The radius of the circumscribed circle and m∠OAC will be 6.5 cm and 44.8°.
The complete question and missing diagram is given below.
Suppose AC = 5 cm, BC = 12 cm, and mAC = 45.2°. to the nearest tenth of a unit, the radius of the circumscribed circle is cm and m∠OAC.
What is a circle?It is the center of an equidistant point drawn from the center. The radius of a circle is the distance between the center and the circumference.
Suppose AC = 5 cm, BC = 12 cm, and mAC = 45.2°.
Then the radius of the circumscribed circle will be given by Pythagoras theorem.
(2r)² = 5² + 12²
(2r)² = 169
(2r) = 13
r = 6.5 cm
The angle subtend by7 the end points of the diameter at periphery is 90 degrees.
And the measure of the angle ∠OAC will be
∠OAC + 90° + 45.2° = 180°
∠OAC = 44.8°
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If a number x is chosen at random from the numbers -2,-1, 0, 1,2.what is the probability that x2<2.
Answer:
Do you mean 2x<2 or
X <2 or do you mean x²<2
Step-by-step explanation:
If your question is X²<2
Then
Total outcomes=5
Possible outcomes=3(-1,0,1)
Probability of x²<2=3/5
If your question means probability of2x<2
Then
Total outcomes=5
Possible outcomes=3 (-2,-1,0)
Probability of 2x<2=3/5
If your question means x< 2
Then
Total outcomes=5
Possible outcomes=4 (-2,-1,0,1)
Probability of x <2 =4/5
If I have not answered your question
then you can comment and ask me if you have any doubts
Hope this helps
is 7 1/2 a rational number
Answer: Yes
Step-by-step explanation:
Any number that can be written as a fraction, or in other words the ratio between two numbers, is a rational number. It is also a real number as rational numbers are a sub-set of the collection of real numbers
a pie is made up of 8 slices. if 37.5% of the pie slices remain after dinner, how many slices of pie remain after dinner?
Answer:
3 slices
Step-by-step explanation:
37.5% = 0.375
We take
8 times 0.375 = 3 slices
So, 3 slices of pie remain after dinner.
7. Which describes the range for a set of ordered pairs?
A the x-coordinates, or the inputs
B the x-coordinates, or the outputs
C the y-coordinates, or the inputs
D the y-coordinates, or the outputs
Answer:
D
Step-by-step explanation:
The range of the function is all possible y-values of an function or an output.
A researcher is interested in the effect of vaccination (vaccinated vs not vaccinated) and health status (healthy vs with pre-existing condition) on rates of flu. She samples 20 healthy people and 20 people with pre-existing conditions. 10 of the healthy people and 10 of the people with pre-existing conditions are given a flu shot. The other 10 healthy people and people with pre-existing conditions are not given flu shots. All of the subjects are monitored for a year to see if they contract the flu. How many total subjects (N) are there in the study? O 10 20 30 40
In this study, there are a total of 40 subjects. The researcher samples 20 healthy people and 20 people with pre-existing conditions. Out of these, 10 healthy people and 10 people with pre-existing conditions are given a flu shot, while the other 10 from each group are not given flu shots.
To calculate the total number of subjects (N), we add the number of healthy people to the number of people with pre-existing conditions:
N = Number of healthy people + Number of people with pre-existing conditions
N = 20 + 20
N = 40
Therefore, the total number of subjects in the study is 40.
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which is more 0.225 or 0.25
Answer:
0.25
Step-by-step explanation:
The city library has 763,045 books. What is the value of the digit 6 in this
number?
I tried to do this problem but I have to do something like this
Answer:
The 6 is in the ten-thousands place
Step-by-step explanation:
6 written as a ten-thousand is 60,000
please help due by midnight
At michael’s school, 38% of the students have a pet dog and 24% of the students have a pet cat. michael found that 11% of the students had both a pet dog and a pet cat. what is the probability that a randomly chosen student at michael’s school will have a pet dog or a pet cat?
Answer:
0.51 or 51%.
Step-by-step explanation:
If there were 100 students in the school, then 38 have a dog 24 a cat and 11 have both.
So there are 38 - 11 = 27 who only have a dog and 24-11 = 13 who only have a cat.
So total number having a pet = 27+11+13
= 51 students.
So Prob(You will choose a student with a pet) = 51%.
Drawing a Venn diagram would help to answer this and make it clearer.
Answer: answer above me is correct
find the value riven by the problem
Answer:
SM = 13
Step-by-step explanation:
M is the midpoint of ST, then
SM = MT , that is
2x + 3 = 4x - 7 ( subtract 4x from both sides )
- 2x + 3 = - 7 ( subtract 3 from both sides )
- 2x = - 10 ( divide both sides by - 2 )
x = 5
Then
SM = 2x + 3 = 2(5) + 3 = 10 + 3 = 13
Elsa invested $500 in a fund for 4 years and was paid simple interest. The total interest that she received on the investment was $80. As a percentage, what was the annual interest rate of her investment?
The annual interest rate of her investment would be = 4%
Calculation of annual interest rateThe principal amount invested= $500
The period of investment= 4years
The interest received= $80
The interest rate= ?
To calculate the interest rate use the formula,
SI = P×T×R/100
80 = 500 × 4 ×R/100
Make R the subject of formula,
R= 80 ×100/500×4
R= 8000/2000
R= 4%
Therefore, the annual interest rate of her investment would be = 4%.
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Which triangle congruency theorem can b used to prove the triangles are congruent??
Answer:
SSS
SAS
ASA
RHS
AAS COROLLARY
Use inverse operations to solve each equation. Explain each step and identify the property used to reach step.
19 = h/3 − 8
I'd normally know how to do this but I've completely forgotten lol
Answer:
h = 81
Step-by-step explanation:
Simplify
19+8=27 h/3-8+8=h/3
Isolate the variable
27 = h/3
27 x 3 = 81
Original cost $7.50 markup % 50%
Answer:
3.75
Step-by-step explanation:
3.75 because 7.50 × .50 (or 7.50/2) is 3.75
Let X1 and X2 be jointly distributed random variables with finite variances.
a) Show that (E(X1X2))2≤E(X21)E(X22). (Hint: Note that, for any real number t, E((tX1−X2)2)≥0.)
b) Lep rho be the correlation of X1 and X2. Using the inequality of part (a), show that rho2≤1.
a) To prove the inequality (E(X1X2))2≤E(X21)E(X22), we can start by expanding the square on the left-hand side:
(E(X1X2))2 = (cov(X1,X2) + E(X1)E(X2))2
= cov(X1,X2)2 + 2cov(X1,X2)E(X1)E(X2) + (E(X1)E(X2))2
Using the fact that cov(X1,X2) = E(X1X2) - E(X1)E(X2), we can rewrite the above expression as:
E(X1X2)2 - 2E(X1X2)E(X1)E(X2) + E(X1)2E(X2)2
Now, note that for any real number t, E((tX1−X2)2)≥0. This means that the discriminant of the quadratic expression t2E(X1)2 - 2tE(X1X2) + E(X2)2 is non-positive. Therefore,
(E(X1X2))2 - E(X21)E(X22) ≤ 0
which proves the desired inequality.
b) Using part (a), we have:
rho2 = (cov(X1,X2) / (sd(X1)sd(X2)))2 ≤ 1
where sd(X1) and sd(X2) are the standard deviations of X1 and X2, respectively.
Since the standard deviations are positive, we can take the square root of both sides to obtain:
|rho| ≤ 1
Part (a) is proven by expanding the square on the left-hand side and using the fact that E((tX1−X2)2)≥0 for any real number t. Part (b) follows from part (a) and the fact that the correlation coefficient is bounded between -1 and 1.
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Mercury has a mass of 3.30 * 10 23 kg.
Mars has a mass of 6.42 x 10 23 kg.
How many times more massive is Mars than Mercury?
51x 10 23 kg
51
1.95 10 23 kg
1.95
Answer:
Option (4)
Step-by-step explanation:
Mass of Mercury = 3.3 × \(10^{23}\) kg
Mass of Mars = 6.42 × \(10^{23}\) kg
Therefore, ratio of the masses of Mars and Mercury = \(\frac{6.42\times 10^{23} }{3.30\times 10^{23}}\)
= 1.95
\(\frac{\text{Mass of Mars}}{\text{Mass of mercury}}=1.95\)
Mass of Mars = 1.95 × (Mass of Mercury)
Therefore, mass of Mars is .95 times more than Mercury.
Option (4) will be the answer.
ANSWER Q IN PIC ASAP PLS- 50 POINTS
\(\\ \rm\hookrightarrow x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\)
\(\\ \rm\hookrightarrow x=\dfrac{-5\pm\sqrt{25+32}}{4}\)
\(\\ \rm\hookrightarrow x=\dfrac{-5\pm\sqrt{57}}{4}\)
A trapezoid has a height of 10 centimeters. One parallel base has a length of 7 centimeters, and the other parallel base has a length of 13 centimeters.
What is the area of the trapezoid?
Need to Find :- The area of the trapezium.
We are here provided with height and two parallel bases of trapezium and we are interested in finding out the area of the trapezium.
As we know that,
\(\implies\sf \red{Area_{trapezium}= \dfrac{1}{2}\times (sum\ of \ parallel\ sides )\times height}\)
On substituting the respective values,
\(\sf: \implies Area =\dfrac{1}{2}\times (7cm +13cm)\times 10cm \\ \)
\(\sf : \implies Area = 20cm \times 5cm \\\)
\(\sf : \implies \underline{\boxed{\pink{\frak{ Area = 100cm^2}}}}\\\)
\(\underline{\underline{\textsf{ $\therefore$Hence the area of the trapezium is \textbf{100 cm$\bf ^2$ }.}}}\)
Given :
Base = 7 cm and 13 cm.Height = 10 cm.To find :
Area of trapezoid.Solution :
We know,
\({\qquad \dashrightarrow{ \bf{Area_{(Trapezoid)}= \dfrac{1}{2 } \times (b_{1} + b_{2}) \times h} }}\)
Now, Substituting the values :
\({\qquad \dashrightarrow{ \sf{Area_{(Trapezoid)}= \dfrac{1}{2 } \times (7 + 13) \times 10} }}\)
\({\qquad \dashrightarrow{ \sf{Area_{(Trapezoid)}= \dfrac{1}{2 } \times 20 \times 10} }}\)
\({\qquad \dashrightarrow{ \sf{Area_{(Trapezoid)}= \dfrac{1}{2 } \times 200} }}\)
\({\qquad \dashrightarrow{ \bf{Area_{(Trapezoid)}=100} }}\)
Therefore,
The area of the trapezoid is 100 cm² .Will mark brainliest! Please help I have no idea!
Answer:
the decimals should line up.
Answer:
press the right arrow 3 times
Step-by-step explanation:
to properly subtract any numbers the value of the digits need to be in line
If f is an increasing and g is a decreasing function and fog is defined, then fog will be____a. Increasing functionb. decreasing functionc. neither increasing nor decreasingd. none of these
If f is an increasing function and g is a decreasing function, then fog will be a decreasing function (option b).
The behavior of the composite function fog when f is an increasing function and g is a decreasing function. To answer this question, let's examine the properties of fog.
1. f is an increasing function: This means that if x1 < x2, then f(x1) < f(x2).
2. g is a decreasing function: This means that if y1 < y2, then g(y1) > g(y2).
Now, let's analyze the behavior of fog(x):
fog(x) = f(g(x))
Let's consider two points x1 and x2 such that x1 < x2.
Since g is a decreasing function, we have:
g(x1) > g(x2)
Now, as f is an increasing function, when we apply f to both sides, we get:
f(g(x1)) > f(g(x2))
This translates to:
fog(x1) > fog(x2)
Since x1 < x2, and fog(x1) > fog(x2), we can conclude that the composite function fog is a decreasing function.
So, the answer to your question is: If f is an increasing function and g is a decreasing function, then fog will be a decreasing function (option b).
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If angle A is 4x+2 and angle B is 11x, what is the value of x? (round to the nearest tenth)
The value of the x in the vertical angles are the 7/2.
According to the statement
We have to find that the value of the x in the given angles.
So, For this purpose, we know that the
An angle is formed when two straight lines or rays meet at a common endpoint.
From the given information:
If angle A is 4x+2 and angle B is 11x.
Then from the given figure, The given angles are the verticals.
We know that the Verticals angles are equal.
Then
4x+2 = 11x
7x = 2
x = 2/7.
Here the values of the x in the given vertical angles are 7/2.
So, The value of the x in the vertical angles are the 7/2.
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y
20
18
46
14
12
10
8
6
4
2 G
2
D
LL
E
F
4 6 8 10 12 14 16 18 20
X
Complete the steps to find the area of the kite.
What is GE?
Square root of
What is DF?
✓units
Square root of
units
What is the area of the kite to the nearest unit?
square units
The lengths of the diagonals are:
GE = 8√5 units
DE = 4√5 Units
Area = 80 sq. units
How to find the distance between two coordinates?We have been given an image of a kite on coordinate plane.
To find the length of GE we will use distance formula:
Distance = √[x₂ - x₁)² + (y₂ - y₁)²]
Substituting coordinates of point G and E in above formula we will get,
GE = √[16 - 0)² + (8 - 0)²]
GE = √(256 + 64)
GE = √320
GE = 8√5 units
Similarly we will find the length of diagonal DF using distance formula.
DF = √[14 - 10)² + (2 - 10)²]
DE = √(16 + 64)
DE = √80
DE = 4√5 Units
Area of kite is given by the formula:
Area = (p * q)/2
where p and q are diagonals of kite.
Thus:
Area = ( 8√5 * 4√5)/2
Area = 80 sq. units
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You are an office manager, and you need to buy a new
printer. You are looking at two options for the printer
model you like. A local electronics store offers the
model for $499.99 plus a 5% sales tax. An online store
offers the same model for $549.99 plus $22.95 for
shipping and no sales tax. You plan to use a coupon
for the online store for 10% off the purchase price
before the shipping fee.
What will be the final price of the better deal?
$472.49
$515.65
$517.94
$524.99
$572.94
First let's calculate the final price at the electronic store.
499.99*(1+0.05)≈524.99
Now let's calculate the final price online
(549.99+22.95)*(1-0.1)≈515.65
If we compare the two we can see that the online price is cheaper at around 515.65 dollar therefore the second choice is correct.
I hope this helped if you have any questions please ask!
Point (∃xP(x)∧Q(x))≡∃x(P(x)∧Q(x)) Q6 1 Point Which rule of ND justifies P(0) from ∀xP(x) ? There is no rule of ND that justifies this. (∀E) (∀I) (∃E) (∃I)
The (∃E) rule is used to infer P(0) from ∀xP(x), and this conclusion is supported by the existence of an object that satisfies the predicate.
The rule of natural deduction that justifies P(0) from ∀xP(x) is the existential elimination (∃E) rule. This rule allows us to infer a particular instance of an existential quantification based on the existence of an object that satisfies the predicate. In this case, since we have the universal quantification ∀xP(x), we can use (∃E) to conclude P(0) by substituting 0 for x. By doing so, we have shown that there exists an object, namely 0, that satisfies the predicate P(x). Therefore, (∃E) justifies the statement P(0) from the given universal quantification.
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Which of the following is not a factor in capacity planning?
a) approach used to measure capacity
b) economies of scale
c) prepare to deal with capacity in "chunks"
d) proximity to suppliers
e) identify the best operating level
The option that is not a factor of capacity planning is the option d
d) Proximity to suppliers
What is capacity planning?The process of ascertaining the production capacity an organization needs in order to meet changing demand for the products and services of the organization is known as capacity planning.
The factors considered in capacity planning are factors which include the capacity measurement approach, the economies of scale, preparedness to deal with the capacity in chunks, and activities towards identifying the best operating level.
Therefore, from the listed options, the option that is not a factor in capacity planning is the option (d) proximity to suppliers
Other aspects of the operations of an organization, such as supply chain management and logistics can be affected by the proximity of suppliers, but the proximity of suppliers is not directly linked to the determination process for the production capacity needed to meet the market demand.
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What is the cosine of the 30゚ angle in the cosine of the 60゚ angle
Answer:
cos 30 = √3 /2
cos 60 = 1/2
Explanation:
The cosine ratio for 30 degrres gives
\(\cos 30=\frac{4\sqrt[]{3}}{8}\)which simplifies to give
\(\cos 30=\frac{\sqrt[]{3}}{2}\)The cosine ratio for 60 degrees gives
\(\cos 60=\frac{4}{8}\)simplifying the right-hand side gives
\(\cos 60=\frac{1}{2}\)which is our answer!
Hence, the correct answer choices are
cos 30 = √3 /2
cos 60 = 1/2
simply this number 15min :3hours
Answer:
1 min : 12 min
Step-by-step explanation:
To simplify the given ratio, convert both to the same unit of time.
1 hour = 60 minutes
3 hours = 3 x 60 minutes
= 180 minutes
So that,
15 min : 3 hours = 15 min : 180 min
divide through by 15 to have;
15 min : 180 min = 1 min : 12 min
Thus the simplified form of the number give is 1 min : 12 min.
Chelsea shows her work in finding the solution to 4x−5=2 3(x−3). After checking her answer in the original equation, she found that it did not work. Where did she make a mistake?.
we can continue solving the equation correctly and find the accurate value for x. identify where Chelsea made a mistake, let's analyze the equation and her solution step by step:
Given equation: 4x - 5 = 23(x - 3)
Chelsea's solution:
Step 1: Distribute the 23 to the terms inside the parentheses:
4x - 5 = 23x - 69
Step 2: Simplify the equation by subtracting 23x from both sides:
4x - 23x - 5 = -69
Step 3: Combine like terms:
-19x - 5 = -69
Step 4: Add 5 to both sides to isolate the variable:
-19x = -64
Step 5: Divide both sides by -19 to solve for x:
x = -64 / -19
x ≈ 3.3684
Chelsea's mistake occurred in step 4. Instead of adding 5 to both sides, she subtracted it. The correct equation should be:
-19x + 5 = -69
By making this correction, we can continue solving the equation correctly and find the accurate value for x.
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Suppose the length and width of the box double. Does the surface area S double? Complete the explanation. (ignore the options i put at the bottom they were incorrect
Answer:
No, the surface area didn't double. It more than doubled (closer to tripled).
=====================================================
Explanation:
L = 24 = lengthW = 27 = widthH = 10 = heightS = surface area of the box
S = 2*(LW + LH + WH)
S = 2*(24*27+24*10+27*10)
S = 2316 square cm
-----------------
Let's double the values of L and W
L = 24 doubles to L = 48W = 27 doubles to W = 54Keep H = 10 the same as before.Now let's recompute the surface area
S = 2*(LW + LH + WH)
S = 2*(48*54+48*10+54*10)
S = 7224 square cm
-----------------
Summary so far:
The original box has surface area 2316 sq cmThe larger box has surface area 7224 sq cmDivide the larger value over the smaller to find that 7224/2316 = 3.119 approximately.
Since this result is not 2, it means the surface area did not double. It more than doubled. It would be more accurate to say the surface area roughly tripled.
Side note: if you were to double the length, width, and height, then the surface area would quadruple.
What equations go where? One solution, no solution, infinite solution. Picture attached of problem. Plsss
Help
Answer:
see below
Step-by-step explanation:
1. x-9=-17-simplifies to a single solution-one solution
2.x+4=4+x-same thing on each side-infinite solutions
3. 0.4x=0.4x+2-same variable coefficient plus a number-no solutions
4. 5x=5x-3-same as above-no solutions
5. 5x=2-variable on one side, constant on another-one solution
6. x-5=x-5-same thing on each side-infinite solutions
7.3x=3x-same thing as above-infinite solutions
8.8x-10=8x-same coefficient for each variable plus a constant-no solutions
Answer:
One solution:
x + 9 = -17
5x = 10
No solution:
0.4x = 0.4x +2
5x = 5x - 3
8x - 10 = 8x
Infinite solutions:
x + 4 = 4 + x
x - 5 = x - 5
3x = 3x
Step-by-step explanation:
x + 9 = -17
- 9 -9
x = -26 (one solution)
x + 4 = 4 + x
- 4 - 4
x = x (infinite solutions)
0.4x = 0.4x +2
-0.4x -0.4x
0 = 2 (no solution)
5x = 5x - 3
-5x -5x
0 = -3 (no solution)
5x = 10
/5 /5
x = 5 (one solution)
x - 5 = x - 5
+ 5 + 5
x = x (infinite solutions)
3x = 3x (infinite solutions)
8x - 10 = 8x
+ 10 + 10
8x = 8x + 10
-8x -8x
0 = 10 (no solution)
Hope this helps!