The answer is A Height and Mass
Gravitational potential energy depends on the strength of gravity; A. height and mass of the object.
Gravitational potential energy (G.P.E) can be defined as the energy possessed by a physical object or body due to its position (height) above planet Earth.
Hence, gravitational potential energy (G.P.E) is highly dependent on mass, height of an object or body and the acceleration due to gravity.
Mathematically, gravitational potential energy (G.P.E) is given by the formula;
\(GPE = mgh\)
Where:
G.P.E is the gravitational potential energy. m is the mass of an object. g is the acceleration due to gravity. h is the height of an object.In conclusion, the three (3) main factors that gravitational potential energy (G.P.E) depends on are:
I. Strength of gravity.
II. Height.
III. Mass.
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Homeostasis refers to
A.
the similarity of genetic traits to one another.
B.
a mixture or solution that is the same throughout.
C.
the tendency of a cell to maintain a stable internal environment.
D.
the effect of natural selection on human evolution.
NEED HELP QUICK!!!!!!!!
Answer:
(C)
the tendency of a cell to maintain a stable internal environment.
Answer:
Homeostasis refers to C. the tendency of a cell to maintain a stable internal environment.
Earth and Jupiter are shown next to each other. Earth is much smaller than Jupiter.
Why is Jupiter so much larger than Earth? Check all that apply.
Inner planets were created at higher velocities.
Outer planets have less gravity than inner ones.
Outer planets attracted helium, hydrogen, and other gasses.
Inner planets formed where temperatures were cooler.
Gases escaped from inner planets and not from outer ones.
Answer:
A, C, and E. I hope you have a good day.
Explanation:
Answer:
1, 3, and 5
Explanation:
when a catalyst is added to a reaction mixture, it group of answer choices provides reactant molecules with more energy. increases the rate of collisions between reactant molecules. none of these choices are correct. provides a new pathway (mechanism) for the reaction. slows down the rate of the back reaction.
When a catalyst is added to a reaction mixture, it provides a new pathway or mechanism for the reaction. This means that the catalyst creates an alternative route for the reaction to occur, which is typically a lower energy pathway than the original reaction mechanism.
By providing this new pathway, the catalyst reduces the activation energy required for the reaction to take place, making it easier for reactant molecules to participate in the reaction.
It is important to note that while a catalyst does not provide reactant molecules with more energy, it does increase the rate of collisions between reactant molecules. This is because the catalyst alters the structure of the reactants, making it more likely for them to collide in a way that promotes the desired reaction.
While a catalyst does not slow down the rate of the back reaction, it can often shift the equilibrium of the reaction in favor of the desired product. This is because the catalyst increases the rate of the forward reaction, making it more likely that products will be formed before they have a chance to react and form reactants again.
In summary, the addition of a catalyst to a reaction mixture provides a new pathway or mechanism for the reaction, increases the rate of collisions between reactant molecules, and can shift the equilibrium of the reaction in favor of the desired product.
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Which explanations did you include in your response? Check all that apply. The oxidation number of carbon changes from -1 to +4. The oxidation number of oxygen changes from 0 to -2. Carbon is oxidized. Oxygen is reduced. Electrons are transferred from carbon to oxygen.
Answer:
B, E
Explanation:
Edge
Arroyave AM, Penaranda EK, Lewis CL. Organizational change: a way to increase colon, breast and cervical cancer screening in primary care practices. J Community Health. 2011;36(2)281-88
Arroyave, Penaranda, and Lewis in 2011 studied the role of organizational change in increasing colon, breast, and cervical cancer screening in primary care practices.
According to the study, changes to an organization may boost cancer screening in primary care practices.However, the study did not suggest the ideal structure of organizational change to enhance screening in primary care settings. Nonetheless, it is important to note that organizational change can improve the delivery of preventive care such as cancer screening in primary care practices.
A change in the organization can help improve the quality of care delivered to patients by focusing on preventive services that are necessary. A study by Solberg et al. (2012) suggested that a change in organizational structure can lead to the improvement of preventive care services and better outcomes.
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B) A company president would like to offer a 4.00 L cylinder containing 500 g of chlorine in the new catalog. The cylinders you have on hand have a rupture pressure of 40 atm. Use both the ideal gas law and the van der Waals equation to calculate the pressure in a cylinder at 25°C. Given a = 6.58 L2 atm mol-2 and b = 0.056 L mol-2, Cl =35.5. (5 marks)
Answer:
43.1atm is the pressure using gas law and 27.2atm using Van der Waals Law.
Explanation:
Ideal gas law is:
PV = nRT
Where P is pressure in atm
V is volume = 4.00L
n are moles of the gas (For chlorine Molar Mass: 70.90g/mol):
500g * (1mol / 70.90g) = 7.052 moles
R is gas constant = 0.082atmL/molK
T is absolute temperature = 25°C + 273 = 298K
To solve the pressure, P:
P = nRT/V
P = 7.052mol*0.082atmL/molK*298K / 4.00L
P = 43.1atm is the pressure using gas law.
Van der Waals equation is:
\(P + a(\frac{n}{V})^2 * (V-nb) = nRT\)
Where a is 6.58L²atm*mol⁻²
b = 0.056Lmol⁻²
Solving for pressure:
\(P + a(\frac{n}{V})^2 = \frac{nRT}{(V-nb)}\)
\(P = \frac{nRT}{(V-nb)}-a(\frac{n}{V})^2\)
\(P = \frac{7.052mol*0.082atmL/molK*298K}{(4.00L-7.052mol*0.056L*mol)}-6.58L^2mol^{-2}(\frac{7.052mol}{4.00L})^2\)
P = 172.323 / 3.6051 - 20.4866
P = 27.2atm using Van der Waals Law
N2(g) + 3H2 (g)→2NH3(g) The reaction rate is measured as 0.032 M NH3/s. Determine the rate of disappearance of N2 and the rate of disappearance H2. Explain how you arrived at your answers.
The rate at which N\(_{2}\) disappears is 0.016 M/s, while the rate at which H\(_{2}\) disappears is 0.0213 M/s.
In the balanced chemical equation N\(_{2}\)(g) + 3 H\(_{2}\) (g) → 2NH\(_{3}\)(g), the stoichiometric coefficients represent the mole ratios between the reactants and products.
Since the reaction rate is given for NH\(_{3}\), we can determine the rates of disappearance of N\(_{2}\) and H\(_{2}\) by comparing their stoichiometric ratios in the reaction.
The stoichiometric ratio between N\(_{2}\) and NH\(_{3}\) is 1:2, meaning for every mole of N\(_{2}\) consumed, 2 moles of NH\(_{3}\) are produced. Therefore, the rate of disappearance of N\(_{2}\) is half of the rate of formation of NH\(_{3}\).
Similarly, the stoichiometric ratio between H\(_{2}\) and NH\(_{3}\) is 3:2. This means that for every 3 moles of H\(_{2}\) consumed, 2 moles of NH\(_{3}\) are produced. Therefore, the rate of disappearance of H\(_{2}\) is (2/3) times the rate of formation of NH\(_{3}\).
Given the rate of formation of NH\(_{3}\) as 0.032 M/s, the rate of disappearance of N\(_{2}\) would be 0.016 M/s (0.032 M/s ÷ 2), and the rate of disappearance of H\(_{2}\) would be approximately 0.0213 M/s (0.032 M/s × 2/3).
Therefore, the rate of disappearance of N\(_{2}\) is 0.016 M/s, and the rate of disappearance of H\(_{2}\) is 0.0213 M/s.
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Find the product for each of the following and write your answer in proper scientific notation.
a. 37,000 x 7,000 =
Answer:
Ummm haven't learneed it yet
Explanation:
is the standard free energy of hydrolysis of phosphoarginine more similar to that of glucose 6‑phosphate or of atp? why?
The standard free energy of hydrolysis of phosphoarginine is more similar to that of ATP (adenosine triphosphate) rather than glucose 6-phosphate. This is because both phosphoarginine and ATP are high-energy phosphate compounds involved in energy transfer and metabolism.
Phosphoarginine is a phosphorylated compound found in certain organisms, particularly in tissues with high energy demands like muscle tissue. It serves as a reservoir for high-energy phosphate bonds, which can be rapidly hydrolyzed to release energy during muscle contraction.
Similarly, ATP is a universal energy currency in cells and is involved in various energy-requiring processes. It is hydrolyzed to ADP (adenosine diphosphate) and inorganic phosphate, releasing energy that can be utilized by cells.
On the other hand, glucose 6-phosphate is an intermediate in glucose metabolism and is not directly involved in energy transfer processes like phosphoarginine and ATP. While it does have a phosphorylated group, its role is primarily in carbohydrate metabolism rather than energy transfer.
Therefore, the standard free energy of hydrolysis of phosphoarginine is more similar to that of ATP due to their shared involvement in energy transfer and metabolism.
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Apply the law of conservation of matter
Answer:
in science a lot as a general statement that explains a large number of observations before being accepted a llama be verified many times under many conditions law are therefore considered the highest form of scientific knowledge and are generally thought to be inviolable scientific laws for form the core of scientific knowledge 1 scientific law that provides the foundation for understanding in chemistry is the law of conservation of matter states that in any given system that is closed the transfer of matter in an out the amount of matter in the system stays constant the concise way of expressing this law is to say that the amount of matter in a system is conserved
Why are metals so strong and hard ?
Answer:
Metals are tough because of an effect called plasticity
Explanation:
if you want to know more go to this site
https://en.wikibooks.org/wiki/A-level_Physics_(Advancing_Physics)/Metals#:~:text=Metals%20are%20tough%20for%20the,This%20effect%20is%20called%20plasticity.
Answer:
The strength of metal depends upon the status of its molecular bonding in the lattice. Stronger the forces stronger will be the metal.
Which element has 6 valence electrons?
Group 16 elements have 6 valence electrons in the periodic table.
It is defined as a substance which cannot be broken down further into any other substance. Each element is made up of its own type of atom. Due to this reason all elements are different from one another.
Elements can be classified as metals and non-metals. Metals are shiny and conduct electricity and are all solids at room temperature except mercury. Non-metals do not conduct electricity and are mostly gases at room temperature except carbon and sulfur.
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the chemical formula for an ionic compound of potassium and oxygen is:
Answer:
Potassium oxide
EXPLANATION
metal oxide Potassium oxide (K2O)
How would you upscale your chemistry learning through
the knowledge of periodic table. Explain? (5 marks worth answer)
Explanation:
The periodic table brings order to information about the chemical elements. It helps chemists to understand why elements react as they do. Elements in the same group have similar chemical properties. This is because they have the same number of outer electrons and the same valency
Examine the given Beer's law standard curve for an unknown dye measured in a 1. 0 cm cuvette. Y = 15200x-0. 18.
What is the molar absorptivity (in M–1cm–1) of the unknown dye at 542 nm?
The Beer's Law equation is A = εlc, where A is the absorbance, ε is the molar absorptivity, l is the path length (1.0 cm in this case), and c is the concentration.
Rearranging the equation, we can solve for ε: ε = A / (lc) = A / (l * c).
Since the equation given is Y = 15200x - 0.18, where x is the concentration,
we can use it to find the absorbance (A) at a given concentration.
For a concentration of x = 0.005 M, the absorbance (A) can be found by substituting the values into the equation: Y = 15200x - 0.18,
Y = 15200 * 0.005 - 0.18
Y= 0.76.
Therefore, the molar absorptivity (ε) at a wavelength of 542 nm for a concentration of 0.005 M can be calculated as:
ε = A / (lc)
Substitute the value in above equation we get,
= 0.76 / (1.0 * 0.005)
= 152 M^-1cm^-1.
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How many moles of gold (Au) are there in 3.01 X 10^23 atoms of gold (Au)?
How many molecules are there in 0.661 mol of O2 gas?
Answer:
One mole of oxygen gas, which has the formula O2, has a mass of 32 g and contains 6.02 X 1023 molecules of oxygen but 12.04 X 1023 (2 X 6.02 X 1023) atoms, because each molecule of oxygen contains two oxygen atoms.
Then he observed the model each day some of his observation are listed below but they are not in the correct order in what order did they happen
1) Vapor pressure. Water exerts vapor pressure. This pressure is produced by the water molecules that change their state from liquid to gas.
2) Setting a similar system and watching what happens.
If we set a system similar to that shown in the image (place the cup of water in the jar and then close the jar), we will see the following
1) The big jar has no molecules of water gas since we just closed it.
2) Some water molecules change from liquid to gas and start filling the big jar.
3) The big jar will have a certain amount of vapor water.
4) The big jar has so much water that it starts condensing on the walls of the big jar.
5) After enough water is condensed on the walls, it runs down the walls and precipitates.
3) The order observed.
1) Water evaporated from the cup
2) water condensed on the walls of the jar.
3) Water precipitated, or ran down the walls of the jar.
Convert 65kg to mg
A 65,000mg
B 65mg
C 65,000,000
Answer:
65,000,000 Milligrams
Explanation:
Answer:
65000000 is right
Explanation:
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Calculate the average atomic weight of Fe if abundance of isotopes 54Fe, 56Fe and 57Fe are 5%, 90%, 5% respectively.
Answer:
here is the answer
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Barium metal was quantitatively precipitated from a 1. 52 g sample of bacl2∙2h2o. The mass of the barium that was collected was 0. 844 g. Calculate the experimental mass percent of barium in the sample.
To calculate the experimental mass percent of barium in the sample, we need to use the following formula:
Experimental Mass Percent = (Mass of Barium / Mass of Sample) x 100
Given that the mass of the barium collected was 0.844 g and the mass of the sample was 1.52 g, we can substitute these values into the formula to calculate the experimental mass percent:
Experimental Mass Percent = (0.844 g / 1.52 g) x 100
Simplifying the equation:
Experimental Mass Percent = 0.555 x 100
Calculating the value:
Experimental Mass Percent = 55.5%
So, the experimental mass percent of barium in the sample is 55.5%. The experimental mass percent of barium in the sample is 55.5%. To calculate the experimental mass percent, we divided the mass of barium collected by the mass of the sample and multiplied the result by 100. This gives us the proportion of barium in the sample, expressed as a percentage. To calculate the experimental mass percent of barium in the sample, we used the formula (Mass of Barium / Mass of Sample) x 100. Given that the mass of barium collected was 0.844 g and the mass of the sample was 1.52 g, we substituted these values into the formula to calculate the experimental mass percent. By dividing 0.844 g by 1.52 g, we obtained the proportion of barium in the sample. Multiplying the result by 100, we converted this proportion into a percentage. The final result, 55.5%, represents the experimental mass percent of barium in the sample. This calculation allows us to quantify the amount of barium present in relation to the total sample mass.
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who tryna date? like ong
Answer:
Im confused. Do you need help with something?
Explanation:
Answer:sheshhh sayless XD
Explanation:
2. A lens is being used to look at an object 40cm away. An image appears 20 points
30 cm away. What is the focal length of the lens?
Answer:
f = 17.14 cm
Explanation:
Given that,
The object distance, u = -40 cm
The image distance, v = +30 cm
We need to find the focal length of the lens. The lens formula is given by :
\(\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}\\\\\dfrac{1}{f}=\dfrac{1}{30}-\dfrac{1}{(-40)}\\\\f=17.14\ cm\)
So, the focal length of the lens is 17.14 cm.
Which group of coefficients balances the following chemical equation? 2KCIO3 → _KCI + _O2 a 1, 3 b 2,2 C 2,3 d 2.1 e 1, 1
Answer:
2KClO3 = 2KCl + 3O2
I hope it's helps you
What are the chemical compounds of neon and argon?
Answer:
Silica.
Explanation:
Argon fluorohydride or argon hydrofluoride is an inorganic compound with the chemical formula HArF. It is a compound of the chemical element argon.
Neon is a very inert element, however, it has been reported to form a compound with fluorine. It is still questionable if true compounds of neon exist, but evidence is mounting in favor of their existence.
Lucy volunteers at an animal shelter, and she takes care of an orange tabby 1 point
cat and her kittens. Some of the kittens have orange markings, but some
have gray markings. What units of genetic material determine how living
things look?
Answer; the answer is variations
The unit of genetic material that determines how living things look is called variations, look below for more description.
What are genetic variations?Hereditary variety alludes to contrasts among the genomes of individuals from similar species. A genome is all the innate data — every one of the qualities — of a creature. Hereditary variety is the distinction in DNA successions between people inside a populace.
For example, the human genome contains somewhere close to twenty and 25 thousand qualities.
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Zinc metal reacts with hydrochloric acid (HCl) to produce hydrogen gas. What best describes this reaction?
Answer: What best describes the reaction is "A single replacement reaction takes place because zinc is more reactive than hydrogen."
_____has particles with the greatest average kinetic energy
a
Ice water
b
Hot water
c
Warm water
d
Room temperature water
Answer:
c warm water
Explanation:
Kinetic energy is related to temperature. The molecules in a glass of warm water have more kinetic energy (they move faster – see Racing Molecules) than the molecules in a glass of cold water. The temperature of a substance is the average* amount of kinetic energy its molecules have.
Answer:
hot water
Explanation:
Q1 Define and differentiate between the following: i. Temporary and permanent hardness
ii. Organic, ortho and poly phosphorus in wastewater
iii. Self-cleansing and scouring velocity in sewers iv. Type 1 and Type 2 settling in water/wastewater treatment v. Chloramines and Disinfection by-products
Temporary and permanent hardness of water Temporary hardness of water is caused by the presence of bicarbonate, carbonate, and sulfate ions, while permanent hardness is caused by the presence of chlorides, sulfates, and nitrates.
Carbonate and bicarbonate hardness can be removed using a process called boiling. Permanent hardness, on the other hand, can be removed using a process called ion exchange.ii. Organic, ortho, and polyphosphorus in wastewaterOrganic phosphorus is present in wastewater in the form of organic molecules like DNA, RNA, and phospholipids. Orthophosphate is the most common form of phosphorus found in wastewater. Polyphosphates, which are a chain of orthophosphate molecules, can also be found in wastewater.iii. Self-cleansing and scouring velocity in sewersSelf-cleansing velocity is the minimum velocity of wastewater flow required to prevent the deposition of solids in the sewer. Scouring velocity, on the other hand, is the minimum velocity required to remove previously deposited solids. Scouring velocity is higher than self-cleansing velocity.
Type 1 and Type 2 settling in water/wastewater treatment Type 1 settling occurs when particles of different sizes and densities settle separately, forming distinct layers. In type 2 settling, particles of different sizes and densities settle together in a mixed floc. Type 1 settling is more effective at removing larger particles, while type 2 settling is better at removing smaller particles.v. Chloramines and disinfection by-products (DBPs)Chloramines are a combination of chlorine and ammonia that are used as a disinfectant in water treatment. Disinfection by-products (DBPs) are formed when chlorine reacts with organic matter in the water. Some common DBPs include trihalomethanes (THMs) and haloacetic acids (HAAs), which are known to be carcinogenic.
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1
Metal elements tend to___
electrons and become___
ions
a.) lose, negative
b.) lose, positive
c.) gain, negative
d.) gain, positive
Answer:
d
Explanation:
i did this b4