helppp nowwww please!!!!

To break the bonds in the hydrogen molecules in the reaction N2(g) + 3H2(g) → 2NH3(g), approximately 1305 kJ of energy needs to be supplied.

In order to break the bonds in the hydrogen molecules (H2), energy needs to be supplied to overcome the attractive forces between the atoms within the molecules. Breaking bonds requires an input of energy and is an endothermic process.

In the given chemical reaction, N2(g) + 3H2(g) → 2NH3(g), the hydrogen molecules (H2) are broken as the reactants, N2 and H2, are converted into ammonia (NH3).

Breaking one H2 molecule requires the energy equivalent to the bond dissociation energy (also known as bond energy) of the H-H bond. The bond dissociation energy is the energy required to break one mole of a particular bond in a gaseous molecule.

The bond dissociation energy for the H-H bond is approximately 435 kJ/mol. This means that it takes approximately 435 kJ of energy to break one mole of H-H bonds.

In the given reaction, three moles of H2 molecules are involved. Therefore, the total energy required to break the bonds in the hydrogen molecules is:

Energy required = 3 moles * 435 kJ/mol = 1305 kJ

So, to break the bonds in the hydrogen molecules in the reaction N2(g) + 3H2(g) → 2NH3(g), approximately 1305 kJ of energy needs to be supplied.

It's important to note that breaking bonds requires energy input, while forming bonds releases energy. In this reaction, the formation of new bonds in the ammonia (NH3) molecules will release energy, resulting in an overall exothermic reaction. The energy change of the reaction, often referred to as the enthalpy change (ΔH), will depend on the difference between the energy required to break the bonds and the energy released when new bonds are formed.

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Answer: Yes

Explanation:

Duh it can change.  Because matter is what we are made of, and if we change, then matter also changes along with us :)

As combustion always result into the formation of water, the other type of reactions that may result into formation of water are Acid-Base Neutralization Reactions and Hydrogen and Oxygen Reaction.

Acid-Base Neutralization Reactions:

A neutralisation reaction is a chemical process in which an acid and a base combine to produce salt and water as the end products.

H⁺ ions and OH⁻ ions combine to generate water during a neutralisation reaction. Acid-base neutralisation is the most common type of neutralisation reaction.

Example: Formation of Sodium Chloride (Common Salt):

HCl + NaOH → NaCl + H₂O

Hydrogen and Oxygen Reaction:

Water vapour is created when hydrogen gas (H₂) and oxygen gas (O₂) are combined directly. This reaction produces a lot of heat and releases a lot of energy.

Example: 2 H₂ + O₂ → 2 H₂O

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Answer:

To resolve this, we need to place the coefficient “2” in front of the sodium in the reactant, to give the equation shown below. 2 Na (s) + Cl 2 (g) → 2 NaCl (s) In this equation, there are two sodiums in the reactants, two sodiums in the products, two chlorines in the reactants and two chlorines in the products; the equation is now balanced.

Explanation:

Answer:

true

Explanation:

photons are emitted when electrons move from from a lower energy level to a higher energy level

We must first determine the heat needed to heat 175mL of water. In the working temperature range we can assume that the density of water is 1g/mL, so the mass of water that we must heat will be 175g of water.

Now, the heat we need to heat that mass of water is calculated with the following equation:

Where Q is the heat required to heat the water

Cp is the specific heat of water equal to 4186 J/g°C

delta T is the change of temperature = 25°C-20°C=5°C

We replace the know values:

Now, to heat the water they tell us that the glucose combustion will take place. We must assume that all the heat generated in the reaction will go to heating the water and that there is no heat loss to the environment.

The combustion reaction of glucose generates 2538.7 kJ/mol. So the moles of glucose needed will be:

We calculate the grams of glucose by multiplying the moles by the molar mass of glucose equal to 180.2g/mol

grams of glucose= 1.44 mol x 180.2 g/mol=260g

Answer: To heat 175 mL of water from 20.0 °C to 25.0°C are required 260g of glucose

Answer: An example is sodium ethoxide (NaOCH2CH3) dissolved in ethanol (CH3CH2OH).

Hope this helps!

We frequently observe kids playing with polythene bags filled with water that have little holes drilled into them at various locations so they can sprinkle water on other kids. Through this experiment, we can say that pressure acts in all directions in liquids.

Since both liquids and gases may flow, they are both referred to as fluids. Fluids under rest pressure behave uniformly in all directions.

Weather forecasts can be made using barometers. They track the evolution of atmospheric pressure throughout time.

On weather forecast maps, pressure variations appear as an isobar pattern. Predictions are made using these changes in pressure, and they are fairly accurate when combined with wind observations.

As you go away from a liquid's surface, pressure rises. for instance: A bucket has three holes that are all the same size. Since there is more pressure at the bucket's bottom, the water spills out more forcefully. Dams are thicker at the bottom for this reason.

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Approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M.

To determine the mass of glucose (C6H12O6) required to prepare a 0.215 M solution in 5000 mL, we need to use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

First, let's convert the volume of the solution from milliliters (mL) to liters (L):

5000 mL = 5000/1000 = 5 L

Now, we can rearrange the formula to solve for moles of solute:

moles of solute = Molarity (M) x volume of solution (L)

moles of solute = 0.215 M x 5 Lmoles of solute = 1.075 mol

Since glucose (C6H12O6) has a molar mass of approximately 180.16 g/mol, we can calculate the mass of glucose using the equation:

mass of solute = moles of solute x molar mass of solute

mass of glucose = 1.075 mol x 180.16 g/mol

mass of glucose = 194.0 g (rounded to three significant figures)

Therefore, approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M. It's important to note that the molar mass of glucose used in this calculation may vary slightly depending on the level of precision required.

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The balanced form of the nuclear equation is as follows; 249/98 Cf + 15/7 N⟶ 260/105 Db + 4(1/0) n.

A nuclear equation is process such as the fission of an atomic nucleus, or the fusion of one or more atomic nuclei and/or subatomic particles in which the number of protons and/or neutrons in a nucleus changes.

According to this question, Californium element is a reactant to produce dubnium and a neutron as products.

However, the law of conservation of mass must be fulfilled by ensuring the mass and atomic numbers of elements in reactant and product side are the same.

249/98 Cf + 15/7 N⟶ 260/105 Db + 4(1/0) n

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Answer:

Dmitri Mendeleev=Russian chemist, Albert Ghiorso=American scientist

Explanation:

Answer:

25J

Explanation:

K.E = 1/2mv^2

= 1/2*0.5*10^2

= 25J

The kinetic energy of the ball is 25 J

Kinetic energy can be defined as the energy possessed by an object in motion. Mathematically, it can be expressed as:

KE = ½mv²

From the question given above, the following data were obtained:

KE = ½mv²

KE = ½ × 0.5 × 10²

KE = 0.25 × 100

KE = 25 J

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The weaker acid involved in the given reaction is HC₂O₄⁻. Option B is correct.

The position of equilibrium in an acid-base reaction can provide information about the relative strength of the acids and bases involved. In the given reaction, if the equilibrium lies to the left, it indicates that the forward reaction is not favored and the reverse reaction is favored.

This means that the products NH₃(aq) and H₂C₂O₄(aq) have a tendency to react and form the reactants HC₂O₄⁻(aq) and NH₄⁺(aq).

Therefore, the acid dissociation constant of HC₂O₄⁻(aq) is K_a1 = 5.9 × 10⁻². The acid dissociation constant of H₂C₂O₄(aq) is K_a2

= 5.9 × 10⁻⁵.

Since the equilibrium lies to the left, it means that the concentration of HC₂O₄⁻(aq) is higher than that of H₂C₂O₄(aq) at equilibrium. This suggests that HC₂O₄⁻(aq) is the weaker acid, as it does not dissociate as much as H₂C₂O₄(aq) does.

Hence, Option B is correct.

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According to Dalton's law of partial pressures, the total pressure by a mixture of gases is equal to the sum of the partial pressures of each of the constituent gases. The partial pressure is defined as the pressure each gas would exert if it alone occupied the volume of the mixture at the same temperature. The Law of Partial Pressures is commonly applied in looking at the pressure of a closed container of gas and water. The total pressure of this system is the pressure that the gas exerts on the liquid. The gas is made up of whatever sample of gas there is plus the evaporated water. Dalton's law of partial pressures, Pt = P1 + P2 + ..., says that the total pressure of a gas mixture is the sum of the partial pressures of constituent gases. Dalton's law states that the total pressure of a gas is the sum of the individual pressures of all the gas molecules in the container. In other words, it's the average pressure exerted by all the gas particles in a given system.

Answer:

what do you need help with

The mass of Dichloromethane used in the above reaction has a similar density throughout the reaction.

The density and mass concentration of a pure substance is numerically equivalent. Density can affect buoyancy, purity, and packing. Varied materials typically have different densities. At normal temperatures and pressures, osmium and iridium have the highest densities of any known elements.

mass is occasionally substituted by the dimensionless quantity "relative density" or "specific gravity," i.e. the ratio of the material's density to that of a standard material, typically water, to make density comparisons across different systems of units easier. In other words, if a substance's relative density is less than one in relation to water, it floats.

Temperature and pressure affect a substance's density.

We know that density will be the same throughout mixing.

Hence, density = mass/ volume

now comparing density for both the condition we get

33.13 / 25= mass / 252.5

Mass = 33461 g

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Answer:

The water goes into groundwater

Explanation:

when the water runs into the ocean it flows and becomes ground water when the water is evaporated

The enthalpy change of the reaction C(diamond) → C(graphite) is -2.9 kJ.

The given information is ΔHrxn for the reaction C(diamond) → C(graphite) can be calculated with the given equations:Equations:  C(diamond) + O2(g) → CO2(g) ΔH = −395.4 kJ  2 CO2(g) → 2 CO(g) + O2(g) ΔH = 566.0 kJ  C(graphite) + O2(g) → CO2(g) ΔH = −393.5 kJ  2 CO(g) → C(graphite) + CO2(g) ΔH = −172.5 kJThe required reaction can be obtained by adding the equations (1) and (4), as follows:C(diamond) + O2(g) + 2CO(g) → C(graphite) + 3CO2(g)Addition of the two equations (1) and (4) results in a reaction whose products are C(graphite) and CO2.

To get the final equation that involves only the required reactants and products, the equation (2) should be added, which consumes CO2 and produces O2, as shown below:C(diamond) + O2(g) → CO2(g)  ΔH = −395.4 kJ [eq. (1)]  2 CO(g) → C(graphite) + CO2(g)  ΔH = −172.5 kJ [eq. (4)]  2 CO2(g) → 2 CO(g) + O2(g)  ΔH = 566.0 kJ [eq. (2)]  C(diamond) + O2(g) + 2CO(g) → C(graphite) + 3CO2(g)  ΔHrxn=ΣΔHf(products)−ΣΔHf(reactants)  ΔHrxn=[(3 mol CO2)(-393.5 kJ/mol) + (1 mol C(graphite))(0 kJ/mol)] − [(1 mol C(diamond))(0 kJ/mol) + (1 mol O2)(0 kJ/mol) + (2 mol CO(g))(−172.5 kJ/mol)] − [(2 mol CO2)(566.0 kJ/mol)]  ΔHrxn=−2.9 kJ.

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Answer: 160

Explanation:

45 liters of O2 x 1 mol O2/22.4 L O2 x 2 mol Ca/1 mol O2 x 40.078g Ca/1 mol Ca= 161 ( I got 161 but there was an answer choice of 160 so i chose it and got it right)

The balanced redox reaction in the chemical reaction is given below:

40H2S + 48H+ + 16MnO4¯ ---> 5S8 + 16Mn2+ + 64H2O

Balancing the redox reaction:

Solution:

1) Half-reactions:

H2S ---> S8

MnO4¯ ---> Mn2+

2) Balance:

8H2S ---> S8 + 16H+ + 16e¯

5e¯ + 8H+ + MnO4¯ ---> Mn2+ + 4H2O

3) Make the number of electrons equal (note that there are no common factors between 5 and 16 except 1):

40H2S ---> 5S8 + 80H+ + 80e¯ <--- factor of 5

80e¯ + 128H+ + 16MnO4¯ ---> 16Mn2+ + 64H2O <---

factor of 16

4) Thus, the final answer is given below;

40H2S + 48H+ + 16MnO4¯ ---> 5S8 + 16Mn2+ + 64H2O

Oxidation-reduction can simply be defined as a special type of chemical reaction in which the oxidation states of the substrate change.

So therefore, the balanced redox reaction in the chemical reaction is given below:

40H2S + 48H+ + 16MnO4¯ ---> 5S8 + 16Mn2+ + 64H2O

Complete question:

Balance the following redox reaction:

MnO4¯ + H2S ---> Mn2+ + S8

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Answer:

The correct solution is "3.6975 M".

Explanation:

The given values are:

Volume of solution,

V = 23.2 mL

Density,

D = 1.42 g/mL

Final volume,

= 200 mL

or,

= 0.2 L

Now,

The mass will be:

= \(D\times V\)

= \(1.42\times 23.1\)

= \(32.802 \ g\)

Mass of HNO₃ will be:

= \(\frac{32.802}{0.704}\)

= \(46.59375 \ g\)

Mol of HNO₃ will be:

= \(\frac{mass}{MW}\)

= \(\frac{46.59375}{63}\)

= \(0.7395 \ mol\)

hence,

The concentration will be:

= \(\frac{mol \ of \ HNO_3}{final \ V}\)

= \(\frac{0.7395}{0.2}\)

= \(3.6975 \ M\)

Explanation:

hybridization refers to the process of mixing atomic orbitals in a way that creates new hybrid orbitals. This is commonly observed in organic chemistry, where hybridization is used to explain the shapes and bonding properties of molecules.

The hybridization of atomic orbitals occurs when atoms bond to form molecules. In the hybridization process, the valence electrons of an atom are rearranged and redistributed in order to form new orbitals with different shapes and energies. This can result in stronger and more stable bonding between atoms.

The most common types of hybridization are sp, sp2, and sp3, which involve the mixing of s and p orbitals. For example, in the sp3 hybridization of carbon, the 2s orbital and three 2p orbitals are combined to form four sp3 hybrid orbitals, which are arranged in a tetrahedral shape.

The effects of hybridization in chemistry include changes in the bond angles, bond lengths, and overall shape of molecules. This can affect the reactivity and chemical properties of the molecule, such as its acidity or basicity.

Answer:

1:3

Explanation:

nitrogen and hydrogen combine qt high pressure and temperature to form ammonia gas.this method is used to prepare ammonia industrially and the process is called haber's process.

the balanced equation is given as:

N2+3H2=>2NH3

we can see that 1 mole of nitrogen combines with 3 moles of hydrogen to produce 2 moles of ammonia.

hence ratio of nitrogen and hydrogen molecules should be 1:3 for reactants to get used up completely.

I hope it's helpful!

Answer:

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\ \)

But from the question

volume = final volume of water - initial volume of water

volume = 165 - 150 = 15 mL

We have

\(density = \frac{225}{15} = 15 \\ \)

We have the final answer as

Hope this helps you

A chemical reaction is started by adding the borax solution to the glue mixture. A elastic, springy new material is produced when the glue and borax molecules interact.

Although cleaning is borax's most well-known application, the substance is also included in a wide range of home goods, such as specialty toothpastes and mouthwashes. goods for treating acne, including lotions, skin creams, moisturizers, and sunscreen. Ceramic glaze and paint.

Borax (sodium tetraborate) is different from baking soda (sodium bicarbonate). Both salts and widely used as "green" home cleaners, baking soda and borax have pH values of 8 and 9.5, respectively.

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Answer:

\(f=4.47\times 10^{14}\ Hz\)

Explanation:

Given that,

The wavelength of light, \(\lambda=670\ nm=670\times 10^{-9}\ m\)

We need to find the frequency of the light. The relation between the frequency and wavelength is given by :

\(v=f\lambda\)

The speed of light is equal to c.

So,

\(f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{670\times 10^{-9}}\\\\f=4.47\times 10^{14}\ Hz\)

So, the frequency of light is equal to \(4.47\times 10^{14}\ Hz\).

Thermal energy is heat it heats you up it give people heat it give away the heat it has until it is cold

Either you miswrote that or something else

Answer:

1. 2K(s) + Cl2(g) → 2KCI(s)

2. 4NH3(g) → 2N2(g) + 6H2(g)

3. 2AgNO3(aq) + CaCl2(aq) → 2AgCl(s) + Ca(NO3)2(aq)

4. CH4(g) + 2O₂(g) → CO2(g) + 2H₂0(g)

The temperature increase from 20 °C to 46 °C indicates that the reaction between zinc and copper sulfate solution is exothermic, with heat being released into the surroundings.

In the given reaction between zinc and copper sulfate solution, the temperature change can provide insights into the type of heat change occurring during the reaction. Based on the provided information, the initial temperature of the copper sulfate solution was 20 °C, and the final temperature of the mixture after the reaction was 46 °C.

The temperature increase observed in this reaction indicates an exothermic heat change. An exothermic reaction releases heat energy into the surroundings, resulting in a temperature rise. In this case, the reaction between zinc and copper sulfate solution is exothermic because the final temperature is higher than the initial temperature.

During the reaction, zinc displaces copper from copper sulfate to form zinc sulfate and copper metal. This displacement reaction is known as a single displacement or redox reaction. Zinc is more reactive than copper and therefore replaces copper in the compound.

The formation of new chemical bonds during the reaction releases energy in the form of heat. This energy is transferred to the surroundings, leading to an increase in temperature. The heat released is greater than the heat absorbed, resulting in a net increase in temperature.

The exothermic nature of this reaction can be explained by the difference in bond energies between the reactants and products. The breaking of bonds in the reactants requires energy input, while the formation of new bonds in the products releases energy.

In this case, the energy released during the formation of zinc sulfate and copper metal is greater than the energy required to break the bonds in copper sulfate and zinc.

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