convert 174% to a decimal
Please answer fast​

Total pounds of potatoes sold = $1420 / $1.75 = 811.43 lbs. Converting to kilograms: 811.43 lbs * 0.4536 kg/lb = 368.23 kg. Grocery shoppers bought approximately 368.23 kg of potatoes.

 To determine the number of kilograms of potatoes grocery shoppers bought, we need to convert the total weight from pounds to kilograms.

First, let's find out how many pounds of potatoes were sold:

Total sales = $1420

Price per pound = $1.75

Number of pounds of potatoes sold = Total sales / Price per pound

Number of pounds of potatoes sold = $1420 / $1.75

Number of pounds of potatoes sold = 811.43 pounds (approximately)

Now, to convert pounds to kilograms, we know that 1 pound is approximately 0.4536 kilograms.

Number of kilograms of potatoes sold = Number of pounds of potatoes sold * 0.4536

Number of kilograms of potatoes sold = 811.43 pounds * 0.4536

Number of kilograms of potatoes sold = 368.23 kilograms (approximately)

Therefore, grocery shoppers bought approximately 368.23 kilograms of potatoes.

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z does not necessarily lie between x and y on the number line.

In order to determine if z lies between x and y on the number line, we need to compare the distances between these points.

Statement 1: xyz < 0

This statement does not provide any direct information about the relative positions of x, y, and z on the number line. It only indicates that the product of x, y, and z is negative. However, this does not give us any information about the specific values or their positions on the number line.

Statement 2: xy < 0

This statement tells us that the product of x and y is negative. This means that x and y have opposite signs, indicating that they lie on opposite sides of zero on the number line. However, this statement still does not give us any information about the position of z relative to x and y.

Therefore, neither statement alone is sufficient to determine whether z lies between x and y on the number line.

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Distance between two points \((-3, 4)\) and \((5, -2)\) is \(10\) units.

Mid-point of the line segment joining \((-1, -5)\) and \((7, 1)\) is  \((3, -2)\).

Degree of the given polynomial is \(7\).

6) Distance between two points \((x_1, y_1)\) and \((x_2, y_2)\) is:

\(\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)

So, distance between two points \((-3, 4)\) and \((5, -2)\) is:

\(=\sqrt{(5-(-3))^2+(-2-4)^2}\)

\(=\sqrt{(8)^2+(-6)^2}\)

\(=\sqrt{64+36}\)

\(=\sqrt{100}\)

\(=10\)

So, option D is correct.

7) Mid-point of the line segment joining \((x_1, y_1)\) and \((x_2, y_2)\) is:

\((\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})\)

Mid-point of the line segment joining \((-1, -5)\) and \((7, 1)\) is:

\((\frac{-1+7}{2}, \frac{-5+1}{2})\)

\(= (\frac{6}{2}, \frac{-4}{2})\)

\(= (3, -2)\)

So, option A is correct.

8) Degree of a polynomial is the highest power of the variable in the polynomial.

\(f(x)=3x^2-7x^4+9x^7+2x^3\)

Here, the highest power of the variable is \(7\).

So, option B is correct.

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Answer:

3.2seconds

Step-by-step explanation:

Step one:

Robert run the 100 meter dash in 13.5 seconds

We are told that he later  run same distance in 10.3 seconds

Required.

The time difference in the first dash and the second

Step two:

The first dash took 13.5 seconds

the second took 10.3 seconds

the difference = 13.5-10.3= 3.2seconds

Answer:

\({ \tt{27 = {3}^{3} }} \\ { \tt{}} \sqrt[4]{27} = {27}^{ \frac{1}{4} } \\ { \tt{ = {3}^{3( \frac{1}{4}) } }} \\ = { \tt{ {3}^{ \frac{3}{4} } }} \\ { \boxed{ \bf{a = 3 \: \: and \: \: k = \frac{3}{4} }}}\)

The car was driven 105 miles.

What is rent?

An agreement where a fee is paid for the temporary use of a good, service, or property owned by another is known as renting, sometimes known as hiring, or letting.

In the given example the cost function is, c = 15 + 2m

Where, c is the total cost and m is the number of miles car driven.

The total cost was $225.

So, plug c = $225 in the above equation.

225 = 15 + 2m

210 = 2m

   m = 105

Therefore, the car was driven 105 miles.

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Step-by-step explanation: Stretches and compression change the slope of a linear function.

If the line becomes steeper, the function has been stretched vertically or compressed horizontally.

If the line becomes flatter, the function has been stretched horizontally or compressed vertically.

Horizontal Stretch/Compression by a factor of b

f(x)→ f(1• f(x→f(1 bx) • b > 1 stretches away from the y-axis.

• 0 < |b| < 1 compresses toward the y-axis.

• y-intercepts remain the same.

Vertical Stretch/Compression by a factor of a

• f(x) → a f(x) • a > 1 stretches away from the x-axis.

• 0 < |a| < 1 compresses toward the x-axis.

• x-intercepts remain the same.Stretches and compression's change the slope of a linear function.

If the line becomes steeper, the function has been stretched vertically or compressed horizontally.

If the line becomes flatter, the function has been stretched horizontally or compressed vertically.

Horizontal Stretch/Compression by a factor of b

• f(x)→f(1 bx) • b > 1 stretches away from the y-axis.

• 0 < |b| < 1 compresses toward the y-axis.

• y-intercepts remain the same.

Vertical Stretch/Compression by a factor of a

• f(x) → a f(x) • a > 1 stretches away from the x-axis.

• 0 < |a| < 1 compresses toward the x-axis.

• x-intercepts remain the same.Stretches and compression change the slope of a linear function.

If the line becomes steeper, the function has been stretched vertically or compressed horizontally.

If the line becomes flatter, the function has been stretched horizontally or compressed vertically.

Horizontal Stretch/Compression by a factor of b

• f(x)→f(1 bx) • b > 1 stretches away from the y-axis.

• 0 < |b| < 1 compresses toward the y-axis.

• y-intercepts remain the same.

Vertical Stretch/Compression by a factor of a

• f(x) → a f(x) • a > 1 stretches away from the x-axis.

• 0 < |a| < 1 compresses toward the x-axis.

• x-intercepts remain the same.

Answer:

f=-27, hope this helped my love have a good rest of your day ^^

Step-by-step explanation:

subtract 24 from both sides

the you get f=-27

A pound is a unit of weight commonly used in the United States, while grams are a unit of weight commonly used in the metric system. To convert between the two units, it's important to know that 1 pound is equal to approximately 453.59 grams.

To find out how many grams are in a half pound, you can use the conversion factor of 1 pound = 453.59 grams. To convert a measurement in pounds to grams, you multiply the number of pounds by 453.59. So, to find out how many grams are in a half pound, you would multiply 0.5 (which is half of 1) by 453.59.

The calculation is 0.5 * 453.59 = 226.795 grams. So, there are 226.795 grams in a half pound.

It's also important to note that when measuring smaller or larger quantities, it's important to use the correct units. For example, a small weight like a gram is more appropriate for measuring the weight of a small object like a paperclip, while a larger unit like a pound would be more appropriate for measuring the weight of a bag of flour.

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It should be noted that the number of hours slept will have to be plotted on the x-axis.

Also, the number of mistakes that was made will be plotted on the y-axis.

Each point on the scatterplot will represent one participant in the study.

It should be noted that to illustrate the two variables given in Table 1, we can create a scatterplot using R code.

In this case the number of hours slept will have to be plotted on the x-axis, and the number of mistakes made will be plotted on the y-axis.

Looking at the scatter plot, we can see that there is a general trend that more hours of sleep are associated with fewer mistakes made.

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a. The impulse response can be determined as \(h[n] = a^(^(^n^-^D^)u[n-D])u[n-D]\) where u[n] is the unit step function.

b. The magnitude response of the IIR filter exhibits D peaks and D dips over 0 ≤ ω < 2π, with values and locations depending on D and a.

c. The impulse and magnitude responses for D = 5, a = 0.9 and D = 8, a = -0.8 can be plotted to visualize the filter's behavior.

The impulse response of the comb filter, denoted as h[n], can be expressed as \(h[n] = a^(^(^n^-^D^)u[n-D])u[n-D]\), where a is a constant between -1 and 1, D represents the sample spacing between echoes, and u[n] is the unit step function. This function describes the decaying amplitudes of infinite echoes generated by the comb filter. By substituting the given values of D = 4 and a = 0.8, the impulse response can be computed using MATLAB to verify its accuracy.

Moving on to the magnitude response of the IIR filter, it exhibits D peaks and D dips over the frequency range 0 ≤ ω < 2π, where ω represents the angular frequency. The exact values and locations of these peaks and dips depend on the specific values of D and a. To determine them, further calculations need to be performed, and the results can be verified by plotting the magnitude response using the provided values of D = 4 and a = 0.8.

To gain a better understanding of the filter's behavior, additional plots can be generated for different parameter values. For instance, by considering D = 5 and a = 0.9, or D = 8 and a = -0.8, both the impulse and magnitude responses can be visualized. These plots provide insights into how changes in D and a affect the filter's characteristics.

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Answer:

640

Step-by-step explanation:

Answer:

640

Step-by-step explanation:

Changes made to your input should not affect the solution.

0.61" was replaced by "(61/100)". 2 more similar replacement(s)

S) 61/100

To divide fractions, write the division as multiplication by the reciprocal of the divisor

Answer: slope is negative 1

Step-by-step explanation:

Answer:

Step-by-step explanation:

This is classic right triangle trig. If you're solving for x, which you are, you have to consider how the given sides relate to that angle. The side with a length of 50 is opposite the angle x, while the side of length 36 is adjacent to angle x. The trig ratio that utilizes the sides opposite and adjacent is tangent; HOWEVER, we are looking for a missing angle. Finding missing angles on your calculator requires the 2nd button. To find the missing angle x, you are looking for the angle that has a tangent ratio of 50 over 36 (opposite over adjacent...Toa in SohCahToa). Hit the 2nd button on your calculator and then the tangent button (in degree mode, not radian mode) and you will see this on your screen:

\(tan^{-1}(\)

After the parenthesis, enter the fraction and then hit the enter button to get the angle measure in degrees:

\(tan^{-1}(\frac{50}{36})=54.2\) degrees.

It's very important that you learn how to use your calculator to find the trig identities that give you the ratio in decimal form and how to find the missing angles. Missing angles always use the 2nd button along with whatever trig identity you are using.

To prove that two triangles are similar, one of the following conditions must be satisfied: 1) Three pairs of corresponding sides are proportional (SSS Similarity), 2) Two pairs of corresponding sides are proportional and the included angles are congruent (SAS Similarity), or 3) Two pairs of corresponding angles are congruent (AA Similarity).

SSS Similarity: If we can show that the ratios of the corresponding sides of two triangles are equal, then the triangles are similar. For example, if the ratios of the lengths of the corresponding sides of triangle ABC and triangle DEF are AB/DE, BC/EF, and AC/DF, and these ratios are equal, then the triangles are similar.

SAS Similarity: If we can prove that two pairs of corresponding sides of the triangles are proportional and the included angles between them are congruent, then the triangles are similar. For example, if AB/DE = BC/EF and angle BAC = angle EDF, then triangles ABC and DEF are similar.

AA Similarity: If we can demonstrate that two pairs of corresponding angles in the triangles are congruent, then the triangles are similar. For example, if angle A in triangle ABC is congruent to angle D in triangle DEF, and angle B in triangle ABC is congruent to angle E in triangle DEF, then the triangles are similar.

It is important to note that proving similarity based on these conditions does not require measuring the actual lengths of the sides or angles but rather establishing the proportional relationships or congruence between them.

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The equation is $1.75+$0.85m= $8.75, after solving the value m =8.24 miles.

An algebraic expression contains one or more variables along with numbers show the equality among them.

we use equation to determine an unknown value. we create equation based on a mathematical statement and finally solve it.

The following is the solution of equation of the statement given in question.

Given, fee per mile = $0.85

Charges = $1.75

Total cost of ride = $8.75

let, m is the number of miles travelled

Now, the equation is $1.75+$0.85m = $8.75

                  after solving     0.85m = 7.00

                             m = 8.24 miles

hence, the Uber travelled 8.24 miles

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The equation is equivalent to the r = d/t.

There are numerous ways in which one may define an equation. In its simplest form in algebra, the definition of an equation is a mathematical statement that shows that two mathematical expressions are equal. Equations are mathematical statements containing two algebraic expressions on both sides of an 'equal to (=)' sign. It shows the relationship of equality between the expression written on the left side with the expression written on the right side. In every equation in math, we have, L.H.S = R.H.S (left hand side = right hand side). Equations can be solved to find the value of an unknown variable representing an unknown quantity. If there is no 'equal to' symbol in the statement, it means it is not an equation. It will be considered as an expression.

We have to find which equation is equivalent to the formula d = rt.

Formula given: d = rt

Divide both sides by t

d/t = rt / t

d/t = r

Thus, the equation is equivalent to the r = d/t.

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The function f(x) = –2x^3 + 39x^2 -216x + 6 has one local minimum at x = 4 and one local maximum at x = 9.

To determine if the function f(x) = –2x^3 + 39x^2 -216x + 6 has a local minimum or maximum, we need to find the critical points of the function and then determine the nature of those critical points.

First, we take the derivative of the function to find the critical points:

f(x) = –2x^3 + 39x^2 -216x + 6

f'(x) = –6x^2 + 78x - 216

f'(x) = –6(x^2 - 13x + 36)

f'(x) = –6(x - 4)(x - 9)

Setting f'(x) = 0, we get:

–6(x - 4)(x - 9) = 0

This gives us two critical points at x = 4 and x = 9.

To determine the nature of these critical points, we need to look at the sign of the derivative on either side of each critical point.

When x < 4, we have:

f'(x) = –6(x^2 - 13x + 36) < 0

When 4 < x < 9, we have:

f'(x) = –6(x^2 - 13x + 36) > 0

When x > 9, we have:

f'(x) = –6(x^2 - 13x + 36) < 0

This means that f(x) is decreasing on the interval (–∞, 4), increasing on the interval (4, 9), and decreasing on the interval (9, ∞). Therefore, we have a local minimum at x = 4 and a local maximum at x = 9.

To confirm this, we can evaluate the function at these critical points:

f(4) = –2(4)^3 + 39(4)^2 -216(4) + 6 = –26

f(9) = –2(9)^3 + 39(9)^2 -216(9) + 6 = 603

Therefore, the function f(x) = –2x^3 + 39x^2 -216x + 6 has one local minimum at x = 4 and one local maximum at x = 9.

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There are 4 incongruent primitive roots and 6 has order 12 and it is a primitive root.

There are 12 elements of the group     \(U_{13}\)   , namely all the positive integers less than 13, as these are relatively prime to 13. Now, if there are primitive roots, there are     \(\phi (\phi (n))\)    of them. So we must compute     \(\phi (12) = \phi (4\times 3) = \phi (4) \phi (3) = 2\times 2 = 4\)   . There are 4 incongruent primitive roots.

To find them, take the powers each element in turn:

1, 2, 4, 8, 3, 6, 12, 11, 9, 5, 10, 7, 1  (2 has order 12, it is a primitive root)

Of course, the higher powers of 2 cannot be.

Proceeding this way, we get next get that 6, 7, and 11 are also primitive roots.

For example, the powers of 6 give: 6, 10, 8, 9, 2, 12, 7, 3, 5, 4, 11, 1. We see 6 has order 12 and it is a primitive root. So 2, 6, 7, 11.

Therefore, There are 4 incongruent primitive roots and 6 has order 12 and it is a primitive root.

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ANSWER: (12,11), (x,y)

12 steps to the right on the x-axismaking the value a plus, and 11 steps up on the y axis making the numeral positive as well.

Answer:

D. He answers the same number of questions correctly in both rounds and the same number of questions incorrectly in both rounds​.

Step-by-step explanation:

In the first equation he earns 5 points and loses 3 points. The value of one question is 5 points, and the value of losing one question is 3 points. The same goes for the second equation except the fact that its 10 points and 4 points lost instead.

Answer:

VW = 1

Step-by-step explanation:

Tan 45 = 4/VW

VW = 4/Tan 45 = 1

a. To calculate the Euclidean distances between the three pairs of facilities, we use the formula: d = sqrt((x2 - x1)^2 + (y2 - y1)^2) where (x1, y1) and (x2, y2) are the coordinates of the two points.

Calculating the Euclidean distances:

dAB = sqrt((51 - 27)^2 + (59 - 17)^2) ≈ 45.28 miles

dBC = sqrt((61 - 51)^2 + (66 - 59)^2) ≈ 10.82 miles

dAC = sqrt((61 - 27)^2 + (66 - 17)^2) ≈ 51.23 miles

b. To calculate the rectilinear distances, we use the formula:

d = |x2 - x1| + |y2 - y1|

Calculating the rectilinear distances:

dAB = |51 - 27| + |59 - 17| = 27 + 42 = 69 miles

dBC = |61 - 51| + |66 - 59| = 10 + 7 = 17 miles

dAC = |61 - 27| + |66 - 17| = 34 + 49 = 83 miles

Therefore, the Euclidean distances are approximately dAB = 45.28 miles, dBC = 10.82 miles, and dAC = 51.23 miles. The rectilinear distances are dAB = 69 miles, dBC = 17 miles, and dAC = 83 miles.

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To solve the given linear programming (LP) problem using the graphical LP approach, we will plot the feasible region, identify the corner points, and determine the optimal solution.

Here are the steps:

Step 1: Plot the constraints:

- Plot the line 5x + y = 32, which represents the constraint 5x + y ≤ 32. To do this, find two points that lie on this line by assigning values to x and solving for y. For example, when x = 0, y = 32, and when x = 6, y = 2. Connect these points to draw the line.

- Plot the line x + 3y = 12, representing the constraint x + 3y ≥ 12. Again, find two points on this line and connect them. For instance, when x = 0, y = 4, and when x = 12, y = 0.

- Draw the lines representing x = 20 and y = 20 as vertical and horizontal lines passing through x = 20 and y = 20, respectively.

Step 2: Identify the feasible region:

- Shade the area that satisfies all the constraints. The feasible region is the intersection of the shaded regions.

Step 3: Identify the corner points:

- Find the coordinates of the corner points of the feasible region. These points are the intersections of the lines representing the constraints.

Step 4: Evaluate the objective function:

- Calculate the objective function Z = 3x + 12y for each corner point.

Step 5: Determine the optimal solution:

- Identify the corner point that gives the minimum value of the objective function Z. This point corresponds to the optimal solution of the LP problem.

Once you have completed these steps, you will have the complete solution to the LP problem using the graphical LP approach.

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Answer:

m= -7

Step-by-step explanation:

The monthly payment is given as 11.95 0f the loan amount.

A percentage is a value that indicates 100th part of any quantity.

A percentage can be converted into a fraction or a decimal by dividing it by 100.

The given problem can be solved by the loan formula as follows,

The expression for the loan formula is given as,

PM = A(r(1 + r)ⁿ)/((1 + r)ⁿ- 1)

Where A is the loan amount, r is the rate of interest and n is the time interval.

The corresponding values of r and n as per the question are 6% = 0.06 and 12 respectively.

Substitute these values in the above expression to get,

PM = A(0.06(1 + 0.06)ⁿ)/((1 + 0.06)ⁿ- 1)

     = 0.119A

Which can be written in the form of percentage as,

PM = 0.119 × 100% of A

      = 11.9% of A

Hence, the per month payment of the loan will be 11.9% of the loan amount.

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Since P is a point of tangency of the circumference O, then the angle OPQ is a right angle.

Then, the triangle OPQ is a right triangle. Use the Pythagorean Theorem to write an equation for r. Then, solve that equation.

Since OQ is the hypotenuse of OPQ, then:

Since OP=r, OQ=r+9 and PQ=15, then:

Expand the quadratic binomial on the right member of the equation:

Since the term r^2 appears on both sides, simplify the equation:

Simplify all terms and solve for r:

Therefore, the radius of the circumference is:

Answer:

2-241x

Step-by-step explanation: