Gebhardt Electronics produces a wide variety of transformers that it sells directly to manufacturers of electronics equipment. For one component used in several models of its transformers, Gebhardt uses a 3-foot length of. 20 mm diameter solid wire made of pure Oxygen-Free Electronic (OFE) copper. A flaw in the wire reduces its conductivity and increases the likelihood it will break, and this critical component is difficult to reach and repair after a transformer has been constructed. Therefore, Gebhardt wants to use primarily flawless lengths of wire in making this component. The company is willing to accept n more than a l in 20 chance that a 3-foot length taken from a spool will be flawless. Gebhardt also occasionally uses smaller pieces of the same wire in the manufacture of other compo- nents, so the 3-foot segments to be used for this component are essentially taken randomly from a long spool of. 20 mm diameter solid OFE copper wire Gebhardt is now considering a new supplier for copper wire. This supplier claims that its spools of. 20 mm diameter solid OFE copper wire average 50 inches between flaws. Gebhardt now must determine whether the new supply will be satisfactory if the supplier's claim is valid. Managerial Report In making this assessment for Gebhardt Electronics, consider the following three questions:


1. If the new supplier does provide spools of. 20 mm solid OFE copper wire that aver age 50 inches between flaws, how is the length of wire between two consecutive flaws distributed?


2. Using the probability distribution you identified in (I), what is the probability that Gebhardt's criteria will be met (i. E. , a l in 20 chance that a randomly selected 3-foot segment of wire provided by the new supplier will be flawless)


3. In inches, what is the minimum mean length between consecutive flaws that would result in satisfaction of Gebhardt's criteria


4. In inches, what is the minimum mean length between consecutive flaws that would result in a l in 100 chance that a randomly selected 3-foot segment of wire provided by the new supplier will be flawless?

Solution:

Given the functions;

Then;

Also;

ANSWERS:

To calculate the duration of the shift, you need to subtract the clock-in time from the clock-out time.

In this case, the shift worker clocked in at 1730 hours (5:30 PM) and clocked out at 0330 hours (3:30 AM). However, since the clock is based on a 24-hour format, it's necessary to consider that the clock-out time of 0330 hours actually refers to the next day.

To calculate the duration of the shift, you can perform the following steps:

1. Calculate the duration until midnight (0000 hours) on the same day:

  - The time between 1730 hours and 0000 hours is 6 hours and 30 minutes (1730 - 0000 = 6:30 PM to 12:00 AM).

2. Calculate the duration from midnight (0000 hours) to the clock-out time:

  - The time between 0000 hours and 0330 hours is 3 hours and 30 minutes (12:00 AM to 3:30 AM).

3. Add the durations from step 1 and step 2 to find the total duration of the shift:

  - 6 hours and 30 minutes + 3 hours and 30 minutes = 10 hours.

Therefore, the duration of the shift was 10 hours.

Answer:

720

Because

area of squre =SIDE MULTIPLE BY SIDE

SO

10 MULTIPLE 3 MULTIPLE 4 MULTIPLE 6

SO ANS 720

Answer:

$205.00

Step-by-step explanation:

$615÷3 =205

205 × 3= 205

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The sample mean is 5.0833 and the standard deviation is 3.476 and the confidence interval is (2.87, 7.29).

In the given question, a random sample of 12 employees was taken, and the number of days each was absent for sickness was recorded (for a 1-year period).

Using these data to create a 95% confidence interval for the population mean days absent for sickness

2   5   3   7   10   0   6   8   5   11   3   1

a) We have to find the sample mean and the standard deviation (round to two decimal places).

The sample mean;

X = 2+5+3+7+10+0+6+8+5+11+3+1/12

X = 61/12

X = 5.0833

Now the standard deviation

SD = √[{x(1)-X)^2+(x(2)-X)^2…………….(x(12)-X)^2}/N]

After solving using that formula;

SD = 3.476

b) 95% confidence in interval for the population mean days absent for sickness.

Lower Bound = X - t(α/2)*s/√n

Upper Bound = X + t(α /2)*s/√n

where

α /2 = (1 - confidence level)/2 = 0.025

X = sample mean = 5.083333333

t(α/2) = critical t for the confidence interval = 2.20098516

s = sample standard deviation = 3.476108936

n = sample size = 12

df = n - 1 = 11

Thus,

Lower bound = 2.874719086

Upper bound = 7.291947581

Thus, the confidence interval is (2.87, 7.29).

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The right question is:

How healthy are the employees at direct marketing industry? A random sample of 12 employees was taken, and the number of days each was absent for sickness was recorded (for a 1-year period). Use these data to create a 95% confidence interval for the population mean days absent for sickness.

2   5   3   7   10   0   6   8   5   11   3   1

a) Find the sample mean and the standard deviation (round to two decimal places)

b) 95% confidence in interval for the population mean days absent for sickness.

Answer:

x = 5

Step-by-step explanation:

Given

9x - 3 - 8x = 7 - x , that is

x - 3 = 7 - x ( add x to both sides )

2x - 3 = 7 ( add 3 to both sides )

2x = 10 ( divide both sides by 2 )

x = 5

Answer:

Step-by-step explanation:

The correct option is statistical inference (b).

The professor uses sample data from the population to determine the average age. Anytime inferential statistics or statistical inference is used to make inferences from samples.

Instead of gathering data from the entire institution, the professor took age samples from a class and used those data to draw conclusions about the entire university.

Descriptive statistics in statistics help you describe the facts, whereas inferential statistics assist you in drawing conclusions from the data.

Data from the sample are used in inferential statistics, which allows you to generalise about the population.

Inference generally refers to "guessing," which involves drawing conclusions about something.

So, drawing conclusions about the population is what is meant by statistical inference. It makes use of a number of statistical analytic tools to draw a conclusion about the population.

Therefore, the correct option is statistical inference.

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Answer:

7.37%

Step-by-step explanation:

9/20 x 8/19 x 7/18 = 7/95 (simplified) which is 7.37%

Answer:

Image attached.

1 left 4 right

2 left 3 right

3 left 2 right

4 left 1 right

Step-by-step explanation:

When evaluated...

7 ÷ 1/4 = 7 * 4 = 28

2/3 ÷ 4/5 = 2/3 * 5/4 = 5/6

4/5 ÷ 3/2 = 4/5 * 2/3 = 8/15

1/4 ÷ 1/7 = 1/4 * 7 = 7/4

An image has been attached to better explain this.

Answer:

y^6 - 9y^4 + 27y² - 27

Step-by-step explanation:

(y² - 3) (y^4 - 6y² + 9)

y^6 - 6y^4 + 9y² - 3y^4 + 18y² - 27

y^6 - 9y^4 + 27y² - 27

It is important to consider external costs when determining the appropriate price for garbage collection.

Instead, they should provide a step-by-step explanation in their answer. The terms "people pay nothing", "extra pound of garbage", "demanded", and "marginal cost" are relevant to the question.

A price for garbage collection that is appropriate is one that takes into account the external costs of garbage disposal that the community is faced with.

The quantity of free garbage collection now demanded is 40.

(b) If a fee of $4 per pound were charged, then the quantity demanded would be 20.Social demand curve when an external benefit of $2 per pound exists can be drawn as follows:

To plot a social demand curve, we need to sum up the marginal private benefit of each unit of the good (which in this case is free garbage collection) with the marginal external benefit of each unit.

The marginal private benefit curve is already given.

The marginal external benefit is $2 per pound. Thus, the social demand curve is given as follows:

(d) The optimal level of garbage collection if the marginal cost of collecting garbage were constant at $6 per pound can be calculated as follows:

At equilibrium, marginal social benefit (MSB) = marginal social cost (MSC).

MSB = marginal private benefit (MPB) + marginal external benefit

(MEB) = P - 0.5 + 2 = P + 1.5MSC = marginal private cost (MPC) = $6Equating the two, we get:

P + 1.5 = $6P = $4.5At P = $4.5, Q = 30.

This is the optimal level of garbage collection using the social demand curve.

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The scatterplot with the least squares line provides insights into the relationship between average annual global surface temperature and the years from 2000 to 2015, allowing us to assess trends, strength of correlation, and make predictions within certain limitations.

The scatterplot represents the relationship between the average annual global surface temperature, in degrees Celsius, and the corresponding years from 2000 to 2015. The line drawn on the plot is the least squares line, which is the best fit line that minimizes the overall distance between the observed data points and the line.

The least squares line is determined using a statistical method called linear regression. It calculates the equation of a straight line that represents the trend in the data. This line serves as a mathematical model to estimate the average temperature based on the year.

By analyzing the scatterplot and the least squares line, we can make several observations. Firstly, we can see whether the temperature has been increasing, decreasing, or remaining relatively stable over the given years. If the slope of the line is positive, it indicates a positive correlation, implying that the temperature has been increasing. Conversely, a negative slope suggests a decreasing trend.

Additionally, we can evaluate the strength of the relationship between temperature and time by examining how closely the data points cluster around the line. If the points are closely grouped around the line, it suggests a strong correlation, indicating that the line is a good representation of the data. On the other hand, if the points are more scattered, the correlation may be weaker.

Furthermore, the line can be used to predict the average annual global surface temperature for future years beyond the data range of 2000 to 2015. However, it's important to note that such predictions should be made with caution and considering other factors that may affect global temperatures, such as climate change and natural variability.

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Question

The given scatterplot shows the average annual global surface temperature, in degrees celsius, for each year from 2000 to 2015. the line drawn is the least squares line for the data set.

In the given figure, we can observe that two triangles are formed: ΔASB and ΔTSC.

It is given that:

Length of ST = 54 ft

Length of TB = 25 ft

Length of SC = 18 ft

To find: The length of SA

The length of TA can be found as follows:

Using the Pythagorean theorem,

In ΔTSC,TS² + SC² = TC²

54² + 18² = TC²

2916 + 324 = TC²

3240 = TC²

TC = 60 ft

Now, in ΔTSA,

TS² + SA² = TA²

60² + SA² = TA²

3600 + SA² = TA²

In ΔTAS,

TA² + AS² = TS²

TA² + AS² = 60²

TA² + AS² = 3600

In ΔASB,

AB² + BS² = AS²

AB² + 25² = AS²

AB² = AS² - 625

In ΔAST,

AS² + ST² = AT²

AS² + 54² = AT²

AS² + 2916 = AT²

From the above equations,

AS² - 625 + 2916 = AT²

AS² + 2291 = AT²

Substituting this value in ΔTAS:

TA² + AS² = 3600

TA² + (AT² - 2291) = 3600

TA² + AT² - 2291 = 36002

TA² = 5891TA² = 2945

TA = 54.23 ft (approx.)

Therefore, the length of SA is

From the above calculation, the length of SA is 43 ft.

In the given figure, two triangles are formed ΔASB and ΔTSC. We are to find the length of segment SA.

For that, we use the Pythagorean theorem to find the length of AT first.

The length of ST is 54 ft, SC is 18 ft and the length of TB is 25 ft. Applying the Pythagorean theorem, we get the length of TC as 60 ft.

Using this value, we apply the Pythagorean theorem again to find the length of AT, which comes out to be 54.23 ft (approx.).

Now that we have the length of AT, we apply the Pythagorean theorem in the triangle ΔTAS.

We find that the value of TA² is 2945. Substituting this value in the equation, we get that the length of SA is 43 ft.

Therefore, the length of line segment SA is 43 ft.

Therefore, from the above calculation, the length of line segment SA is 43 ft.

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Using the division operation, the number of 2/3's in 3 is 4

3 ÷ 2/3

change the sign to multiplication and take inverse of 2/3

3 × 3/2 = 9/2 = 4.5

We need only the whole number value .

Therefore, the number of 2/3's in 3 is 4.

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Let's say we have the equation x = y + z. To solve for y, we can rearrange the equation as follows: x = y + z. x - z = y. It takes one step to solve for y by subtracting z from both sides of the equation.

To solve for z, we can rearrange the equation as follows: x = y + z.  x - y = z.  Again, it takes one step to solve for z by subtracting y from both sides of the equation. Therefore, it takes one step to solve for both y and z in this scenario.

In general, the number of steps required to solve for a variable depends on the complexity of the equation and the operations involved. In this case, it is relatively simple as we only need to perform a single subtraction operation to isolate each variable.

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This results in a probability of approximately 0.044, or 4.4%.  the probability of any number of eagles surviving their first year can be calculated using the binomial probability formula.

The probability of a bald eagle surviving its first year of life is 62%. If 45 bald eagles are randomly selected, we can use the binomial probability formula to calculate the probability of a certain number of eagles surviving their first year.

P(x=k) = (n choose k) * p^k * (1-p)^(n-k)

Where n is the total number of trials (45), k is the number of successes (surviving eagles), p is the probability of success (0.62), and (n choose k) is the binomial coefficient.

To find the probability that exactly 20 eagles survive their first year, we plug in the values:

P(x=20) = (45 choose 20) * 0.62^20 * 0.38^25

This results in a probability of approximately 0.044, or 4.4%.

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Answer:

Line L has a slope of 1 and Line k has a slope of 2.

Step-by-step explanation: You can figure this out by using the rise (up) over run (left/right) method. Line l had 1/1 which equals 1 and line K was 2/1 which equals 2!

Answer: it is D

Step-by-step explanation:

line L hits a new point every 1 point. Line

K hits a new point at every 2 points.

To estimate the difference between proportions, sample around 3355 stalks from each section of the field.

In order to estimate the true difference between proportions of stalks damaged in the two sections of the sugarcane field, we need to determine the sample size required to achieve a desired level of precision and confidence.

To estimate the required sample size, we can use the formula for sample size determination for estimating the difference between two proportions. This formula is based on the assumption of a normal distribution and requires the proportions from each section.

Let's denote the proportion of stalks damaged in the middle section as p1 and the proportion of stalks damaged in the outer perimeter as p2. We want to estimate the difference between these proportions to within 0.02 (±0.02) with 90% confidence.

To calculate the required sample size, we need to make an assumption about the value of p1 and p2. If we don't have any prior knowledge or estimate, we can use a conservative estimate of p1 = p2 = 0.5, which maximizes the required sample size.

Using this conservative estimate, we can apply the formula for sample size determination:

n = (Z * sqrt(p1 * (1 - p1) +\(p2 * (1 - p2)))^2 / d^2\)

where:

Plugging in the values, we get:

n = (1.645 * sqrt(0.5 * (1 - 0.5) + 0.5 *\((1 - 0.5)))^2 / 0.02^2\)

n = (1.645 * sqrt\((0.25 + 0.25))^2\)/ 0.0004

n = (1.645 * sqrt\((0.5))^2\) / 0.0004

n =\((1.645 * 0.707)^2\) / 0.0004

n =\(1.158^2\) / 0.0004

n = 1.342 / 0.0004

n ≈ 3355

Therefore, the required sample size from each section of the field would be approximately 3355 stalks, in order to estimate the true difference between proportions of stalks damaged in the two sections to within 0.02 with 90% confidence.

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To estimate the true difference between proportions of stalks damaged in the two sections of the sugarcane field, approximately 665 stalks from each section should be sampled.

In order to estimate the true difference between proportions of stalks damaged in the middle and outer perimeter sections of the sugarcane field, a representative sample needs to be taken from each section. The goal is to estimate this difference within a certain level of precision and confidence.

To determine the sample size needed, we consider the desired precision and confidence level. The requirement is to estimate the true difference between proportions of stalks damaged within 0.02 (i.e., within 2%) with 90% confidence.

To calculate the sample size, we use the formula for estimating the sample size needed for comparing proportions in two independent groups. Since an equal number of stalks will be sampled from each section, the total sample size required will be twice the sample size needed for a single section.

The formula to estimate the sample size is given by:

n = [(Z * sqrt(p * (1 - p)) / d)^2] * 2

Where:

n is the required sample size per section

Z is the Z-value corresponding to the desired confidence level (for 90% confidence, Z = 1.645)

p is the estimated proportion of stalks damaged in the section (unknown, but assumed to be around 0.5 for a conservative estimate)

d is the desired precision (0.02)

Plugging in the values, we can calculate the sample size needed for each section.

n = [(1.645 * sqrt(0.5 * (1 - 0.5)) / 0.02)^2] * 2

n ≈ 664.86

Rounding up, we arrive at approximately 665 stalks that should be sampled from each section.

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Answer:

19

Step-by-step explanation:

it is 19

yes

wait no its 100000000000

I big brain UwU

Answer:

Step-by-step explanation:its 21

Answer:

67.84 is the answer.

Step-by-step explanation:

12.8 times 5.3 equals 67.84

#teamtrees #WAP (Water And Plant)

y=3-2x

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If there are 6 students and one is selected for best student and another is selected for runner up, then 15 different ways that we can arrange the students

Total number of students in the class = 6 students

Number of students for best student = 1 student

Number of students for runner up = 1 students

Total number of students needed = 2

Here we have to use the combination

6\(C_2\) = 6! / 2!(6 - 2)!

= 6! / 2! × 4!

Split the terms and cancel it

= 6 × 5 / 2 × 1

Multiply the terms

= 30 / 2

Divide the numbers

= 15 combinations

Therefore, there are 15 combinations

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Using PEDMAS to simplify the expression, the result is -830t² + 164t + 5798.4

To solve this problem, we have to simplify the expression. This is a process of breaking it down from a complex form to the least possible form. In doing this, we often apply mathematical operations such as multiplication, addition, subtraction etc.

In the expression 362.4 * 16 - 2t + 83t * (2 - 10t)

Let's apply PEDMAS here

362.4 * 16 = 5798.4

83t (2 - 10t) = 166t - 830t²

We can bring them together now;

5798.4 - 2t + 166t - 830t²

Collecting like terms

-830t² + 164t + 5798.4

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If a group of 29 friends gets together to play a sport, first people must be divided into teams each team has to have exactly 4 players and no one can be in more than one team, then the number of teams they could make is 7

The total number of people = 29

Number of people in each group = 4

No one can be more than one team

To find the number of group that they could make, we have to do the division

The number of groups = The total number of people / Number of people in each group

= 7.25

≈ 7 groups

Hence, if a group of 29 friends gets together to play a sport, first people must be divided into teams each team has to have exactly 4 players and no one can be in more than one team, then the number of teams they could make is 7

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