For the reaction C + 2 H2 --> CH4 how many moles of hydrogen are required to produce 10 moles of methane, CH4?

The mass number is the atomic mass rounded to a whole number.

The mass number, can be regarded as the atomic mass number or nucleon number, which can be seen as the total number of protons  as well as neutrons in an atomic nucleus however if it is  approximated , it can be considered to be equal to the atomic mass of the atom expressed in atomic mass units.

It should be noted that the mass number is established by rounding the atomic weight to the nearest whole number.

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Question: an oil drum weights 11.8kg. when it is filled, pentane it weighs 55.32kg. how many molecules of pentane c5h12 exist in this oil drum?

Answer:

3.64×10²⁶ molecules

Explanation:

Applying,

n = M/M.M................... Equation 1

Where n = number of moles of pentane, M = mass of pentane, M.M = reacting mass of pentane

From the question,

Given: M = 55.32-11.8 = 43.52 kg = 43520 g

Constant: M.M of octane (C₅H₁₂) = [(12×5)+(1×12)] = 60+12 = 72 g/mol

Substitute these values into equation 1

n = 43520/72

n = 604.44 moles

Therefore,

number of molecules = n×(6.02×10²³)

number of molecules = 604.44(6.02×10²³)

number of molecules = 3.64×10²⁶ molecules

The volume of the gas sample held at a constant pressure of 760 mmHg would be 3.92 L.

We can use the combined gas law to solve this problem, which relates the pressure, volume, and temperature of a gas:

P₁V₁/T₁ = P₂V₂/T₂

where P₁, V₁, and T₁ are the initial pressure, volume, and temperature, and P₂, V₂, and T₂ are the final pressure, volume, and temperature, respectively.

We are given P₁ = 760 mmHg, V₁ = 4 L, T₁ = 23°C + 273.15 = 296.15 K, and T₂ = 18°C + 273.15 = 291.15 K. We want to find V₂.

Substituting the given values into the formula, we get:

(760 mmHg)(4 L)/(296.15 K) = (P₂)(V₂)/(291.15 K)

Simplifying and solving for V₂, we get:

V₂ = (760 mmHg)(4 L)(291.15 K) / (296.15 K)(P₂)

We can solve for P₂ by rearranging the equation:

P₂ = (760 mmHg)(296.15 K) / (4 L)(291.15 K)

P₂ = 738.7 mmHg

Substituting this value for P₂, we get:

V₂ = (760 mmHg)(4 L)(291.15 K) / (296.15 K)(738.7 mmHg)

V₂ = 3.92 L

Therefore, the volume of the gas will be 3.92 L when the temperature drops to 18°C.

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Answer:

Compounds are substances composed of two or more elements chemically combined that can be separated into simpler substances only by chemical means. Water, for example, is a compound because pure water is composed of only H2O molecules.

Pls choose me as brainliest!

Answer: mixture

Explanation: Answer my own question on my page please.

Answer: A mixture.

Explanation: A substance has to do with the chemical composition changing, so if you just dissolve sugar into water nothing changes in either’s chemical composition.

Locomotion and movement are brought about by skeletal and muscular system of the body. It’s a coordinated event of the skeletal and muscular system brought by contraction and relaxation of muscles.

Locomotion occurs with help of specialised muscles, muscular and non-muscular by nature.

It involves the interaction of muscles (tendons and ligaments) and skeletal joints and cartilage

Locomotion is a voluntary action which require involvement of the nervous system.

In muscles actin and myosin protein forms cross bridges, consuming ATP.

Hence, to bring about locomotion skeletal and are responsible.

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Answer:

B) 1 amu

Explanation:

The normal atomic orbitals are joined mathematically during the process of hybridization to create new atomic orbitals known as hybrid orbitals. Even if hybrid orbitals are not identical to regular atomic orbitals.

Atomic theory & quantum mechanics use the mathematical concept of a "atomic orbital" to describe the location and wavelike behavior of an electron within an atom. Each of those orbitals can contain a maximum of electron pairs, each with a unique spin quantum number s.

Within every of an atom's shells, various orbital combinations can be found. The n=1 shell has just s orbitals; the n=2 shell contains s and p orbitals; the n=3 shell contains s, p, and d orbitals; and the n=4 up shells include all four types of orbitals.

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Answer:

Explanation:

Consider the motion of a Hot Wheels car beginning from rest at an elevated position. The Hot Wheels car rolls down a hill and begins its motion across a level surface. Along the level surface, the Hot Wheels car collides with a box and skids to a stop over a given distance. How could work and energy be utilized to analyze the motion of the Hot Wheels car? Would the total mechanical energy of the Hot Wheels car be altered in the process of rolling down the incline or in the process of skidding to a stop? Or would the total mechanical energy of the Hot Wheels car merely be conserved during the entire motion?

Of course the answers to these questions begin by determining whether or not external forces are doing work upon the car. If external forces do work upon the car, the total mechanical energy of the car is not conserved; the initial amount of mechanical energy is not the same as the final amount of mechanical energy. On the other hand, if external forces do not do work upon the car, then the total mechanical energy is conserved; that is, mechanical energy is merely transformed from the form of potential energy to the form of kinetic energy while the total amount of the two forms remains unchanged.

While the Hot Wheels car moves along the incline, external forces do not do work upon it. This assumes that dissipative forces such as air resistance have a negligible affect on the car's motion. This is a reasonable assumption for the low speeds of the car and its streamline characteristics. Since external forces do not do work on the car, the total mechanical energy of the car is conserved while moving along the incline. As the work-energy bar charts in the animation below depict, energy is transformed from potential energy (the stored energy of position) to kinetic energy (the energy of motion). The car gains speed as it loses height. The bar chart also depicts the fact that the total amount of mechanical energy is always the same; when the two forms are added together, the sum is unchanging.

When the Hot Wheels car collides with the box and skids to a stop, external forces do a significant amount of work upon the car. The force of friction acts in the direction opposite the car's motion and thus does negative work upon the car. This negative works contributes to a loss in mechanical energy of the car. In fact, if 0.40 Joules of mechanical energy are lost, then -0.40 Joules of work are done upon the car. As this work is done, the mechanical energy of the car (in the form of kinetic energy) is transformed into non-mechanical forms of energy such as sound and heat.

The pH of the solution after the addition of NaOH is 4.83.

The chemical equation for the reaction is:

CH₃COOH + NaOH → CH₃COONa + H₂O

At the start of the titration, only the weak acid is present in the solution, and its concentration can be calculated using the formula:

C₁V₁ = C₂V₂

where C₁ is the initial concentration of CH₃COOH, V₁ is the initial volume of the solution (52.0 mL), C₂ is the final concentration of CH₃COOH (which is unknown), and V₂ is the final volume of the solution after the addition of NaOH (52.0 mL + 23.0 mL = 75.0 mL).

Rearranging the equation,

C₂ = (C₁V₁) / V₂

C₂ = (0.35 M x 52.0 mL) / 75.0 mL

C₂ = 0.243 M

This is the concentration of the weak acid after the addition of 23.0 mL of NaOH. The moles of NaOH added to the solution can be calculated as follows:

n(NaOH) = C(NaOH) x V(NaOH)

n(NaOH) = 0.40 M x 23.0 mL

n(NaOH) = 0.0092 mol

Since NaOH is a strong base, it completely reacts with the weak acid. The moles of CH₃COOH that are neutralized by the NaOH can be calculated as follows:

n(CH₃COOH) = n(NaOH)

n(CH₃COOH) = 0.0092 mol

The remaining moles of CH₃COOH can be calculated as follows:

n(CH₃COOH) = n(initial) - n(NaOH)

n(CH₃COOH) = (0.35 M x 52.0 mL) / 1000 mL - 0.0092 mol

n(CH₃COOH) = 0.0154 mol

The equilibrium expression for the dissociation of CH₃COOH is:

Kₐ = [H⁺][CH₃COO⁻] / [CH₃COOH]

At equilibrium, some of the CH₃COOH has dissociated into CH₃COO⁻ and H⁺. Since we know the initial concentration of CH₃COOH and the amount of CH₃COOH that has reacted with NaOH, we can calculate the concentration of CH₃COOH at equilibrium:

[CH₃COOH] = (n(CH₃COOH) / V₂) = (0.0154 mol) / (75.0 mL / 1000 mL/L) = 0.205 M

The concentration of CH₃COO⁻ at equilibrium is equal to the concentration of NaOH that has reacted with CH₃COOH:

[CH₃COO⁻] = n(NaOH) / V₂ = (0.0092 mol) / (75.0 mL / 1000 mL/L) = 0.123 M

To calculate the concentration of H⁺ at equilibrium, we can use the equilibrium expression and the fact that [H⁺] x [CH₃COO⁻] = Kₐ x [CH₃COOH]:

Kₐ = [H⁺][CH₃COO⁻] / [CH₃COOH]

We know that the concentration of H⁺ at equilibrium is 1.49 x 10^-5 M. To calculate the pH, we can use the formula:

pH = -log[H+]

pH = -log(1.49 x 10^-5)

pH = 4.83

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The volume of 0.500-M KOH(aq) should be added to 100 ml of a buffer solution initially containing 0.13 mol HF and 0.16 mol of NaF is 100 mL of 0.500 M KOH. ka = 6.8 × 10⁴ and pH is 3.59

given that :

ka = 6.8 × 10⁴

and pH is 3.59

moles of HF = 0.13 mol

moles of NaF = 0.16 mol

the pH formula is given as :

pH = pka + log [base]/[acid]

pH = -log(6.8 × 10⁻⁴) + log (0.16 ) / 0.13

pH =  3.33  + 0.0899

pH = 3.5

Thus, the volume of 0.500 M KOH should be added to a buffer solution 0.500 M.

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Answer:

1 atm = 101.325 kPa

Therefore, 204 atm = 204 * 101.325 = 20670.3 kPa

Rounded to three significant figures, the pressure of 204 atm is 2.07 x 10^4 kPa.

Answer: Examples of surface tension

Explanation:

Water striders use the high surface tension of water and long, hydrophobic legs to help them stay above water. Water striders use this surface tension to their advantage through their highly adapted legs and distributed weight.

Answer:

They are still the same particals just. packed together diffrently depending on what stae of matter it's in.

Explanation:

The classification of alcohols that can undergo oxidation to yield a ketone is only primary alcohols.

Primary alcohols undergo oxidation to yield aldehydes, which further oxidize to ketones. The oxidation process involves the removal of two hydrogen atoms and the addition of an oxygen atom.

In contrast, secondary and tertiary alcohols do not undergo oxidation to form ketones because they lack the hydrogen atom on the carbon atom directly attached to the hydroxyl group (-OH).

The hydrogen atom on primary alcohols makes them more susceptible to oxidation, allowing them to undergo the oxidation process to form ketones. This reaction is commonly used in organic chemistry to synthesize ketones.

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Answer:

B. Past changes in the climate have been faster than the changes we're seeing today

Explanation:

The Earth is warming abnormally quickly . Over the past century it has warmed roughly 10 times faster than the average increase in temperature after each ice age .

so the answer is B.Past changes in the climate have been faster than the changes we're seeing today.

Answer:

4092 atoms of iron i am guessing

Explanation:

The mass of AgBr produced from 22.5 L of AgNO₃ is 50.01 gram

Mass is a measure of the amount of matter in a substance or an object.

Here given reaction is stoichiometric

From the balanced equation for the reaction si

2AgNO₃ + MgBr₂ → 2AgBr + Mg(NO₃)₂

The mole ratio of AgNO₃ and AgBr is 2 : 1

Mole of 22.5 g AgNO₃ = 22.5/169.87

Mole of 22.5 g AgNO₃ = 0.1325 mole

Equivalent mole of AgBr = 0.265 mole

Mass of 0.265 mole AgBr = 0.265×188.77

Mass of 0.265 mole AgBr = 50.01 gram

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Answer:

Yes is incorrect

Explanation:

not all veins carry blood rich in CO2 , the pulmonary vein carries blood with O2 which means that not all veins carry blood rich in CO2

The probability that a system is in a particular state after a large number of periods is dependent on the beginning state of the system.

This is because the probability of transitioning from one state to another is influenced by the current state of the system.

However, as the number of periods increases, the probability of being in a particular state tends to converge to a fixed value, known as the steady-state probability.

This steady-state probability is not necessarily the same for every ending system, as it depends on the transition probabilities between states.

The probability of being in a particular state after a large number of periods can be calculated using Markov chain analysis, which considers the probabilities of transitioning between states over time.

Therefore, options a and d are incorrect, while options b and c partially capture the nature of the system's probability distribution.

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Answer:

Sulfite contains 3 oxygens and sulfate contains 4 oxygens

Explanation:

The term "greenhouse" can refer to two different concepts: the physical structure known as a greenhouse and the greenhouse effect in the Earth's atmosphere.

Greenhouse gases are gases that trap heat in the Earth's atmosphere, contributing to the greenhouse effect and influencing the Earth's climate. They include:

1. Carbon Dioxide (CO2): This is the most significant greenhouse gas emitted by human activities. It is released through the burning of fossil fuels (such as coal, oil, and natural gas), deforestation, and other industrial processes.

2. Methane (CH4): Methane is produced by natural processes (such as wetlands and termites) as well as human activities such as agriculture (rice cultivation, livestock farming), fossil fuel production, and waste management (landfills).

3. Nitrous Oxide (N2O): Nitrous oxide is emitted through agricultural and industrial activities, including the use of synthetic fertilizers, fossil fuel combustion, and biomass burning.

4. Fluorinated Gases: This category includes hydrofluorocarbons (HFCs), perfluorocarbons (PFCs), and sulfur hexafluoride (SF6), which are synthetic gases used in various industrial applications, including refrigeration, air conditioning, and electronics.

These greenhouse gases trap heat radiated from the Earth's surface, preventing it from escaping into space and leading to a warming effect known as global warming.

Ice Age:

During the Ice Age, greenhouse gas concentrations were significantly lower compared to the present day. Unfortunately, specific measurements for carbon dioxide (CO2), methane (CH4), and nitrous oxide (N2O) concentrations during the Ice Age are not available.

1750:

In the 1750s, greenhouse gas concentrations were still relatively low, but human activities were starting to have an impact. Again, precise measurements for CO2, CH4, and N2O concentrations during this period are not available.

Today:

The current atmospheric CO2 concentration is over 410 parts per million (ppm). Methane concentrations have risen to over 1,800 parts per billion (ppb), and nitrous oxide concentrations have increased to over 330 ppb. These increased greenhouse gas concentrations have contributed to a warming effect on the Earth's climate. Global average temperatures have also risen compared to pre-industrial times, with an increase of about 1.1 degrees Celsius.

To obtain the most accurate and up-to-date information on greenhouse gas concentrations and temperature.

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Answer: I think this one is the boiling water

sorry if wrong

Explanation:

Hydrolysis occurs when Fe2O3 is dissolved in water, resulting in the formation of Fe(OH)3 and H+ ions. For every Fe in Fe2O3, there are 1.5 O. Thus, the iron content of Fe2O3 is reduced.

Water in the liquid state serves as the solvent in an aqueous solution. In other words, water molecules surround and integrate solute (dissolved) ions and molecules into their web of bonds. Following that, the dissolved species dispersed all over the water.

Aqueous solutions are made up of water and one or more dissolved materials. Solids, gases, or other liquids can all dissolve in an aqueous solution.

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Question:

How Many Particles Fe2O3 Will Produce In An Aqueous Solution (In Water).

The amount of concentrated solution needed is (0.286 M)(65 mL) / C M, and the amount of water needed is 65 mL minus the volume of the concentrated solution.

To calculate the molarity of Kool Aid desired, we need to determine the number of moles of Kool Aid powder and sugar in the package. Since the molecular formula for sugar is C12H22O11, we can calculate its molar mass as follows:

Molar mass of C12H22O11 = (12 * 12.01) + (22 * 1.01) + (11 * 16.00)

= 144.12 + 22.22 + 176.00

= 342.34 g/mol

Given that the package contains 4.25 grams of Kool Aid powder, we can calculate the number of moles of Kool Aid powder using its molar mass:

Number of moles of Kool Aid powder = Mass / Molar mass

= 4.25 g / 342.34 g/mol

≈ 0.0124 mol

Similarly, for the sugar, which has a molar mass of 342.34 g/mol, we can calculate the number of moles of sugar using its mass:

Number of moles of sugar = Mass / Molar mass

= 192.00 g / 342.34 g/mol

≈ 0.5612 mol

Now, to calculate the molarity of the desired Kool Aid solution, we need to determine the volume of water. Given that 1.06 quarts is equal to 1 liter, and we have 2.00 quarts of water, we can convert it to liters as follows:

Volume of water = 2.00 quarts * (1.06 liters / 1 quart)

= 2.12 liters

To find the molarity, we use the formula:

Molarity (M) = Number of moles / Volume (in liters)

Molarity of Kool Aid desired = (0.0124 mol + 0.5612 mol) / 2.12 L

≈ 0.286 M

To prepare 65 mL of the desired molarity, we can use dilution calculations. We need to determine the volume of concentrated solution and the volume of water needed.

Let's assume the concentration of the concentrated Kool Aid solution is C M. Using the dilution formula:

(C1)(V1) = (C2)(V2)where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

Given that C1 = C M and V1 = V mL, and we want to prepare a final volume of 65 mL (V2 = 65 mL) with a final concentration of 0.286 M (C2 = 0.286 M), we can rearrange the formula to solve for the volume of the concentrated solution:

(C M)(V mL) = (0.286 M)(65 mL)

V mL = (0.286 M)(65 mL) / C M

So, the amount of concentrated solution needed is (0.286 M)(65 mL) / C M, and the amount of water needed is 65 mL minus the volume of the concentrated solution.

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A person can order a two-course meal in 80 different ways at this restaurant. To calculate the number of ways a person can order a two-course meal at this restaurant, you'll want to use the concept of counting methods in combinatorics. In this case, you can use the multiplication principle.

The multiplication principle states that if there are 'a' ways to do one task and 'b' ways to do another task, there are 'a x b' ways to do both tasks together. Here, the tasks are choosing an appetizer and a main course.
The restaurant offers 8 appetizers and 10 main courses. So, a person has 8 options for appetizers and 10 options for main courses.

To find the total number of ways to order a two-course meal, simply multiply the number of appetizers by the number of main courses:
8 appetizers × 10 main courses = 80 possible two-course meals

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The term that describes what she is measuring is called partial pressure.

From the Dalton's law of partial pressure, the total pressure of a gas is regarded as the sum of the partial pressures of all the gases in the mixture.

As such, each of the gases; carbon dioxide, oxygen, and nitrogen all possess partial pressures thus the term that describes what she is measuring is called partial pressure.

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The correct word equation for the reaction described is: calcium hydride + water → calcium hydroxide + hydrogen gas. Therefore, the correct chemical equation for this reaction is: CaH2 + 2H2O → Ca(OH)2 + 2H2

Calcium hydride is an inorganic compound with the chemical formula CaH2. It is a white to gray solid, often sold in a powder form, and is highly reactive with water. When calcium hydride reacts with water, it produces hydrogen gas and calcium hydroxide. Calcium hydride is commonly used as a drying agent in organic solvents and gases because it reacts with water to form hydrogen gas and calcium hydroxide, which can be easily removed. It is also used in the production of hydrogen gas for fuel cells and as a reducing agent in metallurgy.

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The maximum solubility of Ag₂CO₃ = = 1 x 10⁻⁵

Given

0.02 M Na₂CO₃

Ksp of  Ag₂CO₃ is 8 x 10⁻¹²

Required

The solubility of Ag₂CO₃

Solution

Ag₂CO₃ ⇒ 2Ag⁺ + CO₃²⁻

s                  2s        s

s = solubility

Ksp Ag₂CO₃ = [Ag⁺]² [CO₃²⁻]

Ksp Ag₂CO₃ = (2s)².s

Ksp Ag₂CO₃ = 4s³

In 0.02 M Na₂CO₃ ⇒ 2Na⁺ + CO₃²⁻⇒ [ CO₃²⁻]=0.02, so Ksp Ag₂CO₃ :

8 x 10⁻¹² = [2s]² [0.02]

8 x 10⁻¹² = 4s² [0.02]

4s² = 8 x 10⁻¹² / 2 × 10⁻²

4s² = 4 x 10⁻¹⁰

s² = 1 x 10⁻¹⁰

s = √1 x 10⁻¹⁰

s = 1 x 10⁻⁵