Solve for X
\( \frac{x - 6}{2} = \frac{2 - x}{x} \)
​

Step-by-step explanation:

Area: bh

The shape is a square in which the side lengths are the same, so we multiply the number squared.

A = 6.25(6.25)

A = 39.06

Volume: lwh

6.25^3 = V

V = 244.14

Hope this helps:)

Step-by-step explanation:

Area: bh

The shape is a square in which the side lengths are the same, so we multiply the number squared.

A = 6.25(6.25)

A = 39.06

Volume: lwh

6.25^3 = V

V = 244.14

I hope I contributed

The diameter of Earth in kilometers is approximately 12,682 km, making option D the correct answer.

To convert the diameter of Earth from miles to kilometers, we can multiply the given diameter in miles by the conversion factor of 1.6 kilometers per mile.

Given that Earth's diameter is 7,926 miles, we can calculate its diameter in kilometers as follows:

Diameter in kilometers = Diameter in miles × Conversion factor

Diameter in kilometers = 7,926 miles × 1.6 kilometers/mile

Diameter in kilometers = 12,681.6 kilometers

Rounding this value to the nearest whole number, we get 12,682 kilometers.

Therefore, the correct answer is option D: 12,682 km.

Option A: 49,553 km is not the correct answer. It is not consistent with the given diameter of Earth.

Option B: 120,586 km is also not the correct answer. It is not consistent with the given diameter of Earth.

Option C: 1,392,650 km is significantly larger than the actual diameter of Earth and is not a plausible value.

In conclusion, the diameter of Earth in kilometers is approximately 12,682 km, making option D the correct answer.

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Answer:

two is a number

too means in addition

to means motion in the direction

Step-by-step explanation:

a) Standard deviation: 3 blueberries.

b) We assume, to apply this rule, that the distribution of blueberries per muffin is bell-shaped, approximately normal.

Standard Deviation:

In statistics, standard deviation is a measure of the amount of variation or distribution of a set of values. A low standard deviation indicates that the values ​​tend to be close to the ensemble mean (also called the expected value), while a high standard deviation indicates that the values ​​are spread over a wider range.

The standard deviation can be abbreviated SD, and is often used in mathematical texts and equations by the lowercase Greek letter σ (sigma) for population standard deviation, or the Latin letter s for standard deviation of the sample.

We know that the number of blueberries in a blueberry muffin baked by Earth Harvest Bakeries can range from 19 to 37 blueberries.

(a) If we use the Empirical Rule 68-95-99.7, specifically the last term, we have that:

- 99.7% of the data will fall between 3 standard deviations from the mean.

(b) Then, if we consider the range of 19 to 37 containing 99.7%, we can calculate the standard deviation as:

   UL - LL = 2 × (3σ)

⇒ 37 - 19 = 6σ

⇒ 6σ = 18

⇒ σ = 3

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The volume of the cone in real life will be 6 feet³.

The volume of the cone model will be:

= 1/3πr²h

= 1/3 × 3.14 × 0.6² × 0.8.

= 0.24

Therefore, the volume of the cone in real life will be:

= 0.24 × 25

= 6 feet³

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The volume of the cone in real life will be

6 feet³.

Step-by-step explanation:

How to calculate the volume?

The volume of the cone model will be:

= 1/3πr²h

= 1/3 x 3.14 x 0.62 x 0.8.

= 0.24

Therefore, the volume of the cone in real life will be:

= 0.24 × 25

= 6 feet³

You are looking so hot (⊙_◎)

Answer:

es un ángulo de 80

Answer:

None

Step-by-step explanation:

We can eliminate the x's by add the 2 equations :

2y = 18

Divide both sides by 2 :

y = 9

Substitute this value into equation 1 to solve for x :

-3x + (9) = 6

Subtract 9 from both sides :

-3x = -3

Divide both sides by -3 :

x = 1

Substitute these values into equation 2 to check :

-3(1) + 6 = 12 ❌❌

So it has no solution

Answer:

2

Step-by-step explanation:

Scale factor is \(2:1\)

A parallelogram is a quadrilateral in which opposite sides are parallel.

Also, opposite sides of a parallelogram are equal.

Find scale factor of the sides in parallelograms \(PQRS,KLMN\),

\(PS:KN=18:9\)

               \(=\boldsymbol{2:1}\)

\(RS:MN=42:21\)

               \(=\boldsymbol{2:1}\)

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Using long division 2/3 is found to be 0.6667, the value is discontinued by approximating a 6 to 7

3 | 2 =

3 | 2 = 0.

3 | 20 = 0.

3 | 20 = 0.6        20 - 3 * 6 = 20 - 18 = 2

3 | 2 = 0.6

3 | 20 = 0.6

3 | 20 = 0.66      20 - 3 * 6 = 20 - 18 = 2

3 | 2 = 0.66

3 | 20 = 0.66

3 | 20 = 0.666      20 - 3 * 6 = 20 - 18 = 2

The procedure continues unending to get 0.666666666.........

Hence we say that 2/3 = 0.6666...≅ 0.6667

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Answer:1 is 36 friends. 2 is $24 as her weekly allowance. 3 is 37 students on each bus

Step-by-step explanation:1. 80-8 because 8 is the amount she has left. You would get 76 which is the amount she gave away. Then you divide 76 by 2 because she gave 2 balls to 1 friend. Then you get the amount of friends she has.

2. When we read the problem it says she spent half of her allowance on mini golf. The half is very important. She earns $20 from cleaning her parent’s car and ends up with $32 all you do is subtract the $20 from $32 because it’ll leave you with 1/2 the money she began with (32-20=12). Then she she already spent half of the money you can either add 12 or multiply the 12 by 2 to get your answer (12+12=24 or 12•2=24).

3.(229-5) you’re subtracting 5 from the 229 students because 5 of them traveled in car. Then you do 224 students divided by 6 buses and you should get 37 students per bus.

a) The area of rectangle ABCD in terms of x and y = 4xy.

b) xy = 10

c) area of triangle EBF​ = 5 m².

Part A) The area of rectangle ABCD:

See the diagram;

The length of rectangle is 2x.

The width of breadth is 2y.

Area = length×breadth

Area = 2x × 2y

Area of ABCD = 4xy m².

Part b) value of xy.

The area of the triangle DEF is 15m².

area ΔDEF = area ABCD - area ΔADE - area ΔBEF - area ΔDFC.

Put the values;

area ΔDEF = 4xy - 2xy/2 - 2xy/2  - xy/2

area ΔDEF = 3xy

equate;

ΔDEF = 3xy and DEF = 15m².

3xy/2 = 15

xy = 10

Thus, the value of xy = 10.

Part c) area of triangle EBF​:

area ΔEBF = xy/2

Put the value of xy = 10.

area ΔEBF = 10/2  = 5

Thus, the area of the triangle EBF 10m².

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The maximum volume of his box is approximately 15.

The maximum value of a graph that represents a function is the y-value of the vertex of the parabola, that is, the point where the graph begins to shift from increasing to decreasing.

Thus, in the graph given, the volume is plotted on the y-axis. The graph also shows a parabola that has a vertex at y = 15. This represents the maximum value.

The vertex, which is at y = 15, represents the maximum volume of the box.

Therefore, this means that the maximum volume of his box is approximately 15.

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Answer: If Frank and John can meet these goals with their diets , they will weigh same after 9.6 weeks and they will weigh 179.2 pounds.

Step-by-step explanation:

Let x = Number of weeks.

As per given question ,

Weight of Frank after x weeks = 160+2x (pounds)

Weight of John after x weeks = 208-3x (pounds)

When Weight of Frank= Weight of John

Weight of Frank after 9.6 weeks = 160+2(9.6) = 179.2 pounds

Weight of John after 9.6 weeks = 208-3(9.6)=179.2 pounds

Hence, If Frank and John can meet these goals with their diets , they will weigh same after 9.6 weeks and they will weigh 179.2 pounds.

Answer:

The one that you pick is correct

According to the question The formula \(\(C(t) = \frac{{0.000001 - 0.000001 \cdot e^{-0.005t}}}{{0.005}}\)\)  for the concentration. the initial value problem for the contaminant concentration \(\(C(t)\)\) in the pond is:

\(\(\frac{{dC}}{{dt}} = 0.000001 - \frac{{0.5C}}{{100}}\)\)

Let's denote \(\(V(t)\)\) as the volume of water in the pond at time \(\(t\)\) and \(\(C(t)\)\) as the concentration of the toxic chemical in the pond at time \(\(t\).\)

The rate at which the contaminant enters the pond can be calculated by multiplying the volumetric flow rate of the contaminated water \((\(0.5 \, \text{m}^3/\text{min}\))\) by the concentration of the toxic chemical \((\(0.0002 \, \text{kg/m}^3\)):\)

\(\(\text{Rate of inflow} = 0.5 \, \text{m}^3/\text{min} \times 0.0002 \, \text{kg/m}^3\)\)

The rate at which the contaminant leaves the pond is given by the volumetric flow rate of the outflowing water, which is also \(\(0.5 \, \text{m}^3/\text{min}\)\), multiplied by the concentration \(\(C(t)\)\) in the pond.

Therefore, the rate of change of the contaminant concentration in the pond can be expressed as:

\(\(\frac{{dC}}{{dt}} = \frac{{\text{Rate of inflow}}}{{V(t)}} - \frac{{\text{Rate of outflow}}}{{V(t)}}\)\)

Since the volume of the pond \(\(V(t)\)\)  remains constant at \(\(100 \, \text{m}^3\),\) the initial value problem for the contaminant concentration becomes:

\(\(\frac{{dC}}{{dt}} = \frac{{0.5 \, \text{m}^3/\text{min} \times 0.0002 \, \text{kg/m}^3}}{{100 \, \text{m}^3}} - \frac{{0.5 \, \text{m}^3/\text{min} \times C}}{{100 \, \text{m}^3}}\)\)

To find the equilibrium concentration, we set \(\(\frac{{dC}}{{dt}}\)\) to zero and solve for \(\(C\):\)

\(\(\frac{{0.5 \times 0.0002}}{{100}} - \frac{{0.5 \times C}}{{100}} = 0\)\)

Simplifying the equation, we get:

\(\(0.0001 - \frac{{C}}{{200}} = 0\)\)

Solving for \(\(C\)\), we find the equilibrium concentration:

\(\(C = 0.0001 \times 200\)\)

The equilibrium concentration is \(\(C = 0.02\), \(\text{kg/m}^3\).\)

To determine the stability of the equilibrium, we can analyze the sign of \(\(\frac{{dC}}{{dt}}\)\)around the equilibrium concentration.

Taking the derivative of \(\(\frac{{dC}}{{dt}}\)\) with respect to \(\(C\)\), we have:

\(\(\frac{{d}}{{dC}}\left(\frac{{dC}}{{dt}}\right) = -\frac{{0.5}}{{100}}\)\)

Since the derivative is negative, the equilibrium concentration of \(\(C = 0.02 \, \text{kg/m}^3\)\) is stable.

Therefore, the initial value problem for the contaminant concentration \(\(C(t)\)\) in the pond is:

\(\(\frac{{dC}}{{dt}} = 0.000001 - \frac{{0.5C}}{{100}}\)\)

The initial value problem for the contaminant concentration \(\(C(t)\)\) in the pond is given by \(\(\frac{{dC}}{{dt}} = 0.000001 - \frac{{0.5C}}{{100}}\)\) with the initial condition \(\(C(0) = 0\).\)

Solving this differential equation yields the formula \(\(C(t) = \frac{{0.000001 - 0.000001 \cdot e^{-0.005t}}}{{0.005}}\)\)  for the concentration in the pond at any time \(\(t\).\)

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The statement "the horizontal, continuous lintel on a classical building supported by columns is called a stylobate" is False.

The horizontal, continuous lintel on a classical building supported by columns is called an entablature, while the stylobate is the platform on which the columns stand.

In classical architecture, the entablature is the horizontal, continuous lintel that rests on top of the columns and consists of three parts: the architrave (the bottom layer), the frieze (the middle layer), and the cornice (the top layer). The entablature helps to unify the columns and create a sense of continuity across the facade of the building.

The stylobate, on the other hand, is the platform or base upon which the columns stand, and is usually elevated above ground level. Together, the stylobate and entablature form the colonnade, a defining feature of classical architecture.

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Answer:

the answer should be w=-E/hf

if it not plz tell me so i can edit  my answer

Step-by-step explanation:

Hope this helps❤️

Answer:

hf-E

Step-by-step explanation:

I took the test

when an ANOVA test results in rejecting the null hypothesis and the experiment has more than two treatment conditions

When an ANOVA test results in rejecting the null hypothesis, it means that there is significant evidence to suggest that there are differences among the treatment conditions. However, it does not provide information about which specific treatment conditions are significantly different from one another. To determine where the significant difference lies, post-hoc tests can be performed. Post-hoc tests are used to compare all possible pairs of means to determine which pairs differ significantly. These tests can include Bonferroni, Tukey, and Scheffe's tests.
It is important to note that the use of post-hoc tests increases the likelihood of committing a Type 1 error, which occurs when the null hypothesis is incorrectly rejected. Therefore, it is important to adjust the level of significance when performing multiple tests to avoid this error.
These tests can help identify the specific treatment conditions that differ significantly from one another.

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Answer: $4,222.50.

Step-by-step explanation:

The polynomial function of degree 7 with the given zeros and multiplicities is: f(x) = x³(x + 2)³(x - 2)

To find a polynomial function with the specified zeros and multiplicities, we can construct it using the factors that correspond to each zero and multiplicity.

Since -2 has a multiplicity of 3, it means it appears three times as a zero. Similarly, 0 has a multiplicity of 3, and 2 has a multiplicity of 1.

A polynomial function with these zeros and multiplicities can be written as:

f(x) = (x + 2)³ × x³ × (x - 2)

To make it a polynomial of degree 7, we can multiply it by an additional linear factor:

f(x) = (x + 2)³ × x³ × (x - 2) × (x - r)

Where "r" is a constant representing the last factor. This factor ensures the degree of the polynomial is 7.

Now, we need to find the value of "r" to complete the polynomial. Since we already have three factors with multiplicity 3 and one factor with multiplicity 1, the polynomial has already reached its degree of 7.

Therefore, we don't need to include the "x - r" factor, and the final polynomial is:

f(x) = (x + 2)³ × x³ × (x - 2)

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The polynomial function of degree 7 with -2 as a zero of multiplicity 3, 0 as a zero of multiplicity 3, and 2 as a zero of multiplicity 1 is f(x) = x^7 + 4x^6 - 12x^5 + 20x^4 - 16x^2.

To find a polynomial function of degree 7 with the given zeros and multiplicities, we can start by constructing the factors of the polynomial.

Since -2 is a zero of multiplicity 3, we have the factor (x + 2)^3. Similarly, since 0 is a zero of multiplicity 3, we have the factor x^3. Lastly, since 2 is a zero of multiplicity 1, we have the factor (x - 2).

Multiplying these factors together, we obtain:

(x + 2)^3 * x^3 * (x - 2)

Expanding this expression, we get:

(x^3 + 6x^2 + 12x + 8) * x^3 * (x - 2)

To simplify further, we multiply the terms:

(x^6 + 6x^5 + 12x^4 + 8x^3) * (x - 2)

Expanding again, we obtain:

x^7 - 2x^6 + 6x^6 - 12x^5 + 12x^4 - 24x^3 + 8x^3 - 16x^2

Combining like terms, we get:

x^7 + 4x^6 - 12x^5 + 20x^4 - 16x^2

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Answer:

a) 29.6%

b)29.9%

Step-by-step explanation:

Here, we want to change the values to percentage form

a) we have this as;

21/71 * 100% = 29.6%

b) we have thus as;

46/154 * 100% = 29.9%

The correct option is option (a) $3,992.50. Pavi currently has a $3,992.50 credit on her current card.

The calculation of the provided data, according to the question, is as follows:

$8000 is the credit limit on the card.

Paid in Full = $2,500

$1,500 has been credited to the account.

The value of recent purchases made by Pavi is $3,000

Applied finance charges equal $7.50

The card's current balance is equal to $4,007.50.

Using the formula below, we can now determine the amount of credit that is now available on the card:

The credit line on the card = Available Credit - New Balance

By entering values into the formula provided, we obtain

Credit available on the current card: $8,000 - $4,007.50= $3,992.50.

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Answer:

Jonah only added two sides together instead of all four sides

Perimeter = 12 \(\frac{1}{2}\)x - 6

Step-by-step explanation:

P = 2(6x - 5) + 2(1/4x + 2)

P = 12x - 10 + 1/2x + 4

P = 12 1/2x - 6

Answer:

divide fifty out of one hundred times thirty. so x equals to fifteen hours

Answer:

1

Step-by-step explanation:

GCF of 343 and 477 is 1, because no number can multiply and get both of them.

The greatest common factor of 343 and 477 is 1, indicating that the two numbers have no common factors other than 1.

To find the greatest common factor (GCF) of 343 and 477, we can determine the common factors of both numbers and identify the largest one.

First, let's list the factors of each number:

The factors of 343 are: 1, 7, 49, 343.

The factors of 477 are: 1, 3, 9, 53, 159, 477.

Now, we identify the common factors from both lists: 1.

Therefore, the greatest common factor of 343 and 477 is 1.

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Answer:

u are wrong ans is 2 nd one

The surface area of the rectangular prism is 88 square inches.

Given that:

Length, L = 6 inches

Width, W = 2 inches

Height, H = 4 inches

Let the prism with a length of L, a width of W, and a height of H. Then the surface area of the prism is given as

SA = 2(LW + WH + HL)

SA = 2(6 x 2 + 2 x 4 + 4 x 6)

SA = 2 (12 + 8 + 24)

SA = 2 x 44

SA = 88 square inches

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Answer:

B 16/3

Step-by-step explanation:

on edg

The volume of the pyramid shown is 16√3 cm³.

Volume of a three dimensional shape is the space occupied by the shape.

Given a solid oblique pyramid.

It has an equilateral triangle as a base with an edge length of 4√3 cm and an area of 12√3 cm².

Volume of the pyramid = 1/3 × base area × height

Base area = 12√3 cm²

Height = 4√3 × tan (30°) = 4√3 × 1/√3 = 4

Volume = 1/3 × 12√3 × 4

             = 16√3 cm³

Hence the volume is 16√3 cm³.

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Answer:

 X= -2

Step-by-step explanation: