girl what the hell is this someone help

Answer:

Part A)

\(\displaystyle \frac{dy}{dx}=\frac{2xy}{y-x^2}\)

Part B)

\(y=x-2\)

Part C)

\((0, \sqrt{3})\text{ and } (0, -\sqrt3)\)

Part D)

\(\displaystyle \frac{d^2y}{dx^2}_{(1, -1)}=-\frac{1}{2}\)

Step-by-step explanation:

We have the equation:

\(y^2-2x^2y=3\)

Part A)

We want to find the derivative of the equation. So, dy/dx.

Let’s take the derivative of both sides with respect to x. Therefore:

\(\displaystyle \frac{d}{dx}\Big[y^2-2x^2y\Big]=\frac{d}{dx}[3]\)

Differentiate. We will need to implicitly different on the left. The second term will also require the product rule. Therefore:

\(\displaystyle 2y\frac{dy}{dx}-4xy-2x^2\frac{dy}{dx}=0\)

Rearranging gives:

\(\displaystyle \frac{dy}{dx}\Big(2y-2x^2\Big)=4xy\)

Therefore:

\(\displaystyle \frac{dy}{dx}=\frac{4xy}{2y-2x^2}\)

And, finally, simplifying:

\(\displaystyle \frac{dy}{dx}=\frac{2xy}{y-x^2}\)

Part B)

We want to write the equation for the line tangent to the curve at the point (1, -1).

So, we will require the slope of the tangent line at (1, -1). Substitute these values into our derivative. So:

\(\displaystyle \frac{dy}{dx}_{(1, -1)}=\frac{2(1)(-1)}{(-1)-(1)^2}=1\)

Now, we can use the point-slope form:

\(y-y_1=m(x-x_1)\)

Substitute:

\(y-(-1)=1(x-1)\)

Simplify:

\(y+1=x-1\)

So:

\(y=x-2\)

Part C)

If the line tangent to the curve is horizontal, this means that dy/dx=0. Hence:

\(\displaystyle 0=\frac{2xy}{y-x^2}\)

Multiplying both sides by the denominator gives:

\(0=2xy\)

Assuming y is not 0, we can divide both sides by y. Hence:

\(2x=0\)

Then it follows that:

\(x=0\)

Going back to our original equation, we have:

\(y^2-2x^2y=3\)

Substituting 0 for x yields:

\(y^2=3\)

So:

\(y=\pm\sqrt{3}\)

Therefore, two points where the derivative equals 0 is:

\((0, \sqrt{3})\text{ and } (0, -\sqrt3)\)

However, we still have to test for y. Let’s go back. We have:

\(0=2xy\)

Assuming x is not 0, we can divide both sides by x. So:

\(0=2y\)

Therefore:

\(y=0\)

And going back to our original equation and substituting 0 for y yields:

\((0)^2-2x^2(0)=0\neq3\)

Since this is not true, we can disregard this case.

So, our only points where the derivative equals 0 is at:

\((0, \sqrt{3})\text{ and } (0, -\sqrt3)\)

Part D)

Our first derivative is:

\(\displaystyle \frac{dy}{dx}=\frac{2xy}{y-x^2}\)

Let’s take the derivative of both sides again. Hence:

\(\displaystyle \frac{d^2y}{dx^2}=\frac{d}{dx}\Big[\frac{2xy}{y-x^2}\Big]\)

Utilize the quotient and product rules and differentiate:

\(\displaystyle \frac{d^2y}{dx^2}=\frac{(2y+2x\frac{dy}{dx})(y-x^2)-2xy(\frac{dy}{dx}-2x)}{(y-x^2)^2}\)

Let dy/dx=y’. Therefore:

\(\displaystyle \frac{d^2y}{dx^2}=\frac{(2y+2xy^\prime)(y-x^2)-2xy(y^\prime-2x)}{(y-x^2)^2}\)

For (1, -1), we already know that y’ is 1 at (1, -1). Therefore:

\(\displaystyle \frac{d^2y}{dx^2}_{(1, -1)}=\frac{(2(-1)+2(1)(1))((-1)-(1)^2)-2(1)(-1)((1)-2(1))}{((-1)-(1)^2)^2}\)

Evaluate:

\(\displaystyle \frac{d^2y}{dx^2}_{(1, -1)}=-\frac{1}{2}\)

I disagree with Eva. The pool will be full at 11:45 pm thus option (D) will be correct.

Work is the completion of any task for example if you have done your homework in 5 hours then you have done 5 hours.

Another example of work is that if you have done your food by 1 hour it means your work duration is 1 hour so work is basically the time duration of any task which you have done.

As per the given table,

The pool filled out 1000 gallons every 15 minutes.

In 1 hour = 1000 x 4 = 4000 gallons,

To fill out a full pool of 15000 gallons,

15000/4 = 3 + 2000/3

3 hour + (15 + 15 + 15) minutes

⇒ 3 hours and 45 minutes

Since, it begins at 8:00 am thus 8 + 3 + 45 minutes = 11:45 am.

Hence "I don't concur with Eva. At 11:45 p.m., the pool will be filled".

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The probability of picking a red marble, then a green marble, and finally a blue marble is 0.091424%, or approximately 0.09%.

To find the probability of picking a blue marble, given that we have already picked a red and a green marble, we use the same method:

P(B|R and G) = P(R and G and B) / P(R and G)

where P(B|R and G) is the probability of picking a blue marble, given that a red marble and a green marble have been selected, and P(R and G and B) is the probability of picking a red marble, then a green marble, and finally a blue marble.

Using the given probabilities, we can plug in the values and simplify:

P(B|R and G) = (0.2 x 0.2857 x 0.228) / (0.2 x 0.2857) = 0.016

This means that if we have already picked a red marble, then a green marble, there is a 1.6% chance of picking a blue marble next.

Finally, to find the probability of picking a red marble, then a green marble, and finally a blue marble, we multiply the probabilities of each event together:

P(R and G and B) = P(R) x P(G|R) x P(B|R and G)

=> 0.2 x 0.2857 x 0.016 = 0.00091424 or 0.09%

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Answer:

m<CAB = 59

m<ACB = 59

Step-by-step explanation:

4x - 41 = 2x + 9

2x - 41 = 9

2x = 50

x = 25

m<CAB: 4x - 41

4(25) - 41

59

m<ACB: 2x + 9

2(25) + 9

59

Answer:

Please find attached the required graph for the temperature time relationship

Step-by-step explanation:

The parameters given are arranged in a tabular form as follows;

At

Time  \({}\)                                          Temperature

6 a. m.        \({}\)                                    56° F

7 a. m.          \({}\)                                   59° F

8 a. m.             \({}\)                                62° F

9 a. m.             \({}\)                                66° F

10 a. m.            \({}\)                               70° F

11 a. m.                  \({}\)                          74° F

12 p. m.              \({}\)                             74°F

1 p. m.                     \({}\)                        74°F

2 p. m.                  \({}\)                          74°F

3 p. m.                   \({}\)                         74°F

4 p. m.                   \({}\)                         74°F

5 p. m.                  \({}\)                          74°F

6 p. m.                 \({}\)                           74°F

7 p. m.                       \({}\)                     71°F

8 p. m.                      \({}\)                      68°F

9 p. m.                          \({}\)                  65°F

10 p. m.                  \({}\)                         62°F

11 p. m.                        \({}\)                    61.5°F

12 a. m.                        \({}\)                    61°F

With the above table as the data points, the graph can be drawn

From Excel, The Mean temperature is approximately 68.1°F

The standard deviation is 6.079 °F

Since Dylan noted the time of day and the temperature, in degrees Fahrenheit, and his findings are as follows: At 6 am, the temperature was 56 ° F, for the next 2 hours, the temperature rose 3 ° per hour, for the next 3 hours, it rose 4º per hour, and the temperature then stayed steady until 6 pm, while for the next 4 hours, the temperature dropped 3 ° per hour, and the temperature then dropped steadily until the temperature was 61 ° at midnight , to determine the average temperatures, the following tables must be made:

6 AM = 56

7 AM = 59

8 AM = 62

9 AM = 66

10 AM = 70

11 AM = 74

6 PM = 74

7 PM = 71

8 PM = 68

9 PM = 65

10 PM = 62

11 PM = 61.5

12 AM = 61

Thus, the average daily temperature was 68°F.

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Answer:

4

Step-by-step explanation:

Answer:

x=4

Step-by-step explanation:

the sides are proportional by 5. so the equation needed is

3x+8=20

3x=20-8

3x=12

x=12/3

x=4

Answer: 3mn^2.

Step-by-step explanation: GCF stands for Greatest Common Factor, as you know. The greatest common factor of 75 and 27 is 3. For the rest, we just use the smallest values. Thus, the answer is 3mn^2.

Answer:

A = 2 1/2 ft^2

Step-by-step explanation:

The area of a rectangle is given by

A = l*w

A = 3 * 5/6

A = 5/2 ft^2

A = 2 1/2 ft^2

Answer:

A=2.5 ft^2

Step-by-step explanation:

A=3

A=3(5/6)

A=2.5 ft^2

1.\(\sqrt{11}\) is less than 3.5

2. \(\sqrt{5}\) is more than 2.1

3. -5.3 is more than -5 \(\frac{3}{5}\)

4. \(\frac{8}{10}\) is less than 0.8 repeating

Answer: Find the equation with a point and y-intercept.

y = 49/32x + 1/4

image below

Answer:

r = 6

Step-by-step explanation:

Calculate the slope m using the slope formula and equate to \(\frac{3}{2}\)

m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)

with (x₁, y₁ ) = ( 3, - 6) and (x₂, y₂ ) = (11, r)

m = \(\frac{r+6}{11-3}\) = \(\frac{r+6}{8}\) = \(\frac{3}{2}\) ( cross- multiply )

2(r + 6) = 24 ( divide both sides by 2 )

r + 6 = 12 ( subtract 6 from both sides )

r = 6

The  Trigonometric Identity sin² x + cos²x = 1 is: A. Pythagorean Identity.

The Pythagorean Identity which  tend to asserts that for every angle x, the sum of the squares of the sine and cosine of x is equal to one  is known as or called a  trigonometric identity.

The  Pythagorean identity can be expressed as:

sin² x + cos² x = 1

This identity is crucial to understanding trigonometry and tend to have several uses in numerous branches of science and engineering.

Therefore the correct option is A.

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Answer:

2

Step-by-step explanation:

3x = x + 4

2x = 4

x = 2

3x = 6

x + 4 = 6

The value of x will be 0.48 which makes the following expression equal.

A phrase is considered a mathematical expression if it contains at least two numbers or variables and one or more mathematical operations. Mathematicians can multiply, divide, add, or subtract. An expression is structured as follows: Number/variable, mathematical operator, and expression.

It is given that the expression is, 9.3x = x +4

The value of x is obtained to make the expressions equal.

Apply the arithmetic operation in order to find the value of x.

9.3x = x +4

9.3x-x=4

8.3x=4

x=4/8.3

x=0.48

Thus, the expression below is equivalent since the value of x will be 0.48.

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The formula we need to use is given above. In this formula, we will substitute the desired values. Let's start.

A) First, we can start by analyzing the first premise. The team has \(8\) wins and \(5\) losses. It earned \(8 \times 3 = 24\) points in total from the matches it won and \(1\times5=5\) points in total from the matches it drew. Therefore, it earned \(24+5=29\) points.

B) After \(39\) matches, the team managed to earn \(54\) points in total. \(12\) of these matches have ended in draws. Therefore, this team has won and lost a total of \(39-12=27\) matches. This number includes all matches won and lost. In total, the team earned \(12\times1=12\) points from the \(12\) matches that ended in a draw.

\(54-12=42\) points is the points earned after \(27\) matches. By dividing \(42\) by \(3\) ( because \(3\) points is the score obtained as a result of the matches won), we find how many matches team won. \(42\div3=14\) matches won.

That leaves \(27-14=13\) matches. These represent the matches team lost.

Finally, the answers are below.

\(A)29\)
\(B)13\)

Answer:

  a) 29 points

  b) 13 losses

Step-by-step explanation:

You want to know points and losses for different teams using the formula P = 3W +D, where W is wins and D is draws.

The number of points the team has is ...

  P = 3W +D

  P = 3(8) +(5) = 29

The team has 29 points.

You want the number of losses the team has if it has 54 points and 12 draws after 39 games.

The number of wins is given by ...

  P = 3W +D

  54 = 3W +12

  42 = 3W

  14 = W

Then the number of losses is ...

  W +D +L = 39

  14 +12 +L = 39 . . . substitute the known values

  L = 13 . . . . . . . . . . subtract 26 from both sides

The team lost 13 games.

__

Additional comment

In part B, we can solve for the number of losses directly, using 39-12-x as the number of wins when there are x losses. Simplifying 3W +D -P = 0 can make it easy to solve for x. (In the attached, we let the calculator do the simplification.)

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The probability that he will receive the job will be 1 / 6

The complete question is given below:-

A job applicant estimates that his chance of passing a qualifying examination is 2/3, and his chance of being appointed if he does pass is 1/4. What is the probability that he will receive the job?

Probability is defined as the ratio of the number of favourable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

It is given that:

The chance of passing a qualifying examination is 2/3=P

and chance of being appointed, if he does pass, is 1/4=P'

Now, we are asked to find the probability that he will receive the job.

We are asked to find the probability that he will receive the job.

The probability is calculated as The probability that he qualify the exam×Probability that he is being appointed.

=P×P'

=(2/3)×(1/4)

=1/6

Therefore the probability that he will receive the job will be 1 / 6

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The equation for the quadratic function in standard form is 4x² - 16x - 9

From the question, we are to write an equation for the quadratic function in standard form.

From the given quadratic graph,

The roots of the function are -0.5 and 4.5.

That is,

x = -0.5 and x = 4.5

That is,

x = -1/2 and x = 9/2

Therefore,

2x = -1 and 2x = 9

The factors of the quadratic function are (2x + 1) and (2x - 9)

Thus,

We can write that

(2x + 1)(2x - 9) = 0

4x² - 18x + 2x - 9 = 0

Simplify

4x² - 16x - 9 = 0

Hence, the equation is f(x) = 4x² - 16x - 9

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a) A function that expresses f(x) is f(x) = 1.5x.

b) A graph of the function is shown in the image below.

c) The domain and range of the function are all real numbers or [-∞, ∞].

Assuming the variable x represent the amount of a transaction and the variable f(x) represent the amount Isabel is charged for the transaction, a linear function charges on each sale by the credit card company can be written as follows;

f(x) = 1.5x

Part b.

In this exercise, we would use an online graphing tool to plot the function f(x) = 1.5x as shown in the graph attached below.

Part c.

By critically observing the graph shown below, we can logically deduce the following domain and range:

Domain = [-∞, ∞] or all real numbers.

Range = [-∞, ∞] or all real numbers.

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Complete Question:

A transaction is positive if there is a sale and negative when there is a return. Each time a customer uses a credit card for a transaction, the credit company charges Isabel. The credit company charges 1.5% of each sale and a fee of 0.5% for returns.

a) Let x represent the amount of a transaction and let f(x) represent the amount Isabel is charged for the transaction. Write a function that expresses f(x).

b) Graph the function.

c) What are the domain and range of the function?

Answer:

\(S_\infty=\frac{108}{5}\)

Step-by-step explanation:

The infinite series sum of a converging geometric series is: \(\frac{a_1}{1-r}\)

A geometric sequence can generally be defined as: \(a_n=a_1(r)^{n-1}\)

The series you provided, seems to be oscillating from negative to positive values. What this is telling us, is that the "r" value or what's being multiplied from one term to another, is negative.

We know this because take for example: \(a_n=a_1(-r)^{n-1}\)

When n=1: \(a_1=-r*a_1\)

When n=2: \(a_2=r^2*a_1\)

When n=3: \(a_3=-r^3*a_1\)

When n=4: \(a_4=r^4*a_1\)

Basically, when the degree is odd the negative sign isn't cancelled out, but when the degree is even, the negative signs can be "paired" in groups of twos in which they cancel out resulting in a positive number. So it will be positive then negative then positive then negative and so on...

So we know that r is negative, but what is the magnitude of r?

Well we can find this by dividing one value by the previous value.

\(\frac{-24}{36}=-\frac{2}{3}\)

\(\frac{16}{-24}=-\frac{2}{3}\)

Also we didn't really need to analyze the series to see that "r" was negative, we could've just divided. I just wanted to clarify as to why "r" is negative.

Anyways moving on, as given in the series the first term is 36, so: \(a_1=36\) and \(r=-\frac{2}{3}\)

This gives us a sum of: \(S_\infty=\frac{36}{1-(-\frac{2}{3})}\)

Cancel out the negatives: \(S_\infty=\frac{36}{1+\frac{2}{3}}\)

Rewrite the 1 as 3/3: \(S_\infty=\frac{36}{\frac{3}{3}+\frac{2}{3}}\)

Combine the denominator into one fraction: \(S_\infty=\frac{36}{\frac{5}{3}}\)

Keep, change, flip: \(S_\infty=\frac{36}{1}*\frac{3}{5}\)

Multiply Values: \(S_\infty=\frac{108}{5}\)

This is our answer.

Answer:

2,666.67 L of water

Step-by-step explanation:

Solve for W:

1) 3200 = 2400 + 0.3w

2) 800 = 0.3w

Divide both sides by 0.3 to get the variable alone

3) (800)/0.3 = (0.3w)/0.3

4) w = 2,666.67 L

The angles of the triangle is :

A = 0.506 , B = 3.692 and C  = 1.850

We have the following information is:

A triangle is defined by the three points A=(3,10), B=(6,9), and C=(5,2).

We have to find the:

Determine all angles theta, theta, and thetaθA, θB, and θC in the triangle.

Now, According to the question:

The first thing we need to do, is find the length of the sides a , b and c. We can do this by using the Distance Formula.

The Distance Formula states, where d is the distance, that:

\(d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)

So,

\(a=\sqrt{(6-5)^2+(9-2)^2}\)\(=\sqrt{50}\)

\(b=\sqrt{(3-5)^2+(10-2)^2} =\sqrt{66}\)

\(c=\sqrt{(6-3)^2+(9-10)^2}=\sqrt{10}\)

We now know all 3 sides, but since we don't know any angles, we will have to use the Cosine Rule.

The Cosine Rule states that:

\(a^2=b^2+c^2-2bc.cos(A)\)

Plug all the values:

\((\sqrt{50} )^2=(\sqrt{66} )^2+(\sqrt{10} )^2-2(\sqrt{66} )(\sqrt{10} ).cosA\)

50 = 66 + 10 -2\(\sqrt{66}.\sqrt{10} cosA\)

cos (A) = 50-66-10/ -2\(\sqrt{66}.\sqrt{10}\)

cos (A) = 13/25.69

A = \(cos ^ -^1 \, (cos(A))=cos^-^1\)(13/25.69) = 0.506

We rearrange the formula for angle B.

\(b^2=a^2+c^2-2bc.cos(A)\)

Angle B:

\((\sqrt{66} )^2=(\sqrt{50} )^2+(\sqrt{10} )^2-2(\sqrt{66} )(\sqrt{10} ).cosA\)

66 = 50 + 10 -2\(\sqrt{66}.\sqrt{10} cosA\)

cos (A) = 66 -50 -10/ -2\(\sqrt{66}.\sqrt{10}\)

cos(A) = 6/ -2\(\sqrt{66}.\sqrt{10}\)

cos(A) = 3.692

A = \(cos ^ -^1 \, (cos(A))=cos^-^1\)3.692

Angle C:

\(\pi -(\frac{\pi }{4} +0.506)\) = 1.850

The angles of the triangle is :

A = 0.506 , B = 3.692 and C  = 1.850

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Answer:

5x(2x - 1)

Step-by-step explanation:

Factor 10x^2 - 5x:

Then:  10x^2 - 5x = 5x(2x - 1), since 5x is common to the two given terms

Answer:

\(10x^{2} -5x\) in factored form would be \(5x(2x-1)\)

Step-by-step explanation:

If we look at all of the terms in this binomial, we can see that they both have 5x in common.  We can now factor 5x out of the equation to get our answer.

To do this, we must divide both terms by 5x.

\(10x^2\) divided by \(5x\) is \(2x\), and \(-5x\) divided by \(5x\) is \(-1\).

So, our final answer is \(5x(2x-1)\).

Answer: B (18.5b-21.2)

The required expression −18.5b − 21.2 is equivalent to the given expression which is the correct answer that would be option (A).

Algebraic expressions are mathematical statements with a minimum of two terms containing variables or numbers.

We have been given the expression below as

5(−2.3b − 4.1) − (7b + 0.7)

Open the parentheses and apply the distributive property of multiplication,

⇒ −2.3b × 5 − 4.1 × 5 − 7b - 0.7

⇒ -11.5 - 20.5 − 7b - 0.7

Rearrange the likewise terms and apply the arithmetic operation,

⇒ −18.5b − 21.2

Hence, the required expression −18.5b − 21.2 is equivalent to the given expression.

Thus, the correct answer would be an option (A).

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Answer:

12x7x4+1

Step-by-step explanation:

12x7x4+1=337

Hope this helps!!!

Answer:

y = −x − 2

is the answer

Answer:

Slope = -2/3

Step-by-step explanation:

Slope = \(\frac{y_{2} -y_{1}}{x_{2}-x_{1}}\)

Slope = \(\frac{-1 -(-5)}{-4-2} = \frac{4}{-6} =-\frac{2}{3}\)

Answer:A-false B-false C-true D-true E-false

Step-by-step explanation:

if im wrong pls tell me :)

We can fill in the given blanks as follows:

x1 =6, x2 = 7 , y1 = -1,  y2 =3. The slope is 4.

What is meant by the slope of a line?

We have seen lines drawn on the coordinate plane in geometry. The best approach to determine without using any geometrical tools if the lines are parallel, perpendicular, or at any angle is to measure the slope. A line's steepness can be determined by looking at its slope. A line's slope in mathematics is defined as the ratio of the change in the y coordinates to the change in the x coordinates. By calculating the difference between the coordinates of the two points, (x1,y1) and (x2,y2), it is simple to calculate the slope of a straight line between them. The letter "m" is frequently used to denote slope.

Given,

(x1, y1)  = (6, −1)

(x2, y2) = (7, 3)

The slope of the line = \(\frac{y_2-y_1}{x_2-x_1}\) = 3 -(-1) / 7-6 = 4/1 = 4

Therefore we can fill in the given blanks as follows:

x1 =6, x2 = 7, y1 = -1,  y2 =3. The slope is 4.

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