Answers
Hello there. To solve this question, we'll have to remember some properties about polygons.
We have to indicate the meaning of the following shapes:
1. Rectangle
This is a case of a 4-sided polygon, with 4 right angles on its corners and two parallel sides with measures called length and width, say L and W.
The sketch is as follows:
2. Square
As a special case of the rectangle, it is another 4-sided polygon with right angles on its corners, but this time the length and the width are the same, therefore all its sides have the same measure.
The sketch is as follows:
Related Questions
Brian set his compass equal to the radius of circle C and drew two circles centered at points A and B on circle C. He labeled the points of intersection of the two circles as shown.
Two circles are drawn by having another circle in the center. The center circle has points A, M, N, B, P, Q, and C. At C the two circles intersect, and at P the center circle and the top circle intersect.
To complete his construction, Brian only needs to use his straightedge to draw some chords of circle C.
Which figures could Brian be constructing?
equilateral triangle MNQ inscribed in circle C
equilateral triangle ANP inscribed in circle C
regular hexagon AMNBPQ inscribed in circle C
square MNPQ inscribed in circle C
square ANBQ inscribed in circle C
Answers
The correct options that could be constructed by Brian using his straightedge to draw some chords of circle C are:
Equilateral triangle MNQ inscribed in circle C
Regular hexagon AMNBPQ inscribed in circle C
Brian is constructing figures inscribed in circle C.
Equilateral triangle MNQ inscribed in circle C:
This option is possible since the points M, N, and Q are labeled and they lie on circle C.
Equilateral triangle ANP inscribed in circle C:
This option is not possible. The points A and P are labeled, but the third vertex of the equilateral triangle is not specified.
Regular hexagon AMNBPQ inscribed in circle C:
This option is possible since the points A, M, N, B, P, and Q are labeled and they lie on circle C.
Square MNPQ inscribed in circle C:
This option is not possible based on the given information. The label points do not form a square.
Square ANBQ inscribed in circle C:
This option is not possible . The points A, N, B, and Q are labeled, but they do not form a square.
The correct options that could be constructed by Brian using his straightedge to draw some chords of circle C are:
Equilateral triangle MNQ inscribed in circle C
Regular hexagon AMNBPQ inscribed in circle C
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Help me please for me it’s confusing
Answers
Answer:
-∞ < x < 0
Step-by-step explanation:
The domain is the horizontal extent of the graph.
The arrow at upper left means the graph extends to infinity upward and to the left.
The open circle on the y-axis means the value x=0 is not included in the domain.
So, the graph extends from -∞ to as close to zero as you like:
domain: -∞ < x < 0
HELP THIS IS MY LAST CHANCE
If the vertical length is 10 , what is the horizontal length?
Answers
Answer:
5
Step-by-step explanation:
because its the correct answer
Answer:
Its 5 :D have a nice day and dont forget that brainliest nah jk you can if you want lol
Step-by-step explanation:
Hello, I need some assistance with this homework question please for precalculusHW Q35
Answers
The given polynomial function is:
\(f(x)=-2(x-1)(x+3)^2\)a. Find any real zeros of f.
To find the real zeros, we need to find the x-values that make each of the factors equal to zero, so, the factors of the polynomial function are:
\(\begin{gathered} -2 \\ (x-1) \\ (x+3)^2 \end{gathered}\)Equal (x-1) and (x+3) to zero and solve for x:
\(\begin{gathered} x-1=0 \\ x=1\text{ Real zero} \\ x+3=0 \\ x=-3\text{ Real zero} \end{gathered}\)The real zeros of f are 1,-3
The multiplicity is given by the power of the factor, then 1 has multiplicity 1 and -3 has multiplicity 2, so:
The multiplicit of the larger zero is 1
The multiplicity of the smaller zero is 2
b. Determine whether the graph crosses or touches the x-axis at each x-intercept.
When multiplicity is even the graph touches the x-axis and when is odd the graph crosses the x-axis.
Then, the graph crosses the x-axis at the larger x-intercept.
The graph touches the x-axis at the smaller x-intercept.
c. The maximum number of turning points is determined by the degree of the polynomial, we can rewrite the polynomial as:
\(\begin{gathered} f(x)=(-2x+2)(x+3)^2 \\ f(x)=(-2x+2)(x^2+2*3*x+3^2) \\ f(x)=(-2x+2)(x^2+6x+9) \\ f(x)=-2x*x^2-2x*6x-2x*9+2x^2+2*6x+2*9 \\ f(x)=-2x^3-12x^2-18x+2x^2+12x+18 \\ f(x)=-2x^3-10x^2-6x+18 \end{gathered}\)The degree (n) is the greatest power, then this polynomial is degree n=3, and the number of turning points is given by n-1, so:
The maximum number of turning points on the graph is 2
d. Type the power function that the graph of f resembles for large values of |x|
We can apply the end behavior theorem which states: for larger values of |x| the graph of the polynomial:
\(f(x)=a_nx^n+a_{n-1}x^{n-1}+...+a_1x+a_0\)resembles the graph of the power function:
\(y=a_nx^n\)Thus, the power function that the graph of f resembles for larger values of |x| is:
\(y=-2x^3\)determine 3x4 2x5 if x1, x2, x3, x4, and x5 satisfy the system of equations given below: 2x1 x2 x3 x4 x5
Answers
On solving the linear equations we get the result as
x1 + x2 − 2x3 + 3x4 + 2x5 = 6
3x1 + 3x2 − x3 + x4 + x5 = 12
2x1 + 2x2 − x3 + x4 − 2x5 = 5
4x1 + 4x2 + x3 +0x4 − 3x5 = 16
8x1 + 5x2 − 2x3 − x4 + 2x5 = 29
where ,
x1 = 5,x2 = -1, x3 = 3 ,x4 = 2 , x5 = 1
Finding the value of an equation's unknown variable can be done by solving the equation. If an equation contains a "equal to" sign, it is considered to be balanced. This equation so shows that the two quantities on both sides of it are equal. Left hand side and right hand side are the two sides of the equation (Right hand side).
One equation is x - 4 = 5, for instance. It illustrates that x - 4 (LHS) = 5. (RHS). Here, x is an unknowable quality or variable. Therefore, in order to determine the value of x, we must solve this equation.
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Hiromi goal is to collect 40 dollars for a school fundraiser he has already collected 26.50 dollars Hiromi wants to know how much more money he needs to collect
Answers
he needs to collect 40-26.50=13.50 dollars more
Find the arc length parameter along the curve from the point where t=0 by evaluating the integral s= V(T) dt. Then find the length of the indicated portion of the curve.
r(t) = (4 + 5t)i + (8 + 2t)j + (2 - 7t)k, -1sts
Answers
The arc length parameter along the curve from the point where t = 0 by evaluating the integrals s is equal to \(\sqrt{54}\) and the length of the indicated portion of the curve is \(\sqrt{54}+1\)
To find the arc length parameter along the curve, to evaluate the integral of the magnitude of the velocity vector with respect to t.
The velocity vector is the derivative of the position vector r(t) with respect to t:
\(v(t) = dr/dt\)
Plugging value of r into v
\(v(t) = 5i + 2j - 7k\)
Now, to find the magnitude of the velocity vector:
\(|v(t)| = \sqrt{5^2 + 2^2 + (-7)^2}\)
On adding gives:
\(|v(t)| = \sqrt{54}\)
The arc length parameter s is given by the integral of |v(t)| with respect to t with the limits from t = 0 to t = 1
\(s = \int_{t=0}^1 |v(t)| dt\)
Plugging the values of v(t) in the above equation:
\(s = \int_0^1\sqrt{54}\,dt\)
Take out the constant from the integral sign results:
\(s = \sqrt{54} \int_0^1\,dt\)
On integrating gives:
\(s = \sqrt{54}\times t |_{0}^1\)
on multiplying gives:
\(s = \sqrt{54} t |_{0}^s\)
Evaluated limits from t = 0 to t = 1:
\(s = \sqrt{54} (1-0).\)
On multiplying inside the brackets gives:
\(s = \sqrt{54} \times 1 - \sqrt{54} \times 0\)
Simplifying further:
\(s = \sqrt{54} \times 1\)
On multiplying with 1 gives:
\(s = \sqrt{54}\)
Now, given that the curve is traversed from t = -1 to t = s,
so the length of the indicated portion of the curve is simply:
\(s - (-1)\):
Length \(= s - (-1) \\= s + 1 \\= \sqrt{54} +1\)
Therefore, arc length parameter along the curve from the point where t = 0 by evaluating the integrals s is equal to \(\sqrt{54}\) and the length of the indicated portion of the curve is \(\sqrt{54}+1\).
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Help Lesson 11 & 12: A shop sells bagels for $5 per dozen. At this rate, how much would 6 bagels cost? Your answer is a dollar amount, so it must have a number to the left of the decimal and two numbers to the right of the decimal. (Example: $5.50 would be entered as 5.50) *
Answers
Calc II Question
Find the volume of the solid obtained by rotating the region bonded bt the given curves about the specified line.
Y = In x
Y = 1
Y = 2
X = 0
About the Y axis
Answers
Work attached in image. Since the solid is being rotated about the y-axis, you would need to solve y=lnx in terms of x. The rest of the process is showed in the image.
Find the quotient and express the answer in scientific notation. 302 ÷ (9.1 x 10^4 )
Answers
The quotient of 302 ÷ (9.1 x \(10^4)\) in scientific notation is approximately 3.31868131868 x \(10^1\)
How to find the quotientDividing 302 by 9.1 gives:
302 ÷ 9.1 ≈ 33.1868131868
Now, to express this result in scientific notation, we need to move the decimal point to the appropriate position to create a number between 1 and 10. In this case, we move the decimal point two places to the left:
33.1868131868 ≈ 3.31868131868 x\(10^1\)
Therefore, the quotient of 302 ÷ (9.1 x \(10^4\)) in scientific notation is approximately 3.31868131868 x\(10^1\)
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¿De qué número 64 es el 80%?
Answers
What is the M.A.D. (mean absolute deviation) of the following data set?
8 9 9 7 8 6 9 8
Answers
The mean absolute deviation is 0.75
How to determine the mean absolute deviationTo calculate the mean absolute deviation (M.A.D.), you need to find the average of the absolute differences between each data point and the mean of the data set
From the information given, we have that the data set is;
8 9 9 7 8 6 9 8
Let's calculate the mean, we get;
Mean = (8 + 9 + 9 + 7 + 8 + 6 + 9 + 8) / 8
Mean = 64 / 8
Divide the values
Mean = 8
Let's determine the absolute difference, we get;
Absolute differences=
|8 - 8| = 0
|9 - 8| = 1
|9 - 8| = 1
|7 - 8| = 1
|8 - 8| = 0
|6 - 8| = 2
|9 - 8| = 1
|8 - 8| = 0
Find the mean of the absolute differences:
Average of absolute differences = (0 + 1 + 1 + 1 + 0 + 2 + 1 + 0) / 8
Absolute difference = 6 / 8 = 0.75
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what is the smallest number to be subtracted from 9610,so that the remainder will be a perfect square
Answers
Answer:
Hello,
Answer 6
Step-by-step explanation:
\(\sqrt{9610} =98,03060...\\\\ENT(\sqrt{9610})=98\\\\9610-98^2=9610-9604=6\\\\\)
The smallest number to be susbtracted is 6
PLEASE HELP ILL GIVE BRAINLIESTTTT
Answers
Answer:
A’ = (-2, 1.5)
B’ - (2, 1.5)
C’ - (-2, -2)
D- (2, -2)
Step-by-step explanation:
A - (-4, 3)
B- (4, 3)
C - (-4, -4)
D- (4, -4)
A’ = (-2, 1.5)
B’ - (2, 1.5)
C’ - (-2, -2)
D- (2, -2)
Answer:
have a look at the attachment image......
if dilatation center is A, connect all of the the alphabet (B, C, D)to A and the scale factor is 1 by 2. so make a dot in the middle of line that is connected to dilatation center....
if the line is D to A then the dot on the line D will be D prime.... same like that find C and B prime
if you don't understand let me know in the comments
Help me plssssss ASAP
Answers
Answer No Can not help in I-Ready Diagnostic That really counts as cheating and its state law to help with Diagnostics.
Step-by-step explanation:
Round 231469.335329 to the nearest thousand.
Answers
Answer:
Below
Step-by-step explanation:
231469.335329 to the nearest thousand. '1' is the thousand position
the '4' next to it says leave the '1' alone to get
231000 rounded to nearest thousand.
1 is the thousands place and the number to the right is 4. Because 4 is under 5, the number 1 will remain 1 and the rounded number will be 231,000
In circle O, secants ADB and AEC are drawn from external point A
such that points D, B, E, and C are on circle O. If AD = 8, AE = 6,
and EC is 12 more than BD, the length of BD is
(1) 6
(2) 22
(3) 36
(4) 48
Answers
The length of BD is 22.
In the given scenario, let's consider the following information.
AD = 8
AE = 6
EC is 12 more than BD.
To find the length of BD, we can utilize the Intercepted Arcs Theorem, which states that when two secants intersect outside a circle, the measure of an intercepted arc formed by those secants is equal to half the difference of the measures of the intercepted angles.
From the given information, we know that AD = 8 and AE = 6.
Since these are the lengths of the secants, we can use them to calculate the intercepted arcs.
First, let's find the intercepted arc corresponding to AD:
Intercepted Arc ADB = 2 \(\times\) AD = 2 \(\times\) 8 = 16
Similarly, we can find the intercepted arc corresponding to AE:
Intercepted Arc AEC = 2 \(\times\) AE = 2 \(\times\) 6 = 12
Now, we know that EC is 12 more than BD.
Let's assume the length of BD as x.
BD + 12 = EC
Now, let's consider the intercepted arcs theorem:
Intercepted Arc ADB - Intercepted Arc AEC = Intercepted Angle B - Intercepted Angle C
16 - 12 = Angle B - Angle C
4 = Angle B - Angle C.
Since Angle B and Angle C are vertical angles, they are congruent:
Angle B = Angle C.
Therefore, we can say:
4 = Angle B - Angle B
4 = 0
However, we have reached an inconsistency here.
The equation does not hold true, indicating that the given information is not consistent or there may be an error in the problem statement.
As a result, we cannot determine the length of BD based on the given information.
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You start at (0,-4). You move left 1 unit and right 4 units. where do you end?
Answers
If you start at (0,-4) and you move left 1 unit and right 4 units, you end at (3, -4)
Calculating the endpoint of the pointFrom the question, we have the following parameters that can be used in our computation:
Start = (0, -4)
Also, we have
You move left 1 unit and right 4 units
Mathematically, this can be expressed as
(x, y) = (x - 1 + 4, y)
Substitute the known values in the above equation, so, we have the following representation
Endpoint = (0 - 1 + 4, -4)
Evaluate the expression
Endpoint = (3, -4)
Hence, the endpoint is (3, -4)
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What is the final amount if 784 is decreased by 1% followed by a 4% increase?
Give your answer rounded to 2 DP.
Answers
Answer:
3136
Step-by-step explanation:
Thats the answer please I don't have time to write the explanation
Sam Long anticipates he will need approximately $225,300 in 12 years to cover his 3-year-old daughter's college bills for a 4-year
degree.
How much would he have to invest today at an interest rate of 8% compounded semiannually?
Answers
The amount of principal for the given situation is $87,894.37
What is compound interest?
The interest that is paid on both the initial principal and the accumulated past interest is known as compound interest.
The principal, interest rate, and time period are used to calculate compound interest.
Given, compound amount (A) = $225,300
time period (t) = 12 years
interest rate (r) = 8% = 0.08
compounded semiannually (n) = 2
principal amount (P) =?
Then. the compound amount is given by
\(A = P(1 + \frac{r}{n} )^{nt}\)
or, \(225300 = P(1 + \frac{0.08}{2} )^{2*12}\)
or, \(P= 225300/(1+0.04)^{24}\)
or, P = 87,894.37
Hence, the amount of investment today is $87,894.37
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Question 14 (Essay Worth 12 points)
(Comparing Data HC)
The stem-and-leaf plot displays data collected on the size of 15 classes at two different schools.
Sky View School
9, 7, 2,0
8, 7, 6, 5, 5, 5, 4, 3, 1, 0
0
1
South Lake School
5,8
0, 1, 2, 6, 6, 8
2
0 3
Key: 2|1|0 means 12 for Sky View and 10 for South Lake
5, 5, 6, 7, 8
0,6
Part A: Calculate the measures of center. Show all work. (5 points)
Part B: Calculate the measures of variability. Show all work. (5 points)
Part C: If you are interested in a smaller class size, which school is a better choice for you? Explain your reasoning. (2 points)
7
Answers
To find the measures of center, we need to determine the median for each school.
For Sky View School:
Arrange the data in order: 0, 0, 1, 2, 3, 4, 5, 5, 5, 6, 7, 7, 8, 9
The median is the middle value, which is 5.
For South Lake School:
Arrange the data in order: 0, 0, 1, 2, 2, 5, 6, 6, 8
The median is the middle value, which is also 5.
Therefore, the median class size for both schools is 5.
Part B: Measures of variability
To find the measures of variability, we need to determine the range and interquartile range (IQR) for each school.
For Sky View School:
The smallest value is 0 and the largest value is 9, so the range is 9 - 0 = 9.
To find the IQR, we need to find the first and third quartiles. The median is 5, so the first quartile is the median of the lower half, which is (0 + 1 + 2 + 3 + 4)/5 = 2. The third quartile is the median of the upper half, which is (6 + 7 + 8 +9)/4 = 7.25 (rounded to two decimal places).
Therefore, the IQR is 7.25 - 2 = 5.25.
For South Lake School:
The smallest value is 0 and the largest value is 8, so the range is 8 - 0 = 8.
To find the IQR, we need to find the first and third quartiles. The median is 5, so the first quartile is the median of the lower half, which is (0 + 0 + 1 + 2)/4 = 0.75 (rounded to two decimal places). The third quartile is the median of the upper half, which is (6 + 6 + 8)/3 = 6.67 (rounded to two decimal places).
Therefore, the IQR is 6.67 - 0.75 = 5.92 (rounded to two decimal places).
Part C: Choosing a school based on class size
If you are interested in a smaller class size, South Lake School is the better choice. This is because the range and IQR for South Lake School are smaller than those for Sky View School, indicating that the class sizes at South Lake School are more consistent and less variable. Additionally, the largest class size at South Lake School is 8, while the largest class size at Sky View School is 9, further indicating that South Lake School may have smaller class sizes overall.
Measures of center for Sky View School:
Mean = (0+1+2+3+4+5+5+5+6+7+7+8+9)/13
Mean = 4.8
Median = 5
Measures of center for South Lake School:
Mean = (0+1+2+2+3+5+6+6+8+8)/10
Mean = 4.1
Median = 5
Part B:
Measures of variability for Sky View School:
Range = 9 - 0 = 9
Interquartile Range (IQR) = Q3 - Q1 = 7 - 2 = 5
Variance = [(0-4.8)^2 + (1-4.8)^2 + (2-4.8)^2 + (3-4.8)^2 + (4-4.8)^2 + (5-4.8)^2 + (5-4.8)^2 + (5-4.8)^2 + (6-4.8)^2 + (7-4.8)^2 + (7-4.8)^2 + (8-4.8)^2 + (9-4.8)^2]/12
Variance = 7.6
Standard Deviation = √7.6
Standard Deviation = 2.76
Measures of variability for South Lake School:
Range = 8 - 0 = 8
Interquartile Range (IQR) = Q3 - Q1 = 6 - 1 = 5
Variance = [(0-4.1)^2 + (1-4.1)^2 + (2-4.1)^2 + (2-4.1)^2 + (3-4.1)^2 + (5-4.1)^2 + (6-4.1)^2 + (6-4.1)^2 + (8-4.1)^2 + (8-4.1)^2]/9
Variance = 6.45
Standard Deviation = √6.45
Standard Deviation = 2.54
Part C:
If you are interested in a smaller class size, South Lake School is a better choice for you. This is because the measures of center and variability for South Lake School are both smaller than those for Sky View School.
A researcher wants to find out if there is a significant difference between men and women in the average number of tattoos that a person has. After doing the statistical analysis, the researcher finds that the p-value is 0.003. If the chosen significance level is 0.05 (5%), which of the following statements is the best interpretation of this p-value?A. The results are statistically significant.B. The results are not statistically significant.
C. The magnitude of a p-value has no impact on statistical significance.
Answers
Answer:
The correct option is (A).
Step-by-step explanation:
The p-value is well-defined as per the probability, [under the null-hypothesis (H₀)], of attaining a result equivalent to or more extreme than what was the truly observed value of the test statistic.
A small p-value (typically p < 0.05) specifies strong evidence against the null hypothesis (H₀), so the null hypothesis is rejected. A p-value less than 0.05 is considered as statistically significant.
A large p-value (p > 0.05) specifies fragile proof against the H₀, so the null hypothesis is failed to be rejected.
In this case the p-value of the test is,
p-value = 0.003
And the significance level of the test was,
α = 0.05.
p-value = 0.003 < α = 0.05.
The p-value less than the significance level of the test.
Thus, the results are statistically significant.
The correct option is (A).
Why is it essential to know how to solve Exponential equations in order to solve Logarithmic equations? (Make sure to fully explain).
Answers
Answer:
Because you need it for your later life and for your GCSES and if you dont want to fail then you will need it.
Step-by-step explanation:
Given an exponential equation in which a common base cannot be found, solve for the unknown. Apply the logarithm of both sides of the equation. If one of the terms in the equation has base 10, use the common logarithm. If none of the terms in the equation has base 10, use the natural logarithm.
what is the value of x?
Answers
Answer:
x=4
Step-by-step explanation:
By SAS we know that
\(\triangle ABE \sim \triangle ADC\)
by a ratio of
\(1:2\)
so we have
\(\frac{BE}{DC}=\frac{1}{2}\\\\2BE=DC\\\\2(x+2)=12\\\\2x+4=12\\\\2x=12-4\\\\2x=8\\\\x=4\)
the least common multiple of the two numbers is 40 the ratio of the greater number is the to the lessor number is 5, 4
Answers
if 40 is the least frequent multiple of two whole numbers. The higher number to lesser number ratio is 4:5. The two digits after that are 8 and 10.
What is Least Common Multiple (LCM)?Least Common Multiple is the meaning of the abbreviation LCM.
The lowest number that may be divided by both numbers is known as the least common multiple (LCM) of two numbers.
It can also be computed using two or more numbers.
Finding the LCM of a given collection of numbers can be done in a variety of ways.
Utilizing the prime factorization of each number and then calculating the product of the greatest powers of the shared prime factors is one of the quickest techniques to determine the LCM of two numbers.
In mathematics, the least common multiple is sometimes referred to as LCM or the lowest common multiple.
The smallest number among all numbers is called the least common multiple of two or more numbers.
According to our question-
The number LCM is equal to 40.
4 × 5 × x = 40
20 × x = 40
20x=40
x=2
The larger number is equal to 4 x=4(2)=8.
The smaller value is =5x=5(2)=10.
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Complete question-
The least common multiple of two whole numbers is 40. The ratio of the greater number to the lesser number is 4:5. What are the two numbers?
How many units are there between point A (-3,80) and point B (-3,12)
Answers
Answer:
68 units
Step-by-step explanation:
Given:
Point A = (-3, 80)Point B = (-3, 12)As the x-values of points A and B are the same (x = -3), the line through points A and B is vertical.
Therefore, to find the distance between the two points, simply subtract the y-value of point B from the y-value of point A:
\(\sf distance=y_A-y_B=80-12=68 \ units\)
Domain:
O-85x<0 or 0
O-85x50or 0≤x≤2
O 1
O 2
Answers
The domain and the range of the piecewise function in this problem are given as follows:
Domain: -6 ≤ x < 0 or 0 < x ≤ 2.Range: 0 ≤ y < 1 or 1 < y ≤ 6.How to obtain the domain and range of a function?The domain of a function is defined as the set containing all the values assumed by the independent variable x of the function, which are also all the input values assumed by the function.The range of a function is defined as the set containing all the values assumed by the dependent variable y of the function, which are also all the output values assumed by the function.The function in this problem is defined for all values of x between -6 and 2, except x = 0, and assumes all values of y between 0 and 6, except y = 1, hence the domain and range are given as follows:
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What is the ratio of x to y?
5x = 6y
Answers
Answer:
6:5
Step-by-step explanation:
Divide both sides by y . ⇒5xy=6y y. ⇒5xy=6. Divide both sides by 5 . ⇒5 x5 y=65. ⇒xy=65. ⇒x:y=6:5.
The ratio between x and y, when 5x = 6y, is 6:5.
Given is an equation 5x = 6y, we need to find the ratio between x and y,
To determine the ratio of x to y in the equation 5x = 6y, we need to isolate one of the variables and express it in terms of the other.
Let's isolate x:
5x = 6y
Divide both sides of the equation by 5:
x = (6y) / 5
Now we have an expression for x in terms of y. The ratio of x to y can be represented as:
x/y = (6y) / (5y)
The y terms cancel out:
x/y = 6/5
Therefore, the ratio of x to y is 6:5.
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The table shows the number of sodas left in the vending machine after each hour.
Time in Hours
0
1
2
3
Number of Sodas 310 290 270 250
If the pattern stays the same, which expression gives the number of sodas left after t hours?
A. 250 - 200
B. 290 - 200
C. 310 - 20t
D. 330 - 200
Answers
Answer: A
Step-by-step explanation: -20
Which type of information could best be displayed on a two-way frequency table? Select all that apply.
A the number of library books, by genre, borrowed by children and adults during the summer
B the amount of rainfall each week during a year
c the number of daylight hours each day for a month
D the number and type of meals students choose in a lunchroom
Answers
Answer: B C and D
Step-by-step explanation: