what are the subsystems of a crane

The absolute pressure at an ocean depth of 1.0 x 10^3 m is 1.002 x 10^8 Pa.

Hydrostatic pressure is the pressure that a fluid exerts on a surface due to the weight of the fluid above it. It is the result of the force of gravity acting on a column of fluid, and it is directly proportional to the height of the column of fluid and the density of the fluid.

The absolute pressure at an ocean depth of 1.0 x 10^3 m can be calculated using the hydrostatic pressure equation:

P = ρgh + Po

where:

P is the absolute pressure at the given depth

ρ is the density of the water

g is the acceleration due to gravity (assumed to be 9.81 m/s²)

h is the depth of the ocean

Po is the atmospheric pressure at the surface (assumed to be 1.01 x 10^5 Pa)

Substituting the given values, we get:

P = (1.025 x 10^3 kg/m³) x (9.81 m/s²) x (1.0 x 10^3 m) + 1.01 x 10^5 Pa

P = 1.025 x 9.81 x 10^6 Pa + 1.01 x 10^5 Pa

P = 1.002 x 10^8 Pa.

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Answer:

123.6 N

Explanation:

I will try to answer this

Find height of the ball

  9. 5   - 9.5 cos 35  = 1.72 m   of potential energy

   PE = mgh    will be converted to KE at the bottom of the swing

     mgh = 1/2  m v^2

    sqrt( 2 gh )  = v      at the bottom = 5.81  m/s

then the tension is the mass times the acceleration of gravity PLUS the acceleration of circular motion  v^2 / r

F = ma

F = 9.25 kg ( 9.81 m/s^2 + 5.81^2 / 9.5 m/s^2 ) = tension = 123.6 N

(Let me know if this is incorrect, and I will research a bit more)

Thermal energy is produced when a burner in a stove is lit up

Heat energy or thermal energy is a form of energy that is due to the differences in temperature between two bodies.

Thermal energy is produces by burning substances.

Heat flow is from hot to colder bodies

When a burner in a stove is lit up, it converts chemical energy to heat energy.

Therefore, a burner on a stove produces thermal energy.

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Answer:

3.666 × 10³ kg/m³

Explanation:

Let's assume the volume of metal Y in the alloy is V cubic meters. Since the volume of metal X is twice that of Y, the volume of metal X would be 2V cubic meters.

The density of a substance is given by the formula:

Density = Mass / Volume

Let's assume the mass of metal X is Mx and the mass of metal Y is My.

For metal X:

Density of X = Mx / (2V) -- Equation 1

For metal Y:

Density of Y = My / V -- Equation 2

Given that the density of metal X is 3 × 10³ kg/m³ and the density of metal Y is 5 × 10³ kg/m³, we can rewrite Equations 1 and 2 as:

3 × 10³ = Mx / (2V) -- Equation 1

5 × 10³ = My / V -- Equation 2

To find the density of the alloy, we need to find the total mass of the alloy (M) and the total volume of the alloy (Vt). The total mass of the alloy is the sum of the masses of metal X and metal Y, and the total volume of the alloy is the sum of the volumes of metal X and metal Y.

M = Mx + My

Vt = 2V + V

We can rearrange Equation 1 to find Mx in terms of V:

Mx = 3 × 10³ * (2V) = 6 × 10³V

Substituting the values in the equation for M:

M = 6 × 10³V + My

We can substitute the value of Mx in Equation 2:

5 × 10³ = My / V

Rearranging Equation 2 to find My in terms of V:

My = 5 × 10³V

Substituting the values of Mx and My in the equation for M:

M = 6 × 10³V + 5 × 10³V

M = 11 × 10³V

The density of the alloy (Da) is given by the formula:

Da = M / Vt

Substituting the values of M and Vt:

Da = (11 × 10³V) / (2V + V)

Da = (11 × 10³V) / (3V)

Da = 11 × 10³ / 3

Simplifying further:

Da = 3.666 × 10³ kg/m³

Therefore, the density of the alloy is approximately 3.666 × 10³ kg/m³.

Answer:

no it's opaque

hope this helps

have a good day :)

Explanation:

The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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Answer:

11.25J

Explanation:

15=(output/75)x100

output =(75x15)/100=11.25J

Answer:

PE = 137.2931 J

Explanation:

PE = 137.2931 J

Answer:

a) 28877 AU

b) 1.795 sec

Explanation:

Time it took the radio signal to reach earth = 4 hours = 4 x 3600 = 14400 s

speed of radio signal = speed of vacuum speed of light  = 3 x 10^8 m/s

Distance traveled by this signal = speed x time

distance = 3 x 10^8 x 14400 = 4.32 x 10^12 m

One Astronomic unit AU is the distance between the Earth and the sun and it is approximately equal to 1.496 x 10^8 m

The distance traveled by the signal in AU = (4.32 x 10^12)/(1.496 x 10^8) = 28877 AU

b) The minimum separation between Earth and Mars = 0.36 AU

This distance = 0.36 x 1.496 x 10^8 = 538560000 m

Time that will be taken for a radio signal to travel this distance = distance/speed

==> 538560000/(3 x 10^8) = 1.795 sec

Hello!

\(\large\boxed{-2m/s^{2} }\)

Find the acceleration using the formula a =  (vf - vi) / t where:

vf = final velocity

vi = initial velocity

t = time

Plug in the points above:

vf = +10 m/s

vi = +20 m/s

t = 5 sec

(10 - 20) / 5 = -10 / 5 = -2 m/s²

Mechanical energy changes when a roller coaster starts at a height of 40 meters and reaches a height of 20 meters. The potential energy decreases, while the kinetic energy increases.

When a roller coaster starts at a height of 40 meters and reaches a height of 20 meters, mechanical energy changes. In physics, mechanical energy is the sum of potential and kinetic energy that is present in the objects. When an object is moved, it gains or loses energy, thus the mechanical energy changes. There are two forms of mechanical energy, namely kinetic energy and potential energy. Kinetic energy is the energy that a moving object possesses due to its motion, while potential energy is the energy that an object possesses due to its position or shape.
In the case of a roller coaster, when it starts at a height of 40 meters, it has potential energy that is equal to its mass multiplied by the acceleration due to gravity multiplied by its height. As it moves down the track, the potential energy gets converted into kinetic energy, which is the energy of motion. When the roller coaster reaches a height of 20 meters, it has a lower potential energy compared to when it started. The difference in potential energy is equal to the amount of work done by the force of gravity in bringing the roller coaster down from a height of 40 meters to a height of 20 meters. At the same time, the roller coaster has a higher kinetic energy than when it started, as it gained speed during the descent.
Therefore, in summary, mechanical energy changes when a roller coaster starts at a height of 40 meters and reaches a height of 20 meters. The potential energy decreases, while the kinetic energy increases.

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We have that  the ratio of his walking pace  to the walking pace of a person of average height is

\(\frac{V_2}{V_1}=1.10\)

given the assumption and the calculation given below

From the question we are told that:

Consider a person 18\% shorter than average

Let average height of a person be \(10m\)

Therefore

The height of an \(18\%\) shorter man is mathematically given as

H=10*0.18

H=8.2m

Generally, the equation for velocity is mathematically given by

\(v=\frac{1}{2\pi} \sqrt{{g}{l}}\)

Where we have the  Assumption that a person's leg swings like a pendulum and that the angular amplitude of everybody's stride is about the same

Therefore

\(\frac{V_1}{V_2}=\frac{l_1}{l_2}\)

\(\frac{V_1}{V_2}={82}{100}\)

\(\frac{V_2}{V_1}=1.10\)

In conclusion

The ratio of his walking pace (that is, the frequency 'f' of his motion) to the walking pace of a person of average height is

\(\frac{V_2}{V_1}=1.10\)

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Answer:

One possible explanation students can make: The crabs cannot see the plankton they eat near the ocean floor. For the crabs to see the plankton, some color of visible light would need to reach the plankton so that it can be reflected into the crabs' eyes.

Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

Answer:

where u put it last time or retrace ur steps to where u last put it

If you pull with a constant force of 400 N for 0.2 meters, then the work done will be equal to 80 J.

In physics, the word "work" involves the measurement of energy transfer that takes place when an item is moved over a range by an externally applied, at least a portion of which is applied within the direction of the displacement.

The length of the path is multiplied by the element of a force acting all along the path to calculate work if the force is constant. The work W is theoretically equivalent towards the force f times the length d, or W = fd, to portray this concept.

As per the given information in the question,

Force, f = 400 N

Displacement, d = 0.2 meters

\(Work done(W)=Force(f)*Displacement(d)\)

W = 400 × 0.2

W = 80 J.

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Answer:

-2.3 × 10^-9 Coulombs(C).

Explanation:

So, we are given the following data or information or parameters that is going to help us to solve the problem effectively and efficiently;

=> " the shuttle's potential is typically changed by -1.4 V during one revolution. "

=> " Assuming the shuttle is a conducting sphere of radius 15 m".

So, in order to estimate the value for the charge we will be making use of the equation below:

Charge, C =( radius × voltage or potential difference) ÷ Coulomb's law constant.

Note that the value of Coulomb's law constant = 9 x 10^9 Nm^2 / C^2.

So, charge = { 15 × (- 1.4)} / 9 x 10^9 Nm^2 / C^2.

= -2.3 × 10^-9 Coulombs(C).

The conversion factor of 5280 feet per mile is used to convert the distance, and rounding to the nearest tenth gives us approximately 3.6 miles. The correct answer is option D: 3.6 mi.

To convert 18,900 feet to miles, we can use the conversion factor of 5280 feet per mile. By dividing the distance in feet by this conversion factor, we will obtain the equivalent distance in miles.

Distance in miles = 18,900 feet ÷ 5280 feet/mile

Calculating this expression, we find:

Distance in miles = 3.57 miles

Rounding to the nearest tenth, the distance is approximately 3.6 miles.

Therefore, the correct answer is option D: 3.6 mi.

It is important to note that the conversion factor of 5280 feet per mile is derived from the definition of a mile as 5,280 feet. This conversion factor is widely used to convert measurements between feet and miles in various contexts, such as distance calculations, road signs, and sports events. Here option D is the correct answer.

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Known :

z1 = 380 ft

z2 = 210 ft

D1 = 8 in

D2 = 4 in

hL = 36 ft

Solution :

Continuity Equation

Q1 = Q2

A1 • V1 = A2 • V2

(πD1²/4) • V1 = (πD2²/4) • V2

D1² • V1 = D2² • V2

8² • V1 = 4² • V2

V2 = 4V1 ... (i)

Energy Equation :

P1/γ + V1²/2g + z1 = P2/γ + V2²/2g + z2 + hL

Since P1 = P2, then

V1²/2g + z1 = V2²/2g + z2 + hL

V1²/2(32.2) + 380 = V2²/2(32.2) + 210 + 36

V2² - V1² = 8.63 × 10³ ... (ii)

Subtitute (i) into (ii)

(4V1)² - V1² = 8.63 × 10³

15V1² = 8.63 × 10³

V1 = 24 ft/s

Q = A1 • V1

Q = [π(8/12)² / 4] • 24

Q = 8.377 cfs

The dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.

Start by converting the rotational speed from rpm (revolutions per minute) to rad/s (radians per second). Since 1 revolution is equal to 2π radians, we can use the conversion factor:

Angular speed (ω) = (1100 rpm) × (2π rad/1 min) × (1 min/60 s)

ω ≈ 115.28 rad/s

The moment of inertia (I) is given as 2.0 × 10^-7 kg⋅m².

Use the formula for rotational kinetic energy:

Rotational Kinetic Energy (KE_rot) = (1/2) I ω²

Substituting the given values:

KE_rot = (1/2) × (2.0 × 10^-7 kg⋅m²) × (115.28 rad/s)²

Calculate the value inside the parentheses:

KE_rot ≈ (1/2) × (2.0 × 10^-7 kg⋅m²) × (13274.28 rad²/s²)

KE_rot ≈ 1.331 × 10^-3 J

Round the result to the proper number of significant figures, which in this case is three, as indicated by the given moment of inertia.

KE_rot ≈ 4.8 × 10^-4 J

Therefore, the dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.

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Answer:96.1

Explanation:

The minimum time necessary to pull out Margo is 2.64 seconds.

Given the data in the question;

There are two forces acting on Margo, as shown in the image below, the rope Tension acting upward and the force of gravity acting downward.

From Newton's second law of motion:

\(F = m*a\)  

where F is the Force acting on the body, m is the mass and a is the acceleration.

Also, \(F = T - mg\)

So, \(T - mg = ma\)

We know that the value of "g" gravitation due to gravity is \(9.81m/s^2\) and \(1Newton = 1 kg.m/s^2\)

We substitute in our values to find "a"

\(755 kg.m/s^2 - ( 70.0kg*9.81m/s^2) = (70kg * a )\)

\(755 kg.m/s^2 - 686.7 kg.m/s^2 = (70kg * a )\)

\(68.3kg.m/s^2 = (70kg * a )\)

\(a = \frac{68.3kg.m/s^2}{70kg}\)

\(a = 0.9757 m/s^2\)

Now, we set \(v_0 = 0\) to get the minimum time required

From the second equation of motion:

\(s = v_0t + \frac{1}{2} at^2\)

Since \(v_0 = 0\)

\(s = \frac{1}{2} at^2\)

We make time "t", the subject of the formula

\(t = \sqrt{\frac{2s}{a} }\)

We substitute in our values

\(t = \sqrt{\frac{2*3.4m}{0.9757m/s^2} }\)

\(t = 2.63995 s\\\\t = 2.64s\)

Therefore, the minimum time necessary to pull out Margo is 2.64 seconds.

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The correct answer is : B. The air above the land heats up and cools off more quickly than the air over water is the most important factor that creates wind patterns.

This is because temperature differences between land and water create differences in air pressure, which in turn causes the movement of air (wind). During the day, land heats up faster than water, causing the air above the land to rise and cooler air to flow in from over the water, creating a sea breeze. At night, the opposite happens, with the land cooling off faster than the water and creating a land breeze. These temperature differences and resulting wind patterns can also be influenced by the geography and topography of the surrounding area.

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Answer:

Explanation:

Please post if there is a graph showing the data.

Without a graph, in general the trend can be described as:

"positive" when the dependent variable increases with an increase in independent variable

"negative" when the dependent variable decreases with an increase in independent variable

"neutral" when the dependent variable remains the same with an increase or decrease in independent variable

Answer:

The mass is essentially "how much stuff" is in an object. ... Weight: There is a gravitational interaction between objects that have mass. If you consider an object interacting with the Earth, this force is called the weight. The unit for weight is the Newton (same as for any other force).

Explanation:

Answer:the difference is weight is the force exerted from an object by gravity

Explanation:

And mass is how much “stuff” is in an object

Let F be the magnitude of the force applied to the cart, m the mass of the cart, and a the acceleration it undergoes. After time t, the cart accelerates from rest v₀ = 0 to a final velocity v. By Newton's second law, the first push applies an acceleration of

F = m a   →   a = F / m

so that the cart's final speed is

v = v₀ + a t

v = (F / m) t

If we force is halved, so is the accleration:

a = F / m   →   a/2 = F / (2m)

So, in order to get the cart up to the same speed v as before, you need to double the time interval t to 2t, since that would give

(F / (2m)) (2t) = (F / m) t = v

Insurance is an example of benefits therefore the corrct answer is option D.

The exercise has a beneficial effect on the body and differs the type of death a person undergoes. If a person exercises but sits for too long can result in many diseases that ultimately lead to death. Along with exercise, the person should do mobile activities so that it increases their fitness.

It is among the most notable and significant advantages of insurance. According to insurance plans, the insured person or companies are protected from liabilities. The correct kind of insurance coverage might help you protect yourself from losses brought on by various life uncertainty.

Insurance is a good example of a benefit because, unlike salaries, which are things you earn as a base when you start a job, benefits are things you only receive as a result of working in certain jobs.

Thus,the correct answer is option D.

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Answer:

Material that allow the electrons to move freely in order to produce a current

Please mark as brainliest if answer is right

Have a great day, be safe and healthy  

Thank u  

XD  

If a wave has an amplitude of 0.0800 m and is moving 7.33 m/s. The

wavelength of the wave is 1.69m.

The wavelength of a wave can be determined using the equation:

Wavelength = velocity / frequency

To determine the frequency we need to calculate the reciprocal of the time it takes for one complete oscillation.

frequency = 1 / time

frequency = 1 / 0.230

frequency ≈ 4.35 Hz

Substitute the values into the wavelength equation:

wavelength = velocity / frequency

wavelength = 7.33 / 4.35

wavelength ≈ 1.69m

Therefore the wavelength of the wave is approximately 1.69 meters.

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