The puck can have a maximum speed of approximately 4 m/s and a maximum acceleration of approximately 800 m/\(\rm s^2\) when the spring is released.
Using the given information, we can determine the following quantities related to the motion of the puck:
1. Maximum potential energy stored in the compressed spring \((\(PE_{\text{max}}\))\):
\(\[ PE_{\text{max}} = \frac{1}{2}kx^2 \]\)
where \(\( k = 120 \, \text{N/m} \)\) (spring constant) and \(\( x = 0.020 \, \text{m} \)\) (maximum compression of the spring).
\(\[ PE_{\text{max}} = \frac{1}{2} \times 120 \times (0.020)^2 = 0.024 \, \text{Joules} \]\)
2. Maximum speed of the puck \((\( v_{\text{max}} \))\) when the spring is released:
At the maximum compression of the spring, all potential energy is converted into kinetic energy. So, \(\( PE_{\text{max}} = \frac{1}{2}mv_{\text{max}}^2 \), where \( m = 0.0030 \, \text{kg} \)\) (mass of the puck).
\(\[ v_{\text{max}} = \sqrt{\frac{2 \times PE_{\text{max}}}{m}} = \sqrt{\frac{2 \times 0.024}{0.0030}} \approx 4 \, \text{m/s} \]\)
3. Maximum acceleration of the puck \((\( a_{\text{max}} \))\) when the spring is released:
Maximum acceleration is given by \(\( a_{\text{max}} = \frac{F_{\text{max}}}{m} \), where \( F_{\text{max}} \)\) is the maximum force exerted by the spring.
\(\[ F_{\text{max}} = kx = 120 \times 0.020 = 2.4 \, \text{N} \]\\\\\ a_{\text{max}} = \frac{2.4}{0.0030} \approx 800 \, \text{m/s}^2 \]\)
In summary, using the given spring constant and maximum compression of the spring, we determined that the puck can have a maximum speed of approximately 4 m/s and a maximum acceleration of approximately 800 m/\(\rm s^2\) when the spring is released.
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What is the minimum speed (in m/s) of an incident electron that could produce this emission line? (hint: recall the expression for relativistic kinetic energy given in topic 26.)
To determine the minimum speed of an incident electron that could produce a specific emission line, we need to use the expression for relativistic kinetic energy.
The expression for relativistic kinetic energy is given by:
KE = (γ - 1) * mc^2
Where:
KE is the kinetic energy of the electron
γ is the Lorentz factor, which is given by γ = 1 / sqrt(1 - v^2/c^2)
m is the rest mass of the electron
c is the speed of light in a vacuum
v is the velocity of the electron
Since we are looking for the minimum speed, we need to find the velocity (v) that corresponds to a specific energy level.
First, we need to know the rest mass of the electron, which is approximately 9.10938356 x 10^-31 kilograms.
Next, we need to know the emission line that we are considering. Once we have this information, we can determine the energy level associated with that emission line.
Finally, we can substitute the values into the equation and solve for v.
It is important to note that the value of the speed of light in a vacuum is approximately 3 x 10^8 meters per second.
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A child looks at his reflection in a spherical Christmas tree ornament 8.0 cm in diameter in season that the image of his face is reduced by 1/2 how far is his face from the ornament
From the information given,
diameter of ornament = 8
radius = diameter/2 = 8/2
radius of curvature, r = 4
Recall,
focal length, f = radius of curvature/2 = 4/2
f = 2
Recall,
magnification = image d
The plate separation of a charged capacitor is 0.8 m. A proton and an electron are released from rest at the midpoint between the plates. Ignore the attraction between the two particles, and determine how far the proton has traveled by the time the electron strikes the positive plate.
we get the distance traveled by the proton as,distance traveled = vt = vp(t)distance traveled = (vp(2d/vp)) = (2d(vp/√(2qVp/m)))Thus, by the time the electron strikes the positive plate, the proton would have traveled 1.13 cm.
Given that the plate separation of a charged capacitor is 0.8 m. A proton and an electron are released from rest at the midpoint between the plates.The acceleration experienced by each particle is given as, a = F/mwhere m is the mass of the particle and F is the force experienced by the particle. The force experienced by each particle is given as F = qEwhere q is the charge of the particle and E is the electric field experienced by the particle.The electric field between the plates of the capacitor is given by
E = V/d, where V is the potential difference across the plates and d is the distance between the plates.The potential difference across the plates is given as V = Ed = (Vf - Vi)
where Vf is the final potential of the positive plate, Vi is the initial potential of the negative plate.Substituting the value of electric field,
we get V = Ed = (Vf - Vi)By the law of conservation of energy, the kinetic energy gained by the electron is equal to the potential energy lost by the capacitor.
Kinetic energy gained by electron = 1/2 mv² = qVqV = 1/2 mv²The potential energy lost by the capacitor = 1/2 CV² = qVqV = 1/2 CV²qV = 1/2 mv² ⇒ v = √(2qV/m)
By the time the electron strikes the positive plate, the time taken = t = (2d/v)where d is the plate separationSubstituting the values, we get the time taken as,t = (2d/v) = (2 × 0.8)/ √(2qV/m)
Similarly, the time taken by the proton is given by,t = (2d/vp)where vp is the velocity of the protonvp = √(2qVp/m)The distance traveled by the proton by the time the electron strikes the positive plate is given by,
distance traveled = vt = vp(t)
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3. Two fans blow at 5 ms^-1 in a easterly direction and 8ms^-1 in a Northerly
direction. What is the total wind speed of both fans combined?
Addition of vectors is done by adding the components of the vectors
The total speed of the fan is approximately 9.43 m/s,
Direction of total wind 58° counterclockwise from the positive x-axis
The reason the value is correct is as follows:
The given parameters are:
The direction at which the fan blowing at 5 m/s is blowing = Easterly
The direction in which the fan blowing 8 m/s is blowing = Northerly
The total speed of the van, |v| ≈ 9.43 m/s
Required:
To find the total wind speed of the fans
Solution:
Taken the easterly direction as the ith component, and the northerly direction as the jth component, the vector representing the speed of the fan is presented as follows
v = 5·i + 8·j
The magnitude of the total wind speed of the fan, |v| = √(5² + 8²) = √(89) ≈ 9.43
The total wind speed of the fan , |v| ≈ 9.43 m/s
The direction of the total speed with respect to the x-axis, θ, is given as follows;
θ = arctan(8/5) ≈ 58°
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Photoelectric Effect The work function of calcium metal is W0=2.71 eV.1 electron volt (eV)=1.6×10−19 J. Use h=6.626×10−34 J⋅s for Planck's constant and c=3.00×108 m/s for the speed of light in a vacuum. An incident light of unknown wavelength shines on a calcium metal surface. The max kinetic energy of the photoelectrons is 3.264×10−20 J. Part A - What is the energy of each photon in the incident light? Use scientific notations, format 1.234∗10n, unit is Joules photon energy = Part B - What is the wavelength of the incident light? Enter a regular number with 1 digit after the decimal point, in nm.1 nm=10−9 m
In the given scenario of the photoelectric effect with calcium metal, the work function is 2.71 eV, and the maximum kinetic energy of the photoelectrons is 3.264×10^(-20) J.
The task is to determine the energy of each photon in the incident light (Part A) and the wavelength of the incident light (Part B).
Part A: The energy of each photon in the incident light can be calculated using the equation E = hf, where E is the energy, h is Planck's constant, and f is the frequency of the light.
Since we are given the wavelength of the light, we can find the frequency using the equation c = λf, where c is the speed of light. Rearranging the equation, we have f = c / λ. By substituting the values for h and f, we can calculate the energy of each photon.
Part B: To determine the wavelength of the incident light, we can use the equation E = hc / λ, where λ is the wavelength. Rearranging the equation, we have λ = hc / E. By substituting the given values for h and E, we can calculate the wavelength of the incident light.
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Which occupation is not an example of specialization?
A waiter
B journalist
C student
OD carpenter
Answer:
A waiter
Explanation:
Specialization is the process of concentrating on and becoming an expert in a particular subject or skill. It can also be used to refer to the area on which someone becomes an expert. All the other options require years of gradual learning that builds up over the years for one to be considered an expert, asides for that of a "waiter"
Waiting does not require much training, and cannot be referred to as an area of specialization.
Answer:
student
Explanation:
it's the only one that is not an example of specialization.
One strategy that has been implemented to address the drug epidemic in Philadelphia was the creation of something called
The One strategy implemented to address the drug epidemic in Philadelphia is the creation of Comprehensive User Engagement Sites (CUES). These sites aim to tackle the widespread issue of drug addiction and related energy health concerns.
The CUES are safe spaces where individuals battling addiction can energy access various harm reduction services, such as clean syringes, medical support, and overdose prevention. These sites provide connections to addiction treatment programs and mental health services, helping people on their path to recovery. By offering safe and supervised spaces, CUES work to reduce public drug use, discarded syringes, and other related issues in the community. CUES also serve as educational hubs, raising awareness and providing information about the dangers of drug addiction and available resources for support. Lastly, these sites foster community engagement and collaboration, uniting various stakeholders in the fight against the drug epidemic. In summary, Comprehensive User Engagement Sites play a significant role in addressing the drug epidemic in Philadelphia. They provide harm reduction services, treatment programs, and community support, all while promoting a safer and healthier environment for the city's residents.
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A train traveling 45 m/s north is speed or velocity
Answer:
It is velocity
It has both magnitude and direction, 45 m/s is the magnitude and north is the direction.
Velocity is a vector quantity, with both magnitude and direction.
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Calculate the total displacement of a mouse walking along a ruler, if it begins at the location x = 5 m, and then does the following:
- It walks to x = 12 m
- It then walks a displacement of -8 m (NOT the same as x = -8 m)
- Lastly, it walks to the location x = 7 m
Answer:
18
Explanation:
12 - 5 + 8 = 15
12 - 8 = 4
7 - 4 = 3
15 + 3 = 18
peregrine falcons are known for their maneuvering ability. in a tight circular turn, a falcon can attain a centripetal acceleration 1.5 times the free-fall acceleration.
We can apply the formula \(v = \sqrt{(14.715 m/s^2 * r)}\) to determine the peregrine falcon's speed. A falcon can reach a centripetal acceleration that is 1.5 times the acceleration of free fall.
We can use the centripetal acceleration formula to find the speed of the peregrine falcon in this scenario:
\(a_c = v^2 / r\)
where \(a_c\)is the centripetal acceleration, v is the speed of the peregrine falcon, and r is the radius of the circular turn.
We are given that the centripetal acceleration of the peregrine falcon is 1.5 times the free-fall acceleration, which we can approximate as 9.81 m/s². Therefore, we have:
\(a_c = 1.5 * 9.81 m/s^2\\a_c = 14.715 m/s^2\)
We can also assume that the radius of the circular turn is a characteristic of the maneuvering ability of the peregrine falcon, and is independent of its speed. Therefore, we can write:
\(a_c = v^2 / r\)
Solving for v, we get:
\(v = \sqrt{(a_c * r)}\)
Substituting the values we obtained earlier, we get:
\(v = \sqrt{(14.715 m/s^2 * r)}\)
Therefore, the speed of the peregrine falcon in this tight circular turn depends on the radius of the turn. If we know the radius, we can use the equation \(v = \sqrt{(14.715 m/s^2 * r)}\) to calculate the speed of the peregrine falcon.
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If you were told an atom was an ion, you would know the atom must have a...
Neutral Charge
Charge
Negative Charge
Positive Charge
---- Thank you !
Answer:
option (b) charge
Explanation:
Consider an ideal spring that has an unstretched length l_0. Assume the spring has a constant k. Suppose the spring is attached to an cart of mass m that lies on a frictionless plane that is inclined by an angle theta from the horizontal. Let g denote the gravitational constant The given quantities in this problem are l_0, m, k, theta, and g. a) The spring stretches slightly to a new length l>l_0 to hold the cart in equilibrium. Find the length l in terms of the given quantities. b) Now move the cart up along the ramp so that the spring is compressed a distance x from the unstretched length l_0. Then the cart is released from rest What is the velocity of the cart when the spring has first returned to its unstretched length l_0? c) What is the period of oscillation of the cart?
The length of the spring in equilibrium is l = l0 +(mgsin(theta)/k in terms of the given quantities
a) The length of the spring in equilibrium can be calculated using the spring's force equation, F = -k(l-l0).The force exerted by gravity on the cart is mgsin (theta), which must be equal to the force exerted by the spring in order to achieve equilibrium. Setting these two forces equal to each other and solving for l gives:
l = l0 +(mgsin(theta)/k
b) When the cart is released from rest, it will have potential energy stored in the spring. This potential energy can be converted into kinetic energy as the spring expands. The velocity of the cart when the spring has first returned to its unstretched length can be found using the conservation of energy. The potential energy stored in the spring when the cart is released is (1÷2) kx2, and the kinetic energy at the point when the spring returns to its unstretched length is (1÷2) mv². Setting these two equal to each other and solving for v gives:
sqrt(2kx÷m) = v
c) The period of oscillation of the cart is the time it takes for the cart to complete one full oscillation. T = 2pisqrt(m/k) can be used to calculate it.
2pisqrt(m÷k) = T
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How much energy is required to heat 600g of iron (c+0. 41J/g Celsius) from a starting temperature of 25 Celsius to 60 Celsius
The energy required to heat 600g of iron from 25°C to 60°C is 8,760 Joules. to calculate this, we can use the equation:
Energy = mass × specific heat capacity × temperature change
Given:
Mass (m) = 600g
Specific heat capacity (c) = 0.41 J/g°C
Temperature change (ΔT) = 60°C - 25°C = 35°C
Plugging these values into the equation, we get:
Energy = 600g × 0.41 J/g°C × 35°C = 8,760 Joules.
Therefore, 8,760 Joules of energy is required to heat 600g of iron from 25°C to 60°C.
In the calculation, we use the formula for calculating the energy required to heat a substance: Energy = mass × specific heat capacity × temperature change. We are given the mass of iron (600g), the specific heat capacity of iron (0.41 J/g°C), and the temperature change (35°C). By substituting these values into the equation, we find that 8,760 Joules of energy is needed to heat the iron from 25°C to 60°C.
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Calculate the net force experienced by Mr. Ferrari if he has a mass of 100 kg and an acceleration of 3.5 m/s/s.
What’s the answer?
What is the total energy of the reaction? is this an endothermic or exothermic reaction?.
The total energy of a reaction is determined by the breaking and forming of bonds between the reactant molecules. The total energy of the reaction is calculated by subtracting the sum of the bond energies of the products from the sum of the bond energies of the reactants. The bond energies can be found in tables of thermochemical data.
2. Endothermic or exothermic reactionAn exothermic reaction occurs when the sum of the reactants' bond energies is greater than the sum of the products' bond energies, so that energy is released in the form of heat and light. The energy of the reaction is released in the form of heat and light, and can be used to power other reactions. Exothermic reactions are characterized by a decrease in the total energy of the system, and can be identified by a negative change in enthalpy.
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Need help asap! you are the star soccer player and you are late to your game. Everyone is happy to see you and wants you to jump in and play. The safest thing to do in this situation is to
avoid the coach since you were late
go back home to avoid injury and ridicule
jump in and play to make up for being late
warm up your muscles before playing
Answer:
c and d
what i would do is ask the coach if you could take a minute to stretch and as soon as posible jump into the game
Explanation:
i play soccer lol
Answer: i'm pretty sure its warm up your muscles before playing
Explanation:
if you don't u get hurt.
if a person pulls on a cart to the right with a force of 10n and a second person pulls to the left with a force of 3n, what is the net force direction on the cart?
The net direction on the cart, if a person pulls on a cart to the right with a force of 10n and a second person pulls to the left with a force of 3n, is 7n to the right.
The net force direction can be determined by finding the net vector sum of the forces acting on it.
Since the first person pulled the cart to the right with a force of 10n,
Assuming the right direction as positive, this force can be represented as a vector ⇒(+)10n
Similarly, as the second person pulls the cart to the left, the force can be represented as a vector ⇒ (-)3n,
∴ Net force = Net vector sum of the forces
=(+10n) + (-3n)
⇒Net force = +7n
Thus, the net direction on the cart, if a person pulls on a cart to the right with a force of 10n and a second person pulls to the left with a force of 3n, is 7n to the right.
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Answer: 7n
Explanation:
In a closed system that has 45 J of mechanical energy, the gravitational
potential energy of a ball rolling down an inclined plane decreases from 8 J to
Answer:
the answer is d
Explanation:
I just did this test
A sample of nitrogen gas is inside a sealed container. The volume of the container decreases while the temperature is kept constant. This is a ________ process.
a) isothermal
b) constant-volume
c) adiabatic
d) isobaric
what would be the velocity
when a dog of 10kg and it's kinetic energy is 20J
Answer:
2 m/s
Explanation:
Simulate a blackbody spectrum of temperature 900 Kelvin. Determine the peak wavelength in nanometers of an object of that temperature nanometers What is the emissive intensity of the object (the amount of power emitted per unit area )? ×10 W/m 2
A blackbody spectrum of temperature 900 Kelvin has been simulated. The peak wavelength in nanometers of an object of that temperature is determined to be nanometers. The intensity of the blackbody radiation at a given temperature and wavelength can be determined using Planck's law.
Planck's law, which describes the intensity of blackbody radiation, is given byI(λ) = 2hc²λ⁻⁵[exp(hc/λkT) - 1]⁻¹Where c = speed of light, h = Planck's constant, k = Boltzmann constant, T = temperatureλ = wavelength of lightI (λ) = spectral radiant intensity expressed in watts per square metre per unit wavelength.
Simulating the blackbody spectrum for a temperature of 900 K:
Using the equation for peak wavelength λ_max = 2897/T nm, where T = 900 KTherefore,λ_max = 2897/900λ_max = 3.22 µm or 3220 nm.
The emissive intensity of the object (the amount of power emitted per unit area) is given asI = σT⁴, where σ is the Stefan-Boltzmann constant.
Therefore,I = σT⁴ = 5.67 × 10⁻⁸ × (900)⁴W/m²= ×10 W/m².
Hence, the emissive intensity of the object is ×10 W/m².
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Which use of iron is due to its chemical properties?
Item 3
Which option is an example of a physical property?
flammability
solubility
reactivity
toxicity
Write AT LEAST 10 SENTENCES based on ONE event that has happened in your life.
Please do it am so tired
Sorry your tired, ill try to make it worth reading.
One day I walked outside, I looked around. THEN BAM a wasp lands right on my face. Its hideously sharp stinger impaled my flesh. I could almost hear it going deeper and deeper. I screamed and ran around in circles until it finely flew away. As I started walking to the door I could feel my heart pules where the thing had stung. I opened the door and went into the bathroom. Right in the middle of my face just above my nose was a red dot, with a slightly less red ring around it, like an ateroid impact. I sat down and went over the entire event five times. I decided to go back outside, as I walked around the corner, another wasp landed on me.
Two forces whose resultant is 100N are at right angle to eachother. if one of them makes an angle of 30° with the resultant, determine its magnitude
Let F₁ and F₂ denote the two forces, and R the resultant force.
F₁ and F₂ point perpendicularly to one another, so their dot product is
F₁ • F₂ = 0
We're given that one of these vectors, say F₁, makes an angle with R of 30°, so that
F₁ • R = ||F₁|| ||R|| cos(30°)
But we also have
F₁ • R = F₁ • (F₁ + F₂) = (F₁ • F₁) + (F₁ • F₂) = F₁ • F₁ = ||F₁||²
So, knowing that ||R|| = 100 N, we get that
(100 N) ||F₁|| cos(30°) = ||F₁||²
(100 N) cos(30°) = ||F₁||
||F₁|| ≈ 86.6 N
(And the same would be true for F₂.)
If 80,000 Joules of heat is absorbed by 210 grams of ice at 0°C, what happens to the ice?
It partially melts and stays at 0°C
It completely melts but stays at 0°C
It completely melts and has a final temperature of 11.2°C
It completely melts and has a final temperature of 22.4°C
It completely melts and has a final temperature of 33.6°C
Answer:
It completely melts and has a final temperature of 22.4°C
Explanation:
(I am very bad at explaining, I am not a teacher, I am a student but I had exact same question on my test so I wanted to help.)
Okay, well to find the Heat required to melt Ice, we have to use the equation:
Q=(m·cΔT)+(m·hf)
Q= HeatM= MassC= Specific heatΔT= Change in temperature. hf= heat fusionSo we can just plug in the values into the equation and see which one adds up too 80,000. (there is probably a better way i just did it this way)
For this situation, we know that:
Mass=210 gramsSpecific heat = 2.10 (I got this number 2.10 from the internet. The universal number for specific heat of ice is 2.10 J/g°C ) Change in temperature= 0 °C or 11.2 °C or 22.4 °C or 33.6 °C (all the answers) Heat fusion=334 (universal number for heat fusion of melting ice is 334)So we can just change the value of change and temperature and see which one equals 80,000.( I will bold the value of change in temperature.)
Q=(m·cΔT)+(m·hf)
(210g)*(2.10)*(0)+(210)*(334)=70140(210g)*(2.10)*(11.2)+(210)*(334)=75079.2(210g)*(2.10)*(22.4)+(210)*(334)=80018.4(210g)*(2.10)*(33.6)+(210)*(334)=84957.6So which one equals 80,000? Equation #3 with the temperature at 22.4 °C
So the answer would be It completely melts and has a final temperature of 22.4°C.
Hope this makes sense, again I am not a teacher I am so bad at explaining, but I did my best. ;)
7. Explain how changes in temperature affect the particle motion of a substance. (3 points)
Answer:
When heat is added to a substance, the molecules and atoms vibrate faster. As atoms vibrate faster, the space between atoms increases. The motion and spacing of theparticles determines the state of matter of thesubstance. The end result of increased molecular motion is that the object expands and takes up more space.
488 nm light passes through a single
slit. The first (m = 1) diffraction
minimum occurs at an angle of
0.559º. What is the width of the slit?
[?] x 10-5 m
Answer:
5.00
Explanation:
a sinθ=mλ
You are missing (a) so you move sinθ to the other side than solve from there.
For first diffraction, the width of the slit is \(5*10^{-5} m\).
What is diffraction?Diffraction of light is defined as the bending of light around corners such that it spreads out and illuminates areas where a shadow is expected.
a sinθ=mλ
\(a = \frac{1*488*10^{-9} }{sin 0.559}\)
\(a = 5*10^{-5} m\)
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What is the change in gravitational potential energy of a 45 kg weight that is moved from 2 m to 18 m on earth? What is it on the moon (g = 1.6 m/s2)?
Answer:
to find the weight, use the following formula
F= m x g
in Earth---> 45 x 9.8= 441 N
in Moon---> 45 x 1.6= 72 N
Explanation:
I HOPE THIS HELPS!!! :)
The change in gravitational potential energy of a 45 kg weight that is moved from 2 m to 18 m on Earth and Moon are 7.056kJ and 1.152kJ respectively.
What is Gravitational Potential energy?
Gravitational potential energy is defined as the energy possessed by or acquired by an object due to a change in its position when it is present in a gravitational field. This can be said that gravitational potential energy is the energy which is related to the gravitational force or gravitation.
Gravitational potential energy is expressed as
U=m g h
Where, U = gravitational potential energy
m = mass
g = gravitational field
h = height
For above given example,
The change in gravitational potential energy for Earth
mass= 45kg
Difference in height \((H_2-H_1)\)= 18-2= 16m
g= \(9.8m/s^2\)
U= 45*16*9.8 = 7056J or 7.056kJ
The change in gravitational potential energy for Moon
mass= 45kg
Difference in height \((H_2-H_1)\)= 18-2= 16m
g= \(1.6m/s^2\)
U= 45*16* 1.6= 1152J or 1.152kJ
Thus, the change in gravitational potential energy of a 45 kg weight that is moved from 2 m to 18 m on Earth and Moon are 7.056kJ and 1.152kJ respectively.
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What type of interaction allows the sidewalk to heat up and cook the egg? absorption diffraction reflection transmission
By the processes of heat transfer, the sidewalk absorbs heat by radiation and cooks the egg.
What is heat energy?Heat energy is a form of energy that is due to difference in temperature between two bodies.
Heat energy always flow from hotter to colder bodies
The processes of heat transfer include;
conductionconvectionradiationThe sidewalk absorbs heat by radiation and cooks the egg.
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Answer:
absorption
Explanation: