1) push down on the end of the lever, and 2) 3/4 of the way from the fulcrum
based on what you learned about atoms, select all of the correct statements from the following list.1)Protons are positively charged.2)Doppler shifts in spectral lines give clues to the motions of stars.3)The Lyman and Paschen series of the hydrogen spectrum are not visible.4)Stellar spectra are absorption spectra.5)Spectra can reveal the chemical composition of stars.6)Electrons surround the nucleus.7)The number of neutrons determines the isotope of an atom.8)Neutral atoms have the same number of protons as electrons.
Neutral atoms contain the same amount of protons and electrons, protons are electrostatic attraction, stellar spectra are absorbance spectra, and spectra may show the chemical makeup of stars.
What do stellar spectra refer to?Information about a star's temperature, chemical make-up, and inherent brightness may be found in its spectrum. A series of photographs taken at various wavelengths of the split in the star's light make up spectrograms produced by slit spectrographs.
What processes result in stellar spectra?The transitions of electrons inside atoms or ions form spectral lines, which are typically dark absorbing lines but may also be dazzling emission lines in some things.
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ASAP
An object was placed in 75 ml of water. When the object was then measured in the water, the new volume of the water with the object was 86 ml. What is the volume of the object?
Note: You only have to fill in the numerical answer.(no units)
Answer:
The answer is 11 mLExplanation:
To find the volume of the object we use the formula
volume of object = final volume of water - initial volume of water
From the question
final volume of water = 86 mL
initial volume of water = 75 mL
So we have
volume of object = 86 - 75
We have the final answer as
11 mLHope this helps you
What is the speed (in m/s ) of a proton that has been accelerated from rest through a potential difference of (6. 0×10
∧
3)V ?
According to given information,the speed of the proton accelerated through a potential difference of (6.0×10³)V is approximately 1.07×10⁵ m/s.
The speed of a proton that has been accelerated from rest through a potential difference of (6.0×10³)V can be calculated using the formula:
speed = √(2qV / m)
where:
- speed is the velocity of the proton,
- q is the charge of the proton (1.6×10⁻¹⁹ C),
- V is the potential difference (6.0×10³ V),
- m is the mass of the proton (1.67×10⁻²⁷ kg).
Plugging in the given values into the formula, we get:
speed = √(2(1.6×10⁻¹⁹C)(6.0×10³ V) / 1.67×10⁻²⁷ kg)
Simplifying the equation further:
speed = √(1.92×10⁻¹⁹ J / 1.67×10⁻²⁷ kg)
Next, we divide the numerator by the denominator to obtain the final value:
speed = √(1.15×10¹¹ m²/s²)
Therefore, the speed of the proton is approximately 1.07×10⁵ m/s.
Conclusion, The speed of the proton accelerated through a potential difference of (6.0×10³)V is approximately 1.07×10⁵ m/s.
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which is not one of the ways that codes of ethics can vary from each other?
a. authorship
b. level
c. principle
d. purpose
One of the ways in which code of ethics does not vary from each other is ; ( C ) Principle
What is code of ethics ?Code of ethics is a set of written principles that serves as a guideline to ethical behaviors expected from individuals under some form of authority usually at the place of work.
Code of ethics is different from code conduct because code of conduct is a set of rules that oultines the proper practices of individuals at the place of work. The code of ethics vary in autorship, level and purpose.
Hence we can conclude that One of the ways in which code of ethics does not vary from each other is ; ( C ) Principle
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What magnetic field strength is needed in each magnet to steer protons around the ring with a speed of 3.0 × 10^7 m/s? Assume that the field is uniform inside the magnet, zero outside.
A magnetic field strength of approximately 3.13 T is needed in each magnet to steer protons around the ring with a speed of\(3.0 × 10^7 m/s\).
To steer protons around the ring with a speed of \(3.0 × 10^7 m/s\), we need to apply a magnetic field perpendicular to their motion, which will exert a centripetal force on them and keep them moving in a circular path. The magnitude of this force is given by the equation:
\(F = mv^2/r\)
where m is the mass of the proton, v is its speed, and r is the radius of the circular path.
The centripetal force is also equal to the magnetic force on the proton, given by the equation:
F = qvB
where q is the charge of the proton, v is its speed, and B is the magnetic field strength.
Setting these two equations equal to each other, we get:
\(mv^2/r = qvB\)
Solving for B, we get:
B = mv/rq
Substituting the values for the mass and charge of the proton, and the speed and radius of the circular path, we get:
\(B = (1.67 × 10^-27 kg) × (3.0 × 10^7 m/s) / (0.28 m) / (1.6 × 10^-19 C) ≈ 3.13 T\)
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5. Two ice skaters, of mass 30 kg and 80 kg, are
skating across the surface of a frozen lake on a
collision course, with respective velocities of 2.0
m/s in a general north direction, and 1.0 m/s
generally west, as shown below. After they
collide, the pair of skaters move off in a direction
"Wist
north of wet with a momentum of approximately
100 kgm/s. How much kinetic energy was lost in
the collision?
The lost in kinetic energy after the collision is 55.45 J.
What is the lost in kinetic energy after collision?The kinetic energy lost after collision is calculated as follows;
Their final velocity after the collision is calculated as;
(80 + 30) v = 100 kgm/s
110v = 100
v = 100/110
v = 0.91 m/s
The sum of their initial velocity before and after collision;
K.Ei = 0.5 x (30)(2²) + 0.5 x (80)(1²)
K.Ei = 100 J
K.Ef = 0.5(30 + 80)(0.9²)
K.Ef = 44.55 J
ΔE = 100 J - 44.55 J
ΔE = 55.45 J
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Calculating the Magnitude of the Resultant Vector
R
13 m
5m
What is the magnitude of the resultant vector? Round
your answer to the nearest tenth.
m
The magnitude of the resultant vector is 13.9m.
The size of the resulting vector can be determined using the Pythagorean theorem. As you can see from these two examples, the result of adding three or more rectangular vectors is easy to determine using the Pythagorean theorem. The vectors should be added in a different order. Equation 2 Subtracts the vectors in opposite directions from each other to get the resulting vector.
Where vector B is in the opposite direction to vector A and R is the resulting vector. The resulting vector is defined as a single vector that produces the same effect as many vectors produced together. The size of a vector is the length of the vector. The absolute value of vector a is represented by |a|. For more information on vector sizes, see Vectors overview. The formulas for the sizes of 2D and 3D vectors in terms of coordinates are derived on this page.
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which products rely on the ability of ionic compounds to conduct electricity? check all that apply.
1. papers
2. cell phones
3. soaps
4. glazed pottery
5. remote control toys
What does itmean to have an acceleration of 8 m/s2
A. You speed up 8 m/s every second.
B. You travel 8 meters every second.
C. You slow down 8 m/s every second.
D. You travel 8 meters every other second.
Answer:
The answer is option A.
You speed up 8 m/s every second
Hope this helps you
explain why predation is a density-dependent factor.
Predation is a density-dependent factor because its impact on a population is influenced by the population's density.
Predation refers to the act of one organism, called the predator, feeding on another organism, known as the prey. The relationship between predators and prey is intricately tied to population density. When the population density of prey is low, predators may struggle to find enough individuals to sustain themselves, resulting in lower predation rates. However, as prey density increases, there is greater availability of potential prey, leading to an increase in predation rates.
As prey density rises, predators have a higher chance of encountering and capturing prey individuals. This results in an increase in the predator population size and their overall predation rate. However, as the predator population grows, the availability of prey may start to decline due to predation pressure. This leads to a decrease in prey density over time. Consequently, the predator population may experience reduced food availability, causing a decline in their population size. This cycle of interactions between predator and prey populations demonstrates how predation acts as a density-dependent factor, with changes in prey and predator densities influencing each other.
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Is an electron cloud bigger than an atom?
Answer:
no
Explanation:
An electron is one of the components of an atom, so it cannot be larger than that.
Answer:
No, it's not.
Explanation:
The tightly packed nucleus is 100,000 times smaller than the electron cloud.
A 13 foot ladder is leaning against a vertical wall. if the bottom of the ladder is sliding away from the wall at a rate of 4 feet per minute, how fast is the angle, , formed by the ladder and the ground, changing at the instant the ladder is 5 feet from the wall.
The angle between the ladder and the ground is changing at rate of 2.4ft/s.
Determine how fast is the angle formed by the ladder and the ground, changing at the instant the ladder is 5 feet from the wall.A right tringle is formed when ladder is against the wall,
x²+y² = 13²
dy/dt = -4ft/s
y = 5 feet
2[dx/dt] + 2[dy/dt] = 0
y = 10, x= √69 z = 13ft
2×√69[dx/dt] + 2×5×(-4) = 0
16.6[dx/dt] = 40
dx/dt = 40/16.6
dx/dt = 2.4 ft/s
The angle between the ladder and the ground is changing at rate of 2.4ft/s.
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Switch 1 has been in position a and switch 2 has been closed for a long time. At t=0 switch 1 moves instantaneously to position b. Four hundred microseconds later, switch 2 opens, remains open for 1 ms, and then recloses. Find v o (t)1. 6 ms after switch 1 makes contact with terminal b. Answer v o (1. 6 ms)=6. 63 V
The voltage at t=1.6 ms in the circuit, after the specified switch movements, is found to be 6.63 V.
The switch in a circuit has a significant impact on the current and voltage in the circuit. The question provides a scenario where switch 1 has been in position a for a long time, and switch 2 is closed. Then, at t=0, switch 1 moves to position b, and 400 microseconds later, switch 2 opens, remains open for 1 ms, and then recloses. The question requires us to find the voltage at t=1.6 ms.The initial state of the circuit is in steady-state. Thus, the voltage across the capacitor (C) and inductor (L) is V o. After switch 1 moves instantaneously to position b, the voltage across the capacitor is still V o. However, the current in the inductor changes from V o/R to 0 instantaneously. Then, the capacitor discharges into the inductor as it seeks to maintain the same voltage across it. The voltage across the capacitor decreases as a result, and the voltage across the inductor increases. The voltage across the inductor becomes negative, indicating that it is opposing the change in the current. After 400 microseconds, switch 2 opens, causing the voltage across the inductor to drop to zero since the current can no longer flow. The voltage across the capacitor is negative now, and it causes the current to flow through the resistor (R) and back to the capacitor. This process continues until switch 2 recloses, allowing the current to flow in the original direction. The final voltage across the capacitor (V o) can be found using the following formula: \(V o = 50/(15 + 25 + 1/(j*10^{-4}*10^6) + 1/(j*10^4*10^{-6})) = 4.9629V\)The voltage at t=1.6 ms can be calculated using the following formula: V o (t) = V o (∞) + [V o (0) - V o (∞)]\(e^{(-t/\tau)}\) = V o (∞) + [V o (0) - V o (∞)]\((1 - e^{(-t/\tau)}\)), where τ = L/R = 40 microsecondsThe initial voltage across the capacitor (V o (0)) is 4.9629V, and the final voltage across the capacitor (V o (∞)) is 0V. Thus, the voltage at t=1.6 ms is: V o (1.6 ms) = \(4.9629(1 - e^{(-1.6/40)}) = 6.63V.\)Therefore, the voltage across the capacitor is 6.63 V.For more questions on voltage
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1. A vehicle leaves Leeds at 8.00am and
arrives in Newcastle at 10.30am. If the
distance is 140 km, what was the average
speed of the vehicle?
The average speed with which the vehicle travels is equal to 56 Km/hr.
Velocity is measured as a vector quantity. There is a magnitude to it as well as a direction. The magnitude of velocity is measured by speed. The S.I. unit for this is the meter per second. Additionally, there are other units like km/h and km/s. Its dimensional equation is [LT-1].
The average speed of any vehicle is calculated over a given range of time. It is the total distance traveled by the vehicle in the given interval of time divided by the given time interval. It is a scaler quantity.
Average speed= Total Distance/ Time Taken
Given in the question
Distance = 140 km
Time of leaving Leeds = 8.00 am
Time of arriving Newcastle = 10.30 am
Time Taken = Time of arriving Newcastle - Time of leaving Leeds
= 10.30 - 8.00
= 2 hours and 30 minutes
So, the time taken is = 2.5 hr
Put in the values, we get
Average speed= Total Distance/ Time Taken
Average speed= 140/ 2.5 Km/Hr
Average speed= 56 Km/Hr
So, the average speed with which the vehicle travels is equal to 56 Km/hr.
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Hello people ~
what's the value of acceleration due to gravity on earth?
Answer:
9.8 m/s2
Its value is 9.8 m/s2 on Earth. That is to say, the acceleration of gravity on the surface of the earth at sea level is 9.8 m/s2. When discussing the acceleration of gravity, it was mentioned that the value of g is dependent upon location.
When liquid helium is exposed to room temperature, it forms a gas. Which best explains why this happens?
Answer:
the liquid helium absorbs energy from the air in the room
Using the graph, describe what is happening between 4 and 6 seconds. The object is moving away from the origin at a constant velocity. The object is not moving. The object is moving toward the origin at a constant velocity. The object is changing velocity.
The position in the graph between 4 - 6 seconds is the region of constant velocity.
What is constant velocity?The term constant velocity refers to the period in the graph when the velocity is not changing with time. As such, the graph is shown to be a flat portion at such a point.
Hence, it follows that the position in the graph between 4 - 6 seconds is the region of constant velocity.
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At what point does the ball have the most gravitational potential energy?
A car is accelerating at 4.90 m/s2 [S] for 6.20 s. If the car's initial velocity was 12.0
m/s [S], what will the final velocity of the car be?
Answer:Assuming
"m"
is a variable
|
Use
"m/s2"
as
instead
Assuming multiplication
|
Explanation:
A sturdy balloon with volume of 0.500 m ^3 is attached to a 2.50×10^2 kg iron weight and tossed overboard into a freshwater lake. The balloon is made of a light material of negligible mass and elasticity (though it can be compressed). The air in the balloon is initially at atmospheric pressure. The system fails to sink and there are no more weights, so a skin diver decides to drag it deep enough so that the balloon will remain submerged. (denisty of water =1000 kg/m^3) (a) Find the volume of the balloon at the point where the system will remain submerged, in equilibrium. (b) What is the balloon pressure at that point? Assume the temperature does not change with depth.
The volume of the balloon when it is submerged in the water and remains in equilibrium is 0.038 m^3. The pressure of the balloon at that point is 1.55 x 10^5 P
Since the system is in equilibrium, the weight of the balloon is equal to the buoyant force acting on it. The buoyant force is equal to the weight of the water displaced by the balloon. Hence, we can use Archimedes' principle to find the volume of the balloon when it is submerged and remains in equilibrium. We know that the density of water is 1000 kg/m^3 and the weight of the iron weight is 2.50 x 10^2 kg. Therefore, the weight of the water displaced by the iron weight is 2.50 x 10^2 kg x 9.81 m/s^2 = 2.4525 x 10^3 N. This is also equal to the weight of the balloon. Let the volume of the balloon when it is submerged be V. Then, the density of the balloon can be found using the mass and volume of the balloon. The mass of the balloon is negligible, so we can assume that the density of the balloon is the same as the density of the air inside it, which is approximately 1.29 kg/m^3. Therefore, the weight of the balloon is equal to the density of the balloon times the volume of the balloon times the acceleration due to gravity. Hence, we have 1.29 V x 9.81 = 2.4525 x 10^3. Solving for V, we get V = 0.038 m^3.
The pressure inside the balloon can be found using the ideal gas law, which relates the pressure, volume, and temperature of a gas. Since the temperature does not change with depth, we can assume that the temperature inside the balloon remains constant. Let P be the pressure inside the balloon at the point where it remains submerged. Then, the initial volume of the balloon is 0.500 m^3 and the initial pressure is atmospheric pressure, which is approximately 1.013 x 10^5 Pa. Using the ideal gas law, we have P x 0.500 = (1.013 x 10^5) x V. Substituting the value of V that we found earlier, we get P = 1.55 x 10^5 Pa. Hence, the pressure inside the balloon at the point where it remains submerged is 1.55 x 10^5 Pa.
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What should you do in case of radiation exposure?
Lock any windows and doors that are open. Head to the centre or basement of the structure. The recommended course of action is to stay as far away from the building's walls and top as you can since radioactive.
What is the highest source of radiation exposure?If radon gas is allowed to build up in a residence, it not only poses a health concern to uranium miner but also to homeowners. It is typically the biggest source of exposure to natural radiation.
Why, in your opinion, is it crucial to be knowledgeable about radiation exposure?We have been surrounded by radiation throughout our development. Therefore, the low amounts we are exposed each day are something our bodies are built to handle. However, excessive radiation can harm tissues by altering cell structure and DNA. Cancer is only one of the significant health issues this can lead to.
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Velocity vs time given information in the velocity vs time graph
The velocity vs. time graph provides information about how the velocity of an object changes over time.
The velocity vs. time graph is a graphical representation of the object's velocity at different points in time. The graph consists of two axes: the vertical axis represents velocity, and the horizontal axis represents time. By examining the graph, you can determine various characteristics of the object's motion.
For example, a positive slope on the graph indicates that the object is moving in a positive direction with increasing velocity. A negative slope indicates motion in the opposite direction or decreasing velocity.
A horizontal line represents constant velocity, as the slope is zero. The steepness of the slope indicates the rate at which the velocity is changing. A steeper slope indicates a faster change in velocity.
The velocity vs. time graph is a valuable tool in understanding the motion of objects. By analyzing the graph's shape and slope, you can determine important information such as acceleration, deceleration, constant velocity, and direction of motion.
It provides a visual representation that aids in interpreting and predicting an object's motion over time.
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Lúc 6 giờ sáng một học sinh đi học từ nhà đến trường mất 10 phút quãng đường từ nhà đến trường là 6 km hỏi học sinh đi với vận tốc là bao nhiêu
A 4.0 cm tall light bulb is placed a distance of 35.5 cm from a
convex mirror with a focal length of -12.2 cm. The image distance is determined to be -9.1 cm. What is the image size?
a 3.12 cm
b 5.78 cm
C 7.23 cm
d 1.02 cm
Answer:
D
Explanation:
Answer:
Image distance () = - 9.08 cm
Image height () = 1.02 cm
Given: (object distance) , (object height) , (focal length)
Required: image distance () and image size ()
Equations:
Eqn 01: (mirror equation)
Eqn 02: (magnification equation)
Solution:
Solving for the image distance:
Solving for the image height / size:
there are 3 significant figures (35.5 is 3, 4.00 is 3, -12.2 is 3), therefore,
Answer:
Image distance () = - 9.08 cm
Image height () = 1.02 cm
Describe the energy and motion of particles in a solid.
Answer:
Particles in solids are always vibrating (moving back and forth) in place. The vibrational motion of particles in solids is kinetic energy. Heat makes the particles in a solid vibrate faster, giving them more kinetic energy. Faster-vibrating particles bump into one another more often and hit each other harder.
Explanation:
a certain wheel has eight equally-spaced spokes and is spinning at a rate of 1.0 rev/s. you want to shoot a 20-cm arrow through the wheel without hitting any of the spokes. assume that the arrow and the spokes are very thin. what minimum speed must the arrow have, in m/s?
the minimum speed the arrow must have to pass through the wheel without hitting any spokes is 1.6 m/s. To shoot a 20-cm arrow through the wheel without hitting any spokes, we need to consider the time it takes for the arrow to pass through the gap between two spokes.
Since the wheel has eight equally-spaced spokes, the angular distance between adjacent spokes is 360 degrees divided by 8, which is 45 degrees.
The time it takes for the arrow to pass through the gap between two spokes can be calculated using the formula:
time = angular distance / angular velocity
In this case, the angular distance is 45 degrees, which is equivalent to (45/360) of a revolution, and the angular velocity is 1.0 revolutions per second.
Substituting the values, we have:
time = (45/360) rev / 1 rev/s = 0.125 s
To calculate the minimum speed of the arrow, we need to divide the distance traveled (20 cm) by the time taken (0.125 s):
speed = distance / time = 0.2 m / 0.125 s = 1.6 m/s
Therefore, the minimum speed the arrow must have to pass through the wheel without hitting any spokes is 1.6 m/s.
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1. A car starts from the rest on a circular track with a radius of 300 m. It accelerates with a constant tangential acceleration of a = 0.75 m/s?. Determine the distance traveled and the time elapsed"
Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.
To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.
The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).
Using the equation:
v = v₀ + at
where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:
v = 0 + (0.75 m/s²) * t
v = 0.75t m/s
The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:
v = ωr
Substituting the values:
0.75t = ω * 300
Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:
ω = ω₀ + αt
ω = 0 + (0.75 m/s²) * t
ω = 0.75t rad/s
We can now substitute the value of ω into the equation:
0.75t = (0.75t) * 300
Simplifying the equation gives:
0.75t = 225t
t = 0.75 seconds
The time elapsed is 0.75 seconds.
To calculate the distance traveled (s), we can use the equation:
s = v₀t + (1/2)at²
Since the initial velocity (v₀) is zero, the equation becomes:
s = (1/2)at²
s = (1/2)(0.75 m/s²)(0.75 s)²
s = (1/2)(0.75 m/s²)(0.5625 s²)
s = 0.2119 meters or approximately 21.19 centimeters
Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.
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In a submarine equipped with sonar, the time delay between the generation of a pulse and its echo after reflection from an enemy submarine is observed to be 80 sec. If the speed of sound in water is 1460 ms-1. What is the distance of enemy submarine?
will give u BRAINLIEST
First find time taken to reach submarine
\(\\ \bull\tt\dashrightarrow t=\dfrac{80}{2}=40s\)
Velocity=1460m/s\(\\ \bull\tt\dashrightarrow Distance=Velocity \times Time\)
\(\\ \bull\tt\dashrightarrow Distance=1460(40)\)
\(\\ \bull\tt\dashrightarrow Distance=58400m\)
\(\\ \bull\tt\dashrightarrow Distance=58.4km\)
Answer:
116800 meters away i think:)
Explanation:
why does sexual reproduction result with genetic variation
Explanation:
sexual reproduction provides genetic diversity because the sperms and the egg that are produced contain different combination of the genes than the parent organisms so in order to from a new organisms two gamete the sex cells sperm and egg must fuselage further mixing the gene to produce more genetic diversity
Explanation:
Sexual reproduction increases genetic variation in offspring, which in turn increases the genetic variability in species. You can see the effects of this genetic variability if you look at the children in a large family and note how each person is unique. Imagine this kind of variability expanded to include all the families you know (not to mention all the families of all the sexually reproducing organisms on Earth), and you begin to get a feel for the dramatic genetic impact of sexual reproduction
. A car starts to move from rest has an acceleration of 3m/s².what will be the velocity and distance travelled by the car after 50sec.
Sure! Here are the steps for calculating the velocity and distance traveled by the car after 50 seconds :
Step 1: Calculate the velocity using the equation:
\(v = u + at\)
where:
- \(v\) is the final velocity
- \(u\) is the initial velocity (0 m/s, as the car starts from rest)
- \(a\) is the acceleration (3 m/s²)
- \(t\) is the time (50 seconds)
Substituting the values into the equation:
\(v = 0 + (3 \, \text{m/s²}) \times (50 \, \text{s})\)
Step 2: Calculate the distance traveled using the equation:
\(s = ut + \frac{1}{2}at^2\)
where:
- \(s\) is the distance traveled
- \(u\) is the initial velocity (0 m/s)
- \(a\) is the acceleration (3 m/s²)
- \(t\) is the time (50 seconds)
Substituting the values into the equation:
\(s = 0 \times (50 \, \text{s}) + \frac{1}{2} \times (3 \, \text{m/s²}) \times (50 \, \text{s})^2\)
Now, let's simplify these equations:
\(v = 3 \times 50\)
\(s = \frac{1}{2} \times 3 \times 50^2\)
Calculating the results:
\(v = 150\) m/s
\(s = 3750\) meters
Therefore, after 50 seconds, the car will have a velocity of 150 m/s and would have traveled a distance of 3750 meters.