How Many milligrams are in 94.2g?

When we have an ionic compound, we have elements with different charges, cations are known for the + charges being carried by them, in this group of elements we found the metals. Within this group of elements, we have monovalent cations (Cs+ for example), divalent cations (Ca2+), but in the transition metals we find multivalent or polyvalent ions, like Fe, that can be Fe2+, Fe3+, and Fe4+, so these elements are able to carry different charges as cations, more examples of these multivalent ions are Copper, Zinc, Manganese, and many more.

Answer:

The correct option is;

X, W, Y, Z

Explanation:

The parameters given are;

Spring (S),         Spring Constant (N/m)

      W,                   24

      X,                    35

      Y,                    22

      Z,                    15

The equation for elastic potential energy, \(E_e\), is \(E_e = 0.5 \times k \times x^2\)

The above equation can also be written as \(E_e =\dfrac{1}{2} \times k \times x^2\)

Where:

k = The spring constant in (N/m)

x = The spring extension

Therefore, since the elastic potential energy, \(E_e\), of the spring is directly proportional to the spring constant, k, we have the springs with higher spring constant will have higher elastic potential energy, \(E_e\), therefore the correct order is as follows;

X > W > Y > Z

Answer:

B. X, W, Y, Z

Explanation:

The gas X is C₃H₈, which is propane.

  Organic substances known as hydrocarbons only produce CO2 and water when they burn. So, by the hit and trial method of x and y in the general formula of the reaction mentioned, we get propane.

  A three-carbon alkane, propane has the chemical formula C3H8. At room temperature and pressure, it is a gas, but it can be compressed into a liquid for transportation. It is a by-product of the processing of natural gas and the refining of petroleum and is frequently used as fuel.

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The diffusion rate of carbon dioxide out of the shell can be calculated using Fick's first law of diffusion, which states that the diffusion rate is proportional to the diffusion coefficient, the surface area, and the concentration difference.

First, we need to calculate the surface area of the shell:

The diameter of the shell is given as 4.5 cm, so the radius is half of that, which is 2.25 cm.

The surface area of a sphere is given by the formula A = 4πr^2.

Plugging in the radius, we get A = 4π(2.25 cm)^2 = 63.59 cm^2.

Next, we need to calculate the concentration difference:

The carbon dioxide concentration inside the shell is given as 2.0 atm, while the concentration outside the shell is essentially zero. The concentration difference is therefore 2.0 atm - 0 atm = 2.0 atm.

Now we can calculate the diffusion rate using the formula diffusion rate = diffusion coefficient * surface area * concentration difference. Plugging in the given values, we get diffusion rate = (2.5×10^(-12) m^2/s) * (63.59 cm^2) * (2.0 atm) = 3.18×10^(-9) cm^3·atm/s.

To convert this to molecules per second, we need to use Avogadro's number, which is 6.022×10^23 molecules/mol. Since carbon dioxide has a molar mass of approximately 44 g/mol, we can convert the diffusion rate to molecules per second by multiplying it by Avogadro's number and dividing by the molar mass of carbon dioxide. The molar mass of carbon dioxide is 44 g/mol = 44000 mg/mol.

diffusion rate (in molecules/s) = (3.18×10^(-9) cm^3·atm/s) * (6.022×10^23 molecules/mol) / (44000 mg/mol) = 4.34×10^14 molecules/s.

So, the diffusion rate of carbon dioxide out of the shell is 4.34×10^14 molecules/s.

For Part B, we can use the diffusion rate from Part A to calculate the time it takes for the carbon dioxide pressure to decrease to 1.0 atm.

The initial pressure is 2.0 atm and the final pressure is 1.0 atm.

Since the rate is constant, we can use the formula time = (final pressure - initial pressure) / diffusion rate.

Plugging in the values, we get time = (1.0 atm - 2.0 atm) / (4.34×10^14 molecules/s) = -2.3×10^(-15) s.

To convert this to hours, we divide by 3600 s/hour and take the absolute value to get time = |(-2.3×10^(-15) s) / (3600 s/hour)| = 6.4×10^(-19) hours.

So, it will take approximately 6.4×10^(-19) hours for the carbon dioxide pressure to decrease to 1.0 atm, assuming a constant diffusion rate.

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Answer:

Increase

Explanation:

Fe + CuSO4 - - > Fe2(SO)3 + Cu

If concentration of Fe increases, it will increase the frequency of collisions between the two reactants. Therefore the amount of Cu will also increase.

Answer:

here

Explanation:

This is the electron configuration of the element carbon.

The product containing copper after the reaction of CuSO₄(aq) and Zn is Cu(s). In this reaction, zinc (Zn) displaces copper (Cu) from copper sulfate (CuSO₄), resulting in the formation of solid copper.

The reaction between CuSO₄ and Zn is a single replacement reaction, also known as a displacement reaction. In this type of reaction, a more reactive element (Zn) displaces a less reactive element (Cu) from its compound (CuSO₄).

During the reaction, zinc atoms lose electrons to form Zn²⁺ ions, while copper ions gain electrons to form copper atoms. The copper atoms then bond together to form solid copper. The resulting copper is a reddish-brown metal that can be observed as a solid in the product.

Therefore, the correct option from the given choices is "cu(s)".

It is important to note that Cu(OH)₂(s), Cu(NO₃)₂(aq), CuO(s), and none of these are not the correct products formed in this reaction.

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Answer:

B.Revisionary

Explanation:

Revisionary movement usually use legal channels to seek change

A movement that  tries to improve a part of society, usually through legal methods is a  revisionary movement.

A revisionary movement always target the revision or improvement of the whole or part of the society. Many revisionary movements across the world are calling for different types of social changes such as gender equality and equal access to education.

Hence, a movement that  tries to improve a part of society, usually through legal methods is a revisionary movement.

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Answer:

I am working on science rn 2

Answer:

The answer is option B.

Hope this helps you

Answer: O2                                                                                                                  

Explanation:

Addition of acid to an equilibrium solution of a slightly soluble ionic compound will increase the solubility of the compound if: the anion is a weak base.

According to the Bronsted-Lowry theory of acids and bases, an acid is defined as a proton donor while a base is defined as a proton acceptor. If a strong acid is added to a slightly soluble ionic compound, then it will break down into its constituent ions.

Therefore, if the anion is a weak base, it will be able to react with the acid, forming a conjugate acid that is more soluble than the original ionic compound. This will increase the solubility of the compound.

In summary, if the anion is a weak base, the addition of acid to an equilibrium solution of a slightly soluble ionic compound will increase the solubility of the compound.

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The availability of energy has the greatest impact on the number of molecules formed in a hydrogen ion pump.

In a hydrogen ion pump, the factor that most likely has the greatest effect on the number of molecules is the rate of energy supply or availability. If there is a high energy supply, more small molecules can be joined together to form larger ones. Conversely, if the energy supply is limited or insufficient, the rate of molecule formation will be lower, resulting in fewer molecules being produced. Therefore, the availability of energy plays a crucial role in determining the extent of molecule formation in a hydrogen ion pump.

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Answer:

6 gallons of gasoline for $14.45 is the best price

Explanation:

26.29/11=2.39 $ per gallon

14.45/11=1.31 $ per gallon

B. 50kj, is the energy liberated from the air or the walls of the container. The quantity of heat emitted by one component in a closed system equals the amount of heat absorbed by other components. Released Q equals absorbed Q.

Energy cannot be generated or destroyed, according to the definition of the law of conservation of energy, but it may be transformed from one form into another. The environment must release the same amount of heat that the chemical reaction absorbs into the surrounding space. The total heat emitted by the environment is equal to the total heat absorbed during the chemical process. Heat transfer's overall net change is zero. The energy consumed by the chemical processes is equivalent to 50 Kj, thus the energy released from the air, or the container walls would be equal to that.

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Complete Question:

a chemical reaction is carried out in a closed container. the energy absorbed by the chemical reaction is 50 kj. what is the energy liberated from the air or the walls of the container?

A. 25kj

B. 50kj

C. 75kj

D. 100kj

The magnitude of the force acting on the body is 4000 Newtons.

To find the magnitude of the force, we can use Newton's second law of motion, which states that the force applied to an object is equal to the product of its mass and acceleration.

The given information includes the mass of the body (80 kg) and the resulting velocity (10 m/s). However, since the time duration (0.2 seconds) is also provided, we can use it to calculate the acceleration of the body.

The formula to calculate acceleration is:

Acceleration = Change in Velocity / Time

The change in velocity can be calculated by subtracting the initial velocity (which is 0 m/s as the body is at rest) from the final velocity:

Change in Velocity = Final Velocity - Initial Velocity

Change in Velocity = 10 m/s - 0 m/s

Change in Velocity = 10 m/s

Now, we can calculate the acceleration:

Acceleration = Change in Velocity / Time

Acceleration = 10 m/s / 0.2 s

Acceleration = 50 m/s²

Finally, we can calculate the magnitude of the force using Newton's second law:

Force = Mass x Acceleration

Force = 80 kg x 50 m/s²

Force = 4000 N

Therefore, the magnitude of the force acting on the body is 4000 Newtons.

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Answer:

Chemical bonds

Explanation:

Because it has an image of atoms being held together by chemical bonds.

Answer:

The correct answer is - 2Cu + 4HBr → 2H[CuBr2] + H2

Explanation:

Copper (Cu) and hydrobromic acid (HBr), which is a dissolved form of hydrogen bromide in the water, react and produce hydrogen dibromidocuprate (I) and hydrogen molecules.

The complete and balanced equation is -

2Cu + 4HBr → 2H[CuBr2] + H2

This reaction takes place in the medium of ester. Copper is in the suspension form in this reaction.

Thus, the correct answer is - 2Cu + 4HBr → 2H[CuBr2] + H2

As per the given problem, 400 kg of a solution containing 35 wt % acetic acid in water is contacted with 400 kg of pure isopropyl ether. We need to calculate the amounts and compositions of the extract and raffinate layers, and the percentage of acetic acid removed.

Using the lever-arm rule, we can determine the amounts of the extract and raffinate layers. Since the two solvents are being mixed in equal quantities, the total weight of the system is 800 kg. The lever arm for the isopropyl ether is 1, and for the acetic acid/water solution is (0.35/0.65) = 0.538. Therefore, the weight of the extract can be calculated as (1/1.538) × 400 kg = 259.97 kg, and the weight of the raffinate can be calculated as (0.538/1.538) × 400 kg = 140.03 kg.

To determine the compositions of the extract and raffinate layers, we use the lever-arm rule and the equilibrium data from Appendix A.3. For the extract layer, the lever-arm for isopropyl ether is 1, and for acetic acid, it is (0.90/0.10) = 9. Therefore, the weight percent of acetic acid in the extract layer is (1/10) × 35% = 3.5%. Similarly, for the raffinate layer, the lever arm for isopropyl ether is 0, and for acetic acid, it is (0.04/0.96) = 0.042. Therefore, the weight percent of acetic acid in the raffinate layer is (0.042/1.042) × 35% = 1.48%.

To determine the percentage of acetic acid removed, we need to calculate the amount of acetic acid that remains in the raffinate layer. The weight of acetic acid in the original solution is 0.35 × 400 kg = 140 kg. The weight of acetic acid in the raffinate layer is 0.0148 × 140.03 kg = 2.07 kg. Therefore, the amount of acetic acid removed is 140 kg - 2.07 kg = 137.93 kg. The percentage of acetic acid removed is (137.93 kg/140 kg) × 100% = 98.52%.

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The actual magnitude of positive charge that is experienced by an electron in an atom is called nuclear charge. This charge determines the electrostatic attraction between the electrons and the nucleus.

Nuclear charge refers to the electric charge that the nucleus of an atom carries. This charge is equal in magnitude to the number of protons in the nucleus. Because the protons are positively charged, the nuclear charge is positive as well.

The nuclear charge determines the attraction of electrons towards the nucleus. Electrons move around the nucleus, attracted by the positively charged nucleus. The electrons are also repelled by the negatively charged electrons in the atom. The balance between attraction and repulsion determines the behavior of electrons in an atom.

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Answer:

313.2 g of \({K_{2} }S O_{4}\)  must be added to 1.20 liters of water to produce a 1.50 molar solution.

Explanation:

What is molarity?

According to the given question,

Solution :

∴ Number of moles of solute, here, \({K_{2} }S O_{4}\)

= molarity x volume of the solution

= 1.20 x  1.50 = 1.8

∴ Mass of 1.8 moles of \({K_{2} }S O_{4}\) = 1.8 x molar mass of   \({K_{2} }S O_{4}\)  

Now the molar mass of \(K_{2} SO_{4}\)

= (Gram atomic mass of K x 2) + (Gram atomic mass of S) + (Gram atomic mass of O x 4)

= (39x2) + 32 + (16 x 4) g

= 174 g.

∴ Mass of 1.5 moles of \({K_{2} }S O_{4}\)

= 1.8 x molar mass of   \({K_{2} }S O_{4}\)  

= 1.8 x 174 g

= 313.2 g.

Thus, 313.2 g of \({K_{2} }S O_{4}\)  must be added to 1.20 liters of water to produce a 1.50 M solution.

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Answer:

assalam o aalaikum

Explanation:

o

90

180

270

360 x

-1

Given that 0 find the value of a and the value of b.

(2 marks)

.

The salt with the lowest molar solubility in water is Fe(OH)2.

compare the given Ksp values of each salt, as Ksp is a measure of solubility. The salt with the smallest Ksp value will have the lowest molar solubility in water.

Here are the Ksp values of each salt:

a. Ni(OH)2 (Ksp = 2.0 × 10^-15)
b. Fe(OH)2 (Ksp = 8 × 10^-16)
c. PbI2 (Ksp = 6.5 × 10^-9)
d. CaCO3 (Ksp = 3.8 × 10^-9)
e. AgBr (Ksp = 5.0 × 10^-13)

Comparing these values, we can see that the salt with the lowest Ksp value is Fe(OH)2 (Ksp = 8 × 10^-16).

Therefore, the salt with the lowest molar solubility in water is Fe(OH)2.

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The salt with the lowest molar solubility in water among the given options is Ni(OH)₂ (Ksp = 2.0 × 10⁻¹⁵).

How does the solubility product constant (Ksp) determine the molar solubility of a salt?

The solubility product constant (Ksp) is an equilibrium constant that represents the degree of solubility of a salt in water. It is determined by the concentrations of the dissociated ions in the equilibrium equation for the salt's dissolution. A lower value of Ksp corresponds to a lower molar solubility of the salt.

To determine the salt with the lowest molar solubility, we compare the given Ksp values. The salt with the lowest Ksp will have the lowest molar solubility, indicating that it is less soluble in water.

In this case, the salt Ni(OH)₂ has the lowest Ksp value of 2.0 × 10⁻¹⁵ among the given options.

Therefore, Ni(OH)₂ has the lowest molar solubility in water.

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Answer:

\(1.7137\ \text{mg/L}\)

Explanation:

Chlorine gas available = 27 lbs = \(27\times 453.59237=12247\ \text{g}\)

Amount of water used each day = 750000 gal = \(750000\times3.785411784=2839058.84\ \text{L}\)

Rate at which chlorine gas used = 2.6 mg/L

Chlorine gas used

\(2839058.84\times 2.6\times 10^{-3}=7381.55\ \text{g}\)

Residual content of chlorine = \(12247-7381.55=4865.45\ \text{g}\)

Concentration of the residual chlorine is given by

\(\dfrac{4865.45}{2839058.84}=0.0017137\ \text{g/L}=1.7137\ \text{mg/L}\)

Concentration of the residual chlorine is \(1.7137\ \text{mg/L}\).

The mole fraction of the sulfur dioxide gas present in a falsk which contains 21.8 g of chlorine gas and 47.8 g of sulfur dioxide gas is 0.708.

Mole fraction of any substance will be calculated by dividing the moles of desired substance by the total moles of the species present in that sample.

Moles can be calculated as:

n = W/M, where

W = given mass

M = molar mass

Moles of 21.8g of chlorine gas = 21.8g / 71g/mol = 0.307mol

Moles of 47.8g of sulphur dioxide gas = 47.8g / 64g/mol = 0.746mol

Mole fraction of sulphur dioxide gas = 0.746 / 0.746+0.307 = 0.708

Hence required mole fraction of sulphur dioxide gas is 0.708.

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Answer:

2+

Explanation:

Apex lolz

Answer:

Density

Explanation:

Density is a physical property that describes the relationship between mass and volume. Density is the amount of matter in a given space, or volume.

Answer:

The relationship between the mass and volume of a substance is known as its density. Density is defined as the mass of a substance per unit volume. In other words, it is a measure of how much matter is packed into a given space. The density of a substance is determined by dividing its mass by its volume. For example, if a substance has a mass of 10 grams and a volume of 2 cubic centimeters, its density would be 10 grams / 2 cubic centimeters = 5 grams/cubic centimeter. Density is an important physical property of substances, as it can be used to identify and classify different materials and understand their behavior.

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Explanation:

Answer:

The new pressure will be

1000 L