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The final velocity of the ball to one decimal place is approximately 10.0 m/s.

From the third equation of motion:

v² = u² + 2as

Where v is final velocity, u is initial velocity, a is acceleration and s is the distance covered.

Given that:

Plug the given values into the abovr formula and solve for the final velocity v.

v² = u² + 2as

v² = 0² + ( 2 × 6.4 m/s² × 7.8 m )

v² =   2 × 6.4 m/s² × 7.8 m

v² = 99.84 m²/s²

v = √(  99.84 m²/s² )

v = 10.0 m/s

Therefore, the final velocity is 10.0 m/s.

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Answer:

1425kgm/s

Explanation:

Given parameters:

Mass  = 95kg

Velocity  = 15m/s

Unknown:

Momentum  = ?

Solution:

The momentum of a body is the amount of motion it posses;

  Momentum  = mass x velocity

Insert the parameters and solve;

 Momentum  = 95 x 15  = 1425kgm/s

The lifetime of the excited state that produced this line is 416.66sec if a wavelength ranges from 401nm and 403nm.

For solving this problem we use Rydberg equation whose formula is given by

v=[(1 / λ₁) -1 / λ₂)]×(h×c)

where v is the frequency of the photon,

λ is the wavelength of the photon

h is plank's constant

and c is the speed of light in vacuum

Since we are given λ₁ ,λ₂ as 401nm and 403nm respectively.Also we know that value of h is 6.6ˣ10⁻³⁴(J-sec)/m and c=3ˣ10⁸m/sec

So,putting all values on above formula,we get

=>v=[(1/401)-(1/403)]ˣ(6.6ˣ10⁻³⁴) ˣ (3ˣ10⁸)

=>v=[(403-401) ˣ (6.6ˣ10⁻³⁴) ˣ (3ˣ10⁸)] / (401 ˣ 403)ˣ(1/10⁻²⁷)

=>v= [[2 ˣ (6.6ˣ10⁻³⁴) ˣ (3ˣ10⁸)] ₓ(1/10⁻²⁷)] ˣ (1 / 401 ˣ 403)

=>v=(39.6 ˣ 10) / 161603

=>v = 396/161603

=>v = 0.0024/sec

We know time period is reverse of frequency, so  lifetime span is

=>t=1/v

=>t=1/ (0.0024/sec)

=>t=416.66sec

Hence, lifetime of the excited state is 416.66sec.

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Work = (force) x (distance)

Your force was not enough to move the building, so the distance is zero.

Work = (your force) x (zero)

Work = zero

16432 N force is required  to accelerate a 1,264 kg car at a rate of 13 m/s²

Force is an external agent that may change the condition of rest or motion of a body. It has a magnitude as well as a direction. The direction of the force is the place where force is applied, and the application of force is the location where force is applied. Newton (N) is the SI unit of force.

Given that,

Mass of the car (m) = 1264 kg

Acceleration (a) = 13 m/s²

Now calculate how much force (F) is required,

F = m × a

F = 1264 × 13 kg m/s²

F = 16432 N

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Of the options listed, the only effect that can be caused by exposure to infrared light is overheating (option a).

Infrared light is a form of electromagnetic radiation that is invisible to the human eye but can be detected as heat. When exposed to high levels of infrared light, such as in close proximity to a powerful infrared source, it can lead to overheating of the body or objects. Skin cancer (option b) is not directly caused by infrared light. It is primarily associated with overexposure to ultraviolet (UV) radiation from the sun or artificial sources like tanning beds. UV radiation falls in the higher energy range of the electromagnetic spectrum, while infrared radiation has lower energy. Radiation sickness (option c) is caused by exposure to high-energy ionizing radiation, such as gamma rays or X-rays. Infrared light does not possess enough energy to cause ionization and is therefore not capable of inducing radiation sickness. Memory loss (option d) is not a known effect of exposure to infrared light. Memory loss can be attributed to various factors, such as neurological conditions, head injuries, or aging, but not specifically to infrared light exposure. In summary, while exposure to high levels of infrared light can lead to overheating, it does not cause skin cancer, radiation sickness, or memory loss.

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Answer:

No of proton is 13 and nucleus is 13

A series circuit is a circuit in which resistors are arranged in a chain, so the current has only one path to take. The current is the same through each resistor. The total resistance of the circuit is found by simply adding up the resistance values of the individual resistors: ... I = V / R = 10 / 20 = 0.5 A.

Answer:

Its a series circuit.

Explanation:

I took the test :)

Answer:

p_{f} = 6 m / s

Explanation:

We can solve this exercise using conservation of momentum. For this we define a system formed by the two balls, so that the forces during the collision have been intense and the moment is preserved

Initial instant. Before the crash

        p₀ = m v +0

Final moment. Right after the crash

        \(p_{f}\) = (m + m) v_{f}

how the moment is preserved

        p₀ = p_{f}

       m v = 2 m v_{f}

       v_{f} = v / 2

we calculate

       v_{f} = 12/2

       p_{f} = 6 m / s

Heat transfer by radiation is faster than heat transfer by conduction because radiation can occur through a vacuum, while conduction requires the presence of a medium, such as a solid, liquid, or gas. Radiation is the transfer of energy through electromagnetic waves and does not require any medium to propagate, which means that radiation can occur even in a vacuum or through transparent materials.

On the other hand, conduction requires particles to transfer heat energy from one object to another. In a solid, this occurs through the transfer of kinetic energy from one molecule to another through direct contact, while in a liquid or gas, conduction occurs through collisions between molecules. This process of molecule-to-molecule transfer of heat energy is much slower than radiation and is limited by the physical properties of the medium, such as its thermal conductivity.

Therefore, heat transfer by radiation is faster than heat transfer by conduction because radiation can occur through a vacuum, and is not limited by the physical properties of a medium, while conduction is limited by the thermal conductivity of the medium and requires direct contact between molecules.

The x -component of the angular momentum of the particle is 0.99 kgm²/s.

The y -component of the angular momentum of the particle is 3.3 kgm²/s.

The z -component of the angular momentum of the particle is 0.

Angular momentum is the property of any rotating object given by moment of inertia times angular velocity.

Mathematically, the formula for angular momentum is given as;

L = mvr

where;

The given parameters include the following;

the velocity of the particle = ( 3.1i - 8.1 k) m/s

the mass of the particle = 74 g = 0.074 kg

the displacement of the particle, x = 4.3 m, y = - 5.5 m

The x -component of the angular momentum of the particle is calculated as;

Lx = 0.074 x 3.1 x 4.3

Lx = 0.99 kgm²/s

The y -component of the angular momentum of the particle is calculated as;

Ly = 0.074 x ( -8.1) x (-5.5)

Ly = 3.3 kgm²/s

The z-component of the angular momentum of the particle is calculated as;

Lz = 0.074 x ( 0 ) x (0)

Lz = 0

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The electric field of magnitude 16 N/C will be at a distance of 6.0 meters from the charged object.

The magnitude of the electric field due to a point charge object follows the inverse square law, which states that the magnitude of the electric field is inversely proportional to the square of the distance from the charged object. Mathematically, this is expressed as:

\(E = k*q/r^2\)

where E is the electric field, k is Coulomb's constant (\(k = 9 x 10^9 N*m^2/C^2\)), q is the charge of the object, and r is the distance from the object.

We can use this formula to find the distance at which the electric field has a magnitude of 16 N/C. Let's call this distance x:

16 = \(k*q/x^2\)

We can rearrange this equation to solve for x:

x = \(\sqrt(k*q/16)\)

To find q, we need another piece of information. We know that the electric field has a magnitude of 9 N/C at a distance of 4.0 m. Using the same formula as before, we can solve for q:

9 = \(k*q/4^2\)

q = \(9*4^2/k\)

Now we can substitute this value for q into the equation for x:

x =\(\sqrt(k*(9*4^2/k)/16)\)

x =\(\sqrt(9*4^2/16)\)

x = \(\sqrt(36)\)

x = 6.0 meters

Therefore, the electric field of magnitude 16 N/C will be at a distance of 6.0 meters from the charged object.

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Up to 230 homes could be heated by the performance of the power plant.

By definitions of energy efficiency (\(\eta\)), no unit, and principle of energy conservation, the amount of waste heat rate (\(\dot Q_{waste}\)), in megawatts, is equal to the difference between the energy input and the useful output, that is to say:

\(\dot Q_{waste} = \left(\frac{1}{\eta} -1\right)\cdot \dot E_{out}\) (1)

Where \(\dot E_{out}\) is the useful output, in watts.

According to the statement, an average home uses 70 GJ of energy per year for heating and home heating takes place at a steady rate for half a year, then the number of homes (\(n\)), no unit, benefited by the co-generation plant is calculated by this formula derived from physical definition of power:

\(n = \frac{\dot Q_{waste}\cdot \Delta t}{Q_{home}}\) (2)

Where:

Now we proceed to find the number of houses: (\(\dot E_{out} = 1.9\times 10^{6}\,W\), \(\eta = 0.65\), \(\Delta t = 1.577\times 10^{7}\,s\), \(Q_{home} = 7\times 10^{10}\,J\))

By (1):

\(\dot Q_{waste} = \left(\frac{1}{0.65}-1 \right)\cdot (1.9\times 10^{6}\,W)\)

\(\dot Q_{waste} = 1.023\times 10^{6}\,W\)

By (2):

\(n = \frac{(1.577\times 10^{7}\,s)\cdot (1.023\times 10^{6}\,W)}{7\times 10^{10}\,J}\)

\(n = 230.467\)

Up to 230 homes could be heated by the performance of the power plant. \(\blacksquare\)

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Answer: the spiral stick wouldnt be wet because it isnt touching the water, so therefore the sprial stick wouldnt be hot because it isnt touching the water.

Explanation:

Answer:

There is less gravitational force in space.

Explanation:

Gravity doesn't exist as it does on Earth. Earth's gravity is as 6 times stronger as it is on the moon.

It is not recommended to fire a gun straight up into the air.

When a bullet is fired into the air, it will eventually come down and can pose a danger to people and property below. The bullet can still be lethal when it reaches the ground, especially if it lands on a hard surface or hits someone directly.

Additionally, firing a gun in a residential area can be illegal and can result in legal consequences. In general, guns should only be fired in designated shooting ranges or in self-defense situations where there is an immediate threat to life. It is important to handle firearms responsibly and follow all safety guidelines to prevent accidents and injuries.

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Answer:

B. A and D

Explanation:

Two resistors have the same current if they are in series. It means that they are connected one after the other. On the other hand, they are in parallel when they are both connected to the source. For example:

Therefore, the resistors in series are A and D. So, they have the same current.

Then, the answer is:

B. A and D

The constant acceleration of the train is 50/9 m/s².

The two balls will collide at a height of approximately 10.204 meters above the ground.

Using the kinematic equations of motion, we have:

distance = initial velocity * time + 1/2 * acceleration * time^2

For the first phase of acceleration, the initial velocity is zero, the time is 5 minutes = 300 seconds, and the distance traveled is unknown. So we have:

d1 = 0 + 1/2 * a * (300)^2

For the second phase of constant speed, the initial velocity is v, the time is 5 minutes = 300 seconds, and the distance traveled is also unknown. So we have:

d2 = v * 300

For the third phase of deceleration, the initial velocity is v, the time is also 5 minutes = 300 seconds, and the distance traveled is again unknown. So we have:

d3 = v * 300 + 1/2 * (-a) * (300)^2

The total distance traveled is the sum of these three distances:

distance = d1 + d2 + d3 = 1/2 * a * (300)^2 + v * 600 - 1/2 * a * (300)^2 = v * 600

Since the total distance traveled is given as 10 km = 10000 m, we have:

v * 600 = 10000

Solving for v, we get:

v = 10000/600 = 50/3 m/s

Now we can use the second equation above to find a:

d2 = v * 300 = (50/3) * 300 = 5000 m

Therefore, the constant acceleration of the train is:

a = 2 * (5000 - 1/2 * a * (300)^2) / (300)^2 = 50/9 m/s^2

The constant acceleration of the train is 50/9 m/s^2.

Problem 2: The height of the first ball dropped is given as 10m. Let's assume the height of the collision point is h meters above the ground.

Using the kinematic equation for free fall, we have:

h = 10 + 1/2 * g * t^2

where g is the acceleration due to gravity, which is approximately 9.81 m/s^2, and t is the time it takes for the second ball to reach the collision point after being thrown upwards.

The initial upward velocity of the second ball is 10 m/s, and we know that at the collision point, its velocity will be zero, since it will have reached its maximum height and will be momentarily at rest before falling back down.

Using the kinematic equation for motion with constant acceleration, we have:

0 = 10 + (-g) * t

Solving for t, we get:

t = 10/g = 10/9.81 seconds

Substituting this value of t into the first equation, we get:

h = 10 + 1/2 * 9.81 * (10/9.81)^2

Simplifying, we get:

h = 10.204 m

The two balls will collide at a height of approximately 10.204 meters above the ground.

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The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Before the ball hits the ground, it is 2.8 seconds in the air. The result is obtained by using the equations in uniformly accelerated straight motion.

The equations apply in uniformly accelerated straight motion in vertical dimension are

v₁ = v₀ + gt

v₁² = v₀² + 2gh

h = v₀t + ½ gt²

Where

A student standing on the ground throws a ball straight up with

Find the time it takes for the ball to reach the ground!

We use g = 9.8 m/s². See the illustration picture in the attachment!

The ball will go upward and stop at a certain height with v₁ = 0. The time needed is

v₁ = v₀ - gt₁

0 = 13.0 - 9.8t

13.0 = 9.8t

t₁ = 13.0/9.8

t₁ = 1.3 s

The height above the hand when the ball stops is

v₁² = v₀² - 2gh₂

0 = 13.0² - 2(9.8)h₂

13.0² = 2(9.8)h₂

169 = 19.6h₂

h₂ = 8,62 m

The ball stops at a height of

h₃ = h₁ + h₂

h₃ = 2.50 + 8.62

h₃ = 11.12 m

The ball goes downward and reach the ground. Initial velocity in this condition is v₁ = 0. The time needed is

h₃ = v₁t + ½ gt₂²

11.12 = 0 + ½ (9.8)t₂²

11.12 = 4.9t²

t₂² = 2.27

t₂ ≈ 1.5 s

The time that the ball in the air is

t = t₁ + t₂

t = 1.3 + 1.5

t = 2.8 s

Hence, the ball is in the air for 2.8 seconds.

Your question is incomplete, but most probably your full question was

A student standing on the ground throws a ball straight up. The ball leaves the student's hand with a speed of 13.0 m/s when the hand is 2.50 m above the ground. How long is the ball in the air before it hits the ground? (The student moves her hand out of the way).

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Answer:

300 J

Explanation:

Work = (Force)*(distance) = 600 N ∗ 0.5 m = 300 J

The contact force (in N) between each pair of boxes is mathematically given as

F_{ab} = 3.56 N

F_{bc} = 1.2 N

Generally, Any force that is generated as a consequence of two objects coming into touch with one another is referred to as a contact force. Contact forces are present everywhere and are the cause of the vast majority of macroscopic groupings of matter's obvious interactions with one another.

In conclusion, The equation for is  Acceleration of the system is mathematically given as

a = 8.25 / (5.85 + 2.95 + 1.50)

a= 0.8 m/s^2

Therefore

F_{ab} = (Mb + Mc)*a

F_{ab} = (2.95 + 1.50) * 0.8

F_{ab} = 3.56 N

F_{bc} = Mc * a

F_{bc}= 1.5 * 0.8

F_{bc} = 1.2 N

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To determine the image characteristics using the 3 principal rays and SALTS (Size, Attitude, Location, Type), we'll consider both lenses and mirrors separately. Here's how you can analyze each case:

Lenses:

Place an object at different distances to the left of a lens with a focal length (f).

a) Object placed beyond 2f:

In this case, the object is placed far beyond twice the focal length of the lens.

Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.

Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.

Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.

The image will be formed on the opposite side of the lens, between the focal point and twice the focal length.

SALTS:

Size: The image will be smaller than the object.

Attitude: The image will be inverted.

Location: The image will be located between the focal point and twice the focal length.

Type: The image will be real.

b) Object placed at 2f:

In this case, the object is placed at twice the focal length of the lens.

Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.

Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.

Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.

The image will be formed on the opposite side of the lens at twice the focal length.

SALTS:

Size: The image will be the same size as the object.

Attitude: The image will be inverted.

Location: The image will be located at twice the focal length.

Type: The image will be real.

c) Object placed between f and 2f:

In this case, the object is placed between the focal point and twice the focal length of the lens.

In this case, the object is placed far beyond twice the focal length of the mirror.

Principal ray 1: A ray parallel to the principal axis will reflect through the focal point on the same side.

Principal ray 2: A ray passing through the focal point on the object side will reflect parallel to the principal axis.

Principal ray 3: A ray passing through the center of curvature will reflect back along the same path.

The image will be formed on the opposite side of the mirror, between the focal point and twice the focal length.

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Answer:

Elements heavier than iron are formed by neutron capture processes during stellar death and supernovae.

Explanation:

Most of the elements heavier than iron are formed during the death of stars through neutron capture processes, specifically the R-Process and the S-Process. The R-Process is a rapid capture of neutrons, while the S-Process is a slow capture of neutrons. These processes either directly form elements or indirectly form them through decay processes [^1]. Elements heavier than iron are primarily made in environments with free-neutron densities in excess of a million particles per cubic centimeter [^2]. In the extreme energetic conditions of supernovae, atoms are bombarded by a very large number of neutrons, and rapid successive neutron capture, followed by beta decay, produces the heavier atoms [^5].

So, elements heavier than iron are formed by neutron capture processes during stellar death and supernovae.

[^1

Answer:

The half-life of 14C is 5703 years.

a maget with its north pole pointed doğnwards is fallling doğn directliy above a wire loop as the maghet

Answer:

Weight = 17780.82 N

Explanation:

The weight of the heaviest invertebrate = 2 tons

It is spread out over its length of 70 feet.

We need to find its weight in newtons.

We know that,

1 ton = 907.185 kg

2 ton  = 1814.37 kg

Weight of a body is given by :

W = mg

Where

g is the acceleration due to gravity, g = 9.8 m/s²

So,

W = 1814.37 kg × 9.8 m/s²

W = 17780.82 N

Hence, the weight of heaviest invertebrate is 17780.82 N.

The weight will be "19600 Newtons".

Given values:

Length,

Mass,

            = 2 × 1000

            = 2000 kg

As we know,

→ \(W = mg\)

By substituting the values, we get

       \(= 2000\times 9.8\)

       \(= 19600 \ N\)

Thus the response above is appropriate.

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The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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