h+c = $3
4h + 4c = $10

Solve for h and c

The actual annual value of this job to Karla is 33000.

What are arithmetic operations?

Arithmetic operations is a branch of mathematics that studies numbers and the operations on numbers that are useful in all other branches of mathematics. It consists primarily of operations like addition, subtraction, multiplication, and division.

We have,

the job will pay 2400 per month,

if the full cost of the medical insurance is 450 a month and Karla plans to contribute the full 1500 every year tpa retirement plan,

the actual annual value of this job to Karla is:

2400 per month

annual value  = 2400 * 12 = 28,800

the medical insurance is 450 a month

half the cost of medical insurance is  225 a month

annual value  = 225  * 12 = 2700

the full 1500 every year tpa retirement plan,

So, the total value is:

= 28,800 + 2700 + 1500

= 33000

Hence,  the actual annual value of this job to Karla is 33000.

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Answer:

Step-by-step explanation:

Хх0х

Answer:  134 miles

Step-by-step explanation:  

f(m) = 16.95 + 0.92m

140.23 = 16.95 + 0.92m

0.92m = 140.23 - 16.95

0.92m = 123.28

m = 123.28/0.92

m = 134 miles

The true statement about the function is C. function f and function g are not inverse because f{g(x)} = g{f(x)} .

An inverse function or an anti function, which can reverse into another function.In simple words, if any function “f” takes x to y then, the inverse of “f” will take y to x. If the function is denoted by 'f' or 'F', then the inverse function is denoted by f-1 or F-1.

now the given functions are,

f(x) = √(2x + 2) and

g(x) = (x^2 -2)/2

Now,

f{g(x)} = f{(x^2 -2)/2}

         = √(2(x^2 -2)/2 + 2)

         = √ x^2 -2 + 2

f{g(x)} = √ x^2

f{g(x)} =  x

Now,

g{f(x)} = g{ √(2x + 2)}

         = (√(2x + 2)^2 -2)/2

         = (2x + 2) -2 /2

         = 2x/2

f{g(x)} = x

Here we see that ,

f{g(x)} = g{f(x)}

Hence f and g are not inverses.

∴The true statement about the function is C. function f and function g are not inverse because f{g(x)} = g{f(x)} .

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The length of EB is approximately 14.6 units when rounded to the nearest tenth.

To find the length of EB, we can use the property of similar triangles in this diagram. By looking at triangle DFE and triangle CFB, we can see that they are similar triangles.

Using the similarity ratio, we can set up the proportion:

DF / CF = DE / EB

Plugging in the given values, we have:

13.1 / 10.9 = 17.5 / EB

To find EB, we can cross-multiply and solve for EB:

13.1 * EB = 10.9 * 17.5

EB = (10.9 * 17.5) / 13.1

EB ≈ 14.6

Therefore, the length of EB is approximately 14.6 units when rounded to the nearest tenth.

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Answer:D

Step-by-step explanation:

please mark brainliest

Answer:

9.50$

Step-by-step explanation:

First, multiply 20 by the given fractions

20*1/8=2.5

20*2/5=8

Add the two together to get the total amount of money Jeff spent, 10.5, then subtract 10.5 from 20 to get the total amount he has left, 9.5

Answer:

$9.50

I did a test with this question and the correct answer was 9.50

Answer: 13/51

Step-by-step explanation: After shuffling there are 52 permutations of 52 cards. Each has the probability of occurrence equal to another, that is the probability of any sequence of cards is 1/52.

Let's count only those where there is a red card on the first place and black card on the second. There are 26 red and 26 black cards. Therefore, we have 26 ⋅26 choices for a pair of two first cards. The sequence of other 50 cards in unimportant and any permutation among them is fine for us since we fixed the first two.

Therefore, we have 26 ⋅ 26 ⋅50 different permutations when the first card is red and the second is black.

Therefore, we have 26 ⋅ 26 ⋅50 different permutations when the first card is red and the second is black.

The final probability, therefore, is

26 ⋅26 ⋅50 / 52 = 26 ⋅26 / 52 ⋅ 51 = 13 / 51

13/51 is the final answer

Answer:

Step-by-step explanation:

In math some strengths are strong number sense, like being able to quickly compare groups of items and know which is larger and which is smaller. Weakness in math are incomplete mastery of number facts and difficulty transferring knowledge along with making connections.

Answer:

\(r \geqslant - 16\)

Step-by-step explanation:

\( \frac{ - 10 + r}{2} \geqslant - 13\)

multiply both sides by 2:

\( - 10 + r \geqslant - 26\)

add 10 on both sides:

\(r \geqslant - 16\)

Answer:

\(r \ge -16\)

Step-by-step explanation:

To solve any equation/inequality:

1. get the variable to show up exactly once

2. isolate it

\(\frac{-10+r}{2} \ge -13\)

Multiply both sides by 2 and simplify (note that we're multiplying by a positive, not a negative, so the direction of the inequality stays the same, whereas multiplying or dividing by a negative would have changed the direction of the inequality)

\(\frac{-10+r}{2} *2 \ge -13 *2\)

\(-10+r \ge -26\)

Add 10 to both sides, and simplify

\((-10+r)+10 \ge (-26)+10\)

\(r \ge -16\)

Answer:

495

Step-by-step explanation:

using the definition

n\(C_{r}\) = \(\frac{n!}{r!(n-r)!}\)

where n! = n(n - 1)(n - 2) ... × 3 × 2 × 1

then

12\(C_{4}\)

= \(\frac{12!}{4!(12-4)!}\)

= \(\frac{12!}{4!(8!)}\)

cancel 8! on numerator/ denominator

= \(\frac{12(11)(10)(9)}{4!}\)

= \(\frac{11880}{4(3)(2)(1)}\)

= \(\frac{11880}{24}\)

= 495

Answer:

Explanation:

Answer:

THX  OK

Step-by-step explanation: OK

Answer:

tysm

Step-by-step explanation:

The perimeter of the rectangle in scale is 48 inches

Perimeter of Rectangle could be considered as one of the important formulae of the rectangle. It is the total distance covered by the rectangle around its outside.

The formula of perimeter of a rectangle is given as

P = 2(L + W)

The length of the floor is 26 feet and the width is 22 feet.

But on the scale, the length is equal to 13 inches, we can find the width of the rectangle by calculating the scale

Using the dimensions;

26 feet = 13 inches

22 feet = x

x = (22 * 13) / 26

x = 11 inches

The perimeter of the scale drawing will be

P = 2(L + W)

P = 2 (13 + 11)

P = 2 * 24

P = 48 inches

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9514 1404 393

Answer:

  5 units

Step-by-step explanation:

The distance between the points can be found using the distance formula:

  d = √((x2 -x1)² +(y2 -y1)²)

  d = √((5 -1)² +(1 -4)²) = √(4² +(-3)²) = √(16 +9) = √25

  d = 5

The distance between the end points is 5 units.

Answer:

-10

Step-by-step explanation:

could u vote me brainliest plz, im trying to level up. thx:)

The segment CD is common on both ΔACD and ΔBCD.

Polygon, which has three sides and three vertices, is called a triangle.

The sum of all the angles of the triangle is 180°.

Given:

Two triangles ΔACD and ΔBCD in the given image.

To find the commonality between two triangles ΔACD and ΔBCD:

The sides of the triangle ΔACD are AC, CD, and AD.

The sides of the triangle ΔBCD are BC, CD, and BD.

From the diagram,

we can clearly see that the segment CD is common on both ΔACD and ΔBCD.

CD ≅ CD (reflexivity)

Therefore, the common segment is CD.

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Answer:

\(y=0.25x+4.25\)

Step-by-step explanation:

Step 1:  Determine the two forms

Point Slope Form → \((y-y_1)=m(x-x_1)\)

Slope Intercept Form → \(y=mx+b\)

Step 2:  Plug into point slope form

\((y-4)=0.25(x-(-1))\)

\(y-4=0.25(x+1)\)

Step 3:  Convert to slope intercept form

\(y-4+4=0.25x + 0.25+4\)

\(y=0.25x+4.25\)

Answer:  \(y=0.25x+4.25\)

The equation for the relationship between the number of bracelets made and the number of beads is y = 21x.

First, the rate of change

= (483 - 210) / (23 - 10)

= 273 / 13

= 21

So, the equation for the relationship between the number of bracelets made and the number of beads used.

(y - 210) = 21 (x-  10)

y - 210 = 21x - 210

y = 21x

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People started getting stimulus checks during the time when c0vid-19 was a major issue because most places where people would work were closed, so people were getting money through stimulus checks because they were basically unemployed. This money went back into the economy to buy mostly essentials and health products, so therefore it helped businesses that sold these kinds of things.

Step-by-step explanation:

x = pounds of cheaper chocolate

y = pounds of more expensive chocolate

30 pounds for $1.10 per pound were sold.

so, the 30 pounds cost

1.1 × 30 = $ 33.00

and then we know

x + y = 30

0.9x + 1.5y = 33

from the first equation we get

x = 30 - y

and we use that in the second equation

0.9×(30 - y) + 1.5y = 33

27 - 0.9y + 1.5y = 33

0.6y = 6

y = 10 pounds

x = 30 - y = 30 - 10 = 20 pounds

anyway, 10 pounds of the $1.50 chocolate was used.

The midpoint of the line segment with endpoints (-3,4) and (7,6) is (2,5).

The midpoint formula is expressed as:

\(M = (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2} )\)

Where (x₁, y₁) and (x₂, y₂) are the coordinates of the two endpoints of the line segment.

Given that:

Point 1 (-3,4)

Point 2 (7,6)

Plug the values into the above midpoint formula and simplify.

\(M = ( \frac{x_1+x_2}{2},\frac{y_1+y_2}{2} \\\\M = ( \frac{-3+7}{2},\frac{4+6}{2} )\\\\M = ( \frac{4}{2},\frac{10}{2} )\\\\M = (2,5)\)

Therefore, the midpoint of the line is (2,5).

Option 1) (2,5) is the correct answer.

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Answer:

s = (1/3) t³ - (3/2) t² - 2t + 4

Step-by-step explanation:

v = t² - 3t - 2

s = ∫v dt

= (1/3) t³ - (3/2) t² - 2t + c.

when s=10, t=6.

10 = (1/3) (6)³  - (3/2) (6)² - 2(6) + c

   = 72 - 54 - 12 + c

   = 6 + c

c = 10 - 6 = 4.

s = (1/3) t³ - (3/2) t² - 2t + 4

Recall the beta function definition and gamma identity,

\(\displaystyle \mathrm{B}(x,y) = \int_0^1 t^{x-1} (1-t)^{y-1} \, dt = \frac{\Gamma(x) \Gamma(y)}{\Gamma(x+y)}\)

Consider the sum

\(\displaystyle S(x) = \sum_{m=1}^\infty \frac{\Gamma(m) \Gamma(x)}{\Gamma(m+x)}\)

Compute it by converting the gammas to the beta integral, interchanging summation with integration, and using the sum of a geometric series.

\(\displaystyle S(x) = \sum_{m=1}^\infty \mathrm{B}(m,x) \\\\ ~~~~ = \sum_{m=1}^\infty \int_0^1 t^{m-1} (1-t)^{x-1} \, dt \\\\ \int_0^1 (1-t)^{x-1} \sum_{m=1}^\infty t^{m-1} \, dt \\\\ ~~~~ = \int_0^1 (1-t)^{x-2} \, dt \\\\ ~~~~ = \int_0^1 t^{x-2} \, dt \\\\ ~~~~ = \frac1{x-1} = \frac{(x-2)!}{(x-1)!} = \frac{\Gamma(x-1)}{\Gamma(x)}\)

It follows that

\(\displaystyle S(n+x) = \sum_{m=1}^\infty \frac{\Gamma(m) \Gamma(n+x)}{\Gamma(m+n+x)} = \frac{\Gamma(n+x-1)}{\Gamma(n+x)}\)

Now we compute the sum of interest. It's just a matter of introducing appropriate gamma factors to condense the double series into a single hypergeometric one.

Recall the definition of the generalized hypergeometric function,

\(\displaystyle {}_pF_q \left(\left.\begin{array}{c} a_1,a_2,\ldots,a_p\\b_1,b_2,\ldots,b_q\end{array}\right\vert z\right) = \sum_{n=0}^\infty \frac{(a_1)_n (a_2)_n \cdots (a_p)_n}{(b_1)_n (b_2)_2 \cdots (b_q)_n} \frac{z^n}{n!}\)

where \((a)_n\) denotes the Pochhammer symbol, defined by

\(\begin{cases}(0)_n = 1 \\ (a)_n = a(a+1)(a+2)\cdots(a+n-1) = \frac{\Gamma(a+n)}{\Gamma(a)}\end{cases}\)

We'll be needing the following identities later.

\((1)_n = n! = \dfrac{\Gamma(n+1)}{\Gamma(1)}\)

\((x)_n = \dfrac{\Gamma(n+x)}{\Gamma(x)}\)

\((x+1)_n = \dfrac{\Gamma(n+x+1)}{\Gamma(x+1)}\)

The \(m\)-sum is

\(\displaystyle \sum_{m=1}^\infty \frac{\Gamma(m)}{\Gamma(n+m+x)} = \frac1{\Gamma(n+x)} \sum_{m=1}^\infty \frac{\Gamma(m)\Gamma(n+x)}{\Gamma(n+m+x)} \\\\ ~~~~~~~~ = \frac{S(n+x)}{\Gamma(n+x)} \\\\ ~~~~~~~~ = \frac{\Gamma(n+x-1)}{\Gamma(n+x)^2}\)

Then the double sum reduces to

\(\displaystyle \sum_{n=1}^\infty \sum_{m=1}^\infty \frac{\Gamma(n)\Gamma(m)\Gamma(x)}{\Gamma(n+m+x)} = \sum_{n=1}^\infty \frac{\Gamma(n)\Gamma(x)\Gamma(n+x-1)}{\Gamma(n+x)^2}\)

Rewrite the summand. We use the property \(\Gamma(x+1)=x\Gamma(x)\) to convert to Pochhammer symbols.

\(\displaystyle \frac{\Gamma(n)\Gamma(x)\Gamma(n+x-1)}{\Gamma(n+x)^2} = \frac{\Gamma(n)\Gamma(x)^2\Gamma(n+x-1)}{\Gamma(n+x)^2 \Gamma(x)}\)

\(\displaystyle . ~~~~~~~~ = \frac1{x^2} \frac{\Gamma(n)\Gamma(x+1)^2\Gamma(n+x-1)}{\Gamma(n+x)^2\Gamma(x)}\)

\(\displaystyle . ~~~~~~~~ = \frac1{x^2} \frac{\Gamma(n) \frac{\Gamma(n+x)}{\Gamma(x)}}{\frac{\Gamma(n+x-1)^2}{\Gamma(x+1)^2}}\)

\(\displaystyle . ~~~~~~~~ = \frac1{x^2} \frac{(n-1)! (x)_{n-1}}{\left[(1+x)_{n-1}\right]^2}\)

Now in the sum, shift the index to start at 0, and introduce an additional factor of \(n!\) to get the hypergeometric form.

\(\displaystyle \sum_{n=1}^\infty \frac1{x^2} \frac{(n-1)! (x)_{n-1}}{\left[(1+x)_{n-1}\right]^2} = \frac1{x^2} \sum_{n=0}^\infty \frac{(n!)^2 (x)_n}{\left[(1+x)_n\right]^2} \frac1{n!} \\\\ ~~~~~~~~ = \frac1{x^2} \sum_{n=0}^\infty \frac{[(1)_n]^2 (x)_n}{\left[(1+x)_n\right]^2} \frac1{n!} \\\\ ~~~~~~~~ = \boxed{\frac1{x^2} \, {}_3F_2\left(\left.\begin{array}{c}1,1,x\\1+x,1+x\end{array}\right\vert1\right)}\)

The area of the shaded portion of the composite figure could be easily 25*25 - 1/2*13*10 that is 625 - 65 = 560 feet

When referring to a two-dimensional space or points, in mathematics, the term "area" is used. It refers to a region's or a flat object's size, such a square or rectangle. The area of a form is determined in geometry by dividing the length by the breadth. For example, the area of a square with a side length of 4 units is 4 x 4 = 16 square units. Square units, such as square inches, square feet, or square meters, are used to measure area. Triangles (1/2 x base x height), circles ( x radius squared), and trapezoids (1/2 x (base 1 + base 2) x height) are other basic geometric forms with associated area calculations.

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