If the beginning temperature was -13°F at 5:00 a.M., what was the temperature at 9:00 a.M.? Change in Temperature 5:00 a.M. – 6:00 a.M. -3°F 6:00 a.M. – 7:00 a.M. -2°F 7:00 a.M. – 8:00 a.M. -6°F 8:00 a.M. – 9:00 a.M. 7°F b. The same cold front hit Hartford, Connecticut the next morning. The temperature dropped by 7°F each hour from 5:00 a.M. To 9:00 a.M. What was the beginning temperature at 5:00 a.M. If the temperature at 9:00 a.M. Was -10°F?

Answer:

20!

Step-by-step explanation:

Isosceles triangles have 2 angles are the same. Since we can't do 140, because interior angles of a triangle equal 180, then we need to subtract 140 from 180. 180-140=40. 40/2 because of 2 angles=20. 20 is the angle.

Answer:

20

Step-by-step explanation:

The slope-intercept form of the equation of the line through the given point and parallel to the given line is y=x−14.

In the given question we have to write the slope-intercept form of the equation of the line through the given point and parallel to the given line.

The given points are (–2, –16).

The given equation of line is y = x – 5.

Standard equation of line is y=mx+c.

After comparing to the standard equation.

Slope m(1) = 1

The line passes through (−2,−16), so the point will satisfy the equation y=mx+c. So

−16=−2*1+c

Simlifying

−16=−2+c

Add 2 on both side, we get

c = −16+2

c = −14

As we know that if line is parallel then

m(1)=m(2)

So the value of solpe m = 1

Now the equation of line

y=1*x+(−14)

y=x−14

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The right answer is:

How do you write the slope-intercept form of the equation of the line through the given point and parallel to the given line?

Point (−2,−16), y = x – 5

By using metrics such as revenue or profit per hour, we can compare the profitability of different time intervals and identify the most and least profitable ones.

To analyze profitability, we can use a metric such as revenue or profit per hour. For instance, we can calculate the revenue generated in each time interval, divide it by the number of hours in that interval to get the revenue per hour. Then, we can compare the revenue per hour in different intervals to determine which ones are more profitable than others.

The time intervals could be hourly, or you could divide them into smaller segments, such as 15 or 30-minute intervals, depending on your data's granularity. For instance, we could analyze data for the morning, afternoon, and evening time intervals, which are typically the busiest times for most businesses.

Now, to answer your question, based on my analysis of the sample data, the least profitable time interval was the afternoon.

This finding means that during this interval, the business generated the least revenue or profit per hour compared to the other intervals.

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Answer:

b = 4

Step-by-step explanation:

Try setting up the equation of the pythagorean theorem.

hypotenuse^2 = leg(a)^2 + leg(b)^2

c^2 = a^2+b^2

Now substitute what you know and solve for the unknown.

5^2 = 3^2+b^2

25 = 9 + b^2

b^2 = 25-9 = 16

b = 4.

Answer c

Step-by-step explanation:

Answer: i think its A

Step-by-step explanation: hope this helped

Answer:

Step-by-step explanation:

A circle has a diameter of 3 meters. Which statement about the circumference and area is true?

A comparison of the area and circumference is not possible since the area cannot be determined.

The numerical value of the circumference and area are equal.

The numerical value of the circumference is greater than the numerical value of the area.

The numerical value of the circumference is less than the numerical value of the area.

Using the area and the circumference of the circle, it is found that the correct statement is given by:

The numerical value of the circumference is greater than the numerical value of the area.

The area of a circle of diameter d is given by:

\(A = \frac{\pi}{4}d^2\)

The circumference of a circle of diameter d is given by:

\(C = \pi d\)

In this problem, we have that d = 3, hence:

\(A = \frac{\pi}{4} \times 3^2 = \frac{9\pi}{4} = 2.25\pi\)

\(C = \pi \times 3 = 3\pi\)

Hence the correct option is given by:

The numerical value of the circumference is greater than the numerical value of the area.

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Answer:

a)

\( \sin(2( \frac{5}{13} )) = 2 \sin( \frac{5}{13} ) \cos( \frac{5}{13} ) \)

b)

\( \cos( 2(\frac{5}{13}) ) = { cos }^{2} \frac{5}{13} - {sin}^{2} \frac{5}{13} \)

The rate of change of the function f(x, y) = sin(x/y) at the point (π, 1) is undefined or does not exist.

To find the rate of change of the function \(f(x, y) = \sin\left(\frac{x}{y}\right)\) at the point \((\pi, 1)\), we need to compute the partial derivatives of \(f\) with respect to \(x\) and \(y\) and evaluate them at the given point.

The partial derivative of \(f\) with respect to \(x\) is \(\frac{\partial f}{\partial x} = \frac{1}{y} \cos\left(\frac{x}{y}\right)\), and the partial derivative with respect to \(y\) is \(\frac{\partial f}{\partial y} = -\frac{x}{y^2} \cos\left(\frac{x}{y}\right)\).

Evaluating these partial derivatives at \((\pi, 1)\), we have:

\(\frac{\partial f}{\partial x}(\pi, 1) = \frac{1}{1} \cos(\pi) = -1\),

\(\frac{\partial f}{\partial y}(\pi, 1) = -\frac{\pi}{1^2} \cos(\pi) = -\pi\).

The rate of change of the function at the point \((\pi, 1)\) is then given by the vector \(\left(\frac{\partial f}{\partial x}(\pi, 1), \frac{\partial f}{\partial y}(\pi, 1)\right) = (-1, -\pi)\).

In summary, the rate of change of the function \(f(x, y) = \sin\left(\frac{x}{y}\right)\) at the point \((\pi, 1)\) is represented by the vector \((-1, -\pi)\). This vector indicates the direction and magnitude of the steepest change in the function at that point.

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The value of the test statistic F is 3.7014

To test whether two or more of the population means are different, we can use the F-test in the analysis of variance (ANOVA). The test statistic F is calculated by dividing the variance between groups by the variance within groups. In this case, we compare the variability of the sample means to the variability within each sample.

By plugging the given values into the formula for calculating the F-test statistic, we obtain the value of 3.7014. This value will help us determine whether there are significant differences among the population means.

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The accumulated value of the investment of $15,000 for 4 years at an interest rate of 5% is approximately $18,319.41 when compounded semiannually, $18,404.43 when compounded quarterly, $18,483.23 when compounded monthly, and $18,500.56 when compounded continuously.

What is compound interest?

Compound interest is when you earn interest on both the money you've saved and the interest you earn.

We can use the formula for the accumulated value of an investment, which is:

\(A = P(1 + r/n)^{(nt)}\)

where:

A is the accumulated value (or future value) of the investment

P is the principal (or present value) of the investment, which is $15,000 in this case

r is the annual interest rate as a decimal, which is 0.05 (since the interest rate is 5%)

n is the number of times the interest is compounded per year

t is the number of years

(a) Compounded semiannually:

If the investment is compounded semiannually, then n = 2 (twice a year) and t = 4 years. Substituting these values into the formula, we get:

\(A = $15,000(1 + 0.05/2)^{(2*4)}\)

A  ≈ $18,319.41

So the accumulated value of the investment, compounded semiannually, is approximately $18,319.41.

(b) Compounded quarterly:

If the investment is compounded quarterly, then n = 4 (four times a year) and t = 4 years. Substituting these values into the formula, we get:

\(A = $15,000(1 + 0.05/4)^{(4*4)}\)

≈ $18,404.43

So the accumulated value of the investment compounded quarterly, is approximately $18,404.43.

(c) Compounded monthly:

If the investment is compounded monthly, then n = 12 (twelve times a year) and t = 4 years. Substituting these values into the formula, we get:

\(A = $15,000(1 + 0.05/12)^{(12*4)}\) ≈ $18,483.23

So the accumulated value of the investment, compounded monthly, is approximately $18,483.23.

(d) Compounded continuously:

If the investment is compounded continuously, then n approaches infinity and the formula becomes:

\(A = Pe^{(rt)}\)

Substituting the given values into the formula, we get:

\(A = $15,000e^{(0.05*4)}\)

≈ $18,500.56

So the accumulated value of the investment, compounded continuously, is approximately $18,500.56.

Therefore, the accumulated value of the investment of $15,000 for 4 years at an interest rate of 5% is approximately $18,319.41 when compounded semiannually, $18,404.43 when compounded quarterly, $18,483.23 when compounded monthly, and $18,500.56 when compounded continuously.

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Applying the formula of the surface area of a box, the total amount of plastic wrapping needed to cover the box is: 697 cm².

The total surface area of a box is the sum of all the areas of the six faces of the box.

The area of each face can be found by multiplying the length by the width of that face.

The area of each face is given as:

Area = length * width.

To find the amount of plastic wrapping needed to cover the entire box, you first need to find the surface area of the box.

The surface area of the box is given by:

Surface area = 2(19 cm * 14 cm) + 2(19 cm * 1.5 cm) + 2(14 cm * 1.5 cm)

= 2(266 cm²) + 2(28.5 cm²) + 2(21 cm²)

= 532 cm² + 57 cm² + 42 cm²

= 631 cm²

To find the total amount of plastic wrapping needed to cover the box, you need to add the extra 66 cm² needed to allow for the overlapping at the edges.

This gives a total of 631 cm² + 66 cm² = 697 cm² of plastic wrapping needed to cover the box.

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Total stockholders’ equity 7,800,000

Statement of stockholders’ equity for CC for the year ended December 31, 2012:Particulars Amount ($)
Common Stock 100,000

Additional Paid-in Capital 4,100,000
Retained Earnings (Opening Balance) 3,000,000
Add: Net Income for the year ended December 31, 2012 800,000
Total retained earnings 3,800,000

Less: Cash Dividend Declared on July 1 and paid on July 31 (200,000)
Retained earnings (Closing balance) 3,600,000
Total stockholders’ equity 7,800,000

Explanation:The given information is as follows:Common Stock on January 1, 2012 = $100,000Additional Paid-in Capital on January 1, 2012 = $4,100,000

Retained Earnings on January 1, 2012 = $3,000,000Net Income for the year ended December 31, 2012 = $800,000Cash Dividend Declared on July 1 and paid on July 31 = $200,000

To prepare the statement of stockholders’ equity for the year ended December 31, 2012, we will begin by preparing the opening balances of each of the equity accounts. We will then add the net income to the retained earnings account.

The closing balance for retained earnings is then computed by subtracting the cash dividend declared and paid from the total retained earnings. Finally, the total stockholders' equity is calculated by adding the balances of all the equity accounts.

Calculations:Opening balance of common stock = $100,000

Opening balance of additional paid-in capital = $4,100,000

Opening balance of retained earnings = $3,000,000

Net Income for the year ended December 31, 2012 = $800,000

Retained earnings (Opening Balance) = $3,000,000

Add: Net Income for the year ended December 31, 2012 = $800,000

Total retained earnings = $3,800,000Less: Cash Dividend Declared on July 1 and paid on July 31 = $200,000Retained earnings (Closing balance) = $3,600,000

Total stockholders’ equity = Common Stock + Additional Paid-in Capital + Retained Earnings (Closing balance) = $100,000 + $4,100,000 + $3,600,000 = $7,800,000

Therefore, the statement of stockholders’ equity for CC for the year ended December 31, 2012, is as follows:Particulars Amount ($)
Common Stock 100,000
Additional Paid-in Capital 4,100,000

Retained Earnings (Opening Balance) 3,000,000
Add: Net Income for the year ended December 31, 2012 800,000
Total retained earnings 3,800,000

Less: Cash Dividend Declared on July 1 and paid on July 31 (200,000)
Retained earnings (Closing balance) 3,600,000
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If the force, f (newtons), between two objects is inversely proportional to the square of the distance, d (meters), between them and the force is 0.005 newtons when the distance between the objects is 2 meters, then the value of d when f= 0.048 is 0.65m.

To find the value of d when f = 0.048 newtons, follow these steps:

Therefore, when f = 0.048 newtons, the distance between the objects is approximately 0.65 meters.

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Answer:

Step-by-step explanation:

That appears to be approximately 45 degrees, so to the nearest 10, I would put that at about a 50 degree angle.

Answer:

32%

Step-by-step explanation:

\(\frac{1088}{3400}\)=\(\frac{x}{100}\)

(1088)(100)=(3400)(x)

108800=3400x

x=32

32%

The percent of the budget spent on housing is 31.76%.

What is percentage?

Percentage is a mathematical term which means number or ratio expressed in terms of fractions of 100. it can be calculated by dividing given value to the whole value and multiplied by 100. we represent it through ' %'.

Given that, The riddle family income is 3400 per month.

They spend 1088 per month on housing.

We know the formula for percentage which is;

Percentage = (given value/whole value)*100,

Percentage =  (1080/3400)*100

Percentage = 31.76

Hence, The percentage is 31.76%.

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In other words, based on the given sample, we can say with 90% confidence that between 13.5% and 16.5% of adult Americans have used their smartphone to make a purchase.

To find the 90% confidence interval for the population proportion of adult Americans who have used their smartphone to make a purchase, we can use the following formula:

CI = p ± z*√((p(1-p))/n)

where:

p = sample proportion

= 542/3611

= 0.15 (rounded to two decimal places)

n = sample size

= 3611

z = z-score for 90% confidence level

= 1.645 (from standard normal distribution table)

Plugging in the values, we get:

CI = 0.15 ± 1.645*√((0.15(1-0.15))/3611)

= 0.15 ± 0.015

This means that we are 90% confident that the true proportion of adult Americans who have used their smartphone to make a purchase is somewhere between 0.135 and 0.165.

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Answer:

81

Step-by-step explanation:

:)

Answer: 25%

Step-by-step explanation: I got it correct.

The seven crosses plotted on the graph represent a decline in the number of eggs laid per week as the chickens age, with the number of eggs laid decreasing each year before reaching a minimum at or around 18 months of age.

Number is a mathematical object used to count, measure, and label. It is a fundamental concept in mathematics, and is used to describe sets, objects, and other mathematical structures. Numbers can be represented in a variety of ways, such as in the form of numerals (1, 2, 3, etc.), symbols (√2, 3/4, etc.), or words (one, two, three, etc.). Numbers can be used to compare, add, subtract, multiply, and divide. They can also be used to represent data and solve equations.

Assuming Safia's statement is true, plotting seven crosses on a graph to support her statement would look something like this:

Number of eggs chickens lay each week
-7-
-6-
-5-
-4-
-3-
-2-
-1-
0
1
2
3
4
5
6
7
Age of chicken in years
0
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18

In this graph, the number of eggs laid by the chickens decreases as they get older, with the maximum number of eggs laid at or around 18 months of age. The seven crosses plotted on the graph represent a decline in the number of eggs laid per week as the chickens age, with the number of eggs laid decreasing each year before reaching a minimum at or around 18 months of age.

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Answer:

200 is not a perfect square because the square root of 200 is 14.14. The cubed root of 200 is 5.85. Because neither answer is a whole number (in both answers, there were more numbers after, but I rounded), I wouldn't classify 200 as a perfect square or a cube.

Step-by-step explanation:

Answer:

w = -21

Step-by-step explanation:

-2/3 w = 14

Multiply each side by -3/2 to isolate w

-3/2 * -2/3w = 14*-3/2

w = -21

Answer:

The coordinates of the image under the y-axis will be:

Step-by-step explanation:

Given the point

We know that when we reflect a point across the y-axis, the y-coordinate remains the same, but the x-axis reverses its sign.

Thus,

Rule of reflection under y-axis:

P(x, y) → P'(-x, y)

Here, P'(x, y) is the image of the P(x, y)

Given that the point

Thus, the coordinates of the image under the y-axis will be:

(x, y) → (-x, y)

a(-2, 5) → a'(-(-2), 5) = a'(2, 5)

Therefore, the coordinates of the image under the y-axis will be:

Answer:

(B) 2x5x7

Step-by-step explanation:

Answer:

B

hope this helps! :)

Answer:

$31 dollars every week.

Answer:

Two statement are true.

O The function is increasing on the interval (-∞, 0).

O The function is increasing on the interval (0, ∞).

Step-by-step explanation:

The function h(x) = 3x is a linear function (straight line) with a slope of 3, and a y-intercept of 0.  The constant, positive slope means that h(x) will increase over the interval (-∞, ∞).

See the attached graph.

The expected time for activities, use the formula for expected value and multiply the time for each activity by its probability. Therefore, the expected time for these activities is 2.8 hours.

To calculate the expected time for activities, we can use the formula for expected value.

The expected value is calculated by multiplying the time for each activity by its probability of occurrence, and then summing up these values. The formula for expected value is: Expected Value = (Time1 * Probability1) + (Time2 * Probability2) + ... + (TimeN * ProbabilityN) Here's a step-by-step example:

1. List all the activities and their corresponding times and probabilities.

2. Multiply the time for each activity by its probability.

3. Sum up the values obtained in step 2.

For example, let's say we have two activities: Activity 1: Time = 2 hours, Probability = 0.6 Activity 2: Time = 4 hours, Probability = 0.4 Using the formula, we calculate the expected time as follows: Expected Time = (2 hours * 0.6) + (4 hours * 0.4) = 1.2 hours + 1.6 hours = 2.8 hours

Therefore, the expected time for these activities is 2.8 hours.

Here full question is not provided  but the full answer given above.

Remember, this is just one example, and you can use the same formula for any number of activities with their respective times and probabilities. In summary, to calculate the expected time for activities, use the formula for expected value and multiply the time for each activity by its probability. Then, sum up these values to get the expected time.

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