven meets Mary at the door and shows her around Misselthwaite Manor.Mary is brought to her rooms and told to stay there.Mr. Pitcher and Mr. Craven have supper with Mary.Mrs. Medlock shows Mary around Misselthwaite Manor and then shows her toher rooms. All of the following nondependent taxpayers are U.S. citizens. Which is/are required to file a 2022 income tax return If you know how a text is organized, you can grasp its ideas more quickly. How can you identify a texts organizational pattern, before you even begin reading it? Why do you think "Pay Day" loans are theworst? Guys pls help me!!!!!!! Consider the graph of the function f(x)=10^x. What is the range of function g if g(x)=-2f(x)+1?A. (-infinity, 1)B. (-2, infinity) C. (-infinity, 2) D. (0, infinity) PLEASE ANYONE HELP ME BADLY I NEED THIS Assignment SummaryFor this assignment, you will create a response to a self-selected fiction text. As you read, use the strategies you have learned to add to your own comprehension of the text. You will use a graphic organizer to help you use strategies with success. Background InformationWhen choosing a fiction text, find something that interests you. Look for complex ideas and characters. Consider books that explore perspectives and cultures different from your own. Choose a book that matches your reading ability or provides an appropriate challenge for you.When reading, use strategies to monitor and improve your comprehension. Questioning involves generating questions to ask yourself before, during, and after reading. You can also make predictions about the characters and the plot of a story. It is also important to use your background knowledge to build a connection to the text. These connections might be text-to-text, text-to-self, or text-to-world. Another important strategy is to control the pacing of your reading. If you do not understand a section of text, you can slow down or reread it. Lastly, taking notes or annotating is a key strategy that will help you improve your reading comprehension.MaterialsSelf-selected fiction textStudent GuideAssignment InstructionsFor this project, you are expected to submit two things:Your completed graphic organizerThe completed Connecting Questions sectionStep 1: Prepare for the project. Read through the guide before you begin so you know the expectations for this project. If anything is not clear to you, ask your teacher for assistance.Step 2: Choose a text and establish a purpose to read.Choose a text to read. List your title in the graphic organizer at the end of this document.Establish a purpose for reading and list it in the graphic organizer.Step 3: Generate questions to ask before, during, and after reading. Write two questions to ask yourself before you begin reading, two questions to ask yourself while you read, and two questions to ask yourself after reading. List your questions in the graphic organizer below.Step 4: Read your text and monitor your comprehension.Read your text.Monitor comprehension and use reading strategies to improve comprehension. Make adjustments by using reading strategies such as:RereadingChanging paceUsing background knowledgeAnnotating the textRecord your use of these reading strategies in the graphic organizer below. Answer your during-reading and after-reading questions.Step 5: Describe and make connections to the text.Describe personal connections by answering question 1 in the Connecting Questions section of this document.Make personal connections to the text by answering question 2 in the Connecting Questions section of this document.Create connections between the text and the world around you by answering question 3 in the Connecting Questions section of this document. Step 6: Use this checklist to evaluate your project.If you can check each box below, you are ready to submit your project.Did you identify a purpose for reading?Did you generate questions to ask yourself before, during, and after reading the text?Did you monitor your comprehension as you read?Did you create connections by answering the three Connecting Questions at the end of this document?Step 7: Revise and submit your project. If you were unable to check off all of the requirements on the checklist, go back and make sure that your project is complete. Save your project before submitting it.Turn in your graphic organizer and your Connection Questions to your teacher. Be sure that your name is on it.Congratulations! You have completed your project.Graphic Organizer Use this graphic organizer to help you apply reading strategies to increase your reading comprehension. Text you have chosen Your purpose for reading Questions You HaveBefore reading 1.2.During reading 1.2.After reading 1.2.Reading Strategies (List how you used each strategy and how it helped your comprehension.)Rereading Changing pace Using background knowledge Annotating the text Connecting QuestionsCreate connections to your text by answering the questions below.1. How does this text relate to another text you have read? List similarities and differences. 2. How does this text connect to your life experiences? Are there similarities between you and one of the characters? Have you ever visited a similar setting? 3. What does this text tell you about society or the world around you? Connect events in the text to events in history, or connect issues in the text to issues we face today. HELP!! I HAVE THE ANSWERS I Just NEED TO SHOW THE WORK!!What is the value of y in the diagram below? Answer: C HELP please this is due at 11:55 so like in hour and I am confused What are the adjectives in these sentences? The red, white and blue flag waved gently in the soft breeze.My lazy cat likes to sit on a big branch of the old tree.