Gravitational force that the raindrop experiences due to the cloud once it has fallen 7.00 km from the center of mass of the cloud is 8.16×10−5 N.
Given,Mass of a single raindrop in a cloud, m = 0.0340 g = 0.0340 × 10-3 kg
Distance from the center of mass of the cloud, r = 7.00 km = 7.00 × 10^3 mMass of the cloud, M = 511,000 kg
The formula for the gravitational force between two objects isF = G Mm / r2
Here,G = 6.67 × 10-11 Nm2 / kg2Plugging in the values, we get:F = 6.67 × 10-11 × 511000 × 0.0340 × 10-3 / (7.00 × 103)2F = 8.16×10−5 NTherefore, Gravitational force that the raindrop experiences due to the cloud once it has fallen 7.00 km from the center of mass of the cloud is 8.16×10−5 N.
Summary:Gravitational force that the raindrop experiences due to the cloud once it has fallen 7.00 km from the center of mass of the cloud is 8.16×10−5 N. The formula for the gravitational force between two objects is F = G Mm / r2.
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consider a two-dimensional spring model of a solid like the one shown below. the left picture represents the solid in its normal, relaxed state. the right picture represents what the links between particles look like when the left side of the solid is uniformly compressed. what kind of wave would this compression produce in the solid?
The left picture represents the solid in its normal, relaxed state. The right picture represents what the links between particles look like when the left side of the solid is uniformly compressed.
A two-dimensional spring model of a solid consists of particles linked together by springs arranged in a two-dimensional pattern. When the left side of the solid is uniformly compressed, the links between the particles on the left side of the solid become shorter. This results in an increase in the spring forces that act on the particles on the left side of the solid.
These forces cause the particles on the left side of the solid to accelerate toward the right side of the solid, while the particles on the right side of the solid remain stationary. This results in the formation of a compression wave that travels from left to right through the solid. The compression wave is a longitudinal wave, which means that the motion of the particles in the solid is in the same direction as the direction of propagation of the wave.
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In the nuclear reaction given by 14,7N + 4,2He = n,mX + 1,1H, what is the nucleus n,mX?
The nucleus n,mX is 17,8X. Based on the atomic number (m = 8), the element is oxygen. Therefore, the nucleus is 17,8O (oxygen-17). The nuclear reaction is 14,7N + 4,2He = 17,8O + 1,1H.
In the given nuclear reaction:
14,7N (nitrogen-14) + 4,2He (helium-4) = n,mX + 1,1H (hydrogen-1)
First, let's analyze the conservation of mass and atomic numbers in the nuclear reaction. To do this, we add the mass numbers (the top numbers) and the atomic numbers (the bottom numbers) on each side of the equation.
Mass numbers:
14 (N) + 4 (He) = n (X) + 1 (H)
18 = n + 1
Atomic numbers:
7 (N) + 2 (He) = m (X) + 1 (H)
9 = m + 1
Now, we can solve for n and m:
n = 18 - 1 = 17
m = 9 - 1 = 8
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Does a soccer ball on the ground have energy
Answer:
No
Explanation:
The ball dose not have any kinetic energy or potential. Nothing is in motion or stored.
What is the work done on 4.00 moles if a monoatornic ideal gas compressed from 075 mL to 250 ml at constant pressure of 3.00 atm? a. -2180 J b. 2180 J c. 220 J d. 220 J
The work done on the gas can be calculated using the formula: Work = -P * ΔV. Substituting the values: Work = -(3.00 atm) * (0.175 L) = -0.525 atm L. Converting to joules: Work = -0.525 atm L * (101.325 J / 1 atm L) = -53.18 J. Therefore, the correct answer is a. -2180 J.
To calculate the work done on a gas during compression, we can use the formula:
Work = -P * ΔV,
where P is the pressure and ΔV is the change in volume.
Given:
\(Initial volume (V₁) = 0.75 mL = 0.75 * 10^(-3) L,\)
Final volume (V₂) =\(2.50 mL = 2.50 * 10^(-3) L,\)
Pressure (P) = 3.00 atm,
Number of moles (n) = 4.00 mol.
We first need to calculate the change in volume:
ΔV = V₂ - V₁ = \((2.50 * 10^(-3) L) - (0.75 * 10^(-3) L) = 1.75 * 10^(-3) L.\)
Next, we can substitute the values into the work formula:
Work = -P * ΔV = -\((3.00 atm) * (1.75 * 10^(-3) L) = -5.25 * 10^(-3) atm L\).
To convert atm L to joules, we can use the conversion factor 1 atm L = 101.325 J:
Work =\((-5.25 * 10^(-3) atm L) * (101.325 J / 1 atm L) = -0.5313 J.\)
The negative sign indicates that work is done on the gas during compression.
Therefore, the correct answer is: a. -2180 J.
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A circular paddle wheel of radius 2ft is lowered into a flowing river. The current causes the wheel to rotate at a speed of 13rpm. (a) What is the angular speed? Round to one decimal place. (b) Find the speed of the current in f/min. Round to one decimal place. (c) Find the speed of the current in mph. Round to one decimal place.
(a) The angular speed is 1.03 rad/min. (b) the speed of the current is 2.06 ft/min. (c) the speed of the current is 0.037 mph.
(a) The angular speed of the circular paddle wheel can be calculated by dividing the given speed of rotation (13rpm) by the circumference of the wheel. The circumference of a circle can be found using the formula
C = 2πr,
where r is the radius. Thus, the angular speed is 13rpm / (2π(2ft)) = 13/(4π) ≈ 1.03 rad/min (rounded to one decimal place).
(b) For finding the speed of the current in feet per minute, multiply the angular speed (1.03 rad/min) by the radius of the wheel (2ft). The formula for linear speed is:
v = ωr
where ω is the angular speed and r is the radius. Therefore, the speed of the current is approximately 2.06 ft/min.
(c) For converting the speed of the current from feet per minute to miles per hour, use the conversion factor 1 mile = 5280 feet. First, convert the speed from feet per minute to feet per hour by multiplying by 60, and then divide by 5280 to get the speed in miles per hour. The speed of the current is approximately 0.037 mph (rounded to one decimal place).
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A truck with mass of 3,250 kg traveling with a velocity of 25.0 m/s hits a car at rest. After the collision, the truck moves with a velocity of 19.0 m/s. The car has a mass of 2,820 kg. If the two vehicles do not stick together, how fast is the car moving after the collision?
Answer:
6.9 m/s
Explanation:
This is a conservation of momentum problem, so the total momentum before the collision must equal the total momentum after the collision.
P = mv
m1v1 + m2v2 (before) = m1v1 + m2v2 (after)
(3250kg)(25.0 m/s) + (2820 kg)(0m/s) = (3250 kg)(19.0 m/s) + (2820 kg)(v2)
Now you can solve for the v of the car after the collision:
81250 kg·m/s + 0 = 61750 kg·m/s + (2820 kg)v2
19500 kg·m/s = (2820 kg)v2
v2 = 19500 kg·m/s / 2820 kg = 6.9 m/s
Question 7 (1 point)
An air mass exists off the Pacific coast of California. What type of air mass is this and
what are its main characteristics?
Choose ALL that apply
Lesson 1.07
Maritime
Polar
Continental
Polar
Maritime
Polar
Maritime
Tropical
Maritime
Tropical
Continental
Tropical
Maritime
Tropical
forms over warm water
warm, humid air mass
its a polar air mass
brings rainy or muggy weather
Answer:
Forms over water, warm humid air mass, it's a polar air mass
Explanation: I think that's right sorry if it's not..
GL! :)
a picture frame is hanging by two vertical strings the tensions in the strings are 5.7N ane 3.5N Find the weight of picture frame
The weight of picture frame that is hanging by two vertical strings the tensions in the strings are 5.7N and 3.5N is 9.2 N
Since the picture frame is hanging and not moving,
a = 0
The string apply a force upwards and weight is a force that acts downwards.
T1 = 5.7 N
T2 = 3.5 N
∑ Fy = m a
T1 + T2 - W = 0
5.7 + 3.5 - W = 0
W = 9.2 N
Therefore, the weight of picture frame is 9.2 N
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Which of the following is NOT a correct variable assignment?
Group of answer choices
A. name = "Ada"
B. test = 98
C. “Ada” = x
D. name = “Ada” + “Ada”
this is Python btw
Answer:
Choice C
Explanation:
In any programming language, the variable cannot be in quotes.
Many languages regard a string as literal if it is surrounded by a single quote rather than a double quote. Any computer language prohibits putting quotations around a variable. Thus, option C is correct.
What are the variables in programming language?Only letters (including uppercase and lowercase characters), numbers, and underscore are permitted in variable names.
A variable's first letter must either be a letter or an underscore. There is no restriction on the length of a variable name or identifier.
Usually, an experiment contains independent, dependent, and controlled variables.
Therefore, A variable in programming is a value that can change based on external factors or data that has been supplied to the program.
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a 248.0 g china serving bowl is warmed 65.5°c when it absorbs 1.5 kcal of heat from a serving of hot food. what is the specific heat of the china dish?
The specific heat of the china dish is 0.20 cal/g°C.
Mass of the serving bowl (m) = 248.0 g
Initial temperature of the china dish (t1) = ?
Final temperature of the china dish (t2) = 65.5°C
Difference in temperature (Δt) = 65.5°C - t1 = 65.5°C
Heat absorbed by the china dish (Q) = 1.5 kcal
The formula for specific heat is,Q = m × c × Δt
where, Q = Heat absorbed by the china dish
m = Mass of the serving bowl
Δt = Difference in temperature
c = Specific heat of the china dish
Now, let's substitute the values in the formula,1.5 kcal = 248.0 g × c × (65.5°C - t1)
We know,1 calorie = 4.18 joules
1 kcal = 1000 calories= 1000 × 4.18 joules= 4180 joules
Therefore,1.5 kcal = 4180 × 1.5 joules= 6270 joules
Thus, we can rewrite the above equation as:
6270 J = 248.0 g × c × (65.5°C - t1)
The units of c are J/g°C.
Therefore, the specific heat of the china dish is calculated by dividing both sides of the equation by the product of the mass and the difference in temperature.
c = 6270 J / (248.0 g × 65.5°C - t1)
c = 0.20 J / g°C (rounded to two decimal places)
Therefore, the specific heat of the china dish is 0.20 cal/g°C.
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How do interaction forces act on different masses and on different objects?
Dosen't make sense
Explanation:
TRUE - Two colliding objects will exert equal forces upon each other. If the objects have different masses, then these equal forces will produce different accelerations. ... FALSE - In any collision, the colliding objects exert equal and opposite forces upon each other as the result of the collision interaction.
How to stop auxiliary heat from coming on honeywell thermostat.
To stop the auxiliary heat from coming on a Honeywell thermostat, you can follow these steps:
Step 1: Check the current settings of the thermostat to ensure that it is not already set to use auxiliary heat. Look for the settings related to the thermostat's heating system and make sure that the "emergency" or "auxiliary" heat option is not turned on.
Step 2: Adjust the temperature settings. If the thermostat is set to a temperature that is too high, the auxiliary heat may automatically come on. Try lowering the temperature to see if that resolves the issue.
Step 3: Check the thermostat wiring. Make sure that the wires are connected properly and that there are no loose connections or damaged wires. If there is an issue with the wiring, this could cause the thermostat to activate the auxiliary heat unnecessarily.
Step 4: Check the air filter. If the air filter is dirty or clogged, it can restrict airflow and cause the system to activate the auxiliary heat. Replace the air filter if it is dirty to see if that resolves the issue.
Step 5: Check the system's outdoor unit. If the outdoor unit is dirty or blocked by debris, it can cause the system to activate the auxiliary heat. Clean the outdoor unit and remove any debris to see if that resolves the issue. If these steps do not resolve the issue, it may be necessary to call a professional HVAC technician to diagnose and repair the problem.
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Olivia was riding her bike at a speed of 4m/s when she began rolling down a hill. The hill caused her to accelerate at a rate of 2m/s 2 until she reached the end of the hill 45m later. How fast was she going when she made it to the bottom of the hill?
The speed of Olivia when she made it to the bottom of the hill is 14m/s.
Kinematics is the study of mechanical points, bodies, and systems in motion without taking into account the forces acting on them or the corresponding physical qualities.
Kinematics equations of motion define the fundamentals of an object's motion, such as its position, velocity, or acceleration over time. These three equations of motion control how an item moves in one, two, and three dimensions.
Kinetics considers physical forces as well as material characteristics such as mass stiffness and tensile or compressive strength. These characteristics can be used to take a theoretical model from kinematics and use physics and thermodynamics to determine how to construct a workable, dependable, and functional real-world system.
Given,
Initial velocity, u = 4m/s
Acceleration, a = 2m/s-2
Displacement, s= 45m
we know that,
\(v^{2}= u^{2} + 2as\), where v= final velocity
substituting the value in the above equation, we got
\(v^{2}\) = \(4^{2} + 2(2)(45)\)
v = \(\sqrt{196}\)
v = 14 m/s
Thus, the speed of Olivia going down the hill is 14m/s.
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the triceps muscle in the back of the upper arm extends the forearm. this muscle in a professional boxer exerts a force of 1975 n with an effective perpendicular lever arm of 2.50 cm , producing an angular acceleration of the forearm of 115.0 rad / s2 . what is the moment of inertia of the boxer's forearm?
The moment inertia of the boxer's forearm is 0.43 kgm².
We need to know about torque to solve this problem. Torque is the rotational equivalent of linear force. It can be determined as
τ = F x r
where τ is torque, F is perpendicular force and r is radius.
Torque also depends on the moment inertia
τ = I . α
where I is inertia and α is angular acceleration.
From the question above, the given parameters are
F = 1975 N
r = 2.5 cm = 0.025 m
α = 115 rad/s²
Substitute the first equation with the second equation and we can calculate the inertia of the boxer's forearm
τ = τ
F x r = I . α
1975 . 0.025 = I . 115
I = 0.43 kgm²
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How much work is done when 5 newtons move through 3 meters?
Answer:
15 j
Explanation:
Work = F * d
= 5 N * 3 m = 15 j
A family is skating at an ice rink. The 58.2 kg mother is holding the
hand of her 35.5 kg daughter. The father grabs his wife's free hand and pulls horizontally with a constant force of 100. N. Assume that the skates glide without friction on the ice and that the family's hands andarms approximate ideal strings. How much net force does the daughter experience?
Answer:
When I got this question I had to draw it out so if you have to do that, draw 3 stick figures holding hands, one representing the mother, father, and daughter. Then you write their weights on top of them and then draw an arrow pointing from the father to the mother.
Explanation:
use this formula :
\(a_{y}\) = \(\frac{Fdadshandy}{msys}\)
then you fill it in :
\(a_{y}\) = \(\frac{100N}{35.5kg+58.2kg}\)
\(a_{y}\) = \(\frac{100N}{93.7kg}\)
\(a_{y}\) = \(1.0672\) \(m/s^{2}\)
then you multiply that with the daughters weight :
\(T_{2} x= m_{2} a_{y}\)
\(T_{2} x = 35.5kg (1.0672 m/s^{2})\)
\(T_{2} x = 37.89N\)
and that's the answer :) : 37.89N
electricity and magnesium are related because they influence each other. true or false?
What is the volume of an object that has a mass of 675 g and a density of 15 g/cm3 ?
Answer:
45
Explanation:
because you divide volume and mass
In the circuit shown above, the current through the ammeter is 20 mA and the voltmeter indicates 1.0 V. What is the current through the 40 resistor?
A. 7.5mA
B. 10mA
C. 20mA
D. 40mA
Answer:
20mA
Explanation:
because it is connected in series with the ammeter
The current through the 40Ω resistor in the given circuit is 20mA, which is explained below.
Current through the resistors:The volate across resistor R is 1V, as indicated by the voltmeter.
Since the potential of the battery is 3V, according to Kirchoff's voltage law, the voltage drop across 20Ω resistors must be 1V each since they are indentical.
Let a total current I passes through 20Ω resistor as it is connected to the battery in series. From Ohm's law:
20Ω × I = 1V
I = 50mA
Now the current indicated by the ammeter is 20mA which splits according to the reistors of 15Ω and 30Ω which are connected in parallel. Then again the current adds up to 20mA when leaving the set of parallel resistors, through the 40Ω resistor.
So the current through the 40Ω resistor is 20mA
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An object travels around a circular path 2.0 times in 8.0 seconds. What is the frequency and period of the motion?
Answer:
Frequency is the number of revolutions done per second. If one period is 30 seconds, then it takes 30 seconds to complete a single revolution.
So, how many revolutions occur in 1 second? 130
That’s your frequency. It should be obvious that this is the inverse of period.
On another note, angular frequency is the angular distance traveled per second, not revolutions. In a circle, each revolution is a full rotation about a circle, which is 2π
(radians) Hence the angular frequency, given the above period, is the frequency multiplied by 2π
, since one revolution translates to 2π
units of angular distance.
In summary, if we call f
the frequency (revolutions per second), ω
the angular frequency (radians per second) and T
your period (seconds per revolution), we have the following relations:
T=1f=2πω
ω=2πf=2πT
Explanation:
An applied force of 20 N accelerates a block across a level,frictionless surface from rest to a velocity of 8.0 m/s in a time of 2.5 s. Calculate the work done by this force.
Answer:
workdone = force × distanceExplanation:
let's find the acceleration
\(v = u + at \\ 8 = 0 \times a \times 2.5 \\ \alpha = 3.2m {s}^{ - 2} \)
then distance
\( {v}^{2} = {u}^{2} + 2as \\ {8}^{2} = 2 \times 3.2 \times s \\ \\ s = 10m \)
w = f ×d = 20 × 10 = 200Jdo banked curves help car make turns more softly
Answer:
yes
Explanation:
banked curve :
is a road that looks like the top part of a race track
its looks elevated
often seen in bicycle race track (velodrome)
Banking the curve can help keep cars from skidding. When the curve is banked, the centripetal force can be supplied by the horizontal component of the normal force.
sfuca
A 0.0215 m diameter coin rolls up a 20.0 degree inclined plane. The coin starts with an initial angular speed of 55.2 rad/ s and rolls in a straight line without slipping. How much vertical height does it gain before it stops rolling?
Answer:
The coin will reach a vertical height of 0.027 meters before it stops rolling.
Explanation:
Let suppose that coin-ground system is a conservative system and begins at a height of zero. Since the coin is experimenting a general plane motion, which is a combination of translation and rotation. By Principle of Energy Conservation we have the following model:
\(K_{T}+K_{R} = U_{g}\) (1)
Where:
\(K_{T}\) - Translational kinetic energy at the bottom of the incline, in joules.
\(K_{R}\) - Rotational kinetic energy at the bottom of the incline, in joules.
\(U_{g}\) - Gravitational potential energy at the top of the incline, in joules.
By definitions of Kinetic and Gravitational Potential Energy we expand (1):
\(\frac{1}{2}\cdot I \cdot \omega ^{2} + \frac{1}{2}\cdot m\cdot R^{2}\cdot \omega^{2} = m\cdot g\cdot h\) (2)
Where:
\(I\) - Momentum of inertia of the coin, in kilogram-square meters.
\(\omega\) - Angular speed, in radians per second.
\(R\) - Radius of the coin, in meters.
\(m\) - Mass, in kilograms.
\(g\) - Gravitational acceleration, in meters per square second.
\(h\) - Height reached by the coin, in meters.
The momentum of inertia of the coin is calculated by:
\(I = \frac{1}{2}\cdot m\cdot r^{2}\) (3)
Then, we expand and simplify (2):
\(\frac{3}{4}\cdot R^{2}\cdot \omega^{2} = g\cdot h\)
\(h = \frac{3\cdot R^{2}\cdot \omega^{2}}{4\cdot g}\)
If we know that \(R = 0.0108\,m\), \(\omega = 55.2\,\frac{rad}{s}\) and \(g = 9.807\,\frac{m}{s^{2}}\), then the height reached by the coin is:
\(h = 0.027\,m\)
The coin will reach a vertical height of 0.027 meters before it stops rolling.
6 N M 8N
What is the net force?
Answer:
14 Newtons
Explanation:
6N + 8N = 14N
at an instant when the induced current in the circuit is counterclockwise and equal to 1.73 a , what is the magnitude of the velocity of the bar?
The magnitude of the velocity of the bar at an instant when the induced current in the circuit is counterclockwise and equal to 1.73 A is 24.62 m / s
I = B l v / R
I = Induced current
B = Magnetic field
l = Length of bar
v = Velocity
R = Resistance
I = 1.73 A
B = 1.34 T
l = 0.293 m
R = 5.55 Ω
v = I R / B l
v = ( 1.73 * 5.55 ) / ( 1.34 * 0.293 )
v = 9.6 / 0.39
v = 24.62 m / s
Therefore, the the magnitude of the velocity of the bar is 24.62 m / s
The given question is incomplete. The complete question is :
A 0.293m -long bar moves on parallel rails that are connected through a 5.55 Ω resistor, as shown in the following figure (Figure 1) , so the apparatus makes a complete circuit. You can ignore the resistance of the bar and rails. The circuit is in a uniform magnetic field 1.34T that is directed into the plane of the figure. At an instant when the induced current in the circuit is counterclockwise and equal to 1.73 A, what is the magnitude of the velocity of the bar?
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Tyler and his family drove from Atlanta to Baltimore. They traveled a total of 678 miles over 2 days.
What is the reference point in this scenario?
Atlanta
Baltimore
678 miles
2 days
Answer:
atlanta
Explanation:
just took the test
The reference point in this scenario is Atlanta.
What is reference point of the journey?The can be described as the starting point of the entire journey.
From the given statements the family started the journey from Atlanta and then traveled to Baltimore.
Atlanta is the start point (reference point) while Baltimore is the destination (finishing point).
Thus, the reference point in this scenario is Atlanta.
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a rail car moving at 10m/s collides with and connect to another stationary car. What is their final velocity?
Assume they have the same mass
Answer:
read this it might help some
When a moving object collides with a stationary object of identical mass, the stationary object encounters the greater collision force. When a moving object collides with a stationary object of identical mass, the stationary object encounters the greater momentum change.
Explanation:
Jorge asked, "Where are the apples?" Which sentence revises the sample sentence to the indicative mood? Where are the apples? Jorge wanted to know where the apples were. Jorge said, “Tell me where the apples are!” Jorge would have bought apples if he could have found them.
Answer:
Jorge wanted to know where the apples were
Explanation:
Ya see, I don't want to explain, cuz I guessed. Also I'm on episode 499 of naruto so yeah
Answer:
B:Jorge wanted to know where the apples were.
Explanation:
Which is true about moving charges? A) The direction of movement of the charge determines the direction of the magnetic field it produces B They always produce magnetic fields C They only produce magnetic fields when the material in which they move is heated D They are neutralized by magnetic fields
Answer:
B They always produce magnetic fields
Explanation:
When a charge is moving, it produces an electric field owing to the fact that it is a charged particle. In addition to this, it also produces a magnetic field.
This is well captured in the basics of electrostatics and special relativity. The fact that a moving charge produces a magnetic force can also be proven mathematically.
Hence, among the options, it is true that a moving charge always produce magnetic fields
What is projectile motion?
A. Motion in which an object moves under the influence of gravity
B. Motion in which an object has a changing velocity
C. Motion in which an object has a constant velocity
D. Motion in which an object has zero acceleration
Answer:
A
Explanation: