In a solution, the particles of different substances are ___ a. mixed evenly, b. never mixed, c. mixed unevenly, d. separated from each other. PLEASE ANSWER ASAP TY

Answer:

26.4 L

Explanation:

O₂ + C₅H₈

Given: 80 g of C₅H₈

Find actual gram-formula mass of C₅H₈: 68 g

Create a proportion: 80 g/68 g = 1.176…

Find actual gram-formula mass of O₂: 16 g

Find new mass of O₂: 16 g * 1.176… = 19 g

Use dimensional analysis for conversion (see attachment).

Explanation:

i cant see the picture!!!

The atomic ratio of carbon to oxygen in carbon monoxide (CO) is 1:1, and the atomic ratio of carbon to oxygen in carbon dioxide (CO₂) is 2:1.

Firstly, we can analyze the decomposition of carbon monoxide (CO) and carbon dioxide (CO₂) to determine the atomic ratios involved.

Let's denote the atomic ratio of carbon to oxygen in carbon monoxide as x, and the atomic ratio of carbon to oxygen in carbon dioxide as y.

According to the given data;

Decomposition of carbon monoxide (CO);

Oxygen produced = 3.36 g

Carbon produced = 2.52 g

We know that the atomic mass of carbon is 12 g/mol, and the atomic mass of oxygen is 16 g/mol. Using these values, we can calculate the number of moles for each element;

Number of moles of oxygen = mass / atomic mass = 3.36 g / 16 g/mol = 0.21 mol

Number of moles of carbon = mass / atomic mass = 2.52 g / 12 g/mol = 0.21 mol

Since the atomic ratio of carbon to oxygen in carbon monoxide is x, we can write the following equation;

0.21 mol C / (0.21 mol O) = x

Simplifying the equation, we have;

x = 1

Therefore, the atomic ratio of carbon to oxygen in carbon monoxide is 1:1.

Decomposition of carbon dioxide (CO₂);

Oxygen produced = 9.92 g

Carbon produced = 3.72 g

Following the same calculations as before;

Number of moles of oxygen = mass / atomic mass = 9.92 g / 16 g/mol = 0.62 mol

Number of moles of carbon = mass / atomic mass = 3.72 g / 12 g/mol = 0.31 mol

Since the atomic ratio of carbon to oxygen in carbon dioxide is y, we can write the following equation;

0.31 mol C / (0.62 mol O) = y

Simplifying the equation, we have;

y = 0.5

Therefore, the atomic ratio of carbon to oxygen in carbon dioxide is 1:0.5, which can be simplified to 2:1.

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--The given question is incomplete, the complete question is

"Missed this? watch kcv: atomic theory; read section 2.3. you can click on the review link to access the section in your text. carbon and oxygen form both carbon monoxide and carbon dioxide. when samples of these are decomposed, the carbon monoxide produces 3.36 g of oxygen and 2.52 g of carbon, while the carbon dioxide produces 9.92 g of oxygen and 3.72 g of carbon. Calculate the atomic ratio of carbon to oxygen in carbon monoxide, and carbon dioxide."--

Answer:

B. Biosphere

Explanation:

Answer:

I not sure if this is right but maybe b since its particles is more spread out?

The volume of the irregular solid from the image that have been shown is  12 mL

To obtain the volume of the irregular solid;

a. Measure the initial volume of water in the cylinder.

b. Carefully lower the irregular solid into the water, ensuring it is fully submerged without trapping any air bubbles.

c. Record the new volume of water in the cylinder.

d. The volume of the irregular solid is equal to the difference between the final and initial water volumes.

The volume is;

32 mL - 20 mL = 12 mL

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To synthesize a carboxylic acid from ethyne using the reagents provided, follow these steps: Hydroboration-oxidation, Tautomerization, Nucleophilic addition, Oxidation and Oxidative cleavage.

Hydroboration-oxidation- Reagent 1: Diborane (B2H6); Reagent 2: Hydrogen peroxide (H2O2) and sodium hydroxide (NaOH) Ethyne (C2H2) will undergo hydroboration-oxidation using diborane (B2H6) followed by treatment with hydrogen peroxide (H2O2) and sodium hydroxide (NaOH) to form an alkene (vinyl alcohol) with three bonds to hydrogen and one bond to a hydroxyl group.

Tautomerization- The vinyl alcohol formed in step 1 will undergo tautomerization (keto-enol equilibrium) to form an aldehyde with two carbons. Nucleophilic addition- Reagent 3: n-Propyl Grignard reagent (n-PrMgBr) Add the n-Propyl Grignard reagent (n-PrMgBr) to the aldehyde. This will result in a nucleophilic addition reaction, leading to the formation of a tertiary alcohol with a four-carbon chain.

Oxidation- Reagent 4: Chromic acid (H2CrO4), Oxidize the tertiary alcohol to a ketone using chromic acid (H2CrO4). This will form a ketone with a four-carbon chain. Oxidative cleavage- Reagent 5: Ozone (O3), Reagent 6: Zinc (Zn) and water (H2O), Perform an oxidative cleavage of the ketone using ozone (O3) followed by a reductive workup with zinc (Zn) and water (H2O). This will result in the formation of a carboxylic acid bonded to a four-carbon chain.

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First, we will calculate the number of moles of mixture of Xenon and Neon gases.Number of moles of mixture of Xenon and Neon gases:

Let x be the mole fraction of Neon.

Therefore, (1 - x) is the mole fraction of Xenon

.Mole fraction of Neon + Mole fraction of Xenon = 1x + (1 - x) = 1x = 1 - (1 -

x = 0 + x

x = 0.279

Mole fraction of Neon = 0.279

Mole fraction of Xenon = 0.721

Number of moles of gas = (Total Pressure * Volume)/(Gas Constant * Temperature)

Number of moles of Xenon = (7.10 atm * 16.75L * 0.721)/(0.08206 * (273 + 30))

Number of moles of Xenon = 8.44 moles

Number of moles of Neon = (7.10 atm * 16.75L * 0.279)/(0.08206 * (273 + 30))

Number of moles of Neon = 3.29 moles

Now, we can calculate the partial pressure of Xenon and Neon.

Partial pressure of Xenon:

Partial Pressure of Xenon = Mole fraction of Xenon * Total Pressure

Partial Pressure of Xenon = 0.721 * 7.10 atm

Partial Pressure of Xenon = 5.12 atm

Partial pressure of Neon

Partial Pressure of Neon = Mole fraction of Neon * Total Pressure

Partial Pressure of Neon = 0.279 * 7.10 atm

Partial Pressure of Neon = 1.98 atm

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Answer:

Phosphorus can have expanded octet, because it can shift it's lone pair electrons (3s orbital electrons) to empty 3d obital during excited state and thus can form 5 bonds.

Explanation:

hope it helps

A particular first-order reaction has a rate constant of 7.85 × 104 s-1 at 25.0 °c. The magnitude of k at 42.5 °C is 6.01 × 10^7 s^-1.

We can use the Arrhenius equation to relate the rate constant k at two different temperatures:

k2 = A * exp(-Ea/R * (1/T2 - 1/T1))

where k2 is the rate constant at the new temperature T2, A is the pre-exponential factor, Ea is the activation energy, R is the gas constant, and T1 is the initial temperature.

We are given k1 = 7.85 × 10^4 s^-1 at T1 = 25.0 °C = 298.15 K, Ea = 34.7 kJ/mol, and T2 = 42.5 °C = 315.65 K.

We can calculate A by rearranging the equation to solve for A:

A = k1 / exp(-Ea/R * 1/T1)

A = 7.85 × 10^4 s^-1 / exp(-34.7 kJ/mol / (8.314 J/mol·K) * (1/298.15 K))

A = 2.07 × 10^13 s^-1

Now, we can use A and Ea to calculate k2 at T2:

k2 = A * exp(-Ea/R * (1/T2 - 1/T1))

k2 = 2.07 × 10^13 s^-1 * exp(-34.7 kJ/mol / (8.314 J/mol·K) * (1/315.65 K - 1/298.15 K))

k2 = 2.07 × 10^13 s^-1 * exp(-3.86)

k2 = 6.01 × 10^7 s^-1

Therefore, the magnitude of k at 42.5 °C is 6.01 × 10^7 s^-1.

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Answer:

Refer to the attachment

The ionic compounds are substances composed of positive and negative ions. Let's check which among the given compounds are ionic compounds NH4Cl.

This is an ionic compound. It is formed by the reaction between ammonium (NH4+) and chloride (Cl-) ions. SrO This is an ionic compound. It is made up of strontium (Sr2+) and oxide (O2-) ions. SO2 This is not an ionic compound. It is a molecular compound that consists of sulfur (S) and oxygen (O) atoms.

BrCl This is not an ionic compound. It is a molecular compound that contains bromine (Br) and chlorine (Cl) atoms. Therefore, the ionic compounds among the given compounds are a) NH4Cl and b) SrO.

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Answer:

CLEANER

Explanation:

Independent variable is the variable in an experiment that is changed or manipulated by the experimenter in order to bring about a measurable response.

In this question, Marie notices that the current cleaner she is using on her shower is not cutting through the hard water build-up that has accumulated. She decides to purchase 3 other cleaners to see if one of them will do a better job of cutting through the stains. The CLEANERS being changed in this experiment is the INDEPENDENT VARIABLE.

Answer: 0.02 moles

Explanation:

The number of moles in 4.38 g of AgNO₂ is equal to 0.028 mol.

A mole can be described as a standard unit that can be utilized to calculate a given number of particles. The constituents counted are usually individually distinct but identical entities.

A mole of the substance can be used to calculate quantities of atoms, molecules, ions, or other particular particles. The quantity of matter can be described as measured by elementary entities.

The number of constituents present in one mole is equal to 6.023× 10 ²³ which is known as Avogadro’s constant.

Given, the mass of AgNO₂ = 4.38 g

The mass of one mole of AgNO₂ =  153.87 g

The number of moles of in 4.38 g of AgNO₂ = 4.38/153.87 = 0.028 mol

Therefore, the number of moles of  AgNO₂ is equal to 0.028 mol.

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Main sequence stars with low temperatures tend to have low luminosity is based on Hertzprung-Russell diagram

The bright, hot stars in the image's upper left are the main sequence group, which stretches roughly diagonally to the lower right (dim and cool). In the bottom left are white dwarfs, which are small, faint, and hot. In the top right are giant and supergiant stars, which are big, bright, and cool.

Main sequence stars have a wide range of effective temperatures, but because they are brighter at higher temperatures, they normally follow a band from the bottom right to the top left of the diagram. Inside the cores, hydrogen and helium are fusing together.

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Answer: White dwarfs

Explanation: edge2020

Covalent bonds are formed when atoms of elements share electrons.

A covalent bond is a type of chemical bond where two atoms are connected to each other by the sharing of two or more electrons.

These electron pairs are known as shared pairs or bonding pairs and they form when the difference between the electronegativities of two atoms is too small for an electron transfer to occur to form ions.

For example, in a chemical compound HCl, it can be said that hydrogen and chlorine are joined by covalent bonding.

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Answer:

by watching and writing down the information that is provided

Explanation:

a) The sphere emits thermal radiation at a rate of 139.75 Watts.

b) The sphere absorbs thermal radiation at a rate of 37.66 Watts.

c) The sphere's net rate of energy exchange is 102.09 Watts.

To calculate the rates of thermal radiation emission and absorption, we can use the Stefan-Boltzmann law, which states that the rate of thermal radiation emitted or absorbed by an object is proportional to its surface area, temperature, and the Stefan-Boltzmann constant.

a) The rate of thermal radiation emitted by the sphere can be calculated using the formula:

Emitting Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(temperature^4 - environment\ temperature^4\))

Plugging in the given values:

Emitting Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((32.2 + 273.15)^4 - (82.9 + 273.15)^4)\)

Emitting Rate ≈ 139.75 Watts

b) The rate of thermal radiation absorbed by the sphere can be calculated in a similar way but using the environment temperature as the object's temperature:

Absorbing Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(environment\ temperature^4 - temperature^4\))

Plugging in the given values:

Absorbing Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((82.9 + 273.15)^4 - (32.2 + 273.15)^4)\)

Absorbing Rate ≈ 37.66 Watts

c) The net rate of energy exchange is the difference between the emitting rate and the absorbing rate:

Net Rate = Emitting Rate - Absorbing Rate

Net Rate = 139.75 Watts - 37.66 Watts

Net Rate ≈ 102.09 Watts

Therefore, the sphere emits thermal radiation at a rate of 139.75 Watts, absorbs thermal radiation at a rate of 37.66 Watts, and has a net rate of energy exchange of 102.09 Watts.

Note: The units for all the rates are Watts.

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The removal of the alcohol seen in the conversion of the nasal decongestant pseudoephedrine to the illicit drug methamphetamine constitutes the type of reduction process.

Redox is a type of chemical reaction in which the oxidation state of the substrate changes. Oxidation generally can be defined as the loss of electrons or increase in the oxidation state, while reduction is the gain of electrons or decrease in the oxidation state. The removal of alcohol observed in the conversion of pseudoephedrine to the illicit drug methamphetamine constitutes a reduction process. The "red phosphorus method" is a chemical reduction reaction that converts pseudoephedrine to methamphetamine using red phosphorus/hydrogen iodide oxidation chemistry.

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The molarity of the solution made by dissolving 125 g of Na₃PO₄ in water resulting to a volume of 250 ml is approximately 3.05 M.

To calculate the molarity (M) of the solution, we need to know the moles of solute (Na₃PO₄) and the volume of the solution in liters.

1. Convert grams of Na₃PO₄ to moles:
Molecular weight of Na₃PO₄ = (3 × 22.99) + (1 × 30.97) + (4 × 16.00) = 68.97 + 30.97 + 64.00 = 163.94 g/mol

125 g Na₃PO₄ / 163.94 g/mol ≈ 0.762 moles of Na₃PO₄

2. Convert volume of the solution to liters:
250 mL = 250/1000 = 0.25 L

3. Calculate the molarity (M):
M = moles of solute / volume of solution in liters
M = 0.762 moles / 0.25 L ≈ 3.05 M

The molarity of the Na₃PO₄ solution is approximately 3.05 M.

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Answer:

The thermometer in the [black] paper shows the greatest increase in temperature because black [absorbs] all wavelengths of visible light. The thermometer in the [white] paper shows the smallest increase in temperature because white [reflects] all colors of visible light. The thermometers in the green, red, and blue paper all show an increase in temperature. However, they don't increase as much as the thermometer in the black paper because these colors [absorb all other colors and reflect their own color.]

Explanation:

Hope this helps you! [______] This means it's the answer that needs to be filled in.

The thermometer in the black paper shows the greatest increase in temperature because black absorbs all wavelengths of visible light. The thermometer in the white paper shows the smallest increase in temperature because white reflects all colors of visible light. The thermometers in the green, red, and blue paper all show an increase in temperature. However, they don't increase as much as the thermometer in the black paper because these colors absorb all other colors and reflect their own color.

A person with a history of chemical dependency on controlled substances who desires to obtain A License. A license to practice Nursing students may be required to show proof of current sobriety and fitness to practice.

This rule is from the Texas Board of Nursing’s (BON) Administrative Rules. It is stated that any nurse who has a chemical dependency diagnosis or a history of controlled substance abuse must demonstrate the following through "objective, verifiable evidence" of current sobriety and fitness to practice to get a license.

This objective, verifiable evidence could be obtained through AA records, negative drug tests, an assessment by a specialist in addiction, and testimonies from group members, colleagues, and other close friends.

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Answer:

Molecules that contain only carbon and hydrogen are Hydrocarbons.

Answer:

Being young, kittens can also be called “cubs” although the name “kitten” is more commonly used. Most consider cats as kittens if they are still less than one year of age. However, some vets say that a kitten can already be considered a cat when it reaches eight or nine months.

Or could also use:

Specie and stripes

1. A cat and it’s litter can’t be related without the producer which in this case is the mother

2. The stripes shows that the two are related and yeah you can have to cats that have the same stripes but that’s not likely, every-time any two cats with stripes are put together the cats show similarities but that doesn’t tell us that their related. Every cat has similar stripes but there is something that’s always gonna be off with the stripes whether the stripes have the same color or the stripes have the same arrangement on the cat. Like people cats have similar traits but that doesn’t mean there related (ex: two blue eyed people, that’s doesn’t prove that their related in any type of way).

Explanation:

Answer:

Inherited characteristics that show that a cat and kitten are related include physical traits such as fur pattern and color, eye shape, and body type. Another example is behavioral traits such as playfulness and social behavior. These traits are passed down from parent to offspring through genes and provide evidence of a familial relationship.

Explanation:

It takes 1 mol of sulfur to produce 1 mol of sulfur dioxide. Therefore, 64 g of sulfur is required to produce 64 g of sulfur dioxide.

To calculate the mass of sulfur required to produce 64 g of sulfur dioxide, the following equation can be used:

m (sulfur) = (64 g SO2) / (32 g/mol SO2) × (1 mol S/ 32 g S) = 2 mol S

Therefore, the mass of sulfur required to produce 64 g of sulfur dioxide is 2 mol S or 64 g.

The mass of sulfur that must be burned to produce 64 g of sulfur dioxide is 64 g. This is because the molar mass of sulfur dioxide is 32 g/mol and the molar mass of sulfur is 32 g/mol.

Therefore, it takes 1 mol of sulfur to produce 1 mol of sulfur dioxide. Therefore, 64 g of sulfur is required to produce 64 g of sulfur dioxide.

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1.08 x 10²¹ molecules of methionine are present for every 1.0 mole of glycine in the sample.

Given data -

Glycine in the sample = 1.0 mole

Avogadro's number = 1.8 x 10⁻³ moles (we know)

To find the number of molecules of methionine , multiply the molar ratio by the Avogadro's number.

Number of molecules = Avogadro's number x molar ratio

                                     = (1.8 x 10⁻³ moles) x (6.02 x 10²³ molecules/mole)

                                     = 1.08 x 10²¹

Methionine is an essential amino acids for human. For the growth of new blood vessels and for he supplementation, it is an important  amino acid. Too much methionine reslts in the damage to the brain and might be fatal.

Glycine is also an amino acid which has only one single hydrogen as its side chain. It is used in the treatment of some rare metabolic disorders and schizoprenia, stroke, etc.

Glycine is responsible to reduce the levels of methionine in the blood. Glycine is considered a precursor for many necessary metabolites such as purines, glutathione, creatinine and porphyrins. It acts as a neurotransmitter in CNS.

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The amount of COCl₂ in grams in the equilibrium mixture is approximately 0.403 mg.

To determine the amount of COCl₂ in grams in the equilibrium mixture, we can use the given equilibrium concentrations and the volume of the flask.

Here's how to calculate it:

Calculate the moles of CO and Cl₂ in the flask:

Moles of CO = [CO] * Volume of flask

Moles of Cl₂ = [Cl₂] * Volume of flask

Moles of CO = (1.6×10⁻⁶ M) * (4.89 L) = 7.82×10⁻⁶ mol

Moles of Cl₂ = (8.3×10⁻⁷ M) * (4.89 L) = 4.06×10⁻⁶ mol

Use the stoichiometry of the balanced equation to determine the moles of COCl₂:

From the balanced equation: 1 mol CO + 1 mol Cl₂ -> 1 mol COCl₂

The moles of COCl₂ will be the same as the limiting reactant, which is the reactant with fewer moles.

In this case, since the moles of COCl₂ are not provided, we assume it to be zero initially.

Moles of COCl₂ = 0 + (moles of limiting reactant)

Moles of COCl₂ = 0 + 4.06×10⁻⁶ mol = 4.06×10⁻⁶ mol

Convert moles of COCl₂ to grams using its molar mass:

The molar mass of COCl₂ is the sum of the atomic masses of carbon, oxygen, and two chlorine atoms.

Molar mass of COCl₂ = (12.01 g/mol) + (2 * 16.00 g/mol) + (2 * 35.45 g/mol)                                  = 98.96 g/mol

Mass of COCl₂ = Moles of COCl₂ * Molar mass of COCl₂

Mass of COCl₂ = (4.06×10⁻⁶ mol) * (98.96 g/mol) = 0.403 mg (rounded to three significant figures)

Therefore, the amount of COCl₂ in grams in the equilibrium mixture is approximately 0.403 mg.

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Complete Question:

Consider the reaction: CO(g)+Cl₂(g)⇌COCl₂(g) Keq= 2.9×1010 at 25 ∘C A 4.89⁻ L flask containing an equilibrium reaction mixture has [CO]= 1.6×10⁻⁶ M and [Cl2]= 8.3×10⁻⁷ M .

How much COCl₂ in grams is in the equilibrium mixture?

Answer:

Yes

It is an organic chemical compound

Its formula is \(C_6H_6\)

Explanation: