If a little bit of lead nitrate gets in contact with a persons eye will it cause serious issues?

Answer:

Latitude

ocean currents

Wind

Elevation

Water

The activity of the sample containing 1.00 µg of radioactive 223Ra is 5.14 x 10^-5 curies.

We will use the equation

Activity = (number of radioactive nuclei) x (decay constant)

The number of radioactive nuclei can be found using Avogadro's number, which gives the number of atoms in a mole of substance.

For 223Ra, the number of atoms in 1.00 µg (or 1.00 x 10^-6 g) is:

(1.00 x 10^-6 g) / (223 g/mol x 6.022 x 10^23 atoms/mol) = 2.69 x 10^14 atoms

The decay constant is found as:

t1/2 = 11.4 days = 9.84 x 10^5 seconds (since 1 day = 8,6400 seconds)

λ = ln(2) / t1/2 = 7.05 x 10^-9 s^-1

In conclusion, the activity of the sample is:

Activity = (2.69 x 10^14 atoms) x (7.05 x 10^-9 s^-1) = 1.90 x 10^6 Bq

When converted to curries, we have:

Activity = (1.90 x 10^6 Bq) / (3.7 x 10^10 Bq/Ci) = 5.14 x 10^-5 Ci

Learn more about Avogadro's number, at: https://brainly.com/question/14138110

#SPJ1

Q = Ksp = 1 × 10^(-12).

Substituting the values into the Nernst equation, we have:

0.799 V = E° - (RT/2F) * ln(1 × 10^(-12))

Now, solving for E°:

E° = 0.799 V + (RT/2F) * ln(1 × 10^(-12))

The value of R is the ideal gas constant, T is the temperature in Kelvin, and F is the Faraday constant.

To find the standard reduction potential at 25°C for the half-reaction Ag2CrO4(s) + 2e¯ → 2Ag(s) + CrO4²-(aq), we can use the Nernst equation, which relates the standard reduction potential (E°) to the equilibrium constant (K) and the reaction quotient (Q).

The Nernst equation is given as follows:

E = E° - (RT/nF) * ln(Q)

Given information:

Ksp = 1 × 10^(-12)

E = +0.799 V (standard reduction potential of Ag+ to Ag)

Since the reaction involves the dissolution of Ag2CrO4(s), the reaction quotient Q can be expressed as [Ag+]²/[CrO4²-].

Since the stoichiometry of the reaction is 2:1 for Ag2CrO4 to Ag+, we can say that [Ag+]² = Ksp.

Therefore, Q = Ksp = 1 × 10^(-12).

Substituting the values into the Nernst equation, we have:

0.799 V = E° - (RT/2F) * ln(1 × 10^(-12))

Now, solving for E°:

E° = 0.799 V + (RT/2F) * ln(1 × 10^(-12))

The value of R is the ideal gas constant, T is the temperature in Kelvin, and F is the Faraday constant.

Please note that without specific values for temperature (T) and the ideal gas constant (R), the exact standard reduction potential at 25°C cannot be determined.

For more question on temperature

https://brainly.com/question/4735135

#SPJ8

The concentration of I in 0.10 M AgNO, saturated with AgI in the solubility product  is 8.3 x 10^-16 M.

The solubility product expression for AgI is:

Ksp = [Ag+][I-]

At equilibrium, the concentration of Ag+ ions is equal to the solubility of AgI, which is equal to the molar solubility of AgI in 0.10 M AgNO3. Let's assume that the molar solubility of AgI is x. Then, the equilibrium concentrations of Ag+ and I- ions are:

[Ag+] = 0.10 M + x

[I-] = x

The solubility product expression can be written as:

Ksp =\(\sqrt{x}\) ([Ag+] * [I-])

Substituting the equilibrium concentrations into the solubility product expression, we get:

Ksp = √(0.10 M + x) * (x)

Using the quadratic equation, we can solve for x:

Ksp =√ 8.3 x 10^-17

0.10 M is much greater than x, so we can assume that (0.10 M + x) ≈ 0.10 M

Ksp = (0.10 M) * (x)

x = Ksp / (0.10 M)

x = 8.3 x 10^-16

So, the molar solubility of AgI is 8.3 x 10^-16 M. Since the concentration of I- ions is equal to the solubility of AgI, the concentration of I- ions is also 8.3 x 10^-16 M.

Learn more about solubility product  below.

https://brainly.com/question/857770

#SPJ1

Approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

To determine the number of molecules of HCl required to form 34.52 g of MgCl₂, we need to use the molar mass and stoichiometry of the balanced equation:

Mg(OH)₂(s) + 2 HCl(aq) → 2 H₂O(l) + MgCl₂(aq)

The molar mass of MgCl₂ is 95.21 g/mol.

First, we need to calculate the number of moles of MgCl₂ formed:

Moles of MgCl₂ = mass of MgCl₂ / molar mass of MgCl₂

Moles of MgCl₂ = 34.52 g / 95.21 g/mol

Moles of MgCl₂ = 0.363 mol

According to the balanced equation, the stoichiometric ratio between HCl and MgCl₂ is 2:1. Therefore, the moles of HCl required can be calculated as follows:

Moles of HCl = 2 * Moles of MgCl₂

Moles of HCl = 2 * 0.363 mol

Moles of HCl = 0.726 mol

To calculate the number of molecules, we need to use Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.

Number of molecules of HCl = Moles of HCl * Avogadro's number

Number of molecules of HCl = 0.726 mol * 6.022 x 10^23 molecules/mol

Number of molecules of HCl = 4.37 x 10^23 molecules

Therefore, approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

For more such questions on molecules

https://brainly.com/question/1351818

#SPJ8

Answer:

major ecological grouping of plants and animals

food chain

*biome*

bacteria and fungi that break down dead matter

*decomposers*

a state of change in which the end result is equal or

balanced

*dynamic equilibrium*

the basic relationships that show how a community of plants,

animals, and bacteria live and grow and how these living

*ecosystem*

things are dependent on each other as well as the Sun, soil,

and other nonliving parts of their environment; a cycle of

relationships

line of plants and animals that shows the order in which

*Food chain*

organisms are eaten

a condition or conditions of the nonliving surroundings, such

*environmental factor*

Explanation:

Answer:Favorable

Explanation:um I know That it is Favorable sorry!

The gas law that is calculated with the pressure and volume variables at a constant temperature is Boyle's Law. Boyle's Law states that the pressure (P) of a gas is inversely proportional to its volume (V) when temperature (T) is held constant.

Mathematically, it is expressed as P₁V₁ = P₂V₂, where P₁ and V₁ represent the initial pressure and volume, and P₂ and V₂ represent the final pressure and volume.According to Boyle's Law, if the volume of a gas is reduced while keeping the temperature constant, the pressure will increase proportionally.

Similarly, if the volume is increased, the pressure will decrease. This relationship holds as long as the temperature remains constant throughout the process. Boyle's Law is one of the fundamental gas laws and provides insights into the behavior of gases under changing pressure and volume conditions at a constant temperature.

For more such questions on gas law

https://brainly.com/question/30233942

#SPJ11

Answer:

Friction, tension, air resistance requires physical contact .

The density of water is 1.0 grams per milliliter then it will be sink in water

Density is a word we use to describe how much space an object or substance takes up in the volume and in relation to the amount of matter in that object or substance its mass) and another way to put it is that density is the amount of mass per unit of volume

Here given density is 1.0 grams per milliliter and it will be sink in water because the density of water in 1.0 g/ml and this object is more dense than water and the density of an object determines whether it will float or sink in another substance and an object will float if it is less dense than the liquid it is placed in and an object will sink if it is more dense than the liquid it is placed

Know more about density

https://brainly.com/question/18366165

#SPJ1

Answer:

Nitrite

Explanation:

Nitrous Oxide = N₂O

Nitrite = NO₂

Ammonia = NH₃

Nitrate = NO₃⁻

para sakin ang magiging pasiya ko ay susunod sa payo ng mga magulang ko dahil yun ang nakabubuti sakin

A leather jacket and printer paper are examples of items that can be made from renewable resources, while plastic forks, metal cans, and electronics are not considered renewable due to their reliance on non-renewable materials and processes. Option  C, E

The two correct answers that are made from renewable resources are:

C) Leather jacket: Leather is derived from animal hides, which are a byproduct of the meat industry. As long as there is a sustainable and responsible approach to animal farming, the production of leather can be considered renewable. The hides are obtained from animals that are raised for meat consumption, and their use in leather production helps reduce waste.

E) Printer paper: Printer paper can be made from various sources, including trees, bamboo, and recycled paper fibers. If the paper is sourced from sustainably managed forests or from fast-growing plants like bamboo, it can be considered renewable. Additionally, the use of recycled paper fibers reduces the demand for materials and promotes a more circular economy.

The other options, A) plastic fork, B) metal can, and D) electronics, are not made from renewable resources:

A) Plastic fork: Plastics are typically derived from fossil fuels, which are non-renewable resources. The production of plastic involves the extraction and processing of petroleum or natural gas, both of which are finite resources.

B) Metal can: Metal cans are predominantly made from aluminum or steel. While these metals can be recycled, their initial production requires the extraction of raw materials from the Earth, which is not a renewable process.

D) Electronics: Electronics are made from a wide range of materials, including metals, plastics, and various chemical compounds. The production of electronics involves the extraction of raw materials, many of which are non-renewable resources.

Option C and E.

For more such questions on renewable resources visit:

https://brainly.com/question/27734408

#SPJ8

Answer:

102.6 mL

Explanation:

The reaction that takes place is:

First we calculate how many NaOH moles are there in 50.00 mL of a 0.8000 M solution:

Then we convert NaOH moles into HCl moles:

Finally we calculate the volume of a 0.3900 M solution would contain 40 milimoles:

Approximately 766.08 grams of oxygen are required to completely react with 240g of C₂H₆.

To determine the amount of oxygen required to completely react with 240g of C₂H₆ (ethane), we need to set up a balanced chemical equation for the combustion of ethane.

The balanced equation for the combustion of ethane is as follows:

C₂H₆ + O₂ → CO₂ + H₂O

From the balanced equation, we can see that the stoichiometric ratio between C₂H₆ and O₂ is 1:3. This means that for every one mole of C₂H₆, three moles of O₂ are required for complete combustion.

To calculate the amount of oxygen required, we need to convert the given mass of C₂H₆ to moles using its molar mass, and then use the stoichiometric ratio to determine the moles of O₂ required. Finally, we can convert the moles of O₂ back to grams using the molar mass of oxygen.

The molar mass of C₂H₆ is calculated as follows:

(2 x atomic mass of carbon) + (6 x atomic mass of hydrogen)

(2 x 12.01 g/mol) + (6 x 1.01 g/mol) = 30.07 g/mol

Now, we can proceed with the calculation:

Calculate the moles of C₂H₆:

moles of C₂H₆ = mass of C₂H₆ / molar mass of C₂H₆

moles of C₂H₆ = 240 g / 30.07 g/mol ≈ 7.98 mol

Determine the moles of O₂ using the stoichiometric ratio:

moles of O₂ = moles of C₂H₆ x (3 moles of O₂ / 1 mole of C₂H₆)

moles of O₂ = 7.98 mol x 3 ≈ 23.94 mol

Convert moles of O₂ to grams:

mass of O₂ = moles of O₂ x molar mass of O₂

mass of O₂ = 23.94 mol x 32.00 g/mol = 766.08 g

For more such questions on oxygen visit:

https://brainly.com/question/28009615

#SPJ8

Answer:

The answer is A.

Explanation:

Answer:

Explanation:

I believe it is a

Answer:

1.37x10²⁵atoms of carbon

2.74x10²⁵ atoms of oxygen.

33.7g of KNO₃

Explanation:

To answer this question you must use molar mass of carbon dioxide (44g/mol) and 1 mole are 6.022x10²³atoms.

1.00kg are 1000g of CO₂. Moles are:

1000g CO₂ * (1mol / 44g) = 22.73 moles of CO₂ = 22.73 moles of carbon.

In atoms:

22.73 moles C * (6.022x10²³atoms / 1mole) = 1.37x10²⁵atoms of carbon

There are 22.73 moles of CO₂ * 2 = 45.45 moles of oxygen are present in the carbon dioxide. In atoms:

45.45 moles Oxygen * (6.022x10²³atoms / 1mole) = 2.74x10²⁵ atoms of oxygen.

1 mole of Potassium nitrate, KNO₃, contains 3 moles of oxygen. 1 mol of oxygen are:

1.00 mol O * (1mol KNO₃ / 3 moles O) = 0.33 moles of KNO₃

As molar mass of KNO₃ is 101.1g/mol:

0.33 moles of KNO₃ * (101.1g / mol) = 33.7g of KNO₃

Answer:

1. 1.37 * 10^25 atoms of carbon

2. 2.74 * 10^25 atoms of oxygen

3. 33.67g of Potassium Nitrate

Explanation:

2. Firstly, we want to know the number of atoms of oxygen in 1 kg of carbon dioxide.

Firstly, we will need to know the number of moles of carbon iv oxide in 1kg of carbon iv oxide

Mathematically;

number of moles = mass/molar mass

molar mass of carbon iv oxide is 44 g/mol

mass here is 1000g (1kg is 1000g)

So the number of moles of CO2 in 1kg of CO2 will be; 1000/44 = 22.73 moles

Now 1 mole of CO2 contains 2 atoms of oxygen, thus 1 mole of CO2 contains 2 moles of oxygen

So the number of moles of oxygen in 1kg CO2 will be 2 * 22.73 = 45.46 moles

Mathematically, 1 mole contains 6.02 * 10^23 atoms

So 45.46 moles will contain =

6.02 * 10^23 * 45.46 = 2.74 * 10^25 atoms of oxygen

1. 1 mole of co2 contains 1 atom of carbon , thus, 1 mole of CO2 will

contain 1 mole of carbon

From above, 1kg of carbon iv oxide contains 22.73 moles , thus 1kg of carbon iv oxide will contain 22.73 moles of carbon too

So the number of atoms will be 22.73 * 6.02 * 10^23 = 1.37 * 10^25 atoms

3. Mass of KNO3 that contains 1 mole of oxygen atom

From the formula of the compound, we can see that 1 mole of KNO3 contains 3 atoms of oxygen which translates to 3 moles of oxygen

So 1 mole of oxygen will translate to 1/3 mole of KNO3

Mathematically;

mass = number of moles * molar mass

Molar mass of KNO3 = 39 + 14 + 3(16) = 39 + 14 + 48 = 101 g/mol

So the mass will be = 1/3 * 101 = 33.67g

Answer:

56.9 mmoles of acetate are required in this buffer

Explanation:

To solve this, we can think in the Henderson Hasselbach equation:

pH = pKa + log ([CH₃COO⁻] / [CH₃COOH])

To make the buffer we know:

CH₃COOH  +  H₂O  ⇄   CH₃COO⁻  +  H₃O⁺     Ka

We know that Ka from acetic acid is: 1.8×10⁻⁵

pKa = - log Ka

pKa = 4.74

We replace data:

5.5 = 4.74 + log ([acetate] / 10 mmol)

5.5 - 4.74 = log ([acetate] / 10 mmol)

0.755 = log ([acetate] / 10 mmol)

10⁰'⁷⁵⁵ = ([acetate] / 10 mmol)

5.69 = ([acetate] / 10 mmol)

5.69 . 10 = [acetate] → 56.9 mmoles

Answer:

I believe your answer would be grams.

Answer:

lice, mosquito

Explanation:

both are examples of parasitism

edit: wait nvm i thought this was bio

Answer:

Endothermic

Explanation:

Storing sugar for later use is an example of an endothermic reaction because that energy is being absorbed.

The electronic configuration of organic compounds depends on the orbitals of their atoms and molecules.

The expression 'electronic configuration' makes reference to the spacial arrangement of electrons in distinct energy orbitals of an atom/molecule.

The orbitals are designed with numbers and letters, whereas the amount of electrons in each orbital is expressed as superscripts (e.g., 1s² 2s² 2p² in the C atom that form glucose).

In conclusion, electronic configuration of organic compounds depends on the orbitals of their atoms and molecules.

Learn more about electronic configurations here:

https://brainly.com/question/26084288

#SPJ1

The given reaction releases 906 kJ of heat energy when 4 moles of ammonia react.

So, the amount of heat energy released when 1 mole of ammonia reacts is:

906 kJ ÷ 4 mol = 226.5 kJ/mol

To produce 453 kJ of heat energy, we can use the following proportion:

226.5 kJ/mol = 453 kJ/x

where x is the number of moles of ammonia required.

Solving for x, we get:

x = (453 kJ × 4 mol) ÷ 906 kJ

x ≈ 2 mol

Therefore, 2 moles of ammonia must react to produce 453 kJ of heat energy.

Learn more about balanced equation from

https://brainly.com/question/28722049

#SPJ1

The given reaction releases 906 kJ of heat energy when 4 moles of ammonia react.

So, the amount of heat energy released when 1 mole of ammonia reacts is:

906 kJ ÷ 4 mol = 226.5 kJ/mol

To produce 453 kJ of heat energy, we can use the following proportion:

226.5 kJ/mol = 453 kJ/x

where x is the number of moles of ammonia required.

Solving for x, we get:

x = (453 kJ × 4 mol) ÷ 906 kJ

x ≈ 2 mol

Therefore, 2 moles of ammonia must react to produce 453 kJ of heat energy.

Learn more about balanced equation from

brainly.com/question/28722049

#SPJ1

Iron because it loses electrons

An electrochemical cell is a device that converts chemical energy into electrical energy, or vice versa, through the transfer of electrons between two electrodes.

The cell typically consists of two half-cells, each containing an electrode immersed in an electrolyte solution. The two half-cells are separated by a membrane or a porous barrier that allows the flow of ions between them.

Electrochemical cells have numerous applications, including batteries, fuel cells, corrosion protection, and electroplating, among others.

Learn more about electrochemical cell:https://brainly.com/question/12034258

#SPJ1

Answer:

Pb²++2I−→PbI2(s)

yellow precipitate

Explanation:

Answer:

no

Explanation:

different mixtures have different boiling and melting points

Answer:

Yes, they do.

Explanation:

To boil at a constant temperature, the vapour composition of the mixture has to account for liquid mixture composition.

And these mixtures are known as azeotropes or azeotropic mixture

\({}\)

The volume of 12 gas forms when 21 L Cl2 react at STP is 21 L.

To determine the volume of 12 gas (I assume you mean I2 gas) formed when 21 L of Cl2 reacts at STP (standard temperature and pressure), we need to use the ideal gas law equation.

The ideal gas law equation is given by:

PV = nRT

Where:

P = pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

At STP, the pressure is 1 atm, and the temperature is 273.15 K.

From the balanced equation, we can see that the molar ratio between Cl2 and I2 is 1:1. So, if 21 L of Cl2 reacts, it will produce an equal volume of I2 gas.

Given that the volume of Cl2 is 21 L, we can assume the volume of I2 gas formed will also be 21 L.

Therefore, the volume of I2 gas formed is 21 L.

For more such questions on volume

https://brainly.com/question/1749900

#SPJ8

C. The pH stays about the same.

Answer:

C.The pH stays about the same.

Explanation:

Buffer reactions maintain stable pH of solutions.