How would the pattern of bright and dark fringes produced in a Young's double-slit experiment change if the light waves coming from both slits had their phases shifted by an amount equivalent to a half wavelength

Arbitrary variable X: The individual car's speed through the intersection, expressed in mph. X is evenly distributed between the range of 11 and 35 mph, inclusive, according to the formula X = Uniform speed (11,35).

A spread metric for a random variable distribution that identifies how far the values deviate from the expected value. The standard deviation of the random variable X is frequently written as or X.

(f) Standard deviation σ:

σ = sqrt[(35 - 11)² / 12] ≈ 6.18

(g) Chance that a car will travel at most 26 mph:

P(X ≤ 26) = (26 - 11) / (35 - 11) = 15 / 24 = 5 / 8

(h) The likelihood that a car will travel between 18 and 22 miles per hour:

P(18 ≤ X ≤ 22) = (22 - 18) / (35 - 11) = 4 / 24 = 1 / 6

Probability questions:

P(19 < X < 56) = 1, since X cannot be greater than 35 mph.

P(X < 19 | X < 56) = P(X < 19) = (19 - 11) / (35 - 11) = 8 / 24 = 1 / 3

P(X = 19 or X = 56) = 0, since X is a continuous random variable.

P(X < 19 or X > 56) = P(X < 19) + P(X > 35) = (19 - 11) / (35 - 11) + (35 - 35) / (35 - 11) = 8 / 24 + 0 = 1 / 3

P(19 ≤ X ≤ 56) = P(X ≤ 56) - P(X < 19) = (35 - 11) / (35 - 11) - (19 - 11) / (35 - 11) = 24/24 - 8/24 = 2 / 3

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The local sidereal time at the observatory located at a longitude of 30° E is approximately 208.75 degrees since Betelgeuse crossed the Greenwich meridian.

To determine the local sidereal time at the given observatory, we need to calculate the time elapsed since Betelgeuse crossed the Greenwich meridian.

First, we convert the right ascension of Betelgeuse from hours and minutes to decimal form. Since 1 hour is equal to 15 degrees of right ascension, and 1 minute is equal to 0.25 degrees, we have:

5 hours 55 minutes = (5 × 15) + (55 × 0.25) = 75 + 13.75 = 88.75 degrees.

Next, we calculate the time difference between Betelgeuse crossing the Greenwich meridian and the current time. Since 1 sidereal hour is equal to 15 degrees of Earth's rotation, and the given time difference is 6.0 sidereal hours, we have:

Time difference = 6.0 × 15 = 90 degrees.

Now, we can calculate the local sidereal time at the observatory by adding the longitude of the observatory (30° E) to the accumulated time difference:

Local sidereal time = 88.75 degrees + 90 degrees + 30 degrees = 208.75 degrees.

Therefore, the local sidereal time at the observatory located at a longitude of 30° E is approximately 208.75 degrees.

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Match the volcano type with its correct

1. Cinder Cone:

Plate Tectonic Setting: Mostly Spreading Ridges, some Mantle Plumes

2. Composite/Stratovolcano:

Plate Tectonic Setting: Subduction Zones (Convergent Margins)

3. Shield Volcano:

Plate Tectonic Setting: Mostly Mantle Plumes, some Spreading Ridges

4. Large Igneous Provinces (LIPs):

Plate Tectonic Setting: Various tectonic settings

Volcano types can be associated with specific plate tectonic settings and magma compositions. Let's match the volcano types with their correct plate tectonic settings and magma compositions:

1. Cinder Cone:

Plate Tectonic Setting: Mostly Spreading Ridges, some Mantle Plumes

Magma Composition: Mafic

Cinder cones are typically small, steep-sided volcanoes that form from the eruption of basaltic magma. They are commonly found in volcanic regions associated with spreading ridges, where tectonic plates are moving apart, or in areas influenced by mantle plumes, such as hotspot volcanism.

2. Composite/Stratovolcano:

Plate Tectonic Setting: Subduction Zones (Convergent Margins)

Magma Composition: Intermediate, varies from felsic to mafic

Composite or stratovolcanoes are characterized by their steep slopes and alternating layers of lava flows and pyroclastic materials. They are commonly found in subduction zones, where an oceanic plate is being subducted beneath  continental plate. The magma composition of these volcanoes varies, ranging from felsic (high silica content) to mafic (lower silica content).

3. Shield Volcano:

Plate Tectonic Setting: Mostly Mantle Plumes, some Spreading Ridges

Magma Composition: Mafic

Shield volcanoes are large, broad, and gently sloping volcanoes that form from the eruption of basaltic magma. They are often associated with mantle plumes, such as those found in hotspot regions, as well as in volcanic areas influenced by spreading ridges.

4. Large Igneous Provinces (LIPs):

Plate Tectonic Setting: Various tectonic settings

Magma Composition: Mafic

Large Igneous Provinces (LIPs) are extensive regions of volcanic and intrusive rock formations that are associated with massive outpourings of mafic magma. They can occur in various tectonic settings, including continental rifts, hotspot regions, and flood basalt provinces.

5. Seafloor Volcanism, Pillow Lava:

Plate Tectonic Setting: Mostly Spreading Ridges

Magma Composition: Mafic

Seafloor volcanism is primarily associated with spreading ridges, where magma wells up and creates new oceanic crust. The lava erupted underwater cools rapidly, forming pillow-shaped structures known as pillow lavas. The magma composition is typically mafic, dominated by basaltic lavas.

These associations between volcano types, plate tectonic settings, and magma compositions provide insights into the geological processes and Earth's dynamics that shape the Earth's surface.

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Right-left = ma, 5-friction=0 ,friction = 5,Work Net = change of kinetic energy,Fx-fx= change of kinetic energy,12 (2) - 5 (2) = change of kinetic energy,24-10 = change of kinetic energy.

When a baseball is thrown at such an angle and is traveling upward, its kinetic energy will decrease because gravity is working against the ball's motion to slow it down and change it from kinetic energy to potential energy.

Because the author's kinetic energy does not change when it is brought to the table, the total mechanical force remains constant.

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Answer:

1). average velocity= displacement/time

= here displacement is zero

= 0/1

= 0 m/s

2). average speed= total distance/time

=2πr/1

=(2×22/7×5/10)/1

22/7

3.14 km/h

hope it helps you

please mark brainliest

Explanation:

Answer:

\(\sf \fbox{speed = 3.14 kmph}\)

Explanation:

Given:

Radius of circular field (r) = 0.5 Km

Time taken to complete one round of field (t)= 1 hour

To find:

Average speed for the whole journey=?

Solution:

To find the average speed we will have to find the actual distance covered in given time, & the actual distance covered would be equal to the

\( \sf \: perimeter \: of \: circular \: field = 2 \pi r \\ \sf 2 \pi r = 2 \times 3.14 \times 0.5 = 3.14 \: km\)

Distance covered in 1 hour is 3.14 km,

\(\small \sf Average \: speed = \frac{Distance}{Time} = \frac{3.14}{1} \\ \small \sf \fbox{speed = 3.14 kmph}\)

\( \small\sf \: Thanks \: for \: joining \: brainly \: community! \)

Light photons always travel at a constant speed (the speed of light) regardless of their energy, while the velocity of electrons is not constant and can vary with their energy.

Light photons and energetic electrons do not have constant velocities independent of energy. Light photons, which are particles of electromagnetic radiation, travel at a constant speed in a vacuum, which is approximately 299,792 kilometers per second (or about 186,282 miles per second) in a vacuum, denoted as the speed of light (c). This speed is a fundamental constant of nature and remains constant regardless of the energy of the photons. In other words, all photons, regardless of their energy, travel at the same speed in a vacuum.

On the other hand, energetic electrons do not have a constant velocity independent of their energy. According to classical physics, the velocity of an electron can vary depending on its energy. In classical mechanics, the kinetic energy of an object is related to its velocity. However, in the microscopic world of quantum mechanics, the behavior of particles such as electrons is described differently.

In quantum mechanics, the concept of particle velocity becomes less straightforward. Instead of velocity, quantum particles are described by wavefunctions, which represent the probability distribution of finding the particle at a certain location. The wavefunction of an electron evolves over time according to the Schrödinger equation, and it does not directly correspond to a well-defined classical velocity.

However, in certain situations, such as in electron beams or particle accelerators, electrons can be accelerated to high energies. In these cases, the energy of the electrons is related to their speed, but it is not a constant relationship. As the energy of the electrons increases, their speed can also increase, but it is not independent of their energy.

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False

The Pressure Gradient Force (PGF) is the force that drives air from areas of high pressure to areas of low pressure. In both a trough and a ridge, the PGF is the same.

However, the winds will not be the same in both features.  

In a trough, the winds tend to move towards the center of the trough, where the air is rising, and this causes convergence and lifting. This upward motion causes a decrease in pressure, leading to a steeper pressure gradient, which means stronger winds. On the other hand, in a ridge, the winds move away from the center of the ridge, where the air is sinking, and this causes divergence and sinking. This sinking motion causes an increase in pressure, leading to a weaker pressure gradient and lighter winds.  

Therefore, assuming the same PGF, the trough will have the faster winds compared to the ridge.

Answer:

a. No. The overall loudness is not proportional to the number of speakers.

b. No, it will not sound 4 times louder.

Explanation:

a. Loudness is the quality of how loud or soft the sound is. Since loudness is proportional to intensity and intensity proportional to the amplitude of the sound, the overall loudness of the sound would not be proportional to the number of speakers.

Since the sound from each speakers adds by superposition, their phases might be different but their amplitudes the same. So, the resultant wave from the four speakers has the same amplitude as the wave from one speaker. And, since loudness is proportional to amplitude, the loudness of the resultant wave is equal to the loudness of each individual speaker.

So, the loudness is not proportional to the number of speakers.

b. No, it will not sound 4 times louder.

This is because loudness is a function of amplitude.

Since the devices are identical and playing the same sound, their amplitudes are the same. They will thus add by superposition to generate a resultant wave which has an amplitude the same as each individual wave.

Since the amplitude of the resultant wave is the same and not an addition of each individual amplitude, the resultant wave does not sound 4 times louder.

Answer:

0.25 N-m

Explanation:

PE=0.5kx^2; PE=potential engery, k=stiffness of spring, x=displacement

=0.5(50)(0.1^2)

=0.25 N-m

import numpy as np:

random_vector = np.random.rand(15)

modified_vector = np.where(random_vector == np.max(random_vector), -1, random_vector)

print("Original Array:", random_vector)

print("Modified Array:", modified_vector)

A NumPy program that creates a random vector of size 15, replaces the maximum value with -1, and prints both the original array and the modified array:

```python

import numpy as np

# Create a random vector of size 15

random_vector = np.random.rand(15)

# Find the maximum value in the vector

max_value = np.max(random_vector)

# Replace the maximum value with -1

modified_vector = np.where(random_vector == max_value, -1, random_vector)

# Print the original and modified arrays

print("Original Array:")

print(random_vector)

print("\nModified Array:")

print(modified_vector)

```

When you run this program, it will generate a random vector of size 15 and display the original array. Then, it will replace the maximum value in the array with -1 and display the modified array.

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Answer:

9.8 meters per second squared

Explanation:

Answer:

9.8 meters per second squared

Explanation:

edge

Answer:

Ans : C

Explanation:

C. The force of gravity acting on the chair

Answer:

D. the force from the chair on the student

Explanation:

Newton's third law: If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.

This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself. 

Hope this helps :)

Answer:

225-Ib person weighs 1000 N

If you stand on one side of a strike-slip fault and the block on the other side of the fault has moved to your left, this is known as a(n)  left lateral fault.

There are several distinct sorts of fault lines, and they are called based on the fault's movement and the fault plane's own direction. These faults may be found all over the world, but the most active and earthquake-producing ones are in the Pacific Ocean's Ring of Fire region.

When you gaze along the length of a fault line, the left side will move toward you while the right side moves away from you. This is referred to as a left-lateral fault.

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(a) red, green, blue. the distance between adjacent bright fringes, also known as the fringe spacing, is inversely proportional to the wavelength of light. Red light has the longest wavelength, followed by green and then blue. Therefore, the fringe spacing is smallest for red light and largest for blue light.

In a Young's double slit experiment, when light passes through two narrow slits and forms an interference pattern on a screen, the fringe spacing is determined by the wavelength of the light. The fringe spacing is given by the equation:

s = λD / d,

where s is the fringe spacing, λ is the wavelength of light, D is the distance between the screen and the double slits, and d is the distance between the slits.

Since the distance D and the distance between the slits d are constant in this experiment, the fringe spacing is solely determined by the wavelength. The longer the wavelength, the smaller the fringe spacing, and vice versa.

Therefore, since red light has the longest wavelength, followed by green and then blue light, the fringe spacing is smallest for red light and largest for blue light. Thus, the correct ranking of the colors by the distance between adjacent bright fringes is (a) red, green, blue.

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Answer:

the answer is B

Explanation:

because i had this question in 8th grade

The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)

The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.

To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).

The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).

In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).

Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.

If co > co_critical, the system is considered overdamped (Option E).

If co = co_critical, the system is considered critically damped (Option D).

If co < co_critical, the system is considered underdamped (Option C).

Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.

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To determine the new force of gravity in the first scenario, we can use the formula for gravitational force:

\(Fg = (G * m1 * m2) / r^2,\)

where G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between their centers.

If we triple the mass of one object and double the distance between their centers, the new force of gravity can be calculated as follows:

New \(Fg = (G * (3m) * m) / (2r)^2.\)

Simplifying this expression, we get:

New Fg = (G * 3m * m) / (4r^2).

Since (3m * m) / (4r^2) is equivalent to (3/4) * (m * m) / (r^2), we can rewrite the equation as:

New \(Fg = (3/4) * (G * m * m) / r^2.\)

Comparing this to the original force of gravity, Fg, we see that the new force is (3/4) times the original force. Therefore, the answer is C) 0.75 Fg.

Regarding the second scenario, for objects in stable orbit, the orbital period is determined by the formula:

\(T = 2π * sqrt(r^3 / (G * M)),\)

where T is the orbital period, r is the distance between the center of the object and the center of the Earth, G is the gravitational constant, and M is the mass of the Earth.

If Satellite B is twice as far from the Earth's center compared to Satellite A, we can say that r_B = 2 * r_A.

Let's compare the orbital periods of the two satellites:

T_B = 2π * sqrt((2r_A)^3 / (G * M)) = 2π * sqrt(8r_A^3 / (G * M)).

T_A = 2π * sqrt(r_A^3 / (G * M)).

Dividing T_B by T_A, we get:

T_B / T_A = (2π * sqrt(8r_A^3 / (G * M))) / (2π * sqrt(r_A^3 / (G * M))).

Simplifying this expression, we find:

T_B / T_A = sqrt(8r_A^3 / (r_A^3)) = sqrt(8) = 2.83.

Therefore, the answer is a) 2.83 times larger.

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When two objects are experiencing gravitational attraction, if you triple the mass of one of the objects and double the distance between their centers, the new force of gravity compared to the old will be 0.75 times the original force (0.75 Fg).The orbital period of Satellite B compared to Satellite A is 2.83 times larger.

This is because the force of gravitational attraction between two objects is inversely proportional to the square of the distance between their centers of mass. If you double the distance between two objects, the force of gravitational attraction decreases by a factor of 4 (2^2). On the other hand, if you triple the mass of one of the objects, the force of gravitational attraction increases by a factor of 3.

Therefore, combining these effects, the new force of gravity will be 3/4 or 0.75 times the original force.

Satellite A and Satellite B are both in stable orbit around the Earth, but Satellite B is twice as far from the Earth's center as Satellite A. The orbital period of Satellite B compared to Satellite A is 2.83 times larger.

This is because the orbital period of an object in circular motion is dependent on the radius of the orbit. The further an object is from the center of the orbit, the longer it takes to complete one full orbit. Since Satellite B is twice as far from the Earth's center as Satellite A, its radius is also twice as large. The orbital period is directly proportional to the radius, so Satellite B's orbital period will be 2.83 times larger than Satellite A's orbital period.

Therefore, the correct statement is:

The new force of gravity compared to the old will be 0.75 Fg.

The orbital period of Satellite B compared to Satellite A is 2.83 times larger.

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Answer:

Jorge wanted to know where the apples were

Explanation:

Ya see, I don't want to explain, cuz I guessed. Also I'm on episode 499 of naruto so yeah

Answer:

B:Jorge wanted to know where the apples were.

Explanation:

The study of radioactivity by Marie Curie marked a significant turning point in the realm of physics and had a significant influence on scientific knowledge. Now let's get into the specifics.

"Radioactivity" is the term Marie Curie coined to describe the phenomenon whereby materials emit radiation that can fog photographic plates. During her uranium investigation in 1896, she made this discovery. This game-changing discovery opened the door for more research into and comprehension of radioactivity, which resulted in important developments in the field of nuclear physics.

Marie Curie's research on radioactivity served as a springboard for additional nuclear physics research and has profound ramifications for other fields of science and medicine. It resulted in improvements in our knowledge of atomic structure, the creation of radiation therapy for the treatment of cancer, and the eventual exploitation of nuclear energy.

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For the given mode values with n > 1, we will calculate the average frequency and uncertainty for each resonance based on the spread in the measured maximum and minimum sustainable frequencies are 33.3 Hz and 47.7 Hz.

For n = 2, the maximum sustainable frequency is 33.6 Hz, and the minimum sustainable frequency is 33.3 Hz. To calculate the average frequency, we take the average of these two values: (33.6 Hz + 33.3 Hz) / 2 = 33.45 Hz. The uncertainty is obtained by taking half of the difference between the maximum and minimum frequencies: (33.6 Hz - 33.3 Hz) / 2 = 0.15 Hz. Therefore, the average frequency for n = 2 mode is 33.45 Hz with an uncertainty of ±0.15 Hz. The fundamental frequency for this mode would be the minimum sustainable frequency, which is 33.3 Hz.

For n = 3, the maximum sustainable frequency is 48.9 Hz, and the minimum sustainable frequency is 47.7 Hz. Following the same procedure, the average frequency is (48.9 Hz + 47.7 Hz) / 2 = 48.3 Hz, and the uncertainty is (48.9 Hz - 47.7 Hz) / 2 = 0.6 Hz. Therefore, the average frequency for n = 3 mode is 48.3 Hz with an uncertainty of ±0.6 Hz. The fundamental frequency for this mode is 47.7 Hz.

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Strange as it may seem, the statement in the question appears to be TRUE.  

-- Before the shot, neither the cannon nor the ball is moving, so their combined momentum is zero.  

-- Since momentum is conserved, we know immediately that their combined momentum AFTER the shot also has to be zero.

-- (20g is rather puny for a "cannonball" ... about the same weight as four nickels. But we'll take your word for it and just do the Math and the Physics.)

-- Momentum = (mass) x (velocity)

After the shot, the momentum of the cannonball is

(0.02 kg) x (100 m/s ==> that way)

Momentum of the ball = 2 kg-m/s ==> that way.

-- In order for both of them to add up to zero, the momentum of the cannon must be (2 kg-m/s this way <==) .

Momentum of cannon = (5 kg) x (V m/s this way <==)

2 kg-m/s this way <== = (5 kg) x (V m/s this way <==)

Divide each side by (5 kg):

V m/s  =  (2/5) m/s this way <==

Speed of recoil of the cannon = -- 0.4 m/s

Answer: Optical test is a test which is used to assess vision and ability of the person to focus on the objects.

Explanation:

The following are the advantages of utilizing plane mirror in optical testing:

1. When a plane mirror is used for testing the image of the test card must be placed at distance equal to the distance of the object.  

2. Larger distance in between the object or test card and viewer is obtained. This can help in determining the exact ability of the eye to focus on objects.

Aldehydes and ketones react with nucleophiles at the carbonyl carbon. In an IR spectrum, the carbonyl absorption of cyclic ketones shifts to higher wavenumbers as the size of the ring decreases and the ring strain increases.

Aldehydes and ketones possess a carbonyl group (C=O) which is highly reactive and susceptible to nucleophilic attack. This reactivity is due to the presence of a polarized carbonyl bond, with the carbon atom being electron-deficient and therefore prone to nucleophilic substitution or addition reactions.

Nucleophiles, such as primary amines, Grignard reagents, or water, can react with aldehydes and ketones at the carbonyl carbon, leading to the formation of various products.

Infrared (IR) spectroscopy is a valuable technique used to analyze the functional groups present in a compound.

The carbonyl group in aldehydes and ketones displays a characteristic absorption band in the IR spectrum, typically appearing between 1680 and 1750 cm-1.

In the case of cyclic ketones, the position of this absorption band shifts to higher wavenumbers (i.e., towards the right on the spectrum) as the size of the ring decreases and the ring strain increases.

This phenomenon is attributed to the increased ring strain in smaller cyclic ketones, which affects the bond length and bond strength of the carbonyl group, resulting in a higher wavenumber for the absorption.

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The coefficient of friction can be calculated by dividing the friction force by the normal reaction force. In this case, the coefficient of friction is 0.64.

Coefficient of friction (μ) is defined as the ratio of the frictional force to the normal reaction force. So, we can use the given formula,
Coefficient of friction (μ) = Frictional force (f)/Normal reaction force (N)

Calculate the friction force by dividing the normal reaction force by the coefficient of friction:
Friction force = Normal reaction force / Coefficient of friction
Friction force = 120 N / 0.64
Friction force = 77.4 N

Calculate the coefficient of friction by dividing the friction force by the normal reaction force:
Coefficient of friction = Friction force / Normal reaction force
Coefficient of friction = 77.4 N / 120 N
Coefficient of friction = 0.64


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The speed of the wind is 17 mph and the speed of the plane in still air is 119 mph.

Let the speed of the plane be x and the speed of the wind be y. Then, the speed of the plane with the wind becomes x + y, while the speed of the plane against the wind is x - y.

The distance traveled with the wind in 3 hours is 408 miles.

Therefore, we can write the equation as:

3(x + y) = 408

Divide both sides by 3:

x + y = 136  .... (1)

The distance traveled against the wind in 4 hours is also 408 miles.

Therefore, the equation can be written as:

4(x - y) = 408

Divide both sides by 4:

x - y = 102  .... (2)

Now we can solve these two equations using the elimination method.

Add equations (1) and (2):

x + y + x - y = 136 + 1022x = 238x = 119 mph

Therefore, the speed of the plane in still air is 119 mph.

Now, substitute this value of x in equation (1):

119 + y = 136y = 17 mph

Therefore, the speed of the wind is 17 mph.

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The correct question is:

A plane flies 408 mi with the wind in 3 hr. The return trip takes 4 hr. What is the speed of the wind and the speed of the plane in still air?

Answer:

the answer is at the BOTTOM OF THEIR QUESTION

Explanation:

IT IS CORRECT BTW