help pls i'm so behind

Help Pls I'm So Behind

Answers

Answer 1

Answer:

I'(-3,2)

E'(-3,3)

Q'(4,4)

Z'(0,5)


Related Questions

use the properties of operations to multiply (-2.7x + 4) (-0.2x)

Answers

Answer:

0.54x² - 0.8x

Step-by-step explanation:

(-2.7x + 4) (-0.2x)

we open the brackets by multiplication of the terms

0.54x² - 0.8x

WILL VOTE BRAINLIEST FOR THE FIRST RIGHT ANSWER

WILL VOTE BRAINLIEST FOR THE FIRST RIGHT ANSWER

Answers

Answer:

B

Step-by-step explanation:

Let t and d be their ages now.

2 years ago, their ages were t - 2 and d  2.

Now, Tyler is 3 years older than David: t = d + 3

2 years ago, Tyler was 4 times as old as David: t - 2 = 4(d - 2)

The system of equations is:

t = d + 3

t - 2 = 4(d - 2)

Answer: B

Answer:

D

Step-by-step explanation:

Can someone help ? What’s the square units ?

Can someone help ? Whats the square units ?

Answers

A square unit(s) is a square who’s sides have 1 length and have four points.
A unit square/square unit is a unit of measurement

This three pleaseee

This three pleaseee

Answers

Answer:

Hi. 6.2 is rational

Step-by-step explanation:

Irrational numbers never end. They go on forever.

x^3*x^8=x^11 (When you multiply, add the powers)

First one is x^11 and the second one 13/50

Ok so I need help with multiplying fractions, this is the way my teacher did it but I have no idea how to do it the way he did it so if someone can, please explain to me on how to do it

Ok so I need help with multiplying fractions, this is the way my teacher did it but I have no idea how

Answers

you just cross sinplify and then multiply the numerators by themselves and denominators by themselves and get your answer

example 1: this is basically reducing WHILE multiplying. since 5 and 10 have a greatest common factor and is able to be reduced by each other, we do so. hence the reason 5 went to 1 and 10 went to 2 because 5 goes into 5 once and 5 goes into 10 twice. it was a different case for 3 and 8. 3 obviously cant go into 8 and 3 is prime so nothing can be done with those. ONLY REDUCE WHILE MULTIPLYING DIAGONALLY you CANNOT do up and down or side to side. so our new fractions are \(\frac{3}{2}\) and \(\frac{1}{8}\) so multiply across and get \(\frac{3}{16}\) which cant be reduced more.

example 2: this one in my opinion is pretty easy. you take the two fractions and multiply regularly across. you get \(\frac{27}{80}\). that fraction can be reduced. so we find the prime factorization of each number. 3 is a prime factor. 3x3x3=27 which is our top number. 2 and 5 are all prime numbers used to reach 80. 2x2x2x2x5=80. that's the prime factorization method its an easier way to check your work also.

example 3: this one is practically a combination of the two previous ones. \(\frac{16}{21}\) and \(\frac{7}{8}\) can be diagonally reduced on both diagonals. 7 goes into 7 once and 7 goes into 21 three times 8 goes into 8 once and 8 goes into 16 twice. now we have \(\frac{1}{1}\) and \(\frac{2}{3}\) multiply across and get just \(\frac{2}{3}\). prime factorization is the best way to do this but, more effective with larger numbers. \(\frac{2*2*2*2*7}{3*7*2*2*2}\) now cross out the numbers that are the same on the top and bottom. three 2's cancel out, one 7 cancels out, and now we're left with \(\frac{2}{3}\).

I really hope this helps you!!

An experimenter would like to construct a 99% confidence interval with a width at most 0. 5 for the average resistance of a segment of copper cable of a certain length. If the experimenter knows that the standard deviation of such resistances is 1. 55. How big a sample should the experimenter take from the population? what happens if the standard deviation and the width of the confidence interval are both doubled?.

Answers

A big sample that should the experimenter take from the population is 256 and if the standard deviation and the width of the confidence interval are both doubled then the sample is also 256.

In the given question,

The confidence level = 99%

Given width = 0.5

Standard deviation of resistance(\sigma)= 1.55

We have to find a big sample that should the experimenter take from the population and what happens if the standard deviation and the width of the confidence interval are both doubled.

The formula to find the a big sample that should the experimenter take from the population is

Margin of error(ME) \(=z_{\alpha /2}\frac{\sigma}{\sqrt{n}}\)

So n \(=(z_{\alpha /2}\frac{\sigma}{\text{ME}})^2\)

where n=sample size

We firstly find the value of ME and \(z_{\alpha /2}\).

Firstly finding the value of ME.

ME=Width/2

ME=0.5/2

ME=0.25

Now finding the value of \(z_{\alpha /2}\).

Te given interval is 99%=99/100=0.99

The value of \(\alpha\) =1−0.99

The value of \(\alpha\) =0.01

Then the value of \(\alpha /2\) = 0.01/2 = 0.005

From the standard table of z

\(z_{0.005}\) =2.58

Now putting in the value in formula of sample size.

n=\((2.58\times\frac{1.55}{0.25})^2\)

Simplifying

n=(3.999/0.25)^2

n=(15.996)^2

n=255.87

n≈256

Hence, the sample that the experimenter take from the population is 256.

Now we have to find the sample size if the standard deviation and the width of the confidence interval are both doubled.

The new values,

Standard deviation of resistance(\(\sigma\))= 2×1.55

Standard deviation of resistance(\(\sigma\))= 3.1

width = 2×0.5

width = 1

Now the value of ME.

ME=1/2

ME=0.5

The z value is remain same.

Now putting in the value in formula of sample size.

n=\((2.58\times\frac{3.1}{0.5})^2\)

Simplifying

n=(7.998/0.5\()^2\)

n=(15.996\()^2\)

n=255.87

n≈256

Hence, if the standard deviation and the width of the confidence interval are both doubled then the sample size is 256.

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Which points are on the graph of the equation -3x + 6y + 5 = -7?Drag and drop all of the points that are on the graph of theequation-3x + 6y + 5 = -7 into the box.

Which points are on the graph of the equation -3x + 6y + 5 = -7?Drag and drop all of the points that

Answers

Explanation: To solve this question we just need to substitute the x and y values from each point into the equation, if the equality is true it means the point is on the graph but if the equality is wrong it means the point is not on the graph of the equation.

Step 1: Let's substitute the values for each of the points and calculate as follows

Final answer: So the points on the graph are (0,-2) and (8,2).

Which points are on the graph of the equation -3x + 6y + 5 = -7?Drag and drop all of the points that
Which points are on the graph of the equation -3x + 6y + 5 = -7?Drag and drop all of the points that
Which points are on the graph of the equation -3x + 6y + 5 = -7?Drag and drop all of the points that
Which points are on the graph of the equation -3x + 6y + 5 = -7?Drag and drop all of the points that
Which points are on the graph of the equation -3x + 6y + 5 = -7?Drag and drop all of the points that

The line plots represent data collected on the travel times to school from two groups of 15 students.Compare the data and use the correct measure of center to determine which bus typically has the faster travel time. Round your answer to the nearest whole number, if necessary, and explain your answer. Bus 47, with a median of 16 Bus 14, with a median of 14 Bus 47, with a mean of 16 Bus 14, with a mean of 14

Answers

We can conclude that Bus 14 typically has the faster travel time since its median is lower than that of Bus 47.

When data are sorted in ascending or descending order, the median, a measure of center, indicates the dataset's middle value. Extreme numbers or data outliers have no impact on it.

From the given information, we know that the median travel time for Bus 47 is 16 and the median travel time for Bus 14 is 14.

What is median?

When values are arranged in order of magnitude, the median, a measure of central tendency, indicates the midpoint of the dataset. You must organise the values in ascending order from smallest to largest before determining the middle value to determine the median.

The mean, on the other hand, is affected by extreme values or outliers in the data, which can skew the value. Therefore, we cannot solely rely on the mean to compare the travel times of the two buses. However, for completeness, we also have the mean travel times of Bus 47 and Bus 14, which are both given as 16 and 14, respectively.

Therefore, we can conclude that Bus 14 typically has the faster travel time since its median is lower than that of Bus 47.

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Factor the expression completely.
-18 + 42x

Answers

Answer:

factor the polynomial

6 (7x-3)

Step-by-step explanation:

\( - 18 + 42x \\ divide \: both \: sides \: by \: 6 \\ 2(7x -3)\)

you are a researcher studying the lifespan of a certain species of bacteria. a preliminary sample of 35 bacteria reveals a sample mean of hours with a standard deviation of hours. you would like to estimate the mean lifespan for this species of bacteria to within a margin of error of 0.4 hours at a 99% level of confidence. what sample size should you gather to achieve a 0.4 hour margin of error? round your answer up to the nearest whole number.

Answers

The sample size required to achieve a margin of error of 0.4 hours with a 99% level of confidence is 621.

To achieve a margin of error of 0.4 hours with a 99% level of confidence, you need to gather a sample size of 621 bacteria. The formula to calculate the sample size is given by:
n = [(Zα/2)2 · σ2] / (E2)
where n is the sample size, Zα/2 is the z-score, σ is the population standard deviation, and E is the margin of error.
For the given example, Zα/2 = 2.576, σ = hours, and E = 0.4. Plugging these values in the formula, we get n = 621. Thus, the sample size required to achieve a margin of error of 0.4 hours with a 99% level of confidence is 621.

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Is 2mi equal to 3,333 yrds?

Answers

approximately, yes, but 3,333 yards is exactly 1.894 miles.

Find the slope of the line that passes through (-1, -1) and (98, 87).

Answers

Answer:    slope =  ⁸/₉  

Step-by-step explanation:      

    The question gives us two points,  (-1, -1) and (98, 87), from which we can find the slope and later the equation of the line.

Finding the Slope  

The slope of the line (m)   = (y₂ - y₁) ÷ (x₂ - x₁)  

                                            = (87 - (-1)) ÷ (98 - (-1))        

                                            =  (88) ÷ (99)    

                                            =   ⁸/₉  

Checking my answer visually:  

Finding the Equation

We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line. Once we have that equation, we can graph it to see if it passes through the two points. If it does, then we calculated the slope correctly.

                               ⇒  y - (-1) = ⁸/₉ (x - (-1)              [using the point (-1, -1)]

                                      y + 1  = ⁸/₉ (x + 1)  

 

To test my answer, I have included a Desmos Graph that I graphed using the information provided in the question and my answer.  

Find the slope of the line that passes through (-1, -1) and (98, 87).

Simple Interest QuizIf $3,000 is loaned for 48 months at a 4.5% annual rate, how much is the ending balance?

Answers

Given:

Principal (p) =$3,000

Time (T) = 48 months = 4 years

Interest rate = 4.5%

Required :

Ending balance = ?

The simple interest :

\(\begin{gathered} SI\text{ = PRT} \\ =\text{ 3000 }\times\text{ 0.045 }\times\text{ 4} \\ =\text{ \$ 540} \end{gathered}\)

Ending balance :

\(\begin{gathered} \text{Ending balance = Principal + SI} \\ =\text{ \$ 3000 + \$ 540} \\ =\text{ \$ 3540} \end{gathered}\)

Ending balance = $ 3540

plz guys cmonnnnn there's gonna be more. WILL GIVE BRAINLIEST

plz guys cmonnnnn there's gonna be more. WILL GIVE BRAINLIEST

Answers

Answer:

\( 6.3 \le p \le 8.1 \)

The third reading must be between 6.3 and 8.1 inclusive.

Step-by-step explanation:

To find the average of three numbers, add the three numbers and divide by 3.

Let the third reading = p.

The average of the three readings is

\( \dfrac{7.4 + 7.9 + p}{3} \)

This average must be between 7.2 and 7.8 inclusive. "Inclusive" means that the values 7.2 and 7.8 are allowed. That means the average must be greater than or equal to 7.2 and less than or equal to 7.8. We can write this as the following inequality.

\( 7.2 \le \dfrac{7.4 + 7.9 + p}{3} \le 7.8 \)

Simplify the numerator.

\( 7.2 \le \dfrac{15.3 + p}{3} \le 7.8 \)

Multiply the three sides by 3.

\( 21.6 \le 15.3 + p \le 23.4 \)

Subtract 15.3 from the three sides.

\( 6.3 \le p \le 8.1 \)

Answer: The third reading must be between 6.3 and 8.1 inclusive.

A car insurance company has determined that 11% of all drivers were involved in a car accident last year. In a random selection of 12 driver, use the binomial distribution to find the probability for each: (10 pts) a) Getting exactly 3 (x=3) that were involved in a car accident. b) Getting 3 or fewer (x≤3) that were involved in a car accident. c) Getting at least one (x≥1) that was involved in a car accident. d) Find the mean and standard deviation for the number that were involved in a car accident. e) Would it be a rare event for none (x=0) of the drivers to be involved in a car accident?

Answers

a. the probability of getting exactly 3 drivers involved in a car accident is approximately 0.2111. b. the probability of getting 3 or fewer drivers involved in a car accident is approximately 0.8866. c.The probability of getting at least one driver involved in a car accident is approximately 0.6833. d. the mean number of drivers involved in a car accident is 1.32, and the standard deviation is approximately 1.043.

To solve these problems, we can use the binomial distribution formula:

P(x) = C(n, x) * p^x * (1 - p)^(n - x)

where P(x) is the probability of getting exactly x successes, n is the number of trials, p is the probability of success in a single trial, and C(n, x) represents the binomial coefficient.

In this case:

n = 12 (number of drivers)

p = 0.11 (probability of a driver being involved in an accident)

q = 1 - p = 0.89 (probability of a driver not being involved in an accident)

a) To find the probability of getting exactly 3 drivers involved in a car accident:

P(x=3) = C(12, 3) * (0.11)^3 * (0.89)^(12 - 3)

Using a binomial coefficient calculator or software, we find that C(12, 3) = 220.

P(x=3) = 220 * (0.11)^3 * (0.89)^9 ≈ 0.2111

Therefore, the probability of getting exactly 3 drivers involved in a car accident is approximately 0.2111.

b) To find the probability of getting 3 or fewer drivers involved in a car accident:

P(x≤3) = P(x=0) + P(x=1) + P(x=2) + P(x=3)

Using the binomial distribution formula for each value of x and summing them up:

P(x≤3) = C(12, 0) * (0.11)^0 * (0.89)^12 + C(12, 1) * (0.11)^1 * (0.89)^11 + C(12, 2) * (0.11)^2 * (0.89)^10 + C(12, 3) * (0.11)^3 * (0.89)^9

Calculating this expression, we find that P(x≤3) ≈ 0.8866

Therefore, the probability of getting 3 or fewer drivers involved in a car accident is approximately 0.8866.

c) To find the probability of getting at least one driver involved in a car accident:

P(x≥1) = 1 - P(x=0)

Using the binomial distribution formula for x=0:

P(x=0) = C(12, 0) * (0.11)^0 * (0.89)^12

Calculating this expression, we find that P(x=0) ≈ 0.3167

Therefore, P(x≥1) = 1 - 0.3167 ≈ 0.6833

The probability of getting at least one driver involved in a car accident is approximately 0.6833.

d) The mean and standard deviation for the number of drivers involved in a car accident can be calculated using the formulas:

Mean (μ) = n * p

Standard Deviation (σ) = √(n * p * q)

Mean (μ) = 12 * 0.11 = 1.32

Standard Deviation (σ) = √(12 * 0.11 * 0.89) ≈ 1.043

Therefore, the mean number of drivers involved in a car accident is 1.32, and the standard deviation is approximately 1.043.

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Your total for dinner was $18.50. If you want to leave a 20% tip, how much will your grand total be?​

Answers

Answer:

$3.70 honestly just divide lol

To control his weight, Joel reduced his calorie intake from 2500 calories to 1950 calories each day. What was his percent decrease for calorie intake?

Answers

Answer:

22%

Step-by-step explanation:

The change in calories = 1950 - 2500 = -550

percent decrease for calorie intake = (change in calories / initial calorie intake ) x 100

\(\frac{-550}{2500}\)  X 100 = -22%

Answer:

22%

Step-by-step explanation:

i did the quiz

ABCD is shown. Help…

ABCD is shown. Help

Answers

In the above geometric shape, quadrilateral

13) ∠ABC is 109°

14) If BD = 2.8, then CP is 1.1

What is the explanation for the above response?

13)  note that ∠ABC is 109° because the Opposite angles of a quadrilateral sum up to 180°.

Therefore,

∠ABC = 180 - (37+34)

∠ABC = 109°

14)
given that BD is = AC, and

BD = 2.8 while AP = 1.7

Since PC = AC - AP

PC = 2.8 - 1.7

Thus

PC = 1.1

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find a particular solution for y'' 4y' 3y = 1/1+e^t using transfer functions, impulse response and convolutions. (other methods are not accepted)

Answers

To find a particular solution for y'' 4y' 3y = 1/(1+e^t) using transfer functions, impulse response, and convolutions, we first need to find the homogeneous solution and then the particular solution.

The homogeneous solution is y_h = c1 e^(-t) + c2 e^(-3t), where c1 and c2 are constants. The transfer function is H(s) = 1/(s^2 + 4s + 3), and the impulse response is h(t) = e^(-t) - e^(-3t).

To find the particular solution, we need to first find the Laplace transform of the input function, which is F(s) = 1/(s+1)(1+e^(-s)). We can then use the convolution theorem to find the output function in the Laplace domain, which is Y(s) = H(s) F(s). Simplifying this expression using partial fraction decomposition and inverse Laplace transform, we get the particular solution y_p = (e^(-t) - e^(-3t)) / (2 - e^(-t)). Therefore, the general solution for the differential equation is y = y_h + y_p, where y_h is the homogeneous solution and y_p is the particular solution.

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reduce the following rational expression to the lowest form

\(\frac{64x^{5} - 64x}{( 8x^{2} +8) (2x +2) }\)

please answer this. But no spam answers please
hurry

Answers

Answer:

4x(x - 1)

Step-by-step explanation:

Factor the numerator and denominator

64\(x^{5}\) - 64x ← factor out 64x from both terms

= 64x(\(x^{4}\) - 1) ← difference of squares

= 64x(x² - 1)(x² + 1) ← x² - 1 is also a difference of squares

= 64x(x - 1)(x + 1)(x² + 1)

---------------------------------

(8x² + 8)(2x + 2) ← factor out 8 and 2 from each factor

= 8(x² + 1) × 2(x + 1)

= 16(x² + 1)(x + 1)

Then expression can be written as

\(\frac{64x(x-1)(x+1)(x^2+1)}{16(x^2+1)(x+1)}\) ← cancel (x² + 1) and (x + 1) on numerator/ denominator

= \(\frac{64x(x-1)}{16}\) ← cancel common factor 16 on numerator/ denominator

= 4x(x - 1)

sec7.2: problem 9 previous problem problem list next problem (1 point) book problem 33 find the volume of a cap of a sphere with radius r=68 and height h=49. volume=

Answers

The volume of a cap of a sphere with radius `r=68` and height `h=49` is `7866 cm³`.

Given,

Radius of the sphere `r = 68` units

Height of the cap `h = 49` units

The formula for the volume of the spherical cap is `V = 1/3πh^2(3r-h)`

Using the above formula for the given values we have,

V = `1/3 * π * 49^2 * (3 * 68 - 49)` = `(1/3) * 22/7 * 49 * 117` = `7866 cm³`

Therefore, The volume of a cap of a sphere with radius `r=68` and height `h=49` is `7866 cm³`.

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An initial investment of $500 is made in an account which earns 6% interest compounded
semiannually. Which of these equations gives the value of the investment after t years?​

Answers

Answer:

A = 500(1+6%/2)^2t

Step-by-step explanation:

Given the general compound interest formula A = P(1+r/n)^nt. With an initial investment of $500, and percent interest of 6% compounded semi annually(every six months/half a year/twice in one year). A = 500(1+6%/2)^2t .

i.e if given two years of compound interest, t=2. A = 500(1+6%/2)^2(2), 500(1+0.03)^4, 500(1.03)^4, 500(1.12550881), 500(≈1.1255) = 562.75

A = 562.75$ for two years

Find the tenth term of the
sequence.
4, 3, 0, -5, - 12, ...

Answers

Answer:

-76

each term is being subtracted from the preceding the next odd number

two mechanics worked on a car. The first mechanic worked for 10 hours, and the second mechanic worked for 5 hours. Together they charged a total of $1600. what are the rate charged per hour by each mechanic. if the sum of the two rates are $215 per hour.

Answers

Let's make,
mechanic #1's rate = x
mechanic #2's rate = y

* Their rate is dollars per hour ($/hr)

mechanic #1 worked for 20 hours (hr × $/hr = $)
20x = money earned by mech#1

and mechanic #2 worked for 5 hours
5y = money earned by mech#2

together they charged a total of $1150. So the amount of money earned by both mechanics.

20x + 5y = 1150

the sum of the two rates was $95 per hour.

x + y = 95

which means
x = 95 - y

plug (95 - y) in for "x" in the other equation to get everything in terms of one variable.

20(95 - y) + 5y = 1150

solve for y

1900 - 20y + 5y = 1150
1900 - 15y = 1150
-15y = 1150 - 1900
-15y = -750
y = -750/-15
y = 50 $/hr

Now use this to solve for x

x + y = 95
x + 50 = 95
x = 95 - 50
x = 45 $/hr

mech#1 charged 45$/hr
mech #2 charged 50$/hr

The rate charged per hour by the first mechanic = $105,

And the rate charged per hour by the second mechanic = $110.

Use the concept of ratio defined as:

A ratio indicates how many times one number contains another number. The ratio of two numbers is written as x: y, which is equivalent to x/y.

Where x and y are individual amounts of two quantities.

And, the Total quantity gives after combining as x + y.

Given that,

Two mechanics worked on a car.

The first mechanic worked for 10 hours.

The second mechanic worked for 5 hours.

Together, they charged a total of $1600.

The sum of the two rates charged per hour is $215.

Assume that,

The rate charged per hour by the first mechanic is = x dollars,

The rate charged per hour by the second mechanic is = y dollars.

The first mechanic worked for 10 hours,

The total amount earned by the first mechanic would be 10 times their hourly rate = 10x dollars.

Similarly,

The second mechanic worked for 5 hours,

The total amount earned by the second mechanic would be 5 times their hourly rate =  5y dollars.

Set up two equations based on the given information:

The first equation is the sum of the two rates, which is,

x + y = 215  ......(i)

The second equation is the total amount earned by both mechanics,

10x + 5y = 1600  .....(ii)

Use substitution to find the values of x and y:

From the first equation, we can express x in terms of y as,

x = 215 - y

Substitute this value of x into the second equation:

10(215 - y) + 5y = 1600

Expanding the equation, we get,

2150 - 10y + 5y = 1600

Combining like terms, we have:

-5y = 1600 - 2150

-5y = -550

Dividing both sides of the equation by -5, we get:

y = 110

Now that we have the value of y,

Substitute it back into the first equation to find x:

x + 110 = 215

Subtract 110 from both sides, and we get:

x = 105

Hence,

The rate charged per hour by the first mechanic is $105, &  the rate charged per hour by the second mechanic is $110.

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I WILL MARK YOU BRAINLIEST

I WILL MARK YOU BRAINLIEST
I WILL MARK YOU BRAINLIEST

Answers

The first should look like this I think sorry I'm not 100%sure. But the big black dot is where the coordinates lead if you follow them
I WILL MARK YOU BRAINLIEST

The number of trades (in thousands) completed daily by an online stock brokerage follows a normal distribution with a mean of 101. 1 and a standard deviation of 26. 5. On average, the brokerage receives $6. 04 commission per trade. For samples of size n=15 days: 1. Determine the mean and standard deviation of the sampling distribution of the sample mean daily commissions received (in thousand dollars) accurate to 3 decimal places: a) Mean = thousand dollars b) Standard deviation = thousand dollars 2. Determine the following probabilities (as percentages) accurate to one (1) decimal place. What is the probability that the mean daily commissions received is a) more than $581,652? % b) between $561,116 and $697,016 ? % 3. For the given sample size,what is the maximum average daily commissions receivable from the lowest 7. 5% volume trading days? Round to the nearest thousand dollars. A population of values has a normal distribution with μ=99. 7 and σ=2. 9. You intend to draw a random sample of size n=29. First calculate z, round it to two (2) decimal places, then use the rounded z-score to determine the required probability accurate to four (4) decimal places. 1. Find the probability that a single randomly selected value is less than 101. 2. P(x<101. 2)= 2. Find the probability that a sample of size n=29 is randomly selected with a mean less than 101. 2. P( x

ˉ

<101. 2)=

Answers

a)The mean of the sampling distribution is equal to the population mean, so it is 6.04 thousand dollars.

b)Standard deviation \(= 26.5 / \sqrt(15) = 6.830\) thousand dollars.

the probability that the mean daily commissions received is between \(\$561,116\)and \(\$697,016\) is approximately \(99.77\% - 0.01\% = 99.76\%.\)

To solve the given questions, we'll use the properties of the normal distribution.

1. Sampling Distribution:

a) Mean of the sampling distribution of the sample mean daily commissions received:

The mean of the sampling distribution is equal to the population mean, so it is 6.04 thousand dollars.

b) Standard deviation of the sampling distribution of the sample mean daily commissions received:

The standard deviation of the sampling distribution is equal to the population standard deviation divided by the square root of the sample size:

Standard deviation\(= 26.5 / \sqrt(15) = 6.830\) thousand dollars.

2. Probability Calculations:

a) Probability that the mean daily commissions received is more than $581,652:

We'll calculate the z-score using the formula\(\[ z = \frac{{(\$581,652 - \$604)}}{{\left(\frac{{6.830}}{{\sqrt{15}}}\right)}} \approx -3.161 \]\)

Using a standard normal distribution table, we find that the probability is approximately 0.0008, or 0.08%.

b) Probability that the mean daily commissions received is between $561,116 and $697,016:

We'll calculate the z-scores for both values and find the probabilities associated with those z-scores:

\(z_1 = ($561,116 - $604) / (6.830 / \sqrt(15)) = -3.907\)

\(z2 = ($697,016 - $604) / (6.830 / \sqrt(15)) = 2.870\)

Using the standard normal distribution table, we find the probability associated with z1 as approximately 0.0001, or 0.01%, and the probability associated with z2 as approximately 0.9977, or 99.77%.

Therefore, the probability that the mean daily commissions received is between $561,116 and $697,016 is approximately 99.77% - 0.01% = 99.76%.

3. Maximum average daily commissions receivable from the lowest 7.5% volume trading days:

We'll find the z-score corresponding to the lowest 7.5%:

Using a standard normal distribution table, we find the z-score corresponding to the lowest 7.5% as approximately -1.15.

Now we'll find the corresponding value in the original scale:

\(\[ z = \frac{{(x - \mu)}}{\sigma} \]\)

\(-1.15 = (x - 99.7) / 2.9\)

\(x - 99.7 = -1.15 * 2.9\)

\(x - 99.7 = -3.335\)

\(x = 96.365\)

Rounding to the nearest thousand dollars, the maximum average daily commissions receivable is approximately \(\$96,000.\)

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1. a) Mean = $6.04 thousand dollars
  b) Standard deviation = $6.823 thousand dollars
2. a) Probability = 100%
  b) Probability = 100%
3. Maximum average daily commissions receivable = $98,000

1. To determine the mean and standard deviation of the sampling distribution of the sample mean daily commissions received (in thousand dollars), we can use the following formulas:

a) Mean of the sampling distribution = Mean of the population = $6.04
b) Standard deviation of the sampling distribution = Standard deviation of the population / Square root of the sample size

= \(\frac{\$26.5}{\sqrt{15}} = \$6.823\)


2. To find the probabilities, we need to use the z-score formula:

a) To find the probability that the mean daily commissions received is more than $581,652, we first need to find the z-score.

The z-score formula is given by:

\(z = \frac{x - \mu}{\frac{\sigma}{\sqrt{n}}}\),

where x is the value we want to find the probability for, μ is the mean of the population, σ is the standard deviation of the population, and n is the sample size.

z = \(\frac{\$581,652 - \$6.04}{\left(\frac{\$26.5}{\sqrt{15}}\right)}\)


z = 21518.78

Using a standard normal distribution table or a calculator, we find that the probability is approximately 1.



b) To find the probability that the mean daily commissions received is between $561,116 and $697,016, we need to find the z-scores for both values.

z₁ = \(\frac{(\$561,116 - \$6.04)}{\left(\frac{\$26.5}{\sqrt{15}}\right)}\)


z₁ = 20618.03



z₂ = \(\frac{\$697,016 - \$6.04}{\left(\frac{\$26.5}{\sqrt{15}}\right)}\)


z₂ = 25618.23

Using the standard normal distribution table or a calculator, we find that the probability is approximately 1.



3. To find the maximum average daily commissions receivable from the lowest 7.5% volume trading days, we need to find the z-score that corresponds to a cumulative probability of 0.075.

Using the z-score formula and rearranging it to solve for x, we have: \(x = z \cdot \left(\frac{\sigma}{\sqrt{n}}\right) + \mu\)


First, we find the z-score using the standard normal distribution table or a calculator. For a cumulative probability of 0.075, the z-score is approximately -1.405.

Then, we plug in the values to find x:

x = \(-1.405 \cdot \left(\frac{$2.9}{\sqrt{29}}\right) + $99.7\)


x = $98.324

Rounding to the nearest thousand dollars, the maximum average daily commissions receivable from the lowest 7.5% volume trading days is $98,000.

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The function C(m)=0.55m+3.75 models the cost to take an m mile-long taxi ride from Quick Cabs. The table below shows the cost to take a cab different distances from Get You There Cabs.





Which statement is true about the two cab companies?


Quick Cabs costs less per mile but has a higher fixed fee than Get You There Cabs.

Quick Cabs costs more per mile but has a lower fixed fee than Get You There Cabs.

Quick Cabs costs more per mile but has a higher fixed fee than Get You There Cabs

Quick Cabs costs less per mile but has a lower fixed fee than Get You There Cabs.

The function C(m)=0.55m+3.75 models the cost to take an m mile-long taxi ride from Quick Cabs. The table

Answers

Quick cans costs more per mile but has a lower fixed fee then get you there cans

Problem 8 (10 Marks) - INVENTORY MANAGEMENT Susan manages the packaging supplies for the New Zealand distributorship of AllBirds product lines. It's her job to order all the shoe boxes that house each pair of shoes (whether going to retail stores, or shipping directly to consumers via the online store). She purchases shoe boxes from a local printing supplier. The NZ distributor ships on average 325 boxes of shoes each month. Boxes cost $2.25 each, and each order costs $18.00 to process. Because of limited storage space, Susan's manager wants to charge inventory holding at 25-percent of the unit cost. The lead time is 7 days. Assume 360 working days per year. Calculate the following: a. Economic Order Quantity (Marks: 2) b. Reorder Point (assuming no safety stock) (Marks: 1) c. Number of Orders-per-Year (Marks: 1) d. Total Annual Cost (Marks: 2) e. If storage space weren't so limited, Susan estimates that inventory holding costs would only be 15% of unit cost. How would that change total annual costs? (Marks: 4)

Answers

a) approximately 500 boxes. b) The reorder point is approximately 76 boxes. c) approximately 8 orders d) total annual cost is approximately $9,059.63 e) approximately $9,003.38

a. Economic Order Quantity (EOQ):

The Economic Order Quantity (EOQ) can be calculated using the formula:

EOQ = sqrt((2 * D * S) / H)

Where:

D = Annual demand

S = Ordering cost per order

H = Holding cost per unit per year

Annual demand (D) = 325 boxes per month * 12 months = 3,900 boxes

Ordering cost per order (S) = $18.00

Holding cost per unit per year (H) = 0.25 * $2.25 = $0.5625

Substituting the values into the EOQ formula:

EOQ = sqrt((2 * 3,900 * 18) / 0.5625)

   = sqrt(140,400 / 0.5625)

   = sqrt(249,600)

   ≈ 499.6

b. Reorder Point (assuming no safety stock):

The reorder point can be calculated using the formula:

Reorder Point = Lead time demand

Lead time demand = Lead time * Average daily demand

Lead time = 7 days

Average daily demand = Annual demand / Working days per year

Working days per year = 360

Average daily demand = 3,900 boxes / 360 days

                    ≈ 10.833 boxes per day

Lead time demand = 7 * 10.833

               ≈ 75.83

c. Number of Orders-per-Year:

The number of orders per year can be calculated using the formula:

Number of Orders-per-Year = Annual demand / EOQ

Number of Orders-per-Year = 3,900 boxes / 500 boxes

                        = 7.8

d. Total Annual Cost:

The total annual cost can be calculated by considering the ordering cost, holding cost, and the cost of the shoe boxes themselves.

Ordering cost = Number of Orders-per-Year * Ordering cost per order

             = 8 * $18.00

             = $144.00

Holding cost = Average inventory * Holding cost per unit per year

Average inventory = EOQ / 2

                = 500 / 2

                = 250 boxes

Holding cost = 250 * $0.5625

            = $140.625

Total Annual Cost = Ordering cost + Holding cost + Cost of shoe boxes

Cost of shoe boxes = Annual demand * Cost per box

                 = 3,900 boxes * $2.25

                 = $8,775.00

Total Annual Cost = $144.00 + $140.625 + $8,775.00

                = $9,059.625

e. If storage space weren't so limited, and the inventory holding costs were reduced to 15% of the unit cost:

To calculate the new total annual cost, we need to recalculate the holding cost using the reduced holding cost percentage.

Holding cost per unit per year (H_new) = 0.15 * $2.25

                                    = $0.3375

Average inventory = EOQ / 2

                = 500 / 2

                = 250 boxes

New holding cost =

Average inventory * Holding cost per unit per year

                = 250 * $0.3375

                = $84.375

Total Annual Cost (new) = Ordering cost + New holding cost + Cost of shoe boxes

Total Annual Cost (new) = $144.00 + $84.375 + $8,775.00

                      = $9,003.375

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HW Slide 2
Which angle relationship is the only one that is supplementary?
If Angles 1 and 4 are alternate exterior and m<1-85. What is the
measure of angle 4?
If Angles 1 and 5 are consecutive interior and m<1-43 what is the
measure of angle 5?

HW Slide 2Which angle relationship is the only one that is supplementary?If Angles 1 and 4 are alternate

Answers

The angle relationships that is supplementary is angle 1 and angle 5.

What are supplementary angles?

Supplementary angles are those angles that sum up to 180 degrees.

In other words, supplementary angles refer to the pair of angles that always sum up to 180°.

Alternate exterior angles are congruent to each other.

Therefore, ∠1 and ∠4 are not supplementary angles.

Hence,

m∠4 =m∠1

m∠4 = 85°

Consecutive interior angles are supplementary. That is they sum up to 180 degrees.

m∠1 = 43°

m∠5 = 180 - 43

m∠5 = 137°

Therefore, ∠1 and ∠5 are supplementary angles.

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Determine if the graph represents a linear function, quadratic function, or exponential function.



Group of answer choices

Exponential

Linear

Quadratic

Determine if the graph represents a linear function, quadratic function, or exponential function.Group

Answers

Answer:

Step-by-step explanation:

Answer:

quadratic function

Step-by-step explanation:

y=(x-1)²-3

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