Below is a possible implementation of the teamFormation function in Python:
sql
def teamFormation(score, team, m):
selected = []
for i in range(team):
if len(score) < m:
employee = max(score)
else:
left = score[:m]
right = score[-m:]
if max(left) >= max(right):
employee = max(left)
if left.count(employee) > 1:
index = score.index(employee)
else:
index = score.index(employee, 0, m)
else:
employee = max(right)
if right.count(employee) > 1:
index = score.index(employee, len(score)-m)
else:
index = score.index(employee)
score = score[:index] + score[index+1:]
selected.append(employee)
return sum(selected)
What is the function about?The function takes three arguments: the list of scores for each employee, the number of team members required, and the size of the array segments to select from. It initializes an empty list to store the selected employees' scores, and then enters a loop that repeats team times.
If the length of the score list is less than m, the function simply selects the employee with the highest score from the remaining list of employees.
Finally, the function returns the sum of the selected employees' scores.
Here's an example of how the function can be called:
makefile
score = [10, 20, 10, 15, 5]
team = 2
m = 1
result = teamFormation(score, team, m)
print(result) # Output: 30
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8. Find the volume of the figure shown below: * V=L x W x H 7 cm 2 cm 2 cm
How to create ground responce analysis using matlab
Which number is equivalent to the decimal number 149?
A.
11011011
B.
100101012
C. 001001112
D. 101010012
Answer:
letter B
Explanation:
basta yan anwer
an adiabatic compressor receives 1.5 meter cube per second of air at 30 degrees celsius and 101 kpa. The discharge pressure is 505 kpa and the power supplied is 325 kW, what is the discharge temperature
Answer:
The discharge temperature is 259.82 K
Explanation:
In this question, we are concerned with calculating the discharge temperature
Please check attachment for complete solution
LOLOLOLOKOLLOLLOLOLOO STRIKER KID THINKS HES SO GOOD LLOLOLOLOLOLOLOLOLOLOOLOLOLOLOLOLOL
Answer:
UUUUUUMMMM do you mean in soccer ????????????????
Explanation:
3. What is special about beryllium-copper alloy tools?
A. They don't conduct electricity.
B. They don't spark.
C. They stay sharp.
D. They're extremely strong.
Answer
Explanation:
A
it's because it won't conduct them but if it was B it would so the answer is A
The thing that is special about beryllium-copper alloy tools is that they don't spark. Therefore, the correct option is option B.
One unique feature of beryllium-copper alloy tools is that they do not ignite. This feature is especially useful in businesses or locations where flammable gases or vapours may be ignited. The use of beryllium-copper alloy tools reduces the possibility of sparking and subsequent ignition, improving safety in such situations.
While the other possibilities may be desirable properties for some tools or materials, they are not specifically linked with tools made of beryllium-copper alloy. Beryllium-copper alloys, for example, are well-known for their high strength but are not necessarily "extremely strong" in compared to other materials.
Therefore, the correct option is option B.
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Technician a says that diesel engines can produce more power because air in fuel or not mix during the intake stroke. Technician be says that diesel engines produce more power because they use excess air to burn feel who is correct
Answer:
Technician be says that diesel engines produce more power because they use excess air to burn feel who is correct
Explanation:
He is correct as many engines are run by diesel. It produces more power as that is how cars produce more power.
The signal from a flow transmitter is filtered using a low-pass filter to ensure that the maximum frequency content of the pressure transmitter signal is 20 Hz. What is the minimum frequency with which the signal must be sampled (digitized) to satisfy the Nyquist sampling criterion
Answer:
40 Hz
Explanation:
To satisfy the Nyquist sampling criterion, the sampling rate must be at least twice the highest frequency contained in the signal being sampled.
2 × 20 Hz = 40 Hz
The minimum sampling frequency is 40 Hz.
You will be using the fictional manufacturing facility Acme Automotive Parts (AAP) throughout the course. AAP manufactures several support parts for new automobiles as a small supplier to Nissan, Honda, and Volkswagen facilities in the United States. Their processes include shipping/receiving, hydraulic presses, metal working lines, robotic welding stations, hand-welding stations in rework areas, two small paint booths, a quality assurance/quality control (QA/QC) laboratory, and a final inspection area.
For this unit please answer the following question:
Determine what information you would use to anticipate health hazards that might be present in each of the eight areas of the AAP plant. State where you might find the information you need.
To anticipate health hazards in each of the eight areas of the AAP plant, the following information could be used:
1. Shipping/Receiving:
Type of materials being received and shippedPossible exposure to hazardous chemicals, dust, and fumesPossible exposure to heavy machinery and equipmentInformation could be found in Material Safety Data Sheets (MSDS) for the materials, as well as through workplace observations and assessments.2. Hydraulic Presses:
Possible exposure to hydraulic fluids and associated fumesPossible exposure to high pressure and loud noise levelsInformation could be found in MSDS for hydraulic fluids and through workplace assessments and monitoring.3. Metal Working Lines:
Possible exposure to metal dust, fumes, and particlesPossible exposure to high noise levelsPossible exposure to sharp edges and hot surfacesInformation could be found through workplace assessments and monitoring, as well as through MSDS for any chemicals used in the metal working process.4. Robotic Welding Stations:
Possible exposure to welding fumes, dust, and particlesPossible exposure to high noise levelsPossible exposure to high heat and bright lightInformation could be found through workplace assessments and monitoring, as well as through MSDS for any chemicals used in the welding process.5. Hand-Welding Stations in Rework Areas:
Same hazards as in robotic welding stationsPossible exposure to sparks and hot surfacesInformation could be found through workplace assessments and monitoring, as well as through MSDS for any chemicals used in the welding process.6. Small Paint Booths:
Possible exposure to paint fumes and particulate matterPossible exposure to high noise levelsInformation could be found through workplace assessments and monitoring, as well as through MSDS for the paint materials.7. QA/QC Laboratory:
Possible exposure to chemicals and hazardous materials used in testing and analysisPossible exposure to high noise levels from laboratory equipmentInformation could be found through workplace assessments and monitoring, as well as through MSDS for the chemicals and hazardous materials used in the laboratory.8. Final Inspection Area:
Possible exposure to dust and fumes from various manufacturing processesPossible exposure to high noise levelsInformation could be found through workplace assessments and monitoring, as well as through MSDS for any chemicals used in the final inspection process.To anticipate health hazards in each area of Acme Automotive Parts (AAP) manufacturing facility, the following information would be relevant.
What are the information that are relevant in this case?1. Shipping/Receiving: Material Safety Data Sheets (MSDS) for chemicals received, potential for heavy lifting injuries, and risks associated with forklift operations.
2. Hydraulic Presses and Metal Working Lines: MSDS for lubricants and coolants, risks of crush injuries, and exposure to metal fumes.
3. Robotic and Hand-Welding Stations: MSDS for welding materials, welding fume exposure, and risk of burns.
4. Paint Booths: MSDS for paints and coatings, potential for volatile organic compounds (VOCs) exposure, and respiratory hazards.
5. QA/QC Laboratory: MSDS for chemicals used in testing, potential for chemical exposure, and ergonomic risks.
6. Final Inspection Area: Ergonomic risks associated with repetitive tasks, MSDS for any chemicals used, and general safety precautions.
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what type of nuclear decay produces energy instead of a particle?
The type of nuclear decay that produces energy instead of a particle is nuclear fusion.
Nuclear fusion is a process in which two atomic nuclei join together to form a larger nucleus, releasing a significant amount of energy in the process. The energy produced is much greater than that produced by nuclear fission, which is another type of nuclear decay that involves the splitting of an atomic nucleus into smaller fragments. Nuclear decay is a process of spontaneous transformation of an unstable atomic nucleus to a more stable configuration accompanied by the release of energy or the emission of subatomic particles. There are several types of nuclear decay such as alpha decay, beta decay, and gamma decay. This question is concerned with the type of nuclear decay that produces energy instead of a particle. Nuclear fusion is a type of nuclear reaction that involves the merging of two atomic nuclei to form a single, more massive nucleus. During the process, a significant amount of energy is released in the form of light, heat, and radiation. This energy is the result of the conversion of a small portion of the mass of the atomic nuclei into energy, as predicted by Albert Einstein's famous equation, E = mc². Nuclear fusion is the energy source of stars like the Sun and other main-sequence stars. It is also being developed as a potential source of energy on Earth, through experiments like the International Thermonuclear Experimental Reactor (ITER) project, which aims to harness nuclear fusion to produce clean and sustainable energy.
In conclusion, the type of nuclear decay that produces energy instead of a particle is nuclear fusion. It is a process in which two atomic nuclei join together to form a larger nucleus, releasing a significant amount of energy in the process. Nuclear fusion is the energy source of stars like the Sun and other main-sequence stars and is being developed as a potential source of energy on Earth.
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in welding connections, the additional metal, sometimes referred to as metal, is deposited from a special electrode, which is part of an electrical circuit that includes the connected part, or metal. group of answer choices a.
In welding connections, the additional metal often referred to as filler metal, is deposited from a special electrode, which is part of an electrical circuit that has the connected part, or welding rod metal. Thus, D. 'filler; welding rod' is the correct answer.
Filler metal is referred to any material that is used to join two pieces of metal during soldering or welding. As the two items are held together, the filler metal is melted between the two to produce a bridge. After the filler dries, it combines with the items on either side to produce a permanent bond. While welding rods are pieces of metal that are heated to high temperatures and used as a filler to fuse other metals together. Thus, for this question option 'D' holds the correct answer.
"
Complete question:
In welding connections, the additional metal, sometimes referred to as metal, is deposited from a special electrode, which is part of an electrical circuit that includes the connected part, or metal. group of answer choices
A: base; flux
B: flux; shielded
C: base; welding rod
D: filler ; welding rod
"
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What is the maximum number of points a player can score during a frame of snooker while curving around at a 45 degree angle going at a speed of 2 miles per hour with the wind speed of 2 mph on a rug coated snooker table?
In snooker, the maximum number of points that can be scored during a single frame is 147. This is achieved by potting all 15 red balls, each worth 1 point, and subsequently potting the colored balls in sequence: yellow (2 points), green (3 points), brown (4 points), blue (5 points), pink (6 points), and black (7 points). Each color is then returned to its original position and can be potted again for additional points.
The angle and wind speed mentioned in your question are not relevant to determining the maximum number of points in a snooker frame. The speed and direction of the balls are controlled by the player's shots, and the rug coating on the table doesn't affect the scoring.
So, regardless of the angle, wind speed, or table surface, the maximum number of points that can be scored in a frame of snooker is 147.
An automobile having a mass of 1100 kg initially moves along a level highway at 120 km/h relative to the highway. It then climbs a hill whose crest is 80 m above the level highway and parks at a rest area located there. Use a reference with kinetic and potential energy each equal to zero for the stationary highway before the hill. Let g = 9.81 m/s^2.
For the automobile, determine its change in kinetic energy and its change in potential energy, both in kJ. For the automobile, determine its change in kinetic energy, in kJ.
a. -8594
b. -663.1
c. -6.63x10^5
d. 663.1
Answer:
\(-6111.11\ \text{kJ}\)
\(863.28\ \text{kJ}\)
Explanation:
m = Mass of automobile = 1100 kg
v = Velocity of car = 120 km/h = \(\dfrac{120}{3.6}\ \text{m/s}\)
h = Height of hill = 80 m
g = Acceleration due to gravity = \(9.81\ \text{m/s}^2\)
Change in kinetic energy
\(KE=\dfrac{1}{2}m(u^2-v^2)\\\Rightarrow KE=\dfrac{1}{2}\times 1100\times (0-(\dfrac{120}{3.6})^2)\\\Rightarrow KE=-611111.11\ \text{J}\)
Change in kinetic energy is \(-6111.11\ \text{kJ}\)
Change in potential energy is given by
\(PE=mgh\\\Rightarrow PE=1100\times 9.81\times 80\\\Rightarrow PE=863280\ \text{J}\)
The change in potential energy is \(863.28\ \text{kJ}\).
technician a says that loose ball joints can cause the vehicle to wander. technician b says that loose control arm bushings can affect alignment angles. who is correct?
Technician a is correct. The car may veer off course due to loose ball joints. The propensity of a vehicle to veer from one side of the road to the other is known as wander.
The propensity of a vehicle to veer from one side of the road to the other is known as wander. Uneven tire pressure or mismatched tires are potential causes number one. Linkage binding or inadequate lubrication is a potential cause number two. The third potential factor is binding or inadequate lubrication of the steering gear.
The bottom line is that before you start to address poor steering performance, you must identify the underlying source of the issue. Oversteer and understeer have been discussed separately, but we've also included 10 other common steering issues with their likely causes below. You can stop cursing and start fixing your steering problems by locating potential problem areas.
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A total of 10 rectangular aluminum fins (k = 203 W/m·K) are placed on the outside flat surface of an electronic device. Each fin is 100 mm wide, 20 mm high and 4 mm thick. The fins are located parallel to each other at a center-to-center distance of 8 mm. The temperature at the outside surface of the electronic device is 72°C. The air is at 20°C, and the heat transfer coefficient is 80 W/m^2·K. Determine:
a. the rate of heat loss from the electronic device to the surrounding air
b. the fin effectiveness.
Answer:
a. the rate of heat loss from the electronic device to the surrounding air
A total of 10 rectangular aluminum fins (k = 203 W/m·K) are placed on the outside flat surface of an electronic device. Each fin is 100 mm wide, 20 mm high and
4 mm thick. The fins are located parallel to each other at a center-to-center distance of 8 mm. The temperature at the outside surface of the electronic device is 72°C. The air is at 20°C, and the heat transfer coefficient is 80 W/m2·K. Determine (a) the rate of heat loss from the electronic device to the surrounding air and (b) the fin effectiveness.
Explanation:
Sorry if wrong, Hope I helped
~#Lilly
234567891234567891234567891
Answer:
234567891234567891234567891 what is this?????
Explanation:
234567891234567891234567891
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How many crankshaft revolutions in degrees is needed to complete 4-strokes?
A. 180
B. 360
C. 90
D. 720
360 crankshaft revolutions in degrees is needed to complete 4-strokes.
What is crankshaft?
A crankshaft is a cylindrical shaft that converts reciprocating linear piston motion into rotation. It is typically found in internal combustion engines and is connected to the pistons by way of connecting rods. The rotation of the crankshaft allows the pistons to move up and down, creating the combustion necessary to power the engine. The crankshaft is usually located at the bottom of the engine and is made up of several main components, including the crankshaft main journals, crankshaft main bearing caps, connecting rod caps, and the crankshaft throws. The crankshaft is also connected to the flywheel, which helps to maintain smooth and consistent power output from the engine.
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Match the use of the magnetic field to its respective description.
oooExplanation:
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In flowing from section (1) to section (2) along an open channel, the water depth decreases by a factor of two and the Froude number changes from a subcritical value of 0.4 to a supercritical value of 2.5. Determine the channel width at (2) if it is 13 ft wide at (1).
Answer:
channel width = 2.621 ft
Explanation:
Given data :
Decreasing Factor = 2
subcritical value = 0.4
super critical value = 2.5
width = 13 ft
attached below is a detailed solution and
help protect the lower legs and feet from heat hazards like molten metal and welding sparks
Answer:
i think its called leggings thats wut my shop teacher told me
Explanation:
Which view of an architectural design displays the complex interior features of an object concealed by hidden lines
Answer:
Cutting-plane View
Explanation:
The view of an architectural design, by which it displays the complex interior features of an object concealed by hidden lines, is a cutting-plane view.
What is view of an architectural design?View of an architectural design is a method of representation of the design of a building or an item from the different perspective.
The cutting-plane view is generally used to represent the complex interior features in an architectural design.
The cutting-plane view is presented by the hidden lines, which is shown in architectural design.
Thus, the view of an architectural design by which it displays the complex interior features of an object concealed by hidden lines, is cutting-plane view.
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Temporal locality of reference is related to a recently used resource is likely to be used again in the near future. O True O False
Temporal locality of reference is related to a recently used resource is likely to be used again in the near future. The given statement is true.
What is temporal locality?
A recent execution of an instruction has a high probability of being repeated, which is referred to as temporal locality. As a result, the instruction is stored in cache memory where it can be quickly retrieved without having to seek for it.
The concept of Temporal locality is that a resource that is referenced at one point in time will be referenced again sometime in the near future.
Temporal locality of reference is related to how many times a resource is used.
Therefore, the given statement is true.
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A hypothetical metal has an orthorhombic unit cell for which the a, b, and c lattice parameters are 0.413 nm, 0.665 nm, and 0.876 nm, respectively. (a) if there are 8 atoms per unit cell and the atomic packing factor is 0.536, determine the atomic radius (in nm). (b) if the density is 3.99 g/cm3, calculate the metal's atomic weight (in g/mol).
To determine the atomic radius, we need to calculate the volume of the unit cell first. The volume of an orthorhombic unit cell is given by \(V = a * b * c\). Plugging in the values, we get \(V = 0.413 nm * 0.665 nm * 0.876 nm\)
\(= 0.198 nm^3\). Next, we can calculate the volume occupied by each atom in the unit cell. Since there are 8 atoms in the unit cell, the volume occupied by each atom is \(V/8 = 0.198 nm^3 / 8 = 0.02475 nm^3.\)
The atomic packing factor (APF) is defined as the ratio of the volume occupied by atoms to the total volume of the unit cell. In this case, APF = (Volume of atoms) / (Volume of unit cell) = 0.02475 nm^3 / 0.198 nm^3\(= 0.02475 nm^3 / 0.198 nm^3\)
= 0.125. Now, we can use the formula for APF in terms of the atomic radius (r) to solve for r. The formula is
\(APF = (4/3) * π * r^3 / (a * b * c)\). Rearranging the formula, we have
\(r = (APF * a * b * c / (4/3 * π))^(1/3)\). Plugging in the values, we get
r = (0.536 * 0.413 nm * 0.665 nm * 0.876 nm / (4/3 * π))^(1/3) \(r = (0.536 * 0.413 nm * 0.665 nm * 0.876 nm / (4/3 * π))^(1/3)\)
= 0.119 nm.
Therefore, the atomic radius is 0.119 nm.
To calculate the metal's atomic weight, we can use the formula: density = (atomic weight * number of atoms in the unit cell) / (volume of unit cell * Avogadro's number). Rearranging the formula, we have atomic weight = (density * volume of unit cell * Avogadro's number) / (number of atoms in the unit cell).
Therefore, the metal's atomic weight is\(4.7908 × 10^-21 g/atom.\)
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which of the following is true for the depletion region capacitance of a pn junction? select one: a. all of these b. the capacitance depends on the square root of the reverse bias for an abrupt step junction c. the capacitance depends on the cube root of the reverse bias for a linearly graded junction d. the capacitance decreases as the reverse bias increases e. the amount of charge stored increases as the reverse bias increases
All of these statements are true.
The depletion region functions as an insulating or dielectric substance. P-n junction diodes can therefore be compared to parallel plate capacitors.
What is PN junction?A P-N junction is the boundary or interface between the p-type and n-type semiconductor material types inside of a semiconductor.The process of doping produces the P-N junction in a semiconductor.In an electrical circuit, a diode (PN junction) makes it easier for current to flow in one way than the other.While reverse biasing is applying a voltage across a diode in the opposite direction, forward biasing refers to applying a voltage across a diode that facilitates easy current passage. High resistance is present in the p-n junction diode's depletion zone.As a result, the depletion region functions as an insulating or dielectric substance.P-n junction diodes can therefore be compared to parallel plate capacitors.Transition capacitance is the measurement of how much capacitance changes as voltage increases.
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Every motor vehicle except for
grade.
must be equipped with a parking brake that can hold a vehicle stationary on any
a) Motorcycles
b) Ambulances
c) Garbage trucks
Answer:
Motor Cycles
Explanation:
Motor cycles have no parking brake
A zoning ordinance typically governs which of the following?
a. Types of activities that may take place on a piece of land
b. How much of the land may be covered by a building
c. How far a building must be set back from property lines
d. The size of exits in a building
Find the etch selectivity required to etch a 400-nm polysilicon layer without removing more than 1 nm of its underlying gate oxide, assuming that the polysilicon is etched with a process having a 10% etch-rate uniformity.
The required etch selectivity is given by: Etch selectivity = Vp / Vo
Etch selectivity is defined as the ratio of etch rates between two different materials. In the context of microfabrication, it is commonly used to describe the ability of a particular etchant to preferentially etch one material over another.In this question, we are given that we need to etch a 400-nm polysilicon layer without removing more than 1 nm of its underlying gate oxide. Let us assume that the etching process has a 10% etch-rate uniformity.
This means that the etch rate of the polysilicon layer will be uniform within ±10% of the average etch rate. Let the average etch rate be denoted by Vp and the etch rate of the oxide layer be denoted by Vo.
Using the definition of etch selectivity, we have:
Etch selectivity = Vp / Vo
We want to find the etch selectivity required to etch the polysilicon layer without removing more than 1 nm of the oxide layer. Therefore, we can write:
Vp x t = (Vp / Etch selectivity) x t + 1 nm
where t is the etch time required to etch the polysilicon layer, assuming a uniform etch rate.
Rearranging this equation, we get:
Etch selectivity = Vp / (Vp - (t / t) x 1 nm)
We are given that the polysilicon layer thickness is 400 nm.
Assuming a uniform etch rate, the etch time required to etch this layer is given by:
t = 400 nm / Vp
We are also given that we cannot remove more than 1 nm of the oxide layer.
Therefore, we have: Vp / (Vp - (400 nm / Vp) x 1 nm) > 1 + 1 / 400
This inequality represents the condition that the selectivity must be greater than the ratio of the thickness of the oxide layer to the thickness of the polysilicon layer plus 1. Solving this inequality for Vp, we get:
Vp > 0.304 µm/min
Therefore, the etch rate of the polysilicon layer must be greater than 0.304 µm/min to ensure that the oxide layer is not removed by more than 1 nm. The required etch selectivity is given by: Etch selectivity = Vp / Vo
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Lucia is playing with magnetic toy vehicles. She has two identical toy vehicles (purple and pink) that start on opposite sides of a center magnet that cannot move. She moves both vehicles one space closer to the center magnet
Incomplete question. The remaining part of the question read;
How did the potential energy of the two vehicles change? Did the potential energy of one vehicle change more than the other? Why do you think so?
Explanation:
1. The potential energy of the two vehicles increased because we could observe that they have unlike poles moving towards the center of the magnet. So the magnet field would be repealing both toy vehicles.
2. The potential energy of the pink vehicle change more than the purple vehicle. This is evident as we notice the pink vehicle is closer to the center of the magnet than the other.
3. The reason for this is because Lucia exerts more force (potential energy) on the pink vehicle to fight the repelling effect of the magnet
Answer:
1. The potential energy of the two vehicles increased because we could observe that they have unlike poles moving towards the center of the magnet. So the magnet field would be repealing both toy vehicles.
2. The potential energy of the pink vehicle change more than the purple vehicle. This is evident as we notice the pink vehicle is closer to the center of the magnet than the other.
3. The reason for this is because Lucia exerts more force (potential energy) on the pink vehicle to fight the repelling effect of the magnet
Explanation:
The moisture content of a saturated clay is 160 %. The specific gravity of the soil solids Gs is 2.40. What are the wet and dry densities of the saturated clay? hints: what is the degree of saturation of a saturated soil?)
Answer: 162.4
Sorry if you get it wrong :(
Explanation:
The Aluminum Electrical Conductor Handbook lists a dc resistance of 0.01558 ohm per 1000 ft at 208C and a 60-Hz resistance of 0.0956 ohm per mile at 508C for the all-aluminum Marigold conductor, which has 61 strands and whose size is 1113 kcmil. Assuming an increase in resistance of 2% for spiraling, calculate and verify the dc resistance. Then calculate the dc resistance at 508C, and determine the percentage increase due to skin effect.
Answer:
a) 0.01558 Ω per 1000 feet
b) 0.0923 Ω per mile
c) 3.57%
Explanation:
a) Calculate and verify the DC resistance
Dc resistance = R = р \(\frac{l}{A}\)
for aluminum at 20°C
р = 17 Ωcmil/ft
hence R = 17 * 1000 / ( 113000 ) = 0.01527 Ω per 1000 feet
there when there is an increase in resistance of 2% spiraling
R = 1.02 * 0.01527 = 0.01558 Ω per 1000 feet
b) Calculate the DC resistance at 50°C
R2 = R1 ( \(\frac{T+t2}{T+ t1}\) )
where ; R1 = 0.01558 , T = 228 , t2 = 50, t1 = 20 ( input values into equation above )
hence R2 = ( 0.01746 / 0.189 ) Ω per mile = 0.0923 Ω per mile
c ) Determine the percentage increase due to skin effect
AC resistance = 0.0956 ohm per mile
Hence; Increase in skin effect
= ( 0.0956 -0.0923 ) / 0.0923
= 0.0357 ≈ 3.57%