I need help please.

h = 11.9 cm

cos = adjacent/ hypotenuse

therefore:

cos(24) = h/ 13

rearrange:

h = 13cos(24)

put into calculator:

h = 11.8760...

rounded to one decimal point:

h = 11.9cm

Answer: 1/2

Step-by-step explanation:

The probabilities must add to 1, so:

\(P(x < 9) +P(X=9)+P(X > 9)=1\\\\\frac{1}{6}+P(X=9)+\frac{1}{3}=1\\\\P(X=9)=\boxed{\frac{1}{2}}\)

Answer:

30 degrees

Step-by-step explanation:

So a complete circle consists of 360 degrees but we are trying to find what ADB equals so we are going to subtract BDC and ADC from 360:

BDC = 150

The graph does not say what ADC equals so we are going to look at the graph and see that ADC is half of the circle so we are going to divide 360 by 2:

360/2 = 180

So ADC equals 180, since we know what ADC and BDC equal we are going to add them together and then subtract them from 360:

180 + 150 = 330

360 - 330 = 30

So ADB = 30 degrees

Hope this helps!

The correct answer is 2 (C) - 2 days is the total slack for activity F. To determine the total slack for activity F, we need to calculate the slack for each activity in the network. Slack refers to the amount of time an activity can be delayed without affecting the project completion time.

1. First, let's draw the network using the information provided:
  - A is the start node and G is the stop node.
  - Activity A has a duration of 5 days and has no predecessor.
  - Activities B, C, and D have durations of 8, 7, and 6 days respectively, and their predecessors are A.
  - Activity E has a duration of 9 days and its predecessors are B, C, and D.
  - Activity F has a duration of 10 days and its predecessors are B, C, and D.
  - Activity G has a duration of 5 days and its predecessors are E and F.

                 A
                /|\
               / | \
              /  |  \
             B   C   D
              \  |  /
               \ | /
                \|/
                 E
                 |
                 F
                 |
                 G

2. Now, let's calculate the slack for each activity:
  - Slack is calculated by subtracting the earliest start time of an activity from the latest start time without delaying the project completion time.
  - The earliest start time for activity F is 17 days.
  - The latest start time for activity F is 19 days (project completion time is 22 days).
  - Total slack for activity F = latest start time - earliest start time = 19 - 17 = 2 days.

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a) The binomial expansion of (1+12x)^1/2 is given by:

(1+12x)^1/2 = 1^1/2 + (1/2)(1^-1/2)(12x) + (1/2)(1^-1/2)(-1/2)*(12x)^2 + ...

Binomial expression: what is it?

A polynomial with only terms is a binomial. An illustration of a binomial is x + 2, where x and 2 are two distinct terms. Additionally, in this case, x has a coefficient of 1, an exponent of 1, and a constant of 2. As a result, a binomial is a two-term algebraic expression that contains a constant, exponents, a variable, and a coefficient.

The first four terms, in ascending powers of x, are:

1, (1/2)(12x), (1/8)(12x)^2, (1/16)*(12x)^3

b) To use x=1/36 in the expansion, you would substitute x=1/36 into the expansion, and keep only the terms up to x^3 (the fourth term in the expansion). This will give an approximation of the value of (1+12x)^1/2 when x=1/36.

This will be an approximation of √12 because x=1/36 corresponds to 12x = 1 and the initial value of the expansion is 1 + 12x .

We can use this approximation to approximate square root of 12 and also for other square roots by using appropriate x values.

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Answer:

c !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Step-by-step explanation:

Answer:

D.

Step-by-step explanation:

The graph represents the slope, the two equations represent the slope, but the chart does not because it isn't set up correctly. Hope this helps! :)

"The mean will be higher than the median in any distribution that" ;

has a positively skewed distribution

A positively skewed distribution is one in which the majority of data values are clustered towards the lower end of the range, while the rest of the values are spread out towards the higher end of the range. As a result, the mean (the average of all the data values) will be higher than the median (the middle value of the data set).

This is because the mean is affected by the higher values in the distribution, while the median is not.

Positively skewed distributions are common in real-world data sets and are often seen in income distributions, stock market returns, and other economic data.

For example, a distribution of incomes may have a few very high earners pushing up the mean, while the majority of people make much lower amounts, resulting in a median that is lower than the mean.

Similarly, stock market returns may have a few very large returns that pull the mean up, while the majority of returns are much lower, resulting in a median that is lower than the mean.

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The smallest amount that Caleb could have converted will be £ 59.

We are given that:

At shop A, Gavin converted £ 30 into € 36.60

At shop B, Amna converted £ 73 into € 86.14

Also, Caleb converted some pounds and got € 71.98.

Rate of conversion at shop A is:

£ 30 = € 36.60

£ 1 = € 36.60 / 30

£ 1 = € 1.22

rate of conversion at shop B is:

£ 73 = € 86.14

£ 1 = € 86.14 / 73

£ 1 = € 1.18

Now, we can see that the rate of conversion is more at shop A.

So, the smallest amount that Caleb might have converted will be:

Pounds = € 71.98 / € 1.22

Pounds = £ 59

Therefore, the smallest amount that Caleb could have converted will be £ 59.

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The equation of the halfpipe is  Option A , (0, 20); Y equals one over eighty times x squared plus 20.

The equation of the halfpipe is  Y = X²/80 +20.

What is parabola ?

The equation of parabola is given by  

(X-h)² = 4p(Y-k)²

In this case h = 0

So we get  

Y = X²/4P +k

Focus point is (h, p+k) , (p+k) = 40

Hence h, k = (0,20)

P = 40-k = 20

Equation Y = X²/80 +20

Therefore, the equation of the halfpipe is  Y = X²/80 +20

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The complete question is -

A skateboard halfpipe is being designed for a competition. The halfpipe will be in the shape of a parabola and will be positioned above the ground such that its focus is 20 ft above the ground. Using the ground as the x-axis, where should the base of the halfpipe be positioned? Which equation best describes the equation of the halfpipe?

(0, 20); y equals one over eighty times x squared plus 20

(0, 20); y equals one over eighty times x squared minus 20

(0, 10); y equals one over forty times x squared plus 10

(0, 10); y equals one over forty times x squared minus 10

The given statement is False. A test statistic based on point estimation is not used to construct the decision rule which defines the rejection region.

In hypothesis testing, a test statistic is calculated using sample data and a specific hypothesis to assess the strength of evidence against the null hypothesis. The decision rule, which determines whether to reject or fail to reject the null hypothesis, is based on the test statistic's distribution under the null hypothesis, rather than the point estimate itself.

The construction of the decision rule involves selecting a significance level (alpha), which represents the probability of rejecting the null hypothesis when it is actually true. The rejection region is determined based on the chosen significance level and the distribution of the test statistic. If the calculated test statistic falls within the rejection region, the null hypothesis is rejected; otherwise, it is not rejected.

Point estimation, on the other hand, is used to estimate an unknown parameter of interest, such as the population mean or proportion, based on sample data. It involves calculating a single value (point estimate) that represents the best guess for the parameter value. The point estimate is not directly involved in constructing the decision rule or defining the rejection region in hypothesis testing.

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False. A test statistic based on point estimation is not used to construct the decision rule that defines the rejection region.

The process of hypothesis testing involves constructing a decision rule to determine whether to accept or reject a null hypothesis based on sample data. The decision rule is typically defined using a critical region or rejection region, which is a range of values for the test statistic.

Point estimation, on the other hand, is a method used to estimate an unknown population parameter based on sample data. It involves calculating a single value (point estimate) that serves as an estimate of the population parameter.

While point estimation and hypothesis testing are both important concepts in statistics, they serve different purposes. Point estimation is used to estimate population parameters, whereas hypothesis testing involves making decisions based on sample data.

The decision rule for hypothesis testing is typically constructed based on the significance level (alpha) and the distribution of the test statistic, such as the t-distribution or the standard normal distribution. The test statistic is calculated using sample data and compared to critical values or calculated p-values to determine whether to reject the null hypothesis.

Therefore, the statement that a test statistic based on point estimation is used to construct the decision rule defining the rejection region is false.

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we have that

the total numbers in the spinner are 8 numbers

numbers greater than 5 -----> 6,7 and 8------> 3 numbers

the probability is

3/8

Multiply by 150 times

150(3/8)=56.25

therefore

The system of equations for Sean's outdoor yard games is: Cost equation: C = 50x + 300. Revenue equation: R = 85x.
Again, we round up to the nearest whole number. Therefore, the least number of games Sean needs to sell for a profit is 9 games.

To find Sean's break-even point, we need to find the point where the cost equals the revenue. So we can set the two equations equal to each other and solve for x:
50x + 300 = 85x
Subtracting 50x from both sides, we get:
300 = 35x
Dividing both sides by 35, we get:
x = 8.57


To determine the least number of games Sean will need to sell in order to make a profit, we need to find the point where the revenue is greater than the cost. So we can set the revenue equation greater than the cost equation and solve for x:
85x > 50x + 300
Subtracting 50x from both sides, we get:
35x > 300
Dividing both sides by 35, we get:
x > 8.57
Again, since Sean can't sell a fraction of a game, we need to round up to the nearest whole number. Therefore, Sean needs to sell at least 9 games to make a profit.
To find Sean's break-even point and the least number of games he needs to sell for a profit, we will work with the given system of equations. The equations for cost (C) and revenue (R) are:
C(x) = 50x + 300
R(x) = 85x
To find the break-even point, we will set the cost equal to the revenue:
50x + 300 = 85x
Now, solve for x:
35x = 300
x = 300 / 35
x ≈ 8.57
Since x represents the number of games, we round up to the nearest whole number because Sean cannot sell a fraction of a game. So, Sean needs to sell at least 9 games to break even.
To find the least number of games for a profit, we need the revenue to be greater than the cost:
85x > 50x + 300
Solve for x:
35x > 300
x > 300 / 35
x > 8.57

So Sean's break-even point is when he sells approximately 8.57 games. However, since he can't sell a fraction of a game, we need to round up to the nearest whole number. Therefore, Sean needs to sell at least 9 games to break even.

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So the first task is to:
First, select the point on the graph that represents Sean's break-even point, which is the point where the costs to make the games will equal the revenue from selling them. Notice that the revenue equation has already been graphed.

We know the initial cost of $300 for supplies, $50 per each game and it's going to be sold at $85.

The graph shows four points. The first one being at 5 games sold, with approximately $425 collected. The second one at around 8.5 games sold, which is about $725. The third one is ten games sold, with $850 collected. The last one is around 11.8 game sold, with approximately $1000 gained.

So: 50 x 5 + 300 = 550 (Cost per game + initial cost)

      85 x 5 = 425 (Cost of games sold)      That removes the first point.

           50 x 8.5 + 300 = 725

           85 x 8.5 = 722   (Close enough:)

That gave us it took Sean 8.5 games to have a revenue equal to the cost of making them.

Then, the second task is to:

Determine the least number of games Sean will need to sell in order to make a profit. Profit occurs when revenue is greater than the cost.

The choices are at 5, 8, 9, or 10 games.

Since we previously found out that it took him 8.5 games to have an equal revenue to the cost, we can easily knot that it took him 9 games to make a profit.

But just for sure:
50 x 9 + 300 = 750

          85 x 9 = 765

Peace:D

ヾ(•ω•`)o

Answer:

$1.4 million

Step-by-step explanation:

A P E X

Answer:1.4 million

Step-by-step explanation:

Answer:

$7665

Explanation:

simple interest: principal * rate (%) * time (years)

Given:

principal: $3,500

rate: 7%

time: 17 years

Solve for interest received:

3,500 * 7% * 17

$4165

Total money in account:

$4165 + $3,500

$7665

we have:

=> 6 ÷ 11 = 12 ÷ AB

=> AB = 12 × 6 ÷ 11 = 72/11 ≈ 6,5

Answer: 72/11 ≈ 6,5

P/s: CA = CD + AD = 6 + 5 = 11

Ok done. Thank to me :>

The value of a from the equation  5y = x + 47 with slope 1/5 is 11.

A line's steepness and direction are measured by the line's slope. Without actually using a compass, determining the slope of lines in a coordinate plane can assist in forecasting whether the lines are parallel, perpendicular, or none at all.

Any two different points on a line may be used to compute the slope of any line. The ratio of "vertical change" to "horizontal change" between two separate locations on a line is calculated using the slope of a line formula.

The increase divided by the run, or the ratio of the rise to the run, is known as the line's slope. In the coordinate plane, it describes the slope of the line. Finding the slope between two separate locations and calculating the slope of a line are related tasks. In general, we require the values of any two separate coordinates of a line in order to determine its slope.

The slope of the line = 1/5

The line passes through (8,a) and (3,10)

The equation of the line is

y = mx + c

where m is slope and c is y-intercept

or , y = x/5 + c

putting (3,10) in the line

10 = 3/5 + c

⇒ c = 47/5

The equation of the line is y = x/5 + 47/5

or, 5y = x + 47

putting (8,a) in the line

5a = 8 + 47

⇒ a = 55/5 = 11

The value of a from the equation  5y = x + 47 with slope 1/5 is 11.

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Answer:

independent

Step-by-step explanation:

because it asked ronald to roll a dice and flip a quarter, no one else he did it himself

At least 10 students scored lower than Jenny.
The possible range of the marks of the top four students is 75.5 to 85.5 marks.
The least possible pass mark is 55.5 marks.

What is frequency ?

Frequency refers to the number of times a particular value or category appears in a set of data. It is a basic concept in statistics that helps to describe and analyze data.

Frequency can also be used to create frequency distributions, which are tables that show the frequency of each value or category in a set of data. Frequency distributions can be used to help visualize and analyze patterns in data, and they are often used in statistical analysis and research.

According to the question:
(a) No, Jenny could not be one of the three students with the lowest marks because her score of 41.5 marks falls above the cumulative frequency of 10 (i.e., the number of students who scored below 40 marks). Therefore, at least 10 students scored lower than Jenny.

(b) To find the possible range of the marks of the top four students, we need to look at the cumulative frequency of 31 (i.e., the number of students who scored below 35.5 marks). The top four students would be the ones who scored above this mark. Looking at the cumulative frequency polygon, we see that this mark falls between the scores of 75.5 and 85.5, so the possible range of the marks of the top four students is 75.5 to 85.5 marks.

(c) If 60% of the students pass the examination, then the total number of students who pass is 0.6 x 35 = 21. The least possible pass mark is the lowest score that is at or above the cumulative frequency of 21. Looking at the cumulative frequency polygon, we see that this mark falls between the scores of 55.5 and 65.5, so the least possible pass mark is 55.5 marks.

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A sequence is (recursively) defined as a1 = 0, a2 = 1, n>2, \(a_n = a_{n-1} - 3a_{n-2}\). The first seven terms are 0, 1, 1, -2, -5, 1, 16.

A recursive sequence is a sequence in which terms are defined using one or more previous terms which are given.

a1 = 0

a2 = 1

\(a_n = a_{n-1} - 3a_{n-2}\)

a3 = a2 - 3*a1 = 1 - 0 = 1

a4 = a3 - 3*a2 = 1 - 3 = -2

a5 = a4 - 3*a3 = -2 - 3 = -5

a6 = a5 - 3*a4 = -5 + 6 = 1

a7 = a6 - 3*a5 = 1 +15 = 16

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Answer:

V=1/3πr^2h

π=1/3r^2hV

The width of the newspaper page is approximately 22.83 inches, and the length is approximately 28.11 inches.

Let's assume the width of the newspaper page is "x" inches. According to the given information, the length is about 1.23 times the width, so the length can be represented as "1.23x" inches.

The area of a rectangle can be calculated using the formula:

Area = Length × Width

640.98 = (1.23x) × x

640.98 = 1.23x²

Now, let's solve for x by dividing both sides of the equation by 1.23:

x² = 640.98 / 1.23

x² ≈ 521.95

Taking the square root of both sides to solve for x, we find:

x ≈ √521.95

x ≈ 22.83

Therefore, the width of the newspaper page is approximately 22.83 inches.

To find the length, we can multiply the width by 1.23:

Length ≈ 1.23 × 22.83

Length ≈ 28.11

Therefore, the length of the newspaper page is approximately 28.11 inches.

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Answer:

173

Step-by-step explanation:

Answer:

A = 173 yds^2

Step-by-step explanation:

The formula for the area of a parallelogram is

A = bh

The base is 17.3 yd

The height is 10 yds

A = 17.3 * 10

A = 173 yds^2

Answer:

?

Step-by-step explanation:

Answer:

They both have H hoel

Step-by-step explanation:

\

Answer:it would be even i think

Step-by-step explanation:

please give me brainliest if   im right

Answer:

1.17279656871

Step-by-step explanation:

Answer:

1.72796569

Step-by-step explanation:

0.4567304 x 2.5678093 = 1.72796569

Laplace transform of the differential equation is\(L(y) = [9/(s(s+1))] + [8/(s^2(s+1))]×L(t) - [32/(s^2(s+1))]\)

The given initial value problem is:\(y' + y = 9 + 8(t - 4), y(0) = 0\) and we need to find the Laplace transform of the given differential equation. Since Laplace transform is linear, we have:

\(L(y' + y) = L(9 + 8(t - 4))L(y') + L(y) = 9L(1) + 8L(t - 4)\)T aking the Laplace transform of y' and using \(L(dy/dt) = sL(y) - y(0)\) , we get: \(sL(y) - y(0) + L(y) = 9/s + 8(1/s^2)×L(t) - 8(1/s^2)×L(4)⇒ (s + 1)L(y) = 9/s + 8(1/s^2)×L(t) - 8(1/s^2)×L(4)L(y) = [9/(s(s+1))] + [8/(s^2(s+1))]×L(t) - [8/(s(s+1))]×(4/s)L(y) = [9/(s(s+1))] + [8/(s^2(s+1))]×L(t) - [32/(s^2(s+1))]\)This is the Laplace transform of the given differential equation.

Therefore, Laplace transform of the differential equation is \(L(y) = [9/(s(s+1))] + [8/(s^2(s+1))]×L(t) - [32/(s^2(s+1))]\)

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The number 1111111111111111111 is not prime. In general, a number with all 1's in base b can be prime only if the number of 1's is prime.

To prove this, let's consider a number N in base b with n 1's, and let's assume n is not prime. Since n is not prime, it can be factored as n = a * b, where a and b are integers greater than 1.

Now, let's rewrite N as a sum of geometric series:

N = 1 + b + b^2 + ... + b^(n-1)

Now, let's factor the series:

N = (1 - b^a) * (1 + b^a + b^(2a) + ... + b^(n-a))

Since both factors are greater than 1, N is not prime. Therefore, a number with all 1's in base b can be prime only if the number of 1's is prime.

As for the term "strabismus," it is unrelated to this mathematical proof. Strabismus is a medical condition related to the misalignment of eyes.

When answering questions on Brainly, you should always aim to be factually accurate, professional, and friendly. It is important to be concise and avoid providing extraneous amounts of detail. While it is okay to overlook typos or irrelevant parts of the question, you should always focus on providing a helpful and accurate answer to the student's question. Additionally, it is important to avoid making any assumptions about the student's question or intentions. Finally, the question about whether this is a test for strabismus is unrelated to the math problem and should be disregarded. As for the math question itself:If a number in radix b is represented by (11...1), where the number of I's is prime, it can be prime. We can see why this is the case by applying Fermat's little theorem, which states that if p is a prime number and a is any positive integer not divisible by p, then a^(p-1) ≡ 1 (mod p).For example, consider the number (111) in base 2 (i.e., binary). This number is equal to 1 x 2^2 + 1 x 2^1 + 1 x 2^0 = 7 in base 10. Since 3 is a prime number, we can test whether 111 is prime by computing 2^(3-1) ≡ 1 (mod 3) and 111 ≡ 0 (mod 3), which implies that 111 is divisible by 3. Therefore, 111 is not a prime number.

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Answer:

c, 14

Step-by-step explanation:

Answer:

the ansewr is b

Step-by-step explanation: