how many atoms are there

Answer:

The acceleration is a negative as the ball is now moving in the opposite direction.

The velocity would decrease as the ball moves upward

Acceleration remains constant and velocity is negative and decreasing as per the given scenario. The correct option is B.

In mechanics, acceleration is defined as the rate of change of an object's velocity with respect to time.

Vector quantities are accelerations. The orientation of an object's acceleration is determined by the orientation of its net force.

Velocity is the directional speed of a moving object as an indication of its rate of change in position as observed from a specific frame of reference and measured by a specific time standard.

The rate of displacement of an entity known as its velocity. It is measured in meters per second. The rate of change in velocity of an object is defined as acceleration.

According to the scenario, acceleration remains constant while velocity decreases and is negative.

Thus, the correct option is B.

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Your question seems incomplete, the missing options are:

The average velocity of the travelling circus van is 12.64km/h.

As we already know, the directions east[E] and west[W] are opposite to each other, north[N] perpendicular to both of them.

We know, average velocity V,

V = total displacement/total time taken

Let us assume the situation on a coordinate plane, and say that the van started from origin,

The circus van first goes to the east direction and travels 50Km. After that, it travels 40Km back,

So, he travels straight 50Km and then return back 40Km, so now, his current position is 10Km in the east direction,

Now, from the point in 10km east, he travels 30km north,

Now, his current and final position is 10km east and 30km north,

His initial position was 0km in east and 0km in north,

So, his total displacement D is,

D² = (10)²+(30)²

D² = 100+900

D² = 1000

D = 10√10 Km.

Total time T taken by him is,

T = 1+1+.05

T = 2.5 hours,

Putting the values, the average velocity V is,

V = D/T

V = 10√10/2.5

V= 12.64 km/h

So, the average velocity is 12.64km/h.

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Answer:

Mandible.

Explanation:

The mandible in the bone that allows you to open and close your mouth, otherwise known ad the jawbone.

Answer:

mandible

Explanation:

which is also the lower jaw and it allows the mouth to open and close

hope i helped

Speed = Distance/ time. Kinetic energy is 1/2 mv2. The kinetic energy is 16.2 J.

Thus, A fundamental idea in physics known as kinetic energy quantifies the work done by an object as a result of its motion. It is essential to our comprehension of many commonplace actions like walking, jumping, and throwing as well as more complicated events like falling.

We shall examine the definition, units of measurement, examples, and transformations of the notion of kinetic energy in this article. Additionally, we will develop the kinetic energy equation and look at how it relates to other types of energy.

We'll also look at the many kinds of kinetic energy and talk about the difference between kinetic and potential energy.

Thus, Speed = Distance/ time. Kinetic energy is 1/2 mv2. The kinetic energy is 16.2 J.

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Answer:

REVIEWS

Wing-Kuen Ling, in Nonlinear Digital Filters, 2007

Controllability and observability

For a continuous time system, assume that x(0) = 0. ∀x1, if ∃t1 > 0 and u(t) such that x(t1) = x1, then the continuous time system is said to be reachable. Similarly, for a discrete time system, assume that x(0) = 0. ∀x1, if ∃n1 > 0 and u(n) such that x(n1) = x1, then the discrete time system is said to be reachable. For a continuous time system, if ∀x0, x1, ∃t1 > 0 and u(t) such that x(0) = x0 and x(t1) = x1, then the continuous time system is said to be controllable. Similarly, for a discrete time system, if ∀x0, x1, ∃n1 > 0 and u(n) such that x(0) = x0 and x(n1 = x1, then the discrete time system is said to be controllable. For LTI systems, the set of reachable state is R(|BAB… AnB|), where R(A) is defined as the range of A, that is R(A) = {y : y = Ax}. Also, the LTI systems are controllable if and only if R(A) = Rn Or in other words, rank(|BAB… AnB|) = n.

The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.

Given:

Object height (h) = 5 cm

Focal length of the convex lens (f) = 10 cm

Object distance (u) = 15 cm (positive since it's on the same side as the incident light)

To determine the nature, position, and size of the image, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the given values:

1/10 = 1/v - 1/15

To simplify the equation, we find the common denominator:

3v - 2v = 2v/3

Simplifying further:

v = 30 cm

The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.

To find the magnification (M), we use the formula:

M = -v/u

Substituting the values:

M = -30 / 15 = -2

The magnification is -2, indicating that the image is inverted and twice the size of the object.

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Answer:

The speed will be "872.7 m/s".

Explanation:

As we know,

At room temperature, speed of sound will be:

e = 345 m/s

In metal bar, sound's speed will be:

= \(v>e\)

Let,

The pulse travel in time "t", then

⇒ \(t=\frac{4.8}{v}\)

⇒ \(t+8.4\times 10^{-3}=\frac{4.8}{345}\)

⇒ \(t+8.4\times 10^{-3}=0.01391\)

⇒                      \(t=5.5 \ ms\)

hence,

The speed of sound will be:

⇒ \(v=\frac{4.8}{t}\)

⇒    \(=\frac{4.8}{5.5}\times 10^3\)

⇒    \(=872.7 \ m/s\)

The force constant of the spring is  866.7 N/m.

In order to fix the question that we have here we have to look at the Hooke's law. From the Hooke's law we have to note that the force that is causing the string to become expanded is proportional to the extension of the spring as long as the elastic limit has not been exceeded.

Now we know that the Hooke's law would refer to the force and the extension and that is what we would need to be able to solve in order to get the force constant as we have been asked in the problem that we have here.

Thus;

F = Ke

F = force

K = force constant

e = extension

Then;

K = F/e

K = 26 N/3 * 10^-2 m

K = 866.7 N/m

From the calculation that we have done in the lines above, we have obtained the force constant to be about  866.7 N/m.

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The exploded star is called a black hole.

The time horizon of the black hole is an area of spacetime where gravitational pull is so intense that nothing, not even light or other electromagnetic waves, have the energy to pass through it.

It is believed that the first black holes appeared shortly after the big bang, in the beginning of the cosmos. When the core of an extremely massive star is collapsed on itself, stellar black holes are created.

A supernova, also known as an exploding star, is also brought on by this collapse and sends a portion of the star into space.

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Answer: the radius of the circular path is approximately 1637.58 meters.

Explanation:

The centripetal force acting on the airplane is provided by the component of the gravitational force that acts towards the center of the circular path. This component is given by:

F_c = m * g * tan(banking angle)

Where:

F_c is the centripetal force

m is the mass of the airplane

g is the acceleration due to gravity

tan(banking angle) is the tangent of the banking angle

Now, the centripetal force is also given by the formula:

F_c = (m * v^2) / r

Where:

v is the speed of the airplane

r is the radius of the circular path

Equating the two expressions for F_c, we get:

(m * g * tan(banking angle)) = (m * v^2) / r

Canceling out the mass (m) on both sides of the equation, we have:

g * tan(banking angle) = v^2 / r

Solving for r, we get:

r = (v^2) / (g * tan(banking angle))

Substituting the given values:

v = 400 km/h = 400,000 m/h

g = 9.8 m/s^2

banking angle = 20°

Converting the speed to m/s:

v = 400,000 m/h * (1/3600) h/s = 111.11 m/s

Converting the banking angle to radians:

banking angle = 20° * (π/180) rad/° = 0.3491 rad

Now, substituting the values into the formula:

r = (111.11^2) / (9.8 * tan(0.3491))

r ≈ 1637.58 meters

Therefore, the radius of the circular path is approximately 1637.58 meters.

Answer:

answer below

Explanation:

Displacement of the student is 739 m due North and it takes 162 s.

We need to find the student's average velocity. Using formula of velocity.

Velocity = displacement/time

v= 739/162

v= 4.56

Answer:

I belive that the answer is the A

Crest describes the high point of a transverse wave. Therefore, the correct option is option A.

Transverse waves are those which oscillate in directions that are opposite to the wave's forward motion. Electromagnetic radiation, seismic waves, or water surface ripples are all examples of transverse waves.

A simple transverse wave can be represented by a sine or cosine curve because any point's amplitude—that are, its distance from the axis—is proportional to the sine (or cosine) associated with that angle. Crest describes the high point of a transverse wave.

Therefore, the correct option is option A.

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Answer:

a = 5 [m/s²]

Explanation:

We know from Newton's second law that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = total force = 50 [N]

m = mass = 10 [kg]

a = acceleration [m/s²]

Now replacing:

\(a = \frac{F}{m} \\a=50/10\\a = 5 [m/s^{2} ]\)

120V is the line-to-neutral voltage .

It is defined as the voltage of a power transmission circuit or distribution circuit up to the point of transformation or utilization.

The secondary line voltage is \(V_{L} = 280 V\)

The notation AC indicates that the current is an alternating current.

The given formula is \(V_{ph} = \frac{V_{L} }{\sqrt{3} }\)

Substitute  208 V into the formula

\(V_{ph} = \frac{V_{L} }{\sqrt{3} } \\\\V_{ph} = \frac{208V}{\sqrt{3} } \\\\= 120 (Approx)\)

So, the line-to-neutral voltage is 120 V.

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When L = L₁, the circuit is a series RL circuit. The voltage across the inductor is given by Vₗ = XL₁i, where XL₁ = ωL₁ is the inductive reactance and i is the current flowing through the circuit. The voltage across the resistor is given by VR = Ri. The voltage across the capacitor is zero since it is connected in series with the inductor and the resistor.

The total voltage across the circuit is given by v = V√2 cos(ωt). By Kirchhoff's voltage law, we have v = Vₗ + VR,

V√2 cos(ωt) = XL₁i + Ri

The current i can be written as i = (1/Z) V√2 cos(ωt - φ), where Z = √(R² + XL₁²) is the impedance of the circuit and φ is the phase angle between the current and the voltage. Substituting i into the equation above, we get:

V√2 cos(ωt) = XL₁/Z V√2 cos(ωt - φ) + R/Z V√2 cos(ωt - φ)

Equating the coefficients of cos(ωt) and cos(ωt - φ), we get:

1 = XL₁/Z cos φ + R/Z sin φ

XL₁ sin φ = Z - R cos φ

tan φ = XL₁ / (Z - R cos φ)

The voltage across the inductor is given by:

Vₗ = XL₁ i = XL₁/Z V√2 cos(ωt - φ)

Vₗ/V = XL₁/Z cos φ

Substituting tan φ into this equation, we get:

Vₗ/V₁ = XL₁/Z₁ √[1 - (XL₁/Z₁)²] ... (1)

When L = L₂, the circuit is a series RC circuit. The voltage across the capacitor is given by VC = XC₂i, where XC₂ = 1/(ωC₂) is the capacitive reactance.  The total voltage across the circuit is given by v = V√2 cos(ωt). By Kirchhoff's voltage law, we have v = VC + VR, which gives:

V√2 cos(ωt) = XC₂i + Ri

Following the same steps as in the previous case, we can show that:

Vₗ/V₂ = XC₂/Z₂ √[1 - (XC₂/Z₂)²] ... (2)

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The intensity of the sound wave produced by the trumpet at a distance of 3.2 m is 1.56×10⁻³ W/m²

From the question given above, the following data were obtained:

The intensity of the sound wave can be obtained as illustrated below:

Intensity (I) = P / 4πr²

Inputting the various parameters, we have:

I = 0.2 / (4 × 3.14 × 3.2²)

I = 0.2 / 128.6144

I = 1.56×10⁻³ W/m²

Thus, we can conclude from the above calculation that the intensity of the sound wave is 1.56×10⁻³ W/m²

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Answer:

31,2 + 38,02 + 45 = 114.22lbs

The combined weight of all the samples can simply be calculated by the arithmetic sum of all the individual weights of each sample.

The total combined weight of all the samples is "114.22 lb".

Adding the individual weights of each sample we get:

Combined weight = Weight of sample 1 + Weight of sample 2 + Weight of sample 3

Combined Weight = 31.2 lb + 38.02 lb + 45 lb

Combined Weight = 114.22 lb

The attached picture shows weight addition.

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Answer: d) 5.88

Explanation:

The efficiency of motor is 90.58%.To determine the efficiency of the motor, we need to calculate the input power and the output power, and then divide the output power by the input power

The input power can be calculated using the formula:

Input Power = Voltage × Current

Given that the voltage is 230 V and the current is 24 A, we have:

Input Power = 230 V × 24 A

Input Power = 5520 W (or 5.52 kW)

The output power of the motor is given as 5 kW (since it is a 5 kW motor).

Now, we can calculate the efficiency:

Efficiency = (Output Power / Input Power) × 100%

Efficiency = (5 kW / 5.52 kW) × 100%

Efficiency ≈ 90.58%

Therefore, the efficiency of this motor is approximately 90.58%.

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Answer:

6.2 x 10^6

Explanation:

The 6 at the end is an exponent the carrot is the symbol

Answer:

6.2*10^7 miles

Explanation:

Answer:

18.60  m/s

Explanation:

Original momentum = mv = 4000        with m = 115    

after collision   m = 115 + 100 = 215 kg

  but the total momentum is still the same (conserved)

          4000 = 215 v      shows v = 18.60 m/s

Answer:

18.60

Explanation:

Answer:

Specific heat capacity is an intensive property and does not depend on sample size.

Explanation:

Answer:

It does not violate the first law because the total energy taken is what is used 100J = 25J + 75J

But violates 2nd lawbecause the engine has a higher energy after doing work than the initial for e.g A cold object in contact with a hot one never gets colder, transferring heat to the hot object and making it hotter confirming the second law

Answer:

0.54

Explanation:

2.7÷5 = 0.54

Hope this helps!

Answer:

44.3 m/s

Explanation:

a) Draw a free body diagram of the mass M.  There are three forces:

Weight force mg pulling down,

Normal force N pushing perpendicular to the ramp,

and tension force T pulling parallel up the ramp.

Sum of forces in the parallel direction:

∑F = ma

T − Mg sin 30° = 0

T = Mg sin 30°

T = Mg / 2

Draw a free body diagram of the hanging mass m.  There are two forces:

Weight force mg pulling down,

and tension force T pulling up.

Sum of forces in the vertical direction:

∑F = ma

T − mg = 0

T = mg

Substitute:

mg = Mg / 2

m = M / 2

M = 2m

b) Velocity of a standing wave in a string is:

v = √(T / μ)

T = mg, and m = 5 kg, so T = (5 kg) (9.8 m/s²) = 49 N.  Therefore:

v = √(49 N / 0.025 kg/m)

v = 44.3 m/s

The actual difference between the guage pressure of a system and an absolute pressure is the same as the pressure at the surface of the fluid.

The correct answer choice is option b.

It follows that the two pressure system mentioned in the given task above has a zero point system as their principle of operation.

When we talk of guage pressure, it uses atmospheric pressure as its own zero point system. However, the sum of both the guage pressure and atmospheric pressure gives what we know as the absolute pressure.

So therefore, we can now deduced that the pressure on a liquid surface is equivalent to the variation between the gauge pressure and absolute pressure.

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The pressure of the gas in a container with a volume of 1.54 L is initially evacuated. Then it is filled with 0.221 g of N2 is 1619Pa.

A gas with a small density and at a sufficiently high temperature so that the interaction between its particles can be neglected can be considered an ideal gas. In this case, the pressure, volume, and temperature of the gas are related as follows:

PV=mMRT, where m is the mass of the gas and M is the molar mass of the gas. The pressure of the gas can be found using the ideal gas law:p =mRT/MV.

The temperature of the gas can be found from the RMS speed of the molecules of nitrogen, which is given by: vrms=√3RT/M. Solving for the temperature, we obtain: T= Mv² / 3 R. And pressure is P= mv² /3V. So P=[ 0.221×(184)²]/ 3×1.54 = 1619 Pa.

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Answer:

Moon appears lit on the right half of the Moon during the First Quarter. The Moon appears lit on the left side during the Third Quarter because the Moon is on the other side of Earth. Again, if you think of the baseball analogy, and you’re standing at home plate, the first base or First Quarter is on your right side.

Explanation:

i hope is help