How does the temperature of the core compare to the Sun?
The core is colder the surface of the Sun.
o The Sun is hotter than the core.
The core may be as hot as the surface of the Sun.
The core is hot during the day but cooler at nighttime.

Answers

Answer 1
i think the answer is c

Related Questions

Sulfuric acid (see chemical formula below) is a strong acid and is a type of acid rain. What happens to the pH of water when five drops of sulfuric acid are added to a sample of water?



1. Adding sulfuric acid to water will not have any effect on the pH of water.

2. Adding sulfuric acid to water will increase the pH dramatically.

3. Sulfuric acid does not reaction with water.

4. Adding sulfuric acid to water will decrease the pH dramatically.

Sulfuric acid (see chemical formula below) is a strong acid and is a type of acid rain. What happens

Answers

Adding sulfuric acid to water will decrease the pH dramatically.option 4.

Sulfuric acid is a strong acid and is a type of acid rain. When five drops of sulfuric acid are added to a sample of water, the pH of water will decrease dramatically. This is because sulfuric acid is a strong acid that is capable of dissociating completely in water, producing a high concentration of hydrogen ions (H+) and sulfate ions (SO4²-). This increase in hydrogen ion concentration lowers the pH of water and makes it more acidic.Acid rain is a type of rain that has a pH lower than 5.6, which is the normal pH of rainwater. The acidity of acid rain is caused by the presence of strong acids like sulfuric acid and nitric acid. These acids are produced when sulfur dioxide (SO2) and nitrogen oxides (NOx) are emitted into the atmosphere by human activities like burning fossil fuels and industrial processes.When these gases react with water, they form sulfuric acid and nitric acid, respectively, which then fall to the ground as acid rain.

Acid rain can have harmful effects on the environment, including the acidification of lakes and rivers, the degradation of forests and soils, and the corrosion of buildings and monuments.To conclude, when five drops of sulfuric acid are added to a sample of water, the pH of water will decrease dramatically.option 4.

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What is meant by functional group in an organic compound?
Functional group for
A) keton
B) acid anhydride
C) aldehyde
D) amide
C) alcohol

Answers

Answer:

i THINK the answer to this is C) aldehyde

Answer:

The answer is C, the guy above is correct.

Explanation:

A new element was recently discovered. It is called Jurupium and has a molar mass of 125 grams/mole. How many moles of Jurupium are in 375 grams of Jurupium metal?

Answers

In 375 grammes of the metal Jurupium, there are 3 moles of the element.

How did element 99 get its name?

On 1 November 1952, the first thermonuclear explosion, which occurred on a Pacific atoll, left behind debris that contained the element Einsteinium. A neighbouring atoll's fallout material was shipped to Berkeley, California, for analysis. It belongs to the group of elements with atomic number 63 that are numerically squeezed between barium and hafnium. A lanthanide, or europium, is one of those mysterious elements outside the periodic table's core.

Divide the mass of Jurupium by its molar mass to see how many moles there are in 375 grammes of Jurupium metal:

375 g / 125 g/mol = 3 moles

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The beaks of finches found on various Galapagos Islands
differed based on:

A. The size of their island.
B. The length of their wings.
С. The available food supply.
D. The predators that hunted them.

Answers

Answer:

c the available food supply

C. The available food supply I think not sure but if not I’m sorry

calculate the value at Kc for the hypothetical reaction

calculate the value at Kc for the hypothetical reaction

Answers

Kc for the hypothetical reaction is 1.5×10⁻⁵

Kc is the ratio of the equilibrium concentrations of products over the equilibrium concentrations of reactants each raised to the power of their stoichiometric coefficients.

Given reaction is

4M(g) ⇄ 2Z(g)  Kc =6.58×10⁻³

2Z(g) ⇄ 4Q(g)+8X(g) Kc =2.07×10⁻²

So for finding another Kc of that given reaction is Q(g)+2X(g) ⇄ M(g)

To find Kc the formula is [M]m/[Q]q[X]x for Q=8.66

Put the given value 6.58×10⁻³/8.66×2.07×10⁻²

= 1.5×10⁻⁵

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A True
B. False
2. T F Variation is a membrane-covered structure that contains all of the material needed for
life.
(5 Points)
O A. True
O B. False
3.5 F Life first evolved during the Precambrian times.
(5 Points)
A True
OB. False

Answers

Answer:

true

true

false

Explanation:

A pencil has a density of .875 g/ml it has a mass of 3.5 grams What is the volume

Answers

Answer:
4 × 10⁻³ L
Explanation:
Density = 0.875 g/mL
Mass = 3.5 grams
Volume = ?

Density = mass / volume
0.875 = 3.5/Volume
*Cross's multiply*
Volume = 3.5/0.875
Volume = 4 mL
The unit of volume is Litres (L), which means mL must be converted to L
To convert from a prefix to a non-prefix, the prefix notation will be replaced with the numeric equivalent of the prefix in the expression
Milli (m) = 10⁻³
So 10⁻³ will be replaced in the place of m
4 mL = 4 (10⁻³) L
4 × 10⁻³ L
Volume = 4×10⁻³ L

Balance the following chemical equation: CH4+ Cl2 → CCl4+ HCI​

Answers

Explanation:

CH4+8/2Cl2—>CCl4+4HCl

that is,1molecule of methane+8/2 molecules of dichlorine—>1molecule of carbon tetrachloride+4molecules of hydrogen chloride

WHAT IS ELECTROLYSIS​

Answers

DEFINTION

"chemical decomposition produced by passing an electric current through a liquid or solution containing ions."

comment if you need anything else

Love,

-Banana

what mass of glucose c6h12o6 would be required to prepare 5000 mL of a 0.215 M solution

Answers

Approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M.

To determine the mass of glucose (C6H12O6) required to prepare a 0.215 M solution in 5000 mL, we need to use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

First, let's convert the volume of the solution from milliliters (mL) to liters (L):

5000 mL = 5000/1000 = 5 L

Now, we can rearrange the formula to solve for moles of solute:

moles of solute = Molarity (M) x volume of solution (L)

moles of solute = 0.215 M x 5 Lmoles of solute = 1.075 mol

Since glucose (C6H12O6) has a molar mass of approximately 180.16 g/mol, we can calculate the mass of glucose using the equation:

mass of solute = moles of solute x molar mass of solute

mass of glucose = 1.075 mol x 180.16 g/mol

mass of glucose = 194.0 g (rounded to three significant figures)

Therefore, approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M. It's important to note that the molar mass of glucose used in this calculation may vary slightly depending on the level of precision required.

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Please help will give brainliest

Please help will give brainliest

Answers

Answer:

B

Explanation:

3d is the sublevel depicted.

how do you create flu vaccine,

Answers

Answer:

Explanation:

The fluid containing virus is harvested from the eggs. For inactivated influenza vaccines (i.e., flu shots), the vaccine viruses are then inactivated (killed), and the virus antigen is purified. The manufacturing process continues with quality testing, filling and distribution.

Heredity Lab Report Instructions:
In the Heredity lab, you investigated how hamsters inherit traits from their parents. Record your observations in the lab report below. You will submit your completed report.
Name and Title: Include your name, instructor's name, date, and name of lab.

Objective(s): In your own words, what was the purpose of this lab?

Hypothesis: In this section, please include the if/then statements you developed during your lab activity.

These statements reflect your predicted outcomes for the experiment.

Test One: If I breed a short fur, FF female with a short fur, Ff male, then I will expect to see (all short fur; some short and some long fur; all long fur) offspring.
Test Two: If I breed a short fur, Ff female with a short fur, Ff male, then I will expect to see (all short fur; some short and some long fur; all long fur) offspring.
Test Three: If I breed a long fur, ff female with a long fur, ff male, then I will expect to see (all short fur; some short and some long fur; all long fur) offspring.
Procedure: The procedures are listed in your virtual lab. You do not need to repeat them here.
Please be sure to identify the test variable (independent variable) and the outcome variable (dependent variable) for this investigation. Remember, the test variable is what is changing in this investigation.
The outcome variable is what you are measuring in this investigation.
Test variable (independent variable): Outcome variable (dependent variable): Data: Record the data from each trial in the data chart below. Be sure to fill in the chart completely. Test One Parent 1: FF Parent 2: Ff Phenotype ratio: ________ : ________ short fur : long fur Test Two Parent 1: Ff Parent 2: Ff Phenotype ratio: ________ : ________ short fur : long fur Test Three Parent 1: ff Parent 2: ff Phenotype ratio: ________ : ________ short fur : long fur Conclusion: Your conclusion will include a summary of the lab results and an interpretation of

Answers

For Test One, phenotype ratio is Short fur : Long fur = 2 : 0; For Test Two, the phenotype ratio is Short fur : Long fur = 3 : 1; For Test Three, the phenotype ratios will be Short fur : Long fur = 0 : 2

What are the phenotype ratios from the test crosses?

For Test One:

Parent 1: FF (homozygous dominant for short fur)

Parent 2: Ff (heterozygous for short fur)

The Punnett square for this cross will give the following genotype ratios:

FF : Ff = 1 : 1

And the corresponding phenotype ratios will be:

Short fur : Long fur = 2 : 0 or 100% short fur

For Test Two:

Parent 1: Ff (heterozygous for short fur)

Parent 2: Ff (heterozygous for short fur)

The Punnett square for this cross will give the following genotype ratios:

FF : Ff : ff = 1 : 2 : 1

And the corresponding phenotype ratios will be:

Short fur : Long fur = 3 : 1 or 75% short fur and 25% long fur

For Test Three:

Parent 1: ff (homozygous recessive for long fur)

Parent 2: ff (homozygous recessive for long fur)

The Punnett square for this cross will give the following genotype ratios:

ff : ff = 1 : 0

And the corresponding phenotype ratios will be:

Short fur : Long fur = 0 : 2 or 100% long fur

For this investigation, the test variable is the breed of hamster and the outcome variable is the phenotype of the hamster.

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The one factor that a scientist changes in an experiment is called the
O
A responding variable.
O
B. hypothesis.
C. controlled variable.
D. manipulated variable.

Answers

Answer:

It might be responding variable.

June 1
June 8
June 11
5. What phase of the moon most likely will appear 28 days after phase C?
A Waning Gibbous
June 15
B
Waning Crescent
с
Waxing Crescent
D
Waxing Gibbous

Answers

Answer:

D

Explanation:

it's D because it goes waxing crescent to waxing gibbous

Identify the substance that has formula mass of 133.5amu.
(a) MgCI
b)SCI
c)BCI
D) AICI​

Answers

The calculated formula masses to 133.5 amu, we find that the substance with a formula mass closest to 133.5 amu is (d) AlCl3. Therefore, the answer is option D.

To identify the substance with a formula mass of 133.5 amu, we need to calculate the formula mass of each given substance and compare it to 133.5 amu.

(a) MgCl2:

The formula mass of MgCl2 can be calculated by adding the atomic masses of magnesium (Mg) and chlorine (Cl).

Mg: atomic mass = 24.31 amu

Cl: atomic mass = 35.45 amu

Formula mass of MgCl2 = (24.31 amu) + 2(35.45 amu) = 95.21 amu

(b) SCl:

The formula mass of SCl can be calculated by adding the atomic masses of sulfur (S) and chlorine (Cl).

S: atomic mass = 32.07 amu

Cl: atomic mass = 35.45 amu

Formula mass of SCl = 32.07 amu + 35.45 amu = 67.52 amu

(c) BCl:

The formula mass of BCl can be calculated by adding the atomic mass of boron (B) and chlorine (Cl).

B: atomic mass = 10.81 amu

Cl: atomic mass = 35.45 amu

Formula mass of BCl = 10.81 amu + 35.45 amu = 46.26 amu

(d) AlCl3:

The formula mass of AlCl3 can be calculated by adding the atomic mass of aluminum (Al) and 3 times the atomic mass of chlorine (Cl).

Al: atomic mass = 26.98 amu

Cl: atomic mass = 35.45 amu

Formula mass of AlCl3 = 26.98 amu + 3(35.45 amu) = 133.78 amu. Option D

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How many valence electrons does an atom of Iodine have?

a) 5
b) 6
c) 7
d) 8

Answers

the answer is 7 !! :)

round off 3259 to 3 sig figs (show work)

Answers

Answer:

3260

Explanation:

3259

as the number after the 3rd number (9) is greater than 5, the 3rd number (5) can be rounded off to be 6
so,

3259

≈ 3260

this is the only method i know of solving this type of question

hope it helps

thnxx

Answer:

3260

Explanation:

3259

the number after the 3rd significant figure(3rd number) is 9 which is greater than 5 so you make the number 0 and add 1 to the 3rd significant figure which is 5

= 3260

BRAINEST PLEASE

Predict the products of the following reactions (assume complete reaction). In your submission include the overall balanced equation, and balanced net ionic equation if applicable:
a. Adding zinc metal to a solution of copper(II) sulfate
b. Dripping silver perchlorate into a solution of sodium carbonate
c. A lump of aluminum metal is dropped into concentrated hydroiodic acid
d. Sucrose is fermented in water by yeast to make ethanol and carbon dioxide (note: water is a reactant)
e. Solid calcium oxide is added to water (careful)
f. A lump of potassium metal is dropped into water (careful)

Answers

Answer:

Zn(s) + CuSO4(aq) -----> ZnSO4(aq) + Cu(s)

Na2CO3 (aq)+ 2AgClO4(aq) → 2NaClO4(aq) + Ag2CO3(s)

2Al(s) + 6HI(aq) ------> 2AlI3(aq) + 3H2(g)

C12H22O11(s)+H2O(l)→4C2H5OH(aq)+4CO2(g)

2K(s) + 2H2O(l) ------->2KOH(aq) + H2(g)

Explanation:

In the first reaction, zinc displaces copper from an aqueous copper II salt since zinc is higher than copper in the electrochemical series.

Reaction two leads to the precipitation of silver carbonate. Remember that carbonates are mostly insoluble in water.

Acids are known to displace hydrogen gas from dilute acids. Hence in the third reaction, aluminum displaced hydrogen from aqueous hydroiodic acid.

In the fourth reaction, the action of yeast leads to the fermentation of sucrose yielding ethanol and carbon dioxide in the process.

Metals are known to form aqueous alkaline solutions liberating hydrogen gas when they react with water. Hence potassium metal reacts with water to liberate hydrogen gas and form alkaline potassium hydroxide.


H2SO, is an example of which of the following?
A) Element
B) Compound
C)Noble Gas
D)Mixture

Answers

Answer:

The answer is B.

Explanation:

Its a chemical compound

moles of each product that would form as a result of the decomposition of aspirin

Answers

The decomposition of aspirin (acetylsalicylic acid,\(C_{9} H_{8} O_{4}\)) can occur through the hydrolysis reaction, resulting in the formation of acetic acid (\(CH_{3} COOH\)) and salicylic acid (\(C_{7} H_{6}O_{3}\)).

The decomposition of aspirin (acetylsalicylic acid, \(C_{9} H_{8} O_{4}\)) can occur through the hydrolysis reaction, resulting in the formation of acetic acid (\(CH_{3} COOH\)) and salicylic acid (\(C_{7} H_{6}O_{3}\)). To determine the moles of each product formed, we need to consider the balanced chemical equation for the reaction:

\(C_{9} H_{8} O_{4} = > C_{7} H_{6}O_{3} +CH_{3} COOH\)

From the equation, we can see that for every 1 mole of aspirin, 1 mole of salicylic acid and 1 mole of acetic acid are produced.

Therefore, the moles of salicylic acid and acetic acid formed will be equal to the number of moles of aspirin that decomposes. If we know the amount of aspirin in moles, we can directly calculate the moles of each product based on stoichiometry.

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For the reaction 2 H2(g) + O2(g) → 2 H2O(g), how many liters of water can be made from 5.0 L of
oxygen gas and an excess of hydrogen?

Answers

Answer: 5L O2 x 1 mol O2/ 22.4L O2 x 2 mol H20/ 1 mol O2 x 22.4L H20/ 1 mol H20 = 10 L H2O

Explanation:

For future reference though, since its at STP that means that the coefficient are in proportion. Since oxygen has a coefficient of 1 and water has a coefficient of 2 for every 1 liter of oxygen there is 2 liters of water. Hence you started with 5 liters and ended with 10


A researcher is studying gold complexes. She makes
a 125 mL solution of gold(III) chloride by dissolving
0.144 moles of the solute into water. Which of the
following would cause the concentration of the
solution to increase?
Additional gold(III) chloride is added to the
beaker.
Part of the solution is poured into the chemical
waste.
O Water is added to the beaker.
We do not have enough information to answer
this question.

Answers

Additional gold(III) chloride is added to the beaker. This would cause the concentration of the solution to increase. Therefore, the correct option is option A.

Concentration in chemistry refers to the quantity of a material in a certain area. The ratio of the solute within a solution to the solvent or whole solution is another way to define concentration. In order to express concentration, mass / unit volume is typically used.

The solute concentration can, however, alternatively be stated in moles or volumetric units. Concentration may be expressed as per unit mass rather than volume. Although concentration is typically used to describe chemical solutions, it may be computed for any mixture. Additional gold(III) chloride is added to the beaker. This would cause the concentration of the solution to increase.

Therefore, the correct option is option A.

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45. Assume that 0.504 g of H₂ gas at STP reacts with
excess CuO according to the following equation:
Cuo(s) + H₂(g) → Cu(s) + H₂O(g)
Make sure the equation is balanced before beginning
your calculations.
a. How many liters of H₂ react?
b. How many moles of Cu are produced?
C. How many grams of Cu are produced?

Answers

The balanced equation for the reaction is:

CuO(s) + H2(g) → Cu(s) + H2O(g)

a. To find the volume of H2 gas at STP, we can use the ideal gas law:

PV = nRT

At STP, the pressure (P) is 1 atm and the temperature (T) is 273 K. The volume (V) of 1 mole of gas at STP is 22.4 L. So, the number of moles (n) of H2 gas is:

n = PV/RT = (1 atm) x V/(0.0821 L·atm/mol·K x 273 K) = V/22.4

We know that 0.504 g of H2 gas reacts. The molar mass of H2 is 2 g/mol. So, the number of moles of H2 gas is:

n = m/M = 0.504 g/2 g/mol = 0.252 mol

Now we can find the volume of H2 gas:

V = n x 22.4 L/mol = 0.252 mol x 22.4 L/mol = 5.65 L

Therefore, 5.65 liters of H2 gas react.

b. From the balanced equation, we can see that the mole ratio of CuO to Cu is 1:1. So, the number of moles of Cu produced is also 0.252 mol.

c. To find the mass of Cu produced, we can use the molar mass of Cu, which is 63.5 g/mol:

mass of Cu = number of moles of Cu x molar mass of Cu
= 0.252 mol x 63.5 g/mol
= 16.02 g

Therefore, 16.02 grams of Cu are produced.

Which is an unavoidable error in this experiment?
Responses
A The tube in the machine is on it's seventh run and may contain the remains of old experiments.The tube in the machine is on it's seventh run and may contain the remains of old experiments.
B Injection of the sample into the machine requires a certain minimum time.Injection of the sample into the machine requires a certain minimum time.
C Darryl washed the sample with the wrong solvent.Darryl washed the sample with the wrong solvent.
D Darryl set the temperature on the machine to 350°C instead of 400°CDarryl set the temperature on the machine to 350°C instead of 400°C

Answers

B bc yea B ………………………….

A 120 mL solution of sea water had 2.7x1022 sodium ions. What is the concentration of sodium in mol/L?

Answers

To calculate the concentration of sodium ions in sea water in units of mol/L, we need to use Avogadro's number to convert the number of ions to moles, and then divide by the volume of the solution in liters.

Avogadro's number is the number of atoms or molecules in one mole of a substance, and it is approximately 6.022 x 10²³.

First, we need to calculate the number of moles of sodium ions in the solution:

Number of moles of Na+ = (2.7 x 10²²) / (6.022 x 10²³) = 0.0448 mol

Next, we need to calculate the concentration of sodium ions in the solution:

Concentration of Na+ = (0.0448 mol) / (0.120 L) = 0.373 mol/L

Therefore, the concentration of sodium ions in sea water is approximately 0.373 mol/L.

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Who used scientific investigations to study atoms?
Check all that apply.
Dalton
Democritus
Rutherford
Thomson

Who used scientific investigations to study atoms?Check all that apply.DaltonDemocritusRutherfordThomson

Answers

Answer:

Rutherford used scientific investigation to study atoms.

Scientist who used scientific investigations to study atoms is Rutherford.

What are atoms?

Atoms are the basic fundamental or functional unit of any substance present in the nature.

Rutherford is also known as the father of nuclear physics and he did scientific investigation on the massive part of atom called nucleus he discovered that there are two types of radiation, coming from the uranium atom are alpha and beta particles.

Scientific investigation is a method in which scientist will study, perform and observe results for the experiment.

Hence Rutherford used scientific investigation.

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0.00401g is dissolved in 675 000ml what is the concentration of this solution in ppm

Answers

Answer:

grams of solute in 1,000,000 mL of solution ... A mass of 0.00401 g of salt is dissolved in 675,000 mL of water.

Explanation:

How many grams are in 4.25 moles of NiS?

Answers

Answer:

386.75 grams

Explanation:

You can use dimensional analysis to help you solve for this question

1. set up a proportion

                          x grams

4.25 mol x        x mole

2. to find the amount of grams/mol that are in NiS we find the gram formula mass (mass of all the atomic masses of each element)

Ni- 59 grams

S- 32 grams

add these together and you get 91 g/mol

3. now plug in the values and multiply across

                    91 grams

4.25 mol x     1 mole

when you multiply across this is equal to 386.75 grams

A mountain has a height of 2.74 miles. How high is the mountain in meters? Use the fact that 1 mi=1.609 km .

Answers

kkknskndcnndcks

a

Answer:

Explanation:

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