Imagine that the reaction in model 1 starts with 100 molecules of A and zero molecules of B. explain why the concentration of substance A will never reach zero.

20.24 grams of \(N_2O\) is formed if 0.46 mole of \(NH_4NO_3\) is used in the reaction.

A mole is defined as 6.02214076 × \(10^{23}\)of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Balanced equation:

\(NH_4NO_3\) → \(N_2O + 2H_2O\).

1 mole \(NH_4NO_3\) gives 1 mole of \(N_2O.\)

0.46 mole of \(NH_4NO_3\) gives \(\frac{ 1 mole}{ 1 mole}\) x 0.46 mole \(N_2O\).

0.46 mole \(N_2O\) =\(\frac{mass}{44.013 g/mol}\)

Mass= 0.46 x 44.013

Mass=20.24gram.

Hence, 20.24 grams of \(N_2O\) is formed if 0.46 mole of \(NH_4NO_3\) is used in the reaction.

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Answer:

Four quantum numbers of unpaired electron of chlorine are n=3,l=1,m=0,s=+1/2.

Explanation:

At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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Explanation:

When you heat an atom, some of its electrons are "excited* to higher energy levels. When an electron drops from one level to a lower energy level, it emits a quantum of energy. ... The different mix of energy differences for each atom produces different colours. Each metal gives a characteristic flame emission spectrum.

Answer:

i going off the top of my head

Explanation

Interpreters: They facilitate communication between a deaf and hearing person in different modalities, such as ASL, tactile interpretation, or Cued Speech.

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Assistive listening systems: They enhance the understanding of speech for deaf people who use their residual hearing or personal devices, such as FM/DM, infrared, or induction loops.

Note takers: They capture important pieces of information in a systematic way for deaf students who split their attention between other accommodations and the instructor.

Answer:

B) 1

Explanation:

Lithium is a univalent element, univalent means that it has only one valence electron. If this is true, then lithium can only provide this one valence electron in a voltaic cell.

From the foregoing, each lithium atom can only provide one valence electron in the voltaic cell.

Answer:

B) 1

Explanation:

I got it in class!

Hope this Helps!! :))

Answer:

A) Using the ideal gas law, we can calculate the number of moles of gas present:

```

PV = nRT

```

where:

* P = pressure (atm) = 1 atm

* V = volume (L) = 5.6 L

* n = number of moles of gas

* R = ideal gas constant = 0.08206 L atm / mol K

* T = temperature (K) = 273.15 K

Solving for n, we get:

```

n = (P * V) / RT

```

```

n = (1 atm * 5.6 L) / (0.08206 L atm / mol K * 273.15 K)

```

```

n = 0.25 mol

```

Therefore, there are 0.25 moles of gas present.

B) The molar mass of the gas can be calculated by dividing the mass of the gas (8.0 g) by the number of moles of gas (0.25 mol):

```

Molar mass = Mass / n

```

```

Molar mass = 8.0 g / 0.25 mol

```

```

Molar mass = 32 g/mol

```

The molar mass of the gas is 32 g/mol.

C) The common atmospheric gas with a molar mass of 32 g/mol is oxygen (O2). Therefore, the gas that was collected is oxygen.

Explanation:

Based on the given reactions, the compounds are as follows:

A: The specific product formed from the reaction between prop-1-yne and either 2HBr or H2O2.

B: The product formed when compound A reacts with 2H2O.

C: The product formed when compound B reacts with K2CO3(aq).

D: The product formed from the heat-induced reaction of compound C.

E: The product formed when compound D reacts with HBr.

Based on the given reactions, let's analyze the compounds involved:

Reaction 1: prop-1-yne + 2HBr/H2O2 = A

The reactant prop-1-yne reacts with either 2HBr or H2O2 to form compound A. The specific product formed will depend on the reaction conditions.

Reaction 2: A + 2H2O = B

Compound A reacts with 2H2O (water) to form compound B.

Reaction 3: B + K2CO3(aq) = C

Compound B reacts with K2CO3(aq) (potassium carbonate dissolved in water) to form compound C.

Reaction 4: C + heat = D

Compound C undergoes a heat-induced reaction to form compound D.

Reaction 5: D + HBr = E

Compound D reacts with HBr (hydrobromic acid) to form compound E.

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Particles in a metal are held together by Covalent attractions. These are the strongest attraction or types of bonding

The bonds that hold atoms together to form molecules are called covalent bonds. They are pretty tough and not easily made or broken apart. It takes energy to make the bonds and energy is released when the bonds are broken.

For example, there is a covalent bonding between a Chlorine molecule. the two chlorine atoms are held strongly via covalent bonds.

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At 25 degrees Celsius, with 50g of sugar, the solution will appear clear and homogeneous, with all the sugar dissolved. The ratio of dissolved sugar to undissolved sugar will be 50:0, as all the sugar has dissolved.

If an additional 55g of sugar is added to the 25-degree water, the solution will become supersaturated. This means that the water cannot dissolve all the sugar, resulting in the excess sugar remaining undissolved as solid particles at the bottom of the container. The solution will appear cloudy, and the ratio of dissolved sugar to undissolved sugar will be 50:5, as only 50g of the added sugar can dissolve.

When the solution is heated, the solubility of sugar increases. As a result, more sugar will dissolve, and the solution will become clear again. The ratio of dissolved sugar to undissolved sugar will approach 105:0 as the temperature increases and more sugar dissolves.

If the heated solution is slowly cooled back to 25 degrees Celsius, the solubility of sugar decreases. This will cause the excess sugar to come out of the solution and form solid crystals, which will be visible as sugar particles. The solution will appear cloudy again, and the ratio of dissolved sugar to undissolved sugar will depend on the amount of sugar that remains dissolved after cooling.

Adding a seed crystal to the mixture provides a surface for sugar crystals to form, resulting in the rapid crystallization of the remaining dissolved sugar. The solution will become saturated with sugar crystals, and the ratio of dissolved sugar to undissolved sugar will be close to 0:55, as most of the sugar will have crystallized. The solution will appear cloudy with a significant amount of sugar crystals present.

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The air pressure is low at higher altitudes. The pressure decreases up the higher altitudes. Same with temperature, as we go up the higher altitudes the temperature decreases as molecules becomes more far apart.

altitude ↑     ||     pressure ↓

altitude ↑     ||    temperature ↓

The weight of an alcohol with a density of 0.8g/ml and volume of 50ml is 40g.

HOW TO CALCULATE WEIGHT:

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Answer: Temperature is an objective measurement of how hot or cold an object is. It can be measured with a thermometer or a calorimeter. It is a means of determining the internal energy contained within a given system.

Explanation:

Answer:

Temperature is a physical quantity that expresses hot and cold

Explanation:

Temperature is a physical quantity that expresses hot and cold. This is how the air feels and how hot/cold something is. The less tight the atoms are, the hotter something is. The more tight the atoms are, the cooler something is.

Answer:

Element

Explanation:

Iron is an element

Answer:

It was deflected by a magnet charged particles

C. It becomes easier for molecules to escape.

Decreasing pressure causes a liquid to boil because it makes it simpler for molecules to escape.

Option A: Reducing the pressure does not increase the temperature or alter the liquid's volume (option B). Also, it doesn't force molecules out of the liquid (option D).

Instead, it lessens the pressure placed on the liquid's surface, which enables the liquid's molecules to more readily overcome their attraction to one another and transition into the gas phase.

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Answer:

Paper, some plastics, frosted glass, etc.

Explanation:

The volume occupied at 25 °C. Remember to convert between °C and K. V2 = 3.311 L is the correct answer.

What is volume?

Volume is a measure of the amount of space occupied by an object, or the amount of matter contained within it. It is measured in units such as cubic metres, cubic centimetres, litres, millilitres, etc. Volume is a three-dimensional concept, meaning that it requires three measurements to be taken in order to accurately measure the amount of space an object occupies. The volume of a solid object can be determined by applying the formula V = l x w x h, where l is the length, w is the width, and h is the height of the object. For a liquid or gas, the volume is calculated by measuring its mass and the density of the substance. Volume can also be used to describe the total amount of space something occupies, such as the volume of a room or the volume of a storage container.

Temperature and Volume equation

Given,

The volume at -12°C = 2.90L

Temperature, T1 = -12°C

= (-12°C + 273)

= 261K

And, Volume at 25°C = ?

(25°C + 273)K

= 298K

Now, by using this equation:-

V1/T1 = V2/T2

V2 = V1 x T2/T1

V2 = 2.90L x 298K/261K

V2 = 3.311L

Hence, The volume at  25°C will be 3.311L

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One mole of H₂ reacts with one mole of Cl₂ to give 2 moles of hydrogen chloride gas. The volume of H₂ that will completely react with Cl₂ is 22.4 litres.

In the International System of Units, the mole is the unit of amount of a substance. It is specified that the mole contains exactly 6.022 * 10²³ elementary particles such as atoms, ions or molecules, similar to how a dozen denotes twelve.

At standard temperature and pressure (STP), one mole of any gas occupies a volume of 22.4 litres. From the given equation, the molar ratio of hydrogen and chlorine is 1:1. Since 22.4 litres of chlorine gas is used, then similarly, 22.4 litres of hydrogen gas must also be used up to give 2 moles of the product, hydrogen chloride gas.

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Option B After recrystallization, the salicylic acid was not completely dried. Reweigh it after it has dried would be a possible explanation for the problem

To address the issue, the student could repeat the recrystallization process with proper care and attention to detail, making sure to measure the mass of the product accurately and to dry the product completely before weighing it.

They could also consider using a different recrystallization solvent or a different technique to purify the product. However, without more information about the specific circumstances, it's difficult to say for sure what the best solution would be.

An alkyl ether is an organic compound that contains an oxygen atom bonded to two carbon atoms, one of which is bonded to an alkyl group. Alkyl groups are chains of carbon atoms that are bonded together and may contain one or more carbon atoms.

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C: "Stability of the conjugate base"  is a factor that does not influence the strength of an acid.

The strength of an acid is primarily determined by the ease with which it donates a proton (H+) to water, forming hydronium (H3O+) ions. The factors that influence the strength of an acid include:

However, the stability of the conjugate base (the species formed after the H atom has been donated) does not have a significant effect on the strength of an acid. This is because the stability of the conjugate base is largely determined by the stability of the corresponding anion, which is not directly related to the ability of the acid to donate a proton.

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Answer:

D. 14

Explanation:

This is a Carbon Atom which has an atomic number of 14. 6+8=14

Answer:

adding a catalyst will increase the reaction rate.

Explanation:

im like 95% sure thats right.

Answer:

A. C. D

Explanation:

ap ex

The reagents needed to carry out the conversion of pentene to 2 pentanone is C) H₂O, HgSO₄ / H₂SO₄.

The reagent we used to convert the alkyne to a ketone and contain the same number of carbon . The conversion of 1 - pentyne to pentan-2 -one  is given as follows :

                                         HgSO₄ / H₂SO₄

CH ≡ C - CH₂ - CH₂ - CH₃   ------------->             CH₃ - C - CH₂ - CH₂ - CH₃

1 - pentyne                              H₂O                              ||

                                                                                     O

                                                                                     pentan-2 -one

This reaction is followed by the markownikoff's rule. the reagent used is the mercuric sulfate and the sulfuric acid.

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Solution :

From Fick's law:

\($\frac{D_{AB}}{\Delta z } \times (C_{A1}-C_{A2})=N_a$\)

Mass balance: Exits = Accumulation

\(-N_A A = \frac{dm}{dt}\)

\(-N_A A = \frac{dVp}{dt}\)

\(-N_A A = \frac{dV}{dt}p\)

\(-N_A A = \frac{dhA}{dt}\)

\(-N_A A = \frac{dh}{dt} \times Ap\)

From the last step, area cancels out and thus leaves :

\(-N_A = \frac{dh}{dt} \times p\)

So now we can substitute the \($N_A$\) by the Fick's law

\($\frac{D_{AB}}{\Delta z } \times (C_{A1}-C_{A2})=\frac{dh}{dt} p$\)

Substituting the values we get

\($=\frac{-4 \times 10^{-13}}{0.0001} \times (3 \times 10^{26} - C_{A2}) = \frac{dh}{dt} \times 2.46$\)

\($=-4 \times 10^{-9} \times( 3 \times 10^{26} - C_{A2}) = 0.0001 \times 2.46$\)

\($= -7800 \times 4 \times 10^{-9} \times (3 \times 10^{26}-C_{A2})=0.000246$\)\($=-(3 \times 10^{26}-C_{A2}) = 7.8846 \times 100 \times \frac{1}{69.62} \times 6.022 \times 10^{23}$\)

\($C_{A2} = 6.85 \times 10^{28} \ \text{ boron atoms} /m^3$\)