The acceleration due to gravity on the moon ,which has the radius 1.74×10⁶ m and mass 7.35×10²² Kg is 1.63 m/s² .
The Acceleration due to gravity is defined as the acceleration of the freely falling bodies due to force of attraction of other body .
it is given that , the radius of the moon is(R) = 1.74×10⁶ m ;
the mass of the moon is(M) = 7.35×10²² Kg ;
we know that the gravitational constant is = 6.67×10⁻¹¹ Nm²/Kg² ;
the formula is :
g = GM/R²
g = (6.67×10⁻¹¹)(7.35×10²²)/(1.74×10⁶)²
g = 4.90×10¹²/3×10¹²
g = 1.63 m/s²
Therefore , the acceleration due to gravity on the moon is 1.63 m/s² .
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A car covers a distance of 200m. If its velocity is 20 m/s², calculate the time taken.
a basketball player grabbing a rebound jumps 70 cm vertically. (a) how much (total) time does the player spend in the top 24 cm of this jump?
a. The total time (ascent and descent) does the basketball player spend in the top 24.0 cm that grabbing a rebound jumps 70 cm vertically = 0.42 s
b. The total time (ascent and descent) does the basketball player spend in the bottom 24.0 cm that grabbing a rebound jumps 70 cm vertically = 0.01 s
Because gravity is pulling on an object as it falls, its speed increases. Gravity near the earth has an acceleration of g = 9.81 m/s². To calculate something's speed (or velocity) after a certain amount of time, simply multiply the acceleration of gravity by the time since it was released.
The free fall object formula:
h = \(\frac{1}{2}\) gt²
v² = 2gh
Where:
h = height/distance (m)
g = acceleration due gravity ( 9.81 m/s²)
t = time (s)
v = the velocity (m/s)
The velocity of the player:
0 - v² = 2gh
v² = 2 x (-9.8) (0.7)
= 3.70 m/s
(a)
The time taken by it in top 24 cm position that grabbing a rebound jumps 70 cm vertically:
h = \(\frac{1}{2}\) gt²
0.24 = \(\frac{1}{2}\) (9.8) t²
t = 0.21 s
The total = 0.42 s
Hence, the total time in that position will be doubled because in that position first it will go up and then go down.
(b) The total time (ascent and descent) does the basketball player spend in the bottom 24.0 cm:
70 - 24.0 = 46 cm = 0.46 m
h = \(\frac{1}{2}\) gt²
0.46 = \(\frac{1}{2}\) (9.8) t²
t₁ = 0.31 s
t₂ = \(\sqrt{\frac{2h}{g} }\)
= 0.3 s
So, the time interval of last 24 cm:
0.31 - 0.30 = 0.01 s
The question is incomplete, it should be:
A basketball player grabbing a rebound jumps 70.0 cm vertically. How much total time (ascent and descent) does the player spend (a) in the top 24.0 cm of this jump and (b) in the bottom 24.0 cm?
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Use the formula given below to calculate the force advantage of the crow-bar (lever) in the picture.
FA = Leffort / Llifting
Select one:
a. 60
b. 32
c. 15
d. 2
Answer:
c.15
FA = Leffort / Llifting
\( \frac{30}{2} \)
=15
why does atomic size increase as you go down a grouping in the table
whats another name 4 the pilgrims.
Answer:
piglets
Explanation:
more than 3
Answer :pedestrian walker.
Explanation:
How many walking paces are there approximately as you walk down Main Street (0.25 miles)?
1 mile = 5280 feet;
1 foot = 12 inches;
22 inches = 1 walking pace
The number of walking paces as you walk down main street (0.25 miles) is 720 walking paces
How to convert 0.25 mile to feet1 mile = 5280 feet
Therefore,
0.25 mile = (0.25 mile × 5280 feet) / 1 mile
0.25 mile = 1320 feet
How to convert 1320 feet to inches1 feet = 12 inches
Therefore,
1320 feet = (1320 feet × 12 inches) / 1 feet
1320 feet = 15840 inches
How to convert 15840 inches to walking pace22 inches = 1 walking pace
Therefore,
15840 inches = (15840 inches × 1 walking pace) / 22 inches
15840 inches = 720 walking paces
Thus, we can conclude that as you walk down main street (0.25 miles), there are 720 walking paces
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An ideal gas in a container is closed on the top by a movable piston. The gas is now heated, so that the temperature goes up. As this happens, the piston moves up. Use ideas about microscopic gas particles and interactions to explain why this happens.
The movement of the piston in response to the heating of the ideal gas can be explained through the kinetic theory of gases. The kinetic theory explains the behavior of gases in terms of the motion of their microscopic particles, such as atoms or molecules.
When the temperature of the gas is increased, the average kinetic energy of the gas particles also increases. This means that the gas particles move faster and collide more frequently with the walls of the container. As a result, the pressure of the gas increases, pushing the piston upwards.
The movement of the piston is a consequence of the gas particles exerting a force on it as they collide with it. The force exerted by each gas particle may be small, but the collective effect of all the collisions results in a net force on the piston that causes it to move upwards.
In summary, the movement of the piston in response to the heating of the ideal gas is due to an increase in the average kinetic energy of the gas particles, resulting in more frequent collisions with the walls of the container and a higher pressure that pushes the piston upwards.
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The kinetic theory of gases helps explain the movement of the piston in response to the heating of the ideal gas. The mobility of small particles in gases, such as atoms or molecules, is explained by the kinetic theory.
The average kinetic energy of the gas particles increases as the temperature of the gas rises. This implies that the gas particles travel quicker and clash with the container's walls more often. As a result, the gas pressure rises, forcing the piston upwards.
The piston moves as a result of the force exerted by the gas particles when they clash with it. Although the force exerted by each gas particle is modest, the cumulative impact of all the collisions results in a net force on the piston, causing it to rise. This results in a net force on the piston that causes it to move upwards.
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PLEASE HELP ASAP WILL GIVE 10 PTS
Which item is made from a synthetic material?
A. cotton pants
B. leather jacket
C. tissue paper
D. wicker basket
Answer: A. Cotton Pants
Explanation:
Answer:
A
Explanation:
A . 2 m/s^2
B . 30 m/s^2
C . 30 m/s
D . 0.5 m/s
Answer:
C-30m/s that my answer
What is the wind speed?
Answer:
the wind speed is 39 right now
1150 kg car is on a 8.70 degree hill. What’s the x component of the normal force
Answer:
The x - component of the normal force is equal to 1706.45 N.
Explanation:
To solve the problem, and since there is no additional information, we can safely assume that the x-axis is parallalel to the hill surface and the y-axis is perpendicular to the x-axis. Knowing that, we can calculate the components of the normal force (or weight for this case), using the following formulas:
\(N
x
=W∗Sin(α)=mg∗Sin(α)\)
\(N
y
=W∗Cos(α)=mg∗Cos(α)\)
Now, using the given information, we have:
\(mass=m=1150Kg\)
\(a=8.70\)
\(g=9.81 \frac{m}{ {s}^{2} } \)
Calculating, we have:
\(N_{x}=mg*Sin(\alpha)\)
\( \: \: \: \: \: \: \: \: \: N_{x}=1150Kg*9.81\frac{m}{s^{2}}*Sin(8.70\°)\)
\(N
x =11281.5
s
2
Kg.m
∗Sin(8.70\°) = \\ \\ 1706.45
s
2
Kg.m
=1706.45.23N\)
Hence, we have that the x-component of the normal force is equal to 1706.45 N.
Answer:
zero
Explanation:
fx=
a rod of negligible mass may rotate about a pivot such that frictional forces are considered to be negligible. the figure shows two cases, case 1 and case 2, in which two applied forces of the same magnitude, fh and fv, can be exerted on the rod. which of the following two statements are correct about the net torque exerted on the rod? select two answers.
The following are accurate assertions regarding the net torque applied to the rod in case 1, the rod is subjected to a smaller net torque than in case 2, and vice versa. The correct options are A and D.
What is torque?The rotating force imposed on an object is measured in torque. The tendency of an object to rotate about an axis is a vector quantity.
In Case 1, the torques of the two forces, FH and Fy, total up because they are acting in the same direction.
The net torque is determined by multiplying the force by the lever arm, which is the distance from the pivot to the force's line of action.
Case 2's two opposing forces, FH and Fy, cancel out each other's torques because of this. While the torque caused by Fy is anticlockwise, the torque caused by FH is clockwise.
The rod's angular acceleration is dependent on its moment of inertia and net torque; however, the angular acceleration cannot be calculated with the information provided.
Thus, the correct options are A and D.
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Your question seems incomplete, the probable complete question is:
Academic integrity only relates to a. Online learning c. Instances of cheating b. All subjects d. Any academic situation I give brainliness
Answer:
answer is d.
Explanation:
are you going to mark me brainlinessist
A diver, of mass 40kg, climbs up to a diving platform 1.25m high. What’s her KE
Explanation:
The formula for KE ( Kinetic Energy ) is : 1/2 mv²
Solution:
First we solve for v ( velocity ) using the formula 2gh, where g is gravity [ 9.8 m/s² ] and h is height [ 1.25 m ]= 2 ( 9.8 m/s² × 1.25 m ) = 24.5 m/s
The velocity is 24.5 m/s.Now solve for KE using the formula 1/2 mv²= 1/2 ( 40 kg × 24.5m/s ² )
= 1/2 ( 40 kg × 600.25 )
= 1/2 ( 24,010 )
= 12,005 Joules
The diver's kinetic energy is 12,005 J.What amount of unbalanced force will cause a 45 kg object to accelerate at a rate of 3.0 m/s2
Answer:
135N will cause a 45 kg object to accelerate at a rate of 3.0 m/s2
Explanation:
Force = mass * acceleration
Force = 45 kg * 3 m/s2
Force = 135N
Force=F
Apply Newton's second law
\(\\ \tt\longmapsto F=ma\)
\(\\ \tt\longmapsto F=45(3)\)
\(\\ \tt\longmapsto F=135N\)
During a lab investigation, students added four 50 g masses to two boxes and arranged the boxes so that they were motionless on a pulley, as shown in the diagram. The students then followed the procedure described in the box. The students recorded their observations after
each procedure and reset the pulley system to the original conditions.
During which procedures did students observe an unbalanced upward force on Box 1?
Group of answer choices
Procedures 4 and 5
Procedures 3 and 4
Procedures 1, 2, and 3
Procedures 1, 3, and 5
Answer:
Procedures 4 and 5.
Explanation:
Both would cause the box to move up.
4, it becomes lighter
5, the other becomes heavier, pulling it down, causing box one to go up
Since we seek the action of force to push up box 1, the students observes an unbalanced upward force on Box 1 in procedures 4 and procedure 5.
In what procedures did students observe an unbalanced upward force on Box 1?Generally, In procedure 4 we added another mass to the box two, therefore, causing box one to experience an upward force.
Therefore, students observe an unbalanced upward force on Box 1 in procedure 4.
Procedure 5 we remove masses from box 1 resulting in box 2 becoming heavier, pulling it down.
Therefore, students observe an unbalanced upward force on Box 1 in procedure 5.
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Which example provides a complete scientific description of an object in motion?
If a man with a mass of 75 kg, standing still, throws an object with a mass of 5 kg at 30 m/s, what will be the recoil velocity of the man, assuming he is standing on a frictionless surface?
Answer:
2 m/s
Explanation:
Given that,
Mass of a man, m₁ = 75 kg
Mass of object, m₂ = 5 kg
Velocity of the object, v₂ = 30 m/s
We need to find the recoil velocity of the man. Let it is v₁. In the whole process, the momentum of the system will remain conserved such that,
\(m_1v_1=m_2v_2\\\\v_1=\dfrac{m_2v_2}{m_1}\\\\v_1=\dfrac{5\times 30}{75}\\\\v_1=2\ m/s\)
So, the recoil velocity of the man is 2 m/s
what is an substance that makes possible the transfer of energy from one location to another especiallt through waves
A medium is a substance that enables the transfer of energy from one location to another through waves or vibrations. It allows the oscillation of particles in the medium, which affects the speed and direction of the wave.
A substance that makes possible the transfer of energy from one location to another through waves is called a medium. A medium is a physical material or substance that can transmit waves or vibrations. Examples of media include air, water, metal, and even vacuum (for electromagnetic waves). When a wave travels through a medium, energy is transferred from one location to another through the oscillation of the particles in the medium. For example, when a sound wave travels through air, the air particles vibrate back and forth, transferring the sound energy from the source of the sound to our ears. The properties of the medium can affect the speed and the direction of the wave. For instance, sound waves travel faster through denser mediums, like water or metal, than through less dense mediums, like air. Similarly, the direction of the wave can change when it encounters a medium with a different density, as in the case of refraction.
In summary, a medium is a substance that can transmit waves or vibrations, allowing the transfer of energy from one location to another through the oscillation of the particles in the medium.
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spheres are not perfect in space. But <> is in the cause of their shape.
Answer:
\( \boxed { \tt{gravitational \: pull(force)}}\)
given that the wavelengths of visible light range from 400 nm to 700 nm, what is the highest frequency of visible light?
The highest frequency of visible light in the light range from 400 nm to 700 nm is 7.5 x 10¹⁴ Hz.
To find out the highest frequency, follow the following concept of optics
f = c/λ
Where c is the speed of light, f is the wave's frequency, and λ is the wavelength of light.
For maximum frequency, we need to choose the lowest wavelength since both share an inverse relation.
f = (3 x 10⁸)/(400 x 10⁻⁹)
f = 7.5 x 10¹⁴
Therefore, the highest frequency is 7.5 x 10¹⁴ Hz.
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WF4-358 is a white dwarf in the globular cluster NGC 6397. This star's spectrum is highlighted with the red box. Notice that wavelength is tracked on the X axis and intensity is tracked on the Y axis. For this activity, we will be paying attention to the wavelengths that have the highest intensity. As you progress throughout the steps of this activity, you will be filling in this table:
Wavelength Suspected Element Frequency Energy
1.
2.
3.
Step 1: Study the Spectrum
Familiarize yourself with the spectral signature of this star, which shows which wavelengths are absorbed at which intensities. After studying the spectrum, notice which wavelengths ranges have the highest intensity (in other words, notice where the black line under WF4-358 reaches a high point and note which wavelengths ranges that point is associated with). Write down three wavelengths that have the highest intensity in WF4-358. Not that because of the scale of this particular graph, you likely won't be able to tell an exact wavelength. Instead, make the best guess that you can with the information you have. Fill in the first column (Wavelengths) of the table with your answer.
Step 2: Determine Elements
After documenting three wavelengths, refer to the diagram below to investigate which elements may be associated with those wavelengths.
For each of the three peaks in the spectrum you noted, make a guess about which element that peak represents. You will take the wavelength you noted in Step 1, and finding that wavelength on the diagram. For example, if you thought that a wavelength of 475 nm was a peak, you would find that wavelength on the chart and note that Argon might be the element represented by that peak. Repeat for all three peaks. Fill the second column (Suspected Element) of the table with your answers.
Step 3: Find Frequencies
Do some online research to find the frequencies of the three wavelengths you identified. Fill in the third column (Frequency) of the table with your answers.
Step 4: Calculate Energy
Use Planck's Equation to calculate the energy of a photon of light at each of the wavelengths you identified. Planck's Equation goes as follows:
E = hv
In this equation:
E = energy, and is unknown. This is what we are solving for.
h = Planck's constant (6.626 x 10^-34 joule-seconds)
v = frequency
Fill in the last column (Energy) of the table with your answers.
Step 5: Reflection Questions)
Would you expect the spectrum of a blackbody radiator to have peaks and valleys like the spectrum of WF4-358? Why or why not? Define blackbody radiators in your answer.
Pick one element from the chart you made. How might you expect its wavelength to change if it goes from traveling through Earth's atmosphere to traveling through water in the ocean?
Submit the following in one word processing document:
The table you completed in Steps 1-4
The answers to the reflection questions from Step 5
The highest points of intensity for WF4-358 include 390nm, 402nm, and 420nm (all estimated by x-axis locations in 10 nm increments).
What is wavelength?Wavelength is the distance between identical points (adjacent crests) in the adjacent cycles of a waveform signal propagated in space or along a wire. In physics, the wavelength is the spatial period of a periodic wave—the distance over which the wave's shape repeats.
These are the closest approximate wavelengths along the x-axis that correspond to the highest intensities along the y-axis for WF4-358.
The highest points of intensity for WF4-358 include 390nm, 402nm, and 420nm (all estimated by x-axis locations in 10 nm increments).
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It's raining. A patch of ground is receiving 35 raindrops per second. Each drop is 1. 1 grams and strikes at 6 m/s. How much force does the rain exert on the patch? Assume the rain does not bounce
The force exerted by the rain on the patch is 0.231 N.
The force exerted by the raindrops on the patch can be found using the formula; F = m × v
where F will be the force, m will be the mass of each raindrop, and v is velocity of each raindrop.
The mass of each raindrop is given as 1.1 grams, which can be converted to kilograms by dividing by 1000;
m = 1.1 g / 1000 = 0.0011 kg
The velocity of each raindrop is given as 6 m/s.
Now, we need to determine the number of raindrops that strike the patch in one second. If the patch is receiving 35 raindrops per second, then the number of raindrops that strike the patch in one second is also 35.
Therefore, the total force exerted by the rain on the patch is;
F = m × v × n
where n will be the number of raindrops per second.
Plugging in the values, we get;
F = 0.0011 kg × 6 m/s × 35
F = 0.231 N
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1. Draw a free body diagram showing all the force on a cart if a shopper pushes the cart with an applied force of 100 N and a friction force of 80N acts on the cart
In physics and engineering, a free frame diagram (FBD; also referred to as a force diagram) is a graphical instance used to visualize the applied forces, moments, and ensuing reactions on a frame in a given situation.
A free-body diagram is a sketch of an item of interest with all the surrounding items stripped away and all of the forces acting on the frame shown. The drawing of an unfastened-body diagram is a critical step in the solving of mechanics issues because it helps to visualize all the forces appearing on an unmarried object.
A free-body diagram is a graphic, dematerialized, symbolic representation of the body (structure, element, or segment of an element) wherein all connecting "pieces" have been removed. An FBD is a convenient method to model the structure, structural detail, or phase that is under scrutiny.
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What is the Morgan-Keenan Spectral Classification system?
A method of classifying stars by their temperatures and compositions.
A method of classifying stars by their distance from the Sun.
A method of classifying stars by their age.
A method of classifying stars by their age and distance from the Earth.
Answer: A method of classifying stars by their temperatures and compositions.
Explanation:
The Morgan-Keenan Spectral Classification system is a method of classifying stars by their temperatures and compositions.
What is Morgan-Keenan Spectral classification of star?The primary factor used to categories stars is their temperature.
The Morgan-Keenan luminosity class (MK or MKK) was developed as a result of the Harvard spectral classification classification scheme does not completely describe the star as it cannot distinguish between stars with the same temperature but different luminosities.
Since then, class I stars have been separated into Ia-O, Ia, and Ib, and classes VI (sub-dwarf), and D (white dwarf) have been added, replacing the original roman numerals between I (supergiant star) and V (main sequence).
The original Harvard classification of the star is supplemented by the MK luminosity class in order to fully define it. For instance, the entire classification of the Sun, which is a main sequence G2 star, is G2V.
The MK luminosity class is added to the Harvard classification of the star in order to fully define it.
A method of classifying stars by their temperatures and compositions is applied in Morgan-Keenan Spectral Classification system.
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Which element most likely interacts with water the same way lithium interacts with water?
Answer:
Is there a multiple choice or select all that apply? I would say Potassium (K) or Sodium (Na)
Explanation:
when 12 is added to a certain number and the result is multiplied by 4. the final result is 60.find the number.
Answer:
3
Explanation:
let the number be x
perform and forming expression
12 is added
=12 + x
4 is multiplied to expression
= 4 (12 + x)
result is 60
equating
4(12 + x) = 60
48 + 4x=60
4x = 60-48
4x = 12
x= 12/4
x= 3
In a free expansion, 1.50 moles of nitrogen doubles in volume. What is the change in entropy? Assume the nitrogen behaves like an ideal gas.
There n is the number of moles, R is the ideal gas constant (8.314 J/molK) and V₁ and V₂ are the initial and final volumes of the gas, respectively.
What is moles?Moles are small animal species belonging to the family Talpidae, which includes various types of mammals commonly referred to as "shrew-moles" or "mole-shrews". They are commonly found in temperate regions of Europe, Asia, and North America and have been known to inhabit a wide range of habitats, from woodlands to grasslands and even wetlands. Moles are small burrowing animals that have a cylindrical body, a pointed snout, and short legs. They have short, velvety fur that helps to camouflage them in the soil and are well adapted to living in underground tunnels. Moles have a strong sense of smell and use their long, sensitive snouts to search for food. They feed mainly on small invertebrates such as earthworms, insects, and larvae.
The change in entropy (ΔS) can be calculated using the equation:
ΔS = nRln(V₂/V₁)
In this case, n = 1.50 moles and V₁ = V₂/2.
Therefore, ΔS = (1.50 moles)(8.314 J/molK)ln(2) = 11.47 J/K
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Choose one of the five types of renewable energy methods and write a 5 sentence paragraph. contrasting the advantages and disadvantages.
Wood and wood waste
Municipal solid waste
Landfill gas and biogas
Ethanol
Biodiesel PLEASE HELP ME 15 POINTS
The renewable energy source among the given is wood and wood wastes. However they cannot be treated as perfectly renewable source because they will produce hydrocarbons when burned and will be exhausted after massive consumption.
What is renewable energy source?Renewable energy source is the source of energy which can be regenerated or recycled after use. Solar energy, wind energy, hydrothermal energy etc. are renewable sources of energy.
Renewable sources are more efficient and nature genuine sources of energy. Whereas non-renewable source such as biogas, fossil fuels, etc. cannot be regenerated and will be exhausted after use.
Wood wastes is a common fuel used in homes as well. However, wood wastes produces harmful gases on burning and moreover they require cutting trees to get sufficient fuel.
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Question 2: What is the velocity ratio of this pulley?
Load
distance=12 m
Effort
distance= 4 m
Answer:
1/3
Explanation:
Velocity ratio = distance moved by effort / distance moved by load