human activities, such as agriculture, can require altering the land. i. identify an environmental problem associated with large-scale intensive agriculture on soil.

Answer:

Motor cortex

Both hemispheres have a motor cortex, with each side controlling muscles on the opposite side of the body (i.e, the left hemisphere controls muscles on the right side of the body).

Explanation:

The altitude of the balloon at the time the sandbag was dropped is 490m.

The height of an object is the measurement taken from its bottom to its top. In geometry, it is occasionally referred to as altitude. It is calculated how far apart the lowest and highest points are vertically. It is frequently the measurement along an object's y-axis in coordinate geometry.

Sandbag dropped from height above ground = H:

H = v₀t-at²/2

= 4.2×t-gt²/2

t = 10 s

g = 9.8 m/s²

H = 4.2×10- 9.8×10²/2

H = -448 m

The height of the balloon when the sandbag was dropped = 448 m

During these 10 s the balloon ascended an additional:

4.2×10 = 42 m

So the height of the balloon when the sandbag reached the ground is:

448+42 = 490 m.

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Answer: Vx= 86.6 m/s & Vy= 50 m/s

Explanation:

Vx= 100*cos30° = 86.6 m/s

Vy= 100*sin30° = 50 m/s

The temperature of the gas (in °C) at this pressure is 248.5 °C

Temperature is a bodily quantity that expresses the hotness of count or radiation. There are 3 kinds of temperature scales. Temperature is the degree of hotness or coldness of an item.

Temperature is a degree of the common kinetic energy of the debris in an object. whilst the temperature increases, the motion of those particles also increases. Temperature is measured with a thermometer or calorimeter.

Given;

P₁ = 1.2 x10⁵ Pa = 1.18430792

T₁ = 25.0°C = 298 K

P₂ = 2.1x10 Pa = 0.000207253886

T₂ = ?

using ideal gas equaion:-

PV = nRT

P₁/T₁ = P₂/T₂

T₂ = P₂T₁  /P₁

   = 2.1x10⁵ x  298 / 1.2 x10⁵

   = 521.5 K

   = 248.5 °C

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Writing in an online journal is different from writing in a paper one in the following way: it is easier to communicate online (option B).

A journal is a newspaper or magazine dealing with a particular subject.

A journal is an efficient medium to communicate the findings or results of an investigation to the public.

However, a journal can be virtual (online) or paper (hard copy). In this 21st century, it is easier to communicate to the masses online because more audience will be captured.

Therefore, writing in an online journal is different from writing in a paper one in the following way: it is easier to communicate online.

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Answer:

1/2

Explanation:

Given

c=distance

a= length

e= c/a

3/6

e= 1/2 or 0.5

vi = 20 m/s

angle = 60°

g= 10 m/s^2

a.Speed at the highest point:

At the highest point, the ball's speed is entirely horizontal.

vx= v0 cos 60 = 20 cos 60 = 10 m/s

b.Speed before it strikes the ground:

It strikes the ground with the same speed that it leaves the ground:

20 m/s

Answer:

2 m/s^2

Explanation:

Acceleration = Force/mass

= 2,000/1,000

= 2

The speed of star A is  0.01×10⁸m/sec if wavelength from level2 to level1 is 121.6m.

The Doppler shift, otherwise called the Doppler impact, is characterized as the adjustment of the frequency or recurrence of the waves concerning the eyewitness who is moving comparative with the wave source. The Doppler shift was conjectured in the year 1842 by the Austrian physicist Christian Doppler.

The standard behind the alarm is that it begins at a higher pitch than its fixed pitch when it slides down from the eyewitness, and again when it retreats from the spectator, it go on at a lower pitch than its fixed pitch. It is utilized in crisis vehicles. Alarm's speed is given as

v=v₀cosθ

where θ is the point between the item's view and the forward speed.

We know that according to doppler-shift formula,

v/c=(λ-λ₀)λ₀

where v is the speed of star c is the speed of light in vacuum,λ is the wavelength of light wave in any other medium and λ₀ is the wavelength of light wave in vacuum.

We know that c=3×10⁸m/sec,v=?,λ=121.3m,λ₀=120.8m

On putting value,we get

=>v/3×10⁸m/sec=(121.3-120.8)/121.3

=>v/3×10⁸m/sec=0.5/121.3

=>v=(0.5/121.3) ×3×10⁸m/sec

=>v=0.0041×3×10⁸m/sec

=>v=0.01×10⁸m/sec.

Hence,speed of star is 0.01×10⁸m/sec.

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(Complete question) is:

In hydrogen, the transition from level 2 to level 1 has a rest wavelength of 121.6 . Suppose you see this line at a wavelength of 120.2 in Star A and at 121.2 in Star B. Calculate the speed of star A.

You have two windlasses  named X and Y. Windlass X drum diameter is 50cm and windlass Y drum diameter is 75cm. Both are hoisting a 50kg weight, Hence, X will lift faster and easier than Y

Generally, the equation for the Torque is  mathematically given as

Torque(X)=weight x radius of drum

T=50x9.81x0.25

T=122.625 Nm

For, Torque (Y)

T=50x9.81x0.375

T=183.93 Nm

Generally, the equation for the Equation of Power is  mathematically given as

P= Torque * Angular velocity

Angular velocity (w)= 2 x pi x N/60

As a consequence, torque has an inverse relationship to speed. Because of this, the torque will decrease as the speed rises.

According to the previous statement, windlass X has a speed of lift that is at its maximum, but windlass Y has a speed that is very low.

Additionally, power is exactly proportional to torque, which means that the highest possible torque required the highest possible amount of energy and vice versa.

Therefore, X should raise at the highest possible speed while using the least amount of energy.

In conclusion, X will lift faster and easier than Y

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The magnitude of the total displacement is 20.28 m.

The angle of the total displacement with the x axis is 70.5⁰.

The total displacement of the player is calculated as follows.

Apply cosine rule as shown below;

d² = d₁² + d₂² - 2d₁d₂ cos(θ)

d² = (24.1)² + (7.9²) - (2 x 24.1 x 7.9) cos(52.5)

d² = 411.42

d = √411.42

d = 20.28 m

Apply sine rule as shown below;

d/sinD = d₂/sinD₂

20.28/sin(52.5) = 7.9/sinD₂

25.562 = 7.9/sinD₂

sinD₂ = 7.9/25.562

sinD₂ = 0.309

D₂ = sin⁻¹(0.309)

D₂ = 18⁰

angle with x axis =  18⁰ + θ

                            =  18⁰ +  52.5⁰

                            = 70.5⁰

Thus, the magnitude of the total displacement is 20.28 m.

The angle of the total displacement with the x axis is 70.5⁰.

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Answer:

Explanation:a

Answer:  40 cm/s.

Explanation:

To solve this problem, we need to use the formula for velocity, which is velocity = distance/time.

We are given the time it takes for one wave to pass the pile of pickerel as 0.50 seconds and the distance that the pickerel protrude along the beach as 20 cm. Plugging these values into the formula gives us:

velocity = distance/time

= 20 cm / 0.50 s

= 40 cm/s

Since we are given the value of g with two significant digits, we should round our answer to the nearest whole number, giving us 40 cm/s.

Plate Boundaries on Earth assignment involves identifying and illustrating different types of plate movements at the Earth's contact points.

Here are the steps to be followed:

Step 1: Understanding the Assignment Requirements

Read through the assignment instructions carefully to ensure a clear understanding of the tasks and expectations.

Step 2: Research

Start by conducting research on plate boundaries, their types, movements, and associated geological processes. Use reliable and valid resources such as scientific journals, textbooks, and reputable websites. Take notes on the different plate movements, their characteristics, and examples of each.

Step 3: Worksheet Setup

Create a table or chart with six rows corresponding to the six categories specified in the assignment instructions: Plate Boundary (Movement), Diagram, Lithosphere (Created or Destroyed), Geologic Process, Real World Example, and References.

Step 4: Fill in Row 1 - Plate Boundary (Movement)

In the first row, list the three types of plate boundaries: convergent, divergent, and transform. Next to each type, write the correct description in parentheses: sliding, separating, or colliding.

Step 5: Fill in Row 2 - Diagram

In the second row, draw a diagram or illustration for each type of plate movement. Use arrows to indicate the direction of movement and whether the plates are colliding, separating, or sliding past each other.

Step 6: Fill in Row 3 - Lithosphere (Created or Destroyed)

In the third row, identify whether the Earth's crust is created or destroyed at each type of plate boundary. Note the corresponding effects of plate movement on the lithosphere.

Step 7: Fill in Row 4 - Geologic Process

In the fourth row, provide at least one example of a geologic process or event that occurs as a result of plate movement at each type of boundary. This could include processes like subduction, seafloor spreading, or earthquakes.

Step 8: Fill in Row 5 - Real World Example

In the fifth row, give at least one real-world example of a location where each type of plate movement is demonstrated along a plate boundary. Include the name of the location and its corresponding plate boundary type.

Step 9: Fill in Row 6 - References

In the final row, provide the references for your research in APA format. Include the sources you used to gather information on plate boundaries, plate movements, and related geological processes.

Step 10: Review and Proofread

Review the completed assignment, ensuring that all information is accurate and properly cited. Proofread for any grammatical or spelling errors.

Note: The specific format and layout of the worksheet may vary based on your preference or instructor's instructions. Make sure to follow any specific formatting guidelines provided by your instructor.

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The primary locations for the birth of new stars are in galaxies' spiral arms. The proportion of the galaxy that can participate in star formation increases as more gas and dust become available.

We refer to some spiral galaxies as "barred spirals" because the centre bulge seems extended, like a bar. The spiral arms of the galaxy seem to emerge from the ends of the bar in barred spirals. Elliptical galaxies are round or oval in shape, as their name implies, and have a rather uniform distribution of stars.

The Norma and Cygnus arm, Sagittarius, Scutum-Crux, and Perseus arms are the four principal spiral arms of the Milky Way.

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Answer:

occipital parietal

Explanation:

Hope this helps, plus I took the test

Answer:

One is that atmospheric pressure is dramatically reduced at high altitudes, so a helium balloon expands as it rises and eventually explodes. If you inflate a balloon beyond its limits at room temperature, it will break into small pieces up to about ten centimetres long

Explanation:

1) The velocity of the pin after the collision is 107.4 m/s.

2) The velocity of the two cars as the collision is inelastic is 48.2 m/s.

We know that by the principle of the conservation of linear momentum, the momentum before Collison is equal to the total momentum after collision. Now we have to use this principle in the both questions that we have here.

1) Given that;

Total momentum before collision = Total momentum after collision

(41.7 * 59.1) + (4.17 * 0) = (41.7 * 48.35) + ( 4.17 * v)

We then have;

2464 + 0 = 2016 +  4.17v

2464 - 2016 = 4.17v

v = 2464 - 2016 /4.17

v = 107.4 m/s

2) Given that;

Total momentum before collision = Total momentum after collision

(51.3 * 50.1) + (100 * 47.2) = (100 +  51.3)v

2570 + 4720 = 151.3v

v = 2570 + 4720/151.3

v = 48.2 m/s

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The motorcycle had covered a distance of 16 meters in half the total time.

a) To calculate the acceleration, we can use the formula:

a = (v - u) / t

where a is the acceleration, v is the final velocity, u is the initial velocity (which is 0 since the motorcycle starts from rest), and t is the time.

Given:

u = 0 m/s (initial velocity)

v = ? (final velocity)

t = 4 s (time)

s = 64 m (distance)

Using the equation of motion:

s = ut + 1/2at^2

We can rearrange the equation to solve for acceleration:

a = 2s / t^2

a = 2(64) / (4)^2

a = 128 / 16

a = 8 m/s^2

Therefore, the acceleration of the motorcycle is 8 m/s^2.

b) To find the final velocity, we can use the formula:

v = u + at

v = 0 + (8)(4)

v = 32 m/s

Therefore, the final velocity of the motorcycle is 32 m/s.

c) To determine the time at which the motorcycle had covered half the total distance, we divide the total distance by 2 and use the formula:

s = ut + 1/2at^2

32 = 0 + 1/2(8)t^2

16 = 4t^2

t^2 = 4

t = 2 s

Therefore, the motorcycle had covered half the total distance at 2 seconds.

d) To calculate the distance covered in half the total time, we use the formula:

s = ut + 1/2at^2

s = 0 + 1/2(8)(2)^2

s = 0 + 1/2(8)(4)

s = 0 + 16

s = 16 m

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a) At the application of the brakes, there is a conversion of kinetic to potential energy.

b) When it climbs the second hill, the kinetic energy of the roller coaster is now converted to potential energy.

Let us recall that according to the principle of the conservation of energy, energy can neither be created nor destroyed but it can be transformed from one form to another. In the roller coaster, we can see the principle of energy transformation at work. This is one of the easiest ways that we could use to be able to describe the conservation of energy.

When a break has been applied in the roller coaster, there is a consversion of energy from kinetic energy to potential energy. Recall that the kinetic energy has to do with the energy that is in motion. This is converted to the potential energy of a stationary roller coaster.

Again when the roller coaster goes up a second hill, there is a change from kinetic to potential energy that the roller coaster would possess at the top of the hill.

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The tension in the swing's chain at the instant shown in the image is 441.6 N.

option D

At the bottom of the swing, the girl is traveling at a constant speed, so her acceleration is zero. Therefore, the net force acting on her is also zero.

Thus, we have:

0 = T - mg - mv²/r

where;

At the bottom of the swing, the radius is equal to the length of the chain, so we have:

r = L = 4.0 m

Substituting the values we have:

T = (32 kg)(9.8 m/s²) + (32 kg)(4 m/s)²/4.0 m

Solving for T, we get:

T = (32 kg)(9.8 m/s²) + (32 kg)(4 m/s)²/4.0 m

T = 441.6 N.

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In most cases, the actions of people could be based on distorted feedback.

We know that self perception and self concept is very important. In psychology, it is often very vital to deal with how a person sees himself as this could be the catalyst of the actions of the person. Let us also recall that people do not often act in isolation of the past. This is why some people are said to be the prisoners of the past. They can not just let go of their past failings and mistakes This could have a very bad impact on then future endeavors of such a person.

Let us put this in the context of our discussion. It is common perception that the past of a person could determine the current or future performances of a person. This is common in recruitment exercises.

This implies that when people tend to act, they tend to act based on distorted feedback.

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Answer:

Explanation:

Doubling the distance reduces the gravity force by four.

F = 0.90(9.8/4) = 2.205 = 2.2 N

could also use F = GmM/r²

F = 6.674e-11(0.90)(5.972e24) / (6.4e6 + 6.4e6 )² = 2.1894... = 2.2 N

According to Newton's Third Law of Motion, the force that object A exerts to object B has the same magnitude as the force that object B to object A, but in the opposite direction:

Then, the force exerted by Earth on the Moon has the same magnitude as the force exerted by the Moon on the Earth.

Therefore, the given statement is false.

Answer:

(B) a whole number of wavelengths.

Explanation:

Two beams of coherent light start out at the same point in phase and travel different paths to arrive at point P. If the maximum destructive interference is to occur at point P, the two beams must travel paths that differ by a whole number of wavelengths.

When the resultant effect of the combination of two identical waves result in their annihilation or complete cancellation of the effect of each other, destructive interference takes place. Hence to have two wave sources producing waves that have the same frequency wavelength and amplitude and which are always in phase with each other or have a constant phase difference are said to be Coherent source

Answer:

A, c, d

Explanation:

edge 2022

The actions which will increase friction such as scratching a surface to make it rougher, increasing the size of a flying object, and the adding extra weight to an object. Thus, the correct options are A, C, and D.

Friction is the force which is resisting the relative motion of two solid surfaces, fluid layers, and the material elements which are sliding against each other. There are several types of friction including dry friction, which is a force that opposes the relative lateral motion of two solid surfaces in contact.

The actions which will increase the friction include scratching a surface to make it rougher, increasing the size of a flying object, and the adding extra weight to an object.

Therefore, the correct options are A, C, and D.

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Answer:

Explanation:

Focal length

f

=

10.8

c

m

Object distance

d

o

=

35.7

c

m

Part A:

The image distance would be

1

f

=

1

d

o

+

1

d

i

1

10.8

c

m

=

1

35.7

c

m

+

1

d

i

d

i

≈

15.5

c

m

Part B:

The magnification would be

m

=

−

d

i

d

o

=

−

15.5

c

m

35.7

c

m

≈

−

0.43

Part C:

The image distance if the object distance

d

o

=

5.59

c

m

, would be

1

f

=

1

d

o

+

1

d

i

1

10.8

c

m

=

1

5.59

c

m

+

1

d

i

d

i

≈

−

11.6

c

m

Part D:

Its magnification would be

m

=

−

d

i

d

o

=

−

−

11.6

c

m

5.59

c

m

≈

2.08

The net force on the top charge due to the other two charges is zero, and the charge will remain in equilibrium.

We can use Coulomb's law to calculate the force exerted by one charge on another. Coulomb's law states that the magnitude of the electrostatic force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them.

Mathematically, it can be expressed as:

F = (kq1q2)/r^2

where;

In this case, we have three charges of equal magnitude q placed at the vertices of an equilateral triangle of side length 1. We can calculate the distance between any two charges using the geometry of the equilateral triangle. The distance between any two adjacent charges is 1, and the distance between any two opposite charges is √3.

Let's consider the force exerted on one of the charges, say the one at the top of the triangle, due to the other two charges at the bottom left and bottom right vertices. The distance between the top and bottom left charges is 1, and the distance between the top and bottom right charges is also 1.

Therefore, the magnitude of the force exerted by the bottom left charge on the top charge is:

F1 = (kqq)/1^2 = k*q^2

Similarly, the magnitude of the force exerted by the bottom right charge on the top charge is also k*q^2. Since the two forces are acting in opposite directions along the same line, we can simply subtract them to find the net force:

F_net = F1 - F2 = kq^2 - kq^2

F_net = 0

Therefore, the net force on the top charge due to the other two charges is zero, and the charge will remain in equilibrium.

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Answer:

D

Explanation:

You are boiling more grams for more time because the more water the longer it takes which requires more calories to burn it.