How many 15W LED bulbs could Niagara Falls power?

The metals will lose electrons while the non metals will gain electrons in order to attain octet structure.

An ion can be cation (positively charged) or anion (negatively charged).

Cations attain octet structure (8) by losing electron(s) while anions become stable or attains octet structure (8) by gaining electron(s).

The remaining elements are completed as follows to attain octet structure;

Element--valence electron--electrons to gain--electrons to lose--ion formed

O ------------ 6 ----------------------  2 ------------------------  none -------------- \(O^{2-}\)

Ca --------   2 ----------------------- none ---------------------- 2 ------------------ \(Ca^{2+}\)

Br ----------- 7 ---------------------     1 ------------------------ none --------------- \(Br^{-}\)

S ------------ 6 -----------------------  2 ------------------------ none --------------- \(S^{2-}\)

Cl ------------ 7 -----------------------  1 ------------------------ none ----------------\(Cl^{-}\)

K -------------- 1 ----------------------- none ----------------------- 1 ------------------ \(K^{+}\)

Mg ------------ 2 ---------------------- none ---------------------- 2 ---------------- \(Mg^{2+}\)

Be ------------- 2 ---------------------- none ---------------------- 2 ---------------- \(Be^{2+}\)

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Answer: they would have to be some where else

Explanation: hope this helps a little

The chocolate chips that are in one mole of chocolate chips is 6.02214 × 10²³ chips.

The mole of a substance is defined as the amount of substance that is my are up of 6.02214 × 10²³ particles and this number is called the Avogadro's number.

This means that 1 mole of substance= 6.02214 × 10²³ of particles that makes up the substance.

The Avogadro's number is a constant used for all substances such as the chocolate chips.

That is to say, one mole of the chocolate chips has a mass of 0.324 g but contains 6.02214 × 10²³ particles of chocolate chips.

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The number of chocolate chips that are included inside one mole of chocolate chips is equal to 6.02214 ×10^23 chips.

The quantity of a material that may be made up of 6.02214 ×10^23 particles is referred to as a mole, and this number is known as Avogadro's number. The mole is the unit of measure used to describe this quantity.

This indicates that there are 6,02214×10^23 particles in one mole of the material, which implies that one mole of the substance is equal to one mole.

Avogadro's number is a constant that is applied to many different kinds of things, including chocolate chips.

In other words, one mole of chocolate chips has a mass of 0.324 g, yet it includes 6.02214 ×10^23 individual chocolate chip particles.

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Answer:

c

Explanation:

metals are good conductors, while non metals are not good conductors

The work done is equal to 1911.53 J.

Solution:

work done =  18.87Latm

= 18.87 x 101.3j

= 1911.53 j

The work done is calculated by substituting the value of pressure, final volume, and initial volume in the work done equation. Then, the unit for work done will be in L atm, and this is converted into joules by multiplying the value in L atm with:

The work done is equal to 101.3j

= 1911.53j

Thus, The work done is equal to 1911.53 J.

The total cost of work in process refers to the sum of the starting cost of work in process and the total manufacturing cost for the period. In other words, the above concept can be obtained by adding the original work-in-progress inventory to the total manufacturing cost.

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Answer:

\(\huge\purple{\overline{\quad\quad\quad\quad\quad\quad\quad\quad\quad \ \ \ }}\)

Browser

Browser: A software application used to locate and display Web pages. The two most popular browsers are Microsoft Internet Explorer and Netscape Navigator

Answer:

Ans: A web browser

Explanation:

A web browser is a software that can be used to look at web pages on the internet

Cellulose

Nitrocellulose

Wax

Nylon

Fatty acids

Mixed hydrocarbons

Any chemical compound that has carbon-hydrogen or carbon-carbon bonds is considered an organic compound.

Examples of organic compounds are:

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Answer:

Marie Curie

Explanation:

Physics in 1903

Chemistry in 1911

Wow

https://www.nobelprize.org/prizes/physics/1903/marie-curie/biographical/

Answer:

Marie Curie was a physicist and chemist who was awarded the Nobel Prize for work in understanding radioactivity and the discovery of polonium.n:

The photon that carries more energy is the blue photon, and it carries around 50% more energy than the average orange photon (590-620 nm). The law used to solve the previous problem suggests that energy is proportional to the frequency of an electromagnetic wave. Thus, the higher the frequency, the higher the energy. The correct option is C.

In electromagnetic radiation, the energy carried by each photon is directly proportional to the frequency and inversely proportional to the wavelength. Thus, higher frequency photons carry more energy than lower frequency photons.

A photon's energy is directly proportional to its frequency and inversely proportional to its wavelength. Thus, higher frequency photons, such as blue photons, carry more energy than lower frequency photons, such as orange photons. The energy of a photon is given by the equation: E = hf

Where E is energy, h is Planck's constant (6.63 x 10⁻³⁴ J s), and f is frequency.

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The standard enthalpy change for reaction (3) is 117.1 kJ.

The standard enthalpy change for reaction (3) can be calculated by using the enthalpy changes of reactions (1) and (2) and applying Hess's Law.

To do this, we need to manipulate the given equations so that the desired reaction (3) can be obtained.

First, we reverse reaction (1) to get the formation of C2H4(g) from C2H6(g):

C2H4(g)C2H6(g) ΔH° = -52.3 kJ

Next, we multiply reaction (2) by 2 and reverse it to obtain 2 moles of C2H6(g) reacting to form 3 moles of H2(g):

2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

Now, we add the two modified equations together:

C2H4(g)C2H6(g) ΔH° = -52.3 kJ
2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

When adding these equations, the C2H6(g) on the left side cancels out with the C2H6(g) on the right side, leaving us with the desired reaction (3):

C2H4(g) + H2(g)C2H6(g) ΔH° = -52.3 kJ + 169.4 kJ = 117.1 kJ

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80g•1moles/68.94g= 1.16g

Answer:

There is no figure provided with the question. Please provide the figure or more context so I can assist you better.

Explanation:

A solution is defined as a mixture of two or more substances, usually, a solute and a solvent, and the difference between these two are in quantity, solute represents the smallest amount and solvent will represent the highest amount, and while you can have more than one solute, you can only have one solvent for a solution. Therefore the statement is true

Answer: The number of atoms = Avogadro's number = 6.022 × 10²³

Number of atoms in a mole = Avogadro's number = 6.022 × 10²³

Explanation:

1.

Mole = \(\frac{given mass}{molar mass}\)

Also, Mole = \(\frac{Number of atoms/molecules/ions}{Avagadro's Number}\)

∴  \(\frac{given mass}{molar mass}\)  = \(\frac{Number of atoms/molecules/ions}{Avagadro's Number}\)

\(\frac{12}{12}\) = \(\frac{number of atoms}{Avogadro's number}\)

number of atoms = Avogadro's number

number of atoms = 6.022 × 10²³

2.

Mole = \(\frac{Number of atoms/molecules/ions}{Avagadro's Number}\)

1 =  \(\frac{Number of atoms/molecules/ions}{Avagadro's Number}\)

number of atoms = Avogadro's number

number of atoms = 6.022 × 10²³

Answer:

Three properties of covalent bonds are low melting and boiling points, softer than ionic bonds, don't dissolve well in the water.

Three properties of ionic bonds are high melting as well as boiling points, hard and brittle in nature and conduct electricity when dissolved in water.

Answer:

That is true

Explanation:

The sum of 89.0, 469, and 0.3469, rounded to the appropriate number of significant figures, is 558.3, with three significant figures.

To calculate the sum of 89.0, 469, and 0.3469, we add these numbers together. The sum of 89.0 and 469 is 558.0, and when we add 0.3469 to this sum, we get 558.3469. However, we need to express the result with the correct number of significant figures.

The rule for determining the number of significant figures in addition is to consider the number with the least number of significant figures. In this case, 0.3469 has four significant figures, whereas 89.0 and 469 have three significant figures. Therefore, our final answer should have three significant figures. Rounding the result to three significant figures, we get 558.3.

Significant figures, also known as significant digits, are used to indicate the precision or accuracy of a measurement or calculation. They represent the digits that carry meaning in a number. When performing calculations, it is important to consider the number of significant figures and apply rounding rules to ensure the result is properly expressed.

In addition, the rule for addition and subtraction is to consider the number with the least number of significant figures. This is because the least precise measurement limits the level of precision for the final result. By rounding to the appropriate number of significant figures, we maintain consistency and avoid falsely implying a higher level of precision than is justified by the original data.

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Answer:

C option

Explanation:

Answer:

Option B. 3–heptyne

Explanation:

To obtain the name of the compound given above, we must:

I. Determine the functional group of the compound.

II. Determine the longest continuous carbon chain. This gives the parent of the compound.

III. Locate the position of the functional group.

IV. Combine the above to obtain the name of the compound.

Now we shall name the compound as follow:

I. The compound has carbon to carbon triple bond (–C≡C–). Thus, the compound is an alkyne.

II. The longest continuous carbon chain is 7 i.e heptyne

III. The functional group i.e the triple bond (–C≡C–) is located at carbon 3

IV. The name of the compound is

3–heptyne

Option B gives the correct answer to the question.

The amount of copper deposited is 0.1778 grams.

The electrolysis reaction for CuSO₄ solution

Copper deposits will occur at the cathode. According to Faraday's law the number of moles of an electron

ne = It ÷ 96,500

ne = (0.450 × 1,200) ÷ 96,500

ne = 540 ÷ 96,500

ne = 5.6 × 10⁻³ mol

The ratio of the coefficients of each element is equal to the ratio of the number of moles.

ne : n Cu = 2 : 1

n Cu = ne ÷ 2

n Cu = (5.6 × 10⁻³) ÷ 2

n Cu = 2.8 × 10⁻³ mol

Calculate the amount of copper

The molar mass for copper = 63.5

m = n × molar mass

m = 2.8 × 10⁻³ × 63.5

m = 0.1778 grams

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Answer:

Ok 15 miles NO2 you need the salt and pepper trick so mix it add water sit in it when you get cold write down uh temperature then you need to get out or it may kill you when it starts to get cold then go to the y- axis then you need to ask your teacher for help after you do the y-axis

Answer:

CuS + 2AgNO3(aq) > Cu(NO3)2(aq) + Ag2S

Explanation:

The reaction is CuS + AgNO3(aq) > Cu(NO3)2(aq) + Ag2S

so the balanced reaction is CuS + 2AgNO3(aq) > Cu(NO3)2(aq) + Ag2S

Cu = 1

S = 1

Ag = 2

NO3 = 2

Answer:

A. Silicon

Explanation:

The ability of an atom to attract electrons is known as electronegativity.

Electronegativity  is the measure of the relative tendency with which the atoms of the element attract valence electrons in a chemical bond.

Condensed structural formulas are written in a single line to save space and make them easier and faster to type out. They display the atoms' positions similarly to a structural formula.

The only amino acid that has one carbon atom is glycine. \($-\mathrm{COOH}$\) plus one \($-\mathrm{NH}_2$\) group that is connected to an alpha-carbon and contains two hydrogens. - \($\mathrm{COOH}$\) Serine is made up of an a-carbon, one hydrogen, and one \($-\mathrm{NH}_2$\) group as well as one  \($-\mathrm{CH}_2 \mathrm{OH}$\)group.

Both glycylserine and serylglycine are dipeptide molecules made up of glycine and serine; however, glycylserine has an amide linkage formed when one H of the \($-\mathrm{NH}_2$\) group of glycine condenses with the - \($\mathrm{OH}$\) of the - \($\mathrm{COOH}$\) group of glycine Comparably, in serylglycine, one  -OH of the - \($\mathrm{COOH}$\) group of serine condenses with one H of the \($-\mathrm{NH}_2$\) group of serine. Serine and glycine are the two byproducts of the hydrolysis of serylglycine. The rupture of the amide bond is seen by the red line. The glycine, serine, and alanine amino acids that make up this tripeptide structure are connected by amide bonds.

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The determine the number of moles of both element X and oxygen present in the given sample. To do this, we divide the given mass of each element by its atomic molar mass. For element X, we have 50.0 g / 100 u = 0.5 moles of X For oxygen, we have 32.0 g / 16 u = 2.0 moles of O.

The determine the ratio in which X and O combine to form the oxide. This can be done by dividing the number of moles of each element by the smaller of the two values. In this case, the smaller value is 0.5 moles of X. Dividing by this value gives us 0.5 moles of X / 0.5 moles of X = 1 2.0 moles of O / 0.5 moles of X = 4 This means that the empirical formula for the oxide of X is XO4. However, we need to simplify this formula by dividing each subscript by the greatest common factor. In this case, the greatest common factor is 4, so we divide each subscript by 4 to get the simplest formula, which is XO. Therefore, the simplest formula for the oxide of element X is XO.

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Yes. The pH of 3.7 should be the equivalency point.

Methyl orange transforms from a basic to an acidic color during a strong acid weak base titration, making it a useful chemical indicator. In acidic and basic media, respectively, methyl orange exhibits red and yellow colors. In titration, the solution appears yellow at first because the pH is high.

Methyl orange is a frequently used pH indicator in titrations because of its easy-to-see color shift. Because it changes color at a weak acid's pH, it is frequently employed in acid titrations. Methyl orange turns red in an acidic medium while turning yellow in a basic one.

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Answer:

D. It often contains heavy metals.

Explanation:

Used antifreeze should not be reused in a vehicle, it is not recyclable, and it should be disposed of properly because it often contains heavy metals, such as lead and copper, which can be harmful to the environment and human health. It should not be treated just like new antifreeze. It is important to check the antifreeze levels and quality regularly and replace it with fresh antifreeze as needed.

The pH of the buffer solution is 9.06.

To solve this problem, we need to use the Henderson-Hasselbalch equation, which relates the pH of a buffer solution to the concentrations of the acid and its conjugate base:

pH = pKa + log([A-]/[HA])

where pKa is the acid dissociation constant, [A-] is the concentration of the conjugate base, and [HA] is the concentration of the acid.

In this case, HCN is the acid and CN- is its conjugate base. The dissociation constant for HCN is given as Ka = 4.0×10^-10. The concentrations of HCN and CN- in the buffer solution are 0.341 M and 0.345 M, respectively.

We can first calculate the ratio of [CN-]/[HCN]:

[Cn-]/[HCN] = 0.345/0.341 = 1.017

Next, we can calculate the pKa using the formula:

Ka = [H+][CN-]/[HCN]

Rearranging this equation gives:

pKa = -log(Ka) + log([HCN]/[CN-])

Substituting the values given:

4.0×10^-10 = [H+][0.345]/[0.341]

[H+] = 2.99×10^-5 M

pKa = -log(4.0×10^-10) + log(0.341/0.345) = 9.21

Finally, we can plug in the values of pKa and [CN-]/[HCN] into the Henderson-Hasselbalch equation to solve for the pH:

pH = 9.21 + log(1.017) = 9.06

Therefore, the pH of the buffer solution is 9.06.

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