How much energy is required to Melt 450g of Ice?
Answer:
The latent heat of fusion for water is 334 joules per gram.
Explanation: im smart
Please help 50 points and Brainly
Mechanical energy → Electrical energy → Thermal energy
What is mechanical energy?
Mechanical energy is the energy possessed by an object due to its motion or position. It is the sum of kinetic energy and potential energy of an object, which can be converted to other forms of energy, such as electrical energy or thermal energy.
What is electrical energy?
Electrical energy is the energy associated with the movement of electrons through a conductor or an electrical circuit. It is the result of the movement of charged particles, such as electrons, and is commonly generated by the conversion of other forms of energy, such as mechanical, chemical, or solar energy.
What is thermal energy?
Thermal energy is the energy associated with the temperature of an object or a system. It is the result of the movement of atoms and molecules in matter, which leads to the transfer of heat from hotter to cooler objects. Thermal energy is commonly measured in units of joules or calories and is proportional to the mass and temperature of an object or a system.
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You take a couple of capacitors and connect them in series, to which you observe a total capacitance of 4.8microfarads. However, when you connect them in parallel their combined capacitance is 35microfarads. Determine the value of each capacitor.
Answer:
C₁ = 34.8 μF
C₂ = 0.2 μF
Explanation:
When the capacitors are connected in series their resultant capacitance is given by the formula:
Cs = 1/C₁ + 1/C₂
where,
Cs = Series equivalent capacitance = 4.8 μF
C₁ = Capacitance of 1st Capacitor
C₂ = Capacitance of 2nd Capacitor
Therefore,
4.8 μF = 1/C₁ + 1/C₂
(4.8 μF)(C₁ C₂) = C₁ + C₂ --------------- equation 1
When the capacitors are connected in parallel their resultant capacitance is given by the formula:
Cp = C₁ + C₂
where,
Cp = Parallel equivalent capacitance = 35 μF
Therefore,
35 μF = C₁ + C₂ -------------- equation 2
solving equation 1 and equation 2 simultaneously, we get:
C₁ = 34.8 μF
C₂ = 0.2 μF
What is the answer to question which statement correctly describes a characteristic that a scientific measuring tool should have ?
To be accurate, a scientific measuring instrument needs to be able to provide repeatable observations of a quantity.
How can you be scientific?of, pertaining to, or showing the scientific concepts or procedures. conducted scientifically or in accordance with findings of scientific investigation: by practicing or employing comprehensive or orderly procedures. advertising using science.
Who is referred to as scientific?A scientist is a person who methodically acquires data and uses it to form hypotheses, test those assumptions and further knowledge and understanding. Additional characteristics of a scientist include: their methodology, such as their use of statistics.
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IS BMI = Hight /Weight?
Yes or no ?
Answer:
Yes,BMI is a simple indicator of weight for height and can't differentiate between muscle mass and fat mass. So BMI tends to overestimate the health risk for adults with a high muscle mass, such as some athletes, and underestimate the risk for adults with a low muscle mass, as can occur with sedentary lifestyles.
Explanation:
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A box of mass m is lifted a vertical distance h in time t with a constant velocity The power supplied by the lifting force is approximately: (A) mght (B) mgh/tC) zero (D) mgt/h(E) mg/ht
Option B is correct. The power supplied by the lifting force is approximately mgh/t.
When an object is lifted upward with constant velocity, the force applied on that object is equal in magnitude and is opposite in direction to the force of gravity acting on the object. The force needed to lift something at a constant speed is equal to the weight of the object. This is known as the lifting force or weight of the body and its magnitude is given by:
lifting force = force of gravity = mass(m) × gravity(g)
Since, Power = (Force × distance) / t,
here, Force(F)= m × g
and, distance= h
Putting these in above formula P=F×d/t, we get :
P = mgh/t
Therefore, the power stored in the box will be mgh/t.
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A spring stretches 0.294-m when a 0.360-kg mass is gently suspended from it as in Fig. 11–3b. The spring is then set up horizontally with the 0.431-kg mass resting on a frictionless table as in Fig. 11–5. The mass is pulled so that the spring is stretched 0.250-m from the equilibrium point, and released from rest.
Determine:
(a) the spring stiffness constant k.
The spring constant k based on the information is 12.0 N/m.
How to calculate the valueFrom the information, a spring stretches 0.294-m when a 0.360-kg mass is gently suspended from it as in Fig. 11–3b. The spring is then set up horizontally with the 0.431-kg mass resting on a frictionless table.
The spring constant k is the force required to stretch or compress the spring by a unit distance. In this case, the spring is stretched by 0.294 m when a 0.360 kg mass is suspended from it.
This means that the force exerted by the spring is equal to the weight of the mass, which is 0.360 kg x 9.8 m/s^2 = 3.53 N.
Therefore, the spring constant k is:
= 3.53 N/0.294 m
= 12.0 N/m.
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Which of the following is NOT an example of a transverse wave?
A vibration of a guitar string
B. light from a star
C. sound from a tuning fork
D. ripple on pond surface
The sound from a tuning fork is not a transverse wave but a longitudinal wave
What is a tuning fork?A tuning fork is a two-pronged steel device used by musicians, which vibrates when struck to give a note of specific pitch.However, tuning forks are used in air, meaning they generate longitudinal sound waves. Well, as Kyle said: the sound produced by a tuning fork (or any other source) is a longitudinal wave. But, the tuning fork itself does both, transversal and longitudinal.A common example of longitudinal waves is sound waves, which are pressure waves or vibrations that travel through air or other materials, like water. Tuning forks produce a single note, or a specific sound, when struck by making the arms move in and out very rapidly (hundreds or thousands of times a second).
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the distance that a body in free fall falls each second is
a. is about 9.8m
b. is about 19.6m
c. increases as time passes
d. none of the above are correct
The distance that a body in free fall falls each second is (A). is about 9.8m is correct option.
The distance that a body in free fall falls each second is about 9.8 meters, which is equivalent to the acceleration due to gravity on the Earth's surface.
This means that in the absence of air resistance, an object dropped from a certain height will fall 9.8 meters during the first second, 19.6 meters during the second second, 29.4 meters during the third second, and so on. The distance increases as time passes, but not at a constant rate, as it is being affected by the acceleration due to gravity.
Therefore, the correct option is (a) .
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water flows into the house by means of pipe.inner diameter 2,4cm
absolute pressure 400kpa
flow rate 6
height 4
upper level inner diameter 1,2cm
calculate pressure at the upper level
The pressure at the upper level of a water flow into the house by means of pipe is 1081 kPa.
How to determine pressure?Calculate the cross-sectional area of the lower pipe:
A₁ = πr₁²
where:
A₁ = cross-sectional area of the lower pipe (m²)
π = mathematical constant (3.14)
r₁ = radius of the lower pipe (m)
A₁ = π(0.12 m)² = 0.0452 m²
Calculate the cross-sectional area of the upper pipe:
A₂ = πr₂²
where:
A₂ = cross-sectional area of the upper pipe (m²)
π = mathematical constant (3.14)
r₂ = radius of the upper pipe (m)
A₂ = π(0.06 m)² = 0.0113 m²
Calculate the flow rate per unit area:
q = Q/A
where:
q = flow rate per unit area (m³/s)
Q = flow rate (m³/s)
A = cross-sectional area (m²)
q = 6 m³/s / 0.0452 m² = 13.28 m²/s
Calculate the velocity of the water in the lower pipe:
v₁ = q/A₁
where:
v₁ = velocity of the water in the lower pipe (m/s)
q = flow rate per unit area (m³/s)
A₁ = cross-sectional area of the lower pipe (m²)
v₁ = 13.28 m²/s / 0.0452 m² = 29.3 m/s
Calculate the velocity of the water in the upper pipe:
v₂ = q/A₂
where:
v₂ = velocity of the water in the upper pipe (m/s)
q = flow rate per unit area (m³/s)
A₂ = cross-sectional area of the upper pipe (m²)
v₂ = 13.28 m²/s / 0.0113 m² = 117.0 m/s
Calculate the head loss:
hL = (v₁² - v2₂²) / 2g
where:
hL = head loss (m)
v₁ = velocity of the water in the lower pipe (m/s)
v₂ = velocity of the water in the upper pipe (m/s)
g = acceleration due to gravity (9.8 m/s²)
hL = (29.3 m/s)² - (117.0 m/s)² / 2(9.8 m/s²) = 23.2 m
Calculate the pressure at the upper level:
p₂ = p₁ + ρghL
where:
p₂ = pressure at the upper level (Pa)
p₁ = pressure at the lower level (Pa)
ρ = density of water (1000 kg/m³)
g = acceleration due to gravity (9.8 m/s²)
hL = head loss (m)
p₂ = 400 kPa + 1000 kg/m³(9.8 m/s²)(23.2 m) = 1081 kPa
Therefore, the pressure at the upper level is 1081 kPa.
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An object is attached to a trolley with a 0.80 kg mass, which is then pushed into an identical trolley at a speed of 1.1 m / s. The two trolleys couple together and move at a speed of 0.70 m / s after the collision. Calculate the mass of the object.
The mass of the object is approximately 0.457 kg.
The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.
Using the momentum equation, the mass of the object can be calculated as follows:
Total momentum before collision = Total momentum after collision
0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s
Solving for the mass of the object, we get:
0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s
0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object
0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object
0.32 kg = 0.70 kg * mass of the object
Dividing both sides by 0.70 kg, we find:
mass of the object = 0.32 kg / 0.70 kg = 0.457 kg
The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.
The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.
After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.
In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.
Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.
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(8.6) A space station in deep space is spun like a giant wheel to produce centrifugal force so the occupants experience artificial gravity of one g. How does a clock at the rim of the space station compare with one residing at the hub? What does this say about the behavior of a clock sitting on the surface of a planet with a surface gravity of one g?
The way that the clock at the rim of the space station compare with one residing at the hub is that Rim clock will always runs slower.
The behavior of a clock sitting on the surface of a planet with a surface gravity of one g is the same.
Is there a timepiece on the ISS?For instance, timekeeping on the International Space Station (ISS) is slightly slower than that of reference clocks on Earth. This explains why astronauts on the International Space Station (ISS) mature more slowly, lagging by 0.007 seconds every six months.
Ground-based atomic clocks have served as the industry standard for timekeeping since the 1950s. These clocks use the extremely steady and accurate frequencies of light emitted by particular atoms to keep time.
Therefore, Satellite clocks run slower due to more velocity but faster due to reduced gravity. Clocks move more slowly at the ISS orbital height because velocity dominates. At GPS altitude, clocks move more quickly due to the influence of gravity.
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Two charges, +4 µC and +14 µC, are fixed 1 m apart, with the second one to the right. Find the magnitude and direction of the net force (in N) on a −5 nC charge when placed at the following locations.
Answer:
\(0.0018\ \text{N/C}\) towards the right.
\(0.001\ \text{N/C}\) towards the right.
Explanation:
\(q_1=4\ \mu\text{C}\)
\(q_2=14\ \mu\text{C}\)
\(Q=5\ \text{nC}\)
\(r_1=r_2=0.5\ \text{m}\)
Let \(Q\) be placed at origin so \(q_1\) becomes negative and \(q_2\) becomes positive
Electric field is given by
\(E=\dfrac{kq_1Q}{r_1^2}+\dfrac{kq_2Q}{r_2^2}\\\Rightarrow E=\dfrac{kQ}{r^2}(q_1+q_2)\\\Rightarrow E=\dfrac{9\times10^{9}\times 5\times10^{-9}}{0.5^{2}}(-4\times10^{-6}+14\times10^{-6})\\\Rightarrow E=0.0018\ \text{N/C}\)
The electric field halfway between the points is \(0.0018\ \text{N/C}\) towards the right.
\(r_1=0.5\ \text{m}\)
\(r_2=1+0.5=1.5\ \text{m}\)
\(E=9\times 10^9\times 5\times 10^{-9}(\dfrac{4\times 10^{-6}}{0.5^2}+\dfrac{14\times 10^{-6}}{1.5^2})\\\Rightarrow E=0.001\ \text{N/C}\)
The electric field halfway between the points is \(0.001\ \text{N/C}\) towards the right.
A small oil droplet is sprayed between the plates of a parallel plate capacitor. The droplet has a net charge equal to that of 3 electrons and feels a total force equal to 9.6 x 10-15 N. What is the electric fieldbetween the plates of the parallel plate capacitor
Answer:
…..
Explanation:
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A textbook weighs 34 N on the surface of the Earth. What is the book’s mass on Earth’s surface?
Answer:
About 3.47kg
Explanation:
Recall that weight is equal to mass times acceleration.
In this case, our acceleration is due to gravity which on earth is about 9.8m/s/s
So we have 34N=9.8 *mass, divide both sides by 9.8 we get mass is equal to about 3.47kg.
Show your work
A 2.0 kg block rests on a level surface. The coefficient of static friction is µs = 0.50, and the coefficient of kinetic friction is µk = 0.30. A horizontal force, F, is applied to the block. As F is increased, the block begins moving.
a)Find the minimum force, F, required for the block to just start to move.
b)Find the force, F, required for the block to continue to move at a constant velocity.
c)Explain what happens to the motion of the block if a force is applied greater than those found above.
a. The minimum force required to start moving the block is 9.8 N
b. The force required to continue moving the block at a constant velocity is 5.88 N.
c. If a force greater than 9.8 N is applied, the block will start moving and continue to move until the applied force is less than 5.88 N.
How to calculate?a. Force = μs * N
N = m * g = 2.0 kg * 9.8 m/s^2 = 19.6 N
Force = μs * N = 0.50 * 19.6 N = 9.8 N
b. Force = μk * N = 0.30 * 19.6= 5.88 N N
c. In conclusion, If a force greater than 5.88 N is applied, the block will accelerate. If a force less than 5.88 N is applied, the block will decelerate and eventually stop if the force becomes less than the force of static friction (9.8 N).
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Which of the following is true about you objects with the same mass but different volumes?
does it has answer choices or
Answer:yea it doesnt have any answer chosices
Explanation:
A ball is projected at an angle of 53°. If the initial velocity is 48 meters/second, what is the vertical component of the velocity with which it was launched?
A.) 31 meters/second
B.) 38 meters/second
C.) 44 meters/second
D.) 55 meters/second
Answer:
The vertical component of the velocity can be found using the formula:
V₀y = V₀ * sin(θ)
where V₀ is the initial velocity, θ is the angle of projection, and V₀y is the vertical component of the velocity.
Substituting the given values, we have:
V₀y = 48 * sin(53°)
Using a calculator, we can evaluate sin(53°) to be approximately 0.799:
V₀y = 48 * 0.799
V₀y ≈ 38.352
Therefore, the vertical component of the velocity with which the ball was launched is approximately 38 meters/second, which corresponds to option B.
Answer:
B.) 38 meters/second
Explanation:
in object in motion tend to stay in motion in object in rest tends to stay in rest. "many years before newton wrote this law,__________stated the same idea as the principal of _______.
An object in motion tends to stay in motion in an object in rest tends to stay in rest. "many years before newton wrote this law, Galileo's the same idea as the principle of inertia.
This is further explained below.
What is inertia?Generally, When an item experiences inertia, it keeps moving in the same direction or at the same pace until another force changes it.
The phrase "the principle of inertia" as it is used in Newton's first rule of motion is correctly interpreted as the word "inertia."
In conclusion, The concept of inertia was first proposed by Galileo many years before Newton codified it as "an object in motion tends to remain in motion whereas an object in rest tends to stay in rest."
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Where is the near point of an eye for which a spectacle lens of power +2 D is prescribed for reading purpose?
The near point of a human eye is about a distance of 25 cm.
The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.
This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.
The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.
In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.
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formula for finding frequency of vibration of a particle
Answer:
The formula for finding the frequency of vibration of a particle is:
f = 1/T
where f is the frequency and T is the period of the vibration.
The period T is defined as the time it takes for one complete cycle of the vibration to occur. It is usually measured in seconds.
The frequency f is the number of cycles of the vibration that occur in one second. It is usually measured in Hertz (Hz), which is equal to one cycle per second.
Therefore, to find the frequency of vibration of a particle, you need to measure the period of the vibration and then use the formula f = 1/T to calculate the frequency
Explanation:
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A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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Select the correct answer from each drop-down menu.
Rocky metallic objects found between the orbits of Mars and Jupiter are(drop down). The largest known of these is(drop down).
Answer:
Blank 1 (asteroids)
Blank 2 (Ceres)
Explanation:
Rocky metallic objects found between the orbits of Mars and Jupiter are asteroids The largest known of these is ceres.
What are asteroids?Asteroids are stony elements that circle the Sun. Although asteroids circle the Sun in the same way as planets, they are considerably smaller.]
A dwarf planet located between Mars and Jupiter in the asteroid belt. Ceres was the first asteroid discovered, it was originally classed as a planet,
Rocky metallic objects found between the orbits of Mars and Jupiter are asteroids The largest known of these is ceres.
The correct option from the drop-down menu is asteroids and ceres.
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Conservation of Energy-not sure how to do problem-confused on how to find the speed and how to figure out energy bar graph
Given data
*The given mass of the rock is m = 2 kg
*The given potential energy is U_p = 407 J
(a)
The diagram of the energy bar graph is drawn below
(b)
If an object is at rest and has potential energy, once it starts to fall from its rest state then this potential energy is completely transferred to kinetic energy. This means that the magnitude of the kinetic energy is equal to the potential energy of the object.
The change in kinetic energy of the rock while falling to the ground is given as
\(\begin{gathered} U_k=U_p \\ =407\text{ J} \end{gathered}\)(c)
The formula for the speed of the block is given as
\(\begin{gathered} U_k=\frac{1}{2}mv^2 \\ v=\sqrt[]{\frac{2U_k}{m}} \end{gathered}\)Substitute the known values in the above expression as
\(\begin{gathered} v=\sqrt[]{\frac{2\times407}{2}} \\ =20.17\text{ m/s} \end{gathered}\)Hence, the speed of the object is v = 20.17 m/s
A single slit forms a diffraction pattern, with the first minimum at an angle of 40° from central maximum. Monochromatic light of 530 nm wavelength is used. The width of the slit, in nm, is closest to which of the following values?
757
723
689
791
825
Define invariant transformations
Answer:
For a given system, there can be particular transformations for which the explicit equations of motion are the same for both the old and new variables. Transformations for which the equations of motion are invariant, are called invariant transformations. It will be shown that if the Lagrangian does not explicitly contain a particular coordinate of displacement qi, then the corresponding conjugate momentum, pi, is conserved. This relation is called Noether’s theorem which states “For each symmetry of the Lagrangian, there is a conserved quantity".
When a point charge of q is placed on one corner of a square, an electric field strength of 2 N/C is observed at the center of the square. Suppose three identical charges of q are placed on the remaining three corners of the square. What is the magnitude of the net electric field at the center of the square
Answer:
Explanation:
Net electric field at the centre will be zero .
Since all the charges are equal and they all are symmetrically situated around the centre . So the electric field produced by each will cancel out each other and hence the resultant electric field will be zero . It happens because electric field is a vector quantity and therefore it adds up vectorially . All the four electric field will form two pairs , in each pair electric fields are acting in opposite direction . So they all cancel out to zero .
Una anciana camina 0.30 km en 10 minutos dando la vuelta un centro comercial calcule su rapidez media 
The average speed of the elderly woman walking around the shopping center is 1.80 km/h.
To calculate the average speed of the elderly woman, we can use the formula for velocity, which is equal to the distance traveled divided by the time taken. In this case, the distance traveled is 0.30 km and the time taken is 10 minutes. However, average speed is generally expressed in units of distance per unit of time, so we need to convert minutes to hours.
There are 60 minutes in one hour, so 10 minutes is equal to 10/60 = 1/6 hours.
Now we can calculate the average speed by dividing the distance traveled (0.30 km) by the time taken (1/6 hours):
Average speed = 0.30 km / (1/6 h)
= 0.30 km * (6/1 h)
= 1.80 km/h
Therefore, the average speed of the elderly woman walking around the shopping center is 1.80 km/h.
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An object’s final velocity is 32 m/s and has an acceleration of 2.4 m/s2 .
What is the initial velocity of an object at t = 8 s?
who is the father of kinematics ?
explain +)
Answer:
FRANZ REULEAUX
Late 19th century kinematics and the theory of machines as seen through the contributions of the German engineering scientist, Franz Reuleaux (1829-1905), often called the "father of kinematics". Extremely famous in his time and one of the first honorary members of ASME, Reuleaux was largely forgotten in much of modern mechanics literature in English until the recent rediscovery of some of his work. In addition to his contributions to kinematics, we review Reuleaux's ideas about design synthesis, optimization and aesthetics in design, engineering education as well as his early contributions to biomechanics. A unique aspect of this review has been the use of Reuleaux's kinematic models at Cornell University and in the Deutsches Museum as a tool to rediscover lost engineering and kinematic knowledge of 19th century history of machine.