Answer:
Range = 120.98 m, (or rounded to the nearest whole number =121 meters)
Explanation:
We can use the formula for range in projectile motion at ground level:
\(Range = \frac{v^2\,\,sin(2\theta)}{g} \\Range= \frac{37^2\,\,sin(120)}{9.8} \\Range\approx 120.98\,\,m\)
Then the cannon's range would be approximately 120.98 m, which may be rounded to the nearest whole number as 121 meters
What two structures help ecoli move
Escherichia coli use long, whip-like structures called flagella to propel themselves.
What is E.coli.?Escherichia coli, also known as E. coli, is a Gram-negative, facultative anaerobic, rod-shaped, coliform bacterium of the genus Escherichia that is commonly found in the lower intestine of warm-blooded organisms
Given is to find what two structures help E.coli move.
Escherichia coli use long, whip-like structures called flagella to propel themselves. Motors in the cell's wall spin the flagella into bundles that rotate counter-clockwise, creating a twist that causes the bacterium to rotate clockwise, or towards the right when viewed from above.
Therefore, Escherichia coli use long, whip-like structures called flagella to propel themselves.
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A stone is dropped in a river surface of water,if it takes 4 seconds to reach surface of water, calculate the velocity with which the stone strikes on the water surface
Answer:from,
v=at+u then ,time=4seconds
we take u=initial speed which is zero
(0)
now, v=(10x4+0)m/s
then, velocity/speed is 40m/s
Explanation:from firt newton's laws of motion where from acceleration is rate of change of speed then we generate the eqn where now the stone was falling fat a certain height were we include acceleration due to gravity and multiply to time and sum to initial speed to get
A 101 kg basketball player crouches down 0.380 m while waiting to jump. After exerting a force on the floor through this 0.380 m, his feet leave the floor and his center of gravity rises 0.920 m above its normal standing erect position. (a) Using energy considerations, calculate his velocity (in m/s) when he leaves the floor. m/s (b) What average force (in N) did he exert on the floor
Answer:
\(4.25\ \text{m/s}\)
\(3391.22\ \text{N}\)
Explanation:
y = Height of compression = 0.38 m
m = Mass of basketball player = 101 kg
h = Height of center of gravity after jump = 0.92 m
g = Acceleration due to gravity = \(9.81\ \text{m/s}^2\)
Energy balance of the system is given by
\(mgh=\dfrac{1}{2}mv^2\\\Rightarrow v=\sqrt{2gh}\\\Rightarrow v=\sqrt{2\times 9.81\times 0.92}\\\Rightarrow v=4.25\ \text{m/s}\)
The velocity of the player when he leaves the floor is \(4.25\ \text{m/s}\)
\(Fy=mgy+\dfrac{1}{2}mv^2\\\Rightarrow F=\dfrac{mgy+\dfrac{1}{2}mv^2}{y}\\\Rightarrow F=\dfrac{101\times 9.81\times 0.38+\dfrac{1}{2}\times 101\times 4.25^2}{0.38}\\\Rightarrow F=3391.22\ \text{N}\)
The force exerted on the floor is \(3391.22\ \text{N}\).
An airplane flies with a constant speed of 600 km/h. to the west. How far can it travel in 1/4 hour?
Answer:
d = 150 km
Explanation:
Speed of an airplane is 600 km/h
We need to find how far it travel in 1/4 hour.
We know that the speed of an object is given by distance travelled divided by the time taken. Let d is the distance covered in 1/4 hour. So,
\(v=\dfrac{d}{t}\\\\d=v\times t\\\\d=600\ km/h \times \dfrac{1}{4}\ h\\\\d=150\ km\)
So, it will cover 150 km.
What particles are considered to be the basic building blocks of elements?
Answer:
Atoms.
Explanation:
The fundamental structure obstructs that make matter are called molecules. What are the various particles found in iotas? (Reply: electrons, protons and neutrons) Where are they found? (Reply: Protons and neutrons are found in the core, and electrons are found in shells around the outside of the core.)
Really hope this helps! :D
Explanation:
The basic components of matter are called atoms. What are the various particles present in an atom?
(Answer: electrons, protons, neutrons) Where are they? (Answer: Protons and neutrons are in the nucleus, and electrons are in the shell around the nucleus.)
A physics instructor wants to project a spectrum of visible light colors from 400 nm to 700 nm as part of a classroom demonstration. She shines a beam of white light through a diffraction grating with 500 lines per mm, projecting a pattern on a screen 2.4 m behind the grating. How wide is the spectrum corresponding to m=1?
Answer:
औडंठः की दुनिया कार्टून दर्शन होली है और यह बियर का अच्छा विकल्प है। विकल्प है। यो कुरा मेरो आफ्ना लागि विचार र त्यहाँको बडेमाको बिल्डिङ भित्र म जिन्दगी एक यात्रा हो कहाँबाट शुरु भइ कहाँ पुगेर अन्त हुन्छ
a ballon holds 24L at 45 k . find the volume if the temperature is increased to 911 k
Some species of jellyfish use jet propulsion to get around, a much gentler form of jet propulsion than squid use. A small jellyfish takes water into its bell; the total mass of jellyfish and water is 3. 2 g. The jellyfish then rapidly ejects 1. 3 g of water, achieving a speed of 0. 070 m/s.
The initial velocity of the jellyfish before it ejected the water was 0.046 m/s.
What is momentum?Momentum is a physical quantity that describes the motion of an object. It is defined as the product of an object's mass and its velocity. Mathematically, momentum (p) can be stated by the equation:
p = m * v
where m is object;s mass and v is its velocity.
We can use the conservation of momentum to calculate the initial velocity of the jellyfish before it ejected the water.
The total momentum before ejection is:
p_before = (m_jellyfish + m_water) * v_before
where m_jellyfish is the mass of the jellyfish, m_water is the mass of the water ejected, v_before is the initial velocity of the jellyfish and water.
The total momentum after ejection is:
p_after = m_jellyfish * v_after
where v_after is the velocity of the jellyfish after ejection.
Since momentum is conserved, we have:
p_before = p_after
(m_jellyfish + m_water) * v_before = m_jellyfish * v_after
Solving for v_before, we get:
v_before = (m_jellyfish / (m_jellyfish + m_water)) * v_after
Substituting the given values, we get:
v_before = (3.2 g / (3.2 g + 1.3 g)) * 0.070 m/s
v_before = 0.046 m/s
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10 points! Please HELP!
Ms. Vetter has not worked out in a long time. She is trying to lift her pet bunny cage off the ground to put into her car for their trip to Bunnyville to visit some of her pet bunnies ancestors. If Ms. Vetter does not have enough ________ _________, she can use a simple machine to help her lift the cage off the ground and into her car.
A. Big Muscles
B. Mechanical Force
C. Craft Supplies
D. Mechanical Advantage
Answer:
B- Mechanical Force
Explanation:
If Ms. Vetter who wants to work out, does not have enough mechanical force, she can use a simple machine to help her lift the cage off the ground and into her car. Thus, the correct option is B.
What is Mechanical force?Mechanical force is the force which is generated by the means of a machine is known as mechanical force. An example of mechanical force is when a car gets started, then its engine creates a mechanical force on the tyre of the car that help the car to accelerate with time. So here, the movement of the car occurs due to the force which is generated by the machine on the tyres.
Ms. Vetter wants to work out with her pet bunny after a long time, does not have enough mechanical energy, she can use a simple machine to help her lift the cage off the ground and into her car.
Therefore, the correct option is B.
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6.3 Calculate the current that flows through the element of a heater when the potential difference is 250V and the resistance of the element is 150.
Answer:
16.66
Explanation:
what is the mass of an object that is experiencing a net force of 225N and an accleration of 3.0 m/s^2. And What is the net force on a cart being pushed with an applied force of 23N with a frictional force of 23N?
Answer:
75 kg
Explanation:
Net Force
\(\sf \longmapsto F_{net} = 225N\)
Acceleration produced
\(\sf \longmapsto \: a = 3 .0 m / {s}^{2}\)
According to Newton's 2nd Law –
F = m•a
\(\sf \longmapsto \: M = \frac{F}{a} \)
\(\sf \longmapsto \: M = \frac{225N}{300m/s ^{2} } \)
\(\sf \longmapsto \: M = \: 75 \: kg\)
Hence, the mass of an object is 75 kg.
5
Drag each label to the correct location on the image.
Distinguish between the benefits of traditional banking and the benefits of online banking.
Consumers can seek
specialized financial
advice from bank employees.
Consumers have the convenience
of electronic deposits and
money transfers.
Traditional Banking Benefits
Consumers can use the
bank's notary services.
Online Banking Benefits
Traditional Banking Benefits
Consumers can seek specialized financial advice from bank employees Consumers can use the bank's notary servicesOnline Banking Benefits
Consumers have the convenience of electronic deposits and money transfersWhy is banking important?Banks provide a secure place to keep money. By depositing money in a bank account, individuals and businesses can keep their money safe from theft, fire, or other unforeseen events.
Check writing, electronic financial transfers, and credit or debit card transactions are all services provided by banks. Individuals and organizations may use these services to pay bills, acquire goods and services, and receive payments more easily.
Individuals and corporations can get loans and lines of credit from banks. These loans can be used to pay for college, buy a house or car, establish a company, or cover unforeseen needs.
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A balloon can be charged by rubbing it with your sleeve while holding it in your hand. You can conclude from this that the balloon is a(n) A. conductor. B. insulator. C. neutral object. D. Gaussian surface. E. semiconductor.
"A balloon can be charged by rubbing it with your sleeve while holding it in your hand. You can conclude from this that the balloon is an insulator." The correct option is B.
Any substance or material that can keep extra charges from moving around in a space is an insulator.
The insulator maintains its position forever by immobilising any excess charge added to the insulating substance and material.
As any excess charge on the balloon has a tendency to remain where it is placed rather than spreading out as an insulator would, we can say that the balloon is an insulator.
So, option B is the best choice.
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For which type of pathogens do immunizations/vaccinations help prevent?
To reduce the risk of atherosclerosis, it is important to cut down on?
The pathogen that immunization helps to prevent is virus.
To reduce the risk of atherosclerosis cut down on saturated fatty foods.
What is immunization?Immunization is defined as the prevention of pathogenic viral organisms from harming a living human host through the exposure of the host to an attenuated form of the virus to develop immunity prior to a future exposure.
Atherosclerosis is the deposition of fatty substances on the arterial wall leading to blocking of the blood vessels.
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Each of the following figures shows a person (not to scale) located on Earth at either 40°N or 40°S latitude. Rank the figures based on how much time the person spends in daylight during each 24-hour period, from most to least. To rank items as equivalent, overlap them.
The ranking is based on the tilt of the Earth's axis and its orbit around the Sun. The figure at 40°N in June receives the most daylight because it is located at a high latitude during the summer solstice in the Northern Hemisphere. The Earth's axis tilts towards the Sun, resulting in longer days and shorter nights. The figure at 40°S in December receives a moderate amount of daylight as it is located at a lower latitude during the summer solstice in the Southern Hemisphere.
The figure at 40°N in December experiences less daylight because it is located at a high latitude during the winter solstice in the Northern Hemisphere, with shorter days and longer nights. Lastly, the figure at 40°S in June receives the least amount of daylight as it is located at a lower latitude during the winter solstice in the Southern Hemisphere, where the days are shortest and the nights are longest. Based on the information given, the ranking of figures based on the amount of daylight they experience in a 24-hour period, from most to least.
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Which statement is correct?
A. If the electric field is zero everywhere inside a region of space, the potential must also be zero in that region.
B. When the electric field is zero at a point, the potential must also be zero there.
C. If the electrical potential in a region is constant, the electric field must be zero everywhere in that region.
D. If the electric potential at a point in space is zero, then the electric field at that point must also be zero.
Answer:
The answer is "Choice C ".
Explanation:
The relationship between the E and V can be defined as follows:
\(\to E= -\Delta V\)
Let,
\(\to E= \frac{\delta V}{\delta x}\)
When E=0
\(\to \frac{\delta V}{\delta x}=0\)
v is a constant value
Therefore, In the electric potential in a region is a constant value then the electric-field must be into zero that is everywhere in the given region, that's why in this question the "choice c" is correct.
22 Humans see different colors of
the visible light spectrum because
A. the wavelength of light is
reflected by what it is hitting and
directed back into the eye.
B. the wavelength of light is
refracted by what it is hitting and
directed back into the eye.
C. the wavelength of light is
diffracted by what it is hitting
and directed back into the eye.
D. the wavelength of light is
absorbed by what it is hitting and
directed back into the eye.
Answer:
A. the wavelength of light is reflected by what it is hitting and directed back into the eye.
Explanation:
Consider the two vectors A and B. You know the magnitudes of these vectors (lmand 10 m respectively), but you do not know anything about their directions ca ment Status here for 9 H a vector is defined to be the sum of these two vectors CHA+B) which of the following are true about the magnitude of C7 Choose all that apply C. cannot be determined Grade Summary Cain
A. The magnitude of C can be determined.
D. The magnitude of C is between 1m and 10m.
When two vectors are added, the magnitude of the resulting vector can be found using the law of cosines. For the vectors A and B, the magnitude of their sum C is given by:
|C|² = |A|² + |B|² + 2|A||B|cosθ,
where θ is the angle between the vectors A and B. Since the directions of A and B are unknown, θ could take any value between 0 and 180 degrees. However, the minimum value of cosθ is -1, which occurs when θ = 180 degrees. Therefore, the minimum magnitude of C is:
|C|min = |A| - |B| = 1 m - 10 m = 9 m.
The maximum value of cosθ is 1, which occurs when θ = 0 degrees. Therefore, the maximum magnitude of C is:
|C|max = |A| + |B| = 1 m + 10 m = 11 m.
Therefore, the magnitude of C is between 1m and 10m, and it can be determined.
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correct question
Which of the following statements are true about the magnitude of the vector C, which is defined as the sum of two given vectors A and B with magnitudes 1m and 10m respectively, but unknown directions? (Choose all that apply.)
A. The magnitude of C can be determined.
B. The magnitude of C is less than 10m.
C. The magnitude of C is less than 1m.
D. The magnitude of C is between 1m and 10m.
E. The magnitude of C is greater than 11m.
A small car with mass 0.610 kg
travels at constant speed on the inside of a track that is a vertical circle with radius 5.00 m
If the normal force exerted by the track on the car when it is at the top of the track (point B
) is 6.00 N
, what is the normal force on the car when it is at the bottom of the track (point A
)?
Express your answer with the appropriate units.
The normal force on the car when it is at the bottom of the track is 8.84 N.
At the top of the track (point B), the normal force (N) acting on the car is equal to the weight of the car (mg) plus the centrifugal force (mv²/r) acting outwards:
N = mg + mv²/r
where m is the mass of the car, g is the acceleration due to gravity, v is the speed of the car, and r is the radius of the track.
Since the car is traveling at constant speed, its acceleration is zero, so the centrifugal force is balanced by the force of gravity, and we have:
N = mg
Substituting the given values, we get:
6.00 N = (0.610 kg)(9.81 m/s²)
Solving for g, we get:
g = 9.68 m/s²
At the bottom of the track (point A), the normal force acting on the car is equal to the weight of the car minus the centrifugal force acting downwards:
N = mg - mv²/r
Substituting the known values, we get:
N = (0.610 kg)(9.81 m/s²) - (0.610 kg)(v²/5.00 m)
Since the car is traveling at constant speed, we can use the fact that its kinetic energy is equal to its gravitational potential energy to solve for v:
mg(2r) = (1/2)mv²
where 2r is the total distance traveled by the car (i.e., the circumference of the circle), so 2r = 2πr = 31.4 m. Solving for v, we get:
v = sqrt(2gr)
Substituting the known values, we get:
v = sqrt(2(9.68 m/s²)(5.00 m)) = 6.19 m/s
Substituting this value of v into the equation for N, we get:
N = (0.610 kg)(9.81 m/s²) - (0.610 kg)((6.19 m/s)²/5.00 m) = 8.84 N
Therefore, the normal force on the car when it is at the bottom of the track is 8.84 N.
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If the same rock is placed in four different locations, in
which location will the rock have the most potential
energy?
Select one:
O In a sandbox.
O On the street.
O On the sidewalk.
O In a tree.
In a tree if the same rock is placed in four different locations, the rock will have the most potential energy.
What means potential energy?Potential energy is a form of energy stored that is dependent on the relationship between different system components. When a spring is compressed or stretched, its potential energy increases.
If a steel ball is raised just above ground as opposed to falling to the ground, it has more potential energy. An object has potential energy as a result of its position in relation to other objects. Potential energy is so named because it has the ability to transform into other types of energy, like kinetic energy.
Where is potential energy?Potential energy is the energy that is held within a material or an object. Energy in an object held vertically is known as gravitational potential energy. Potential energy that can be stretched or compressed is known as elastic potential energy.
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A negatively charged particle is moving in the direction of the +x axis enters a magnetic field. If the particle experiences a magnetic force in the -y direction, determine the direction of the magnetic field in this region. Explain your answer with the aid of labelled diagram of the particle in x, y and z coordinate system. [4 marks]
Answer:
Explanation:
To determine the direction of the magnetic field in this region, we can use the right-hand rule for magnetic forces.
If we point our right thumb in the direction of the particle's velocity (in the +x direction) and our right fingers in the direction of the magnetic force (in the -y direction), then the direction of the magnetic field will be perpendicular to both the velocity and force vectors, and will be in the +z direction.
Here's a labelled diagram to help visualize this:
z
|
|
|
|_______________y
/
/
/
x
In this diagram, the particle is moving in the +x direction (out of the page) and experiences a magnetic force in the -y direction (towards the bottom of the page). Therefore, the magnetic field must be in the +z direction (upwards on the page), perpendicular to both the velocity and force vectors.
Note: This assumes that the particle is negatively charged, which means that its velocity vector points in the opposite direction to the direction of the electric field. If the particle were positively charged, the direction of the magnetic field would be in the -z direction (downwards on the page).
A ball is held at rest at some height above a hard, horizontal surface. Once the ball is released it falls, hits the surface, and starts bouncing vertically up and down. Suppose that with each bounce the ball loses a fixed fraction p (with 1>p>0) of its energy. This loss could be due to a number of reasons (inelasticity, drag, etc) that are left unspecified.How many times will the ball bounce before coming to rest (if at all)? Provide a detailed explanation of your reasoning, not simply a one-line answer.How long will it take for the ball to come to rest (if at all)? Give your answer as a formula that contains as variables only p and the time T1 from the moment that the ball was released to the first contact with the horizontal surface.
It can never theoretically become 0. After n bounces, it may be closer to 0 or extremely tiny, depending on the precise values of p and T1.
Briefing:initial height dropped =h = gT12/2
T1 - time from the moment that the ball was released to the first contact with the horizontal surface.
initial energy T = mgh
after first bounce energy loss = mghp
height it will raise after first bounce mgh1 = mgh(1-p)
after each bounce its energy is reduced by p
after n bounces it will raise to a height
mghn=mgh(1-p)n
hn= h(1-p)n = gT12/2 *(1-p)n
gT₁² (1-p)n/2
Theoritically hn can never become 0. It can be closer to 0 or can be negligibly small after n bounces, depending on the actual values of p and T1 .
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A particle performs simple harmonic motion with period Pi/2 seconds and amplitude 12 m. What is the maximum velocity (in m/s)?
The maximum velocity is 48π m/s.
To solve this problem
The equation: can be used to determine the maximum velocity of a particle in simple harmonic motion.
Vmax = ω * A
Where
Vmax is the maximum velocityω (omega) is the angular frequencyA is the amplitude of the motionThe following formula can be used to get the angular frequency:
ω = 2π / T
Where
T is the motion's period.
Given that the period is π/2 seconds (T = π/2) and the amplitude is 12 m (A = 12), we can find the angular frequency:
ω = 2π / (π/2) = 4π rad/s
Now we can calculate the maximum velocity:
Vmax = ω * A = (4π rad/s) * (12 m) = 48π m/s
Therefore, the maximum velocity is 48π m/s.
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1. A balloon drifts 100 m towards the west in 10 seconds, then the wind suddenly changes
and the balloon flies 60m towards the east in the next 6 seconds.
a) What total distance did it travel? 160 meters
b) What was the average speed during the first 10 seconds?
c) What was its average speed during the next 6 seconds?
d) What was its average speed for the entire trip?
e) What was its total displacement?
1) What was its average velocity during the first 10 seconds?
g) What was its average velocity during the next 6 seconds?
h) What was its average velocity for the entire trip?
Answer:
Explanation:
a) The total distance traveled by the balloon = (100 + 60) m
= 160 metes
b) speed = \(\frac{distance covered}{time taken}\)
The average speed for the first flight = \(\frac{100}{10}\)
= 10 m/s
c) The speed during its next flight = \(\frac{60}{6}\)
= 10 m/s
d) Average speed for the entire trip = \(\frac{(10 + 10)}{2}\)
= 10 m/s
e) Total displacement = \(\sqrt{(100)^{2} + (60)^{2} }\)
= \(\sqrt{13600}\)
= 116.62 m
f) velocity = \(\frac{displacement}{time}\)
Average velocity during the first 10 seconds = \(\frac{100}{10}\)
= 10 m/s
g) Average velocity during the next 6 seconds = \(\frac{60}{6}\)
= 10 m/s
h) Average velocity for the entire trip = \(\sqrt{(10)^{2} + (10)^{2} }\)
= \(\sqrt{200}\)
= 14.14 m/s
Find the momentum of an object traveling at 15 m/s if it has a mass of 2. I kg?
Answer:
momentum=31.5
Explanation:
given,
mass(m)=2.1kg
velocity(v)=15m/s
momentum(p)=?
now,
p=mv
p=15×2.1
p=31.5 kgm/s
The Mars Rover Curiosity has a mass of 900 kg. Taking the gravitational field strength to be 9.8 N/kg
on Earth and 3.7 N/kg on Mars, give the value of the weight of the Rover on earth and mars
The weight of the Mars Rover Curiosity on Earth and on Mars is 8820 N and 3330 N respectively.
Weight of objects on Earth and on MarsThe weight of an object is given by the product of its mass and the gravitational field strength at its location.
On Earth:
Weight = mass x gravitational field strengthWeight = 900 kg x 9.8 N/kgWeight = 8820 NOn Mars:
Weight = mass x gravitational field strengthWeight = 900 kg x 3.7 N/kgWeight = 3330 NTherefore, the weight of the Mars Rover Curiosity on Earth and on Mars are 8820 N and 3330 N respectively.
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Statement: Baseball is not a dangerous sport unless either a bat breaks or a player is hit with a ball.
Key: B = A bat breaks.
D = Baseball is a dangerous sport.
P = A player is hit with a ball.
Answer:
P
Explanation:
If the bat break it will get replaced and you will get another bat,but if u get hit with the ball it's dangerous in many ways
Hi please help on question! . If answer is correct I'll rate you five stars a thanks and maybe even brainliest! You will even get 54 pts!!
Here is a function machine.
Input : multiply by 6. Subtract 80: output
The input is the same as the output. Find the input.
Also can you please show me an easy to work out these type of questions
Answer:
Explanation:
Sure, I'd be happy to help you with the question!
Let's denote the input as x. According to the function machine, the input is multiplied by 6 and then 80 is subtracted from the result to obtain the output.
So, the function can be written as:
Output = (6 * x) - 80
Now, the problem states that the input is the same as the output. Therefore, we can set up the equation:
x = (6 * x) - 80
Let's solve this equation to find the value of x:
x = 6x - 80
Subtracting 6x from both sides, we get:
x - 6x = -80
Combining like terms, we have:
-5x = -80
Dividing both sides by -5, we find:
x = (-80) / (-5)
Simplifying the expression, we have:
x = 16
Therefore, the input (x) that results in the input being the same as the output is 16.
To work out these types of questions, it's important to carefully read the instructions and understand the operations being performed in the function machine. Then, you can set up an equation with the input and output, and solve for the unknown value. Always double-check your solution to ensure it satisfies the given conditions of the problem.
Answer:
16
Explanation:
(x*6) - 80 = x
Multiply the parentheses
6x - 80 = x
Add 80 to each side to get
6x = x + 80
Subtract x from both sides to get
5x = 80
Divide both sides by 5
x = 16
Define invariant transformations
Answer:
For a given system, there can be particular transformations for which the explicit equations of motion are the same for both the old and new variables. Transformations for which the equations of motion are invariant, are called invariant transformations. It will be shown that if the Lagrangian does not explicitly contain a particular coordinate of displacement qi, then the corresponding conjugate momentum, pi, is conserved. This relation is called Noether’s theorem which states “For each symmetry of the Lagrangian, there is a conserved quantity".
. Acceleration is the rate at which/what hap-
pens?