identify the correlation you would expect to see between the weight of baggage someone carries and the speed at which he or she walks. explain.

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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Answer:

Instrument Use

Accelerometer Measures acceleration

Altimeter Measures altitude of an aircraft

Ammeter Measures electric current in ampere

Anemometer Measures wind speed

Answer:

True

Explanation:

Energy decreases as it moves up trophic levels because energy is lost as metabolic heat when the organisms from one trophic level are consumed by organisms from the next level.

Answer:

0.5 m x 1.5 m

Answer:

B. Atomic number minus mass number

Explanation:

A closed system is a system that is completely isolated from its environment. The physical universe, as we currently understand it, appears to be a closed system. An open system is a system that has flows of information, energy, and/or matter between the system and its environment, and which adapts to the exchange.

D makes the most sense, but you just have to put two and two together and go with your gut feeling, first cross out the answers that don't make sense (A didnt make sense) and go from there! I hope the little bit above me helped you answer or decide :) Good luck!

Answer:

Mass = 63.7 kg

Explanation:

Given:

F = 367.5 N - force

a = 4.2 m/s² - acceleration

F₁ = 100 N - frictional force

___________

m - ?  - mass

2 Newton's law:

m·a = F - F₁

Mass:

m = (F - F₁) / a

m = (367.5 - 100) / 4.2 ≈ 63.7 kg

Answer:

I=Q/T

2.8=Q/3

8.4C=Q

Explanation:

Examples of following forces mentioned -

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Answer:

electricity...or Google.

Answer:

A closed loop that electrons can travel in.

Explanation:

We can use currency as a medium of exchange in transactions because of its easy availability.

Currency is the most common medium of exchange accepted as a standard by all parties for settling economic transactions because every region or country has its specific type of currency in which they do transactions and carried out their economic activities world wide.  Currency is also considered as a medium of exchange for goods and services. It is money that is present in the form of paper and coins which is issued by a government. Currency is generally accepted because of high value as a method of payment. U.S. dollars ($), euros (€), Japanese yen (¥), and pounds sterling (£) are the examples of currencies of different countries around the world.

So we can conclude that We can use currency as a medium of exchange in transactions because of its easy availability.

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After the impact, the two players are moving side by side at a speed of roughly 4.12 m/s.

Momentum is never created or destroyed inside a problem domain, according to the principle of momentum conservation. Momentum is only changed by the action of forces as they are described by Newton's equations of motion.

\(p1 = m1 * v1 + m2 * v2\)

\(p1 = 165 kg * 0 m/s + 178 kg * 8 m/s = 1424 kg*m/s\)

\(p2 = (m1 + m2) * v\)

Substituting the values, we get:

\(p2 = (165 kg + 178 kg) * v = 343 kg * v\)

Since the total momentum is conserved, we can equate p1 and p2:

p1 = p2

\(165 kg * 0 m/s + 178 kg * 8 m/s = 343 kg * v\)

\(v = (165 kg * 0 m/s + 178 kg * 8 m/s) / 343 kg ≈ 4.12 m/s\)

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When a car collides with another object, the total momentum of the system before and after the collision must be conserved. Momentum, on the other hand, is a product of mass and velocity. To find the velocity of a car after a collision, we must first consider the initial momentum of the system before the collision and compare it to the final momentum after the collision.

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Explanation:

Given:

Δx = 50 m

v₀ = 0 m/s

a = 0.2 m/s²

Find: v

The problem does not involve time.  Therefore, the required equation is:

v² = v₀² + 2aΔx

Plug in values and solve:

v² = (0 m/s)² + 2 (0.2 m/s²) (50 m)

v = 4.47 m/s

The velocity of the car when it has moved a distance of 50 meters is approximately 4.47 m/s.

To find the velocity of the car when it has moved a distance of 50 meters, we can use the following equation of motion:

v² = u² + 2as

Where:

v = final velocity

u = initial velocity (which is 0 in this case as the car starts from rest)

a = acceleration

s = distance traveled

Plugging in the values into the equation:

v² = 0² + 2(0.2)(50)

v² = 0 + 20

v² = 20

Taking the square root of both sides:

v = √20

v = 4.47 m/s

Therefore, the velocity of the car when it has moved a distance of 50 meters is approximately 4.47 m/s.

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Answer: Phytoplankton

Explanation:

Answer:

The efficiency of Carnot's heat engine is 26.8 %.

Explanation:

Temperature of hot reservoir, TH = 100 degree C = 373 K

temperature of cold reservoir, Tc = 0 degree C = 273 K

The efficiency of Carnot's heat engine is

\(\eta = 1-\frac{Tc}{T_H}\\\\\eta = 1 -\frac{273}{373}\\\\\eta = 0.268 =26.8 %\)

The efficiency of Carnot's heat engine is 26.8 %.

Kinetic energy = 1/2 x mass x velocity^2

Where:

Kinetic energy = 1 J

mass = 1 kg

Isolate v (speed)

KE = 1/2 m v^2

√(2KE/m) = v

v = √(2KE/m)

Replacing with the values given:

v = √(2*1/1)

v= √2 = 1.4 m/s

Answer: 1.4 m/s (B)

Answer:

The magnitude and direction of the rocket acceleration is 68.89 m/s² upward.

The speed of the rocket at the given elevation is 186 m/s.

Explanation:

Given;

time to reach the given height, t = 2.7 s

height reached, h = 93 m

initial velocity of the rocket, u = 0

The magnitude and direction of the rocket acceleration is calculated as;

h = ut + ¹/₂at²

h = 0 + ¹/₂at²

h = ¹/₂at²

a = 2h / t²

a = (2 x 93) / 2.7

a = 68.89 m/s²

the direction of the acceleration is upward.

The speed at this elevation, V = u + at

V = at

V = 68.89 x 2.7

V = 186 m/s

Answer:

a. 365; b. 3; c. 78; d. 1.343 rad; e. 12; f. 10.66

Explanation:

Assume that the function is

\(D(x) = 3 \sin \left (\dfrac{2\pi}{365}(x - 78) \right ) + 12\)

The general formula for a sinusoidal function is

      y = A sin(B(x - C))+ D

   |A| = amplitude

     B = frequency

2π/B = period, P

     C = horizontal shift (phase shift)

     D = vertical shift

By comparing the two formulas, we find

|A| = 3

 B = 2π/365

 C = 78

 D = 12

a. Period

P = 2π/B = 2π/(2π/365) = 2π × 365/2π = 365

The period is 365.

b. Amplitude

|A| = 3

The amplitude is 3.  

c. Horizontal shift

C= 78

The horizontal shift is 78.

d. Phase shift  (φ)

Ths phase shift is the horizontal shift expressed in radians.

φ = C × 2π/365 = 78 × 2π/365 ≈ 1.343

The phase shift is 1.343 rad.

e. Vertical shift

D = 12

The vertical shift is 12.

f. Hours of sunlight on Feb 21

Feb 21 is the 52nd day of the year, so x = 51 (the number of days after Jan 1),

\(\begin{array}{rcl}D(x) &=& 3 \sin \left (\dfrac{2\pi}{365}(x - 78) \right ) + 12\\\\&=& 3 \sin (0.01721(51 - 78) ) + 12\\&=& 3\sin(-0.4648) + 12\\&=& 3(-0.4482) + 12\\\&=& -1.345 + 12\\& = & \textbf{10.66 h}\\\end{array}\)

There will be 10.66 h of sunlight on Feb 21 of any given year.

The figure below shows the graph of the function from 0 ≤ x ≤ 365.

If large areas of land were clear-cut, the evaporation of water from the soil would increase and the local hydrologic cycle would change.

The hydrological cycle is impacted by deforestation because more precipitation falls to the ground and is not absorbed by trees, which causes groundwater levels to rise as a result of nothing obstructing the water's path, prevents transpiration because there are no leaves to do so, and ultimately results in contaminated runoff.

As a result of rising global temperatures, the earth's surface warms, which increases evaporation and increases the capacity of the earth to hold water.

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Answer:

a)  τ = 421.9 N m,  b)   F = 168.76 N

Explanation:

For this exercise we use Newton's second law for rotational motion

          τ = I α

Let's find the angular acceleration with kinematics

           w = w₀ + α t

as part of rest its initial angular velocity is zero wo = 0

           α= w / t

let's reduce the magnitudes to the SI system

            w = 15 rpm (2π rad / 1 rev) (1 min / 60s) = 1.57 rad / s

let's calculate

            α = 1.57 /10

            α = 0.157 rad / s²

Now let's look for the moment of inertia, which is the sum of the moment of inertia of the disk plus the moment of the children

disk moment                   I₁ = ½ M r²

moment of each child      I₂ = m r²

             I = I₁ + 2 I₂

             I = ½ M r² + 2 m r²

we substitute

             τ = (½ M r2 + 2 m r2) alpha

             τ = r² (½ M + 2 m) α

             τ = 2.5² (760/2 + 2 25) 0.157

             τ = 421.9 Nm

What force is applied

          τ = F r

          F = τ / r

          F = 421.9 / 2.5

          F = 168.76 N

Answer:

10 Newtons.

Explanation:

F=MA

F=(5kg)(2 m/s^2)

10 N

Answer:

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Explanation:

The mistakes in the results include options (v) and (vii) which do not follow the five golden rules for reporting results.

The five golden rules for reporting results are:

Using these rules, identify the mistakes in the given results as:

(v) 97.1 × 10³ ± 276Ω - The uncertainty is reported to an inappropriate number of significant figures and the units are not consistent.

(vii) 98.6 × 10³ ± 3 × 10^(-Q) - The uncertainty is not reported to the same number of decimal places as the measured value, and the units are not consistent.

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Answer:

The answer is "0.2711  m/s".

Explanation:

Potential energy = Kinetic energy + Potential energy

\(m_1 gh =\frac{1}{2} m_1v^2 +\frac{1}{2} m_2v^2 + \frac{1}{2} I\omega^2 + m_1gh\\\\\)

\((m_1- m_2)gh =\frac{1}{2} m_1v^2 +\frac{1}{2} m_2v^2 +\frac{1}{2} I\omega^2\\\\2(m_1 - m_2)gh = m_1v^2 + m_1v^2 + I\omega^2\\\\solid \ disk (I) = \frac{1}{2} \ \ M r^2 \\\\\)

When there is no slipping, \omega  =\frac{ v]{r}\\\\  

\(2(m_1 - m_2)gh = m_1v^2 + m_2v^2 + (\frac{1}{2} Mr^2) (\frac{v}{r})^2\\\\2(m_1 -m_2)gh = m_1v^2 + m_2v^2 + \frac{1}{2} Mv^2\\\\4(m_1 -m_2)gh = 2m_1v^2 + 2m_2v^2 + Mv^2\\\\4(m_1 - m_2)gh = (2m_1 + 2m_2 + M) v^2\\\\\)

\(v^2 = \frac{4(m_1 - m_2)gh}{(2m_1 + 2m_2 + M)}v\)

\(v^2 = \frac{4 (0.25 \ kg - 0.20 \ kg) (9.8 \frac{m}{s^2}) (0.21 m)}{ (2 \times 0.25 kg + 2 \times 0.20 kg + 0.50 kg)}\)

\(=\frac{0.1029}{1.4} \ \ \frac{m^2}{s^2}\\\\=0.0735\ \ \frac{m^2}{s^2}\\\\= 0.2711 \ \frac{m}{s}\)

The farther apart the two objects are, the weaker gravitational force they have. Conversely, the closer the objects are, the stronger the gravitational force between them.

What is gravitational force?

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