Answer:
Touka Kirishima <3
Explanation:
Answer:
juuzou
Explanation:
he bad##s
A capacitor stores 7.77 x 10-7 J of
energy when 4.29 x 10-8 C of
charge is on the plates. What is the
voltage across the capacitor?
[?] V
No links please
Answer: \(36.22\ V\)
Explanation:
Given
Energy in a capacitor \(E=7.77\times 10^{-7}\ J\)
Charge \(Q=4.29\times 10^{-8}\ C\)
Energy of a capacitor is given by
\(E=\dfrac{1}{2}CV^2=\dfrac{1}{2}QV\quad [\text{Q=CV}]\)
Insert the values
\(E=\dfrac{1}{2}QV\\\\\Rightarrow 7.77\times 10^{-7}=\dfrac{1}{2}\times 4.29\times 10^{-8}\times V\\\\\Rightarrow V=3.622\times 10\\\\\Rightarrow V=36.22\ V\)
Thus, the voltage around the capacitor is \(36.22\ V\)
2
Which of the following best describes temperature?
A
Number of molecules
B
Motion of molecules
C
Size of molecules
D Type of molecules
Answer:
B
Explanation:
Answer:
b the motion of molecules
Explanation:
i just took the test and it makes the most sense
what is uniform motion?
Light traveling in water, nwater = 1.33, strikes a plastic block at an angle of incidence of 51.4°; part of the beam is reflected and part is refracted. If the index of refraction of the plastic is 2.13, what is the angle made by the reflected and refracted beams?
angle made by the reflected and refracted beams is 28.2°.
The angle made by the reflected and refracted beams can be found using Snell's Law and the law of reflection. First, we know that the angle of reflection equals the angle of incidence. In this case, the angle of reflection is 51.4°.
Next, we'll use Snell's Law to find the angle of refraction (θ₂). Snell's Law states:
n₁ * sin(θ₁) = n₂ * sin(θ₂)
where n₁ and n₂ are the indices of refraction of the two materials, and θ₁ and θ₂ are the angles of incidence and refraction, respectively.
Given:
n₁ (water) = 1.33
θ₁ = 51.4°
n₂ (plastic) = 2.13
Solving for θ₂:
1.33 * sin(51.4°) = 2.13 * sin(θ₂)
θ₂ = arcsin[(1.33 * sin(51.4°))/2.13] ≈ 23.2°
Now, we have both the angle of reflection (51.4°) and the angle of refraction (23.2°). To find the angle between the reflected and refracted beams, simply subtract the smaller angle from the larger one:Angle between beams = 51.4° - 23.2° = 28.2°
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A carpenter apprentice was killed when he was struck in the head by a nail that was fired from a powder actuated tool. The tool operator, while attempting to anchor a plywood form in preparation for pouring a concrete wall, fired the gun, causing the nail to pass through the hollow wall. The nail traveled some twenty-seven feet before striking the victim. The tool operator had never received training in the proper use of the tool, and none of the employees in the area were wearing personal protective equipment. What should be recommended to prevent this accident from happening again?
Answer:
Explanation:
The recommendations that need to be urgently addressed by the workshop and it's employees are
1) Training of all employees (particularly the tool operators) on the safe and proper use of all tools used in the course of the carpentry work.
2) Training of all employees in health, safety and environment (HSE). This training will help them appreciate the importance of always wearing personal protective equipment (PPE) when at the workshop or during the course of a work (because if the apprentice was putting on an engineer's helmet, he could have been safe).
3) Employees who fail to adhere strictly to the use of PPE should be sanctioned or even dismissed from the workplace
how to find the velocity
To find velocity, you need to divide the distance traveled and the time it took to travel that distance.
Velocity is a vector quantity that indicates the rate of change of an object's position in a given direction. It is calculated by dividing the change in position of an object by the time interval over which the change occurred.
The formula for velocity is,
velocity = distance / time
For example, if a car traveled 100 meters in 10 seconds, the velocity would be,
velocity = 100 meters / 10 seconds
velocity = 10 meters per second
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an piece of space debris is released from rest at an altitude that is two earth radii from the center of the earth. compared to its weight on earth, the weight of this debris is? A) one-quarter of its weight on the surface of the earth. B) one-half of its weight on the surface of the earth. C) zero. D) the same as on the surface of the earth. E) one-third of its weight on the surface of the earth.
An piece of space debris is released from rest at an altitude that is two earth radii from the center of the earth. the weight of this debris is zero, which is option C.
The correct option is C. Zero
Weight of this debris is?
The weight of this debris is zero (option C).Explanation: Weight of an object is a force that is caused by the gravitational attraction of the earth for the object. The weight is directly proportional to the mass of the object.
The formula to calculate weight is given as follows: Weight = Mass x Gravitational field strength. The gravitational field strength is the same everywhere on the earth. Its value is approximately 9.8 N/kg. So the weight of an object depends on its mass and the distance from the center of the earth. This altitude is called the state of weightlessness. At this point, the gravitational force and the centrifugal force acting on the object are equal in magnitude, but opposite in direction. Thus, the weight of this debris is zero, which is option C.
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The Event Horizon Telescope took the first picture of a black hole in 2017. The observations used to create this image were made over how many nights in 2017
Answer:
The Event Horizon Telescope (EHT) made history by capturing the first-ever image of a black hole in 2017. This monumental achievement provided astronomers and scientists with a groundbreaking glimpse into the mysterious phenomenon of black holes.
Explanation:
To obtain the image, the EHT utilized a technique called Very Long Baseline Interferometry (VLBI), which involved coordinating a global network of radio telescopes to work together as a single virtual telescope. By synchronizing the data collected from these widely dispersed telescopes, the EHT achieved an incredibly high-resolution image.
The observations necessary for creating the image of the black hole were not limited to a single night in 2017. Instead, the data collection process spanned several nights over the course of that year. The EHT team synchronized and combined the observations from different telescopes to form a cohesive dataset, enabling the creation of the final image.
By observing the target black hole—specifically, the supermassive black hole at the center of the galaxy Messier 87 (M87)—over multiple nights, the EHT team was able to gather a more extensive dataset. This prolonged observation period increased the chances of capturing clear and accurate data, compensating for potential adverse weather conditions or technical challenges on any given night.
Overall, the observations made by the Event Horizon Telescope in 2017 were spread out across several nights to ensure the collection of sufficient data and enhance the accuracy of the resulting image. The collaborative effort and meticulous data analysis led to the groundbreaking achievement of capturing the first-ever direct image of a black hole.
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a person with a mass of 97kg is accelerated at a rate of 1.4m/s2, what’s the force acting upon them?
Answer:
135.8 N
Explanation:
You multiply the mass by the acceleration then you get your answer
You can smell an open bottle of perfume in a room because __________.
A. the liquid vaporizes and the resulting gas molecules wander about the room
B. the scent travels without needing a medium to travel through
C. the air molecules bond with some of the perfume, carrying it around the room
D. the perfume in the bottle is under pressure
Answer:
The answer is C
Explanation:
I've just answered this question on a quiz
do you know any good books about physics and math?
In the compound MgCl2, how many atoms of Mg are there?
a ship leaves a harbor and sails at 27.5∘ to the south of due east. after traveling 365 km, how far east is the ship from the harbor?
The ship is located 200.51 km east from the harbor.
The given angle of travel of the ship is 27.5° to the south of due east. To solve this question, we can use trigonometry, and more specifically, we can use the sin function because we know the opposite and hypotenuse side of the angle of travel of the ship. To get started, we need to break down the angle of travel as well as the displacement of the ship along the eastern axis. We know that the ship sailed at 27.5° to the south of due east and traveled a distance of 365 km. From this information, we can find the opposite and hypotenuse side of the triangle formed by the ship's angle of travel and displacement eastward. Let x be the displacement of the ship along the eastern axis.
Then, east displacement of ship = x
We know that the angle of travel of the ship = 27.5° south of due east. This implies that angle of travel of the ship from the eastern axis is 90° - 27.5° = 62.5°.
We know that opposite side of the ship's angle of travel is the southward displacement of the ship = 365 km.
This implies that the hypotenuse of the ship's angle of travel is given as: hypotenuse = 365 / sin(62.5°) = 398.89 km
Therefore, the displacement of the ship along the eastern axis = east displacement of the ship = hypotenuse × cos(62.5°)
Substituting hypotenuse = 398.89 km and angle of travel of ship from eastern axis = 62.5°, we get:
east displacement of ship = 398.89 × cos(62.5°) = 200.51 km
Therefore, the ship is located 200.51 km east from the harbor.
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(a) In which of the following situations does the force in question do positive work? Check all that apply. A rock falls to the ground under the influence of the gravitational force. The frictional force slows a car as it skids to a stop. The normal force pushes upward on Jean as she rides an escalator to a higher floor at the mall. A batted baseball is slowed by the gravitational force as it rises into the air. The normal force pushes upward on a bicycle as it rides over horizontal ground The gravitational force on a bus is directed downward as the bus moves over a horizontal road The towrope exerts a force on a water skier who is towed behind a speedboat. A block slides down an inclined plane, and the normal force is perpendicular to the plane. Emily pulls upward on her briefcase to support it as she stands at the bus stop, waiting for the bus to arrive. Part (b) In which of the following situations does the force in question do negative work? Check all that apply A rock falls to the ground under the influence of the gravitational force. The frictional force slows a car as it skids to a stop. The normal force pushes upward on Jean as she rides an escalator to a higher floor at the mall. A batted baseball is slowed by the gravitational force as it rises into the air. The normal force pushes upward on a bicycle as it rides over horizontal ground. The gravitational force on a bus is directed downward as the bus moves over a horizontal road. The towrope exerts a force on a water skier who is towed behind a speedboat. A block slides down an inclined plane, and the normal force is perpendicular to the plane. Emily pulls upward on her briefcase to support it as she stands at the bus stop, waiting for the bus to arrive. Part (c) In which of the following situations does the force in question do zero work? Check all that apply. A rock falls to the ground under the influence of the gravitational force. The frictional force slows a car as it skids to a stop. The normal force pushes upward on Jean as she rides an escalator to a higher floor at the mall. DA batted baseball is slowed by the gravitational force as it rises into the air. The normal force pushes upward on a bicycle as it rides over horizontal ground. The gravitational force on a bus is directed downward as the bus moves over a horizontal road The towrope exerts a force on a water skier who is towed behind a speedboat. A block slides down an inclined plane, and the normal force is perpendicular to the plane. Emily pulis upward on her briefcase to support it as she stands at the bus stop, waiting for the bus to arrive.
(a) The forces that do positive work are the forces that act in the direction of displacement.
(b) The forces that do negative work are the forces that act opposite to the direction of displacement.
(c) The forces that do zero work are the forces that are perpendicular to the direction of displacement.
(a) The forces that do positive work are the forces that act in the direction of displacement.
Here are the options:
A rock falls to the ground under the influence of the gravitational force. The gravitational force is acting downward and the rock is moving downward, so the force does positive work. The normal force pushes upward on Jean as she rides an escalator to a higher floor at the mall. The normal force is acting upward and Jean is moving upward, so the force does positive work. The towrope exerts a force on a water skier who is towed behind a speedboat. The towrope is acting forward and the skier is moving forward, so the force does positive work.
(b) The forces that do negative work are the forces that act opposite to the direction of displacement.
Here are the options:
The frictional force slows a car as it skids to a stop. The force is acting backward and the car is moving forward, so the force does negative work. A batted baseball is slowed by the gravitational force as it rises into the air. The force is acting downward and the ball is moving upward, so the force does negative work.
(c) The forces that do zero work are the forces that are perpendicular to the direction of displacement.
Here are the options:
The normal force pushes upward on a bicycle as it rides over horizontal ground. The gravitational force on a bus is directed downward as the bus moves over a horizontal road. A block slides down an inclined plane, and the normal force is perpendicular to the plane. Emily pulls upward on her briefcase to support it as she stands at the bus stop, waiting for the bus to arrive.
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Define standard 1 killogram
" standard 1 meter
" standard 1 second
Answer:
-standard 1 kg : Kilogram (kg), basic unit of mass in the metric system.
-standard 1 meter: The standard metre is the length of the path travelled by light in vaccum during a time interval of 1/299792458 of a second.
- standard 1 second : The second (abbreviation, s or sec) is the Standard International ( SI ) unit of time.
Explanation:
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An electron is placed between equal and oppositely charged parallel plates separated by 10 mm. It experiences an acceleration of1.75×10 ∧ 14 m/s ∧ 2. What is the potential difference between the charged parallel plates? Image size: s ML Max Please enter a numerical answer below. Accepted formats are numbers or "e" based scientific notation e.g.0.23, 2 , 1e6.5.23e−8
The potential difference between the charged parallel plates, charged parallel plates separated by 10 mm is 3.5 x 10³.
The potential difference is directly inversely proportional to the distance between the plates since the electric field is kept constant.
We shall assert in this situation that if the distance between the plates is lowered, the potential difference between the plates will also decrease.
The difference in potential between two places in a circuit represents the energy needed to transport a unit charge, or one coulomb, from one point to the other. Volts or joules per coulomb are used to express potential difference.
capacitance of parallel plate capacitor
c = ε A / d , d is distance between plates , A is surface area , ε is constant
As d becomes two times , Capacitance c = 1/ 2 times ie c / 2
potential V = Q / C
Q is constant , potential
v = Q / c /2
= 2 . Q / C
= 2 V
So potential difference becomes 2 times.
NEW P D = 1.75 X 2
= 3.5 x 10³
potential difference between the charged parallel plates is 3.5 x 10³
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when you plug your cell phone into an electrical outlet to recharge it, you are using energy for a industry. b commercial use. c residential use. d transportation.
When you plug your cell phone into an electrical outlet to recharge it, you are using energy for c) residential use.
This is because the electricity is being consumed in a household setting for personal use. Commercial use would be if the energy was being used in a business or commercial setting, and transportation would involve using energy for moving vehicles. So, the long answer is that plugging your cell phone into an electrical outlet for charging purposes falls under the category of residential use of energy.
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A 20 N force is necessary to stretch a spring 0.5 m. What is the spring constant of this spring?
Answer: The spring constant of a given spring is \(40 N/m\).
Explanation:
Given,
Force (F) = 20N
The displacement of the spring\(= x = 0.5 m\)
To find: Spring constant (k) = ?
As we know that,
Hook's law states that,
\(F = k\) · \(x\)
Therefore, \(k = \frac{F}{x}\)
\(k = \frac{20}{0.5}\)
\(k = \frac{(20)(10)}{5}\)
\(k = 40 N/m\)
Hence, The spring constant of a given spring is \(40 N/m\).
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The slope of a distance-time graph will give
a diffraction grating has 2,160 lines per centimeter. at what angle in degrees will the first-order maximum be for 540 nm wavelength green light?
The angle at which the first-order maximum will occur for green light with a wavelength of 540 nm on a diffraction grating with 2,160 lines per centimeter is approximately 12.6 degrees.
What is Diffraction Grating?
A diffraction grating is an optical device that consists of a series of closely spaced, parallel lines or slits that are etched or formed on a transparent material such as glass or metal. These lines or slits act as a periodic structure that diffracts light waves, causing them to spread out or disperse into a spectrum of colors.
When light passes through a diffraction grating, the waves encounter the slits or lines, which act as sources of secondary waves. The secondary waves interfere with each other constructively and destructively, creating a pattern of bright and dark regions known as interference pattern or diffraction pattern.
To calculate the angle of the first-order maximum, we can use the formula for the angular position of a diffraction maximum:
sinθ = mλ / d
where θ is the angle of the diffraction maximum, m is the order of the maximum (in this case, m = 1 for the first-order maximum), λ is the wavelength of light, and d is the spacing between the grating lines.
Given that the grating has 2,160 lines per centimeter, the spacing between the lines can be calculated as:
d = 1 / (2,160 lines/cm) = 0.000463 cm = 4.63x10⁽⁻⁶⁾ m
Converting the wavelength of green light from nm to meters:
λ = 540 nm × (1x10⁽⁻⁹⁾ m/1 nm) = 5.40x10⁽⁻⁷⁾ m
Substituting these values into the formula, we find:
sinθ = (1)(5.40x10⁽⁻⁷⁾ m) / (4.63x10⁽⁻⁶⁾ m) ≈ 0.1166
Taking the inverse sine (sin⁻¹) of this value, we find:
θ ≈ 12.6 degrees
Therefore, the angle at which the first-order maximum will occur for green light with a wavelength of 540 nm on a diffraction grating with 2,160 lines per centimeter is approximately 12.6 degrees.
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What is the numeric value of the prefix "micro"?
a. 0.00001
b. 0.000001
c. 0.0001
d. 0.001
What is the numeric value of the prefix "micro"?
a. 0.00001
b. 0.000001 ✓"Micro" is a prefix that is used to indicate a value of the factor 10^-6 and means very minute.c. 0.0001
d. 0.001
During each cycle of operation, a refrigerator absorbs 257 j of heat from the freezer and expels 465 j of heat to the room. how much work input is required in each cycle?
Work input is required in each cycle w = 208j
Here can explain as ,according to the law of conservation of energy , the total heat given off the surrounding by a refrigerator is equal to the work done by the refrigerator and the heat removed from the inside of a refrigerator .i.e. the addition of heat removed or absorbs and work done by the refrigerator is equal to the heat expelled to the room during each cycle. It can be shown as ,
\(Q_{h}\) =\(Q_{c}\) + \(W\)
Where,
\(W\) is work input of refrigerator during each cycle.
\(Q_{c}\) is the heat removed or absorbed by the refrigerator.
\(Q_{h}\) is heat expelled to the room during each cycle.
Given here,
\(Q_{c}\) = 257 j
\(Q_{h}\) = 465 j
Therefore from above equation can be find the value of work input by the refrigerator in each cycle,
\(W\) =\(Q_{h}\) - \(Q_{c}\)
w = (465 j) -(257 j)
w= 208j
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I'LL GIVE BRAINLIEST!!! Araw surveyed people that were standing in a line to vote in an election. One of his questions was "How old are you?" The data set shows the results.
{47, 61, 25, 19, 30, 33, 72, 65, 55, 29, 54, 49, 38, 81, 77, 33, 40}
Create a stem-and-leaf plot to represent the data set. Include a key.
The stem and leaf plot to represent the data set on the survey by Araw is:
Stem | Leaf
1 | 9
2 | 5 9
3 | 0 3 3 8
4 | 0 7 9
5 | 4 5
6 | 1 5
7 | 2 7
8 | 1
Key 1 | 9 represents 19
How to design the stem and leaf plot ?To begin, identify the stems; these are the ten digit's numbers from the data set, being 1, 2, 3, 4, 5, 6, 7, and 8. Write the previously mentioned stems in a vertical column beginning at the top and then proceeding downward.
Now, next to the noted stem sequences, determine the respective leaf - the units digits of each individual number - with 47 holding a stem of 4 alongside its own leaf of 7, for instance. When all leaves have been written beside their matching stems, they should be sorted in order of ascending magnitude.
Finally, incorporate a sequential key into the plot that clearly explains how it should be interpreted accordingly.
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Lightning flashes and you hear a thunder clap for seconds later. the velocity of sound is 340 m/s. how far away did lightning strike ?
Answer:
For metric-system conversions, follow this method: Sound travels at about 340 m/s, so multiply the number of seconds you counted by 340, and you'll know how many meters away lightning struck. A three-second count, then, would place the lightning strike about 1,020 m away, or roughly 1 km.
Explanation:
hope it hep and if it doesnt sorry
The distance struck by the lighting flashes is 680 m.
The given parameters;
time taken to hear the thunder clap, t = 4 svelocity of sound, v = 340 m/sThe distance struck by the lighting is calculated by applying the principle of echo as follows;
\(v = \frac{2d}{t} \\\\2d = vt\\\\d = \frac{vt}{2} \\\\d = \frac{340 \times 4}{2} \\\\d = 680 \ m\)
Thus, the distance struck by the lighting flashes is 680 m.
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The atp yield for a molecule depends on where it enters glycolysis or the citric acid cycle. The yield can be compared to the net yield of glucose, 30 atp. Determine the net atp yield of each starting molecule when fully oxidized to co2. Assume that glycolysis, the citric acid cycle, and oxidative phosphorylation are fully active.
The net ATP yield for the given molecules is as follows:
The net ATP yield from fructose 1,6‑bisphosphate is 32 ATPThe net ATP yield from galactose is 30 ATPThe net ATP yield from dihydroxyacetone phosphate is 16 ATPThe net ATP yield from pyruvate is 12.5 ATPThe net ATP yield from lactate is 14 ATPThe net ATP yield from phosphoenolpyruvate is 13.5 ATPWhat are the steps in the formation of ATP in the body?The process of the formation of ATP involved three main reaction pathways, namely:
glycolysis- this is the reaction pathway in which sugar molecules are broken down to produce two molecules of pyruvate.
citric acid cycle - the pyruvate produced from glycolysis is first oxidized to acetyl-CoA which then enters the citric acid cycle to produce ATP and NADH and FADH₂
oxidative phosphorylation - this is the process where electrons are transferred to oxygen by NADH and FADH₂
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Complete question:
The ATP yield for a molecule depends on where it enters glycolysis or the citric acid cycle. The yield can be compared to the net yield of glucose, 30 ATP.
Determine the net ATP yield of each starting molecule when fully oxidized to CO2. Assume that glycolysis, the citric acid cycle, and oxidative phosphorylation are fully active.
net ATP yield from fructose 1,6‑bisphosphate: ______ ATP molecules
net ATP yield from galactose: ______ ATP molecules
net ATP yield from dihydroxyacetone phosphate: ______ ATP molecules
net ATP yield from pyruvate: ______ ATP molecules
net ATP yield from lactate: ______ ATP molecules
net ATP yield from phosphoenolpyruvate: ______ ATP molecules
A 55-kilogram ice skater slides across a level ice surface and the force of friction acting on the skates has a magnitude of 11 newtons.
On a level ice surface, a 55-kilogram skater glides over it while being subject to a friction force of 11 newtons. The skater's acceleration is -0.2 m/s^2.
The force of friction acting on the skater can be calculated as follows:
friction = μ * N
where
μ = coefficient of friction between the ice and skates (assumed to be constant)
N = normal force, which is equal to the weight of the skater
N = m * g
where
m = mass of the skater (55 kg)
g = acceleration due to gravity (9.8 m/s^2)
By substituting the values, we get:
friction = μ * m * g = 11 N
Finally, the net force acting on the skater can be calculated as follows:
net force = friction = -11 N (opposite direction to motion)
The acceleration of the skater can be calculated using Newton's second law of motion:
a = F / m
= -11 N / 55 kg
= -0.2 m/s^2
The acceleration of the skater is -0.2 m/s^2.
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Note: The correct question would be as bellow,
A 55-kilogram ice skater slides across a level ice surface and the force of friction acting on the skates has a magnitude of 11 newtons. Find the coefficients of static and kinetic friction between the skates and the ice.
Describe and contrast stellar orbits in the disk, halo, and bulge of our galaxy.
The stellar orbits in the disk orbit of our galaxy are organized into circles, while stellar orbits in the halo and bulge have a minor level of spatial organization.
What are the stellar orbits of the Milky Way Galaxy?The stellar orbits of the Milky Way Galaxy refer to the movement of the stars inside the Galaxy, which mainly depends on the relative spatial position of the stars in the galaxy
The stellar orbits of our Milky Way Galaxy have different shapes in regard to their relative position which includes circular and also elliptical shapes.
Therefore, with this data, we can see that the stellar orbits of our Milky Way Galaxy depend on the position of the star in the galaxy, for example being circular in the disk region of the galaxy and having elliptical and or less organized formations in other positions.
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Who discovered the basic laws of planetary orbits?.
Answer:
Johannes Kepler
suppose that you're driving down the highway and a moth crashes into the windshield of your car. which undergoes the greater force during the collision
Answer:
See below
Explanation:
The windshield and the moth experience equal but opposite forces. (The magnitudes are the same)
My Dad used to say "I'll bet he doesn't have the guts to do THAT again!"
how can you be able to tell if a force is acting on an object by looking at the velocity time graph?
If the velocity is changing over time, then you know there's an external force being acted on the object. You can tell this by Newton's Second Law F=MA where acceleration is change of velocity over change in time. As a result, if the velocity starts to change, then you know an external force is present on the object.