Sue pumps up a bicycle tire as she does so she notices the pump becomes hot explain how the gas molecules in the tire excerpt pressure on the walls of the tire

Potholder should have high insulation and low conductivity, therefore the correct answer is the option B

Insulation is a type of material used to create barriers to the transmission of the form of energy which either is in form of heat or electricity.

For outdoor trips in cold weather, several thin layers act as better insulating barriers for heat transfer.

The ability of an electric charge or heat to pass through a material is measured by its conductivity. A material is considered a conductor if it offers very little resistance to the flow of thermal or electric energy.

Thus, Potholders should be highly insulated and have low conductivity, therefore the correct answer is the option B

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your question seems incomplete, the complete question is

To be effective, a pot holder should have low _____. viscosity conductivity malleability density

Mitosis is an essential mechanism for life, according to a National Human Genome Research Institute publication. A single cell divides into two genetically identical daughter cells during mitosis.

Multicellular organisms require this mechanism for growth, repair, and reproduction.

Because it doesn't use gametes or fertilization to create genetically identical daughter cells, mitosis is a type of asexual reproduction.

"Mitosis is a type of asexual reproduction that is essential for the growth and development of multicellular organisms," the National Center for Biotechnology Information explains.

Because it is essential for tissue growth and repair, mitosis is a vital process for all living things. The growth and repair of tissues as well as some organisms' asexual reproduction depend on mitosis, according to the American Society of Hematology.

Mitosis enables the expansion of tissues throughout development as well as the generation of new cells that can replace harmed or dying cells in the body.

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Answer:

Right

Explanation:

Coil move right yes

Two sportsmen engage in a tug-of-war by pulling on the rope with 190 N apiece. What is the rope's tension? The rope is under 190 N of tension.

During a tug of war, two opposing teams pull on the rope with equal and opposing forces of 10 KN at either end, creating an equilibrium condition. What is the rope's tension? The tension can match the force applied to any one side of the rope since the force is equal on both sides. As a result, choice C is the best one. A total force of 300 N plus 300 N, or 600 N, is applied when pulling in the same direction. If the two individuals If the two people are pulling against each other, the total force is 300 N in the rope is 300 N, or a net of zero.

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Yes the egg will crack when it hits the ground because its final velocity of 3.58 m/s is greater than the minimum velocity that will prevent it from cracking.

option A is the correct answer.

The time of motion of the egg is the time taken for the egg to hit the ground and it is calculated as follows;

h = vt + ¹/₂gt²

where;

h = 0 + ¹/₂gt²

t = √(2h/g)

t = √(2 x 16 / 0.4)

t = 8.94 seconds

The final velocity of the egg when it hits the ground is calculated as;

vf = vi + gt

vf = 0 + 8.94 s  x 0.4 m/s²

vf = 3.58 m/s

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The wavelength of the light is 1.92 * 10^-6 m which corresponds to the infrared region as shown in the image attached.

We know that the hydrogen atom has electrons that occupy energy levels that are in conformity with the Bohr model. According to the Bohr model, electrons can move from a higher to a lower energy level.

We now have;

1/λ = RH (1/\(n_{2} ^2\) - 1/\(n_{1}^2\))

λ = wavelength

RH = Rydberg constant

The initial and the final levels are also shown therefore;

1/λ = 1.097 * 10^7 ( 1/3^2 - 1/4^2)

1/λ= 1.097 * 10^7 (0.11 - 0.0625)

λ=1.92 * 10^-6 m

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The height of the tower if the distance AB is 50m is 22.36m.

What is distance?

Distance is a measurement of how far apart two objects or points are, either numerically or occasionally qualitatively. Distance can refer to a physical length in physics or to an estimate based on other factors in everyday language (e.g. "two counties over"). The term is also frequently used metaphorically to denote a measurement of the degree of separation between two common pieces (such as statistical distance between probabilistic or edit distance between strings of text). This is because spatial cognition is a rich source of implicatures in human thought. The concept of a metric space is used in mathematics to formalise the majority of these notions of distance, both literal and figurative.

Sol-Here in right ∆AOB

AB= 50m (as per given question)

Let height of the tower is =OD = A meters

in ∆AOD , tan theta= DO/AO

Tan 38= A/∆O

∆O= A /tan 38= a/0.78

Also in ∆ BOD

tan 29 = DO/BO

BO = a/tan 29°

=9/0.55

So a^2 = 500

=>a=10√5=22.36 approx.

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Answer:

Explanation:

The power rating of the battery isn't provided. But let us assume that it is one of the common batteries with ratings of 12 V and 50 A.h

Potential energy possessed by water at that height = mgh

m = mass of the water = ρV

ρ = density of water = 1000 kg/m³

V = volume of water = ?

g = acceleration due to gravity = 9.8 m/s²

h = height of water = 50 cm = 0.5 m

Potential energy = ρVgh = 1000 × V × 9.8 × 0.5 = (4900V) J

Energy of the battery = qV

q = 50 A.h = 50 × 3600 = 180,000 C

V = 12 V

qV = 180,000 × 12 = 2,160,000 J

Energy = 2,160,000 J

At a 100% conversion rate, the energy of the water totally powers the battery

(4900V) = (2,160,000)

4900V = 2,160,000

V = (2,160,000/4900)

V = 440.82 m³

Hence, with our assumed power ratings for the battery (12 V and 50 A.h), 440.82 m³ of water at the given height of 50 cm would power the battery.

Incase the power ratings of the battery in the complete question is different, this solution provides you with how to obtain the correct answer, given any battery power rating.

Hope this Helps!!!

Answer: Friction Forces

Explanation: (I took the same test and got the answer)

_________________________________________

I hope this helps!

After considering the given data and information we come to the conclusion that overall magnitude of the carts' common final velocity is 3.6 m/s, under the condition that a cart with mass m subscript 1 equals 0.25 space k g is at rest on a track.

Then, we can apply the law of conservation of momentum to evaluate the common final velocity of the carts.

The law of conservation of momentum projects that the total momentum of an isolated system stays constant if no external forces act on it. For this required case, the system is the two carts.

Before the collision, the first cart is in the rest and the second cart has a velocity of 6.17 m/s. Hence, the total momentum of the system before the collision is

p = m₁v₁ + m₂v₂

Here,

m1 and m2 are the masses of the carts and `v1` and `v2` are their velocities.

Staging the given values,

p = (0.25 kg)(0 m/s) + (0.35 kg)(6.17 m/s)

Applying simplification this expression

p = 2.16 kgm/s

Post the event of collision, the two carts stick along each other and move with a common final velocity `v`. The total momentum of the system after the collision is

p = (m₁ + m₂)v

Staging the given values, and evaluate for v

v = p / (m₁ + m₂)

Staging the given values

v = (2.16 kgm/s) / (0.25 kg + 0.35 kg)

v = 2.16/0.6

Applying simplification this expression

v ≈ 3.6 m/s

Then, the overall magnitude of the carts' common final velocity is approximately 3.6 m/s.

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Answer:

Explanation:

For this problem we use the translational equilibrium condition. Our reference frame for block 1 is one axis parallel to the plane and the other perpendicular to the plane.

X axis

      -Aₓ - f_e +T = 0        (1)

Y axis

      N₁ - W_y = 0              ( 2)

let's use trigonometry for the weight components

      sin θ = Wₓ / W

      cos θ = W_y / W

      Wₓ = W sin θ

      W_y = W cos θ

We write the diagram for the second body.

Note that in the block the positive direction rd upwards, therefore for block 2 the positive direction must be downwards

      W₂ -T = 0                             (3)

we add the equations is 1 and 3

       - W₁ sin θ - μ N₁ + W₂ = 0

from equation 2

       N₁ = W₁ cos θ

we substitute

        -W₁ sin θ - μ (W₁ cos θ) + W₂ = 0

W₂ = m₁ g (without ea - very expensive)

This is the smallest value that supports the equilibrium system

Answer:

2.2 ma

Explanation:

Given :

Length of the rope = L

Mass of the rope = m

Mass of the object pulled by the rope = M

M = 1.5 m

So, L \($\rightarrow$\) m

For unit length \($\rightarrow \frac{m}{L}$\)

∴ 0.3 L = \($0.3 \ L \left(\frac{m}{L}\right)$\)

            = 0.3 m

And for remaining 0.7 L =  \($0.7 \ L \left(\frac{m}{L}\right)$\)

            = 0.7 m

By Newtons law of motion,

F - T = ( 0.3 m) a .........(1)

T = ( M + 0.7 m) a

T = ( 1.5 m + 0.7 m) a

T = ( 2.2 m ) a  ..............(2)

So from equation (1) and (2), we have

Tension on the rope

T = 2.2 ma

It is not recommended to fire a gun straight up into the air.

When a bullet is fired into the air, it will eventually come down and can pose a danger to people and property below. The bullet can still be lethal when it reaches the ground, especially if it lands on a hard surface or hits someone directly.

Additionally, firing a gun in a residential area can be illegal and can result in legal consequences. In general, guns should only be fired in designated shooting ranges or in self-defense situations where there is an immediate threat to life. It is important to handle firearms responsibly and follow all safety guidelines to prevent accidents and injuries.

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The work required to move the particle with a charge of q = 19 microC from the other vertex to the center of the line joining the fixed charges is approximately -2.03 * 10^-14 J.

The work required to move a charge from one point to another in an electric field is given by the equation W = qV, where q is the charge and V is the potential difference.

In this case, the potential at the center of the line joining the two fixed charges can be calculated using Coulomb's law. The potential difference between the center and the third vertex can then be calculated, giving us the work required to move the particle with a charge q = 19 microC.

W = qV = 19 * 10^-6 C * V

Where V is the potential difference, which can be calculated as follows:

V = (1/(4 * pi * epsilon_0)) * ((Q / a) - (q / a))

Where epsilon_0 is the vacuum permittivity and a is the length of the sides of the equilateral triangle.

Substituting the values, we get:

W = 19 * 10^-6 C * (1 / (4 * pi * 8.854 * 10^-12 C^2/Nm^2)) * ((16 * 10^-6 C / 8 * 10^-6 m) - (19 * 10^-6 C / 8 * 10^-6 m))

W = 19 * 10^-6 C * (1 / (4 * pi * 8.854 * 10^-12 C^2/Nm^2)) * (-3 * 10^-6 C / 8 * 10^-6 m)

W = 19 * 10^-6 C * (1 / (4 * pi * 8.854 * 10^-12 C^2/Nm^2)) * (-3 * 10^-6 / 8) J

W = -2.03 * 10^-14 J

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The pressure of the gas in the deodorant can when it is heated to 900 K is 9 atm.

Gay-Lussac's law states that the pressure exerted by a given quantity of gas varies directly with the absolute temperature of the gas.

It is expressed as;

P₁/T₁ = P₂/T₂

From the data:

We substitute our values into the expression above and solve for final pressure.

P₁/T₁ = P₂/T₂

P₁T₂ = P₂T₁

P₂ = P₁T₂  / T₁

P₂ = ( 3 atm × 900 K ) / 300 K

P₂ = 9.0 atm

Therefore, the final pressure is 9.0 atm.

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Answer:

a

\(\frac{P_1}{P_2}  =  1.188 \  m \)

b

\( Z = 1.08995 \)

Explanation:

From the question we are told that

The filament temperature of the first bulb is \(T_1 = 2100 ^o C = 2100 + 273 = 2373 \ K \)

The filament temperature of the second bulb is \(T_3 = 2 0008^o C = 2000 + 273 = 2273 \ K\)

Generally according to Stefan-Boltzmann law the power emitted by first bulb is mathematically represented as

\(\frac{P}{A} = \sigma T^4_1 \)

Here \(\sigma\) is the Stefan-Boltzmann with value \(\sigma = 5.67*10^{-8} \ W . m ^{-2}. K ^{-4}\)

So

\(\frac{P_1}{A_1} = (5.67*10^{-8}) (2373)^4 \)

=> \(P_1 = 1797935 A_1 \)

Generally according to Stefan-Boltzmann law the power emitted by second bulb is mathematically represented as

\(\frac{P_2}{A_2} = \sigma T^4_2 \)

\(\frac{P_2}{A_2} = (5.67*10^{-8}) * (2273)^4 \)

=> \(P_1 = 1513494 A_2 \)

Given that the two bulbs are identical we have that

\(A_1 = A_2 = A\)

So

The ration is mathematically represented as

\(\frac{P_1}{P_2} = \frac{1797935* A}{1513494 *A}\)

=> \(\frac{P_1}{P_2} = 1.188 \ m \)

Generally the area is mathematically represented as

\(A = \pi r^2\)

Recall that

     \(A_1 = A_2 =  A\)

=>   \(\pi r^2_1 = \pi r^2_2 =  \pi r^2\)

=>   \(r^2_1 =  r^2_2 =  r^2\)

Now if the radius of the cooler bulb is increase by a factor Z (i.e Z * r )then the area of the cooler bulb \(A_2 [\tex] becomes

\( A_2 = (Zr)^2 \)

=>    \( A_2 = Z^2*r^2 \)

Here Z is the factor by which it is made thicker

So  For  \(\frac{P_1}{P_2}  =  \frac{1797935* A}{1513494 *A}\)

\( 1.188 = \frac{1797935* r^2}{1513494 *Z^2*r^2}\)

=> \( Z = 1.08995 \)

Answer:

1.142

Explanation:

Answer:

B is the answer bc it's no way c an a and d can maybe c

Answer:

Sound is the correct answer

The answer is B: Conduction

Answer:

D

Explanation:

when sharing ideas, you are being collaborative

The final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.

The time of motion of the girl is calculated as follows;

h = vt + ¹/₂gt²

where;

Substitute the given parameters and solve for time of motion;

50.8 = 0 + ¹/₂(9.8)t²

2(50.8) = 9.8t²

101.6 = 9.8t²

t² = 101.6/9.8

t² = 10.367

t = √10.367

t = 3.22 seconds

vf = vi + gt

where;

vi is the initial vertical velocity = 0

vf = 0 + 9.8(3.22)

vf = 31.56 m/s

Thus, the final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.

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The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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Answer:

First to find deceleration of the train we use

v²= u²+ 2as

56²= 73²+ 2(0.5)a

a= -2193mi/hr²

Then we find time in which the train does the intersection

Using

S= ut+ 1/2 at²

1= 73t-1/2(1293)t²

t =68.5s

But since the train is to intersect in 3.9s the time will be the difference which is

65.68s

So finding acceleration

S= ut + 1/2at²

1.3mi= 45/3600mi/s(65.58s)+ 1/2a(65.5)²

So a= 1.179ft/s²

To find velocity we use

V= u + at

= 45/3600mi/s + (-2.33E-4mis²)(65.58s)

V= 0.0271mi/s

= 97.6ft/s

Answer:

a = 52s²

Explanation:

How to find acceleration

Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt. This allows you to measure how fast velocity changes in meters per second squared (m/s^2). Acceleration is also a vector quantity, so it includes both magnitude and direction.

Solve

We know initial velocity (u = 16), velocity (v = 120) and acceleration (a = ?)

We first need to solve the velocity equation for time (t):

v = u + at

v - u = at

(v - u)/a = t

Plugging in the known values we get,

t = (v - u)/a

t = (16 m/s - 120 m/s) -2/s2

t = -104 m/s / -2 m/s2

t = 52 s

Answer: False

Explanation:

Since the positive x-direction was established to be to the right, the sleigh's velocity is in this direction (the positive x-direction).

The whole horizontal momentum is conserved since there is no external force operating on the system (the sleigh plus Jonathan and Jane) in the horizontal direction.

Let's say that the positive x-direction is to the right and the positive y-direction is up. Then, we may divide Jonathan and Jane's velocities into their x- and y-components as follows:

vx1 = 5.00 cos 30.0° = 4.33 m/s and vy1 = 5.00 sin 30.0° = 2.50 m/s are the speeds of Jonathan.

Jane's speed is given by the formulas vx2 = 7.00 cos 36.9° = 5.61 m/s and vy2 = 7.00 sin 36.9° = 4.16 m/s.

The sleigh is initially at rest, hence there is no initial total momentum in the x-direction. The total x-direction momentum after Jonathan and Jane jumps out is:

px = (−800 N)(−4.33 m/s) + (600 N)(5.61 m/s) = 6430 N·s

The final momentum in the x-direction is:

p'x = (1000 N + 800 N + 600 N)vx'

where vx' is the final velocity of the sleigh in the x-direction.

Therefore, we can solve for xv:

vx' = px / (1000 N + 800 N + 600 N) = 6430 N·s / 2400 N = 2.68 m/s

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