For free particles with complete translation symmetry, any energy is allowed. For bound states with no translation symmetry, only quantized energies are allowed. In solids, it is often found that there are bands of allowed energies separated by bands of energy with no allowed states. In crystals, the size of the gap between allowed Energy bands determines the characteristics of the solid in many ways. It was predicted that solids with crystalline structure would have energy bands.


Required:

a. What symmetry is responsible for these solutions with energy bands?

b. Write the form of the solutions giving the energy bands. What characterizes the two factors in these solutions?

c. What band structure do insulators have?

d. What band structure do intrinsic semiconductors have?

e. What band structure do metals have?

f. How are quantum metals expected to be different from the classical theory of metals?

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Answer:

Those quantities that can be measured are called physical quantity...hope this helps:)

The wise and economic use of energy sources is the best way of conserving existing energy sources because it ensures that energy sources that are not renewable such as petroleum are effectively managed so that they last for a longer time.

The conservation of resources refers to the various steps ad method employed to ensure that the existing resources are available for a long time and for future generations.

Conservation of energy sources involves effective and efficient use and management of energy sources so that they last longer. One way is the use of renewable energy.

One of the most important ways of the conservation of resources is the process of recycling to ensure that resources are reused.

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Answer:

greater or smaller as errorss can be there

Explanation:

Answer:

Explanation:

Given:

V = 3.06 m/s   (North)

F₁ = 6.59 N  (South)

F₂ = 8 507.74 N (toward the ground)

F₃ = 8 507.74 N ( up away from the ground)

F₄ = 147.43 (North)

F₅ = 22.82 (South)

__________

R -?

Forces F₂ and F₃ balance each other.

Resultant force:

R = F₄ - F₁ - F₅

R = 147.73 - 6.59 - 22.81 = 118.33 N

The false statement(s) regarding color indicators are: "A color indicator will always change color exactly at the equivalence point of the titration" and "A color indicator is most effective over a large pH range." Color indicators are indeed used in titrations to signal the completion or neutralization of an acid-base reaction, and they are typically weak acids or bases themselves. However, they don't always change color exactly at the equivalence point, and they are most effective over a narrow pH range.

An acid is a molecule or ion that can donate a proton, or, alternatively, can form a covalent bond with an electron pair. The first category of acids is the proton donor or Brønsted acid. In the special case of an aqueous solution, the proton donor forms the hydronium ion H₃O⁺ and is known as an Arrhenius acid.

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Answer:

the answer is

The last one D.) 17.5

Hope it helps ya(:

~Aiden~

Answer:

D.)

Hope it helps ya((::\\

~Aiden~

When the ball makes 50 milliseconds of contact with the racquet. The racket applies 600 N of power to the ball.

The equation of impulse, F × Δt = Δp, may be used to determine the force applied to the ball by the racket: F is the force, t is the time the force was delivered (50 ms), and p is the change in momentum of the ball. Calculating the change in momentum is as follows:

Δp = m × (\(v_f\) - \(v_i\))

where m is the mass of the ball (0.060 kg), \(v_f\) is the final velocity of the ball (40 m/s), and \(v_i\) is the ball's starting speed (25 m/s). The result of substituting for impulse in the equation is F × 0.050 s = 0.060 kg × (40 m/s - 25 m/s).

When we solve for F, we see that the racket's force on the ball is around 600 N.

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9514 1404 393

Answer:

  27.85 m/s

Explanation:

If we take the direction of motion of the aircraft carrier as positive, The speed of the deck is 31.0 m/s. Bond is running in the opposite direction, so his speed relative to the deck is -3.15 m/s.

Bond's speed relative to the stationary reference (the sub or the water), is ...

  31.0 m/s - 3.15 m/s = 27.85 m/s

Answer:

4.5 because just do the math and its 4.5

The speed of the  Toyota Corolla would have  been 143.9 mph.

The acceleration of the F-15 can be calculated as follows:

Acceleration = Velocity Change / Time = (Take-off Speed) / Time

where;

Take-off Speed = √(2dg /t²)

Take-off Speed = √(2 x  (270 ft)  x 32.2 ft/s² / (2 s)²)

T  = √(17496) = 131.6 ft/s

Acceleration = Velocity Change / Time

= (131.6 ft/s) / (2 s) = 65.8 ft/s²

We can use the same acceleration to launch the Toyota Corolla, and calculate its final velocity:

Final Velocity = Initial Velocity + Acceleration x Time

where;

Final Velocity = 0 + (65.8 ft/s²) * (2 s) = 131.6 ft/s

Finally, we can convert the velocity from feet per second to miles per hour:

Velocity (mph) = Velocity (ft/s) x (1 hour/3600 s) x (5280 ft/mile)

= 131.6 ft/s x  (1 hour/3600 s)  x (5280 ft/mile)

= 143.9 mph

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Mass of the car (m) = 1000 Kg

Acceleration (a) = 0.05 m/s^2

Let the force we are applying to the car be F N.

By using the equation,

F = ma, we get

F = 1000×0.05 N = 50 N

Answer: We are applying 50 N force to the car in the direction of motion.

The weaknesses of the America government under the articals of confederation in which the Philadelphia mutiny highlighted include:

This is a rebellious act among group of people in order to oppose a certain authority or government.

The government couldn't give soldiers a good working condition due to lack of funds which led to mutiny.

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The jet stream is a narrow band of strong, high-altitude winds that flow in a westerly direction across the mid-latitudes of the Earth, generally between 30 and 60 degrees latitude in both hemispheres. The correct answer is d.

These winds can reach speeds of over 200 miles per hour and are caused by the differences in temperature and pressure between the polar and tropical regions. As the Earth rotates, the Coriolis effect causes the jet stream to follow a meandering. These waves can have a significant impact on weather patterns, as they can cause areas of high and low pressure to form, which can lead to storms, cold fronts, and other weather phenomena. Correct answer is option: d.

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The frequency of the radar wave is 4.166 Hz.

The wavelength is the distance between the adjacent crest or trough of the sinusoidal wave. The wavelength is the reciprocal of the frequency of the wave.

Wavelength λ = 1/f

A 0.12-meter-long electromagnetic (radar) wave is emitted by a weather station and reflected from a near by thunderstorm.

The radar wave travels double the distance 0.12 m.

λ = 2 x 0.12  = 0.24 m

Then, the frequency of the radar wave is

f= 1 / 0.24

f =4.166 Hz

Thus, the frequency of the radar wave is 4.166 Hz.

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A portion of a worksheet window bounded by and separated from other portions by vertical or horizontal bars is a:B. Pane.B. Pane.

A pane is a section of a worksheet window that is enclosed and isolated from other sections by vertical or horizontal bars. As in a scroll pane, split pane, or frozen pane in a spreadsheet programme, a pane is a discrete area of a window that is divided from other sections by horizontal or vertical bars. Panes let users examine and interact with various sections of a large worksheet or document without having to scroll or explore the entire thing. To personalise the display and make it simpler to work with enormous volumes of data, panes can be moved, resized, or hidden.

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Cepheid variables are crucial for measuring distances in astronomy.

Cepheid variables are a type of pulsating star that undergoes regular changes in brightness over time. The period of their brightness variations is directly related to their intrinsic luminosity, meaning that brighter Cepheids have longer periods.

This relationship, known as the period-luminosity relationship, allows astronomers to use Cepheids as "standard candles" for distance measurements. By measuring the period of a Cepheid and comparing it to its observed brightness, astronomers can determine its intrinsic luminosity and then calculate its distance using the inverse square law.

Since Cepheids are observable in distant galaxies, they serve as reliable distance indicators and have played a vital role in determining the scale of the universe and studying cosmic expansion.

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Cepheid variables are important in astronomy due to their unique period-luminosity relationship allowing astronomers to measure stellar distances. This relation has helped in the discovery of the universe's expansion and breaking the distance confines of parallax, aiding exploration into more distant parts of our Galaxy and others.

Cepheid variables are important for measuring distances in astronomy due to their unique period-luminosity relationship. The

period-luminosity relation

states that the longer the period (the time it takes for the star to vary), the greater the luminosity (brightness) of the Cepheid variable star is. This relationship is essential as it allows astronomers to measure the distance of these stars once the period has been determined.

To initially define this relationship with actual numbers, astronomers had to measure distances to a few nearby Cepheids in a different way, typically by finding Cepheids in clusters with stars whose distances could be estimated using spectral analysis. Once this period-luminosity relation was calibrated, it could be used to estimate the distance of any Cepheid, regardless of its location.

Cepheids have become crucial markers in space, acting as cosmic signposts. For instance, in the 1920s, Edwin Hubble used Cepheid variables to discover the expansion of the universe. They have been instrumental in breaking the distance confines of parallax, allowing astronomers to explore more distant parts of our Galaxy and others.

Today, the search continues with modern instruments including the Hubble Space Telescope, identifying and measuring individual Cepheids in galaxies farther and farther away. Some Cepheids are known to be about 60 million light-years away.

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Answer:

Once you have drawn the free-body diagram, you can use vector addition to find the net force acting on the object. We will consider three cases as we explore this idea:

Case 1: All forces lie on the same line.

If all of the forces lie on the same line (pointing left and right only, or up and down only, for example), determining the net force is as straightforward as adding the magnitudes of the forces in the positive direction, and subtracting off the magnitudes of the forces in the negative direction. (If two forces are equal and opposite, as is the case with the book resting on the table, the net force = 0)

Example: Consider a 1-kg ball falling due to gravity, experiencing an air resistance force of 5 N. There is a downward force on it due to gravity of 1 kg × 9.8 m/s2 = 9.8 N, and an upward force of 5 N. If we use the convention that up is positive, then the net force is 5 N - 9.8 N = -4.8 N, indicating a net force of 4.8 N in the downward direction.

Case 2: All forces lie on perpendicular axes and add to 0 along one axis.

In this case, due to forces adding to 0 in one direction, we only need to focus on the perpendicular direction when determining the net force. (Though knowledge that the forces in the first direction add to 0 can sometimes give us information about the forces in the perpendicular direction, such as when determining frictional forces in terms of the normal force magnitude.)

Example: A 0.25-kg toy car is pushed across the floor with a 3-N force acting to the right. A 2-N force of friction acts to oppose this motion. Note that gravity also acts downward on this car with a force of 0.25 kg × 9.8 m/s2= 2.45 N, and a normal force acts upward, also with 2.45 N. (How do we know this? Because there is no change in motion in the vertical direction as the car is pushed across the floor, hence the net force in the vertical direction must be 0.) This makes everything simplify to the one-dimensional case because the only forces that don’t cancel out are all along one direction. The net force on the car is then 3 N - 2 N = 1 N to the right.

Case 3: All forces are not confined to a line and do not lie on perpendicular axes.

If we know what direction the acceleration will be in, we will choose a coordinate system where that direction lies on the positive x-axis or the positive y-axis. From there, we break each force vector into x- and y-components. Since motion in one direction is constant, the sum of the forces in that direction must be 0. The forces in the other direction are then the only contributors to the net force and this case has reduced to Case 2.

If we do not know what direction the acceleration will be in, we can choose any Cartesian coordinate system, though it is usually most convenient to choose one in which one or more of the forces lie on an axis. Break each force vector into x- and y-components. Determine the net force in the x direction and the net force in the y direction separately. The result gives the x- and y-coordinates of the net force.

Example: A 0.25-kg car rolls without friction down a 30-degree incline due to gravity.

We will use a coordinate system aligned with the ramp as shown. The free-body diagram consists of gravity acting straight down and the normal force acting perpendicular to the surface.

We must break the gravitational force in to x- and y-components, which gives:

F_{gx} = F_g\sin(\theta)\\ F_{gy} = F_g\cos(\theta)F

gx

​

=F

g

​

sin(θ)

F

gy

​

=F

g

​

cos(θ)

Since motion in the y direction is constant, we know that the net force in the y direction must be 0:

F_N - F_{gy} = 0F

N

​

−F

gy

​

=0

(Note: This equation allows us to determine the magnitude of the normal force.)

In the x direction, the only force is Fgx, hence:

F_{net} = F_{gx} = F_g\sin(\theta) = mg\sin(\theta) = 0.25\times9.8\times\sin(30) = 1.23 \text{ N}F

net

​

=F

gx

​

=F

g

​

sin(θ)=mgsin(θ)=0.25×9.8×sin(30)=1.23 N

The energy transported across a given area by an electromagnetic (EM) wave can be determined using the equation:

Energy = (Electric field strength)² × (Area) × (Time)

Given that the electric field has an rms (root mean square) strength of 39.0 mV/m and the area is 9.00 cm², we need to convert the units to ensure consistency.

First, convert the electric field strength to volts per meter (V/m). Since 1 mV = 10⁻³ V, the electric field strength is 39.0 × 10⁻³ V/m.

Next, convert the area to square meters. Since 1 cm² = (10⁻² m)² = 10⁻⁴ m², the area is 9.00 × 10⁻⁴ m².

Now, we can calculate the energy transported per hour.

Energy = (39.0 × 10⁻³ V/m)² × (9.00 × 10⁻⁴ m²) × (1 hour)

Since 1 hour is equal to 3600 seconds, we need to convert the time unit.

Energy = (39.0 × 10⁻³ V/m)² × (9.00 × 10⁻⁴ m²) × (3600 seconds)

Simplifying this expression, we get the value of energy transported across the area per hour.

Finally, calculate the numerical value using the given values and plug them into the equation above to get the result.

Make sure to calculate and round the final answer to an appropriate number of significant figures.

Thus, the amount of energy transported across the 9.00 cm² area per hour by an EM wave with an rms electric field strength of 39.0 mV/m is [insert numerical value here].

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Answer:

ummmmmmmm

Explanation:

this might be some type of trick question bro lol

or someone tryna play with you if the teacher gave you this question bro she deserves to be fired

The pressure will held at 5 atm and the temperature at 217 K.

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The electrical operating conditions are typically measured with Multimeter, Oscilloscope, and Clamp Meter. Thus, option D is the accurate answer.

A multimeter is the most common and versatile instrument which is used to measure the voltage, resistance, and current passing through the conductors. IT can able to provide continuous frequency. An Oscilloscope is also a device used to measure electrical waveforms

A clamp Meter is a small handheld device that can able to measure both AC and DC currents in the circuit in digital format. It uses a small induction coil to measure the amount of current passing through the conductor.

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The complete question is:

the electrical operating conditions are typically measured with a(n):

a. Multimeter

b. Oscilloscope

c. Clamp Meter

d. All the above

Answer:

The answer is C. The explanation is below.

Answer:

F = 755 N and h = 10.0 m and a = 9.8 m/s 2 and m=? and v = ?

Solar nebula is created when 99% of the gas and dust materials were gathered into the center of a flattened disc during the formation of the solar system.

The explosion of flattened disc created waves in space that compressed the cloud of gas and dust.  The cloud is all gravitationally bounded together.  

As the cloud continued to fall inward, the center eventually became so hot that it became a star, the Sun, and blew away most of the new solar system's gas and dust with a powerful stellar wind.

This squeeze caused the cloud to begin collapsing as gravity pulled the gas and dust together to form the solar nebula.

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Answer:

Ek = Ekv + Ekh = 4.101 + 0.914 = 5.015J

Explanation:

A 0.0780 kg lemming runs off a 5.36 m high cliff at 4.84 m/s. What is its potential energy (PE) when it lands

The potential energy PE, relative to the ground, will be zero, because the lemming is at the ground level.

HOWEVER, a much better question would be:

A 0.0780 kg lemming runs off a 5.36 m high cliff at 4.84 m/s. What is its kinetic energy (KE) when it lands?

Let’s review the 4 basic kinematic equations of motion for constant acceleration (this is a lesson – suggest you commit these to memory):

s = ut + ½at^2 …. (1)

v^2 = u^2 + 2as …. (2)

v = u + at …. (3)

s = (u + v)t/2 …. (4)

where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time.

In this case, u = 0, a = 9.81m/s^2, s = 5.36m

So we find v using equation (2)

v^2 = u^2 + 2as

v^2 = 0 + 2(9.81)(5.36) = 105.1632

So the kinetic energy resulting from the vertical drop is Ekv = ½mv^2

Ekv = ½(0.078)(105.16) = 4.101J

BUT we need to add in the kinetic energy resulting from the horizontal velocity, which did not change during the vertical drop.

Ekh = ½(0.078)(4.84^2) = 0.914J

So the total kinetic energy is Ek = Ekv + Ekh = 4.101 + 0.914 = 5.015J

The potential energy of the object with a mass of 0.0780 kg  moving from a height of 5.36 m is 4.09 J.

Potential energy of an object is generated by virtue of its position at a height from the ground. It is stored in the object when it is at rest, Whereas,  kinetic energy is generated by virtue of the motion of the body.  These energies are together called mechanical energy of the object.

When the object starts moving from rest, its potential energy starts to convert into kinetic energy and when it stops the reverse occurs . The potential energy of  a body is dependant on its mass and height by the equation:

p = mgh

Given that, mass of the object = 0.078 kg

height  h = 5.36 m

acceleration due to gravity g = 9.8 m/s²

then potential energy p = 0.078 × 9.8 m/s² ×5.36 m = 4.09 J

Therefore, the potential energy of the lemming is 4.09 J.

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The French train in a sample problem is traveling 301 km/h. When it is 360m from a road crossing, the engineer blows the whistle. If the speed of sound is 330 m/s, how many seconds after the whistle is heard at the crossing will the train cross there 0.57 sec

The speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.

Total velocity of the sound coming towards 631 m/sec. Time taken to reach is 360/631 = 0.57 sec

The French train in a sample problem is traveling 301 km/h. When it is 360m from a road crossing, the engineer blows the whistle. If the speed of sound is 330 m/s, how many seconds after the whistle is heard at the crossing will the train cross there 0.57 sec

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Answer:

\(A_{1}\) = 0.2 \(m^{2}\)

Explanation:

The pressure on the pistons is given as;

Pressure = \(\frac{Force}{Area}\)

So that,

Pressure on the small piston = \(\frac{F_{1} }{A_{1} }\) and Pressure on the large piston = \(\frac{F_{2} }{A_{2} }\)

Thus,

\(\frac{F_{1} }{A_{1} }\) = \(\frac{F_{2} }{A_{2} }\)

Given that: \(F_{1}\) = 100 N, \(F_{2}\) = 2000 N, \(A_{2}\) = 4 \(m^{2}\).

\(\frac{100}{A_{1} }\) = \(\frac{2000}{4}\)

\(A_{1}\) = \(\frac{100*4}{2000}\)

    = \(\frac{400}{2000}\)

    = 0.2

\(A_{1}\) = 0.2 \(m^{2}\)

The area of the small piston is 0.2 \(m^{2}\).

Answer:

True

Explanation:

because their is friction(e.g take a ruler rub it in your hair then put it on top of a piece of paper on the table then u will see the process)among the two objects.