if a small rock is released from rest at point a, it will start accelerating towards the asteroid due to the force of gravity. (true or false?)

The frequencies of the wire's first, second, and third harmonics are 755 Hz, 1550 Hz, and 4650 Hz respectively.

The fundamental frequency can be described as the lowest frequency of a periodic waveform. In terms of a superposition of sinusoids, the fundamental frequency can be defined as the lowest frequency sinusoidal in the sum of harmonic frequencies.

Given the mass of the wire, m = 0.341 g = 3.41 × 10⁻⁴ kg

The length of the wire, L 70.5 cm = 0.705 m

The tension in the wire, T = 578 N

The frequency of the fundamental vibration can be calculated as:

\(\displaystyle \nu =\frac{1}{2} \sqrt{\frac{T}{mL} }\)

\(\displaystyle \nu =\frac{1}{2} \sqrt{\frac{578}{3.41 \times 10^{-4}\times 0.705} }\)

ν = f₁ = 755 Hz

Second harmonic, f₂ = 2f₁ = 2 × 775 = 1550 Hz

Third Harmonic, f₃ = 3 f₂ = 3 ×1150 = 4650 Hz

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The 520 nm wavelength is the longest at which a metal will emit an electron.

The wavelength, which is also the distance between two wave crests and troughs, is the measurement of wave length. In cycles per second (Hz), the term "frequency" refers to the number of vibrations that cross a specific area in a second (Hertz). This article talks about the relationship between wavelength and frequency.

The length of a waveform signal that is propagating in space or over a wire is measured by the separation between identical points (adjacent crests) in the adjacent cycles. This length is often stated in meters (m), centimeters (cm), or millimeters (mm) in wireless systems (mm).

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Answer:

F = 37 N

Explanation:

The minimum force required to move the block must be equal to the static frictional force between the block and the table. This force is given as:

F = Frictional Force

F = μs R

where,

F = Force required to move the block  = ?

μs = Coefficient of static friction = 0.74

R = Normal Reaction of the Block = Weight of the Block = 50 N

Therefore,

F = (0.74)(50 N)

F = 37 N

Answer:37

Explanation:

\(\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}\)

\(\\ \sf\longmapsto Acceleration=\dfrac{8-2}{3}\)

\(\\ \sf\longmapsto Acceleration=\dfrac{6}{3}\)

\(\\ \sf\longmapsto Acceleration=2m/s^2\)

Answer: 2 m/s^2

Explanation:

V1-Vf/ T

2m/s - 8m/s / 3s

6m/s / 3s =

2 m/s^2

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question

430 g = 0.43 kg

We have

force = 0.43 × 10

We have the final answer as

Hope this helps you

Answer:

Explanation:

En cuánto tiempo se pueden caminar 20 km? Una persona sana, acostumbrada a andar camina a unos 4 o 5 kilómetros/hora, en terreno llano. Puede tardar 5 horas o 4.

Answer:

4,320meters

Explanation:

Explanation:

\(E = \frac{BA}{t} \sin( \theta) \\ = \frac{1.23 \times 2}{1} \\ = 2.46 \: V\)

Answer:

index fossil

Explanation:

Answer:

Lincoln town car (luxury Ford car)

used commonly for taxi/limos

like around 1995

edmunds

Answer:

i am sorry i have no idea

Explanation:

Answer:

41.52 m

Explanation:

Using,

v = d/t....................... Equation 1

v = speed of pulse of sound, d = distance travelled by the pulse of sound, t = total time taken.

From equation 1, make d the subject of the equation

d = vt............................ Equation 2

Given: t = 0.12 s.

Constant: v = 346 m/s

Susbtitute these values into equation 2

d = 346(0.12)

d = 41.52 m

Answer:

49.06 Newtons

Explanation: Using Newton's Second Law of Physics, F=ma

the mass of the car is 22.3kg and the acceleration of the object is 2.2m/s^2 then you would multiply the two and get 49.06 Newtons. You want the acceleration to be in m/s^2

Answer:

i dont know

Explanation:

Sorry and good luck

A) The mass of 28.76 mL of acetone is approximately 22.7 g.

B) The volume of 6.40 g of acetone is approximately 8.12 mL.

A) To determine the mass of 28.76 mL of acetone, we need to know the density of acetone. The density of acetone is approximately 0.789 g/mL. Therefore, we can calculate the mass as follows:

Mass = Volume * Density

Mass = 28.76 mL * 0.789 g/mL

Performing the calculation:

Mass ≈ 22.67564 g

Rounding the result to the correct number of significant figures, the mass of 28.76 mL of acetone is approximately 22.7 g.

B) To determine the volume of 6.40 g of acetone, we can rearrange the formula:

Volume = Mass / Density

Volume = 6.40 g / 0.789 g/mL

Performing the calculation:

Volume ≈ 8.116 g/mL

Rounding the result to the correct number of significant figures, the volume of 6.40 g of acetone is approximately 8.12 mL.

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Answer:

Either C or D.

Explanation:

Either one of them.

Answer:

While waves that travel within the depths of the ocean are longitudinal waves, the waves that travel along the surface of the oceans are referred to as surface waves. A surface wave is a wave in which particles of the medium undergo a circular motion.

Explanation:

Are you satisfied or I should continue in the comments.

Ari's final vertical jump height is 5.2 m.

Ari's final vertical jump height is calculated from the law of conservation of energy as shown below.

P.E ( of Ari ) = P.E ( of Bari )

m1gh1 = m2gh2

where;

h1 = ( m2h2 ) / ( m1 )

h1 = ( 70 x 4 ) / ( 50 )

h1 = 5.6 m

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Answer:

A

Explanation:

to simplify let's make it apart the denominator into three part

\( \frac{ {3xy}^{2} }{ {x}^{2} {y}^{2} } - \frac{ {8x}^{2} y}{ {x}^{2} {y}^{2} } + \frac{ {5x}^{2} {y}^{2} }{ {x}^{2} {y}^{2} } \)

now let's simplify

\( \frac{3}{x} - \frac{8}{y} + 5\)

so the answer is A

hope it helps

for any question comment me ❤❤

Given an average acceleration of 3.51 m/s² for a duration of 2.01 seconds and a final velocity of 15.9 m/s, the car's initial velocity can be calculated as 8.868 m/s.

The equation of motion that relates acceleration (a), time (t), initial velocity (u), and final velocity (v) is v = u + at. Rearranging this equation, we have u = (v - at).

In this scenario, the car's average acceleration is given as 3.51 m/s² and the time is 2.01 seconds. The final velocity of the car is 15.9 m/s. Plugging these values into the equation, we can calculate the initial velocity of the car.

Substituting the given values, we have 15.9 m/s = u + (3.51 m/s² * 2.01 s). By rearranging the equation and isolating the initial velocity, we get u = 15.9 m/s - (3.51 m/s² * 2.01 s). Performing the calculations, we find that u = 8.868 m/s.

Therefore, the car's initial velocity is determined to be 8.868 m/s.

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Answer:

i dont know

Explanation:

hello

If two object experiences the same displacement at the same time, the two objects must have the same average velocity.

The average velocity of an object is defined as the change in displacement per change in time of motion. This can be written as follows;

\(avg. \ velocity = \frac{\Delta \ displacement }{\Delta \ time} \\\\V = \frac{\Delta \ x}{\Delta t}\)

If two object experiences the same displacement at the same time, it means that the change in displacement with time is constant.

\(\frac{\Delta x_1}{\Delta t_1} = \frac{\Delta x_2}{\Delta t_2} = V_{avg}\)

Thus, we can conclude that if two object experiences the same displacement at the same time, the two objects must have the same average velocity.

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(a) Flowchart: A condenser process flowchart is provided, illustrating the inputs and outputs of the humid air stream, O₂, N₂, and the condensed liquid water. (b) Total flow rate: The total flow rate of the feed stream entering the condenser is 5.296F mol/s, considering the flow rates of water vapor, O₂, and N₂. (c) Enthalpy and heat transfer: The enthalpy changes for water vapor and O₂ are calculated, resulting in a heat transfer of -0.072 kF kW, indicating heat removal by the condenser. the heat transferred by the condenser is -0.072 kF kW.

(a) Flowchart:

(b) Total flow rate of the feed stream:

The flow rate of N2 leaving the condenser is given as 5.18 mol/s.

The flow rate of water vapor entering the condenser is 58.0 mol% of F.

80% of the above water vapor is condensed and removed, leaving 20% remaining.

So, 20% of the above water vapor remaining in the humid air after condensation is 0.116F mol/s.

The flow rate of O2 is given as 8.8 mol% of F.

The total flow rate of the feed stream is the sum of the flow rates of water vapor, O2, and N2:

Total flow rate = Flow rate of water vapor + Flow rate of O2 + Flow rate of N2

              = 0.116F + 0.088F + 5.18

              = 5.296F mol/s

(c) Inlet-Outlet Enthalpy Table:

To calculate the heat transferred by the condenser, we need to determine the enthalpy changes for water vapor (H3 to H4) and O2 (H5).

The enthalpy change for water vapor can be calculated as:

ΔH_vap = Enthalpy of water vapor at 30°C - Enthalpy of water vapor at 150°C

      = [40.657 + 0.119 × (30 - 0)] - [40.657 + 0.119 × (150 - 0)]

      = -13.607 kJ/kmol

Enthalpy of water leaving the condenser (H4) can be calculated as:

H4 = Enthalpy of water vapor at 30°C = 40.657 kJ/kmol

Enthalpy of O2 leaving the condenser (H5) can be taken as:

H5 = Enthalpy of O2 at 30°C = 0.102 kJ/kmol

The heat transferred by the condenser (q) can be calculated as:

q = Total flow rate × ΔH

 = (5.296F mol/s) × (-13.607 kJ/kmol) × 10⁻³ kW/J

 = -0.072 kF kW (where kF is the constant conversion factor 10⁶)

Therefore, the heat transferred by the condenser is -0.072 kF kW.

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99.3°F is equivalent to 37.4°C

A temperature unit developed from the SI (International System of Units) is Celsius (symbol: °C).

Prior to the adoption of the metric system, Fahrenheit (symbol: °F) was a commonly used measurement of temperature.

To convert Fahrenheit (°F) to Celsius (°C) we have to first subtract 32 from Fahrenheit and then multiply it by .5556 or 5/9.

We have to convert 99.3 degrees Fahrenheit (°F) to Celsius (°C),

We can use the following formula:

°C = (°F - 32) x 5/9

As per the given information,

°F = 99.3

Substituting the value 99.3 for °F, we get:

°C = (99.3 - 32) x 5/9

= 67.3 x 5/9

= 37.4

Therefore, 99.3°F is equivalent to 37.4°C.

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Answer:

Se obtienen 2,27 gramos de metanol.

Explanation:

La reacción entre monóxido de carbono e hidrógeno para producir metanol es la siguiente:

CO + 2H₂ → CH₃OH  

Para encontrar el reactivo limitante y el reactivo en exceso, debemos calcular el número de moles de CO y H₂:

\(\eta_{CO} = \frac{m}{M} \)              

En donde:    

m: es la masa

M: es el peso molecular  

\(\eta_{CO} = \frac{m}{M_{CO}} = \frac{2,0 g}{28,01 g/mol} = 0,071 moles \)

\(\eta_{H_{2}} = \frac{2,0 g}{2,02 g/mol} = 0,99 moles \)

Dado que la relación estequiométrica entre CO y H₂ es 1:2, el número de moles de hidrógeno gaseoso que reaccionan con el monóxido de carbono es:

\( \eta_{H_{2}} = \frac{2}{1}*0,071 = 0,142 moles \)      

Entonces, se necesitan 0,142 moles de H₂ para reaccionar con 0,071 moles de CO y debido a que se tienen más moles de H₂ (0,99 moles) entonces el reactivo limitante es CO y el reactivo en exceso es H₂.

Ahora podemos encontar la masa de metanol obtenida usando el reactivo limitante (CO) y sabiendo que la realcion estequiométrica entre CO y CH₃OH es 1:1.    

\( \eta_{CH_{3}OH} = \eta_{CO} = 0,071 moles \)

\( m = 0,071 moles*32,04 g/mol = 2,27 g \)

Por lo tanto, se obtienen 2,27 gramos de metanol.

Espero que te sea de utilidad!      

The accommodation process is essential for the eye to maintain clear vision, regardless of the distance of the objects being viewed.

Accommodation is the process by which the eye’s lens changes shape to focus on objects at varying distances. When the eye is focused on a distant object, the ciliary muscle in the eye relaxes and the lens becomes flatter, thereby increasing the distance between the lens and the retina.

This enables the eye to focus light rays from distant objects on the retina. When the eye is focused on a nearby object, the ciliary muscle contracts and the lens becomes thicker, bringing it closer to the retina and enabling it to focus light rays from the nearby object onto the retina.

Therefore, the human eye can accommodate the images of objects located at different distances from the eye. This is made possible by the ciliary muscles. The ciliary muscle adjusts the curvature of the lens in the eye to enable the eye to focus light rays on the retina, which is at the back of the eye.

The  answer to the question of what is the process of accommodation in the human eye is that the ciliary muscles of the eye adjust the lens’ shape to enable the eye to focus on objects at varying distances, resulting in clearer vision.

The conclusion is that the accommodation process is essential for the eye to maintain clear vision, regardless of the distance of the objects being viewed.

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Explanation:

i think it is 375 J

w=f.dscos.theta

angle is 0 degree bw the force(75N) and displacemnet(5m) .